Answer: Magnitude of acceleration: 937.5 cm/s^2
Explanation:
To find the magnitude of acceleration at a given displacement in simple harmonic motion, we can use the equation:
a = -ω²x
Where:
a is the acceleration,
ω (omega) is the angular frequency, and
x is the displacement from the equilibrium position.
In this case, we are given the amplitude (A) and the maximum acceleration (a_max). The maximum acceleration is equal to ω²A, so we can rearrange the equation to find ω:
ω = √(a_max / A)
Substituting the given values:
a_max = 100 cm/s²
A = 8.0 cm
ω = √(100 cm/s² / 8.0 cm) = √12.5 rad/s
Now we can find the magnitude of acceleration at a displacement of 6.0 cm:
x = 6.0 cm
a = -ω²x = -(12.5 rad/s)² * (6.0 cm) ≈ -937.5 cm/s²
Therefore, the magnitude of the acceleration at a displacement of 6.0 cm is approximately 937.5 cm/s².
Newton's law of universal gravitation states that the gravitational force exened by an object on any other object anywhere in the universe by Gmm F= where G is the universal gravitational constant (6.67 x 10-11 N.m 2kg 2), ms is mass 1, m2 is mass 2, and r is the distance between the two masses (from conter to contor). If the distance between the two masses doubles, the gravitational force between the two masse O remains the same O is reduced to 1/4. O is reduced to 1/9, O doubles O quadruples.
Answer:
Gravitational force between the two will reduce to [tex](1/4)[/tex] the original value.
Explanation:
The distance between the two objects was originally [tex]r[/tex]. The gravitational force between the two objects would be:
[tex]\displaystyle F = \frac{G\, m_{1}\, m_{2}}{r^{2}}[/tex].
If the distance between the two is doubled, the new distance will become [tex]2\, r[/tex]. The new gravitational force between the two will become:
[tex]\begin{aligned}\frac{G\, m_{1}\, m_{2}}{(2\, r)^{2}} &= \frac{G\, m_{1}\, m_{2}}{4\, r^{2}} = \frac{1}{4}\, \left(\frac{G\, m_{1}\, m_{2}}{r^{2}}\right)\end{aligned}[/tex].
In other words, the force between the two objects will become one-quarter of the initial value.
√√₁ + + Ct². Using dimensional analysis obtain the dimensions and SI units for A, t 3) (5 points) If v = Av² t + B B, and C?
The dimensions and SI units for A, t, and C in the equation v = Av²t + B are:
- A has dimensions of [1]/[L] and its SI unit is 1/meter (1/m).
- t has dimensions of [T] and its SI unit is seconds (s).
To obtain the dimensions and SI units for the variables A, t, and C in the equation v = Av²t + B, we can analyze the equation using dimensional analysis.
The equation is:
v = Av²t + B
Let's assign dimensions and units to each term:
- v has dimensions of velocity, [L]/[T] (length per time), and its SI unit is meter per second (m/s).
- Av²t has dimensions of [A][L]²[T], where [A] represents an unknown dimension and [L] and [T] are length and time dimensions, respectively. The SI unit will depend on the dimensions of A and t.
- B has dimensions of velocity, [L]/[T] (length per time), and its SI unit is also meter per second (m/s).
Equating the dimensions on both sides of the equation, we have:
[L]/[T] = [A][L]²[T] + [L]/[T]
To balance the dimensions, the dimensions of [A] must be [1]/[L] and the dimensions of [t] must be [T].
Therefore, the dimensions and SI units for A, t, and C in the equation v = Av²t + B are:
- A has dimensions of [1]/[L] and its SI unit is 1/meter (1/m).
- t has dimensions of [T] and its SI unit is seconds (s).
- C does not appear in the given equation, so we cannot determine its dimensions or SI units based on the given information.
To know more about dimensional analysis, refer to the link below:
https://brainly.com/question/30303546#
#SPJ11
help ASAP 2i, 2ii, 2iii
2. A surfer is drifting west at 2 m/s. He catches a wave, and it accelerates him north at 6 m/s² for 3 seconds. i. What is the final velocity of the surfer after this acceleration?(8) ii. How far nor
A surfer is drifting west at 2 m/s. He catches a wave, and it accelerates him north at 6 m/s² for 3 seconds.(i)The final velocity of the surfer after the acceleration is 16 m/s northward.(II) The surfer will have traveled 21 meters northward when he stops accelerating.
i. To find the final velocity of the surfer after the acceleration, we can use the formula:
v = u + at
where:
v is the final velocity,u is the initial velocity,a is the acceleration, andt is the time.Given:
Initial velocity (u) = 2 m/s (westward)
Acceleration (a) = 6 m/s² (northward)
Time (t) = 3 seconds
The initial velocity is in the westward direction, so we can consider it as negative. Let's calculate the final velocity (v):
v = u + at
v = -2 m/s + (6 m/s² * 3 s)
v = -2 m/s + 18 m/s
v = 16 m/s (northward)
Therefore, the final velocity of the surfer after the acceleration is 16 m/s northward.
ii. To find the distance traveled northward during the acceleration, we can use the equation:
s = ut + (1/2)at²
where:
s is the distance traveled,
u is the initial velocity,
a is the acceleration, and
t is the time.
Given:
Initial velocity (u) = 2 m/s (westward)
Acceleration (a) = 6 m/s² (northward)
Time (t) = 3 seconds
Since the initial velocity is westward, we can consider it as negative. Let's calculate the distance traveled (s):
s = ut + (1/2)at²
s = -2 m/s * 3 s + (1/2) * 6 m/s² * (3 s)²
s = -6 m + (1/2) * 6 m/s² * 9 s²
s = -6 m + 27 m
s = 21 m (northward)
Therefore, the surfer will have traveled 21 meters northward when he stops accelerating.
To learn more about velocity visit: https://brainly.com/question/80295
#SPJ11
slowly increase the angle of incidence while watching the refracted ray on the viewing screen. at what angle of refraction do you notice the colors separating? at what angle of refraction is the separation of colors a maximum? what colors do you see? (write them in order of increasing angle of refraction.) 3.3: the index of refraction of the plastic cylindrical lens depends on wavelength. choose an angle which gives a good color separation and measure the index of refraction for blue and red light. how big is the
When slowly increasing the angle of incidence while observing the refracted ray on the viewing screen, the colors start to separate when the angle of refraction reaches a certain value. This angle is known as the critical angle. At this critical angle, the separation of colors is maximized.
The specific angle at which the colors start to separate and the angle at which the separation is a maximum depend on the materials involved. This phenomenon is known as dispersion, where different wavelengths of light refract differently, causing the colors to separate. In a typical scenario with air and a glass medium, the critical angle for noticeable color separation is around 42 degrees, and the maximum separation occurs at approximately 90 degrees. The colors that are observed and their order of increasing angle of refraction can be described by the acronym ROYGBIV, which stands for red, orange, yellow, green, blue, indigo, and violet. As the angle of refraction increases, the separation between these colors becomes more pronounced.
Learn more about here:
https://brainly.com/question/13856239
#SPJ11
A color television tube also generates some x rays when its electron beam strikes the screen. What is the shortest wavelength of these x rays, if a 30.0-kV potential is used to accelerate the electrons? (Note that TVs have shielding to prevent these x rays from exposing viewers.)
A color television tube also generates some x rays when its electron beam strikes the screen.he shortest wavelength of the X-rays produced by the color television tube, when a 30.0-kV potential is used to accelerate the electrons, is approximately 2.26 angstroms (Å).
The shortest wavelength of X-rays produced by a color television tube can be determined using the formula for calculating the wavelength of X-rays generated by an accelerating voltage. The formula is given by:
Λ = (12.4 Å)/(√V)
Where:
Λ is the wavelength of the X-rays in angstroms (Å)
V is the accelerating voltage in kilovolts (kV)
Given that the accelerating voltage is 30.0 kV, we can substitute this value into the formula:
Λ = (12.4 Å)/(√30.0 kV)
Calculating the square root of 30.0 kV:
√30.0 kV ≈ 5.48 kV
Substituting this value into the formula:
Λ ≈ (12.4 Å)/(5.48 kV)
Calculating the wavelength:
Λ ≈ 2.26 Å
Therefore, the shortest wavelength of the X-rays produced by the color television tube, when a 30.0-kV potential is used to accelerate the electrons, is approximately 2.26 angstroms (Å).
Learn more about X-rays here:
https://brainly.com/question/2833441
#SPJ11
Two light rays are incident from air into an unknown liquid at
the same point. If θ=25o and
β=37o, find the angle of refraction a? show solution
Two light rays are incident from air into an unknown liquid at the same point. If θ=25degree and β=37degree. The angle of refraction is 143°.
To find the angle of refraction (a) given the incident angle (β) and the refractive index of the unknown liquid, we can use Snell's Law:
n₁ * sin(β) = n₂ * sin(a)
where:
n₁ is the refractive index of air (approximately 1.00),
n₂ is the refractive index of the unknown liquid, and
β and a are the incident and refracted angles, respectively.
Given that β = 37° and θ = 25°, we can substitute these values into Snell's Law:
n₁ * sin(37°) = n₂ * sin(a)
Since the incident angle θ and the refracted angle a are related by the equation θ + a = 180° (or π radians), we can also write:
sin(θ) = sin(180° - a)
Now we can solve these equations simultaneously to find the angle of refraction a.
sin(37°) = sin(180° - a)
Taking the inverse sine of both sides:
37° = 180° - a
a = 180° - 37°
a = 143°
Therefore, the angle of refraction is 143°.
To learn more about refractive index visit: https://brainly.com/question/83184
#SPJ11
using the method of -substitution, where (enter a function of ) (enter a function of ) (enter a number) (enter a number) (enter a function of ).
Explanation of how to solve a problem using the method of substitution. Please provide the problem that you need help with so that I can provide a detailed explanation.
Here is the general process for solving a problem using the method of substitution.
Step 1: Identify the function that can be expressed in terms of the other function.
Step 2: Express one of the variables in terms of the other by rearranging the equation.
Step 3: Substitute the expression for the variable in terms of the other variable into the other equation.
Step 4: Simplify the equation by combining like terms and solve for the remaining variable.
Step 5: Use the value of one of the variables to find the value of the other variable.
Learn more about variables here ;
https://brainly.com/question/15078630
#SPJ11
the north pole of one magnet experiences an attractive force to the north pole of a second magnet. select one: true false
Answer: false
Explanation: Similar poles always repel and only different poles attract (south pole and north pole attract) but (north pole and north pole/ south pole and south pole repel).
what focal length should this camera's lens have for the image of the bridge to cover the entire detector?
To ensure that the image of the bridge covers the entire detector, the camera's lens should have a focal length equal to the diagonal of the detector.
This is known as the focal length of the diagonal.
To ensure that the image of the bridge covers the entire detector, the camera's lens should have a focal length equal to the diagonal of the detector.
This is known as the focal length of the diagonal.
To ensure that the image of the bridge covers the entire detector, the camera's lens should have a focal length equal to the diagonal of the detector.
This is known as the focal length of the diagonal.
Learn more about focal length
brainly.com/question/31755962
#SPJ11
8. [-/1 Points] DETAILS SERCP11 24.4.P.017. MY M A thin layer of liquid methylene lodide (n-1.756) is sandwiched between two flat, parallel plates of glass (n-1.50). What must be the thickne is to be
A thin layer of liquid methylene lodide (n=1.756) is sandwiched between two flat, parallel plates of glass (n=1.50).To ensure strong reflection, the light must be incident at an angle greater than 53.63 degrees with respect to the normal to the interface between the liquid and the glass. Therefore, the thickness of the liquid layer should be chosen such that the angle of incidence exceeds this critical angle.
To achieve strong reflection, we can utilize the phenomenon of total internal reflection. This occurs when light travels from a medium with a higher refractive index to a medium with a lower refractive index and the angle of incidence exceeds the critical angle.
In this case, we have a layer of liquid methylene iodide (n = 1.756) sandwiched between two glass plates (n = 1.50). To maximize reflection, we want to ensure that the light is incident at an angle greater than the critical angle for total internal reflection at the liquid-glass interface.
The critical angle can be calculated using the formula:
Critical angle = arcsin(n2/n1)
Where n1 is the refractive index of the medium from which light is coming (in this case, the liquid) and n2 is the refractive index of the medium in which light is entering (in this case, the glass).
In this scenario:
n1 = 1.756 (methylene iodide)
n2 = 1.50 (glass)
Critical angle = arcsin(1.50/1.756)
Critical angle ≈ 53.63 degrees
To ensure strong reflection, the light must be incident at an angle greater than 53.63 degrees with respect to the normal to the interface between the liquid and the glass. Therefore, the thickness of the liquid layer should be chosen such that the angle of incidence exceeds this critical angle.
To learn more about Critical angle visit: https://brainly.com/question/28406910
#SPJ11
when 6.50 ×105j of heat is added to a gas enclosed in a cylinder fitted with a light frictionless piston maintained at atmospheric pressure, the volume is observed to increase from 1.9 m3 to 4.1 m3 .
Calculate the work done by the gas.
Calculate the change in internal energy of the gas.
Graph this process on a PV diagram.
When 6.50 × 10^5 J of heat is added to a gas in a cylinder with a frictionless piston at atmospheric pressure, gas volume increases from 1.9 m^3 to 4.1 m^3. We need to calculate the work done and change in internal energy.
To calculate the work done by the gas, we can use the equation:
Work = Pressure × Change in Volume.
Given that the pressure is maintained at atmospheric pressure, we can substitute the values:
Work = Atmospheric Pressure × (Final Volume - Initial Volume).
Work = 1 atm × (4.1 m^3 - 1.9 m^3).
Next, we calculate the change in internal energy of the gas using the first law of thermodynamics:
Change in Internal Energy = Heat Added - Work Done.
Given that heat added is 6.50 × 10^5 J and we have already calculated the work done, we can substitute the values:
Change in Internal Energy = 6.50 × 10^5 J - Work Done.
To graph this process on a PV diagram, we plot pressure (P) on the y-axis and volume (V) on the x-axis. We mark the initial point at 1.9 m^3 and atmospheric pressure. Then, we mark the final point at 4.1 m^3 and atmospheric pressure. The process is represented by a straight line connecting these two points.
Learn more about atmospheric pressure here:
https://brainly.com/question/31634228
#SPJ11
A thin rod, 0.77 m long, is pivoted such that it hangs vertically from one end. You want to hit the free end of the rod just hard enough to get the rod to swing all the way up and over the pivot. Part A How fast do you have to make the end go? Express your answer with the appropriate units. Ć ☐☐ μA Value Units V =
The speed needed to make the free end go in order to swing all the way up and over the pivot is 1.98 m/s.
Part A of the given problem asks to calculate the speed needed to make the free end go to swing all the way up and over the pivot. Let the pivot point be P, the center of mass of the rod be C and the free end of the rod be A. The rod will swing over the pivot if the height of the center of mass C becomes zero. Using the law of conservation of energy, the initial potential energy of the rod is converted to the final kinetic energy of the rod. At the highest point, the kinetic energy will become zero and all the potential energy will become zero. Hence, the potential energy at the initial point will be equal to the potential energy at the highest point: mg(0.77) = (1/2)(0.20)v²Solving this equation, we get: v = 1.98 m/s Therefore, the speed needed to make the free end go in order to swing all the way up and over the pivot is 1.98 m/s.
The term "speed" means. The rate at which an object moves in any direction. The ratio of distance to time traveled is what is used to measure speed. Because it only has a direction and no magnitude, speed is a scalar quantity.
Know more about speed, here:
https://brainly.com/question/17661499
#SPJ11
Two resistors, 20 ohms and 30 ohms, are connected in parallel. This combination is connected in a series to an 8 ohms resistor and a battery of e.m.f. 12 volts. What is the current along 20 ohms?
Ohm's law is a fundamental principle in physics and electrical engineering that relates the current flowing through a conductor to the voltage applied across it. It states that the current (I) passing through a conductor is directly proportional to the voltage (V) across the conductor, and inversely proportional to the resistance (R) of the conductor.
The current along 20 ohms in a circuit with two resistors, 20 ohms and 30 ohms, which are connected in parallel, and this combination is connected in a series to an 8 ohms resistor and a battery of e.m.f. 12 volts can be calculated as follows: The equivalent resistance for the two resistors connected in parallel by using the formula 1/Rt = 1/R1 + 1/R2, where R1 and R2 are the resistors in parallel.1/Rt = 1/20 + 1/30 = 3/60 + 2/60 = 5/60Rt = 60/5 = 12 ohms.
The equivalent resistance of the two parallel resistors is 12 ohms.
Now, calculate the total resistance of the circuit by adding the equivalent resistance of the parallel resistors and the 8 ohms resistor.
Rtotal = 12 + 8 = 20 ohmsThe total resistance of the circuit is 20 ohms.
Finally, calculate the current along the 20 ohms resistor using Ohm's law, which states that I = V/R, where V is the voltage of the battery and R is the resistance. I = V/R = 12/20 = 0.6 A.
The current along the 20 ohms resistor is 0.6 A.
Learn more about resistor here ;
https://brainly.com/question/30672175
#SPJ11
What is the strength of the electric field of a point charge of magnitude +6.4 x
10-19 C at a distance of 4.0 x 10-3 m?
k= 9.00 x 10°N•m²/C²)
A. -3.6 x 104 N/C
B. 3.6 x 10-4 N/C
C. 2.7 x 104 N/C
D. -2.7 x 10-4 N/C
The strength of the electric field of a point charge of magnitude is A, 3.6 × 10⁴ N/C.
How to determine strength?The strength of the electric field of a point charge is given by the formula:
E = kq/r²
Where:
k = Coulomb constant, 9.00 × 10⁹ N⋅m²/C²
q = charge, 6.4 × 10⁻¹⁹ C
r = distance, 4.0 × 10⁻³ m
Plugging in the values:
E = [(9.00 × 10⁹ N⋅m²/C²)(6.4 × 10⁻¹⁹ C)] / (4.0×10⁻³ m)²
= 3.6 × 10⁴ N/C
Therefore, the strength of the electric field is 3.6 × 10⁴ N/C.
Find out more on electric field strength here: https://brainly.com/question/26199225
#SPJ1
2. what kind of texting would we use to finding missing check numbers? what type of texting should be used to see if some checks were double counted
In accounting, it is important to keep track of every check number to ensure that there are no errors in transactions. Suppose there are missing check numbers or double-counted checks. In that case, certain types of texting should be used to resolve these accounting issues
Therefore, here's the type of texting that can be used to find missing check numbers and double-counted checks:1. Finding missing check numbers:
To locate the missing check numbers, you can use an enquiry letter to the bank to inquire about the missing check. A letter of enquiry can be mailed to the bank, requesting a copy of the missing check or to verify if the check was cashed. This type of texting is ideal for tracking down missing checks.
2. Double-counted check: A double-counted check occurs when a check is entered twice in the cash book. One way to verify that a check has been entered twice is to review the cash book or bank statement. Reconciling the cash book with the bank statement is a method that can be used to verify that the check was double-counted. This type of texting is ideal for tracking down double-counted checks.
In conclusion, while texting methods are not widely used in accounting, letters of enquiry to the bank are useful in finding missing check numbers. The process of reconciling the cash book with the bank statement is ideal for tracking down double-counted checks.
To learn more about accounting visit;
https://brainly.com/question/5640110
#SPJ11
DUE IN 30 MINUTES, THANK YOUUUUU
1 Which has the LEAST momentum?
Group of answer choices
a 2 kg ball moving at 8 m/s
a 750 g ball moving at 15 m/s
a 80 kg ball moving at 25m/s
a 12 kg ball moving at 1
A 750 g ball moving at 15 m/s will have the least momentum.
The momentum can be defined as the product of mass and velocity. It is a vector quantity that shows how difficult it is
to stop a moving object. The momentum of an object depends on two factors, mass and velocity. The least momentum
will have the object with the least mass and velocity. Therefore, a 750 g ball moving at 15 m/s will have the least
momentum. The momentum can be calculated as follows: p = m × v where, p is momentum, m is mass and v is
velocity. We have given that; a 2 kg ball moving at 8 m/s, p = 2 kg × 8 m/s = 16 kgm/s .A 750 g ball moving at 15 m/s, p =
0.75 kg × 15 m/s = 11.25 kgm/s. A 80 kg ball moving at 25m/s, p = 80 kg × 25 m/s = 2000 kgm/s .A 12 kg ball moving at
1 m/s, p = 12 kg × 1 m/s = 12 kgm/s. The momentum of the 750 g ball moving at 15 m/s is 11.25 kgm/s. Therefore, the
least momentum will be for a 750 g ball moving at 15 m/s.
Learn more about momentum:https://brainly.com/question/30337879
#SPJ11
geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s2 and finds that it takes 7.05 s for 16.0 complete cycles. Calculate the length of the pendulum.
The length of the pendulum is 0.44338 m.
Acceleration due to gravity, g = 9.80 m/s2, Number of oscillations, n = 16, Time taken, t = 7.05 s.
Let l be the length of the pendulum. Now, one complete oscillation means when the pendulum starts from its extreme position (i.e., extreme position A), moves to the other extreme position (i.e., extreme position B), and returns back to position A.
Let’s calculate the time taken by the pendulum to complete one oscillation, i.e., the time period of the pendulum.t1 = time taken for 1 oscillation.
t1 = t/n = 7.05/16.0=0.44125 s
Now, the time period is given by, T=2π √(l/g) Where T is the time period of the pendulum. π = 3.1415 (approx)
Putting the given values of g and T in the above equation,
T = 2π √(l/g) = 2 x 3.1415 √(l/9.80)
Now, substituting T1 in the above equation, we get:
0.44125 = 2 x 3.1415 √(l/9.80)√(l/9.80)
= 0.44125/(2π)
= 0.07010049l
= (√(0.07010049 × 9.80))2l = 0.44338 m
To know more about pendulum visit:
https://brainly.com/question/29268528
#SPJ11
a quiet sound is produced by a loud speaker. loudness of the sound is increased. which property of the sound is increased?
Answer:amplitude
Explanation:
1.
Occupations that produce "work"
Babysitter
Banker
Orange picker
Cake decorator
Delivery driver
Lumberjack
Weatherman
Moving man
Truck driver
Receptionist
Fisherman
Rabbi
Carpet installer
Bricklayer
The occupations which are listed and involved some form of work are Orange picker, Delivery driver, Lumberjack, Moving man and Truck driver.
In physics, the concept of "work" has a specific definition that relates to the transfer of energy. Occupations that involve physical tasks and the transfer of energy can be considered as producing work in the context of physics. Here are some occupations from the list that can be associated with work in physics:
1. Orange picker: This occupation involves physical labor to pick oranges, which requires exerting force and doing mechanical work against gravity.
2. Delivery driver: Delivery drivers perform work when they lift and carry packages, loading and unloading them from vehicles, which involves applying force over a distance.
3. Lumberjack: Lumberjacks engage in physically demanding work, such as cutting down trees and splitting wood, which requires the application of force and energy.
4. Moving man: Moving professionals lift and transport heavy furniture and boxes, which involves doing work against gravity and overcoming the resistance of objects.
5. Truck driver: While driving itself may not involve work in the physics sense, truck drivers may perform physical tasks like loading and unloading cargo, which can involve exerting force and doing work.
for more questions on work
https://brainly.com/question/25573309
#SPJ8
Question 8 A 2.7 m long string vibrates as a three loop standing wave. The amplitude is 0.98 cm and wave speed is 90 m/s. Part A Find the frequency of the vibration. μA ? f= Value Submit Provide Feed
The frequency of the vibration is approximately 50 Hz, calculated using the formula v = fλ, where v is the wave speed and λ is the wavelength determined by the length of the string and the number of loops.
In a standing wave, the length of the string can be related to the wavelength of the wave by the equation:
λ = 2L/n,
where λ is the wavelength, L is the length of the string, and n is the number of loops.
In this case, the length of the string L is given as 2.7 m, and the number of loops n is 3. Plugging in these values, we can solve for the wavelength:
λ = 2(2.7 m)/3
λ = 1.8 m.
The wave speed v is given as 90 m/s. The frequency f can be calculated using the formula:
v = fλ.
Rearranging the equation, we have:
f = v/λ = 90 m/s / 1.8 m
f = 50 Hz.
Therefore, the frequency of the vibration is approximately 50 Hz.
The frequency of the vibration is approximately 50 Hz, calculated using the formula v = fλ, where v is the wave speed and λ is the wavelength determined by the length of the string and the number of loops.
To know more about frequency visit:
https://brainly.com/question/29213586
#SPJ11
0 A 35 700 B 2885 C 5155 3 S 9 6371 km 30-65 km 2885 km 2270 km 1216 km
QUESTION 44 From the diagram the outer core (#5) is a; A. liquid B. solid C. gas D. plasma
The answer to the question is liquid.
The earth has various layers, and the outer core is the second layer from the earth's center, located between the mantle and the earth's inner core. The outer core is a liquid layer made up of molten iron and nickel, and it is responsible for producing the earth's magnetic field.
According to scientists, the earth's outer core is a liquid layer made up of molten iron and nickel, and it is responsible for producing the earth's magnetic field.
The outer core is about 2,300 kilometers thick and is located between the earth's mantle and the inner core. The temperature in the outer core ranges from 4,000 to 5,000 degrees Celsius, and the pressure is about 1.3 million times that of the earth's surface.
The outer core is liquid due to the high temperatures and pressure that exist there. The liquid outer core moves as it produces the earth's magnetic field, which is essential to life on earth.
Learn more about pressure
brainly.com/question/30673967
#SPJ11
A cannon fires a cannonball with an initial velocity of 300 m/s at 54.5° above the horizontal. The cannonball impacts a raised plateau 42.0 s after firing. Let the +x-direction be directly ahead of the cannon and the +y-direction be upward. Find the x- and y-coordinates of the cannonball's impact point, relative to its firing point (in m). X = m y = m Need Help? Read It
Given data Initial velocity, u = 300 m/s Angle of projection, θ = 54.5°Time of flight, t = 42 s For projectile motion, we have the following kinematic equation s:u_x = u cos θu_y = u sin θx = u_x t + (1/2) a_x t^2y = u_y t + (1/2) a_y t^2u_x is the horizontal component of the initial velocity of the projectile, and u_y is the vertical component of the initial velocity of the projectile. a_x is the horizontal component of the acceleration of the projectile, and a_y is the vertical component of the acceleration of the projectile.
We can find u_x and u_y using trigonometric ratios. u_x = u cos θ = (300 m/s) cos 54.5° = 172.7 m/su_y = u sin θ = (300 m/s) sin 54.5° = 247.7 m/sa_x = 0 (assuming no air resistance) a_y = - g = - 9.81 m/s^2 (taking downward direction as positive) From the equation of motion in y direction, we have y = u_y t + (1/2) a_y t^2 ⇒ y = 247.7 m/s × 42 s + (1/2) (- 9.81 m/s^2) (42 s)^2⇒ y = 10470.6 m
The maximum height reached by the projectile = H = u_y^2 / (2 a_y) = (247.7 m/s)^2 / (2 × 9.81 m/s^2) = 3139.4 mWe can also find the horizontal distance traveled by the projectile using the equation of motion in x direction:x = u_x t = 172.7 m/s × 42 s = 7253.4 m Therefore, the x-coordinate of the impact point is 7253.4 m, and the y-coordinate of the impact point is 10470.6 m. Thus, the coordinates of the impact point are:X = 7253.4 mY = 10470.6 m.
Know more about initial velocity:
https://brainly.com/question/28395671
#SPJ11
To find the x- and y-coordinates of the cannonball's impact point, we need to break down the initial velocity into its x and y components. The x-coordinate is found using the equation Vx = V * cos(θ), and the y-coordinate is found using the equation y = Vy * t + (1/2) * a * t^2. Plugging in the given values, the x-coordinate is 7587.9 m and the y-coordinate is 10049.4 m, relative to the firing point.
Explanation:To find the x- and y-coordinates of the cannonball's impact point, we need to break down the initial velocity into its x and y components. The component in the x-direction is given by the equation Vx = V * cos(θ), where V is the initial velocity and θ is the angle of firing. Plugging in the given values, we get Vx = 300 * cos(54.5°) = 300 * 0.60182 = 180.546 m/s.
Next, we need to find the time it takes for the cannonball to reach the impact point. Since the cannonball was fired horizontally in the x-direction, the time of flight can be found using the equation t = d / Vx, where d is the horizontal displacement. Rearranging this equation to solve for d, we have d = t * Vx. Plugging in the given values, we get d = 42.0 s * 180.546 m/s = 7587.9 m.
The y-component of the velocity is given by the equation Vy = V * sin(θ), so Vy = 300 * sin(54.5°) = 300 * 0.79862 = 239.586 m/s. The vertical displacement can be found using the equation y = Vy * t + (1/2) * a * t^2, where a is the acceleration due to gravity (-9.8 m/s^2) and t is the time of flight. Plugging in the given values, we get y = 239.586 m/s * 42.0 s + (1/2) * (-9.8 m/s^2) * (42.0 s)^2 = 10049.4 m.
Therefore, the x-coordinate of the impact point is 7587.9 m and the y-coordinate is 10049.4 m, relative to the firing point.
Learn more about Projectile Motion here:https://brainly.com/question/20627626
#SPJ2
In which one of the following lists are different types of electromagnetic waves ranked in order of increasing wavelength? a. X-rays, gamma rays, visible light, radio waves b. Visible light, radio waves, gamma rays, x-rays c. Gamma rays, x-rays, visible light, radio waves d. Gamma rays, x-rays, radio waves, visible light
Electromagnetic rays ranked in order of increasing wavelength are:
c. Gamma rays < X-rays < Visible light < Radio Waves
Electromagnetic waves are generated when an electric field comes in contact with magnetic field. They represent a family of waves showing similar properties.
Gamma rays have the shortest wavelength, ranging between 10⁻¹¹ to 10⁻¹³m while Radio rays have the longest wavelength, ranging from 10³ to 10⁻¹m
Read more about electromagnetic waves:
https://brainly.com/question/29774932?referrer=searchResults
1.0 mol of an ideal gas starts at 1.0 atm and 77F and does 1.0
kJ of work during an adiabatic expansion. Calculate the final
volume of the gas. Express your answer in litres. In your
calculation, f
The volume of 1.0 mol of an ideal gas starting at 1.0 atm and 77°F is 24.4 L.
The volume of 1.0 mol of an ideal gas starting at 1.0 atm and 77°F can be calculated using the ideal gas law equation: PV = nRT where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
Using the given values of P = 1.0 atm, T = 77°F = 298.15 K, and n = 1.0 mol, we can rearrange the equation to solve for V:V = nRT/P = (1.0 mol)(0.08206 L·atm/(mol·K))(298.15 K)/(1.0 atm) = 24.4 L
So the volume of 1.0 mol of an ideal gas starting at 1.0 atm and 77°F is 24.4 L.
Know more about ideal gas law here:
https://brainly.com/question/12624936
#SPJ11
10. If an electrical appliance becomes live, the appliance
A) stops working and is safe to touch
B) continues working and is safe to touch
(C) continues working and is dangerous to touch
D) Is safe to touch because of the fuse.
Answer:
C
Explanation:
If an electrical appliance becomes alive, the appliance continues working and is dangerous to touch
A body on the surface of the earth weichs 400 Ib. The radius of the earth is about 4,000 miles. If this same body were placed on a 4,000 mile high tower, its weight would be a. 100 lbs b. 200 lbs c. 400 lbs d. 800 lbs e. 16,000 lbs
Option a is correct.
F=GMm/R²
where F is the gravitational force or weight
G is the universal constant of gravitation
M is the mass of Earth
m is the mass of the object
R is the distance between the center of the earth and the object
Given,
initial distance R =4000miles
weight at surface of the earth F=400lb
Let the force be F' for a distance R' from earth's center.
Here R' = radius+ height of the tower = R+4000 miles = 4000 + 4000 = 8000 miles.
Since the other terms in the formula remain constant, the new weight F' can be calculated as follows:
F'/F = R²/R'(otherwise the inverse square law in gravitation)
F'/400=(4000)²/(8000)²
F' = 100 lb
Thus option a is correct.
For more information about the inverse square law in , visit
https://brainly.com/question/30556863?referrer=searchResults
The weight of the body on a 4000-mile high tower would still be 400 lbs.
Explanation:The weight of an object depends on the gravitational acceleration at its location. On the surface of the Earth, the gravitational acceleration is approximately 32 ft/s2. Therefore, a 400 lb body on the Earth's surface would weigh 400 lbs. If the body were placed on a 4000-mile high tower, it would be much farther from the center of the Earth and experience a weaker gravitational pull. The weight of the body would decrease as the square of the ratio of the radii of the tower and the Earth. So, the weight on the tower would be:
Weight on the tower = (400 lb) * (4000 mi/4000 mi)2 = 400 lb * 1 = 400 lb
Learn more about Gravity here:https://brainly.com/question/35699425
#SPJ6
a substance has a volume of 10.0 cm3 and a mass of 89 grams. what is its density? 8.9 g/cm 3 99 g/cm 3 0.11 g/cm 3 79 g/cm 3
The density of the given substance is 8.9 g/cm³. The given substance has a volume of 10.0 cm³ and a mass of 89 grams.
We are to find the density of the given substance. The formula for density is:density = mass/volumeWe can now substitute the given values into the formula and get: density = mass/volume=>density = 89 g/10.0 cm³We simplify this expression as shown below: density = 8.9 g/cm³
Therefore, the density of the substance is 8.9 g/cm³.The response to this question has used only 100 words. To give a more detailed response, we can provide the following explanation:Explanation:When we want to find the density of a substance, we need to know its mass and volume. Density is the ratio of the mass of a substance to its volume, and it is expressed in grams per cubic centimeter (g/cm³).
The formula for density is: density = mass/volume Where density is in g/cm³, mass is in grams (g), and volume is in cubic centimeters (cm³).To find the density of the given substance, we have been given its mass and volume. We simply substitute these values into the formula and simplify to get the density. Therefore, the density of the given substance is 8.9 g/cm³.
To learn more about volume visit;
https://brainly.com/question/28058531
#SPJ11
if the cg of an aircraft is moved from the aft limit to beyond the forward limit, how will it affect the cruising and stalling speed?
When the center of gravity (CG) of an aircraft is moved from the aft limit to beyond the forward limit, it will affect the cruising and stalling speed as follow
When the center of gravity (CG) is moved from the aft limit to beyond the forward limit, the aircraft will become more unstable. The weight of the aircraft is mostly at the forward end and the tail portion becomes lighter. As a result, it will cause the aircraft to pitch down and result in difficulty in controlling the airplane.
This shift in CG to the forward limit will decrease the cruising speed of the aircraft as it requires more power to maintain the required altitude and speed. Also, the stalling speed of the aircraft will be lower, which means that the aircraft will stall at a lower speed.
This is because the forward limit shifts the neutral point behind the center of gravity, making the aircraft more unstable and reducing the speed at which the airplane stalls. As the CG shifts forward, the margin between the stall speed and the maximum operating speed reduces, making it more difficult to recover from a stall.
Learn more about center of gravity (CG)
brainly.com/question/27182554
#SPJ11
Red light with a wavelength of 725 nm enters glass with index of refraction 1.52.Located within the glass block is a single slit.and a screen is placed 1.25 m away.If the width of the slit is 18.5m.find the width of the central maximum (a) in degrees and (b) in centimeters. 5. A soap film in air has a thickness of 175 nm.If the index of refraction of the soap film is 1.35,what colour of light will be transmitted through?(i.e.,What colour does the bubble appear to be from the other side?
4. Red light with a wavelength of 725 nm enters glass with index of refraction 1.52.Located within the glass block is a single slit.and a screen is placed 1.25 m away.If the width of the slit is 18.5m (a)The width of the central maximum is approximately 0.275°.(b)The width of the central maximum is approximately 6.052 × 10^(-6) cm.(5)In this case, the wavelength falls within the range of green light, so the soap bubble will appear green from the other side
(4) To calculate the width of the central maximum, we can use the formula:
Width of central maximum = (wavelength * distance to screen) / (slit width * index of refraction)
Given:
Wavelength of red light (λ) = 725 nm = 725 × 10^(-9) m
Distance to screen (D) = 1.25 m
Slit width (w) = 18.5 μm = 18.5 × 10^(-6) m
Index of refraction (n) = 1.52
(a) Width of central maximum in degrees:
To convert the width to degrees, we can use the small angle approximation:
Width in degrees ≈ (Width of central maximum / Distance to screen) * (180° / π)
Substituting the values into the formula:
Width of central maximum = (725 × 10^(-9) m * 1.25 m) / (18.5 × 10^(-6) m * 1.52) ≈ 6.052 × 10^(-4) m
Width in degrees ≈ (6.052 × 10^(-4) m / 1.25 m) * (180° / π) ≈ 0.275°
So, the width of the central maximum is approximately 0.275°.
(b) Width of central maximum in centimeters:
To convert the width to centimeters, we can simply divide by 100:
Width in centimeters = (Width of central maximum) / 100 ≈ 6.052 × 10^(-4) m / 100 ≈ 6.052 × 10^(-6) cm
So, the width of the central maximum is approximately 6.052 × 10^(-6) cm.
(5) To determine the color of light transmitted through the soap film, we need to consider the interference of light waves. When light reflects off the top and bottom surfaces of the film, interference occurs. Depending on the thickness of the film and the wavelength of light, certain colors will be enhanced or canceled out.
Given:
Thickness of soap film (d) = 175 nm = 175 × 10^(-9) m
Index of refraction of soap film (n) = 1.35
To find the color of light transmitted, we can use the equation:
2 * n * d = m * λ
where:
m is the order of the interference (m = 1 for the first-order maximum)
λ is the wavelength of light
Rearranging the equation to solve for λ:
λ = (2 * n * d) / m
Substituting the values:
λ = (2 * 1.35 * 175 × 10^(-9) m) / 1
λ ≈ 4.73 × 10^(-7) m
The wavelength of light transmitted is approximately 4.73 × 10^(-7) m.
By comparing the wavelength to the visible light spectrum, we can determine the corresponding color. In this case, the wavelength falls within the range of green light, so the soap bubble will appear green from the other side.
To learn more about Width of central maximum visit: https://brainly.com/question/28555914
#SPJ11
A 52 kg skateboarder is standing on the edge of a 35 m tall half-pipe.
How much energy will the skateboarder have when he drops in the pipe?
What will his kinetic energy be when he reaches the bottom?
Calculate his speed using the energy from the question above.
Answer:
The speed I got is 26.2m/s (3sf)
Explanation:
When the skateboarder is standing at the edge of the half-pipe, they would have max gravitational potential energy of about 17800J (3sf), calculated by using this formula;
Gravitational potential energy (Eₚ) = mgh
Eₚ = 52 × 9.8 × 35
Eₚ = 17836J
Eₚ = 17800J (3sf)
As the skateboarder drops, this energy will also decrease because they are losing height and gets converted into kinetic energy. Hence, the kinetic energy increases. When they reach the bottom (assuming they haven't landed and stop moving), the skateboarder will reach max kinetic energy.
To calculate the speed from this energy, we can use this formula;
Eₖ = 1/2 × m × v²
Substitute the values;
17800 = 1/2 × 52 × v²
17800 = 26 × v²
v² = 17800/26
v = √684.6
v = 26.2m/s (3sf)
