Answer:
The focal length of the mirror is 10.4 cm.
Explanation:
The object distance ( d₀ ) ( distance of the candle from the mirror) is -18 cm.The Image distance ( dᵢ ) ( distance of the image from the mirror) is -25.0 cm.The mirror equation is 1/f = 1/d₀ + 1/dᵢ.So substitute the values of object distance and image distance in the mirror equation,
1/f = 1/(-18cm) + 1/(-25.0cm)
1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)
1/f = ( -25cm - 18cm)/(18cm x 25cm)
1/f = -43.0/450.0
f = -10.4651 cm.
The focal length of the mirror is approximately -10.4 cm.
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The graph shows the velocity
of a T-Rex as a function
of time. The velocity
of the T-Rex between 2 and 4
seconds shown is
about...
The correct option is C, the velocity between 2s and 4s is 7 meters per second.
What is the velocity of the T-Rex between 2 and 4 seconds?Here we have the graph of the velocity of a T-Rex as function of time in seconds.
Here we need to find the average value between 2 seconds and 4 seconds.
At 2 seconds, the graph says that the velocity is 7m/s
And we can see an horizontal line that ends at 4s, so the veloicty at 4 seconds is 7m/s
Then the average velocity in that interval is that one (because it is constant)
Then the correct option is C.
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Is a flat iron a first class lever
Answer: Yes
Explanation: there is a lever in the flat iron
Multiple-point charges: Four-point charges are placed as shown in the figure. Q=5.0 μC. Find the net electric field at point P shown in the figure. (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)
It's important to note that without the specific distances provided in the figure, it is not possible to provide the exact numerical value of the net electric field at point P.
To find the net electric field at point P, we need to consider the contributions from each of the four point charges. The electric field from a point charge is given by Coulomb's law:
[tex]E = k * (Q / r^2)[/tex]
Where:
E is the electric field,
k is the electrostatic constant ([tex]k = 8.99 * 10^9 N \∙ m^2/C^2[/tex]),
Q is the charge of the point charge, and
r is the distance between the point charge and the point where the electric field is being calculated.
Let's consider each point charge one by one:
1. The charge at the top left:
The electric field at P due to this charge is directed to the right. Its magnitude is given by:
[tex]E1 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.06 m)^2[/tex]
2. The charge at the top right:
The electric field at P due to this charge is directed to the left. Its magnitude is given by:
[tex]E2 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.04 m)^2[/tex]
3. The charge at the bottom left:
The electric field at P due to this charge is directed upward. Its magnitude is given by:
[tex]E3 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.08 m)^2[/tex]
4. The charge at the bottom right:
The electric field at P due to this charge is directed downward. Its magnitude is given by:
[tex]E4 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.1 m)^2[/tex]
Once we have calculated the electric fields due to each point charge, we can add them vectorially to obtain the net electric field at point P. Since the electric fields have different directions, we need to take into account their signs.
Net electric field at[tex]P = E1 - E2 + E3 - E4[/tex]
Performing the calculations and taking into account the signs, we can determine the net electric field at point P.
It's important to note that without the specific distances provided in the figure, it is not possible to provide the exact numerical value of the net electric field at point P.
The calculations outlined above allow for the determination of the magnitude and direction of the net electric field, but the specific numerical value depends on the distances between the charges and point P.
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O Object A: -2
Object B: -2
Object A: +3
Object B: +4
O Object A: -6
Object B: -4
O Object A: -3
Object B: 0
When the objects interact, which option indicates a possible net charge for each object?
At a fabrication plant, a hot metal forging has a mass of 90.8 kg, and a specific heat capacity of 434 J/(kg C°). To harden it, the forging is quenched by immersion in 689 kg of oil that has a temperature of 38.3°C and a specific heat capacity of 2680 J/(kg C°). The final temperature of the oil and forging at thermal equilibrium is 58.9°C. Assuming that heat flows only between the forging and the oil, determine the initial temperature in degrees Celsius of the forging.
The initial temperature of the forging is approximately 1,090.42°C.
To determine the initial temperature of the forging, we can use the principle of conservation of energy. The heat lost by the forging is equal to the heat gained by the oil during the quenching process.
The heat lost by the forging can be calculated using the formula:
Q_lost = m_forging * c_forging * (T_forging_initial - T_equilibrium)
where:
- Q_lost is the heat lost by the forging
- m_forging is the mass of the forging (90.8 kg)
- c_forging is the specific heat capacity of the forging (434 J/(kg C°))
- T_forging_initial is the initial temperature of the forging (unknown)
- T_equilibrium is the final temperature of the oil and forging at thermal equilibrium (58.9°C)
The heat gained by the oil can be calculated using the formula:
Q_gained = m_oil * c_oil * (T_equilibrium - T_oil_initial)
where:
- Q_gained is the heat gained by the oil
- m_oil is the mass of the oil (689 kg)
- c_oil is the specific heat capacity of the oil (2680 J/(kg C°))
- T_oil_initial is the initial temperature of the oil (38.3°C)
Since the heat lost by the forging is equal to the heat gained by the oil, we can set up the following equation:
m_forging * c_forging * (T_forging_initial - T_equilibrium) = m_oil * c_oil * (T_equilibrium - T_oil_initial)
Plugging in the given values, we can solve for T_forging_initial:
90.8 kg * 434 J/(kg C°) * (T_forging_initial - 58.9°C) = 689 kg * 2680 J/(kg C°) * (58.9°C - 38.3°C)
Simplifying the equation:
90.8 * 434 * (T_forging_initial - 58.9) = 689 * 2680 * (58.9 - 38.3)
Solving for T_forging_initial:
T_forging_initial - 58.9 = (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)
T_forging_initial = 58.9 + (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)
Calculating the value:
T_forging_initial ≈ 1,090.42°C
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We can easily tell that a bowling ball rolling down an ally has energy of motion. But why would a scientist say that a white-hot piece of iron also has the energy of motion within it?
A white-hot iron piece has internal motion energy due to constant particle movement at the atomic and molecular levels, as per scientists. Thermal energy or heat energy is motion. Higher temperature means more kinetic energy and faster motion of atoms and molecules.
What is the energy of motion?White-hot iron vibrates atoms and molecules at high temperatures. Kinetic theory states that all matter is made up of moving particles. Motion occurs at the microscopic level, beyond eye view. Higher temperature = greater particle energy.
When a scientist refers to white-hot iron, they recognize its high temperature corresponds to increased kinetic energy and motion. Motion and energy at the atomic level are not visible like a bowling ball, but are fundamental traits of matter.
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