Answer:
The bus travels at 33 miles per hour while the motorcycle travels at 31 miles per hour
Step-by-step explanation:
Represent the bus average speed with x and the motorcycle average speed with y
Given
[tex]x = y + 2[/tex]
Distance covered by bus = 165 miles
Distance covered by motorcycle in same time = 155 miles
Required
Determine the speed of each
Average Speed is calculated as;
[tex]Average\ Speed = \frac{Distance}{Time}[/tex]
Since the two are measured with the same time, represent time with T
For the bus
[tex]Average\ Speed = \frac{Distance}{Time}[/tex] becomes
[tex]x = \frac{165}{T}[/tex]
Make T the subject of formula
[tex]T = \frac{165}{x}[/tex]
For the motorcycle
[tex]y = \frac{155}{T}[/tex]
Make T the subject of formula
[tex]T = \frac{155}{y}[/tex]
Since, T = T; we have that
[tex]\frac{165}{x} = \frac{155}{y}[/tex]
Cross Multiply
[tex]165y = 155x[/tex]
Substitute [tex]x = y + 2[/tex]
[tex]165y = 155(y+2)[/tex]
Open Bracket
[tex]165y = 155y - 310[/tex]
Collect Like Terms
[tex]165y - 155y = 310[/tex]
[tex]10y = 310[/tex]
Divide both sides by 10
[tex]y = 31[/tex]
Recall that [tex]x = y + 2[/tex]
[tex]x = 31 +2[/tex]
[tex]x = 33[/tex]
Hence;
The bus travels at 33 miles per hour while the motorcycle travels at 31 miles per hour
Find the surface area of the regular pyramid shown in the accompanying diagram. If necessary, express your answer in simplest radical form.
Answer:
The area of the pyramid is 360 unit²
Step-by-step explanation:
Given
Base Edge, a = 10
Height, h = 12
Required
Determine the surface area
The surface area of a regular pyramid is calculated as thus;
[tex]A = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}[/tex]
Substitute values for a and h
[tex]A = 10^2 + 2 * 10 * \sqrt{\frac{10^2}{4} + 12^2}[/tex]
Evaluate all squares
[tex]A = 100 + 2 * 10 * \sqrt{\frac{100}{4} + 144}[/tex]
[tex]A = 100 + 2 * 10 * \sqrt{25 + 144}[/tex]
[tex]A = 100 + 2 * 10 * \sqrt{169}[/tex]
Take positive square root of 169
[tex]A = 100 + 2 * 10 * 13[/tex]
[tex]A = 100 + 260[/tex]
[tex]A = 360[/tex]
Hence, the area of the pyramid is 360 unit²
Answer:
B.) 360 units2
Step-by-step explanation:
I got it correct on founders education
A circle has a radius of 7 inches. What is the area of the circle?
A. 21.98 in^2
B. 43.96 in^2
C. 153.86 in^2
D. 615.44 in^2
Please include ALL work! <3
Answer:
C. 153.86 in^2[tex]area = \pi {r}^{2} \\ r = 7 \\ a = \frac{22}{7} \times {7}^{2} [/tex]
[tex]a = \frac{22}{7} \times 49 \\ a = 22 \times 7 = 154 {cm}^{2} [/tex]
Step-by-step explanation:
[tex]area = \pi {r}^{2} \\ a \: = 3.14 \times {7}^{2} \\ a \: = 3.14 \times 49 = 153.86 {cm}^{2} [/tex]
Answer:
C. 153.86 in^2
Step-by-step explanation:
The area of a circle can be found using the following formula.
[tex]a=\pi r^2[/tex]
where r is the radius.
We know the radius is 7 inches. Therefore, we can substitute 7 in for r.
[tex]r= 7 in[/tex]
[tex]a=\pi (7 in)^2[/tex]
Evaluate the exponent.
(7 in)^2= 7 in * 7 in= 49 in^2
[tex]a= \pi * 49 in^2[/tex]
Let's use 3.14 for pi.
[tex]a= 3.14 * 49 in^2[/tex]
Multiply 3.14 and 49
3.14 * 49=153.86
[tex]a= 153.86 in^2[/tex]
The area of the circle is 153.86 square inches. Therefore, C is the correct answer.
graph the linear equation using the slope and y-intercept y=1/9x+5
Answer:
Slope= 1/9
Y-Intercept= 5
A lottery exists where balls numbered 1 to "20" are placed in an urn. To win, you must match the balls chosen in the correct order. How many possible outcomes are there for this game?
Answer: 1860480
Step-by-step explanation:
Initially, there are 20 balls where 5 must be chosen in order.
The number of possible outcomes may be calculated using the concept of permutations.
The formula for permutations is:
nPr =n!/(n−r)!
where n represents the number of items and r represents the number of items to be selected.
The number of ways of selecting 5 balls in order out of 20 is:
20P5 = 20!/15!
= 1860480
To conclude, there are 1860480 possible outcomes.
Determine that 4/16 and 5/20 forms as proportional relationship.
Answer:
Those two are 0.25
4/16 = 1/4
5/20 = 1/4
Answer: Please Give Me Brainliest, Thank You!
4/16 = 5/20 = 1/4
Step-by-step explanation:
Because If you divide 4 and 16 by 4 you get 1/4 and if you divide 5 and 20 with 5 you get 1/4
You buy butter for $5.60 a pound. One portion of onion compote requires 1.7 oz of butter. How much does the butter for one portion cost? Round to the nearest cent.
Answer:
Butter per portion equals 60 cents .
Step-by-step explanation:
A pound of butter is worth $ 5.60.
5.60 dollars are converted to cents, 1 dollar equals 100 cents, then:
- One pound of butter equals 560 cents.
A portion of onion compote requires 1.7 oz of butter.
Convert 1.7 oz to pounds, so:
- 1.7 oz of butter equals 0.10625 pounds.
If a pound of butter is worth 560 cents, how much will 0.10625 pounds of butter be worth.
- Rule of 3 is used:
- 560 cents 1 pound butter
X cents 0.10625 pounds of butters
X = 560 * 0.10625
X = 59.5 cents
X = 60 cents per portion
As you wake up to get your day started, you decide to make muffins for breakfast. The recipe you are
using makes 2 dozen muffins and calls for 3 cups of flour and 1 cup of sugar. You decide to only make
18 muffins. How many cups of flour and sugar will you need for your recipe?
The above problem can easily be solved using a proportion. Show your work
Answer:
4 cups of flour is needed and 4/3 cups of sugar
Step-by-step explanation:
Given
2 dozen Muffins; 3 cups of flour and 1 cup of sugar
Required
Determine the cups of flour if 18 muffins is used
First, we have to determine the proportion of the number of muffins used previously and now;
Represent this with p;
[tex]p = \frac{2\ dozen}{18}[/tex]
[tex]p = \frac{2 * 12}{18}[/tex]
[tex]p = \frac{24}{18}[/tex]
[tex]p = \frac{4}{3}[/tex]
Multiply this to the previous cups of flours and sugars;
Cups of flour = p * previous cups of flour
[tex]Cups\ of\ flour = \frac{4}{3} * 3[/tex]
[tex]Cups\ of\ flour = 4[/tex]
Cups of Sugar = p * previous cups of sugar
[tex]Cups\ of\ sugar= \frac{4}{3} * 1[/tex]
[tex]Cups\ of\ sugar= \frac{4}{3}[/tex]
Hence, 4 cups of flour is needed and 4/3 cups of sugar
Transform the given parametric equations into rectangular form. Then identify the conic. x= -3cos(t) y= 4sin(t)
Answer:
Solution : Option D
Step-by-step explanation:
The first thing we want to do here is isolate the cos(t) and sin(t) for both the equations --- ( 1 )
x = - 3cos(t) ⇒ x / - 3 = cos(t)
y = 4sin(t) ⇒ y / 4 = sin(t)
Let's square both equations now. Remember that cos²t + sin²t = 1. Therefore, we can now add both equations after squaring them --- ( 2 )
( x / - 3 )² = cos²(t)
+ ( y / 4 )² = sin²(t)
_____________
x² / 9 + y² / 16 = 1
Remember that addition indicates that the conic will be an ellipse. Therefore your solution is option d.
What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300
Answer:
Option B.
Step-by-step explanation:
Let as consider the given equation:
[tex]2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30[/tex]
It can be written as
[tex]2(\ln 2x)-(\ln 10x)=\ln 30[/tex] [tex][\because \ln e^a=a][/tex]
[tex]\ln (2x)^2-(\ln 10x)=\ln 30[/tex] [tex][\because \ln a^b=b\ln a][/tex]
[tex]\ln \dfrac{4x^2}{10x}=\ln 30[/tex] [tex][\because \ln \dfrac{a}{b}=\ln a-\ln b][/tex]
[tex]\ln \dfrac{2x}{5}=\ln 30[/tex]
On comparing both sides, we get
[tex]\dfrac{2x}{5}=30[/tex]
Multiply both sides by 5.
[tex]2x=150[/tex]
Divide both sides by 2.
[tex]x=75[/tex]
Therefore, the correct option is B.
Answer:
b x=75
Step-by-step explanation:
Given the following computer printout for a set of sample data, which one of the following represents the value of the Interquartile Range?
Descriptive Statistics: Cycle Time
Variable N Mean StDev Variance Minimum Q1 Median Q3 Maximum
Cycle Time 52 31.808 5.333 28.436 21.700 27.825 31.000 36.075 44.000
A. 22.3
B. 3.175
C. 5.075
D. 8.25
Answer: D. 8.25
Step-by-step explanation: A data set can be divided into 4 equal parts, called Quartile. A quartile divides the data into three points:
Lower quartile: Q1;Median: Q2;Upper quartile: Q3;Interquartile Range (IQR) is a measure of variability based on data divided into quartiles or the measure of where the bulk of the values are.
To calculate interquartile range:
IQR = Q3 - Q1
The table shows Q1 = 27.825 and Q3 = 36.075, then
IQR = 36.075 - 27.825
IQR = 8.25
The value of interquartile range is 8.25.
5(y–3.8)=4.7(y–4) help help
Answer:
y = 2/3 or 0.667Step-by-step explanation:
5(y–3.8)=4.7(y–4)
Expand the terms in the bracket
That's
5y - 19 = 4.7y - 18.8
Group like terms
5y - 4.7y = 19 - 18.8
0.3y = 0.2
Divide both sides by 0.3
We have the final answer as
y = 2/3 or 0.667Hope this helps you
I need help ASAP THANK YOU
Answer:
174 cm²
Step-by-step explanation:
The figure given is a prism with isosceles trapezoid as base.
Its surface area can be calculating the area of each face that makes up the prism, and summing all together.
There are 6 faces. Their dimensions and areas can be calculated as follows:
2 isosceles trapezium:
It has 2 parallel bases, (a and b), of 4cm and 6cm,
Height (h) = 2.8cm
Area = ½(a+b)*h
Area = ½(4+6)*2.8
Area = ½(10)*2.8 = 5*2.8 = 14 cm²
4 rectangles of different dimensions:
Rectangle 1 (down face): l = 10cm, b = 4cm
Area = 10*4 = 40 cm²
Rectangle 2 and 3 (side faces): l = 10cm, b = 3cm
Area = 2(l*b) = 2(10*3) = 60cm²
Rectangle 4 (top face) = l = 10cm, b = 6cm
Area = 10*6 = 60cm²
Surface area of the figure = 14 + 40 + 60 + 60 = 174 cm²
A pharmacist needs 16 liters of a 4% saline solution. He has a 1% solution and a 5% solution available. How many liters of the 1% solution and how many liters of the 5% solution should he mix to make the 4% solution?
x = liters of 1% solution
y = liters of 5% solution
x + y = 16
0.01x + 0.05y = 0.04*16 = 0.64
y = 16 - x
0.01x + 0.05(16 - x) = 0.64
0.01x + 0.8 - 0.05x = 0.64
0.16 = 0.04x
x = 4
y = 12
List the sides in order from the largest to the smallest. A. XY, YW, WX B. XY, WX, YW C. WX, YW, XY D. WX, XY, YW
Answer:
Option (D)
Step-by-step explanation:
By applying Sine rule in the given triangle WXY,
[tex]\frac{\text{SinW}}{\text{XY}}=\frac{\text{SinY}}{\text{XW}}=\frac{\text{SinX}}{\text{WY}}[/tex]
[tex]\frac{\text{Sin59}}{\text{XY}}=\frac{\text{Sin82}}{\text{XW}}=\frac{\text{Sin39}}{\text{WY}}[/tex]
[tex]\frac{\text{Sin59}}{\text{XY}}=\frac{\text{Sin82}}{\text{XW}}[/tex]
[tex]\frac{\text{XW}}{\text{XY}}=\frac{\text{Sin82}}{\text{Sin59}}[/tex]
= 1.1489
XW : XY ≈ 1.15 : 1
[tex]\frac{\text{Sin59}}{\text{XY}}=\frac{\text{Sin39}}{\text{WY}}[/tex]
[tex]\frac{\text{XY}}{\text{WY}}=\frac{\text{Sin59}}{\text{Sin39}}[/tex]
[tex]\frac{\text{XY}}{\text{WY}}=\frac{1.36}{1}[/tex]
[tex]\frac{\text{XY}}{\text{WY}}=\frac{\frac{1}{1}}{\frac{1}{1.36} }[/tex]
[tex]\frac{\text{XY}}{\text{WY}}=\frac{1}{0.7342}[/tex]
XY : WY = 1 : 0.7342
XW : XY : WY = 1.15 : 1 : 0.7342
Therefore, WX > XY > WY
Option (D). will be the correct option.
What is the error in this problem?
Answer:
wrong position of tan 64
Please help me guys :)
Question:
In exercises 1 through 4, find the one-sided limits lim x->2(left) f(x) and limx-> 2(right) from the given graph of f and determine whether lim x->2 f(x) exists.
Step-by-step explanation:
For a left-hand limit, we start at the left side and move right, and see where the function goes as we get close to the x value.
For a right-hand limit, we start at the right side and move left, and see where the function goes as we get close to the x value.
If the two limits are equal, then the limit exists. Otherwise, it doesn't.
1. As we approach x = 2 from the left, f(x) approaches -2.
lim(x→2⁻) f(x) = -2
As we approach x = 2 from the right, f(x) approaches 1.
lim(x→2⁺) f(x) = 1
The limits are not the same, so the limit does not exist.
lim(x→2) f(x) = DNE
2. As we approach x = 2 from the left, f(x) approaches 4.
lim(x→2⁻) f(x) = 4
As we approach x = 2 from the right, f(x) approaches 2.
lim(x→2⁺) f(x) = 2
The limits are not the same, so the limit does not exist.
lim(x→2) f(x) = DNE
3. As we approach x = 2 from the left, f(x) approaches 2.
lim(x→2⁻) f(x) = 2
As we approach x = 2 from the right, f(x) approaches 2.
lim(x→2⁺) f(x) = 2
The limits are equal, so the limit exists.
lim(x→2) f(x) = 2
4. As we approach x = 2 from the left, f(x) approaches 2.
lim(x→2⁻) f(x) = 2
As we approach x = 2 from the right, f(x) approaches infinity.
lim(x→2⁺) f(x) = ∞
The limits are not the same, so the limit does not exist.
lim(x→2) f(x) = DNE
Customers arrive at a rate of 24 people per hour to a bank. Assume that the number of customers arriving can be described using the Poisson distribution. What is the probability that at most 30 customers arrive in the next hour
Answer:
0.90415
Step-by-step explanation:
Given the following :
Arrival rate = mean(μ) = 24
Probability that at most 30 customers arrive in the next hour:
The poisson distribution formula :
P(x, μ) = [(e^-μ) * (μ^x)] / x!
Where :
e = euler's constant
P(x ⩽ 30) = p(0) + p(1) + p(2) +.... + p(30)
Using the online poisson probability distribution calculator :
P(x ⩽ 30, 24) = 0.90415
Therefore there is about 90.4% probability that at most 30 customers will arrive in the next hour.
PLEASE HELP!!! (1/5) - 50 POINTS-
Answer:
consistent independent
Step-by-step explanation:
This is a graph of consistent independent equations
The lines cross and there is one solution
Inconsistent equations never cross and there is no solutions
Consistent dependent equations are equations of the same line
Answer:
Linear
Step-by-step explanation:
This is a graph of linear system of equation.
The two lines represent different equations connected with each other.
They intersect at a common point showing the solution to the system of equation.
2/3a - 1/6 =1/3 please help me
Answer:
[tex]a = \frac{3}{4}[/tex]
Step-by-step explanation:
Let's convert everything to sixths to make it easier to work with.
[tex]\frac{4}{6}a - \frac{1}{6} = \frac{2}{6}[/tex]
Add 1/6 to both sides:
[tex]\frac{4}{6}a = \frac{3}{6}[/tex].
Dividing both sides by 4/6:
[tex]a = \frac{3}{6} \div \frac{4}{6}\\\\a = \frac{3}{6} \cdot \frac{6}{4}\\\\a = \frac{18}{24}\\\\a = \frac{3}{4}[/tex]
Hope this helped!
PLEASE HURRY! i walked north 8 miles, the west 4 miles, and finally south 5 miles, at the end how far was i from where i started
Answer:
5 miles away
Step-by-step explanation:
If you walked north 8 miles, then west 4 miles, then south 5 miles, you have, in total, travelled 4 miles west and [tex]8-5=3[/tex] miles north.
This creates a triangle, in which we can find the the length of the hypotenuse to find how far away you are now.
We can use the Pythagorean theorem since this is a right triangle.
[tex]a^2+b^2=c^2\\3^2+4^2=c^2\\9+16=c^2\\25=c^2\\c=5[/tex]
Hope this helped!
Answer:
5 miles away
Step-by-step explanation:
please help with this
Answer:
[tex]\sin \left(\theta \right)-\frac{1}{2}\cos \left(2\theta \rightt)+C[/tex]
Step-by-step explanation:
We are given the graph of r = cos( θ ) + sin( 2θ ) so that we are being asked to determine the integral. Remember that [tex]\:r=cos\left(\theta \right)+sin\left(2\theta \right)[/tex] can also be rewritten as [tex]\int \cos \left(\theta \right)+\sin \left(2\theta \right)d\theta \right[/tex].
Let's apply the functional rule [tex]\int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx[/tex],
[tex]\int \cos \left(\theta \right)+\sin \left(2\theta \right)d\theta \right[/tex] = [tex]\int \cos \left(\theta \right)d\theta \right+\int \sin \left(2\theta \right)d\theta \right[/tex]
At the same time [tex]\int \cos \left(\theta \right)d\theta \right=\sin \left(\theta \right)[/tex] = [tex]sin( \theta \right ))[/tex], and [tex]\int \sin \left(2\theta \right)d\theta \right[/tex] = [tex]-\frac{1}{2}\cos \left(2\theta \right)[/tex]. Let's substitute,
[tex]\int \cos \left(\theta \right)d\theta \right+\int \sin \left(2\theta \right)d\theta \right[/tex] = [tex]\sin \left(\theta \right)-\frac{1}{2}\cos \left(2\theta \right)[/tex]
And adding a constant C, we receive our final solution.
[tex]\sin \left(\theta \right)-\frac{1}{2}\cos \left(2\theta \rightt)+C[/tex] - this is our integral
2. You are going to produce tennis shoes
that come in 3 different colors. In order to
decide how many to make in each color,
you conduct a survey. Of the 300 people
you survey, 75 said that they would
purchase the yellow shoes. If you are
going to make 10,000 pairs of shoes, how
many should be yellow?
Please help thank you
Answer:
Hey there!
[tex]\frac{75}{300}[/tex]=[tex]\frac{x}{10000}[/tex]
750000=300x
x=2500
They should make 2500 yellow shoes.
Hope this helps :)
Last year, Leila had $30,000 to invest. She invested some of it in an account that paid 6% simple interest per year, and she invested the rest in an account that paid 5% simple interest per year. After one year, she received a total of $1580 in interest. How much did she invest in each account?
Answer:
6%: $8,0005%: $22,000Step-by-step explanation:
Let x represent the amount invested at 6%. Then 30000-x is the amount invested at 5%. Leila's total earnings for the year are ...
0.06x +0.05(30000-x) = 1580
0.01x +1500 = 1580 . . . . . . . . . . . . simplify
0.01x = 80 . . . . . . . . . . . subtract 1500
x = 8000 . . . . . . . . . . . . multiply by 100
Leila invested $8000 at 6% and $22000 at 5%.
A laboratory tested n = 98 chicken eggs and found that the mean amount of cholesterol was LaTeX: \bar{x}x ¯ = 86 milligrams with σ = 7 milligrams. Find the margin of error E corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs.
Answer:
1.3859
Step-by-step explanation:
The formula for Margin of Error is given as:
Margin of Error = Critical value × Standard Error
Critical value = z score
In the question, we are given a confidence interval of 95%.
Z score for a 95% confidence level is given as: 1.96
Hence, critical value = 1.96
Standard Error = σ / √n
Where n = number of samples = 98 chicken eggs
σ = Standard deviation = 7 milligrams
Standard Error = 7/√98
Standard Error = 0.7071067812
Hence, Margin of Error = Critical value × Standard Error
Margin of Error = 1.96 × 0.7071067812
Margin of Error = 1.3859292911
Therefore, the margin of error corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is approximately 1.3859
15. What is the next number in this series?
6, 11, 9, 14, 12,
a. 17
b. 10
C. 18
d. 16
Answer:
a. 17
Step-by-step explanation:
The pattern is add 5 then subtract 2
Write the function in terms of unit step functions. Find the Laplace transform of the given function. f(t) = 5, 0 ≤ t < 7 −3, t ≥ 7
Rewrite f in terms of the unit step function:
[tex]f(t)=\begin{cases}5&\text{for }0\le t<7\\-3&\text{for }t\ge7\end{cases}[/tex]
[tex]\implies f(t)=5(u(t)-u(t-7))-3u(t-7)=5u(t)-8u(t-7)[/tex]
where
[tex]u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t<0\end{cases}[/tex]
Recall the time-shifting property of the Laplace transform:
[tex]L[u(t-c)f(t-c)]=e^{-cs}L[f(t)][/tex]
and the Laplace transform of a constant function,
[tex]L[k]=\dfrac ks[/tex]
So we have
[tex]L[f(t)]=L[5u(t)-8u(t-7)]=5L[1]-8e^{-7s}L[1]=\boxed{\dfrac{5-8e^{-7s}}s}[/tex]
In this exercise you have to find the laplace transform:
[tex]L[f(t)]=\frac{5-8e^{-7s}}{s}[/tex]
Rewrite f in terms of the unit step function:
[tex]f(t)=\left \{ {{5, for 0\leq t\leq 7} \atop {-3, for t\geq 7}} \right. \\f(t)= 5(u(t)-u(t-7)-3u(t-7)=5u(t)-8u(t-7)[/tex]
Where:
[tex]u(t)= \left \{ {{1, t\geq 0} \atop {0, t<0}} \right.[/tex]
Recall the time-shifting property of the Laplace transform:
[tex]L[u(t-c)f(t-c)]= e^{-cs}L[f(t)][/tex]
and the Laplace transform of a constant function,
[tex]L[k]=\frac{k}{s}[/tex]
So we have:
[tex]L[f(t)]= L[5u(t)-8u(t-7)]= 5L[1]-8e^{-7s}L[1]= \frac{5-8e^{-7s}}{s}[/tex]
See more about Laplace transform at : brainly.com/question/2088771
Need help with this as soon as possible pls
Answer:
i think
x=6.77
y=11.33
Today only, a suit is being sold at a 26% discount. The sale price is $259.
What was the price yesterday?
Answer:
$350
Step-by-step explanation:
1. Set up the equation. The sale price of $259 is 74% of the original price.
[tex]\frac{74}{100}[/tex] = [tex]\frac{259}{x}[/tex]
2. Cross multiply
74x = 25900
3. Solve
x = 350
Karmen returned a bicycle to Earl's Bike Shop. The sales receipt showed a total paid price of $211.86, including the 7% sales tax. What was the cost of the bicycle without the sales tax? Any help would be very appreciated! Thank you very much!
Answer:
$198
Step-by-step explanation:
198x.07=13.86
198+13.86=211.86
Amira has 3/4 of a bag of cat food her cat eats 1/10 of a bag per week how many weeks will the food last