In order to solve this question, we will need to use kinematics
Let's see what is given to us:
Distance traveled is 137 meters
Time elapsed is 9.6 seconds
and inital velocity is 0 m/s
Since we are trying to find acceleration, we can use this formula
[tex]\Delta x=v_0t+\frac{1}{2}at^2[/tex]Where Δx is the distance traveled, v0 is the inital velocity, t is time, and a is acceleration
Plugging in what we have, we get
137 = 0(9.6) + 1/2(a)(9.6)^2
Solving for a, we get 2.97 m/s^2
Three liquids are at temperatures of 10 ◦C, 22◦C, and 29◦C, respectively. Equal masses of the first two liquids are mixed, and the equi- librium temperature is 12◦C. Equal masses of the second and third are then mixed, and theequilibrium temperature is 25.9◦C.Find the equilibrium temperature when equal masses of the first and third are mixed.Answer in units of ◦C.
Question 1: Assume that the pendulum of a grandfather clock acts as one of Planck'sresonators. If it carries away an energy of 8.1 x 10-15 eV in a one-quantumchange, what is the frequency of the pendulum? (Note that an energy this smallwould not be measurable. For this reason, we do not notice quantum effects in thelarge-scale world.)
Given:
Energy = 8.1 x 10⁻¹⁵ eV.
Let's find the frequency of the pendulum.
To find the frequency, apply the formula for the energy of a light quantum:
[tex]E=hf[/tex]Where:
E is the energy
h is Planck's constant = 6.63 x 10⁻³⁴ m² kg/s
f is the frequency.
Where:
1 eV = 1.6 x 10⁻¹⁹ J.
Rewrite the formula for f and solve:
[tex]f=\frac{E}{h}[/tex]Thus, we have:
[tex]f=\frac{8.1\times10^{-15}*(1.6\times10^{-19})}{6.63\times10^{-34}}[/tex]Solving further:
[tex]\begin{gathered} f=\frac{8.1\times10^{-15}*(1.6\times10^{-19})}{6.63\times10^{^{-34}}} \\ \\ \\ f=1.95\text{ Hz.} \end{gathered}[/tex]Therefore, the frequency of the pendulum is 1.95 Hz.
ANSWER:
1.95 Hz
Bella is approaching some congested traffic and wisely slows her Audi from 19.6 m/s to 3.7 m/s at a constant rate of -3.33 m/s/s. How much time elapses before the car is traveling at 3.7 m/s?
The Time that elapses before the car is traveling at 3.7 m/s is 4.8 s.
What is time?Time is a measure of non-stop, consistent change in our surroundings, usually from a specific viewpoint.
To calculate the time require for the to be traveling at 3.7 m/s, we use the formula below.
Formula:
t = (v-u)/a........... Equation 1Where:
t = Timev = Final velocityu = Initial velocitya = AccelerationFrom the question,
Given:
v = 3.7 m/su = 19.6 m/sa = - 3.33 m/s²Substitute these values into equation 1
t = (19.6-3.7)/-3.33t = -15.9/-3.33t = 4.8 sHence, the time need for the car to start traveling at 3.7 m/s is 4.8 s.
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the earth moves at a speed of 2.95*10^4m/s and has a mass of 6.0*10^24. calculate the momentum of the earth
Given:
the speed of the earth is
[tex]v=2.95\times10^4\text{ m/s}[/tex]mass of the earth is
[tex]m=6.0\times10^{24}\text{ kg}[/tex]Required:
momentum of the earth needs to be calculated.
Explanation:
To calculate the momentum of the earth we will use momentum formula that is given as
[tex]P=mv[/tex]here P is momentum, m is the mass of the earth and v is the velocity of the earth.
plugging all the values in the above relation. we get,
[tex]\begin{gathered} P=6.0\times10^{24}\text{ kg }\times2.95\times10^4\text{ m/s} \\ P=\text{ 17.7 }\times10^{28}\text{ kg m/s} \end{gathered}[/tex]Thus, the momentum of the earth is
[tex]P=\text{17.7}\times10^{28}\text{kg\frac{m}{s}}[/tex]A hiker walks 14.91 m, N and 4.40 m, E. What is the magnitude of his resultant displacement?
Givens.
• 14.91 meters North.
,• 4.40 meters East.
First, make a diagram to visualize the vectors and the resultant displacement.
In the figure, the purple vector d represents the resultant displacement, which horizontal component is 4.40m and its vertical component is 14.91m.
Let's use the following formula to find the resultant.
[tex]d=\sqrt[]{(y_{})^2+(x)^2}[/tex]Where y = 14.91 and x = 4.40.
[tex]\begin{gathered} d=\sqrt[]{(14.91m)^2_{}+(4.40m)^2} \\ d=\sqrt[]{222.31m^2+19.36m^2} \\ d=\sqrt[]{241.67m^2} \\ d\approx15.55m \end{gathered}[/tex]Therefore, the magnitude of the resultant displacement is 15.55m.
But, the resultant displacement refers to the vector, which is the following
[tex]d=(4.4i+14.91j)m[/tex]you have entered a 134-mile biathlon that consists of a run and a bicycle race. During your run, your average velocity is 6 miles per hour, and during your bicycle ace, your average velocity is 29 miles per hour. You finish the race in 7 hours. What is the distance of the run? What is the distance of the bicycle race?upposeWhat is the distance of the run?miles
ANSWER:
Distance of the run: 18 miles
Distance of the bicycle race: 116 miles
STEP-BY-STEP EXPLANATION:
Given:
Total distance = 134 miles
Total time = 7 hours
Average velocity during running = 6 mph
Average velocity during bicycle = 29 mph
Let x be the running distance and y be the bicycle distance.
We know that velocity equals distance in a given time, like this:
[tex]\begin{gathered} v=\frac{d}{t} \\ \\ \text{ Therefore:} \\ \\ t=\frac{d}{v} \end{gathered}[/tex]Knowing the above, we can establish the following system of equations:
[tex]\begin{gathered} t_1+t_2=7\rightarrow\frac{d_1}{v_1}+\frac{d_2}{v_2}=7\rightarrow\frac{x}{6}+\frac{y}{29}=7\text{ \lparen1\rparen} \\ \\ x+y=134\rightarrow x=134-y\text{ \lparen2\rparen} \end{gathered}[/tex]We substitute the second equation in the first and obtain the following:
[tex]\begin{gathered} \frac{134-y}{6}+\frac{y}{29}=7 \\ \\ \frac{(134-y)(29)+6y}{6\cdot29}=7 \\ \\ \frac{3886-29y+6y}{174}=7 \\ \\ 3886-23y=7\cdot174 \\ \\ y=\frac{1218-3886}{-23}=\frac{-2668}{-23} \\ \\ y=116\rightarrow\text{ bicycle distance} \\ \\ \text{ now, for x:} \\ \\ x=134-116 \\ \\ x=18\rightarrow\text{ running distance} \end{gathered}[/tex]Therefore:
The distance of running is 18 miles and the distance by bicycle is 116 miles.
A beaker of mass 1.2 kg containing 2.5 kg of water rests on a scale. A 3.8 kg block of a metallic alloy of density 3300 kg/m3 is suspended from a spring scale and is submerged in the water of density 1000 kg/m? as shown in the figure. a) What does the hanging scale read? acceleration of gravity is 9.8 m/s?Answer in units of N.b) what does the lower scale read? Answer in units of N.
ANSWER:
a) 25.97 N
b) 47.53 N
STEP-BY-STEP EXPLANATION:
Given:
Beaker mass = 1.2 kg
Water mass = 2.5 kg
Water density = 1000 kg/m^3
Block mass = 3.8 kg
Block density = 3300 kg/m^3
a)
The first thing is to calculate the volume of the block, like this:
[tex]\begin{gathered} d=\frac{m}{V} \\ V=\frac{m}{d} \\ \text{ we replacing} \\ V=\frac{3.8}{3300} \\ V=0.00115m^3 \end{gathered}[/tex]Mass of water displaced by the block is:
[tex]\begin{gathered} d=\frac{m}{V} \\ m=d\cdot V \\ m=1000\cdot0.00115 \\ m=1.15kg \end{gathered}[/tex]The block will receive a push from the water equal to the weight of the water displaced by the block, or the effective weight of the block will be reduced by the same amount:
[tex]\begin{gathered} W=(m_b-m)\cdot g \\ \text{ we replacing} \\ W=(3.8-1.15)\cdot9.8 \\ W=25.97\text{ N} \end{gathered}[/tex]Therefore, 25.97 N is the reading on the hanging scale.
b)
The bottom scale will gain by the same amount (1.15 kg). Therefore, the totalweight on the bottom scale is:
[tex]\begin{gathered} W=(1.2+2.5+1.15)\cdot9.8 \\ W=4.85\cdot9.8 \\ W=47.53\text{ N} \end{gathered}[/tex]Therefore, 47.53 N is the reading on the lower scale.
How much heat is necessary to change 480 g of ice at -19°C to water at 20°C? answer in:____kcal
ANSWER
[tex]18.05\text{ }kcal[/tex]EXPLANATION
The amount of heat necessary to change the ice to water is given by:
[tex]Q=m(c_{ice}\Delta T_{ice}+L+c_{water}\Delta T_{water})[/tex]where m = mass of ice = 480 g = 0.48 kg
c(ice) = specific heat capacity of ice = 2108 J/kg/K
ΔTice = change in temperature of ice = 0 - (-19) = 19 K or 19 °C
L = latent heat of fusion of ice = 33600 J/k
c(water) = specific heat capacity of water = 4186 J/kg/K
ΔTwater = change in temperature of water = 20 - 0 = 20 K or 20 °C
Therefore, the heat necessary is:
[tex]\begin{gathered} Q=0.48([2108*19]+33600+[4186*20]) \\ \\ Q=0.48(40052+33600+83720)=0.48*157372 \\ \\ Q=75538.56\text{ }J \end{gathered}[/tex]Convert this to kcal:
[tex]\begin{gathered} 1\text{ }J=\frac{1}{4184}\text{ }kcal \\ \\ 75538.56\text{ }J=\frac{75538.56}{4184}\text{ }kCal=18.05\text{ }kcal \end{gathered}[/tex]That is the answer.
Which of the following is a graph of the velocity of an object as it falls fromrest if drag is not ignored? Explain your choice
The air drag is a force that depends on the speed of an object relative to the wind. Under certain conditions, it can be modeled as:
[tex]F=-bv[/tex]Where b is a constant.
As a falling object reaches a speed so that its weight is cancelled out by the air drag, the object will reach a maximum velocity.
In a speed vs time gaph, the speed would approach the maximum speed like an asymptote.
On the other hand, since the object falls from rest, the initial speed on the graph must be zero.
Taking these considerations into account, the correct graph for the movement of an object that falls from rest if air drag is not ignored, is option B.
If a 150 pound weight is on a frictionless surface, raised at an angle of 35 degrees, what is the tension in the rope that keeps it from sliding down? What is the force perpendicular to the surface?
This is the given situation.
Where m is the mass of the block and g is the acceleration due to gravity. It is given in the question, mg=150 pound=68.04 kg.
There are two components of weight. One along with x-direction and the other with negative y-direction.
x-component is
[tex]mg\sin \theta[/tex]y-component is
[tex]mg\cos \theta[/tex]Tension on the string is equal to the x-component of the weight. and the normal force,i.e. perpendicular force is equal and opposite to the y component of the weight. But tension is in opposite direction to the x-component of weight and perpendicular force is opposite to the y-component.
Therefore the tension is,
[tex]T=-mg\sin \theta=-68.04\times\sin 35^o=-39.03\text{ N}[/tex]And the normal force is,
[tex]N=mg\cos \theta=60.04\times\cos 35^o=55.74\text{ N}[/tex]Therefore the magnitude of the tension on the string is 39.03 N
And the normal force is 55.74 N
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how do i convert 5.6 kg in hg?
5.6 kg can be converted to hg using unitary method .
The unitary method is a process of finding the value of a single unit, and based on this value
here
kg = kilogram
hg = hectogram
1 kg = 10 hg
using unitary method , we can write
5.6 kg = 5.6 * 10 hg = 56 hg
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McKenna is performing an experiment. She is testing the relationship between the temperature of water, and how long it takes for rust to form on iron plates. If she finds that higher temperatures lead to lower times for rusting, what is the qualitative relationship?positive correlationno correlationnegative correlationinverse square correlation
As with the increase in the temperature, the time taken to form the rust on the iron plate decreases.
This correlation is known as a negative correlation.
Thus, the relationship between the temperature of the water and the time taken to form rust on the iron plate is a negative correlation.
Hence, the third option is the correct answer.
A vector has an x-componentof -309 m and a y-componentof 187 m.Find the magnitude and direction of thevector.
In order to find the magnitude we will follow the next formula
[tex]M=\sqrt[]{C^2_x+C^2_y}[/tex]Cx= -309
Cy=187
We substitute the values
[tex]M=\sqrt[]{(-309)^2+(187)^2}=361.18m[/tex]Then for the direction we need o use the next formula
[tex]\theta=\tan ^{-1}(\frac{Cy}{Cx})[/tex]We substitute the variables
[tex]\theta=\tan ^{-1}(\frac{187}{-309})=-31.181[/tex]In order to obtain the direction we need to add to the angle 180°
the direction is -31.181+180=148.82°
ANSWER
magnitud =361.18
direction =148.82°
You have measured a carts mass and observed that it changed position. What other information do you need to determine the carts momentum during that time? A. The carts electric charge. B. The net force on the cart. C. The displacement of the cart. D. The carts gravitational potential energy
Given that we know the mass and displacement of an object for a given amount of time, to determine the momentum we can use the fact that the change in momentum is equal to the impulse. This can be written as:
[tex]Ft=m\Delta v[/tex]Where:
[tex]\begin{gathered} F=\text{ net force} \\ t=\text{ time} \\ m=\text{ mass} \\ \Delta v=\text{ change in velocity} \end{gathered}[/tex]Therefore, we need to know the net force in order to determine the momentum in that time.
When will the force be balance and when will the force won’t be balance [unbalance]
A force is a pull or push of an object that causes it to accelerate. When there are more than one force acting on a body then we call this a system of forces.
Suppose that we have the following system of two forces:
Forces "a" and "b" are acting in opposite directions. If the forces have the same magnitude then the total acceleration in the object will be zero. When a system of forces produces no acceleration on an object we call this balanced force.
If the magnitude of the forces is different then by Newton's second law we have;
[tex]F_a-F_b=ma[/tex]Where "m" is mass and "a" is acceleration. A system where the sum of forces is the product of mass by acceleration is called an unbalanced force.
6 identical books are lying on a desktop. a tidy student decides to stack the books one on top of the other. if students do 11 J of work width of the spine of each book is 2.5 what is the mass
How much does James have to pay for a vaccum cleaner that he uses for 4 hours a week. In James's neighborhood, the cost of electricity is 27 cents per kwhr.The power is P = 800 W
Given:
The power of the vacuum cleaner is P = 800 W = 0.8 kW
The time consumption is t = 4 hours a week.
The cost of electricity is 27 cents per kWh
To find the cost of the electricity for using the vacuum cleaner for a week.
Explanation:
First, we need to find the energy.
The energy can be calculated as
[tex]\begin{gathered} E=P\times t \\ =0.8\times4 \\ =3.2\text{ kWh} \end{gathered}[/tex]The cost of electricity per week due to vacuum cleaner will be
[tex]27\times3.2=86.4\text{ cents}[/tex]Final Answer: The cost of electricity James has to pay for a vacuum cleaner for using it 4 hours a week is 86.4 cents.
If a bullet leaves the muzzle of a rifle with a speed of 600 m/s, and the barrel of the rifle is 0.800 m long, at what rate is the bullet accelerated while in the barrel?That is the question I am having trouble with
Given that the final velocity of the bullet is
[tex]V_f=600\text{ m/s}[/tex]The initial velocity of the bullet is
[tex]V_i=0\text{ m/s}[/tex]The distance traveled by the bullet is x = 0.8 m
We have to find the acceleration.
Let the acceleration be denoted by a.
The equation which can be used to calculate acceleration is
[tex](V_f)^2-(V_i)^2=2ax[/tex]Substituting the values, acceleration will be
[tex]\begin{gathered} (600)^2-0^2=2\times a\times0.8 \\ a=\frac{360000}{1.6} \\ =225000m/s^2 \end{gathered}[/tex]Thus the acceleration will be 225000 m/s^2.
You deposit $2000 in an account earning 8% interest compounded monthly. How much will you have in the account in 5 years?
The amount in my account after 5 years, if a deposit $2000 will be $2985.62.
What is compound interest?Compound interest is the interest calculated on the principal and the interest accumulated over the previous period.
Tocalculate the amount, that will be in my account in 5 years, we use the formula below.
Fromula:
A = P(1+R/100n)ⁿˣ............... Equation 1Where:
A = AmountP = PrincipalR = Ratex = Timen = Total number of months in a yearFrom the question,
Given:
P = $2000R = 8%n = 12 monthsx = 5 yearsSubstitute these values into equation 1
A = 2000[1+8/(12×100)]⁵*¹²A = 2000(1+0.0067)⁶⁰A = 2000(1.0067)⁶⁰A = $2985.62Hence, the amount in my account will be $2985.62.
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A dog barks with an intensity level of 80 decibels. Two barking dogs produce what intensity level?
We are given that a dog barks with an inetensity level of 80 dB and asked to find out the intensity level produced by two barking dogs.
The combined intensity level of both dogs is the sum of each dog's intensity level.
[tex]\begin{gathered} I_{net}=I_1+I_2 \\ I_{net}=2I_{} \\ I_{net}=2\cdot I_0\cdot10^{\frac{\beta}{10}}_{} \end{gathered}[/tex]Where β is 80 dB and I0 is the reference intensity (1x10^-12 W/m^2)
[tex]\begin{gathered} I_{net}=2\cdot10^{-12}\cdot10^{\frac{80}{10}}_{} \\ I_{net}=2\cdot10^{-12}\cdot10^8_{} \\ I_{net}=2\cdot10^{-12+8} \\ I_{net}=2\cdot10^{-4} \end{gathered}[/tex]The net β is given by
[tex]\begin{gathered} \beta_{\text{net}}=10\log (\frac{I_{net}}{I_0}) \\ \beta_{\text{net}}=10\log (\frac{2\cdot10^{-4}}{10^{-12}}) \\ \beta_{\text{net}}=10\log (2\cdot10^{-4+12}) \\ \beta_{\text{net}}=10\log (20^8) \\ \beta_{\text{net}}=10(8.301) \\ \beta_{\text{net}}=83\; dB \end{gathered}[/tex]Therefore, two barking dogs produce 83 dB intensity level.
What is the wavelength range of electromagnetic radiation thehuman eye can detect?a 4 x 10-7 m to 8 x 10-7 mb 9 x 10-8 m to 11 x 10-9 mC 1x 10-4 m to 3 x 10-5 md 6 x 10-5 m to 7 x 10-5 m
The wavelength range of electromagnetic radiation the human eye can detect is:
a 4 x 10-7 m to 8 x 10-7 m
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Answer:
b heated gas will have decreased kinetic energy and decreased density
Explanation:
gas loses weight
Force acting on an object or system will NOT change the momentum.
From Newton's second law, the force acting on an object is given by the rate of change of momentum.
That is,
[tex]\begin{gathered} F=\frac{dp}{dt} \\ =\frac{d(mv)}{dt} \end{gathered}[/tex]Where p is the momentum of the object, m is the mass and v is the velocity of the object.
Thus, the force acting on an object will change its momentum.
Therefore the given statement is false.
The binding energy of a nucleus is always negative.Question 4 options:TrueFalse
ANSWER
False.
EXPLANATION
Nuclear binding energy is the energy that is required to split the nucleus (of an atom) into nucleons: protons and neutrons.
The binding energy of a nucleus is always positive because nuclei require energy to separate them and it is impossible for nuclei to gain energy by being separated.
Therefore, the answer is false.
6. A van of mass 1200 kg was moving at a velocity of 8 m/s when it was involved in a head-on collisionwith a lorry moving in the opposite direction. Assuming that the van came to a stop after the collision...(a) calculate the momentum of the van before the collision;(b) calculate the momentum of the van after the collision(c) find the change in momentum of the van (d) if the van took .30 s to stop, calculate the force that acted on each driver
Given data:
* The mass of the van is 1200 kg.
* The velocity of the van before the collision is 8 m/s.
* The velocity of the van after the collision is 0 m/s.
Solution:
(a). The momentum of the van before the collision is,
[tex]p_i=mv_i[/tex]where m is the mass of van, p_i is the momentum of van before the collision, and v_i is the velocity of van before the collision,
[tex]\begin{gathered} p_i=1200\times8 \\ p_i=9600kgms^{-1^{}} \end{gathered}[/tex]Thus, the momentum of the van before the collision is 9600 kgm/s.
(b). The momentum of the van after the collision is,
[tex]p_f=mv_f[/tex]weere p_f is the final momentum, and v_f is the final velocity of the van,
Substituting the known values,
[tex]\begin{gathered} p_f=1200\times0 \\ p_f=0^{} \end{gathered}[/tex]Thus, the momentum of the van after the collision is 0 kgm/s.
(c). The change in the momentum of the van is,
[tex]\begin{gathered} dp=p_f-p_i \\ dp=0-9600 \\ dp=-9600kgms^{-1} \end{gathered}[/tex]Here, the negative sign indicates that the momentum of van is decreasing with time.
Thus, the change in the momentum of the van is -9600 kgm/s.
(d). According to the Newton's second law, the force acting on the van in terms of the change in momentum is,
[tex]F=\frac{dp}{dt}[/tex]where dt is the time interval in which the momentum of the van changes,
Substituting the known values,
[tex]\begin{gathered} F=-\frac{9600}{0.30} \\ F=-32000\text{ N} \\ F=-32\times10^3\text{ N} \\ F=-32\text{ kN} \end{gathered}[/tex]Here, the negative sign is indicating the direction of force acting on the van is opposite to the direction of motion of van before the collision.
Thus, the force acting on the van is -32 kN.
Is it possible to get More work out of a machine than you put in?
If we were able to get more work out of a machine than we put in, energy would be created in the process. According to the Law of Conservation of Energy, this is not possible.
Therefore, the answer is:
[tex]\begin{gathered} \text{ No, it is not possible to get more work} \\ \text{ out of a machine than we put in.} \end{gathered}[/tex]A spaceship and an asteroid are moving in the same direction away from Earth with speeds of 0.8 c and 0.45 c, respectively. What is the relative speed between the spaceship and the asteroid?
Answer:
0.35c
Explanation:
The relative speed between the spaceship and the asteroid can be calculated as the difference between their speeds, so it is equal to
Relative speed = 0.8c - 0.45c
relative speed = 0.35c
Therefore, the answer is
0.35c
Determine the mass of an object when the period of oscillation is 11 s and spring constant is 10 N/m.
Answer:
30.65 Kg.
Explanation:
The period of oscillation T, the spring constant k, and the mass m are related by the following equation.
[tex]T=2\pi\sqrt[]{\frac{m}{k}}[/tex]So, solving for m, we get:
[tex]\begin{gathered} \frac{T}{2\pi}=\sqrt[]{\frac{m}{k}} \\ \frac{T^2}{4\pi^2}=\frac{m}{k} \\ \frac{T^2k}{4\pi^2}=m \\ m=\frac{T^2k}{4\pi^2} \end{gathered}[/tex]Therefore, replacing T = 11 s and k = 10 N/m, we get:
[tex]m=\frac{(11s)^2(10\text{ N/m)}}{4\pi^2}=30.65\text{ kg}[/tex]Then, the mass of the object is 30.65 Kg.
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Answer:
A. the speed of the object
Explanation:
The color wouldn't make any difference to the potential energy and knowing the mass the way the object is shaped or the height of it would make no difference
