Answer:
One needs to know the initial speed of the bus to find distance traveled.
Why do planets speed up as they get closer to the sun?:
A. air resistance
B. friction
C. gravity
D. tension
Answer:
C
Explanation:
Gravity is the main reason that make our planets to pull each other
1. If two objects collide and one is initially at rest, is it possible for both to be at rest after the collision? Is it possible for one to be at rest after the collision? Explain.
Answer:
(a)If two objects collide and one is initially at rest, is it possible for both to be at rest after the collision?
No. Because if you have initial momentum P⃗ ≠0 , if both of the objects were at rest after the collision the total momentum of the system would be P⃗ =0 , which violates conservation of momentum
(b)Is it possible for only one to be at rest after the collision?
Yes, that is perfectly possible. It characteristically, happens when both objects are of the same mass. When two objects of the same mass collide and Kinetic energy is conserved (Perfectly Elastic collision) then the two objects interchange velocities.
Examine the roller coaster track above. Assume there is negligible friction as the roller coaster moves from position A to position F. Also assume that the roller coaster has minimal kinetic energy at point A. Create three different models below to describe the kinetic energy, the potential energy, and the total energy of the roller coaster at point E. Examples of models include, but are not limited to: pie charts, bar graphs, equations, textual descriptions, and analogies.
At point E
the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energyWhat is the energy of the roller coaster at point E?The energy of a roller coaster could either be potential energy, kinetic energy or a combination of both potential and kinetic energy.
Using analogies, the energy of the roller coaster at point E can be compared to a falling fruit from a tree which falls onto a pavement and is the rolling towards the floor. Point E can be compared to the midpoint of the fall of the fruit.
At point E
the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energyIn conclusion, the energy of the rollercoaster at E is both Kinetic and potential energy,
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An electron is moving the east with a speed of 5.0 × 106 m/s. There is an electric field of
3.0 kV/m in the east direction. What will be the electrons speed after it has moved 1.00 cm?
The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
What is Electric field?Electric field is the physical field that surrounds a charge.
How to find final velocity of the electron when it moves some distance in a certain electric field?From Newton's second law, the acceleration the electron will bea=F/m=qE/m
where q= charge of electronE= electric field
m= mass of electron
=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)
=10¹⁵×0.526m/s²
The kinematics equation v²=v0²+2a(Δx)where v=final velocity of the electronv0=initial velocity of the electron =5×10⁶m/s
a=acceleration of the electron =10¹⁵×0.526m/s²
Δx=distance moved by the electron in east direction =1cm=10^-2m
Now v^2=(5×10⁶)²+2×10¹⁵×0.526×10^-2=25×10¹²+10.52×10¹²
=35.52×10¹²
Now velocity of electron=5.95×10⁶m/s.Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
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What is meant by constructive interference?
A. Waves combine and their amplitude decreases
B. Waves do not combine and their amplitude decreases
C. Waves do not combine and their amplitude increases
D. Waves combine and their amplitude increases
Answer:
D. Waves combine and their amplitude increases
Explanation:
amplitude is the height of the wave in a graph
constructive interference happens when two waves are lined up perfectly
example when two speakers playing same music while facing each other, music will appear louder
Destructive interference happens when the peaks match the valleys and they cancel perfectly
like with noise cancelling headphones
during constructive interference, waves collide in phase
in phase means add together making the height of the wave in a graph bigger (amplitude increases)
Example: When we see two speakers right next to each other, we can experience constructive interference when the distance from each speaker to the observer is the same
two waves destructively interfere, they must have the same amplitude in opposite directions
quizlet
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A motorboat travels east with a velocity of 4 meters/second relative to the
water when it encounters a current with a velocity of 7.0 meters/second
north relative to the shore. What is the resultant speed (magnitude of
velocity) for the boat relative to the shore?
Answer:[tex]\sqrt{65} m/s[/tex]
Explanation:
A 940-kg sports car collides into the rear end of a 2500-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.8 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact.
What was the speed sports car at impact?
Express your answer to two significant figures and include the appropriate units.
The speed of the sport car at the time of impact is 6.61 m/s.
What is the frictional force of the two cars?Frictional force of the two cars = coefficient of kinetic frictin × mass × acceleration of gravity
= 0.8 × (2500+940) × 9.8
= 26970N
What is the acceleration of the skidded cars?As per Newton's second law of motion, force = mass × accelerationAcceleration= force / mass= 26,970/3440
= 7.8 m/s²
What is the velocity of the sport car at the time of impact?As per Newton's equation of motion, V² - U² = 2aSHere, V = 0 m/s, a= -7.8 m/s², S= 2.8 mSo, 0²-U²= 2×(-7.8)×2.8=> U = √43.68
= 6.61 m/s
Thus, we can conclude that the speed of the sport car at the time of impact is 6.61 m/s.
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A uniform linear charge of 3.0 nC/m is distributed along the y axis from y = -3 m to y=2m. Which of the following integrals is correct for the magnitude of the electric field at y = 4 m on the y axis?
[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex] is the integrals for the magnitude of the electric field.
A characteristic of electricity exists at every location in space when charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
The formula for the electric field due to a point charge is:
[tex]E = \frac{kq}{r^2}[/tex]
Here q is the charge, r is the distance from the charge, and k = 8.99 × [tex]10^9 Nm^2/ C^2[/tex]
Imagine an infinitely - tiny portion of this charge distribution that has a charge [tex]dq[/tex]. This charge produces an electric field dE with magnitude:
[tex]\int\limits^ {} \, dE = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]
[tex]E = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]
Here, λ = 3.0 nC/m dq
= λ.dy dE = ∫k.dq
From y = -3 m to y = 2 m, there is a 3.0 nC/m uniform linear charge distributed along the y axis.
The integrals for the magnitude of the electric field at y = 4 m on the y axis:
[tex]E = k \lambda \int\limits^2_{-3} {} \, \frac{dy}{( 4 - y)^2}[/tex]
[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex]
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What is the equation for the enthalpy of vaporization?
A. Q = m*Lv
B. Q = m/Lv
C. Q = 1/m*Lv
D. Q = Lv/m
Answer:
A: Q = m*Lv
Explanation:
The equation formula for the enthalpy of vaporization is;
Q = m*ΔHv
Where;
q = heat energy
m = mass
ΔHv = heat of vaporization
A bead of mass 15g is sliding on a wire. It has a speed of 2.0m/s at A, and it stops as it reaches the point C. The length of the wire from A to C is 250cm. How large an average friction force opposed the motion of the bead?
Answer:
.12 N
Explanation:
Velocity goes from 2 m/s to 0 m/s so average velocity = 1 m/s
.250 m / 1 m/s = .25 second to stop
change in velocity / change in time = accel
2 m/s / .25 sec = 8 m/s^2
F = ma
= .015 kg * 8 m/s^2 = .12 N
a motorist drives along a straight road at a constant speed of 15 m/s. just as she passes aparked motorcycle police officer , the officer starts to accelerate at 2m/s2 to over take her. assuming the officer maintains this acceleration,
a) determine the time it takes the police to reach the motorist the speed and
b) the total displacement of the officer as he overtakes the motorist
Explanation:
Distance traveled by motorist =(15.0m/s)t
Distance traveled by policeman =1/2(2.00m/s2)t2
(a) Intercept occurs when 15.0t =t2or t=15.0s.
(b) x(officer)=1/2(2.00m/s2)t2= 225m
It has been suggested that rotating cylinders about 19.5 mi long and 5.66 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?
_____rad/s
The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
Angular speed of the cylinder
The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is calculated as follows;
a = v²/r
v² = ar
(ωr)² = ar
ω²r² = ar
ω²r = a
ω² = a/r
ω = √(a/r)
where;
a is centripetal acceleration = acceleration due to gravity, gr is radius of the cylinder = 5.66 m / 2 = 2.83 mi = 4554.4 mω is angular speedω = √(g/r)
ω = √(9.8/4554.4)
ω = 0.046 rad/s
Thus, the angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
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In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of the effect resulting from evacuating air from a container. It is the basis for this problem. Two steel hemispheres of radius 0.430 m (1.41 feet) with a rubber seal in between are placed together and air pumped out so that the pressure inside is 15.00 millibar. The atmospheric pressure outside is 940 millibar.
1. Calculate the force required to pull the two hemispheres apart. [Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 ]
2. Two equal teams of horses, are attached to the hemispheres to pull it apart. If each horse can pull with a force of 1450N (i.e., about 326 lbs), what is the minimum number of horses required?
The values of the required solutions are
F= 53731 N N=37.05What is the minimum number of horses required?What is Force?
In the field of physics, an influence that can alter the motion of an object is referred to as a force. An object having mass can experience a change in its velocity, often known as an acceleration, when subjected to a force. Intuitively, force can also be conceptualized as either a push or a pull. Because it may be measured in both magnitude and direction, a force is considered a vector quantity.
What is atmospheric pressure?
The pressure that is exerted within the atmosphere of the Earth is referred to as barometric pressure as well as atmospheric pressure. As a unit of pressure, the standard atmosphere is defined as having a value of 101,325 Pa. This value is equivalent to 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.
In most situations, the equation for force can be expressed numerically as
Force = pressure * A
Therefore
[tex]F= (970 - 15 B)(\pi * (0.430 )^2)[/tex]
F= 53731 N
In conclusion, If each horse can pull with a force of 1450N
The number of horses required is
[tex]N=\frac{60754 }{1450}[/tex]
N=37.05
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The tires of a car make 68 revolutions as the car reduces its speed uniformly from 85.0 km/h to 56.0 km/h. The tires have a diameter of 0.80 m.
a)What was the angular acceleration of the tires?
Express your answer using two significant figures.
b)If the car continues to decelerate at this rate, how much more time is required for it to stop?
Express your answer to two significant figures and include the appropriate units.
c)If the car continues to decelerate at this rate, how far does it go? Find the total distance.
Express your answer to three significant figures and include the appropriate units.
a) The wheel of the car decelerates at an angular acceleration of - 0.577 radians per square second.
b) The wheel of the car requires a time of 51.149 seconds to stop.
c) The wheel of the car travels a distance of 683.225 meters before stopping.
How to analyze a decelerating rotating wheel
a) In this case we have a rotating wheel that decelerates at constant rate. The angular acceleration, in radians per square second, of the tires is determined by the following formula:
α = [ω'² - ω²] / (2 · θ) (1)
Where:
ω - Initial angular velocity, in radians per second.ω' - Final angular velocity, in radians per second.θ - Change in the angular displacement, in radians.The initial and final angular velocities, in radians per second, are now determined:
ω' = v' / R (2)
ω = v / R (3)
Where:
v - Initial linear velocity, in meters per second.v' - Final linear velocity, in meters per second.R - Radius of the tire, in meters.If we know that R = 0.80 m, v = 23.611 m / s, v' = 15.556 m / s and θ ≈ 427.257 radians, then the angular acceleration of the tire is:
ω' = (15.556 m / s) / (0.80 m)
ω' = 19.445 rad / s
ω = (23.611 m / s) / (0.80 m)
ω = 29.513 rad / s
α = [(19.445 rad / s)² - (29.513 rad / s)²] / [2 · (427.257 rad)]
α = - 0.577 rad / s²
b) The time required to stop the car, in seconds, is determined by the following expression:
t = (ω' - ω) / α (4)
t = (0 rad / s - 29.513 rad / s) / (- 0.577 rad / s²)
t = 51.149 s.
c) First, we find the change in angular displacement of the tire:
θ = [ω'² - ω²] / (2 · α) (5)
θ = [(0 rad / s)² - (29.513 rad / s)²] / [2 · (- 0.577 rad / s²)]
θ = 754.781 rad
Lastly, the distance traveled by the vehicle is:
s = R · θ (6)
s = (0.80 m) · (754.781 rad)
s = 683.825 m
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iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weight of iron ball in air?
Answer:
453 gm
Explanation:
Immersed objects are buoyed up by force equal to mass of displaced liquid
400 + 53 = 453 gm in air
If little herbert does something uncon
sciously he will probably
If little herbert does something unconsciously he will probably, he's definitely very unware of he has done
Doing something unconscious may have some implications which may not be favourable.
What is unconscious?Unconscious simply means a state of someone being absent minded of what is happening to him or her at a particular period of time
So therefore, if little herbert does something unconsciously he will probably, he's definitely very unware of he has done
Complete question:
What happens if little herbert does something unconsciously he will probably
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If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical speed be after having fallen a vertical distance of 50.8m if you neglect air resistance over that distance?
The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.
Time of motion of the girl
The time of motion of the girl is calculated as follows;
h = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0t is time of motiong is acceleration due to gravitySubstitute the given parameters and solve for time of motion;
50.8 = 0 + ¹/₂(9.8)t²
2(50.8) = 9.8t²
101.6 = 9.8t²
t² = 101.6/9.8
t² = 10.367
t = √10.367
t = 3.22 seconds
Final vertical velocity of the skydivervf = vi + gt
where;
vi is the initial vertical velocity = 0
vf = 0 + 9.8(3.22)
vf = 31.56 m/s
Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.
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How does the suns energy affect the climate of an area
There wouldn't be any life on Earth and no climate if it weren't for the Sun.
The spherical form of the Earth results in changes in the amount of sunlight that reaches the surface at various latitudes, giving rise to various climatic zones. Seasons are caused by the tilt of the Earth's axis of rotation in relation to the ecliptic plane.
The surface of the sun is around 6000 C hot; at this temperature, the solar mostly produces visible light. The Earth radiates infrared energy back into space to maintain its energy balance after being warmed by incoming solar radiation. The Earth's surface has an average temperature of 15 C, and at this temperature, the planet emits infrared light.
Carbon dioxide, methane, nitrous oxide, and other atmospheric greenhouse gases let solar energy to pass through but absorb infrared radiation that the planet emits back into space. This feature is not shared by other atmospheric elements like oxygen and nitrogen. These greenhouse gases re-emit infrared radiation in all directions to maintain energy balance, some of which is aimed at the Earth's surface and warms it. More greenhouse gases will increase infrared absorption and raise surface temperatures. This is comparable to how much blanket you cover yourself with at night. The blanket's thickness affects how warm you feel. The result of heat brought on by rising levels of greenhouse gases in the atmosphere is climate change.
In the course of billions of years, the Sun will continue to get hotter and brighter, rendering the Earth uninhabitable.
Additionally, all fossil fuels (coal, petroleum, and natural gas) and renewable energy are directly and indirectly derived from the sun (wind, solar, biomass, and hydroelectric).
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why is the bulb of hydrometer is made heavier give two reasons
The reason behind the heavier hydrometer bulb is the sinking of hydrometer is inversely proportional to the density of hydrometer, hence hydrometers is made heavier.
We all know that hydrometers float in liquid hence to maintain the centre of gravity while floating the hydrometer is made heavier using lead shots.
What is the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean?
It is slightly less than 9.81 m/s2.
It is very large due to the high pressure.
It is zero.
It is significantly less than 9.81 m/s2.
The gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure. That is option B
What is gravitational acceleration?The gravitational acceleration is the acceleration of an object that is under free fall. The acceleration due to gravity is 9.81 m/s2. above the sea level.
One of the factors that affect gravitational acceleration is depth. This is because as the depth increases so will pressure increase.
Increase in pressure leads to increase in gravitational acceleration.
Therefore, the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure.
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A converging lens has a focal length of 20cm. find graphically the image location for an object at each of the following distances from the lens: (a) 50cm (b) 20cm (c) 15cm (d) -40cm: determine the magnification in each case. Check your results by calculating the image position and lateral magnification from Eqs. (10) and (11), respectively.
Answer:
4
Explanation:
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Driving space is the space around your car_____
vulnerable to collision.
O
To the side
All of the above
To the rear
To the front
in which you are
Answer:
to the rear as there will be an elastic collision
Driving space is the space around your car to the rear vulnerable to collision. the correct answer is option(c).
Driving space indicates that you have a space or a larger area to drive in that is unrestricted. You see only broad, open spaces on the road ahead and there are no limits around your automobile, so you are free to travel forward or change lanes without encountering any obstacles.
Any driver must have room around their car, preferably in the front, back, and on the sides, in order to react to problems as they arise. Your separation from the car in front of you is the most important distance to leave. Drivers' Speeding Patterns Federal and state organizations that research various elements of speeding have taken notice of speeding as the most frequent cause of deadly collisions. The NHTSA has discovered tendencies among drivers who speed recently.
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The density of molybdenum is 10.28 g/cm^3 and it crystallizes in the face centered cubic unit cell. Calculate the edge length of the unit cell. (The atomic mass of Mo is 95.96 g/mole)
The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
Volume of molybdenumV = (zm/ρN)
where;
z is 2 for cubic unit cellm is mass of the molybdenumρ is density of the molybdenumV = (2 x 95.96) / (10.28 x 6.02 x 10²³)
V = 3.10 x 10⁻²³ cm³
Edge length of the unit cella³ = V
a = (V)^¹/₃
a = ( 3.10 x 10⁻²³)^¹/₃
a = 3.142 x 10⁻⁸ cm
a = 3.142 x 10⁻¹⁰ m
a = 314.2 x 10⁻¹² m
a = 314.2 pm
Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
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A car with a mass of 1000 kg accelerates from 0 to 90 km/h in 10 seconds. a) What is its acceleration? b) What is the net force on the car?
Answer:
v
f=90km/h=25m/s
v_{_{i}}=0v
i=0
t=10\;\mathrm{s}t=10s
m=1000\;\mathrm{kg}m=1000kg
The acceleration of the car is 2.5 m/s². The net force acting on the car is 2500 Newtons (N). The correct answers are 2.5 m/s², 2500 Newtons (N).
Given:
Mass of the car (m) = 1000 kg
Acceleration (a) = 2.5 m/s²
a) The acceleration of the car is:
Acceleration (a) = Change in velocity / Time taken
Final velocity (v(f)) = 90 × 0.27778 = 25 m/s
Acceleration (a) = (Final velocity - Initial velocity) / Time taken
Acceleration (a) = (25 - 0 ) / 10
Acceleration (a) = 2.5 m/s²
Therefore, The acceleration of the car is 2.5 m/s².
b) Newton's second law of motion:
F = m × a
F = 1000 × 2.5
F = 2500 N
The net force acting on the car is 2500 Newtons (N).
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method to separate the .
sand+iron fillings
Answer:
by using a magnetic field
Use a magnet to attract the iron fillings from the sand!
Hope this helps!
If a body has a velocity 50 m s-1
and the uniform acceleration is 5 m s-2, find the time it takes to travel a distance
of 240 m.
Answer:
Using the relation V^2 = U^2 + 2× a× S
V^2 = 50^2 + (2× 5 × 240 )
V^ 2 = 2500 + 2400
V^ 2 = 4900
V= (4900)^0.5 = 70 m/s
hence, velocity at a distance of 240 m will be 70m/s.
Now using the relation,
V= U + a× t
70 = 50 + 5 × t
20 = 5 × t
t = 20/5 = 4m/s
hence , time required to travel a distance of 240m will be 4s.
a simle arrangement by means of which emf are compared is known as
A simple arrangement by means of which EMF are compared is known as a voltmeter.
Discussion about Voltmeter :
A voltmeter is a straightforward device used to compare electromagnetic fields.When there is no current flowing through a cell, its terminal voltage equals its electromotive force (emf). The difference in potential between a cell's electrodes is what determines its terminal voltage. Since voltmeters use the cell's current to draw voltage, they are unable to measure a cell's emf.Using a voltmeter, one may determine the voltage generated in an electric circuit. Volts are the emf's SI unit (V). Volts are the voltage's SI unit (V). Non-coulomb force, also known as non-electric force operation, defines emf.Learn more about voltmeter here:
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The figure illustrates flow through a pipe with diameters of 1.0 mm and 2.0 mm and with different elevations. Px is the pressure in the pipe, and Vx is the speed of a non-viscous incompressible fluid at locations x = Q,R,S,T, or U. Options are: Greater than, Less than, Equal to
PU is ... PQ
VU is ... 2VT
PR is ... PU.
VR is ... VS
VQ is ... VU
PR is ... PS
By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,
[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]To find the answer, we need to know about the Bernoulli's equation as well as the Equation of continuity.
How to find the solution?1) We have to find the relation between pressure at U and Q.
We have the Bernoulli's equation,[tex]P+\frac{1}{2}dV^2+dgh=constant.[/tex]
where, P is the pressure, V is the velocity, d is density, g is acceleration due to gravity and h is the height of the flow.
By using the equation, we can find the pressure at U and Q.[tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_q+\frac{1}{2}dV_q^2+dgh\\where,\\V_u=V_q, \\since, D_p=D_q\\Thus,\\P_u=P_q+dgh[/tex]
[tex]P_u > P_q[/tex]
2) We have to find the relation between velocity at U and T.
For this, we have the equation of continuity as,[tex]AV=constant\\A_1V_1=A_2V_2[/tex]
From the diagram, we have,[tex]A_u=\pi r^2=\pi *(0.5)^2=0.25\pi *mm^2\\A_t=\pi *1=\pi mm^2\\V_u=V\\V_t=?[/tex]
Thus, the relation between velocity at U and T is,[tex]V_t=\frac{A_uV_u}{A_t}=\frac{V}{4}[/tex]
[tex]2V_t=2*\frac{V}{4} =\frac{V}{2}\\V_u=V\\[/tex]
[tex]V_u > 2V_t[/tex]
3) We have to find the relation between pressure at R and U
[tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_r+\frac{1}{2}dV_r^2+dg*0\\\\V_u=V , then\\V_r=V_t=\frac{V}{4}=\frac{V_u}{4} \\\\P_u=P_r+\frac{1}{16}[/tex]
[tex]P_u > P_r[/tex]
4) We have to find the relation between velocity at R and S
Both points R and S, have same area, thus same velocity.[tex]V_r=V_s[/tex]
5) We have to find the relation between velocity at Q and U
Both points Q and U, have same area, thus same velocity.[tex]V_q=V_u[/tex]
6) We have to find the relation between pressure at R and S
Both points R and S, have same area and thus, same velocities.[tex]P_r=P_s+dgh[/tex]
[tex]P_r > P_s[/tex]
Thus, we can conclude that, By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,
[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]Learn more about the Bernoulli's equation here:
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PLEASE HELP 20 POINTS
Scientists often need to look for patterns that occur in the data they collect and analyze. Explain why identifying patterns is important, using an example from your investigation about habitable worlds.
Answer:
Patterns in science are a little different. Data doesn't have to follow a trend, always going up or down over time. A pattern is a when data repeats in a predictable way. A good example of a pattern in science comes from the father of genetics, Gregor Mendel.After data is collected, it can be analyzed by looking for trends, patterns, and relationships. Trends are general directions of data, such as an overall increase in global temperature. Patterns don't necessarily involve data going one way or the other, but rather describe a repeating observation.In order to interpret and understand scientific data, one must be able to identify the trends, patterns, and relationships in it. Examine the importance of scientific data and recognize how understanding its trends, patterns, and relationships can lead a researcher to support or refute a hypothesis. Updated: 01/06/2022 What Is Scientific Data?
Explanation:
Question 5 & 6 plissssssss
Question: 5
The length of the pendulum is 7.6 m.
What is the expression of length of a pendulum in term of time period?Time period of the pendulum (T) = 2π×√(L/g)L= length of pendulum, g = acceleration due to gravity on earthSo, L = T²g/4π²
What is the length of the pendulum, if the time period is 3.20 s and acceleration due to gravity becomes 3×g?T= 3.20 sL = (3.2²×3×9.8)/4π²= 7.6 m
Thus, we can conclude that the length of the pendulum is 7.6 m i.e option C is correct.
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Question: 6
The object takes 2.55 seconds to reach the ground.
What is the expression of time taken to reach the earth surface by an object?From the conversation of energy, (1/2)mv²=mghSo, v=√(2gh)From Newtown's equation of motion, v=u+atHere, a= acceleration due to gravity which is gSo, √(2gh)=gtt= √(2h/g)
What is the time taken by an object dropped from 31 m to reach the ground?t= √(2×31/9.8)
= 2.55s
Thus, we can conclude that the option A is correct.
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