a capacitor charging circuit consists of a battery, an uncharged 20 μf capacitor, and a 4.2 kω resistor. at t = 0 s the switch is closed; 0.15 s later, the current is 0.54 ma . What is the battery's emf?

After the collision, the 5 kg object would move with a velocity of 9 m/s in the same direction as the initial velocity of the 15 kg object.

According to the Law of Conservation of Momentum, the total momentum before the collision is equal to the total momentum after the collision, provided no external forces are acting on the system.

The momentum of an object is defined as the product of its mass and velocity. Therefore, the momentum of the 15 kg object before the collision is given by:

Momentum of 15 kg object before collision = mass × velocity = 15 kg × 3 m/s = 45 kg·m/s

Since the 15 kg object transfers all of its momentum to the 5 kg object, the momentum of the 5 kg object after the collision will be equal to 45 kg·m/s. Let's denote the velocity of the 5 kg object after the collision as v.

Momentum of 5 kg object after collision = mass × velocity = 5 kg × v

According to the Law of Conservation of Momentum, we can equate the momentum before the collision to the momentum after the collision:

45 kg·m/s = 5 kg × v

Solving this equation for v, we find:

v = 45 kg·m/s / 5 kg = 9 m/s

Therefore, the velocity of the 5 kg object after the collision would be 9 m/s, in the same direction as the initial velocity of the 15 kg object.

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Based on the free-body diagram of the forces acting on the spring, we can determine that the normal force can be utilized as a compression force.

When considering a spring, it is important to consider its behavior when it is compressed. A free-body diagram of the forces acting on a spring that is being compressed can be used to determine if the normal force is being utilized as a compression force.In general, the normal force is a force that acts perpendicular to a surface. When an object is resting on a surface, the normal force acts in the opposite direction of gravity. However, when a spring is compressed, the normal force can act as a compression force. This is because the normal force is exerted by a surface, and in the case of a compressed spring, the surface is the object or force that is compressing the spring.In a free-body diagram of a compressed spring, the normal force is represented by an arrow pointing upwards.

This arrow represents the force that is being exerted on the spring by the object or force that is compressing it. The weight of the spring is represented by an arrow pointing downwards, and the tension force in the spring is represented by an arrow pointing upwards. If the normal force is greater than the weight of the spring, the spring will compress. If the normal force is less than the weight of the spring, the spring will expand.

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The temperature of the blue supergiant star would be hotter than the Sun.

We can determine this based on the concept of Wien's displacement law, which states that the wavelength of peak intensity emitted by a black body is inversely proportional to its temperature. The Sun, with its characteristic yellow-white light, has a temperature of approximately 5,500 degrees Celsius (5,773 Kelvin), which corresponds to a peak wavelength of around 500 nm. In comparison, the blue supergiant star emits high-intensity light with a wavelength of 400 nm, which is shorter than the Sun's peak wavelength. Since shorter wavelengths correspond to higher temperatures, the blue supergiant star must have a higher temperature than the Sun. These stars have surface temperatures typically exceeding 10,000 degrees Celsius (10,273 Kelvin) and can reach even higher temperatures, up to tens of thousands of degrees Celsius.

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Answer:

by taring a balance the process of weighing by difference is done automatically. When a balance is tared with an object, on the balance pan, the weight of the object will be automatically subtracted from reading until the balance is re-tared or zeroed

Answer:

by taring a balance the process of weighing by difference is done automatically. When a balance is tared with an object, on the balance pan, the weight of the object will be automatically subtracted from reading until the balance is re-tared or zeroed

Explanation:

The bicycle's average speed in kilometers per hour is: 23.81 km/h.  To calculate the bicycle's average speed in kilometers per hour, we have to use the formula for speed. The formula for average speed is: Speed = Distance ÷ Time

Let's first convert the distance covered by the bicycle to kilometers.

1 km = 1000 m

Therefore, 300.0 m = 0.3 km

Now we can calculate the average speed of the bicycle in kilometers per hour by dividing the distance by time and converting the answer to kilometers per hour.

Average speed = Distance ÷ Time

= 0.3 km ÷ 45.5 s

First, we have to convert the time to hours.1 hour = 60 minutes and 1 minute

= 60 seconds

Therefore, 1 hour = 60 × 60

= 3600 seconds

Now we can convert the time to hours.

Time = 45.5 s ÷ 3600 s/hour

= 0.0126 hours

Therefore, the bicycle's average speed in kilometers per hour is:

Average speed = 0.3 km ÷ 0.0126 hours

= 23.81 km/h (rounded to two decimal places).

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Answer:

The answer is B.

Explanation:

Two particles are separated by 0.38 m, and the force between the particles, if the distance is doubled, is F = -2.83 × 10⁻⁷ N.

It is the type of field where the magnetic force is obtained. With the help of a magnetic field.

The magnetic force is obtained, it is the field felt around a moving electric charge.

Putting the values in the equation to calculate the force

[tex]F = 9 \times 10^9 \times \dfrac{-6.2 \times 10^-^6 \times 2.91 \times 10^-^9}{0.38} =\ -2.83 \times 10^-^7 N[/tex]

Thus, the force [tex]\rm F =\ -2.83 x 10^-^7 N[/tex]

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When separated by 4 meters, the 20,000-kilogram truck and the 3,200-kg automobile are attracted to one other with a force of attraction of roughly 0.0000016748 N. The right response in this case is option A.

Newton's rule of universal gravitation, which says that the force between two things is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers, may be used to compute the force of attraction between two objects. The equation can be written mathematically as:

F = G * (m1 * m2) / r^2

Where:

F is the gravitational constant, while G is the force of attraction.

The two objects' masses are m1 and m2, and their separation from one another's centers is r.

In this instance, the truck weighs 20,000 kg, whereas the automobile weighs 3,200 kg. They are 4 meters apart from one another.

With these values entered into the formula, we obtain:

F = (6.674 × 10^-11 N(m/kg)^2) * (20,000 kg * 3,200 kg) / (4 m)^2

F = 1.6748 × 10^-6 N

Therefore, at a distance of 4 meters, the force of attraction between the 3,200-kilogram automobile and the 20,000-kg truck is roughly 0.0000016748 N.

Option A is therefore the one that comes the closest to this value, at 0.0003 N.

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The formula for a projectile's position function is given as follows:

s(t) = -16t² + v₀t + s₀

Where: v₀ is the initial velocity

s₀ is the initial position

t is the time elapsed

Let's calculate s(t) for the given data.

The projectile is fired vertically upwards with an initial velocity of 224 ft/s,

so v₀ = 224 ft/s.

Since the projectile is fired upwards, its initial position is 0 ft.

Therefore,

s₀ = 0 ft.

Substituting the function in the formula, s(t) = -16t² + 224t + 0s(t)

= -16t² + 224t

The position function of the projectile is s(t) = -16t² + 224t.

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The escape velocity of the spacecraft, launched from the surface, is about 10.3km/s, and when launched from a height of 13R, its orbital velocity would be around 7.53km/s.

We need to understand the basics of how human-made objects are launched into space and the effect of gravity on such bodies.

Any satellite or spacecraft launched into space first needs a certain speed to orbit around the planet. Any speed less than this would result in the spacecraft falling back into the planet due to its gravity. This speed is needed to beat the centripetal force on the satellite.

This velocity is known as the orbital velocity of the body.

In a few cases, we need the body to be sent out of the gravitational field of the planet, thus allowing it to explore planets and moons outside the field. This would require an even larger velocity, by inference. We need the body to not stop before it crosses the boundaries of the planet's field

This velocity is known as the escape velocity of the body.

Now, we define the expressions for these velocities, from the surface.

V (Orbital) = √(G*M/R)

V (Escape) = √(2*G*M/R)

Notice that escape velocity is √2 times the orbital velocity for any planet.

In the question, we have

M = 4.87E + 24

R = 6.05E + 3   for Venus

So,

The escape velocity from the surface

V  =   √2 *√[6.67*10⁻¹¹ *(4.87E + 24)/6.05E + 3]

V  ≈   10,356 m/s = 10. 35 km/s

For orbital velocity, we need to take into consideration the height of the body.

Thus, in place of R (dist. from the center), we use

new R = R + 13R = 14R

So, the orbital velocity from the given height is:

V = √[6.67*10⁻¹¹ *(4.87E + 24)/14(6.05E + 3)]

V = 7531 m/s = 7.53km/s

Thus, the orbital velocity for the body is 7.53km/s from the height of 13R, and the escape velocity is 10.35km/s.

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A ray of light is refracted by an angle of 34.5 as it enters water from glass. We need to find the angle of incidence.If the angle of refraction is given, we can find the angle of incidence using Snell's law.

Snell's law states that the ratio of the sines of the angles of incidence and refraction is constant for a given pair of media. The formula is n1sinθ1 = n2sinθ2, where n1 and n2 are the refractive indices of the two media and θ1 and θ2 are the angles of incidence and refraction, respectively.

So, we can use this formula to find the angle of incidence. Given, the angle of refraction, θ2 = 34.5 degrees.The refractive indices of glass and water are 1.5 and 1.33 respectively. So, we can substitute these values in the formula and solve for the angle of incidence.n1sinθ1 = n2sinθ2⇒ sinθ1 = (n2/n1) sinθ2⇒ sinθ1 = (1.33/1.5) sin 34.5⇒ sinθ1 = 0.753⇒ θ1 = sin⁻¹(0.753)≈ 49.9 degreesTherefore, the angle of incidence is approximately 49.9 degrees.

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The correct statement is MPK = 400K^(-0.2). This is because the marginal product of capital (MPK) is derived by taking the partial derivative of the production function with respect to capital (K), holding labor (L) constant

To find the marginal product of labor (MPL) and the marginal product of capital (MPK), we need to take partial derivatives of the production function Q = 500L^0.6K^0.8 with respect to each input.

First, let's find MPL:

∂Q/∂L = 500 * 0.6 * L^(0.6-1) * K^0.8

Simplifying, we have:

MPL = 300L^(-0.4)K^0.8

Comparing this with the given options, we see that MPL = 300L^(-0.4)K^0.8 is not one of the options. Therefore, this option is not true.

Now, let's find MPK:

∂Q/∂K = 500 * 0.8 * L^0.6 * K^(0.8-1)

Simplifying, we have:

MPK = 400L^0.6K^(-0.2)

Comparing this with the given options, we see that MPK = 400K^(-0.2) is one of the options. Therefore, this option is true. In conclusion, the correct statement is MPK = 400K^(-0.2).

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The degree of hearing loss is Mild to Moderate at these frequencies (1000 Hz and 2000 Hz).

A hearing threshold of 60 dB HL at 1000 Hz and 2000 Hz means that the person is experiencing mild to moderate hearing loss at these frequencies. dB HL stands for decibels hearing level, which is a measure of how loud a sound needs to be in order for someone to hear it compared to an average person with normal hearing. The degree of hearing loss at these frequencies (1000 Hz and 2000 Hz) is mild to moderate.

Hearing loss is defined by the decibel level of the softest sound a person can hear. The degree of hearing loss is determined by comparing the individual's hearing thresholds to a range of average thresholds. Mild hearing loss is characterized by thresholds between 25 and 40 dB HL, moderate hearing loss by thresholds between 40 and 60 dB HL, severe hearing loss by thresholds between 60 and 80 dB HL, and profound hearing loss by thresholds above 80 dB HL.

In this case, the person's hearing threshold at 1000 Hz and 2000 Hz is 60 dB HL, which falls within the range of mild to moderate hearing loss. Therefore, the degree of hearing loss at these frequencies is mild to moderate.

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Answer:

Scientific theories and laws develop from the acquisition of scientific knowledge.

Explanation:

t

Answer:

Mental time travel has been studied by psychologists, cognitive neuroscientists, philosophers and in a variety of other academic disciplines. Major areas of interest include the nature of the relationship between memory and foresight, the evolution of the ability (including whether it is uniquely human or shared with other animals), its development in young children, its underlying brain mechanisms, as well as its potential links to consciousness, the self, and free will.

Explanation:

The correct answer is O constant, but not necessarily zero.

When an object is made from a conducting material, the electric potential inside the object is constant. This is known as the "electrostatic equilibrium" of conductors. However, the value of the electric potential inside the conductor can be any constant value and is not necessarily zero.

In an electrostatic equilibrium, the charges within the conductor redistribute themselves in such a way that the electric field inside the conductor becomes zero. As a result, the electric potential inside the conductor remains constant. This means that the electric potential is the same at all points inside the conductor, regardless of their location.

Therefore, option O constant, but not necessarily zero, is the correct answer. The electric potential inside a conducting object is constant throughout the object but can have any value, not necessarily zero.

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1. The compressibility of the aquifer skeleton is 1.84 x 10⁻⁴ m²/N.

2. The overall horizontal conductivity is 0.94 ft/day, and the overall vertical conductivity is 10.43 ft/day.

1. The compressibility of the aquifer skeleton can be calculated using the formula: Compressibility of aquifer skeleton = Specific storage / Porosity. Given the specific storage of 8.8 x 10⁻⁶ and porosity of 0.25, we can substitute these values into the formula to find that the compressibility of the aquifer skeleton is 8.8 x 10⁻⁶ / 0.25 = 1.84 x 10⁻⁴ m²/N.

2. To find the overall horizontal and vertical conductivity, we need to calculate the weighted average of the conductivities of each formation based on their thickness. The overall horizontal conductivity is obtained by summing up the product of each formation's thickness and conductivity and dividing by the total thickness: (30 ft x 0.7 ft/day + 15 ft x 78 ft/day + 22 ft x 17 ft/day) / (30 ft + 15 ft + 22 ft) = 0.94 ft/day. Similarly, the overall vertical conductivity is calculated using the same formula: (30 ft x 0.7 ft/day + 15 ft x 78 ft/day + 22 ft x 17 ft/day) / (30 ft + 15 ft + 22 ft) = 10.43 ft/day.

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The newton third law of motion and the second law of motion should be applied in different situations.

In the case when it is not at the time when empty hangs lightly should be against the wall because here there is the inverse reaction force should be on you. So here the third law should be used.

In the case when we carry a heavy load so our hand should be hurt due to the downward force act so here the second law should be used.

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At Jupiter's orbit, the solar radiation flux is approximately 50 W/m^2, while Jupiter's total luminosity is estimated at 3.823x10^17 Watts.

(a) The flux of solar radiation at a given distance from the Sun can be determined using the inverse square law. According to the law, the intensity of radiation decreases with the square of the distance. The luminosity of the Sun, which is the total power it radiates, is approximately 3.828x10^26 Watts. Therefore, at the orbit of Jupiter, which has a radius of dJ = 7.78x10^11 m, the flux of solar radiation can be calculated as follows:

Flux = Luminosity / (4 * π * distance^2)

Flux = 3.828x10^26 / (4 * π * (7.78x10^11)^2)

Flux ≈ 50 W/m^2

(b) The albedo of an object represents the fraction of incident radiation that is reflected. In this case, Jupiter's albedo is given as A = 0.5, meaning that 50% of the radiation it receives is reflected. To calculate Jupiter's total luminosity, we need to consider both the absorbed and reflected radiation.

Luminosity = (1 - Albedo) * Flux * Surface Area

The surface area of a sphere can be calculated using its radius (RJ) as follows:

Surface Area = 4 * π * (radius^2)

Surface Area = 4 * π * (7.14x10^7)^2

Substituting the values into the formula, we get:

Luminosity = (1 - 0.5) * 50 * 4 * π * (7.14x10^7)^2

Luminosity ≈ 3.823x10^17 Watts

Therefore, Jupiter's total luminosity, accounting for its albedo, is estimated to be approximately 3.823x10^17 Watts.

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Answer:

Acceleration = 29 m/s^2, Force = 203 N

Explanation:

The acceleration is given to you in the problem.

If you're trying to find the force and not acceleration:

1. Find the equation for force.

F = ma

2. Plug in what has been given to you in the problem.

F = 7kg × 29m/s^2

F = 203 N

Remember:

Newton = kg × m/s^2

Part A: The average power output of the human sprinter is approximately 1002.3 watts.

Part B: The average power output of the greyhound is approximately 2746.3 watts.

Part A: To calculate the average power output of the human sprinter, we can use the formula ΔE/Δt, where ΔE is the change in energy and Δt is the time interval. The change in energy can be calculated using the formula ΔE = (1/2)mv², where m is the mass and v is the final velocity.

ΔE = (1/2) * 73 kg * (10 m/s)² = 3650 J

The time interval is given as 3.5 seconds, so we can now calculate the average power:

Average power = ΔE/Δt = 3650 J / 3.5 s ≈ 1002.3 W

Therefore, the average power output of the human sprinter is approximately 1002.3 watts.

Part B: Similarly, for the greyhound, we can calculate the change in energy using the same formula:

ΔE = (1/2) * 29 kg * (20 m/s)² = 11600 J

Using the same time interval of 3.5 seconds, we can calculate the average power:

Average power = ΔE/Δt = 11600 J / 3.5 s ≈ 2746.3 W

Therefore, the average power output of the greyhound is approximately 2746.3 watts.

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Answer: Yes, many vehicles passing through non-cemented roads cause soil erosion.

Explanation: Soil erosion is a gradual process that occurs when the impact of water or wind removes upper layer of soil particles, causing the soil to deteriorate. Since the road is non-cemented so the soil is all exposed to the everything. When a vehicle pass through it the motion of the vehicles causes a mild wind which sweeps away the upper layer of the soil. When a lot many vehicles pass, the quantity soil being swept away increases which leads to soil erosion.

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To find the speed at which the bicycle is traveling, we can use the formula that relates the circumference of the wheel to the distance covered in one revolution. By multiplying the circumference by the number of revolutions per minute, we can determine the speed of the bicycle.

The circumference of a circle can be calculated using the formula C = 2πr, where r is the radius of the circle. In this case, the bicycle wheels have a diameter of 26 inches, so the radius is half of that, which is 13 inches. Converting the diameter to inches, the circumference of each wheel is 2π(13) = 26π inches.

Given that the wheels are rotating at 160 RPM, we can multiply the circumference by the number of revolutions per minute to find the distance covered in one minute. This can be converted to the speed in inches per minute.

To obtain the speed in a more common unit, we can convert inches per minute to miles per hour by using appropriate conversion factors. Finally, rounding the answer to three decimal places provides the speed at which the bicycle is traveling down the road.

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The position function of the particle is obtained by integrating the given velocity function. The sign of the coefficient of the highest-degree term in the position function indicates the direction of the particle's movement (left or right).

To determine the particle's position, we need to integrate its velocity function with respect to time. Given that the velocity function is v(t) = t^2 - 9t + 18, we can find the position function by integrating it.

∫(t^2 - 9t + 18) dt

Integrating each term separately:

∫t^2 dt - ∫9t dt + ∫18 dt

Using the power rule of integration, we get:

(1/3)t^3 - (9/2)t^2 + 18t + C

Where C is the constant of integration.

This is the position function, which represents the distance the particle has traveled from some reference point. The position function can provide information about whether the particle is moving left or right based on the signs of the terms. If the coefficient of the t^3 term is positive, it indicates that the particle is moving to the right, and if it is negative, it indicates movement to the left.

Please note that without specific initial conditions or a definite time interval, we cannot determine the exact position or direction of the particle. Additional information is needed to provide a more specific analysis of its motion.

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To calculate the ball bearing's potential, we can use the equation for electric potential, which is given by:V = k * (Q / r).The ball bearing's potential is approximately 5.70 × [tex]10^{-7}[/tex] volts.

In this case, we are given the diameter of the ball bearing, so we need to calculate the radius (r) first:

Radius (r) = Diameter / 2 = 1.40 mm / 2 = 0.70 mm = 0.70 × [tex]10^{-3}[/tex] m

The excess charge is given as 2.20 × [tex]10^{9}[/tex] electrons. To convert this to Coulombs, we need to multiply it by the elementary charge (e), which is approximately 1.602 × [tex]10^{-19}[/tex] C.

Charge (Q) = (2.20 × [tex]10^{9}[/tex]) × (1.602 × [tex]10^{-19}[/tex]) C

Now we can calculate the potential (V):where k is the Coulomb constant (k ≈ 8.99 × [tex]10^{9}[/tex]10^9 [tex]N m^2/C^2[/tex]),

V = (8.99 × [tex]10^{9}[/tex] [tex]N m^2/C^2[/tex]) * [(2.20 × [tex]10^{9}[/tex]) × (1.602 ×[tex]10^{-19}[/tex] ) C] / (0.70 × [tex]10^{-3}[/tex] m)

Calculating this expression gives:

V ≈ 5.70 ×[tex]10^{-7}[/tex]  V

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You have been informed by the carrier that your volume weight ratio is 1 m3 equals 1,000 kg. the chargeable weight for the following is  97,495 kg.

To calculate the chargeable weight for the given scenario, we need to consider the dimensions and weight of each crate. Each crate has dimensions of 6 feet in length, 7.5 feet in width, and 15 feet in height, and a weight of 750 kg.

First, we convert the dimensions of each crate from feet to meters. Since 1 foot is equal to 0.3048 meters, the dimensions become 1.83 meters in length, 2.29 meters in width, and 4.57 meters in height.

Next, we calculate the volume of each crate by multiplying the length, width, and height:

Volume = 1.83 m * 2.29 m * 4.57 m = 19.499 m^3

Since we have 5 crates, we multiply the volume of each crate by 5 to get the total volume:

Total Volume = 19.499 m^3 * 5 = 97.495 m^3

According to the given volume weight ratio of 1 m^3 equals 1,000 kg, the volume weight of the shipment is:

Volume Weight = 97.495 m^3 * 1,000 kg/m^3 = 97,495 kg

Finally, we compare the actual weight of each crate (750 kg) to the volume weight (97,495 kg) and choose the higher value as the chargeable weight. In this case, the chargeable weight for the shipment would be 97,495 kg.

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When the user clicks the play button next to the orbit in the upper left, the planet should move around the elliptical orbit, and two segments of the orbit should become shaded in green. The two aspects of the orbit and shaded segments that are the same are the equal areas that are swept out in equal time.

The shaded segments are swept over the equal amount of time when the planet moves in the elliptical orbit. Kepler's Second Law is based on the principle of equal areas in equal time. This law implies that a planet in an elliptical orbit has a rate of motion that varies depending on its location. A planet moves faster near the Sun than it does farther away because the radius between the Sun and the planet varies during its orbit.

As a result, a planet in an elliptical orbit moves in an elliptical orbit with varying velocities, making equal areas of the orbit swept in equal time. When the user clicks the play button next to the orbit in the upper left, the planet should move around the elliptical orbit, and two segments of the orbit should become shaded in green. The two aspects of the orbit and shaded segments that are the same are the equal areas that are swept out in equal time.

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The orbital speed of the satellite is approximately 1.19 x 10^7 m/s. To find the orbital speed of a satellite, we first need to find the radius of the satellite's orbit.

We can use the period of the satellite's orbit and the gravitational force between the satellite and the Earth. The period (T) of an orbit is the time it takes for the satellite to complete one full revolution.  In this case, the period is given as 1.60 x 10^4 s. The gravitational force (F) between the satellite and the Earth is given by the equation:

F = (G * m1 * m2) / r^2

Where G is the gravitational constant (approximately 6.674 x 10^-11 Nm^2/kg^2), m1 is the mass of the satellite, m2 is the mass of the Earth, and r is the radius of the satellite's orbit.

Since the gravitational force provides the necessary centripetal force for the satellite to maintain its orbit, we can equate the gravitational force to the centripetal force:

F = (m * v^2) / r

Where m is the mass of the satellite and v is the orbital speed.

By equating the two expressions for the force, we can solve for the orbital speed:

(G * m1 * m2) / r^2 = (m * v^2) / r

Rearranging the equation:

v^2 = (G * m2) / r

Taking the square root of both sides:

v = sqrt((G * m2) / r)

Now, we can substitute the given values: m2 = 5.97 x 10^24 kg (mass of the Earth) and T = 1.60 x 10^4 s (period).

First, let's find the radius (r) using the period (T):

T = (2 * π * r) / v

1.60 x 10^4 s = (2 * π * r) / v

Solving for r:

r = (T * v) / (2 * π)

Substituting the known values:

r = (1.60 x 10^4 s * v) / (2 * π)

Now, we can substitute this expression for r into the equation for orbital speed:

v = sqrt((G * m2) / r)

v = sqrt((G * m2) / ((1.60 x 10^4 s * v) / (2 * π)))

Simplifying the equation by squaring both sides:

v^2 = (G * m2) / ((1.60 x 10^4 s * v) / (2 * π))

Multiplying both sides by (1.60 x 10^4 s * v) / (2 * π):

v^2 * ((1.60 x 10^4 s * v) / (2 * π)) = G * m2

Expanding and rearranging the equation:

v^3 = (G * m2 * (1.60 x 10^4 s)) / (2 * π)

Now, we can substitute the values: G = 6.674 x 10^-11 Nm^2/kg^2 and m2 = 5.97 x 10^24 kg:

v^3 = (6.674 x 10^-11 Nm^2/kg^2 * 5.97 x 10^24 kg * (1.60 x 10^4 s)) / (2 * π)

Simplifying the equation:

v^3 = 1.074 x 10^20

Taking the cube root of both sides:

v = (1.074 x 10^20)^(1/3)

Calculating the value, we find:

v ≈ 1.19 x 10^7 m/s

Therefore, the orbital speed of the satellite is approximately 1.19 x 10^7 m/s.

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Answer:

c. limit the scope of the study

Explanation:

i did it.

Answer:

c limit the scope of the study

Explanation:

The electric field in front of a nonconducting wall with a charge density of 8.52 μC/cm² is approximately 4.82 × 10⁶ N/C. To find the electric field in front of a nonconducting wall with a uniform charge density, we can use the formula for the electric field due to a charged plane:

E = σ / (2ε₀)

where E is the electric field, σ is the charge density, and ε₀ is the permittivity of vacuum.

Given that the charge density is 8.52 μC/cm², we need to convert it to the appropriate units. 1 μC/cm² is equal to 10⁻⁶ C/m². Therefore, the charge density becomes 8.52 × 10⁻⁶ C/m².

Substituting the values into the formula, we have:

E = (8.52 × 10⁻⁶ C/m²) / (2 × 8.8542 × 10⁻¹² C²/(N·m²))

Simplifying the expression, we get:

E = 4.82 × 10⁶ N/C

Therefore, the electric field 9.7 cm in front of the wall is approximately 4.82 × 10⁶ N/C.

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