A charge of 2 c is at the origin. when charge q is placed at 2 m along the positive x axis, the electric field at 2 m along the negative x axis becomes zero. what is the value of q?

The final velocity of the ball is  20.8 m/s. Option C

Now we have the equation;

v^2 = u^2 + 2gh

v = final velocity

u = initial velocity

a = acceleration

s = distance

v^2 = (11.4)^2 + (2 * 10 * 15.5)

v^2 = 129.96 + 310

v = √ 129.96 + 310

v = 20.8 m/s

b)

Given that;

R = u^2sin2θ/g

Where;

g = acceleration due to gravity

θ = acute angle

u = velocity

R = (60)^2 sin2(30)/10

R = 310 m

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A wedge is a machine and it is used for separating bodies.

The wedge is a combination of two inclined planes. When the wedge is driven into a body by an effort force, a much larger force will be exerted to each side by the wedge surfaces.

What are the importance of wedge?

A wedge is used to separate bodies which are held together by large forces example of this scenario is splitting of timber. A wedge is a machine and the example of wedge - type of machine are;

Note that a thin wedge has a higher mechanical advantage than a short thick one.

Therefore, a wedge is a machine and it is used for separating bodies.

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Answer:

Thin film interference

The wavelength of radiowaves is 3.042 m.

The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below.

Frequency given, f = 98.6 MHz = 98.6 x [tex]10^{6}[/tex] cycles/second

Electromagnetic waves including radiowaves also travel at the speed of light.

Therefore, c = 3.0 x [tex]10^{8}[/tex] m/sec

Wavelength = speed/frequency

wavelength of 98.6 MHz = 3.0 x [tex]10^{8}[/tex]/98.6 x [tex]10^{6}[/tex] meters

=3.042 meters

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Answer:

The key difference between air pressure and liquid pressure is that air pressure allows the gaseous state of matter to be compressible, whereas liquid pressure makes a liquid incompressible.

Liquid pressure is the pressure that we can observe in a liquid. Air pressure is also known as atmospheric pressure, and it is the pressure as the force exerted by the collisions of particles in the air.

        800 = 0 + [tex]\frac{1}{2}[/tex]a(30)[tex]^{2}[/tex]

        800 = 450a

        a = 1.77m[tex]s^{-2}[/tex]

        s = 0+  [tex]\frac{1}{2}[/tex]1.77[tex]t^{2}[/tex]

        s =  [tex]\frac{1}{2}[/tex]1.77(30)[tex]^{2}[/tex]

        s = 796.5m

        t = 800/8

        t = 100 sec

       2000 -800

      length = 1200m

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An electron moving perpendicular to a magnetic field of 3. 2 × 10-2 t moves in a circle of radius 0. 40 cm. this electron is moving with 2.25 x 10⁷ m/s

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is traveling through a magnetic field.

A magnetic field is defined as a location in space close to a magnet or an electric current where a physical field is formed by a moving electric charge acting as a force on another moving electric charge. The magnetic field of the Earth is an illustration of a magnetic field. The region around a magnet where the effects of magnetism are felt is known as the magnetic field.

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On Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.

To find the answer, we have to know more about the Cassini-Huygens Mission.

Thus, we can conclude that, on Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.

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The resulting velocity of marble B after the collision is 2.4 m/s.

The object with the faster velocity, and thus larger momentum, will impart more energy to the slower object during the collision than vice versa. Following the collision, the object with the lower beginning velocity will travel away from the other object with a higher speed and momentum.
Marble A's mass, marble B's mass, marble B's initial velocity, marble A's final velocity, marble B's final velocity, and marbles A and B's combined mass and initial velocity

Applying the mass-conservation principle
Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v

0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v

0.12 kg m/s = (0.05 kg) v

v = 2.4 m/s

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Answer:

C

Explanation:

Use conservation of momentum

Momentum before collision = mv = 50 (4) = 200  kg-m/s

AFTER collision

  30 * 3    + Blue momentum    = 200

    blue momentum = 110   kg-m/s

Aluminium has a work function of 4. 08 eV. The cutoff wavelength and cutoff frequency for the photoelectric effect is 303.9nm and 911.7× 10¹⁷ s⁻¹ respectively.

Work Function is the minimum energy required to eject an electron from a photoelectric material.

Cutoff Wavelength is the maximum wavelength below which electron will be ejected

Cutoff Frequency is the minimum frequency required to eject electron.

Let the work function of Aluminium be Φ

Given,  work function Φ = 4.08eV

We know that hc/λ =  Φ

where, h is Planck constant

c is speed of light

λ is wavelength of light used

Hence, on subsitution

1240 / λ = 4.08 eV          (hc = 1240)

⇒ λ = 303.9 nm

Hence, cutoff wavelength used is 303.9 nm

We know that ν = c/λ

ν = 3 × 10⁸ / 303.9

⇒ ν = 911.7 × 10¹⁷ s⁻¹

Hence, cutoff frequency used is 911.7 × 10¹⁷ s⁻¹

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The total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.

To calculate the total mass of the earth's atmosphere we use the expression

[tex]P=\frac{F}{A}[/tex]

or, [tex]F=P\times A[/tex]

or,[tex]M\times g=P\times A[/tex]

or,[tex]M=\frac{P\times 4\times \pi\times r^{2} }{g}[/tex]

Here, P= Atmospheric pressure at the surface = [tex]10^{5}[/tex] N/m2

F= Force at the earth surface.

A= Area of the earth.

r= Radius of the earth=6.4 × [tex]10^{6}[/tex] m

g= Acceleration due to gravity. = 9.8 m/s2 ≈ 10 m/s2

Let, M be the total mass of the earth's atmosphere.

Now, [tex]M=\frac{10^{5}\times4\times\pi\times(6.4\times10^{6} )^{2} }{10}[/tex]

M= 5×[tex]10^{8}[/tex] kg.

Thus from the above calculation we can show that, the total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.

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The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s

Given data,

Mass of glider A (M[tex]_{1}[/tex]) = 0.15 kg

Mass of glider B (M[tex]_{2}[/tex]) = 0.3 kg

Initial velocity of A (u[tex]_{1}[/tex]) = 0.80ms-1

Initial velocity of B ( u[tex]_{2}[/tex]) = -2.2m/s

Momentum and kinetic energy are conserved in elastic collision . So,

M[tex]_{1}[/tex]u[tex]_{1}[/tex]+M[tex]_{2}[/tex]u[tex]_{2}[/tex] = M[tex]_{1}[/tex]v[tex]_{1}[/tex]+M[tex]_{2}[/tex]v[tex]_{2}[/tex]

0.15×0.8+0.3x(-2.2) = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]

-0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]

Again if,

u[tex]_{1}[/tex]+v[tex]_{1}[/tex] =u[tex]_{2}[/tex]+v[tex]_{2}[/tex]

0.8 +v[tex]_{1}[/tex] =-2.2+v[tex]_{2}[/tex]

v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3

Solving  for -0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex] and v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3 , we get

v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s

Therefore,The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s

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The maximum height reached by the ball is 0.46m.

To find the answer, we have to know about the potential energy of a spring mass system.

                       [tex]k=400N/m\\m=1kg\\x=0.150m\\h=?\\[/tex]

                             [tex]U=\frac{1}{2}kx^2 \\U=mgh[/tex]

                    [tex]h=\frac{kx^2}{2mg} =\frac{400*(0.15)^2}{2*1*9.8} =0.46m[/tex]

Thus, we can conclude that, the maximum height reached by the ball is 0.46m.

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The mass of the electron is [tex]1.72\times 10^{-30}[/tex] Kg.

To calculate the mass of the electron we are using the formula,

[tex]m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }[/tex]

Here we are given,

[tex]m_0[/tex]=The rest mass of an electron =  [tex]9. 11 \times 10^{-31}[/tex] kg.

v= The velocity of electron =  0. 85c.

c= The velocity of light = c.  (c=[tex]3\times 10^8[/tex] m/s)

We have to found the mass of an electron = m Kg.

Now we substitute the known values, we found that,

[tex]m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-\frac{(0.85c)^{2} }{c^{2} } } }[/tex]

Or,[tex]m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-(\frac{0.85c}{c})^2 } }[/tex]

Or,[tex]m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-({0.85})^2 } }[/tex]

Or, [tex]m=1.72\times 10^{-30}[/tex] Kg.

From the above calculation we can conclude that, The mass of the electron is [tex]1.72\times 10^{-30}[/tex] Kg.

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Answer:

if a car is increasing it's acceleration uniformly in a unit time, the graph will be moving away from it's origin. that's how you get this kind of graph.

Answer:

Apparently, a measuring rod had been used incorrectly and the telescope was not focusing properly - changes were later made to the telescope to correct this problem.

When the light turns from green to yellow while you are already in the intersection, proceed through the intersection at a safe speed.

To find the answer, we have to study more about the importance of traffic signals.

Thus, we can conclude that, When the light turns from green to yellow while you are already in the intersection, proceed through the intersection at a safe speed.

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Answer:

blank 1: close together

blank 2: more

The wavelength of an electron (m = 9. 11 × 10^-28 g) moving at 3. 66 × 10^6 m/s will be  0.197 * [tex]10^{-12}[/tex] m

De Broglie wavelength is an important concept while studying quantum mechanics. The wavelength (λ) that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength. A particle's de Broglie wavelength is usually inversely proportional to its force.

momentum (p) = mv

DE Broglie wavelength = lambda = h / p

where

h = plank's constant

m = mass of electron

v = velocity of electron

lambda = h / mv

            = 6.633 * [tex]10^{-34}[/tex] / 9. 11 × [tex]10^{-28}[/tex] *  3. 66 × [tex]10^{6}[/tex]

            = 0.197 * [tex]10^{-12}[/tex] m

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When energy is transferred between earth's system, some energy is lost to the surroundings in the form of

-light

-movement

-heat

-vibration

Only a few factors account for the majority of the energy in the Earth system: solar energy, gravity, radioactive decay, and the rotation of the Earth. Many surface processes, including winds, currents, the hydrologic cycle, and the entire climate system, are powered by solar energy. Rivers and other materials flow downhill due to gravity, which also causes tides (due to the Moon's gravitational pull). The Earth's interior is heated by radioactive decay, while air and water currents are influenced by the forces of rotation.

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The focal Length of the eye is 0.37cm.

The retina, which is always 2.70 cm away from the lens, serves as the image's primary imaging medium. Image distance is 2.70 cm as a result.

The object is located 265 cm away from the eye's lens.

Based on lens formula:

[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{v}[/tex]

where the object distance is u, the image distance is v, and the focal length is f.

Consequently, u is 265.00 cm and v is 2.70 cm.

[tex]\frac{1}{f} = \frac{1}{265} + \frac{27}{10}[/tex]

[tex]\frac{1}{f} = \frac{7165}{2650}[/tex]

[tex]f = \frac{2650}{7165}[/tex]

f = 0.37

Thus, the focal length of the eye is 0.37cm.

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The intensity of electric field E midway between these two charges is 2.52*10^7N/C.

To find the answer, we have to know more about the electric field.

                      [tex]E=\frac{kQ}{r^2}[/tex]

where, k is the constant equal to 8.99*10^9.

                [tex]E_1=\frac{8.99*10^9*20*10^{-6}}{10*10^{-2}} =1.79*10^7N/C[/tex]

                 [tex]E_2=\frac{8.99*10^9*8*10^{-6}}{(10*10^{-2})^2} =7.19*10^6N/C[/tex]

                [tex]E=1.79*10^7+7.19*10^6=2.52*10^7N/C[/tex]

Thus, we can conclude that, the intensity of electric field e midway between these two charges is 2.52*10^7N/C.

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Answer:

B

Explanation:

reading the volume of water in a graduated cylinder which can be read to the nearest mL is accurate, it lacks precision due to the bottom meniscus formed.

the bottom meniscus may cause a wrong reading due to refraction of light

120kJ work is generated by a healthy adult who circulates 9L of blood through the brachial artery in 10 min.

A flow rate of 900 mL per minute is equal to a flow of 9 L in 10 minutes.

Additionally, you have 200W of total power generated.

9L Equals 9000 mL

900mL/min x 9,000mL/10min

By multiplying the power (watt) by the time, we can derive the work performed by the adult.

10 min = 600s

200W x 600s = 120 kJ

Hence, the work generated is 120kJ.

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Thermo-Electrochemical converter (UTEC) is a thermodynamic cycle that does not account for the Carnot Efficiency.

What is the Carnot cycle in thermodynamics?

An ideal closed thermodynamic cycle that is reversible and consists of the four steps of isothermal expansion to a desired point, adiabatic expansion to a desired point, isothermal compression, and adiabatic compression back to the starting state.

What is the purpose of Carnot cycle?

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(a) The average velocity of the car in m/s for the first leg of the run is 36.2 m/s.

(b) The average velocity (in m/s) for the total trip is 0.

The average velocity of the car in m/s for the first leg of the run is calculated as follows;

Average velocity = total displacement/total time

Average velocity = (760) / (21) = 36.2 M/S

The average velocity (in m/s) for the total trip is calculated as follows;

v =  total displacement/total time

v = 0/(26 + 21)

v = 0

Thus, the average velocity of the car in m/s for the first leg of the run is 36.2 m/s.

The average velocity (in m/s) for the total trip is 0.

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(a) The distance From A to B to M to N is 22 m, the displacement is 22 m, the speed is 4.4 m/s and the average velocity is 4.4 m/s.

(b) The distance From C to A to G to D is 24 m, the displacement is 2 m, the speed is 4.8 m/s and the average velocity is 0.4 m/s.

(c) The distance From J to I to E to H is 16 m, the displacement is -2 m, the speed is 3.2 m/s and the average velocity is -0.4 m/s.

(d) The distance From F to B to K to F is 32 m, the displacement is 0 m, the speed is 6.4 m/s and the average velocity is 0 m/s.

The distance traveled by the object is calculated as follows;

Distance From A to B to M to N

From A to B to M to N = 3 + 18 + 1 = 22

Distance From C to A to G to D

= 5 + 13 + 6

= 24

Distance From J to I to E to H

= 1 + 8 + 7

= 16

Distance from F to B to K to F

= 8 + 16 + 8

= 32

The displacement of the object is calculated as follows;

displacement = final position - initial position

Displacement From A to B to M to N

= 11 - (-11)

= 22

Displacement from C to A to G to D

= D - C

= - 4 - (-6)

= 2

Displacement from J to I to E to H

= H - J

= 5 - 7

= - 2

Displacement From F to B to K to F

= F - F

= 0

The speed of the object is calculated as follows;

speed = total distance/total time

Speed of the object from A to B to M to N

= 22/5 = 4.4 m/s

Speed of the object from C to A to G to D

= 24/5

= 4.8 m/s

Speed of the object from J to I to E to H

= 16/5

= 3.2 m/s

Speed of the object from F to B to K to F

= 32/5

= 6.4 m/s

The average velocity of the object is calculated as follows;

Average velocity from A to B to M to N

= 22/5

= 4.4 m/s

Average velocity of the object from C to A to G to D

= 2/5

= 0.4 m/s

Average velocity of the object from J to I to E to H

= -2/5

= -0.4 m/s

Average velocity of the object from F to B to K to F

= 0

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The 60 degrees is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is given that axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is required to find the angle between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

Suppose the angle between the polarizer and the axis of filter is θ.

The intensity of light that is passing after the filter is 0.2 l₀.

From the law of Malus, we have

I = I₀ [tex]cos^{2}[/tex]θ

0.2I₀= I₀ [tex]cos^{2}[/tex]θ

0.2 =  [tex]cos^{2}[/tex]θ

[tex]cos\\[/tex]θ = 0.447

θ = 60°

Thus the angle between the direction of polarized light and the axis of a polarizing filter is 60 degree.

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(a) The gravitational force received by each 1 kg mass is 8.66 N.

(b) The magnitude of gravitational acceleration is 8.66 m/s².

(c) The orbital speed of the ISS is  7,663.6 m/s.

(d) The time take  for the ISS to orbit round the Earth is 5,558.75 seconds which is equal to 1.54 hours.

The gravitational force received by each 1 kg mass is calculated as follows;

F = Gm₁m₂/r²

where;

F = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 1) / (6780,000)²

F = 8.66 N

mg = GMm/r²

g = GM/r²

where;

g = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ ) / (6780,000)²

g = 8.66 m/s²

v = √GM/r

v = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴  / 6780,000)

v = 7,663.6 m/s

T = 2πr/v

T = (2π x 6780,000) / (7663.6)

T = 5,558.75 seconds

1 hour = 3600 seconds

=  5,558.75/3600

= 1.54 hours

Thus, the gravitational force received by each 1 kg mass is 8.66 N.

The magnitude of gravitational acceleration is 8.66 m/s².

The orbital speed of the ISS is  7,663.6 m/s.

The time take  for the ISS to orbit round the Earth is 5,558.75 s = 1.54 hours.

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