Answer:
Explanation: To solve this problem, we can use the equation for the force on a current-carrying conductor in a magnetic field:
F = I L x B
where F is the force on the conductor, I is the current flowing through the conductor, L is the length of the conductor, and B is the magnetic field strength.
a) Just after the switch is closed, the circuit is completed and a current starts to flow in the bar. The emf of the battery causes a current to flow in the circuit, which is given by Ohm's Law:
I = V / R = 12 / 5 = 2.4 A
The direction of the current is from the battery, through the bar, and back to the battery. Since the magnetic field is directed into the plane, the force on the bar is perpendicular to both the magnetic field and the current. Therefore, the bar experiences a sideways force that pushes it along the rails. The magnitude of the force is given by:
F = I L B = 2.4 x 0.36 x 2.4 = 2.0736 N
The mass of the bar is 0.90 kg, so the acceleration of the bar is:
a = F / m = 2.0736 / 0.90 = 2.304 m/s^2
Therefore, the acceleration of the bar just after the switch is closed is 2.304 m/s^2.
b) When the bar's speed is 2.0 m/s, the force on the bar is still given by:
F = I L B = 2.4 x 0.36 x 2.4 = 2.0736 N
However, now there is an additional force acting on the bar due to its motion through the air. This force is given by:
F_air = -0.5 ρ C_d A v^2
where ρ is the density of air, C_d is the drag coefficient, A is the cross-sectional area of the bar, and v is the speed of the bar. We can estimate the cross-sectional area of the bar as A = 0.01 m^2, and assume that the drag coefficient is C_d = 1. The density of air is ρ = 1.2 kg/m^3.
Substituting the given values, we get:
F_air = -0.5 x 1.2 x 1 x 0.01 x 2^2 = -0.024 N
The negative sign indicates that the air resistance is acting in the opposite direction to the motion of the bar.
The net force on the bar is therefore:
F_net = F + F_air = 2.0736 - 0.024 = 2.0496 N
Using Newton's Second Law, we can calculate the acceleration of the bar:
a = F_net / m = 2.0496 / 0.90 = 2.2778 m/s^2
Therefore, the acceleration of the bar when its speed is 2.0 m/s is 2.2778 m/s^2.
c) The bar's terminal speed is reached when the air resistance force is equal in magnitude and opposite in direction to the force due to the magnetic field. At this point, the net force on the bar is zero, so the acceleration is zero and the bar moves at a constant speed.
Setting F_net = 0, we can solve for the terminal speed:
F + F_air = 0
I L B - 0.5 ρ C_d A v^2 = 0
2.4 x 0.36 x 2.4 - 0.5
ρ C_d A v^2 = 2.0736
v^2 = (2.0736) / (ρ C_d A)
v^2 = (2.0736) / (1.2 x 1 x 0.01)
v^2 = 172.8
v = sqrt(172.8)
v = 13.142 m/s
Therefore, the bar's terminal speed is 13.142 m/s.
DOES FORCE ALWAYS HAVE SOME EFFECT ON ALL OBJECT
Answer:
Answer is down below…
Explanation:
A force does not always bring a change in motion of an object. For instance, if you push the walls of the room with your hands, the walls do not move. Sometimes force changes the shape and size of an object without any change in the state of motion of an object. Q.
the distance that a body in free fall falls each second is
a. is about 9.8m
b. is about 19.6m
c. increases as time passes
d. none of the above are correct
The distance that a body in free fall falls each second is (A). is about 9.8m is correct option.
The distance that a body in free fall falls each second is about 9.8 meters, which is equivalent to the acceleration due to gravity on the Earth's surface.
This means that in the absence of air resistance, an object dropped from a certain height will fall 9.8 meters during the first second, 19.6 meters during the second second, 29.4 meters during the third second, and so on. The distance increases as time passes, but not at a constant rate, as it is being affected by the acceleration due to gravity.
Therefore, the correct option is (a) .
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An object that is 3.0 cm high is placed 18.0 cm in front of a concave mirror with a radius of curvature of 52.0 cm. Find the magnification and location of the corresponding image in relation to the mirrors surface.
Answer:
Explanation: To find the magnification and location of the image produced by a concave mirror, we can use the mirror equation:
1/f = 1/do + 1/di
where f is the focal length of the mirror, do is the distance from the object to the mirror, and di is the distance from the image to the mirror.
We can use the sign conventions for mirrors, where distances are positive when measured in the direction of light propagation and negative when measured in the opposite direction.
In this case, the object is located 18.0 cm in front of the mirror, so do = -18.0 cm. The radius of curvature of the mirror is 52.0 cm, so the focal length is f = R/2 = 26.0 cm.
Substituting these values into the mirror equation, we get:
1/26.0 = 1/-18.0 + 1/di
Solving for di, we get:
1/di = 1/26.0 - 1/-18.0
1/di = 0.0385
di = 26.0 cm / 0.0385
di = 675.3 cm
The negative sign for do indicates that the object is located in front of the mirror, while the positive sign for di indicates that the image is located behind the mirror.
To find the magnification of the image, we can use the magnification equation:
m = -di / do
Substituting the given values, we get:
m = -675.3 cm / -18.0 cm
m = 37.5
Therefore, the image produced by the concave mirror is located 675.3 cm behind the mirror and is magnified by a factor of 37.5.
Give reason why relative density of a substance remains the same in both SI and CGS unit
Answer:As relative density is the ratio of similar quantities, it has no unit.So RD remains the same in both CGS and SI unit
Explanation: i did the test
A buoyant force acts in the opposite direction of gravity. According to Archimedes' Principle, which of the following is
true of an object completely submerged in water?
a. The magnitude of the upward buoyant force on the object is smaller than the weight of the fluid
displaced by the object.
b.
The magnitude of the upward buoyant force on the object is greater than the weight of the fluid
displaced by the object.
c.
The magnitude of the upward buoyant force on the object is equal to the weight of the fluid
displaced by the object.
d.
The object appears to weigh more than it does in air.
According to Archimedes' Principle, an object completely submerged in water experiences an upward buoyant force that is equal to the weight of the fluid displaced by the object. Therefore,
option C is the correct answer.
This principle states that any object placed in a fluid experiences a buoyant force, which is the result of the difference between the pressure on the top and bottom of the object.
If the buoyant force is greater than the object's weight, the object will rise to the surface, and if the buoyant force is less than the object's weight, it will sink.
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A rocket launches into space and continues to travel at a certain speed and a certain direction. Which of the following could alter this rockets speed or direction?
A.) The rocket travels near a planet
B.) The rocket rotates as it travels
C.) The rocket runs out of fuel
D.) The rocket changes shape
Answer:
A, C, and D could alter this rocket's speed or direction.
A) The rocket traveling near a planet could alter its speed or direction due to the gravitational pull of the planet.
B) The rocket rotating as it travels would not change its speed or direction, but it could change the orientation of the rocket's engines or thrust, which could affect its trajectory.
C) The rocket running out of fuel would cause it to slow down or stop moving, which would obviously alter its speed or direction.
D) The rocket changing shape could alter the way air or other particles interact with the rocket, which could affect its speed or direction. For example, if the rocket expanded in size, it would encounter more resistance in its path, which could slow it down or change its direction.
Therefore, the correct answer is A, C, and D.
Answer:
A, C, and D could alter the rocket's speed or direction.
A) The rocket traveling near a planet can alter its speed or direction due to the planet's gravity. This can cause the rocket to speed up, slow down, or change direction as it enters the planet's gravitational field.
C) If the rocket runs out of fuel, it will not be able to continue traveling at its current speed or direction. It may slow down, change direction, or come to a complete stop.
D) If the rocket changes shape, such as losing a piece of its body or encountering debris, this can alter its aerodynamics and affect its speed or direction.
B) The rocket rotating as it travels would not typically alter its speed or direction, as long as the rotation is not significant enough to affect its trajectory. The rocket's rotation could cause some minor changes in its orientation, but it would not significantly alter its speed or direction of travel.
A roller coaster car is released from rest as shown in the image below.
Ignoring friction, what will be the approximate velocity of the car when it
reaches the bottom of the roller coaster in the image? (Recall that g = 9.8
m/s².)
49 m
OA. 16 m/s
OB. 48 m/s
OC. 55 m/s
OD. 31 m/s
The speed of the roller coaster car as shown is 31 m/s
What is the Roller coaster?We know that the roller coaster is the kind of device that we can use to be able to show the conversion of kinetic energy to potential energy. By the use of the roller coaster, we can show that the total mechanical energy in the system is a constant.
As such we have that;
mgh = 1/2mv^2
m = mass of the object
g = acceleration due to gravity
h = height
v = velocity
Hence;
gh= 1/2v^2
v = √2gh
v = √ 2 * 9.8 * 49
v = 31 m/s
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Particles q1 =+9.33 uC, q2 =+4.22 uC, and q3=-8.42 uC are in a line. Particles q1 and q2 are separated by 0.180 m and particles q2 and q3 are separated by 0.230 m. What is the net force on particle q2?
The net force on q₂ will be 1.07 x 10⁻² N, pointing to the left.
To find the net force on particle q₂, we need to calculate the force due to q₁ and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:
F = k × (q₁ × q₂) / r²
where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.
The force due to q₁ on q₂ can be calculated as:
F₁ = k × (q₁ × q₂) / r₁²
where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).
Similarly, the force due to q₃ on q₂ can be calculated as:
F₂ = k × (q₃ × q₂) / r₃²
where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).
The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.
To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:
Fnet = F₁ - F₃
Substituting the values we get:
Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²
Plugging in the values we get:
Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]
Fnet = 1.07 x 10⁻² N
Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.
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earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________
earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.
What is energy?Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
The term earth's energy budget is also described as the balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.
The earth's energy budget was mainly three types as shown:
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1. Two point charges, q1 and q2, are located 5 cm apart. The magnitude of q1 is 3 μC and the magnitude of q2 is -5 μC. What is the force between these charges, according to Coulomb's law?
The force between these charges, according to Coulomb's law would be -54 N.
We can solve this problem applying "Coulomb's Law" which states-
[tex]\qquad\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ [/tex]
[tex] \qquad\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]
Where-
q₁ and q₂ are the two cahrges.r is the distance between the charges.[tex]\sf \epsilon_{0} [/tex] is the permittivity of free space.K is the Coulomb's Constant.k = 9×10⁹ Nm²/C²According to the given parameters -
Magnitude of q₁= 3 μCMagnitude of q₂= -5 μCDistance,r = 5cmNow that required values are given, so we can plug the values into the formula and solve for Force -
[tex]\qquad\qquad \:\sf\underline{Force = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]
[tex] \longrightarrow \sf Force = 9\times 10^9 \times \dfrac{ 3\times 10^{-6}\times -5 \times 10^{-6}}{\bigg(5\times 10^{-2}\bigg)^2}\\ [/tex]
[tex] \longrightarrow \sf Force = -\dfrac{9\times 5\times 3\times 10^{9} \times 10^{-12}}{25\times 10^{-4}}\\ [/tex]
[tex] \qquad\longrightarrow \sf Force =- \dfrac{135 \times 10^{9-12+4}}{25}\\ [/tex]
[tex] \qquad\longrightarrow \sf Force = - \dfrac{\cancel{135}}{\cancel{25}}\times 10\\ [/tex]
[tex] \qquad\longrightarrow \sf Force = -5.4 \times 10\\ [/tex]
[tex] \qquad\qquad\longrightarrow \sf \underline{Force = \boxed{\sf{-54 N}}} \\ [/tex]
Henceforth, The force between these charges, according to Coulomb's law would be -54 N.a wire carrying current I is perpendicular to a magnetic field of strenght B. Assuming a fixed lenght of wire, which of the following changes will result in decreasing the force on the wire by a factor of 2?
*the options are in the picture attached
Since the wire is perpendicular to the magnetic field thus
F=I {l{B}
How to solveForce on current carrying wire due to magnetic field is given as
[tex]\vec{F}=I (\vec{l}\times \vec{B})=I lB\sin\theta[/tex]
Since the wire is perpendicular to the magnetic field thus
F=I {l{B}
Let's check the options
If we change the angle between the current flow and the magnetic field from 90 to 75 or 60 degrees, F doesn't become 1/4 of its initial value. Hence options (d) & (e) is incorrect options.
Now if we decrease the current to 1/8 and increase the magnetic field to 4 times then force F becomes 1/2. Therefore option (a) is the incorrect option.
If we decrease the field to B/2 then the force becomes F/2.
Therefore (c) is also an incorrect option.
We are only left with option (b) which is the correct option.
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Consider a system consisting of a block of mass m attached to a spring with spring constant k, sliding on a frictionless surface. If the block is displaced from its equilibrium position by a distance x and then released, what is the period of its motion?
If the block is displaced from its equilibrium position by a distance x, the period of its motion is T = 2π/ω = 2π√(m/k).
What is the period of motion of the block?
The period of motion of a block under simple harmonic motion is given as;
T = 2π√(m/k)
Where;
T is the periodm is the mass of the blockk is the spring constantWhen the block is displaced from its equilibrium position by a distance x, the force acting on it is given as;
F = -kx
where;
x is displacementWe also know that angular velocity is given as;
ω = √(k/m)
So the equation for the period can also be;
T = 2π/ω = 2π√(m/k)
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A bar of length L = 0.36m is free to slide without friction on horizontal rails. A uniform magnetic field B = 2.4T is directed into the plane. At one end of the rails there is a battery with emf = 12V and a Switch S. The bar has the mass 0.90kg and resistance 5.0ohm. ignore all the other resistance in the circuit. The switch is closed at time t = 0. a) Just after the switch is closed, what is the acceleration of the bar? b)what is the acceleration of. the bar when its speed is 2.0m/s? c) what is the bar's terminal speed?
The acceleration of the bar is zero, and it remains at rest. The acceleration of the bar is 9.24 m/s². The bar's terminal speed is approximately 7.94 m/s.
Just after the switch is closed, the circuit is closed and a current starts flowing in the bar, induced by the magnetic field according to Faraday's Law. The direction of the induced current is such that the bar experiences a force that opposes its motion (Lenz's Law). Therefore, the acceleration of the bar is zero, and it remains at rest.
The force on the bar due to the magnetic field is given by F = IlB, where I is the current flowing in the bar, l is its length, and B is the magnetic field strength. The current in the bar is given by Ohm's Law: I = emf/R, where emf is the voltage of the battery and R is the resistance of the bar. Therefore, the force on the bar is
F = IlB = (emf/R)lB
= (12 V / 5 Ω) × 0.36 m × 2.4 T
= 20.736 N
The net force on the bar is F - mg, where m is the mass of the bar and g is the acceleration due to gravity. Therefore, the acceleration of the bar is
a = (F - mg) / m
= (20.736 N - 0.9 kg × 9.81 m/s²) / 0.9 kg
= 9.24 m/s²
When the bar reaches terminal velocity, the force due to the magnetic field is balanced by the drag force due to air resistance. The drag force is given by Fd = 1/2 × rho × A × [tex]v^2[/tex] × C_d, where rho is the density of air, A is the cross-sectional area of the bar, v is the velocity of the bar, and Cd is the drag coefficient. The terminal velocity occurs when F = Fd, or
IlB = 1/2 × rho × A × v² × Cd
Solving for v, we get
v = √(2IlB / (rho × A × Cd))
Substituting the given values, we get
v = √(2 × (12 V / 5 Ω) × 0.36 m × 2.4 T / (1.225 kg/m³ × 0.00756 m² × 0.47)) = 7.94 m/s
Therefore, the bar's terminal speed is approximately 7.94 m/s.
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aluminium oxide formulae
Answer:
formula of aluminum oxide Al₂O₃
a physical science student is studying ohms law and builds a circuit the supplies voltage is 210v how much resistance will the student need in order to have an amperage of 7.0 A
Ohm's law states that the voltage (V) over a resistor is break even with to the item of the current (I) streaming through it and its resistance (R), or V = I*R.
How much resistance will the student need in order to have an amperage of 7.0 A?To discover the resistance required to have an amperage of 7.0 A with a voltage supply of 210 V, able to improve the condition to unravel for R:
R = V/I
Stopping within the values we know:
R = 210 V / 7.0 A
R = 30 ohms
Subsequently, the understudy will require a resistance of 30 ohms to attain an amperage of 7.0 A with a voltage supply of 210 V.
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Which of the following equations could be used to derive an expression for the electric field created by a changing magnetic field?
Option C is the use of the equations to arrive at an expression for the electric field produced by a shifting magnetic field.
A current will be induced in a coil of wire if the coil is put in a magnetic field that is changing. Since there is an electric field causing the charges to be forced around the wire, current is flowing as a result. The charges are not initially moving, hence it cannot be the magnetic force.
The moving + and - charges radiate a changing electric field, and it is also visible that this field generates a changing magnetic field as well. With increasing distance from the antenna, the source of the radiation, the electric and magnetic fields lose strength.
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The spring shown in the Figure below is compressed 50 cm and used to launch a 100 kg physics student. The track is frictionless until it starts up the incline. The student’s coefficient of kinetic friction on the 30◦ incline is 0.15. (a) What is the student’s speed just after losing contact with the spring?
(b) What is the student’s speed immediately before moving up the 30◦ incline?
(c) How far up the incline does the student go?
part a.
The student’s speed just after losing contact with the spring is 14.14 m/s
part b.
The students can go up to 32.06cm
What is speed?Speed is described as one such measurable quantity that measures the ratio of the distance travelled by an object to the time required to travel that distance.
Given values:
The spring shown below is compressed = 50 cmand is used to launch a 100kg physics student. The track is frictionless until it starts up the incline. The student's coefficient of kinetic friction on the 30° incline = 0.15We apply the conservation of energy, energy in the compressed string:
1/2 mv2 = 1/2 kx²v²
which will be [tex]\sqrt{kxv}/m[/tex]
substituting we have the value as 14.14 m/s
part b.
then conservation of energy equation will become:
1/2 kx² + mgh
substituting we have the value as 32.06cm
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.
Which of the following is NOT a suggestion for relapse prevention?
OA. Make sure the exercise program is easy so that you are not
challenged.
O B. Tell your family and friends about your progress with exercising.
C. Determine ways to overcome barriers.
D. Take injury prevention precautions.
SUBMIT
Make sure the exercise program is easy so that you are not challenged is NOT a suggestion for relapse prevention. The correct option is A
What is relapse prevention ?Relapse prevention is a technique used to support people in maintaining long-term behavioral change and stop them from reverting to previous unhealthy practices.
Relapse prevention can take many different forms including :
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Question 2 (1 point)
What happens to the number of waves when you change the light from green to red?
Increase
decrease
remain the same
there are zero waves
When you change the light from green to red, the number of waves remains the same.
Light waves behave similarly throughout the electromagnetic spectrum. Depending on the nature of the item and the light's wavelength, a light wave can be transmitted, reflected, absorbed, refracted, polarized, diffracted, or dispersed when it strikes a surface.
The number of waves doesn't vary when the light changes from green to red. The distance between each wave's consecutive peaks, or wavelength, determines the color of light. Red and green light both have waves with a set number of peaks and troughs per unit of time, despite green light having a shorter wavelength. As a result, the number of waves is unaffected by changing the colour of the light.
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Great Company manufactures and sells a product whose peak sales occur in the third quarter. Management is now preparing detailed budgets for 20x4- the coming year and has assembled the following information to assist in the budget preparation: The company’s product selling price is Br. 20 per unit. The marketing department has estimated sales in units as follows for the next six quarters.
Answer:
Explanation:
Quarter 1 - 10,000 units
Quarter 2 - 12,000 units
Quarter 3 - 16,000 units
Quarter 4 - 14,000 units
Quarter 5 - 10,000 units
Quarter 6 - 8,000 units
Based on this information, the total estimated sales revenue for the next six quarters is Br. 480,000.
What is the formula for potential difference?
The formula for potential difference (also known as voltage) is, V = ΔE/q, where V is the potential difference in volts (V), ΔE is the change in electric potential energy in joules (J), and q is the charge in coulombs (C).
Electric potential difference, also known as voltage, is a measure of the electric potential energy per unit of charge required to move a charge from one point to another in an electric circuit. It is the difference in electric potential between two points in an electric circuit.
The formula for potential difference, V = ΔE/q, reflects this relationship. The numerator, ΔE, represents the change in electric potential energy between the two points, while the denominator, q, represents the charge that moves between the two points.
For example, if a charge of +1 C moves from a point A to a point B in an electric circuit, and the electric potential energy at point B is greater than at point A by 1 J, then the potential difference between points A and B is 1 V. This means that it takes 1 J of energy to move a unit of charge from point A to point B in the circuit.
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Wayne Gretzky was gliding at 2.00 m/s [W] when he collided with Joel Otto who was gliding at 1.80 m/s [E]. After the head on collision, Gretzky ends up going at 1.00 m/s [E] and Otto at 0.100 m/s [E]. What is the ratio of the mass of Gretzky to the mass of Otto?
Answer:
Mass of Otto is approximately [tex](30 / 17)[/tex] times that of Gretzky.
Explanation:
Let [tex]m_{\text{G}}[/tex] and [tex]m_{\text{O}}[/tex] denote the mass of Gretzky and Otto. Let [tex]u_{\text{G}}[/tex] and [tex]u_{\text{O}}[/tex] denote their velocity before the collision. Let [tex]v_{\text{G}}[/tex] and [tex]v_{\text{O}}[/tex] denote their velocity after the collision.
By the conservation of momentum:
[tex]m_{\text{G}}\, u_{\text{G}} + m_{\text{O}}\, u_{\text{O}} = m_{\text{G}}\, v_{\text{G}} + m_{\text{O}}\, v_{\text{O}}[/tex].
Assume that [tex]m_{\text{O}} = k\, m_{\text{G}}[/tex] for some constant [tex]k > 0[/tex] denoting the ratio of mass between Otto and Gretzky. The equation for the conservation of momentum becomes:
[tex]m_{\text{G}}\, u_{\text{G}} + (k\, m_{\text{G}})\, u_{\text{O}} = m_{\text{G}}\, v_{\text{G}} + (k\, m_{\text{G}})\, v_{\text{O}}[/tex].
[tex]u_{\text{G}} + k\, u_{\text{O}} = v_{\text{G}} + k\, v_{\text{O}}[/tex].
Rearrange and solve for the ratio [tex]k[/tex]:
[tex]\begin{aligned}(v_{\text{O}} - u_{\text{O}})\, k = u_{\text{G}} - v_{\text{G}} \end{aligned}[/tex].
[tex]\begin{aligned}k = \frac{u_{\text{G}} - v_{\text{G}}}{v_{\text{O}} - u_{\text{O}}} \end{aligned}[/tex].
Let the East be the positive direction. Since it is given that the initial velocity of Gretzky is opposite to the East, the initial velocity of Gretzky would be negative: [tex]u_{\text{G}} = (-2.00)\; {\rm m\cdot s^{-1}}[/tex].
It is also given that [tex]u_{\text{O}} = 1.80\; {\rm m\cdot s^{-1}}[/tex], [tex]v_{\text{G}} = 1.00\; {\rm m\cdot s^{-1}}[/tex], and [tex]v_{\text{O}} = 0.100\; {\rm m\cdot s^{-1}}[/tex]. Substitute these values into the equation to find the ratio [tex]k[/tex]:
[tex]\begin{aligned}k &= \frac{u_{\text{G}} - v_{\text{G}}}{v_{\text{O}} - u_{\text{O}}} \\ &= \frac{(-2.00) - 1.00}{0.100 - 1.80} \\ &= \frac{30}{17}\end{aligned}[/tex].
In other words, the mass of Otto was [tex](30 / 17)[/tex] times that of Gretzky.
in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
Firing a gun straight up into the air can be dangerous because the bullet, when it falls back to Earth, can reach a high enough velocity to cause injury or even death.
When a bullet is fired straight up into the air, it will eventually reach the highest point of its trajectory and begin to fall back down due to gravity. As it falls, it gains speed and momentum, which can cause it to reach a lethal velocity when it impacts a person or object on the ground. This phenomenon is known as "celebratory gunfire," and it can cause serious harm to people who are hit by falling bullets. Therefore, firing a gun straight up into the air is never a safe or responsible act.
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--The complete question is, What is the scientific explanation for why firing a gun straight up into the air can be dangerous, despite the fact that the bullet will eventually fall back down to Earth?--
the student measure the massof he wooden block and found it to be =0.20kg.name the apparatus that can used to measure the mass ofthe wooden block
The apparatus that can used to measure the mass of the wooden block by the student is called beam balance.
A beam balance, often referred to as a double-pan balance, is a straightforward tool for determining an object's weight. Two pans or trays are hung from either end of a horizontal beam that is suspended from a pivot point in the middle.
The thing to be weighed is put on one tray, and then the second tray is filled with standard weights until it balances, showing the weight of the object. From little ones used in laboratories to larger ones used in enterprises, beam balances can be found in a variety of shapes and sizes. Because they are precise and operate without electricity or batteries, they are widely used.
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Approximately 20.0gm of milk at 6.0oC is added into a cup containing 270.0 gm of weak tea. The specific heat of weak tea is 3.91 x 103J kg-1 oC-1 and the final temperature of the milk - tea mixture is 85.0oC. Given the initial temperature of the weak tea is 90.0oC, what is the specific heat of milk?
Answer:
4161 J/kg·°C
Explanation:
We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.
Let's first calculate the heat lost by the tea:
Q(tea) = mcΔT
Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)
Q(tea) = 6555 J
where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.
Next, let's calculate the heat gained by the milk:
Q(milk) = mcΔT
Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)
Now we can equate the two expressions:
Q(tea) = Q(milk)
6555 J = (0.02 kg)(c)(79.0°C)
Solving for c, we get:
c = 4161 J/kg·°C
Therefore, the specific heat of milk is approximately 4161 J/kg·°C.
What covers the earth that is found at the upper most layer of the earth's crust
Answer:
The uppermost layer of the Earth's crust is called the soil. It covers the entire Earth and is composed of a mixture of organic matter, minerals, water, and air. The composition and properties of the soil vary depending on the location, climate, and vegetation. Soil plays an essential role in supporting plant life and providing nutrients for crops to grow. It is also critical for water retention and filtration, erosion control, and carbon sequestration. Understanding the properties of soil is important for agricultural, environmental, and industrial practices.
mention any two points to in established the importance of Physics.
Here are two points that establish the importance of Physics:
1. Understanding the natural world: Physics is the branch of science that helps us understand the natural world. By studying the laws of physics, we can understand the behavior of the universe, from the smallest subatomic particles to the largest structures in the cosmos. Physics provides us with a framework for understanding how the world around us works, from the motion of objects to the behavior of light and other forms of energy.
2. Advancing technology and innovation: Physics has been instrumental in advancing technology and driving innovation in many fields. From the development of electricity and electronics to the creation of the internet and advanced materials, physics has provided the fundamental knowledge and tools needed to create many of the technologies that we rely on today. Many of the most important technological advancements of the past century have been based on our understanding of physics, and continued research in this field will likely lead to many more exciting discoveries and innovations in the future.
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Which best describes a difference between energy transformations in power plants and dams?
Answer:
Only power plants use fossil fuels to transform energy. Only dams use fission to generate thermal energy.
Question 1 of 10
A business must decide whether to open a new office in China. If it opens the
branch, it will increase its chances of selling a high volume of its products in
China. On the other hand, the business will have to spend a lot of money to
make the branch operational.
What would be an opportunity cost for the business if it chooses not to open
the new branch in China?
A. The business would lose the chance to make more money in
China.
B. The business would increase its marginal benefits on each
product it makes.
The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars
The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.
Weight of objects on Earth and on MarsThe weight of an object is given by the product of its mass and the gravitational field strength at its location.
On Earth:
Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 NOn Mars:
Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 NTherefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.
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