The star whose absolute magnitude is 1.0 is 0.0128 pc away from the earth.
What is Star?Stars are huge celestial bodies made mostly of hydrogen and helium that produce light and heat from the churning nuclear forges inside their cores.
Given is a certain star has an absolute magnitude of 1.0 and an apparent magnitude of 5.4.
We can write the relation absolute magnitude [M] and apparent magnitude [m] as follows -
M = m + 5(log₁₀p + 1)
Assume that the star is [x] light years away from earth. Then, we can write the above equation as -
M = m + 5[log₁₀ (x/3.2616)+ 1]
1 = 5.4 + 5[log₁₀x - log₁₀ 3.2616 + 1]
1 - 5.4 = 5[log₁₀x - 0.5134 + 1]
- 4.4 = 5[log₁₀x + 0.4866]
- 4.4 = 5log₁₀x + 2.433
- 4.4 - 2.433 = 5log₁₀x
- 1.37 = log₁₀x
x = 0.042 light years
Now, in 1 pc there are 3.2616 light years.
In 1 light year there will be (1/3.2616) pc
So, in 0.042 light years there will be (1/3.2616 x 0.042) = 0.0128 pc
Therefore, the star whose absolute magnitude is 1.0 is 0.0128 pc away from the earth.
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A 96.3 kg cannon at rest contains a 9.5 kg cannon ball. When fired, the cannon ball leaves the cannon with a speed of 84.58 m/s. What is the recoil speed of the cannon?
Using conservation of momentum:
[tex]p1=p2[/tex]Since the cannon is at rest before shots the ball:
[tex]\begin{gathered} p1=0 \\ _{\text{ }}and \\ p2=mv+MV \end{gathered}[/tex]Where:
[tex]\begin{gathered} m=9.5kg \\ v=84.58\frac{m}{s} \\ M=96.3kg \end{gathered}[/tex]So:
[tex]0=9.5\cdot84.58+96.3V[/tex]Solve for V:
[tex]\begin{gathered} 96.3V=-9.5\cdot84.58 \\ 96.3V=-803.51 \\ V=-\frac{803.51}{96.3} \\ V\approx-8.34\frac{m}{s} \end{gathered}[/tex]Answer:
The recoil speed of the cannon is approximately 8.34 m/s
caracteristicas del sonido
In general, intensity, tone, timbre, and duration are the four subjective qualities used to describe musical sounds. Each of these characteristics depends on one or more physically measurable parameters.
What is sound and what are its characteristics?In physics, sound is any phenomenon that involves the transmission of mechanical waves, whether audible or not, through a fluid or solid medium while causing a body to vibrate.
The sensation of sound is one that is brought on by the vibrations of objects and occurs in the ear. An object vibrating generates airborne waves that are transmitted. People communicate with one another through sound, doing so by expressing their thoughts, emotions, and desires.
The sounds are divided into three categories based on their frequency: agudos (high frequency), medios (medium frequency), and graves (baja frecuencia).
There is no change in phase in the reflection when the airborne sound waves (also known as pressure waves) come into contact with a hard surface. To put it another way, when the high pressure portion of a sound wave strikes a wall, it is reflected as a high pressure rather than a low pressure, which would be a phase change.
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Professor Stauffer conducts basic research on the psychological, biological, and behavioral
factors that contribute to heart disease. She is most likely a
High blood pressure, high LDL cholesterol, diabetes, smoking, exposure to secondhand smoke, obesity, a poor diet, and inactivity are the main risk factors for heart disease and stroke.
Explain about the contribute to heart disease?High blood pressure, high cholesterol, and smoking are the three main risk factors for heart disease that at least half of all Americans (47%) have. Age and family history are two uncontrollable risk factors for heart disease.
The most frequent cause of coronary artery disease is atherosclerosis, which is a buildup of fatty plaques in the arteries. Poor diet, lack of exercise, obesity, and smoking are risk factors. Choosing a healthy lifestyle can help reduce the risk of atherosclerosis.
The most prevalent type of heart disease is coronary heart disease (CHD). It happens when plaque deposits cause the arteries that carry blood to the heart to constrict or stiffen. Fat, cholesterol, and other components found in blood make up plaque. The term "atherosclerosis" also refers to this plaque accumulation.
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A small sphere with charge q = 5.00 µC and mass 0.500 g is traveling horizontally toward the east at a height of 60.0 cm above the ground. The sphere has a speed of 2.00 m/s as it enters a region of uniform horizontal electric field with magnitude E directed to the east.
What is E if the sphere has a speed of 5.00 m/sm/s just before it strikes the ground?
If the sphere has a speed of 5.00 m/s just before it strikes the ground the value of E is given as 468.4N
How to solve for the value of Ewe have the following values to solve the problem with.
charge q = 5μc,
speed v = 2 m/s
height h = 60 cm
speed of sphere = 5 m/s
The Kinematic equation is given as
[tex]Y = V_{oy} T+\frac{1}{2} a_{y}t^{2}[/tex]
This is the time that it would take the sphere to hit the ground.
we have to insert the values
60 x 10⁻² = 0 + 1/2 (9.8)t²
t = 0.3499 sec
The sphere hits the ground at 0.3499 seconds
Vy = Voy + ayt
= 0 + 9.8 x 0.3499
= 3.429 m/s
Vn = 2 + qE/m (0,.3499)
= 2 + ((5 x 10⁻⁶) E /0.5 x 10⁻³)0.3499
= 2 + 2.499x10⁻³E
V = √Vx² + Vy²
5² = (2 + 3.499 x 10⁻³E)² + (3.429)²
13.241959 = (2 + 3.499 x 10⁻³E)²
3.638 = 2 + 3.499 x 10⁻³E
take like terms
1.6389 = 3.499 x 10⁻³E
to get E
1.6389 / 3.499 x 10⁻³
E = 468.4N
The value of E given the speed is given as 468.4 Newton
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Experiments and Data Collections and Interpreting Data
While studying paintball equipment, you may have learned that changes in temperature can cause paintballs to change size. At high temperatures, they swell, and at low temperatures, they shrink. This changes the way they fit in the marker barrel. You might affect their performance; if not, you can make an educated guess.
Include the following essential content:
* State a specific question about temperature and paintball performance.
Using the data provided, draw or create a simple graph that can be used to interpret the results.
Be sure to include these points:
*descriptive title
*dependent variable
*independent variable
*legend
At high temperatures, they swell, and at low temperatures, they shrink. This adjustment is the way they are in shape within the marker barrel. we may affect their overall performance.
Data Collection is the system of collecting and measuring statistics on focused variables in an established machine, which then allows one to reply to relevant questions and compare outcomes. statistics collection is a research issue in all study fields, which include physical and social sciences, humanities, and business.
Data Collection is the method of gathering and measuring facts on ation series variables of hobby, in a longtime systematic fashion that permits one to answer stated research questions, test hypotheses, and compare results.
Surveys, questionnaires and bureaucracy, completed online, in character or with the aid of smartphone, electronic mail or ordinary mail; awareness organizations and one-on-one interviews; and. direct observation of participants in a studies look at.
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What will be it’s final speed and kinetic energy after it has been moving for t=5sec
Given data:
* The force applied on the block is,
[tex]F_a=12.5\text{ N}[/tex]* The frictional force acting on the block is,
[tex]F_r=4.2\text{ N}[/tex]* The acceleration of the block is,
[tex]a=1.2ms^{-2}[/tex]Solution:
The net force acting on the block is,
[tex]\begin{gathered} F_{\text{net}}=F_a-F_r \\ F_{\text{net}}=12.5-4.2 \\ F_{\text{net}}=8.3\text{ N} \end{gathered}[/tex]According to Newton's second law, the net force in terms of the mass and acceleration of the block is,
[tex]\begin{gathered} F_{\text{net}}=ma \\ m=\frac{F_{\text{net}}}{a}_{} \end{gathered}[/tex]Substituting the known values,
[tex]\begin{gathered} m=\frac{8.3}{1.2} \\ m=6.92\text{ kg} \end{gathered}[/tex]As the block is initially at rest, thus, the initial speed of the block is u = 0 m/s.
By the kinematics equation, the final speed of the block after t = 5 seconds is,
[tex]\begin{gathered} v-u=at \\ v-0=1.2\times5 \\ v=6\text{ m/s} \end{gathered}[/tex]Thus, the final speed of the block after t = 5 seconds is 6 meters per second.
The kinetic energy of the block after t = 5 seconds is,
[tex]\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}\times6.92\times6^2 \\ K=124.56\text{ J} \end{gathered}[/tex]Thus, the kinetic energy of the block after t = 5 seconds is 124.56 joule.
What is the maximum speed of a wave on a cable with length of 50 m, mass of 200 kg, and a tension force of 1000 N apply to it?V= √ Ft/e
Given:
the length of the cable is
[tex]l=5\text{0 m}[/tex]the mass of the cable is
[tex]m=200\text{ kg}[/tex]the tension force on the cable is
[tex]T=1000\text{ N}[/tex]Required: velocity of the wave.
Explanation:
to find the velocity of the wave on a cable we use the formula that is given by
[tex]v=\sqrt[2]{\frac{T}{\mu}}[/tex]Where
[tex]T[/tex]is the tension force and
[tex]\mu[/tex]is mass per unit length.
first, we calculate the mass per unit length.
[tex]\begin{gathered} \mu=\frac{200\text{ kg}}{50\text{ m}} \\ \mu=4\text{ kg/m} \end{gathered}[/tex]now put this value in the above relation and solve for velocity, we get
[tex]\begin{gathered} v=\sqrt[2]{\frac{T}{\mu}} \\ v=\sqrt[2]{\frac{1000\text{ N}}{4\text{ kg/m}}} \\ v=15.81\text{ m/s} \end{gathered}[/tex]Thus, the speed of the wave is 15.81 m/s.
2
Carly mentions to her friends that her new scented oils have been helping heal her headaches. With no scientific evidence that this "aromatherapy"
actually works, her friends should caution her and tell her to be careful. What do Carly's friends think she may be diving into?
O A. astrology
OB. phrenology
OC. pseudoscience
O D. astronom
Carly's friends think she may be diving into pseudoscience .
When presented as pseudoscience, a claim, finding, or explanatory framework lacks the objectivity needed for scientific inquiry. Research that is based on dubious ideas, a defective experimental design, or unreliable data can also lead to pseudoscience.The word "pseudoscience" can be used to describe a single assertion or claim that is allegedly supported by facts or science but falls apart when put to the test of reason. A complicated system, like astrology, that claims to explain how astronomical occurrences cause and effect world events is another example of a pseudoscience. Many pseudosciences, like astrology, are reasonably safe.To know more about pseudoscience visit : https://brainly.com/question/12257058
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Some electric power companies use water to store energy.Water is pumped from a low reservoir to a high reservoir.To store the energy produced in 1.0 hour by a 180-MWelectric power plant, how many cubic meters of water willhave to be pumped from the lower to the upper reservoir?Assume the upper reservoir is an average of 380 m abovethe lower one. Water has a mass of for every 1.00 x 10^3 kg for every 1.0m^3.
Answer:
1.74 x 10⁵ m³
Explanation:
The power is equal to:
[tex]P=\frac{E}{t}\rightarrow E=Pt[/tex]Where P is the power, E is the energy and t is the time. So, we can calculate the energy replacing
P = 180 MW = 180 x 10⁶ W
t = 1 hour = 3600 s
So, the energy is
[tex]\begin{gathered} E=(180\times10^6\text{ W\rparen\lparen3600 s\rparen} \\ E=6.48\times10^{11}\text{ J} \end{gathered}[/tex]On the other hand, the energy stored will be potential, so
[tex]E=mgh[/tex]Where m is the mass, g is the gravity and h is the height. Solving for m and replacing E = 6.48 x 10^11 J, g = 9.8 m/s², and h = 380 m, we get:
[tex]\begin{gathered} m=\frac{E}{gh} \\ \\ m=\frac{6.48\times10^{11}\text{ J}}{9.8\text{ m/s}^2\text{ \lparen380 m\rparen}} \\ \\ m=1.74\times10^8\text{ kg} \end{gathered}[/tex]Finally, we can calculate the volume of the water in cubic meters using the given ratio that Water has a mass of 1.00 x 10^3 kg for every 1.0m^3, so
[tex]1.74\times10^8\text{ kg }\times\frac{1\text{ m}^3}{1\times10^3\text{ kg}}=1.74\times10^5\text{ m}^3[/tex]Therefore, the answer is 1.74 x 10⁵ m³
The principal of a local high school gave all students breakfast for one week. Teachers commented that students were more alert that week in the morning.
Students commented they were more alert and could concentrate in the morning after eating breakfast. What can be concluded based on the observations?
All principals should give free breakfast every morning.
If students eat breakfast they will be able to concentrate in school in the afternoon.
Teachers should serve breakfast to their students.
Students should eat breakfast to be more alert at school during the morning.
Answer:
D Students should eat breakfast to be more alert at school during the morning.
Explanation:
Because based on the information given they said the principal gave students breakfast and teacher's said the students were more alert and the only common sense answer is D because they are more active in class in the morning not afternoon.
Two coils , held in fixed positions , have a mutual inductance of 100 mH . What is the peak emf in one coil when the current in the other coil is i ( t ) = 10 sin ( 1000 t ) , where is in amperes and t is in seconds ?
The peak emf in one coil at the given current in the other coil is 1,000 A.
What is mutual inductance?Mutual Inductance between the two coils is defined as the property of the coil due to which it opposes the change of current in the other coil.
The peak emf in one coil when the current in the other coil is i ( t ) = 10 sin ( 1000 t ) depends on the mutual inductance and the peak current.
The peak emf in one coil is calculated as follows;
emf₀ = M di/dt
where;
M is the mutual inductancedi/dt is the rate of change of currentdi/dt = (10 x 1000) cos (1000 t)
di/dt = 10,000 cos(1000 t)
The peak rate of change of current from the derivative of di/dt = 10,000 A/s
emf₀ = (100 x 10⁻³) x (10,000 A/s)
emf₀ = 1,000 V
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A 2 kg object and a 1 kg object are dropped from the same height.
Given that the inertia
masses of these objects are not the same, what hypothesis explains
why the two objects
fall with the same acceleration?
Select one:
O a. The force of gravity is the same for the 1 kg object as for the 2 kg object
O b. The force of friction is the same for the 1 kg object as for the 2 kg object.
O c. The force of gravity on the 1 kg object is twice as great as on the 2 kg object.
Od. The force of friction on the 2 kg object is twice as great as on the 1 kg object.
c. The force of gravity on the 1 kg object is twice as great as on the 2 kg object hypothesis explains why the two objects fall with the same acceleration.
Why do heavier and lighter objects fall at the same pace when dropped from the same height?If you disregard air resistance, things falling close to the surface of the Earth accelerate roughly at 9.8 m/s2 (9.8 m/s2, or g) because of gravity. As a result, the objects' acceleration is the same, and as a result, their velocity is likewise rising steadily.
No matter how heavy the object is, if there is no air resistance, the rate of descent simply relies on how far the object has dropped. This indicates that if two things are dropped simultaneously from the same height, they will both touch the ground at the same moment.
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how the water falls connected to gravity?
Answer:
At the top of the waterfall, the water is higher in the gravitational field of the Earth and has gravitational potential energy. When it falls, the potential energy turns into kinetic energy. So energy is not created, it was there at the beginning, stored as potential energy.
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A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.49 radians with the horizontal. The frictional coefficients between the crate and plane are (s = 0.66, k = 0.21 ). What is the magnitude of the acceleration (in meters/second2) of this crate as it slides up the incline?
The acceleration of the crate as it slides up the incline is 2.06 m/s².
What is the acceleration of the crate?
The acceleration of the crate as it slides up the inclined plane is calculated as follows;
Apply the principle of Newton's second law of motion to determine the acceleration of the crate.
Ff = ma
kmg = ma
kg = a
where;
k is the coefficient of kinetic frictiong is acceleration due to gravitya is the acceleration of the cratea = (0.21 x 9.8 m/s²)
a = 2.06 m/s²
Thus, the acceleration of the crate as it slides up the incline depends on the coefficient of kinetic friction since the crate is in motion.
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HELP! Sketch the given vector and its horizontal and vertical components. Use trig ratios to find the magnitude of each component.
16 km 34 degrees N of W
Horizontal component = ?
Vertical component = ?
The x-component and the y-component of the given vector are -
[x] = - 13.36 a[x]
[y] = 8.947 a[y]
What is a vector quantity?A vector quantity is any physical quantity with both magnitude and direction. Examples - velocity, acceleration, displacement etc. Any vector quantity can be resolved into its components along the [x] and [y] axis as follows -
[x] component = AcosФ a[x]
[y] component = AsinФ a[y]
The resultant angle will be -
tanФ = |[y]|/|[x]|
Given is 16 km 34 degrees North of West
Now, in the image attached, it can be seen that a vector making an angle of 34 degrees is directed along the north of west. Now, the x-component will be -
[x] = 16 cos (34) -a[x] = - 13.36 a[x]
And, the y-component will be -
[y] = 16 sin (34) a[y] = 8.947 a[y]
Therefore, the x-component and the y-component of the given vector are -
[x] = - 13.36 a[x]
[y] = 8.947 a[y]
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To a mass m1 = 100 g of water at θ1 = 10°C we add a mass m2 = 60 g of water at θ2 = 55°C. Calculate the final temperature of the mixture? Data: Specific heat capacity of water in the liquid state: 4.18 kJ.kg -1 .K
Given:
The mass of water is m1 = 100 g = 0.1 kg
The temperature of the water is
[tex]\begin{gathered} \theta1=10^{\circ}\text{ C} \\ =10+273 \\ =283\text{ K} \end{gathered}[/tex]The mass of water is m2 = 60g = 0.06 kg
The temperature of the water is
[tex]\begin{gathered} \theta2=\text{ 55 }^{\circ}\text{C} \\ =55+273 \\ =328\text{ K} \end{gathered}[/tex]To find the final temperature of the mixture.
Explanation:
The final temperature of the mixture can be calculated by the formula
[tex]\begin{gathered} T=\frac{(m1\theta1+m2\theta2)}{(m1+m2)} \\ \text{ } \end{gathered}[/tex]On substituting the values, the final temperature will be
[tex]\begin{gathered} T=\frac{(0.1\times283)+(0.06\times328)}{(0.1+0.06)} \\ =293.625\text{ K} \\ =20.625\text{ }^{\circ}C \end{gathered}[/tex]Thus, the final temperature of the mixture is 20.625 degrees Celsius.
If Rodger wants to determine whether a baseball thrown at 100 m/s or a bowling ball thrown at 100 m/s will have more momentum, what is one measurement device he could use to figure this out, without actually throwing either ball?A. a rulerB. a stopwatchC. a balance scaleD. an accelerometer I chose C, I am not completely sure that I’m right
The momentum of an object is given by the product of its mass and its velocity:
[tex]p=mv[/tex]If both objects have the same velocity (in this case, 100 m/s), the object with the greater mass will have the greater momentum.
In order to measure the mass of an object, we can use a balance scale.
Therefore the correct option is C.
evaluate when 8.1p + 7.5r when p=6 and r=7
You have the following expression:
8.1p + 7.5r
if p=6 and r=7, you obtain for the previous expression:
8.1(6) + 7.5(7) = 48.6 + 52.5 = 101.1
Hence, the result is 101.1
What is the spring constant for a spring that stretches by 27 cm when a load of 200 N is suspended from it?1) 0.135 N/m2) 54 N/m3) 740 N/m4) 7.4 N/m
Given data:
Force;
[tex]F=200\text{ N}[/tex]Stretching;
[tex]\begin{gathered} x=27\text{ cm} \\ =0.27\text{ m} \end{gathered}[/tex]The force is given as,
[tex]F=kx[/tex]Here, k is the force constant.
The expression for the force constant is given as,
[tex]k=\frac{F}{x}[/tex]Substituting all known values,
[tex]\begin{gathered} k=\frac{200\text{ N}}{0.27\text{ m}} \\ =740.74\text{ N/m} \end{gathered}[/tex]Therefore, the force constant of the spring is 740.74 N/m. Hence, option (3); 740 N/m is the best choice.
While standing on a 3-foot ladder, a grapefruit is tossed straight up with an initial velocity of 45 fu/sec. The initial position of the grapefruit is 7 feet above the ground when it is released.Its height at time t is given by y = h(t) = -16t^2 + 45t + 7.A) How high does it go before returning to the ground? Round time to 2 decimal places to compute height. ___feet.b) How long does it take the grapefruit to hit the ground? Round time to 3 decimal places. ___ seconds
ANSWER:
A) 38.64 feet.
B) 2.960 seconds
STEP-BY-STEP EXPLANATION:
We have that the function that models the situation of the statement is the following:
[tex]h(t)=-16t^2+45t+7[/tex]A)
We can calculate this height, which would be the maximum height it can reach before it begins to decay, as follows:
[tex]\begin{gathered} t_v=-\frac{b}{2a} \\ \\ \text{ in this case b = 45, a = -16, we replacing:} \\ \\ t_v=-\frac{45}{-16\cdot2}=\frac{45}{32} \\ \\ t_v=1.406\text{ sec} \\ \\ \text{ Now, we replace in the function this time like this: } \\ \\ h(t)=-16\left(1.406\right)^2+45\left(1.406\right)+7 \\ \\ h(t)=38.64\text{ ft} \end{gathered}[/tex]Therefore, the height is equal to 38.64 feet.
B)
To determine the time when the ground, we must make the height 0 and solve for t, just like this:
[tex]\begin{gathered} 0=-16t^2+45t+7 \\ \\ -16t^2+45t+7=0 \\ \\ \text{ We use the general formula for quadratic equations} \\ \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \\ a=-16,b=45,c=7 \\ \\ \text{ We replacing} \\ \\ t=\frac{-45\pm\sqrt{45^2-4(-16)(7)}}{2(-16)} \\ \\ t=\frac{-45\pm\sqrt{2473}}{-32} \\ \\ t_1=\frac{-45+\sqrt{2473}}{-32}=-0.148 \\ \\ t_2=\frac{-45-\sqrt{2473}}{-32}=\:2.960 \end{gathered}[/tex]Therefore, the time is equal to 2.960 seconds
What is force equal to?
Answer 1:Mass plus acceleration
Answer 2:Mass minus acceleration
Answer 3:Mass multiplied by acceleration
A .5kg book is thrown at a speed of 3m/s. What type of energy does it have and how much?
Given:
The mass of the book is m = 0.5 kg
The speed of the book is v = 3 m/s.
To find the type of energy and how much.
Explanation:
As the book is in motion, the energy is kinetic energy.
The formula to calculate kinetic energy is
[tex]K.E.\text{ =}\frac{1}{2}mv^2[/tex]On substituting the values, the kinetic energy will be
[tex]\begin{gathered} K.E.=\frac{1}{2}\times0.5\times(3)^2 \\ =2.25\text{ J} \end{gathered}[/tex]Thus, the kinetic energy will be 2.25 J
Jennifer hits a stationary 0.20-kg ball, and it leaves her racket at 40 m/s. Time-lapse photography shows that the ball was in contact with the racket for 40 ms.What average force did the ball exert on the racket?Express your answer using two significant figures.What is the ratio of this force to the weight of the ball?Express your answer using two significant figures.
Given:
The mass of the stationary ball is: m = 0.20 kg.
The velocity of the ball when it leaves the rocket is: Vf = 40 m/s.
The time for which the ball was in contact with the rocket is: t = 40 ms = 0.04 s.
To find:
The average force the ball exerts on the rocket.
The ratio of the force on a rocket to the weight of the ball.
Explanation
As the ball is initially stationary, its initial velocity Vi is zero. After the ball was hit, it moves with the velocity Vf = 40 m/s for time t = 0.04 s.
Thus, using Newton's second law, we get:
[tex]\begin{gathered} F=ma \\ \\ F=m\times\frac{V_f-V_i}{t} \end{gathered}[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} F=0.20\text{ kg}\times\frac{40\text{ m/s}-0\text{ m/s}}{0.04\text{ s}} \\ \\ F=200\text{ kg.}^\text{m/s}^2 \\ \\ F=200\text{ N} \end{gathered}[/tex]The weight of the ball on the earth is the product of its mass and acceleration due to gravity g. The value of the acceleration due to earth is: g = 9.8 m/s^2.
The weight W of the ball on earth is given as:
[tex]W=mg[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} W=0.20\text{ kg}\times9.8\text{ m/s}^2 \\ \\ W=1.96\text{ N} \end{gathered}[/tex]The ratio of the force F exerted by the ball on the rocket and the weight of the ball is:
[tex]\begin{gathered} \frac{F}{W}=\frac{200\text{ N}}{1.96\text{ N}} \\ \\ \frac{F}{W}=\frac{102.04}{1} \end{gathered}[/tex]Thus, F : W = 102.04 : 1.
Final answer:
The force exerted by the ball on the rocket is 200 N. The ratio of this force and the weight of the ball is 102.04 : 1.
For a body to be in SHM, the restoring force in the ___________ direction as the displacement from equilibrium.A. OppositeB. PerpendicularC. SameD. Not enough info
A. Opposite
ExplanationSimple harmonic motion (SHM)is a very important type of periodic oscillation where the acceleration is proportional to the displacement from equilibrium, in the direction of the equilibrium position.
the oscillation of a mass on a spring when it is subject to the linear elastic restoring force given by Hooke's law
The restoring force is the force that brings the object back to its equilibrium position (red); the restoring force acts in the direction opposite to the displacement.
therefore, the answer is
A. Opposite
I hope this helps you
Inquiry is a process promoted by a Blank
Inquiry is a process prompted by curiosity, observation or question.
Explanation:Inquiry is driven by curiosity, wonder, interest and/or a need to answer a question. Being able to ask rich questions enables students to construct their knowledge and develop an understanding of concepts and experiences.
As the swings ride hits top speed, what applies centripetal force to keep the riders traveling in a circle?
When the swing moves from the lowest point up to either peak, the main force acting is momentum; and when the swing falls from either peak to its lowest point, the main force acting is gravity. If you do not pump your legs fast enough, air resistance along with gravity will keep you down.
What provides centripetal force?The centripetal force is the resultant force because the swings move in a circle. The centripetal force—the force that keeps the rider in a circle and the horizontal component of the tention force—is produced by the total of the forces acting along the x-axis.Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics. A common illustration of centripetal force is when a body moves uniformly fast in a circular motion.A net force that keeps an object moving in a circular motion is known as a centripetal force.To learn more about : Centripetal force.
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How fast must a 10 kg object be traveling to have the SAME momentum as a 2kg object at 8 m/s?
Recall that the momentum is given by
[tex]p=m\cdot v[/tex]Where m is the mass and v is the velocity.
[tex]p=2\cdot8=16\;\;\frac{kg\cdot m}{s}[/tex]So, the momentum of the object is 16 kg m/s.
Now, we need to equate this momentum to find the velocity of the other object.
[tex]\begin{gathered} p=m\cdot v \\ 16=10\cdot v \\ v=\frac{16}{10} \\ v=1.6\;\frac{m}{s} \end{gathered}[/tex]Therefore, the object must be traveling at 1.6 m/s to have the same momentum as the other object.
A 3500 kg van hits a 2500 kg car with a force of 1480 N [E].a) What force does the van experience?b) Calculate the acceleration of both vehicles after the collision.
Given
m1 = 3500 kg (van)
m2 = 2500 kg (car)
F = 1480 N
Procedure
a) In a collision between object 1 and object 2, the force exerted on object 1 (F1) is equal in magnitude and opposite in direction to the force exerted on object 2 (F2). In equation form:
[tex]F1=-F2[/tex]The above statement is simply an application of Newton's third law of motion to the collision between objects 1 and 2.
b) Accelaration
[tex]\begin{gathered} F=ma \\ a=\frac{F}{m} \\ a=\frac{1480N}{3500+2500} \\ a=0.246\text{ m/s} \end{gathered}[/tex]The acceleration would be 0.246 m/s
What is the ratio of the force exerted on the floor by the ground to the persons body weight
We will have the following:
We are given:
m = 67kg
F = 2300N
Now, we have that the average are of a human foot is approximately 76 cm^2.
So, we will deterine the ratio of force excerted on the floor in terms of pressure, that is:
[tex]P=\frac{2300N}{0.0076m^2}\Rightarrow P=302631.5789Pa[/tex][tex]\Rightarrow P\approx302.632kPa[/tex]So, the ratio of the force exerted on the floor by the ground is approximately 302.632 Kilopascals.
A football kicker is attempting a field goal from 44m out. The ball is kicked and just clears the lower bar with a time of flight of 2.9s. If the angle of the kick was 45°, what was the initial speed of the ball, assuming no air resistance?Group of answer choices
Given,
Distance travelled, d=44 m.
The time of flight t=2.9 s
The angle is
[tex]\theta=45^o[/tex]Let the initial velocity be v
The motion is projectile.
Thus the horizontal distance travelled is
[tex]\begin{gathered} d=(v\cos \theta)t \\ \Rightarrow44=v\times\cos 45^o\times2.9 \\ \Rightarrow v=21.5\text{ m/s} \end{gathered}[/tex]Thus the answer is 21.5 m/s
