A block on an inclined surface is connected to another block that is hanging over the top edge of the incline, as shown in the following diagram. The blocks in the system are moving in such a way that block A (with a mass of 3 kg) is moving downwards, as block B (with a mass of 2 kg) slides up the ramp. The coefficient of kinetic friction between the ramp and the sliding block is 0.11.
State the acceleration of each block, and the amount of tension in the string.
Answers
The acceleration of block A is 2.31 m/s², the acceleration of block B is 3.44 m/s², and the tension in the string is 8.75 N.
To solve this problem, we will apply the principles of Newton's laws of motion. We will consider the forces acting on each block separately.
For Block A:
The only force acting on block A is its weight, which is given by:
FgravityA = mA * g
where mA is the mass of block A, and g is the acceleration due to gravity (which is 9.81 m/s²).
Since block A is moving downwards, we can find its acceleration by subtracting the force of friction from its weight, and then dividing by its mass:
aA = (FgravityA - FfrictionA) / mA
where FfrictionA is the force of friction acting on block A. Since the surface is inclined, we need to resolve the weight of block A into its components parallel and perpendicular to the surface:
FparallelA = mA * g * sin(θ)
FperpendicularA = mA * g * cos(θ)
where theta is the angle of inclination of the surface. The force of friction is then given by:
FfrictionA = friction coefficient * FperpendicularA
where friction coefficient is the coefficient of kinetic friction between the surface and block A. Substituting these values, we get:
FparallelA = mA * g * sin(θ) = 3 * 9.81 * sin(30) = 14.2 N
FperpendicularA = mA * g * cos(θ)= 3 * 9.81 * cos(30) = 25.7 N
FfrictionA = friction coefficient * FperpendicularA = 0.11 * 25.7 = 2.83 N
aA = (FgravityA - FfrictionA) / mA = (3 * 9.81 - 2.83) / 3 = 2.31 m/s²
For Block B:
The forces acting on block B are its weight, the tension in the string, and the force of friction. The tension in the string is equal to the weight of block A minus the component of its weight parallel to the surface:
Ftension = mA * g * cos(θ)- FparallelA
The force of friction is given by:
FfrictionB = friction coefficient * Fperpendicular B
where Fperpendicular B is the perpendicular component of the weight of block B:
Fperpendicular B = mB * g * cos(θ)= 2 * 9.81 * cos(30) = 17.0 N
Substituting these values, we get:
Ftension = mA * g * cos(θ) - FparallelA = 3 * 9.81 * cos(30) - 14.2 = 8.75 N
FfrictionB = friction coefficient * Fperpendicular B = 0.11 * 17.0 = 1.87 N
The acceleration of block B is then given by:
aB = (Ftension - Ffriction B) / mB = (8.75 - 1.87) / 2 = 3.44 m/s²
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Related Questions
A car starts 200 m west and moved with constant velocity of 15 m/s toward the east where will the car be 10 minutes later
Answers
i think the formula is distance x velocity = location
If a student were to measure the ball's speed at each position above, at which position would
the ball be traveling the fastest?
A
B
C
D
Answers
Hope I helped :)
1 a Explain the difference between a transverse wave and a longitudinal
wave.
b Give one example of each.
c Draw a diagram of a transverse wave. On your diagram, mark the
wavelength and amplitude of the wave.
Answers
The difference between transverse and longitudinal waves is direction of wave motion in relative to direction of the particle motion.
Transverse vs Longitudinal Waves: What's the Difference?The particle motion in a transverse wave is only perpendicular to the wave motion but in longitudinal wave, the particle motion is parallel to the wave motion.
An example of transverse wave is a wave on a guitar string which when plucked, it vibrates back and forth in a direction perpendicular to the direction of the wave traveling along the string.
An example of a longitudinal wave is sound waves which are created when a source like speaker or a musical instrument vibrates back and forth in the same direction as the wave is traveling through the air.
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How much energy is required to change a 42 g ice cube from ice at −13◦C to steam at 114◦C? The specific heat of ice is 2090 J/kg · ◦ C, the specific heat of water is 4186 J/kg · ◦ C, the specific heat of stream is 2010 J/kg · ◦ C, the heat of fusion is 3.33 × 105 J/kg, and the heat of vaporization is 2.26 × 106 J/kg. Answer in units of J.
Answers
The energy required to change a 42 g ice cube from ice at −13°C to steam at 114°C will be 129964.96 J.
To calculate the energy required to change a 42 g ice cube from ice at −13°C to steam at 114°C, we need to consider the following processes:
Heating the ice from −13°C to 0°C
Melting the ice at 0°C
Heating the water from 0°C to 100°C
Boiling the water at 100°C
Heating the steam from 100°C to 114°C
calculate the energy required for each step:
Heating the ice from −13°C to 0°C:
The specific heat of ice is 2090 J/kg · ◦C. We have 42 g of ice, which is 0.042 kg. The temperature difference is 0◦C - (-13◦C) = 13◦C.
The energy required to heat the ice is:
Q₁ = (0.042 kg) x (2090 J/kg°C) x (13°C) = 1151.04 J
Melting the ice at 0°C:
The heat of fusion of ice is 3.33 × 105 J/kg. The energy required to melt the ice is:
Q₂ = (0.042 kg) x (3.33 × 105 J/kg) = 14046 J
Heating the water from 0°C to 100°C:
The specific heat of water is 4186 J/kg°C. The mass of water is still 42 g. The temperature difference is 100°C - 0°C = 100°C.
The energy required to heat the water is:
Q3 = (0.042 kg) x (4186 J/kg°C) x (100°C) = 17607.72 J
Boiling the water at 100°C:
The heat of vaporization of water is 2.26 × 10 J/kg. The energy required to boil the water is:
Q₄ = (0.042 kg) x (2.26 × 106 J/kg) = 94920 J
Heating the steam from 100°C to 114°C:
The specific heat of steam is 2010 J/kg°C. The mass of steam is the same as the mass of water, which is 0.042 kg. The temperature difference is 114°C - 100°C = 14°C.
The energy required to heat the steam is:
Q₅ = (0.042 kg) x (2010 J/kg°C) x (14°C) = 1239.24 J
The total energy required is the sum of all the energies:
Qtotal = Q₁ + Q₂ + Q₃ + Q₄ + Q₅ = 129964.96 J
Therefore, the energy required to change a 42 g ice cube from ice at −13°C to steam at 114°C is 129964.96 J.
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A group of students were given a balloon, two aluminum soda cans, two Styrofoam cups, and some scotch tape and were told to design an investigation that would demonstrate the distribution of charge by induction. The students charged the balloon positively by rubbing it against a wool sweater. The balloon was then brought into contact with the first soda can (P).
After the cans P and Q are separated, will the balloon be attracted to or repelled by can Q? Why?
A
The balloon will not be attracted to or repelled by can Q because can Q will have no net charge after the cans are separated.
B
The balloon will be repelled by the soda can labelled Q after they are separated because the can labelled Q will be positively charged.
C
The balloon will be attracted to the soda can labelled Q after they are separated because both soda cans will be negatively charged.
D
The balloon will not be attracted to or repelled by can Q because when the balloon is placed in contact with either can no charge is induced on the surface of the cans.
Answers
After the cans P and Q are separated, The balloon will be repelled by the soda can labeled Q after they are separated because the can labeled Q will be positively charged.
How to get the situation of the balloonLets assume that the soda cans (P and Q) are initially neutral and in contact.
When the +ve is brough close to there would be the distribution of charge. The -ve charges that are in P would then be attracted to the area that is closer to ballon. The positives would be repeled. They would be farther
P will then have the net negative on area that faces balloon and Q with the net positive on area facing P
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14. How are an object's speed and velocity related to an object's kinetic energy and total mechanical energy
Answers
Speed and velocity are related to an object's kinetic energy, which is the energy associated with its motion.
What is kinetic energy?Kinetic energy is the energy that an object has due to its motion. It is a form of energy that is associated with the motion of an object, and is calculated by multiplying the mass of the object by the square of its velocity. Kinetic energy is one of the most fundamental forms of energy, and is found in everything from the movement of atoms and molecules to the motion of planets and stars. Kinetic energy is also the energy that is associated with everyday objects, such as a ball that is thrown or a car that is moving. Kinetic energy can be converted into other forms of energy, such as heat or electricity, and can also be used to do work, such as powering a car or a machine. Kinetic energy is a crucial part of the natural world, and is necessary for many of the processes that occur in nature.
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A block of mass M=5.0 kg is hanging at equilibrium from an ideal spring with spring constant k=250 N/m
a) on the dot below, which represents the block, draw and label the forces (not components) that act on the block. Each force must be represented by distinct arrow, starting on, and pointing away from, the dot.
The block is pulled 0.15 m below is equilibrium position and released from rest.
b) determine the maximum displacement of the mass from equilibrium
c) calculate the elastic potential energy of the spring, just as the block is being released
d) calculate the maximum speed, the block will have during its motion
e) calculate the displacement of the block from equilibrium when the kinetic energy of the block is equal to the elastic potential energy of the spring
The block is brought to rest at equilibrium. The block is then pulled down half the original distance.
f) will the new period for the motion of the block, be greater than, less than, or equal to the original period for the motion of the block?
Answers
The maximum displacement of the mass from equilibrium is 0.4 times the square root of the maximum height the block reaches.
What is Displacement?
In physics, displacement is the distance and direction of an object's change in position from its starting point to its end point. It is a vector quantity and is represented by a vector pointing from the object's initial position to its final position. Displacement is different from distance, which is the total path length traveled by an object and is a scalar quantity.
The elastic potential energy of the spring is given by:
U = 1/2 k[tex]x^{2}[/tex]
where U is the elastic potential energy, k is the spring constant, and x is the displacement from equilibrium.
At the instant the block is released, it is pulled 0.15 m below its equilibrium position. Therefore, the initial displacement of the block is x = 0.15 m.
Substituting the given values, we get:
U = 1/2 * 250 N/m * [tex](0.15 m)^{2}[/tex] = 1.875 J
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a body of mass 0.5kg is taken up an inclined plane the length 10m and height 8m and then allowed to slide down to the bottom again the coefficient of friction between the body and the plane is 0.12. what is work done by gravitational force over the ground trip?,work done by applied force over the up work trip?, work done by frictional force over the round trip? and kinetic energy of the body at the end of the trip?
Answers
According to the question Work done by gravitational force over the ground trip: Gravitational force does not do any work over the ground trip since the body is not moving.
What is gravitational force?Gravitational force is the attractive force between two masses. This force is the result of the curvature of spacetime caused by the presence of mass. Gravitational force is what keeps the planets in orbits around the sun, and what keeps the moon orbiting the Earth.
Work done by applied force over the up work trip: The work done by the applied force over the up work trip is given by,
W = F * d * cosθ
= (0.5 kg * 9.81 m/s2) * 10 m * cos(45°)
= 71.4 J
Work done by frictional force over the round trip: The work done by the frictional force over the round trip is given by,
W_f = F_f * d
= (0.5 kg * 9.81 m/s2 * 0.12) * 10 m
= 5.88 J
Kinetic energy of the body at the end of the trip: The kinetic energy of the body at the end of the trip is given by,
KE = 0.5 mv2
= 0.5 * 0.5 kg * (2 * 9.81 m/s2 * 8 m)2
= 611.52 J
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Question 8 (5 points)
What is indicated by the slope of an acceleration vs. time graph?
The maximum speed of the object
The total displacement of the object
The change in position of the object
The velocity of an object
Answers
The velocity of an object is indicated by the slope of an acceleration vs. time graph
What is velocity of an object?Acceleration is how much velocity changes,from the definition here, the slope of the graph tells us how quickly the object's velocity is changing over time.
To dtermine object's velocity from an acceleration vs. time graph, you would have to carry out the integration of the acceleration to get the object's velocity as a function of time.
Hence the last option is the corrcet answer here
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Answer:The velocity of an object
The sum of two point charges is -15µC. They attract each other with a force of 9 x 10-2 N when kept 5m apart. Find their charges.
Answers
According to the question the two charges are -7.5 µC and -7.5 µC.
What is charges?Charges are fees or payments for services or goods. Charges can be one-time payments, recurring payments, or fees associated with using a product or service. Charges can be for products, services, or activities. Examples of charges include fees for using a credit card, fees for using a bank account, fees for renting a car, fees for using a mobile phone plan, fees for using a subscription service, fees for using a streaming service, and fees for using a gym membership.
Let the two charges be x and ( -15 - x ) µC.
According to Coulomb's law,
F = (k × x × ( -15 - x ))/r2
Where k is the Coulomb's constant,
k = 9 × 109 N × m2/C2
Given, F = 9 × 10-2 N
r = 5 m
Substituting these values in the equation,
9 × 10-2 = (9 × 109 × x × ( -15 - x ))/252
⇒ x2+ 15x - 4.5 × 10-4 = 0
Solving this equation,
x = -7.5 µC and ( -15 - x ) = -7.5 µC
Therefore, the two charges are -7.5 µC and -7.5 µC.
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what is speed sound travelling in the soil ?
Answers
The speed of sound traveling in the soil depends on the type of soil.
Speed of sound in the soilThe speed of sound traveling through soil can vary depending on the composition and density of the soil.
In general, sound travels slower through soil than through air, with typical speeds ranging from around 1000 to 4000 meters per second.
The speed of sound in the soil has been researched to have important implications for seismic surveys, which use sound waves to map underground geological structures and identify potential sources of natural resources like oil and gas.
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Use the graph to answer the following questions
1.) About how long is one half-life for Element 1? (Hint: how long does it take for half of it to decay?)
2.) A scientist finds a bone that has about 15% Element 1 left. About how old is the bone?
3.) A scientist finds a rock with about 75% of its Element 1 left. About how old is the rock?
4.) A scientist drops all his samples and is trying to figure out where to classify them. He thinks a sample is from about 9,000,000 years ago. If he tests the sample, how much of element 1 should be left in it?
5.)A paleontologist finds a skeleton that he thinks is about 1,000,000 years old. How much Element 1 should she expect to find in the sample if her guess is correct?
Answers
1. The half-life for element 1 is 3000000 years
2. The age of the bone is 8220000 years
3. The age of the rock is 1230000 years
4. The amount of element 1 remaining is 12.5%
5. The amount of element 1 she would find is 79.55%
1. How do i determine the half-life?The half-life of a substance is the time taken for half the substance to decay.
From the above diagram, we can see that the original amount of element 1 is 100 g. Thus, half of 100 is 50.
Looking at the diagram, the time for 50 g is 3000000 years.
Therefore, we can conclude that the half-life of element 1 is 3000000 years
2. How do i determine the age of the bone?First, we shall determine the number of half lives that has elapsed. This is obtained as follow:
Original amount (N₀) = 100%Amount remaining (N) = 15%Number of half-lives (n) =?2ⁿ = N₀ / N
2ⁿ = 100 / 15
2ⁿ = 6.67
Take the log of both sides
Log 2ⁿ = Log 6.67
nLog 2 = Log 6.67
Take the log of both sides
n = Log 6.67 / Log 2
n = 2.74
Finally, we shall determine the age of the bone. Details below
Half-life of element 1 (t½) = 3000000 yearsNumber of half-lives (n) = 2.74 Age of bone (t) =?t = n × t½
t = 2.74 × 3000000
t = 8220000 years
Thus, the age of the bone is 8220000 years
3. How do i determine the age of the rock?First, we shall determine the number of half lives that has elapsed. This is obtained as follow:
Original amount (N₀) = 100%Amount remaining (N) = 75%Number of half-lives (n) =?2ⁿ = N₀ / N
2ⁿ = 100 / 75
2ⁿ = 1.33
Take the log of both sides
Log 2ⁿ = Log 1.33
nLog 2 = Log 6.67
Take the log of both sides
n = Log 1.33 / Log 2
n = 0.41
Finally, we shall determine the age of the rock. Details below
Half-life of element 1 (t½) = 3000000 yearsNumber of half-lives (n) = 0.41 Age of bone (t) =?t = n × t½
t = 0.41 × 3000000
t = 1230000 years
Thus, the age of the rock is 1230000 years
4. How do i determine the amount remaining?We shall first obtain the number of half lives that will elaspe during the time. Details below:
Half-life of element 1 (t½) = 3000000 yearsTime (t) = 9000000 yearsNumber of half-lives (n) =?n = t / t½
n = 9000000 / 3000000
n = 3
Finally, we shall determine the amount remaining. Details below:
Original amount (N₀) = 100Number of half-lives (n) = 3Amount remaining (N) = ?N = N₀ / 2ⁿ
N = 100 / 2³
N = 100 / 8
N = 12.5%
Thus, we can conclude that the amount remaining is 12.5%
5. How do i know how much of the element she would find?We shall first obtain the number of half lives that will elaspe during the time. Details below:
Half-life of element 1 (t½) = 3000000 yearsTime (t) = 1000000 yearsNumber of half-lives (n) =?n = t / t½
n = 1000000 / 3000000
n = 0.33
Finally, we shall determine the amount she would find. Details below:
Original amount (N₀) = 100Number of half-lives (n) = 0.33Amount found (N) = ?N = N₀ / 2ⁿ
N = 100 / 2^0.33
N = 79.55%
Thus, the amount she would find is 79.55%
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what is hookies law of elasticity
Answers
Hooke's law of elasticity is a principle in physics that states that the force required to extend or compress a spring by some distance is proportional to that distance. It is named after the English physicist Robert Hooke, who first stated the law in 1678. Hooke's law is often written as F = -kx, where F is the force applied to the spring, x is the distance it is stretched or compressed, and k is the spring constant, a measure of the stiffness of the spring.
Using a social marketing strategy, design a persuasive message to promote any health behavior of your choice
Answers
Headline: Make a Move for a Healthier Life!
Subheading: Stay active, stay healthy, stay happy!
Body: Regular exercise is key to a healthier and happier life. By committing to a regular exercise routine, you can improve your physical fitness, reduce your risk of chronic diseases, and boost your mental health and wellbeing. Whether it's going for a jog, joining a fitness class, or simply taking a walk around the block, there are plenty of ways to get active and start reaping the benefits.
Join us in promoting a healthy lifestyle by making a move today. Not only will you feel better physically and mentally, but you'll also inspire others to follow your lead. Remember, a healthy lifestyle starts with a single step. Take it today and keep moving forward towards a healthier, happier you!
Call to Action: Join us and commit to a regular exercise routine starting today! Set achievable goals and stay motivated by tracking your progress. Share your journey with us and inspire others to make a move towards a healthier life!
What are the stages of the sliding filament theory?
Answers
The sliding filament theory explains how myosin and actin interact to cause a muscle contraction. There are 5 stages: resting, excitement-contraction, contraction, recharge, and relaxation.
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1 The resting phase is before there is any tension in the muscle, pretty self explanatory.
2 The excitement-contraction phase occurs once the sarcoplasmic reticulum (SR) releases calcium, that binds to troponin, which causes tropomyosin to shift, allowing the myosin cross-bridge to attach to actin. The muscle force is determined by the number of cross bridges involved. When there's an increase in the number of cross-bridges, myofibril and sarcoplasmic reticulum hypertrophy, which result in more actin + myosin and more fuel for the muscle respectively. To increase the power generated in a contraction, there needs to be an increase in the speed of cross bridges. Also make note: at this point, the muscle still hasn't quite contracted.
3 The contraction phase is where the power stroke occurs. ATP undergoes hydrolysis via the enzyme myosin ATPase, and loses a phosphate to become ADP. This allows the myosin head to change shape and pull on the actin, which is referred to as the power stroke. Myosin pulling on actin causes the muscle fiber to shorten.
4 The recharge phase is when the contraction continues and can only occur when calcium, ATP, and myosin ATPase are all still available.
5 The relaxation phase occurs when nerve stimulation stops and those components are no longer available. The calcium returns to the sarcoplasmic reticulum and myosin lets go of actin.
A rock is thrown straight up with an initial speed of 22 m/s.
A. Graph the vertical position, velocity, and acceleration of the rock on the axes provided.
B. Draw a motion map for the trip.
C. How long will it be in the air before it returns to the thrower?
Answers
The rock will be in the air for 4.48s before it returns to the thrower.
Initial velocity of the rock, u = 22 m/s
Vertical acceleration of the rock, a(y) = -9.8 m/s²
Vertical displacement, Sy = 0
Applying equations of motion,
Sy = ut + 1/2 a(y)t²
0 = 22t - 4.9t²
Time,
t = 22/4.9
t = 4.48 s
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Attaching the image file here.
18. A European sports car dealer claims that his car will accelerate at a constant rate from rest to 100 km/hr in 8.00 s. If so, what is the acceleration?
a. 3.47 m/s²
b. 6.82 m/s²
c. 11.4 m/s²
d. 17.4 m/s²
Answers
The acceleration of a sports car is (a) 3.47 m/s² when it goes from 0 to 100 km/hr in 8.00 s.
Define acceleration ?
Acceleration is the rate of change of velocity with respect to time. It is a vector quantity, which means that it has both magnitude (a numerical value) and direction (either positive or negative).
First, we need to convert the final velocity from km/hr to m/s, since the SI unit of acceleration is m/s²:
100 km/hr * (1000 m/km) / (60 s/hr) ≈ 27.78 m/s
Using the formula for acceleration, which relates acceleration, final velocity, initial velocity, and time:
acceleration = (final velocity - initial velocity) / time
where initial velocity is 0 since the car starts from rest, we can plug in the values given in the problem:
acceleration = (27.78 m/s - 0 m/s) / 8.00 s ≈ 3.47 m/s²
Therefore, the answer is (a) 3.47 m/s².
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26. The city of Detroit has high unemployment. The automobile industry in Detroit has suffered from global competition and has moved much of the remaining production out of Detroit. The population of the city has fallen from a high of 1,850,000 in 1950 to 701,000 in 2013. Some of the highest crime rates in the United States are now those of Detroit, and huge areas of the city are in a state of severe urban decay. The police force and fire service do not have enough money to pay for staff and equipment such as fully operational vehicles. In 2013, Detroit filed the largest municipal bankruptcy case in U.S. history. How does unemployment affect the income of city? Describe how unemployment might lead city bankruptcy. 7
Answers
In the case of Detroit, the high unemployment rate has led to a decrease in tax revenue, as fewer people are paying income taxes. This has made it difficult for the city to fund essential services such as the police force and fire service. The lack of funding for these services can lead to a decrease in public safety, which can further contribute to the decline of the city.
Unemployment can also lead to a decrease in property values, as people may be unable to pay their mortgages or may be forced to sell their homes due to financial hardship. This can lead to a decrease in property tax revenue for the city.
In the case of Detroit, the decline of the automobile industry and the resulting job loss has led to a decrease in population and a decrease in tax revenue. This has made it difficult for the city to fund essential services, and has contributed to the severe urban decay and high crime rates.
Unemployment can lead to city bankruptcy when the city is unable to meet its financial obligations, such as paying for essential services, pensions, and debt payments. When a city declares bankruptcy, it is unable to borrow money and may be forced to cut essential services or sell off assets to pay its debts.
In the case of Detroit, the high unemployment rate, decrease in population, and resulting decrease in tax revenue made it difficult for the city to meet its financial obligations. The city was unable to pay its debts and was forced to file for bankruptcy in 2013. This has had a significant impact on the city, as it has struggled to recover and provide essential services to its residents.
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The work done by a piston is measured to be 1000 J. If the pressure is a constant 1000 Pa, what is the change in volume of the piston?
Is the process described in #10 isovolumetric? Explain.
Answers
The change in the volume of the piston is 1 m³.
What is the change in volume of the piston?The change in volume of the piston is calculated by applying the first law of thermodynamic as shown below;
W = PΔV
where;
W is the work done by the pistonP is the constant pressure of the pistonΔV is the change in volume of the pistonThe change in the volume of the piston is calculated as follows;
ΔV = W/P
ΔV = 1000 J / 1000 Pa
ΔV = 1 m³
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A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a stretched position. The position of the mass at any time is described by x = (7.8 cm)cos[2t/(3.98 s)]. Determine the following.
(c) first time the mass is at the position
x = 0
(d) first time the mass is at the site of maximum compression of the spring
Answers
Answer:
The frequency of the wave is 4.65 Hz.
The period of the motion is 0.22 s.
The amplitude of the wave is 3.9 cm.
The time when the object reaches 2.6 cm is 0.025 s.
The given parameters;
wave equation,
The frequency of the wave is calculated as follows;
The period of the motion is calculated as follows;
The amplitude of the wave is obtained by comparing the given equation with general wave equation;
Amplitude, A = 3.9 cm
The time when the object reaches 2.6 cm is calculated as follows;
Explanation:
By comparing the preceding equation with the general wave equation, the wave's amplitude is determined to be A = 3.9 cm when the mass is at the location of the spring's greatest compression. 1.2s
What is the straightforward meaning of mass?The quantity of matter of a particle or object is represented by the dimensionless quantity mass (symbolised m). The kilogramme (kg) is the accepted unit of mass on the International System (SI).
How is mass determined?The quantity of matter on an item is its mass. Scientists frequently use balances to quantify mass. Using an electronic balance or a beam balance, one may directly determine the mass of solids.
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20. An x vs. t graph is drawn for a ball moving in one direction. The graph starts at the origin and at t = 5 s the velocity of the ball is zero. We can be positive that at t = 5 s,
a. the slope of the curve is non-zero.
b. the ball has stopped.
c. the acceleration is constant.
d. the curve is at x = 0, 1 = 0.
Answers
We can be positive that at t = 5 s, a. the slope of the curve is non-zero.
How to explain the graphIt should be noted that the graph does not indicate that the ball has stopped, as it only tells us that the velocity of the ball is zero at t=5s. Moreover, the curve is not at x=0,1=0 as this statement is not meaningful.
Therefore, the slope of the curve is non-zero. Since the velocity of the ball is zero at t=5s, the slope of the x vs. t graph must be horizontal at this point. However, it is non-zero because the slope was changing up until t=5s.
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in the figure below, wire AX is folded at back at P such that /AP/ is 40cm and is in parallel with PX which is 60cm long to form a parallel combination. Calculate effective resistance of the parallel combination, if the resistance per unit length of the material if the wire is 2ohms per metre.
Answers
The effective resistance of the parallel combination is 80 ohms.
What is resistance ?Resistance is the ability to oppose or reject something or someone. It is often used to describe the opposition of a force or entity such as an electrical current or a political ideology. In physics, resistance is the measure of an object's opposition to a flow of electric current. Resistance is measured in ohms and is determined by the material, geometry, and temperature of the object in question.
The effective resistance of the parallel combination can be calculated using the following formula: 1/R = 1/R1 + 1/R2Where R1, R2 are the individual resistances.In this case, R1 = 2 ohms/m x 40 cm = 80 ohms, and R2 = 2 ohms/m x 60 cm = 120 ohms.Therefore, 1/R = 1/80 + 1/120 = 0.0125,R = 1/0.0125 = 80 ohms.
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A 2000 kg car moves along a horizontal road
at speed v0 = 19.6 m/s. The road is wet,
so the static friction coefficient between the
tires and the road is only µs = 0.176 and
the kinetic friction coefficient is even lower,
µk = 0.1232.
The acceleration of gravity is 9.8 m/s
2
.
Assume: No aerodynamic forces; g =
9.8 m/s
2
, forward is the positive direction.
What is the highest possible deceleration of
the car under such conditions?
Answer in units of m/s
2
.
Answers
The highest possible deceleration of the car under these conditions is 1.725 m/s².
The maximum deceleration of the car occurs when the force of friction is equal to the maximum force of static friction, which is given by;
fs = µs × N
where N is the normal force, which is equal to the weight of the car, mg;
N = mg = 2000 kg × 9.8 m/s² = 19600 N
So, the maximum force of static friction is;
fs = 0.176 × 19600 N = 3449.6 N
The deceleration of the car is given by;
a = -fs / m
where m is the mass of the car. Substituting the given values, we get;
a = -(0.176 × 19600 N) / 2000 kg = -1.725 m/s²
Therefore, the highest possible deceleration of car is 1.725 m/s².
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Which factors directly affect the magnetic force produced by an electromagnet?
Answers
Answer:
The number of turns of wire wound around the coil, and. The amount of current flowing through the wire
Physics Question: Find The Displacement
A jet is taking off from an aircraft carrier. It starts from rest, speeds up constant acceleration (31 m/s²) and reaches a velocity of 64 m/s. Find the displacement.
Answers
The displacement of the jet of acceleration is 31 m/s² is 7.51 m.
What is displacement?Displacement is defined as the change in position of an object.
To calculate the displacement of the jet, we use the formula below
Formula:
s = (v²-u²)/2a.................. Equation 1Where:
s = Displacement of the jetv = Final speed of the jetu = Initial speed of the jeta = Acceleration of the jetFrom the question,
Given:
v = 64 m/sa = 31 m/s²u = 0 m/s (From rest)Substitute these values into equation 1
s = (31²-0²)/(2×64)s = 961/128s = 7.51 mHence, the displacement is 7.51 m.
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You are going to put your senses to the test by experimenting with taste and smell. These sensory tests are very simple but will require you to have a few grocery items on hand.
Take the onion and cut it in half. Take the apple and cut it into quarters—you're going to eat one of those apple quarters. Now that your onion is cut, hold it to your nose and breathe in. Breathe a few times to get all the onion smell into your olfactory glands—the scent glands. Breathe just a few more times. You want to have the smell of the onion completely saturated into your sense of smell. Continue to hold the onion under your nose. Think of an onion in your mind. Picture it and keep smelling your onion. Take one of the apple quarters and bite into it and chew.
What do you notice?
What does the apple taste like?
Were your senses tricked?
Why were you asked to bite into an apple? Onions and apples have a similar texture and consistency. Biting into an apple while smelling an onion should have given your brain the sense that it was biting into something of onion-like consistency. It's all a ploy to trick your brain into thinking that you'd just taken a bite and were eating an onion.
Answers
When you hold the onion to your nose and breathe in, you will likely smell the pungent and sharp aroma of the onion. As you continue to smell the onion and imagine it in your mind, your brain will start to associate the smell with the taste of an onion.
When you take a bite of the apple quarter, you may initially taste the sweetness of the apple, but because your brain is primed to expect an onion taste, you may notice a slightly onion-like flavor in the apple. Your brain may be tricked into interpreting the apple's texture as being more onion-like, even though the two foods have different textures.
Overall, this experiment plays with the way that our senses of taste and smell work together to create flavor perception. Our brains rely on a combination of taste, smell, and texture to interpret what we're eating, and this experiment shows how our brains can be tricked into expecting a certain flavor based on our sense of smell.
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A kettle of water gets boiled. It takes 3 minutes to boil 1.0 kg of water. A student empties it
and puts in 2.0 kg of water. How long will it take to boil?
Answers
It will take 6 minutes to boil 2 kg of water in the kettle.
The given information states that the kettle takes 3 minutes to boil 1 kg of water. Therefore, to boil 2 kg of water, we can multiply the boiling time of 1 kg water by 2. So, it will take 3 x 2 = 6 minutes to boil 2 kg of water in the kettle.
The reason it takes longer to boil 2 kg of water instead of 1 kg is that more water means more energy is required to raise the temperature to the boiling point. This means that the kettle needs more time to heat up the water to the required temperature.
Therefore, after the student empties the kettle and fills it with 2 kg of water, the boiling process will take 6 minutes.
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The brick wall (of thermal conductivity 1.12 W/m · ◦ C) of a building has dimensions of 6.1 m by 13 m and is 14 cm thick. How much heat flows through the wall in a 14.3 h period when the average inside and outside temperatures are, respectively, 12◦C and 7◦C?
Answer in units of MJ.
Answers
The heat flow through the wall in a 14.3 h period would be approximately 0.491 MJ.
To calculate the heat flow through the wall, we need to use the formula:
Q = (kA×ΔT)t / d
Where Q is the heat flow, k is the thermal conductivity of the wall, A is the area of the wall, ΔT is the temperature difference across the wall, t is the time period, and d is the thickness of the wall.
First, let's calculate the area of the wall:
A = l × h = 6.1 m × 13 m = 79.3 m²
Next, let's calculate the temperature difference across the wall:
ΔT = Ti - To = 12◦C - 7◦C = 5◦C
Now, we can substitute the values into the formula:
Q = (1.12 W/m °C × 79.3 m² × 5°C × 14.3 h) / (0.14 m)
= 491,007.14 J
= 491.00714 kJ
= 0.49100714 MJ
Therefore, the heat flow through the wall in a 14.3 h period is approximately 0.491 MJ.
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a block weighing 15 newtons is on a ramp inclined at 30.0º to the horizon\tal
Answers
The weight of the block (W) is given as 15 N. The angle of inclination of the ramp (θ) is given as 30.0º.
We can use the following equations to find the components of the weight:
W_parallel = W * sin(θ)
W_perpendicular = W * cos(θ)
Substituting the given values, we get:
W_parallel = 15 N * sin(30.0º) = 7.5 N
W_perpendicular = 15 N * cos(30.0º) = 12.99 N
Therefore, the component of the weight that acts parallel to the ramp is 7.5 N and the component that acts perpendicular to the ramp is 12.99 N.
Which example represents a class 2 lever? (1 point)
O salad tongs picking up salad
O tweezers plucking hairs
O a car door being opened and shut
a screwdriver opening a paint can
Answers
The example that represents a class 2 lever is: D. a screwdriver opening a paint can.
Which example represents a class 2 lever?The load is situated in a class 2 lever halfway between the fulcrum and the effort. The screwdriver's resting place against the paint can's rim serves as the fulcrum in this scenario.
The paint can's lid serves as the load, and the force exerted by the hand on the screwdriver's handle serves as the effort. A class 2 lever can be identified by the load being situated between the fulcrum and the effort.
Tweezers, salad tongs, and opening and closing a car door are not examples of class 2 levers. Class 1 levers include things like tweezers and salad tongs, whereas class 3 levers include things like car doors that open and close.
Therefore the correct option is D.
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