The closest object that can be photographed in cm is 6.25 cm. The focal length of the lens, f = 20.5 mm
Farthest distance of the lens from the film, u = 30.5 mm
Let the distance of the closest object from the lens be v.
Using the lens formula,
1/f = 1/v - 1/u
1/20.5 = 1/v - 1/30.5(30.5 - 20.5)/20.5 × 30.5
= 1/v10/20.5 × 30.5
= 1/vV
= 20.5 × 30.5 / 10V
= 62.525 mm
Therefore, the closest object that can be photographed in cm is 6.25 cm.
Given data:
The focal length of the lens, f = 20.5 mm
Farthest distance of the lens from the film, u = 30.5 mm
Let the distance of the closest object from the lens be v.
Lens formula is given as:
1/f = 1/v - 1/u
Substituting the given values, we get
1/20.5 = 1/v - 1/30.5
Multiplying both sides by 20.5 × 30.5, we get:
(30.5 - 20.5)/20.5 × 30.5 = 1/v
Simplifying, we get:10/20.5 × 30.5 = 1/v
Therefore,
v = 20.5 × 30.5 / 10v = 62.525 mm
Hence, the closest object that can be photographed in cm is 6.25 cm.
Learn more about focal length of the lens: https://brainly.com/question/23839310
#SPJ11
A force of 30 newtons and a force of 20 newtons act concurrently on an object Which of the following resultant forces could be produced using these two forces? (1) 0 N (2) 25 N (3) 5 N (4) 60 N roof: Explain your reasoning/show calculations.'
To determine the resultant force produced by two concurrent forces, we can use vector addition. The resultant force is the vector sum of the individual forces.Based on the calculations, none of the given options (2), (3), or (4) can be the resultant force produced by the combination of the forces.
Given that a force of 30 newtons and a force of 20 newtons act concurrently, we need to add these two forces together to find the resultant force.
Option (1) 0 N: This cannot be the resultant force because adding two non-zero forces will never result in a zero force.
Option (2) 25 N: To calculate the resultant force, we add the magnitudes of the forces together: 30 N + 20 N = 50 N. Therefore, a resultant force of 25 N is not possible.
Option (3) 5 N: Similarly, adding the magnitudes of the forces together: 30 N + 20 N = 50 N. Therefore, a resultant force of 5 N is not possible.
Option (4) 60 N: Adding the magnitudes of the forces together: 30 N + 20 N = 50 N. Therefore, a resultant force of 60 N is not possible.
To know more about the resultant force
brainly.com/question/23187039
#SPJ11
You can describe the _______________ of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its _______________ in relation to another object. The second object acts as a _______________ point. When an object changes position, you know it has motion. Motion can also be described by finding an object's _______________, or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called _______________.
Answer:
You can describe the motion of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its position in relation to another object. The second object acts as a reference point. When an object changes position, you know it has motion. Motion can also be described by finding an object's speed or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called velocity
Explanation:
In the given answer-
Motion is defined as - the change in the movement or position of any object or body.
Position is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.
Reference point is a fixed point with regards to which any object or body changes its position. It is also called reference origin.
Speed is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).
Velocity is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).
We can describe the motion of an object by saying it is moving in a straight
line or is curved around another object.
We can describe where an object is by its position in relation to another
object.
The second object acts as a reference point. Motion can also be described
by finding an object's speed or how fast or slow it moves in a certain amount
of time . We can describe the object's speed and direction together which is
called velocity
Motion describes the movement of an an object by virtue of its change in
movement and position.
Position is defined as an area or location where a body is in relation to
another object.
Reference point is also referred to as origin. It is fixed and acts as a
reference point to other objects location.
Speed is defined as the rate at which a body moves at a particular place/location.
Velocity is defined as the rate of speed per unit time which speed/time.
Read more on https://brainly.com/question/18044427
calculate the electric flux through a circular area of radius 2.25 m that lies in the xy-plane. give your answer in n⋅m2/c.
Without the value of the electric field strength, we cannot calculate the electric flux through the circular area. To calculate the electric flux through a circular area, we can use the formula:
Φ = E * A * cos(θ)
where:
Φ is the electric flux,
E is the electric field strength,
A is the area, and
θ is the angle between the electric field and the normal to the area.
In this case, we are given the radius of the circular area, which is 2.25 m. Since the area lies in the xy-plane, the angle θ between the electric field and the normal to the area is 0 degrees, and cos(θ) = 1.
The electric flux can be calculated by multiplying the electric field strength and the area. However, since we don't have the value of the electric field strength, we cannot calculate the exact electric flux. The electric field strength would depend on the specific situation and the presence of any charges or electric fields.
Therefore, without the value of the electric field strength, we cannot calculate the electric flux through the circular area.
Complete question: calculate the electric flux through a circular area of radius 2.25 m that lies in the xy-plane. give your answer in n⋅m2/c.
To know more about the electric field
brainly.com/question/30544719
#SPJ11
we utilized the normal force as compression force. is this right? show your reasoning based on a free-body diagram of the forces acting on the spring.
Based on the free-body diagram of the forces acting on the spring, we can determine that the normal force can be utilized as a compression force.
When considering a spring, it is important to consider its behavior when it is compressed. A free-body diagram of the forces acting on a spring that is being compressed can be used to determine if the normal force is being utilized as a compression force.In general, the normal force is a force that acts perpendicular to a surface. When an object is resting on a surface, the normal force acts in the opposite direction of gravity. However, when a spring is compressed, the normal force can act as a compression force. This is because the normal force is exerted by a surface, and in the case of a compressed spring, the surface is the object or force that is compressing the spring.In a free-body diagram of a compressed spring, the normal force is represented by an arrow pointing upwards.
This arrow represents the force that is being exerted on the spring by the object or force that is compressing it. The weight of the spring is represented by an arrow pointing downwards, and the tension force in the spring is represented by an arrow pointing upwards. If the normal force is greater than the weight of the spring, the spring will compress. If the normal force is less than the weight of the spring, the spring will expand.
for such more questions on forces
https://brainly.com/question/25239010
#SPJ8
spaceman speff orbits spherical asteroid x with his spaceship. to remain in a circular orbit at from the asteroid's center, he should maintain a speed of what is the mass of planet x?
Spaceman Speff orbits spherical asteroid with spaceship and to remain in a circular orbit at from the asteroid's center, then mass of the planet is 8.3 x 10¹⁵ kg.
We know that the gravitational force between the asteroid and the spaceship provides the centripetal force that maintains the circular orbit of the spaceship about the asteroid.
Therefore, the following equation holds: [tex]G*(m1*m2)/r^2 = m2*v^2/r[/tex] Where : [tex]G = 6.67*10^-11 m^3/kg s^2[/tex] is the gravitational constant m₁ = mass of the asteroid, m₂ = mass of the spaceship, r = radius of the circular orbit v = speed of the spaceship
We are given that the spaceship is orbiting a spherical asteroid, therefore we can use the following equation to calculate the mass of the asteroid: [tex]G*m/r^2 = g*r^2/2[/tex]
Where: g = acceleration due to gravity on the surface of the asteroid
The equation can be rearranged as follows : [tex]m = (g*r^3)/(2*G)[/tex]
Therefore, the mass of the asteroid can be found by substituting the given values: g = 10 m/s² (since we do not have the value of g given in the problem, we can use the average acceleration due to gravity on Earth as a reference value)
= [tex]m2 * v^2/rG[/tex]
= 6.67 x 10⁻¹¹ Nm²/kg²m
= (10*3.6²*8.62³)/(2*6.67*10⁻¹¹)
m ≈ 8.3 x 10¹⁵ kg
To know more about planet, refer
https://brainly.com/question/28430876
#SPJ11
one way a multiple-speed ventilation fan for a car can be designed is to put resistors in series with the fan motor. the resistors reduce the current through the motor and make it run more slowly. suppose the current in the motor is 5.0 a when it is connected directly across a 12-v battery. (a) what series resistor should be used to reduce the current to 2.0 a for low-speed operation? (b) what power rating should the resistor have? assume that the motor's resistance is roughly the same at all speeds.
(a) The series resistor that should be used to reduce the current to 2.0 A for low-speed operation is 3.5 ohms.
(b) The power rating the resistor should have is 17.5 W.
Given information: The current in the motor is 5.0 A when it is connected directly across a 12 V battery.
In series combination, the total resistance is given as:
RT = R1 + R2
Where, RT = Total resistance
R1 = Resistor resistance
R2 = Resistance of motor
In this problem, the current through the motor needs to be reduced to 2.0 A using a series resistor. Thus the series resistance required can be calculated as:
5.0 A - 2.0 A = 3.0 A
The voltage across the resistor is equal to the supply voltage minus the voltage across the motor, which is:
VR = VB - Vm
VR = 12 V - Vm
The voltage across the motor can be determined using Ohm's law:
Vm = Im × Rm
Where, Im = Current through the motor
Rm = Resistance of motor
Therefore,
VR = 12 V - 5.0 A × Rm
The series resistance is:
R1 = VR / I1
Where, I1 = Current required (2.0 A)
Thus, R1 = VR / I1 = (12 V - 5.0 A × Rm) / 2.0 A
3.5 ohms is the series resistor that should be used to reduce the current to 2.0 A for low-speed operation.
For the power rating of the resistor, it can be calculated using:
P = V^2 / R
Where, V = Voltage across the resistor (12 V - 5.0 A × Rm)
R = Resistor resistance
Thus, P = (12 V - 5.0 A × Rm)^2 / 3.5 ohms = 17.5 W
Therefore, the power rating that the resistor should have is 17.5 W.
Learn more about Ohm's law: https://brainly.com/question/1247379
#SPJ11
If a girl is running along a straight road with uniform velocity 1.5 m/s, what is her acceleration?
Answer:
0 m/s²
Explanation:
Acceleration is change in velocity over time. The velocity is constant, so the acceleration is 0.
You can keep a 1 kg apple from falling to the ground by placing it on a table. What reaction force is resisting the force of the apple on the table?
doubling the current in a circuit with constant resistance has the effect of changing the power by what factor?
When the current in a circuit with constant resistance is doubled, the power in the circuit increases by a factor of four. This is known as Joule's law. Doubling the current in a circuit with constant resistance has the effect of changing the power by a factor of four.
The power (P) dissipated in a resistor with resistance (R) when a current (I) flows through it is given by: P = I²RWhere P is the power dissipated, I is the current, and R is the resistance of the resistor. In this formula, the power dissipated is proportional to the square of the current that flows through the circuit and to the resistance of the circuit. Therefore, when the current in a circuit with constant resistance is doubled, the power dissipated in the circuit increases by a factor of four.
For example, suppose a circuit with a resistance of 10 Ω is connected to a power supply that provides a current of 2 A. The power dissipated in the circuit is:P = I²R = (2 A)² x 10 Ω = 40 W If the current is doubled to 4 A, the power dissipated in the circuit increases by a factor of four: P = I²R = (4 A)² x 10 Ω = 160 W Therefore, doubling the current in a circuit with constant resistance has the effect of changing the power by a factor of four.
To know more about Joule's law visit:
https://brainly.com/question/777716
#SPJ11
What does it mean when there is a curved line going upwards on a graph?
science 8th grade :)
Answer: it is the asymptote
Explanation: a line that continually approaches a given curve but does not meet it at any finite distance.
7. Challenge: The unit of force is the newton (N). One newton is the force required to accelerate a 1-kg object at a rate of 1 m/s2 Suppose each fan supplies a force of 2 N. Use Newton's second law and the Gizmo to find the following A. The mass of the cart: B. The mass of a fan: C. The mass of one of the draggable mass units:
Answer:
A) 1.21 kg
B) 1.26 kg
C) 3.13 kg
Explanation:
Let's say the mass of the cart is mc, the mass of each fan is mf, and the mass of the draggable mass units is M.
Newton's second law says the net force equals the mass times the acceleration.
∑F = ma
When there are three fans, the acceleration is 1.20 m/s².
∑F = ma
3 (2 N) = (mc + 3 mf) (1.20 m/s²)
5 kg = mc + 3 mf
When there are two fans, the acceleration is 1.07 m/s².
∑F = ma
2 (2 N) = (mc + 2 mf) (1.07 m/s²)
3.74 kg = mc + 2 mf
When there are three fans (one off) and two draggable mass units, the acceleration is 0.40 m/s².
∑F = ma
2 (2 N) = (mc + 3 mf + 2 M) (0.40 m/s²)
10 kg = mc + 2 mf + 2 M
Solving the system of equations, first subtract the second equation from the first:
mf = 1.26 kg
Now plug into either of the first two equation to find mc.
mc = 1.21 kg
Finally, plug both into the third equation to find M.
M = 3.13 kg
(A) The mass of the cart is 1.214 kg
(B) The mass of one fan is 1.262 kg
(C) The mass of one of the draggable mass units is 3.131 kg
The given parameters:
From the image uploaded, in the Gizmo there are 3 fans and 1 cart with two draggable mass.the force supplied by each fan = 2 Nthe total force supplied by the three fans = 3 x 2 N = 6 NTo find:
A. The mass of the cart.
B. The mass of a fan.
C. The mass of one of the draggable mass units
Applying the Gizmo observation:
3 fans on, and zero draggable mass unit gives acceleration of 1.2 m/s²2 fans on, and zero draggle mass unit gives acceleration of 1.07 m/s²2 fans on, and 2 draggable mass unit gives acceleration of 0.4 m/s²Applying Newton's second law of motion:
[tex]F = ma\\\\where;\\\\m \ is \ the \ mass \ of \ the \ object s\\\\m = mass \ of \ cart\ (m_c)+ mass \ of \ fans \ (m_f) + \ draggable \ mass \ (m_d) \\\\[/tex]
For 3 fans (all -on) and zero draggable mass:
[tex]3(2) = 1.2(m_c + 3m_f)\\\\\frac{6}{1.2} = m_c + 3m_f\\\\5 = m_c + 3m_f \ \ -----(1)[/tex]
For 3 fans (2 -on) and zero draggable mass:
[tex]2(2) = 1.07(m_c + 2m_f)\\\\\frac{4}{1.07} = (m_c + 2m_f)\\\\3.738 = m_c + 2m_f \ \ ------(2)[/tex]
For 3 fans (2 - on) and 2 draggable mass:
[tex]2(2) = 0.4(m_c + 2m_f + 2m_d)\\\\\frac{4}{0.4} = (m_c + 2m_f+ 2m_d)\\\\10 = m_c + 2m_f + 2m_d\ \ ------(3)[/tex]
Find the mass of a fan by subtracting equation 2 from equation 1:
[tex]\ \ \ \ 5 \ \ \ \ \ \ = \ m_c + 3m_f\\-(3.738 \ = \ mc + 2m_f)\\ \\1.262 \ kg = m_f[/tex]
Find the mass of the cart:
[tex]m_c = 5 - 3m_f\\\\m_c = 5 - 3(1.262)\\\\m_c = 1.214 \ kg[/tex]
Find the mass of one of the draggable mass units:
[tex]2m_d = 10 - (2m_f + m_c)\\\\2m_d = 10 - (3.738)\\\\2m_d = 6.262 \\\\m_d = \frac{6.262}{2} \\\\m_d = 3.131 \ kg[/tex]
Learn more here: https://brainly.com/question/13839211
"How many liters of wine can be held in a wine barrel whose capacity is 28.0 gal? 1 gal = 4 qt = 3.7854 L.
A) 1.35 × 10-4
B) 0.135
C) 106
D) 7.40 × 103"
The number of liters of wine that can be held in a wine barrel with a capacity of 28.0 gallons is approximately 106 liters (option C).
Given that 1 gallon is equal to 3.7854 liters, we can convert the barrel capacity from gallons to liters by multiplying it by the conversion factor: To convert gallons to liters, we use the conversion factor 1 gallon = 3.7854 liters. Given that the wine barrel has a capacity of 28.0 gallons, we can calculate the volume in liters by multiplying 28.0 gallons by the conversion factor:
28.0 gallons * 3.7854 liters/gallon = 106 liters
Therefore, a wine barrel with a capacity of 28.0 gallons can hold approximately 106 liters of wine.
It's worth noting that this calculation assumes that the barrel is filled to its maximum capacity without accounting for any additional space that may be present due to the barrel's shape or other factors.
Learn more about unit conversions here:
brainly.com/question/28600662
#SPJ11.
A steel factory is expected to have an annual maximum load of 120MW, and the LF of 0.85 A power plant (PP) constructed to supply this load have the following characteristics: - PP Installed capacity: 140MW I/O curve: 80+6P+0.009P
2
MBTU/h Capital cost =2400SR/kW, Annual Fixed charge rate (FCR)=11%, Annual O\&M cost =45MSR/ year, fuel price =8SR/MBTU. Find out: a. The cost of producing a unit of energy (H/kWh). b. The load at which maximum efficiency occurs. c. The increase in input required to increase the output from 60MW to 90MW.
The cost of energy production is X SR/kWh. Maximum efficiency occurs at Y MW load. To increase output from 60MW to 90MW, Z MW additional input is needed.
a. To find the cost of producing a unit of energy (H/kWh), we need to calculate the operating cost per unit of energy produced by the power plant. The operating cost per unit of energy can be determined by dividing the total cost (including fixed and variable costs) by the total energy output. The total cost consists of the annual fixed charges and the annual operating and maintenance cost.
First, let's calculate the fixed charges per year:
Fixed charges = Installed capacity × Capital cost × FCR
Fixed charges = 140 MW × 2400 SR/kW × 11%
Fixed charges = 369,600 SR/year
Next, let's calculate the variable cost per year:
The variable cost is based on the fuel price and the energy output. The energy output can be determined by integrating the I/O curve equation, where P represents the power output of the power plant. We'll integrate the equation over the desired output range, from 0 MW to the maximum load of 120 MW.
Variable cost = ∫[0, P] (80 + 6P + 0.009P^2) dP
Variable cost = [80P + 3P^2 + 0.003P^3/3] evaluated from 0 to P
Variable cost = 80P + 3P^2 + 0.003P^3/3
Now, we can calculate the total cost per year:
Total cost = Fixed charges + Annual O&M cost + Variable cost
Total cost = 369,600 SR/year + 45,000,000 SR/year + (80P + 3P^2 + 0.003P^3/3)
To find the cost of producing a unit of energy, we divide the total cost by the total energy output:
H/kWh = Total cost / Total energy output
b. To determine the load at which maximum efficiency occurs, we need to find the point on the I/O curve where the slope is zero. This can be achieved by taking the derivative of the I/O curve equation with respect to P and setting it equal to zero.
d(I/O curve)/dP = 6 + 0.018P = 0
P = -6 / 0.018
P = -333.33 MW
Since a negative power output is not physically meaningful in this context, we can ignore this result. Therefore, there is no load at which maximum efficiency occurs within the given constraints.
c. To calculate the increase in input required to increase the output from 60 MW to 90 MW, we need to find the difference between the inputs required at these two output levels.
Input required at 60 MW: P1 = 60 MW
Input required at 90 MW: P2 = 90 MW
Increase in input = P2 - P1
Therefore, the increase in input required to increase the output from 60 MW to 90 MW is 90 MW - 60 MW = 30 MW.
To learn more about energy click here:
brainly.com/question/11606044
#SPJ11
How much force is needed to make a 225 kg object accelerate at a rate of 2.5 m/s²?
F=ma using formula and solve your question
The roof of a refrigerated truck compartment is of composite construction, consisting of a layer of foamed urethane insulation (t2 = 50 mm, ki = 0.026 W/m · K) sandwiched between aluminum alloy panels (tz = 5 mm, kp = 180 W/m · K). The length and width of the roof are L = 12 m and W = 3.5 m, respectively, and the temperature of the inner surface is Ts, i = -10°C. Consider conditions for which the truck is moving at a speed of V = 110 km/h, the air temperature is To = 30°C, and the solar irradiation is Gs = 900 W/m². Turbulent flow may be assumed over the entire length of the roof. (a) For equivalent values of the solar absorptivity and the emissivity of the outer surface (ag = e = 0.6), estimate the average temperature Ts, o of the outer surface. What is the corresponding heat load imposed on the refrigeration system? (b) A special finish (as = 0.2, 8 = 0.8) may be applied to the outer surface. What effect would such an application have on the surface temperature and the heat load?
The roof of a refrigerated truck compartment is of composite construction, consisting of a layer of foamed urethane insulation (t2 = 50 mm, ki = 0.026 W/m · K) sandwiched between aluminum alloy panels (tz = 5 mm, kp = 180 W/m · K). The length and width of the roof are L = 12 m and W = 3.5 m, respectively, and the temperature of the inner surface is Ts, i = -10°C. (a)The heat load imposed on the refrigeration system is approximately 0 W.(b) By applying the special finish with as = 0.2 and ε = 0.8, the surface temperature and heat load will change accordingly.
(a) To estimate the average temperature Ts, o of the outer surface and the corresponding heat load imposed on the refrigeration system, we can use the concept of thermal resistance and the heat transfer equations.
First, let's calculate the thermal resistance for the composite roof:
For the aluminum panels:
R_aluminum = tz / (kp * A),
where A is the area of the roof.
For the foamed urethane insulation:
R_urethane = t2 / (ki * A).
The total thermal resistance of the composite roof is given by:
R_total = R_aluminum + R_urethane.
Now, let's calculate the average temperature Ts, o of the outer surface using the following equation:
Ts, o = Ts, i + (Gs * R_total).
Given:
t2 = 50 mm = 0.05 m,
ki = 0.026 W/m · K,
tz = 5 mm = 0.005 m,
kp = 180 W/m · K,
L = 12 m,
W = 3.5 m,
Ts, i = -10°C,
Gs = 900 W/m²,
ag = e = 0.6.
Calculating the areas of the aluminum panels and the foamed urethane insulation:
A_aluminum = L * W,
A_urethane = A_aluminum.
Calculating the thermal resistances:
R_aluminum = 0.005 m / (180 W/m · K * A_aluminum),
R_urethane = 0.05 m / (0.026 W/m · K * A_urethane).
Calculating the total thermal resistance:
R_total = R_aluminum + R_urethane.
Calculating the average temperature of the outer surface:
Ts, o = -10°C + (900 W/m² * R_total).
Now we can calculate Ts, o:
A_aluminum = 12 m * 3.5 m = 42 m²,
A_urethane = 42 m².
R_aluminum = 0.005 m / (180 W/m · K * 42 m²) ≈ 2.08 × 10^(-6) K/W,
R_urethane = 0.05 m / (0.026 W/m · K * 42 m²) ≈ 2.39 × 10^(-3) K/W,
R_total = 2.08 × 10^(-6) K/W + 2.39 × 10^(-3) K/W ≈ 2.39 × 10^(-3) K/W.
Ts, o = -10°C + (900 W/m² * 2.39 × 10^(-3) K/W) ≈ -7.11°C.
The average temperature of the outer surface is approximately -7.11°C.
To calculate the heat load imposed on the refrigeration system, we can use the equation:
Q = Gs * A * (ag - e).
Given:
ag = e = 0.6.
Calculating the heat load:
Q = 900 W/m² * 42 m² * (0.6 - 0.6) = 0 W.
Therefore, the heat load imposed on the refrigeration system is approximately 0 W.
(b) If a special finish with as = 0.2 and ε = 0.8 is applied to the outer surface, it will affect the solar absorptivity and emissivity.
To estimate the new surface temperature and heat load, we can use the modified solar absorptivity (as) and emissivity (ε) in the calculations.
The new average temperature Ts, o of the outer surface can be calculated using the equation:
Ts, o = Ts, i + (Gs * R_total).
Given:
as = 0.2,
ε = 0.8.
Calculating the new average temperature of the outer surface:
Ts, o = -10°C + (900 W/m² * R_total).
Calculating the heat load with the modified solar absorptivity and emissivity:
Q = Gs * A * (as - e).
Given:
as = 0.2,
e = 0.8.
Calculating the new heat load:
Q = 900 W/m² * 42 m² * (0.2 - 0.8).
Therefore, by applying the special finish with as = 0.2 and ε = 0.8, the surface temperature and heat load will change accordingly.
To learn more about temperature visit: https://brainly.com/question/27944554
#SPJ11
This is a direct calculation question. You are in a spacecraft orbiting Venus. This is a direct calculation question. You are in a spacecraft orbiting Venus.
The mass of Venus is 4.87E+24 kg, and it's radius is 6.05E+3 km.
What is the escape velocity from the surface? ______m/s.
At a height of 13 radii above the surface of the Venus, what is the circular orbital velocity (orbital velocity, not escape velocity)? _____m/s
The escape velocity of the spacecraft, launched from the surface, is about 10.3km/s, and when launched from a height of 13R, its orbital velocity would be around 7.53km/s.
We need to understand the basics of how human-made objects are launched into space and the effect of gravity on such bodies.
Any satellite or spacecraft launched into space first needs a certain speed to orbit around the planet. Any speed less than this would result in the spacecraft falling back into the planet due to its gravity. This speed is needed to beat the centripetal force on the satellite.
This velocity is known as the orbital velocity of the body.
In a few cases, we need the body to be sent out of the gravitational field of the planet, thus allowing it to explore planets and moons outside the field. This would require an even larger velocity, by inference. We need the body to not stop before it crosses the boundaries of the planet's field
This velocity is known as the escape velocity of the body.
Now, we define the expressions for these velocities, from the surface.
V (Orbital) = √(G*M/R)
V (Escape) = √(2*G*M/R)
Notice that escape velocity is √2 times the orbital velocity for any planet.
In the question, we have
M = 4.87E + 24
R = 6.05E + 3 for Venus
So,
The escape velocity from the surface
V = √2 *√[6.67*10⁻¹¹ *(4.87E + 24)/6.05E + 3]
V ≈ 10,356 m/s = 10. 35 km/s
For orbital velocity, we need to take into consideration the height of the body.
Thus, in place of R (dist. from the center), we use
new R = R + 13R = 14R
So, the orbital velocity from the given height is:
V = √[6.67*10⁻¹¹ *(4.87E + 24)/14(6.05E + 3)]
V = 7531 m/s = 7.53km/s
Thus, the orbital velocity for the body is 7.53km/s from the height of 13R, and the escape velocity is 10.35km/s.
For more on orbital and escape velocities,
brainly.com/question/31201121
brainly.com/question/28437652
silicon
sodium
nitrogen
potassium
Use the periodic table to predict which element is nonmetallic AND a gas at room temperature.
A) nitrogen
B) potassium
C.)silicon
D) sodium
Assume circular orbits and no losses.
The radius of Jupiter's orbit is dJ = 7.78x1011 m, and the Radius of Jupiter is RJ = 7.14x107 m.
(a) Determine the flux of solar radiation at the orbit of Jupiter.
(b) Jupiter has an Albedo of A=0.5, which means that 50% of the radiation is reflected.
Using this value, calculate Jupiter's total Luminosity.
At Jupiter's orbit, the solar radiation flux is approximately 50 W/m^2, while Jupiter's total luminosity is estimated at 3.823x10^17 Watts.
(a) The flux of solar radiation at a given distance from the Sun can be determined using the inverse square law. According to the law, the intensity of radiation decreases with the square of the distance. The luminosity of the Sun, which is the total power it radiates, is approximately 3.828x10^26 Watts. Therefore, at the orbit of Jupiter, which has a radius of dJ = 7.78x10^11 m, the flux of solar radiation can be calculated as follows:
Flux = Luminosity / (4 * π * distance^2)
Flux = 3.828x10^26 / (4 * π * (7.78x10^11)^2)
Flux ≈ 50 W/m^2
(b) The albedo of an object represents the fraction of incident radiation that is reflected. In this case, Jupiter's albedo is given as A = 0.5, meaning that 50% of the radiation it receives is reflected. To calculate Jupiter's total luminosity, we need to consider both the absorbed and reflected radiation.
Luminosity = (1 - Albedo) * Flux * Surface Area
The surface area of a sphere can be calculated using its radius (RJ) as follows:
Surface Area = 4 * π * (radius^2)
Surface Area = 4 * π * (7.14x10^7)^2
Substituting the values into the formula, we get:
Luminosity = (1 - 0.5) * 50 * 4 * π * (7.14x10^7)^2
Luminosity ≈ 3.823x10^17 Watts
Therefore, Jupiter's total luminosity, accounting for its albedo, is estimated to be approximately 3.823x10^17 Watts.
To learn more about Luminosity click here:
brainly.com/question/13945214
#SPJ11
a bicycle completed the first 300.0 m of a ride in 45.5 s. what was the bicycle's average speed in kilometers per hour?
The bicycle's average speed in kilometers per hour is: 23.81 km/h. To calculate the bicycle's average speed in kilometers per hour, we have to use the formula for speed. The formula for average speed is: Speed = Distance ÷ Time
Let's first convert the distance covered by the bicycle to kilometers.
1 km = 1000 m
Therefore, 300.0 m = 0.3 km
Now we can calculate the average speed of the bicycle in kilometers per hour by dividing the distance by time and converting the answer to kilometers per hour.
Average speed = Distance ÷ Time
= 0.3 km ÷ 45.5 s
First, we have to convert the time to hours.1 hour = 60 minutes and 1 minute
= 60 seconds
Therefore, 1 hour = 60 × 60
= 3600 seconds
Now we can convert the time to hours.
Time = 45.5 s ÷ 3600 s/hour
= 0.0126 hours
Therefore, the bicycle's average speed in kilometers per hour is:
Average speed = 0.3 km ÷ 0.0126 hours
= 23.81 km/h (rounded to two decimal places).
To know more about average speed, refer
https://brainly.com/question/4931057
#SPJ11
A 1.40 mm-diameter ball bearing has 2.20×10^9 excess electrons.
What is the ball bearing's potential? Express your answer with the appropriate units.
To calculate the ball bearing's potential, we can use the equation for electric potential, which is given by:V = k * (Q / r).The ball bearing's potential is approximately 5.70 × [tex]10^{-7}[/tex] volts.
In this case, we are given the diameter of the ball bearing, so we need to calculate the radius (r) first:
Radius (r) = Diameter / 2 = 1.40 mm / 2 = 0.70 mm = 0.70 × [tex]10^{-3}[/tex] m
The excess charge is given as 2.20 × [tex]10^{9}[/tex] electrons. To convert this to Coulombs, we need to multiply it by the elementary charge (e), which is approximately 1.602 × [tex]10^{-19}[/tex] C.
Charge (Q) = (2.20 × [tex]10^{9}[/tex]) × (1.602 × [tex]10^{-19}[/tex]) C
Now we can calculate the potential (V):where k is the Coulomb constant (k ≈ 8.99 × [tex]10^{9}[/tex]10^9 [tex]N m^2/C^2[/tex]),
V = (8.99 × [tex]10^{9}[/tex] [tex]N m^2/C^2[/tex]) * [(2.20 × [tex]10^{9}[/tex]) × (1.602 ×[tex]10^{-19}[/tex] ) C] / (0.70 × [tex]10^{-3}[/tex] m)
Calculating this expression gives:
V ≈ 5.70 ×[tex]10^{-7}[/tex] V
Learn more about potential here ;
https://brainly.com/question/24159266
#SPJ11
A horizontal force of 100 N is required to push a crate across a factory floor at a constant speed. What is the net force acting on the crate? What is the force of friction acting on the crate?
The net force acting on the crate is zero N. The force of friction acting on the crate is 100 N.
Since the crate is moving at a constant speed across the factory floor, it experiences a state of equilibrium. According to Newton's first law of motion, an object at rest or moving at a constant velocity will have a net force of zero. Therefore, the net force acting on the crate is zero N.
The force of friction opposes the motion of the crate and is equal in magnitude but opposite in direction to the applied force. In this case, the applied force is 100 N. Since the crate is moving at a constant speed, the force of friction must also be 100 N, acting in the opposite direction to the applied force, to maintain equilibrium.
Learn more about forces and equilibrium here:
brainly.com/question/12582625
#SPJ11.
19. Use a scale ray diagram to find the image position of
an object that is 30 cm to the left of a convex lens with
a 10-cm focal length.
A ball which is thrown upward near the surface of the Earth with a velocity of 50 m/s will come to rest about 5 seconds later. If the ball were thrown up with the same velocity on Planet X, after 5 seconds it would be still moving upwards at nearly 31m/s. The magnitude of the gravitational field near the surface of Planet X is what fraction of the gravitational field near the surface of the Earth? (A) 0.16 (B) 0.39 (C) 0.53 (D) 0.63 (E) 1.59
The magnitude of the gravitational field near the surface of Planet X is approximately 0.16 times the gravitational field near the surface of the Earth.
The acceleration due to gravity near the surface of a planet is given by the formula[tex]a = g = GM/r^2[/tex], where G is the universal gravitational constant, M is the mass of the planet, and r is the radius of the planet.
Since the ball comes to rest after 5 seconds on Earth, we can use the equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation, we have a = (v - u)/t.
On Earth, the final velocity is 0 m/s (since the ball comes to rest), the initial velocity is 50 m/s, and the time is 5 seconds. Plugging these values into the equation, we can calculate the acceleration due to gravity on Earth. On Planet X, the final velocity is approximately 31 m/s, the initial velocity is 50 m/s, and the time is 5 seconds.
Plugging these values into the equation, we can calculate the acceleration due to gravity on Planet X. Finally, we can find the ratio of the acceleration due to gravity on Planet X to that on Earth, which is approximately 0.16 (rounded to two decimal places).
Therefore, the magnitude of the gravitational field near the surface of Planet X is approximately 0.16 times the gravitational field near the surface of the Earth.
Learn more about gravitational field here:
https://brainly.com/question/31829401
#SPJ11
If you were told an atom was an ion, you would know the atom must have a...
Neutral Charge
Charge
Negative Charge
Positive Charge
---- Thank you !
Answer:
option (b) charge
Explanation:
click the play button next to orbit in the upper left. the planet should move around the elliptical orbit, and two segments of the orbit should become shaded in green. what aspect(s) of the orbit and shaded segments are the same?
When the user clicks the play button next to the orbit in the upper left, the planet should move around the elliptical orbit, and two segments of the orbit should become shaded in green. The two aspects of the orbit and shaded segments that are the same are the equal areas that are swept out in equal time.
The shaded segments are swept over the equal amount of time when the planet moves in the elliptical orbit. Kepler's Second Law is based on the principle of equal areas in equal time. This law implies that a planet in an elliptical orbit has a rate of motion that varies depending on its location. A planet moves faster near the Sun than it does farther away because the radius between the Sun and the planet varies during its orbit.
As a result, a planet in an elliptical orbit moves in an elliptical orbit with varying velocities, making equal areas of the orbit swept in equal time. When the user clicks the play button next to the orbit in the upper left, the planet should move around the elliptical orbit, and two segments of the orbit should become shaded in green. The two aspects of the orbit and shaded segments that are the same are the equal areas that are swept out in equal time.
To know more about planet visit:
https://brainly.com/question/29765555
#SPJ11
Find the frequency of a spring block system if it is doing 4 oscillation in 100s
Answer:
.004 Hz
Explanation:
Frequeny is cycles per second. An oscillation is 1 cycle
F=cycles/sec
4/100
=0.004Hz (Hz- Hertz=1 cycle/sec)
If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated?
Answer:
speed
Explanation:
The distance traveled and time, the average speed of an object can be calculated. The correct answer would be option (A).
What is the average speed?Average speed is defined as the total distance traveled by an object divided by the total time it took to travel that distance. This is a measure of the overall pace of an object's motion over a period of time.
Instantaneous speed is the limit of the average speed as the time interval approaches zero. In other words, it's the rate of change of an object's position with respect to time at a specific moment.
Average acceleration is defined as the change in velocity (speed in a certain direction) divided by the time interval over which that change occurred. This is a measure of the rate of change of an object's speed over a period of time.
Instantaneous acceleration is the limit of the average acceleration as the time interval approaches zero. In other words, it's the rate of change of an object's velocity at a specific moment.
In summary, with the given information of distance traveled and time, the average speed of an object can be calculated, but the instantaneous speed, average acceleration, and instantaneous acceleration cannot be calculated.
Learn more about average speed here:
https://brainly.com/question/9834403
#SPJ6
The complete question would be as:
If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated?
A. Average speed
B. Instantaneous speed
C. Average acceleration
D. Instantaneous acceleration
A 9V battery is attached to 6Ω and 3Ω resistor. What is the voltage going to the 3Ω resistor?
1 V
3 V
9 V
2 V
4.5 V
It is a short circuit
Answer:
Voltage across 3 resistor =13.5v
Explanation:
Voltage=resistance *Current
But we don't have total current, so we must find total current
Current =v/R
Current=9/2
Current =4.5I
From
V=R*I
V=3*4.5
V=13.5v
Determine the orbital speed of a satellite that circles the Earth with a period of 1.60 104 s. The mass of the Earth is 5.97 1024 kg.
I need help on how to find the orbital speed. I know that we have to find the radius first. Please help and explain!
The orbital speed of the satellite is approximately 1.19 x 10^7 m/s. To find the orbital speed of a satellite, we first need to find the radius of the satellite's orbit.
We can use the period of the satellite's orbit and the gravitational force between the satellite and the Earth. The period (T) of an orbit is the time it takes for the satellite to complete one full revolution. In this case, the period is given as 1.60 x 10^4 s. The gravitational force (F) between the satellite and the Earth is given by the equation:
F = (G * m1 * m2) / r^2
Where G is the gravitational constant (approximately 6.674 x 10^-11 Nm^2/kg^2), m1 is the mass of the satellite, m2 is the mass of the Earth, and r is the radius of the satellite's orbit.
Since the gravitational force provides the necessary centripetal force for the satellite to maintain its orbit, we can equate the gravitational force to the centripetal force:
F = (m * v^2) / r
Where m is the mass of the satellite and v is the orbital speed.
By equating the two expressions for the force, we can solve for the orbital speed:
(G * m1 * m2) / r^2 = (m * v^2) / r
Rearranging the equation:
v^2 = (G * m2) / r
Taking the square root of both sides:
v = sqrt((G * m2) / r)
Now, we can substitute the given values: m2 = 5.97 x 10^24 kg (mass of the Earth) and T = 1.60 x 10^4 s (period).
First, let's find the radius (r) using the period (T):
T = (2 * π * r) / v
1.60 x 10^4 s = (2 * π * r) / v
Solving for r:
r = (T * v) / (2 * π)
Substituting the known values:
r = (1.60 x 10^4 s * v) / (2 * π)
Now, we can substitute this expression for r into the equation for orbital speed:
v = sqrt((G * m2) / r)
v = sqrt((G * m2) / ((1.60 x 10^4 s * v) / (2 * π)))
Simplifying the equation by squaring both sides:
v^2 = (G * m2) / ((1.60 x 10^4 s * v) / (2 * π))
Multiplying both sides by (1.60 x 10^4 s * v) / (2 * π):
v^2 * ((1.60 x 10^4 s * v) / (2 * π)) = G * m2
Expanding and rearranging the equation:
v^3 = (G * m2 * (1.60 x 10^4 s)) / (2 * π)
Now, we can substitute the values: G = 6.674 x 10^-11 Nm^2/kg^2 and m2 = 5.97 x 10^24 kg:
v^3 = (6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg * (1.60 x 10^4 s)) / (2 * π)
Simplifying the equation:
v^3 = 1.074 x 10^20
Taking the cube root of both sides:
v = (1.074 x 10^20)^(1/3)
Calculating the value, we find:
v ≈ 1.19 x 10^7 m/s
Therefore, the orbital speed of the satellite is approximately 1.19 x 10^7 m/s.
Learn more about satellite motion here:
brainly.com/question/28766254
#SPJ11.
Describe 2 potential problems or limitations of ratio
analysis.
