a chemist reacts 30.0ml of 5.6m hcl with an excess of mg (oh)₂. how many grams of magnesium chloride will be produced?

Answers

Answer 1

When 30.0 mL of 5.6 M HCl is reacted with an excess of Mg(OH)₂, a chemical reaction occurs resulting in the production of magnesium chloride. The amount of magnesium chloride produced can be calculated using stoichiometry.

To determine the amount of magnesium chloride produced, we need to use stoichiometry, which involves the balanced chemical equation and the molar ratios between the reactants and products. The balanced chemical equation for the reaction between HCl and Mg(OH)₂ is:

2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O

From the equation, we can see that 2 moles of HCl react with 1 mole of Mg(OH)₂ to produce 1 mole of MgCl₂. First, we need to calculate the number of moles of HCl present in the reaction:

Moles of HCl = Volume of HCl (L) × Molarity of HCl (mol/L)

            = 0.0300 L × 5.6 mol/L

            = 0.168 mol

Since the reaction occurs with an excess of Mg(OH)₂, all the HCl will react, resulting in the same amount of moles of MgCl₂ produced. Finally, we can calculate the mass of MgCl₂ produced using its molar mass:

Molar mass of MgCl₂ = atomic mass of Mg + 2 × atomic mass of Cl

                   = 24.31 g/mol + 2 × 35.45 g/mol

                   = 95.21 g/mol

Mass of MgCl₂ produced = Moles of MgCl₂ × Molar mass of MgCl₂

                     = 0.168 mol × 95.21 g/mol

                     = 15.97 g

Therefore, the chemist will produce approximately 15.97 grams of magnesium chloride.

To learn more about stoichiometry refer:

https://brainly.com/question/30439815

#SPJ11


Related Questions

At 2000 k the partial pressures of an equilibrium mixture of h2s, h2, and s are 0.0252 , 0.0492 , and 0.0352 atm, respectively. calculate the value of the equilibrium constant kp at 2000 k.
H ₂(g)+ S(g) ⇌ H ₂(g) + S(g)

Answers

The value of the equilibrium constant Kp at 2000 K is approximately 14.521.

To calculate the equilibrium constant Kp at 2000 K, we need to use the partial pressures of the gases in the equilibrium mixture.

The balanced equation for the reaction is:

H₂(g) + S(g) ⇌ H₂S(g)

The equilibrium constant expression is given by:

Kp = (P(H₂S) / (P(H₂) * P(S))

Partial pressures:

P(H₂S) = 0.0252 atm

P(H₂) = 0.0492 atm

P(S) = 0.0352 atm

Now we can substitute these values into the equilibrium constant expression:

Kp = (0.0252) / (0.0492 * 0.0352)

   = 0.0252 / 0.00173424

   ≈ 14.521

Learn more about equilibrium constants at https://brainly.com/question/3159758

#SPJ11

what is the amount in grams of edta needed to make 479.2 ml of a 0.06 m edta solution. the molar mass of edta is 374 g/mol. (only enter numeric value in the answer, do not include the unit)

Answers

The amount in grams of edta needed to make 479.2 ml of a 0.06 m edta solution is 10.75g

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Volume of Edta = 479.2 ml

Concentration = 0.06 M

Moles = Concentration × Volume in liters

= 0.06 × 0.479  = 0.028 moles

Mass of Edta = moles × molar mass

= 0.028 × 374 = 10.75 g

Learn more about Moles, here:

https://brainly.com/question/15209553

#SPJ4

How many molecules of XeF6 are formed from 12.9 L of F2(at 298 K and 2.60 atm) according to the following reaction?

Assume that there is excess Xe.

Xe(g) + 3 F2(g) → XeF6(g)

Answers

Approximately 6.40 × 10^23 molecules of XeF₆ are formed from 12.9 L of F₂.

To determine the number of molecules of XeF₆ formed from 12.9 L of F₂, we need to use the ideal gas law to calculate the number of moles of F₂, and then use the stoichiometry of the reaction to find the number of moles of XeF₆.

First, let's calculate the number of moles of F₂ using the ideal gas law equation:

PV = nRT

Where:

P = pressure of F₂ (2.60 atm)

V = volume of F₂ (12.9 L)

n = number of moles of F₂ (to be calculated)

R = ideal gas constant (0.0821 L·atm/mol·K)

T = temperature in Kelvin (298 K)

Rearranging the equation to solve for n:

n = PV / RT

n = (2.60 atm) * (12.9 L) / (0.0821 L·atm/mol·K * 298 K)

n ≈ 1.063 mol

According to the balanced equation, 1 mole of Xe reacts with 3 moles of F₂ to form 1 mole of XeF₆. Therefore, the number of moles of XeF₆ formed will be the same as the number of moles of F₂, which is approximately 1.063 mol.

Finally, we can convert the number of moles of XeF₆ to molecules by multiplying by Avogadro's number, which is 6.022 × 10^23 molecules/mol:

Number of molecules of XeF₆ = (1.063 mol) * (6.022 × 10^23 molecules/mol)

Number of molecules of XeF₆ ≈ 6.40 × 10^23 molecules

Learn more about XeF₆ at https://brainly.com/question/27111532

#SPJ11

of the following, which element has the highest first ionization energy?question 10 options:1) al2) cl3) na4) p

Answers

The element that has the highest first ionization energy among the options is Cl (chlorine). The correct answer is option 2.

Ionization energy is the amount of energy required to remove an electron from a neutral atom to form a positive ion. As we move from left to right in a period, the ionization energy increases. This happens because the number of protons increases, which pulls the electrons more tightly to the nucleus.

So, more energy is needed to remove an electron from an atom. Here's a list of the first ionization energies of the given elements (in kJ/mol):

Aluminum (Al): 577.5

Chlorine (Cl): 1251.2  

Sodium (Na): 495.8

Phosphorus (P): 1011.8

Therefore, of the given options, Cl (chlorine) has the highest first ionization energy, because it is located at the rightmost side of the periodic table.

Learn more about ionization energy here:

https://brainly.com/question/28385102

#SPJ11

which of the following can be reduced by sodium borohydride? group of answer choices nitrile ketone alkene ester aldehyde carboxylic acid

Answers

The functional groups that can be reduced by sodium borohydride include aldehydes, ketones, and esters.

Sodium borohydride (NaBH4) is a common reducing agent in organic chemistry, meaning it is often used to reduce various functional groups. Among the given choices, the functional groups that can be reduced by sodium borohydride include aldehyde, ketone, and ester.

Nitrile, alkene, and carboxylic acid are not typically reduced by NaBH4. Nitriles are typically reduced using other reagents such as lithium aluminum hydride (LiAlH4). Alkenes are typically hydrogenated using catalysts such as palladium on carbon (Pd/C). Carboxylic acids are typically reduced using more powerful reducing agents such as lithium aluminum hydride (LiAlH4) or borane (BH3).

When NaBH4 is used as a reducing agent, it donates a hydride ion (H-) to the functional group being reduced, leading to the formation of a new, reduced product. For example, when NaBH4 is added to an aldehyde, it donates a hydride ion to the carbonyl carbon, leading to the formation of a new alcohol. The reaction can be represented as follows:

RC=O + NaBH4 + H2O → RCH2OH + NaBO2 + H2

Overall, NaBH4 is a versatile reducing agent that can be used to reduce a variety of functional groups.

To know more about Alkenes visit:

https://brainly.com/question/29283735

#SPJ11

Draw and name the organic product of the following reaction? benzene + CH3Cl---AlCl3----->????+HCl

Answers

The reaction of benzene and CH3Cl with AlCl3 yields the product methylbenzene or toluene (C6H5CH3) and HCl.

The Friedel-Crafts alkylation reaction of benzene with CH3Cl in the presence of anhydrous aluminum trichloride (AlCl3) as a catalyst produces methylbenzene or toluene (C6H5CH3) as the organic product and hydrogen chloride (HCl) as a byproduct.

The reaction mechanism of the Friedel-Crafts alkylation reaction of benzene with methyl chloride can be explained as follows: Formation of carbocation(1) CH3Cl + AlCl3 → CH3+AlCl4-Step 2:Reaction of benzene with carbocation(2) C6H6 + CH3+AlCl4- → C6H5CH3+AlCl4-The reaction can be shown as:C6H6 + CH3Cl → AlCl3C6H5CH3 + HCl In this reaction, the electrophile (CH3+) produced from the reaction of CH3Cl with AlCl3 attacks the benzene ring to form a resonance-stabilized carbocation that reacts further with CH3Cl to produce the toluene product.

To know more about benzene visit:

https://brainly.com/question/31837011

#SPJ11

when adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 600 k is equal to 1.4×105j/mol . calculate the equilibrium constant at 600 k

Answers

The equilibrium constant at 600 K, calculated using the given standard free energy change, is approximately 1.07 × 10^(-13).

To calculate the equilibrium constant (K) at 600 K using the given standard free energy change (ΔG°), we can use the equation:

ΔG° = -RT ln(K)

Where:

ΔG° is the standard free energy change

R is the gas constant (8.314 J/(mol·K))

T is the temperature in Kelvin

K is the equilibrium constant

We can rearrange the equation to solve for K:

K = e^(-ΔG° / RT)

Let's substitute the values into the equation:

ΔG° = 1.4 × 10^5 J/mol

R = 8.314 J/(mol·K)

T = 600 K

K = e^(-1.4 × 10^5 J/mol / (8.314 J/(mol·K) × 600 K))

Calculating this expression:

K ≈ e^(-29.146)

Using a scientific calculator or software, we find:

K ≈ 1.07 × 10^(-13)

Therefore, the equilibrium constant at 600 K is approximately 1.07 × 10^(-13).

The equilibrium constant (K) relates to the standard free energy change (ΔG°) through the equation ΔG° = -RT ln(K), where R is the gas constant and T is the temperature in Kelvin.

By rearranging the equation and plugging in the given values, we can solve for K. The resulting value gives us the equilibrium constant at 600 K.

To read more about equilibrium constant, visit:

https://brainly.com/question/3159758

#SPJ11

For each pair of carbene/alkylidene complexes shown below identify the one that should have the stronger M-C bond. Give a brief explanation for your answer (i) [(CO)5V-C(OMe)(NMe2)]- (ii) Cp2BrTa-CH2 (iii) Cp(PMe3):Re-cBu2 (iv) [Cp(dppe)Fe-CPh2] vs Cp(PMe3)-Re-СМег vs Cp(CO)(PEt3)Ru-CH2l vs Cp(CO)2(PPh3)W-C(OMe2l vs CpO)Nb-CH2 IV

Answers

The given carbene alkylidene complexes [(CO)5V-C(OMe)(NMe2)]-, Cp2BrTa-CH2, Cp(PMe3):Re-cBu2, [Cp(dppe)Fe-CPh2], Cp(PMe3)-Re-СМег, Cp(CO)(PEt3)Ru-CH2, Cp(CO)2(PPh3)W-C(OMe2).

Tantalum has an oxidation state of +4 which indicates that it can provide more electrons to the C atom compared to the metals having higher oxidation states.

Ta-C bond is stronger than other complexes. Hence, Cp2BrTa-CH2 has the stronger M-C bond. Cp2BrTa-CH2 is a metallocene where Ta tantalum is present in a lower oxidation state of +4 which is favorable for stronger M-C bond in comparison to other carbene/alkylidene complexes.

To know more about alkylidene visit:

https://brainly.com/question/31131495

#SPJ11

a 15.0 ml solution of ba(oh)₂ is neutralized with 22.7 ml of 0.200 m hcl. what is the concentration of the original ba(oh)₂ solution?

Answers

The concentration of the original Ba(OH)₂ solution if 15.0 ml solution of Ba(OH)₂ is neutralized with 22.7 ml of 0.200 m HCl is 151.3 mol/dm³

To determine concentration of the original Ba(OH)₂ solution, we must know he balanced chemical equation for the neutralization reaction is:

Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

From the equation above, the stoichiometric ratio of Ba(OH)₂ and HCl is 1:2. That means one mole of Ba(OH)₂ reacts with 2 moles of HCl. The balanced chemical equation also shows that the number of moles of HCl used is the same as the number of moles of Ba(OH)₂. Hence:

moles of HCl = 0.200 mol/dm³ × 22.7 dm³ = 4.54 mol

Using the stoichiometric ratio, the moles of Ba(OH)₂ in the solution can be calculated to be:

moles of Ba(OH)₂ = 4.54 mol ÷ 2 = 2.27 mol

The volume of the Ba(OH)₂ solution is 15.0 mL, which is 0.015 dm³. Therefore, the concentration of the original Ba(OH)₂ solution can be calculated as:

concentration = moles/volume= 2.27 mol ÷ 0.015 dm³= 151.3 mol/dm³

Learn more about concentration: https://brainly.com/question/9537498

#SPJ11

The concentration of the original Ba(OH)₂ solution is 0.302 M.

Given data

Volume of Ba(OH)₂ solution used = 15.0 ml

Volume of HCl used = 22.7 ml

Molarity of HCl solution used = 0.200 M

We need to calculate the concentration of Ba(OH)₂ solution, which is not known.Molar ratio of HCl and Ba(OH)₂ in a balanced chemical equation of their neutralization is;

HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

The balanced chemical equation tells us that 1 mole of HCl is required to neutralize 1 mole of Ba(OH)₂.

So, the moles of HCl used in the reaction is;

moles of HCl = molarity × volume (in liters)

moles of HCl = 0.200 M × 0.0227 L = 0.00454 mole

Since one mole of HCl reacts with 1 mole of Ba(OH)₂,

so the number of moles of Ba(OH)₂ used is also equal to 0.00454 mole. Since we know the volume of the Ba(OH)₂ solution used, we can calculate the molarity of the solution as;

molarity = moles of solute / volume of solution in liters

Molarity = 0.00454 / (15.0 / 1000) = 0.302 M

Therefore, the concentration of the original Ba(OH)₂ solution is 0.302 M.

To know more about concentration visit:

https://brainly.com/question/3045247

#SPJ11

what is the mass of 26.8l ozone gas (o3) at stp? round to 3 significant figures.

Answers

The mass of 26.8L ozone gas (O3) at STP is 72.7 g. Therefore, the mass of 26.8L ozone gas (O3) at STP is 72.7 g.

Given that the volume of ozone gas (O3) is 26.8L.The formula for the mass of any gas is:m = DRT/PM, where D is the density of the gas at STP,R is the gas constant, T is the temperature at STP, and P is the pressure at STP. At STP, T = 273 K, P = 1 atm, andD for ozone gas (O3) is 2.14 g/L.

Substituting these values, we get:m = 2.14 g/L × 273 K / 1 atm × 26.8 L × 48 g O3 / 1 mol= 72.7 g (rounded to 3 significant figures).Therefore, the mass of 26.8L ozone gas (O3) at STP is 72.7 g.

To know more about mass visit:

https://brainly.com/question/11954533

#SPJ11

10.0 grams of argon and 20.0 grams of neon are placed in a 1200.0 ml container at 25.0 C The partial pressure of neon is atm. A) 0.700 B) 8.70 C) 20.4 D) 3.40 E) 5.60 9) Consider the following reaction at equilibrium: 2002 (g) ? 2CO (g) + O2 (g) ?1°=-514k) Le Chatelier's principle predicts that adding O2 (g) to the reaction container will A) increase the partial pressure of CO (g) at equilibrium B) decrease the partial pressure of CO2 (9) at equilibrium C) increase the partial pressure of CO2 (g) at equilibrium D) decrease the value of the equilibrium constant E) increase the value of the equilibrium constant 0) The purpose of the salt bridge in an electrochemical cell is to A) provide a source of ions to react at the anode and cathode. B) provide oxygen to facilitate oxidation at the anode. C) provide a means for electrons to travel from the anode to the cathode. D) maintain electrical neutrality in the half-cells via migration of ions. E) provide a means for electrons to travel from the cathode to the anode.

Answers

D). The total pressure of the gas mixture is given as 1.04 atm. The amount of neon and argon is given as 20.0 g and 10.0 g respectively. We can use the formula;PAr = XAr × PTandPN= XN × PTWhere,PAr = partial pressure of argonXAr = mole fraction of argonPN= partial pressure of neonXN= mole fraction of neonPT= total pressure of the mixture.

Since we have to calculate the partial pressure of neon, we have to find the mole fraction of neon first.The mole fraction of neon (XN) can be calculated as:XN= number of moles of neon/total number of molesNumber of moles of neon can be calculated as:20.0gNe= molar mass of neon = 20.18 g/mol= 0.991 moles of neonNumber of moles of argon can be calculated as:10.0gAr= molar mass of argon = 39.95 g/mol= 0.250 moles of argonTotal number of moles in the mixture = 0.991 + 0.250= 1.241 moles of the mixtureMole fraction of neon = 0.991/1.241= 0.798The mole fraction of argon can be calculated as:XAr= 1 - XN= 1 - 0.798= 0.202Partial pressure of neon can be calculated as:PN= XN × PT= 0.798 × 1.04= 0.830 atmTherefore, the partial pressure of neon is 0.830 atm.

The balanced chemical reaction is given as:2CO(g) + O2(g) ⇌ 2CO2(g) The equilibrium constant (K) can be written as:K= [CO2]2/([CO]2[O2])If we add more oxygen to the reaction container, according to Le Chatelier's principle, the system will shift in the direction to reduce the excess of the added component. Thus, the concentration of O2 will decrease, and the concentration of CO and CO2 will increase, in order to maintain the equilibrium.The partial pressure of CO2 will increase, and the partial pressure of CO will also increase. However, the partial pressure of O2 will decrease. Thus, option (C) is the correct answer.Question 3The purpose of the salt bridge in an electrochemical cell is to maintain electrical neutrality in the half-cells via migration of ions. The salt bridge consists of an inverted U-tube containing an electrolyte, which allows the flow of ions between the half-cells. It completes the electrical circuit and balances the charges produced in the anode and cathode half-cells.  

To know more about pressure  visit:-

https://brainly.com/question/30673967

#SPJ11

a 400 ml sample of a 0.100 m formate buffer, ph 3.75, is treated with 3 ml of 1.00 m koh . what is the ph following this addition? ( pka for formic acid is 3.75)'

Answers

The pH following the addition of KOH is still 3.75.

To determine the pH following the addition of KOH to the formate buffer, we need to consider the reaction between formate (HCOO-) and hydroxide (OH-) ions. The balanced chemical equation for the reaction is:HCOO- + OH- -> H2O + HCO3-Since 3 mL of 1.00 M KOH is added to a 400 mL sample of the formate buffer, we can calculate the number of moles of OH- added:
moles of OH- = volume of KOH (L) * concentration of KOH (M)
= 0.003 L * 1.00 M
= 0.003 mol
The number of moles of OH- is equal to the number of moles of HCOO- consumed in the reaction. Since the initial concentration of formate is 0.100 M and the volume of the buffer is 0.4 L (400 mL converted to liters), we can calculate the initial moles of formate:
initial moles of HCOO- = initial concentration of HCOO- (M) * volume of buffer (L)
= 0.100 M * 0.4 L
= 0.040 mol
The moles of formate remaining after the reaction is:
moles of HCOO- remaining = initial moles of HCOO- - moles of OH- added
= 0.040 mol - 0.003 mol
= 0.037 mol
To calculate the final concentration of formate, we divide the moles remaining by the volume of the buffer:
final concentration of HCOO-
= moles of HCOO- remaining / volume of buffer (L)
= 0.037 mol / 0.4 L
= 0.0925 M
Since the final concentration of formate is equal to the initial concentration of formate, the pH remains the same. Therefore, the pH following the addition of KOH is still 3.75.

To know more about pH, click here
https://brainly.com/question/2288405

#SPJ11




Pipe insulation, vinyl flooring, and ceiling insulation in older homes and buildings may be sources of: carbon monoxide chloroform asbestos formaldehyde

Answers

Pipe insulation, vinyl flooring, and ceiling insulation in older homes and buildings may be sources of asbestos.

Asbestos has been widely used in construction materials until the early 1980s. Asbestos-containing materials (ACMs) are still present in many older buildings and homes, and may pose a risk to those who work or live in them. ACMs are still present in several building materials, including pipe insulation, vinyl flooring, and ceiling insulation in older homes and buildings. These materials should be treated with caution since their fibers, if inhaled, can cause mesothelioma and other lung cancers.

Asbestos is a group of six naturally occurring silicate minerals that can be mined and processed into several materials. Fibrous minerals were widely used in the construction industry, shipbuilding, and fireproofing until the early 1980s. While asbestos is no longer used in construction materials, it can still be found in many older homes and buildings built before the 1980s. Asbestos fibers can be released into the air if ACMs become damaged or weathered. These fibers, if inhaled, can cause severe lung diseases such as asbestosis, mesothelioma, and lung cancer.

To learn more about insulation visit;

https://brainly.com/question/14363642

#SPJ11

One pound-mass of water fills a container whose volume is 2 ft^3 The pressure in the container is 100 psia.
Calculate the total internal energy and enthalpy in the container.

Answers

The total internal energy in the container is approximately 38,738,520 Btu, and the total enthalpy is approximately 38,831,104.2 Btu.

To calculate the total internal energy and enthalpy in the container, we need to use the specific volume of water and the specific internal energy and enthalpy values at the given pressure.

First, we convert the volume from cubic feet (ft³) to cubic inches (in³) since the specific volume of water is typically given in terms of in³/lbm.

1 ft³ = 12³ in³ = 1728 in³

So, the volume of water in the container is [tex]\begin{equation}2\text{ ft}^3 \times \frac{1728\text{ in}^3}{\text{ft}^3} = 3456\text{ in}^3[/tex].

Next, we need the specific volume of water. At the given pressure of 100 psia, the specific volume of water is approximately 0.01604 in³/lbm.

Now we can calculate the total internal energy and enthalpy using the formulas:

Internal Energy = Mass * Specific Internal Energy

Enthalpy = Mass * Specific Enthalpy

The mass of water can be calculated using the specific volume:

[tex]\begin{equation}Mass = \frac{Volume}{Specific Volume} = \frac{3456\text{ in}^3}{0.01604\text{ in}^3/\text{lbm}} = 215214\text{ lbm}[/tex]

Using the specific internal energy and enthalpy values at the given pressure, let's assume the values are approximately 180 Btu/lbm and 180.3 Btu/lbm, respectively.

Internal Energy = 215214 lbm * 180 Btu/lbm = 38,738,520 Btu

Enthalpy = 215214 lbm * 180.3 Btu/lbm = 38,831,104.2 Btu

Therefore, the total internal energy in the container is approximately 38,738,520 Btu, and the total enthalpy is approximately 38,831,104.2 Btu.

To know more about the internal energy refer here :

https://brainly.com/question/31432545#

#SPJ11

for each of the given pairs of elements, pick the atom with the following characteristics. (mg and k) (a) more favorable (exothermic) electron affinity

Answers

When comparing the elements magnesium (Mg) and potassium (K), the atom with the more favourable (exothermic) electron affinity is potassium (K).

Electron affinity refers to the energy change that occurs when an atom gains an electron. It is a measure of the atom's ability to attract and hold onto electrons. A more negative electron affinity value indicates a stronger attraction for electrons. In this case, we are comparing magnesium (Mg) and potassium (K).

Magnesium is located in Group 2 of the periodic table, while potassium is in Group 1. As we move down a group in the periodic table, the electron affinity generally decreases due to the increasing atomic size. Therefore, potassium, being located in Group 1, is likely to have a more negative electron affinity than magnesium.

This means that potassium is more favourable in terms of gaining electrons, making its electron affinity more exothermic than that of magnesium.

Learn more about periodic table here:

https://brainly.com/question/28747247

#SPJ11

If 3.50 mol of Fe reacts with 3.00 mol of oxygen in the following reaction: 4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) Which of the following statements is correct? If 3.50 mol of Fe reacts with 3.00 mol of oxygen in the following reaction: 4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) Which of the following statements is correct?

a)Fe is the limiting reactant and 1.75 mol of product can be produced.

b)O2 is the limiting reactant and 2.00 mol of product can be produced.

c)Fe is the excess reactant and 1.75 mol of product can be produced.

d)O2 is the excess reactant and 2.00 mol of product can be produced.

Answers

Given: Moles of Fe = 3.50 mol Moles of O2 = 3.00 mol4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)Here, 4 moles of Fe reacts with 3 moles of O2 to produce 2 moles of Fe2O3.

The correct answer is: B) O2 is the limiting reactant and 2.00 mol of product can be produced.

Therefore, we will determine the number of moles of Fe2O3 produced when 3 moles of O2 react with Fe. So,First, we determine the number of moles of Fe that can react with O2. As per the balanced equation,4 mol Fe reacts with 3 mol O2So, we need to first calculate how many moles of Fe can be reacted with 3 mol O2.This is given by:Fe/O2 = 4/3 = 1.33 (mole ratio)So,Fe reacted = 1.33 molNow, as the number of moles of Fe present in the reaction mixture is 3.50 mol. This means that Fe is in excess.

As per the balanced equation,4 mol Fe reacts with 3 mol O2So, 1.33 mol Fe reacts with 1 mol O2So, 3 mol O2 reacts with (1.33/1) × 3 = 3.99 mol Fe (rounded off to 4 mol)Now, as the O2 is in limiting quantity, we can calculate the number of moles of Fe2O3 formed using O2, which is 3.00 mol.Fe/O2 = 4/3 = 1.33 (mole ratio)O2 reacted = 3.00 molFe reacted = 3.00 × (3/4) = 2.25 molThe mole ratio of Fe2O3 and O2 is 2/3.So, the number of moles of Fe2O3 formed will be (2/3) × 3.00 mol = 2.00 mol.

To know more about moles visit:

https://brainly.com/question/15209553

#SPJ11

For a methane molecule a) find the irreducible representations using the four C-H bonds as the basis (b) What orbitals on the central C atom will be used to form the sigma bonds in CH4? (c) Could d orbitals on the C atom play a role in orbital formation in CH4? Explain why or why not. (d) In SiH4, could d orbitals be used to form the sigma bonds? If so, which d orbitals?

Answers

The sp³ hybrid orbitals are involved in the formation of sigma bonds with the hydrogen atoms. The four sp³ hybrid orbitals of carbon are involved in forming the bonds with hydrogen.


As per the character table, the reducible representation, Γ(CH4), is given asΓ(CH4) = a1 + t2
Consider the basis functions as four C-H bonds. The number of such functions is four.
Let’s denote each basis function by CHi where i = 1, 2, 3, 4. The basis functions can be written as
CH1 = (1 2 3 4)CH2 = (1423)CH3 = (1342)CH4 = (1243)

Now we can obtain the irreducible representations by using character tables. The character tables for the four C-H bonds, based on the symmetry operations, are given as,
As we have four basis functions and each basis function transforms according to the A1 representation, we have,
A1 ⊗ A1 ⊗ A1 ⊗ A1 = A1 + T1 + T2 + E

To know more about hybrid orbitals visit:-

https://brainly.com/question/30506016

#SPJ11

a molecular compound has the empirical formula xy3. which of the following is a possible molecular formula? question 2 options: x2y3 xy4 x2y5 x2y6

Answers

If a molecular compound has the empirical formula xy3, the molecular formula could be xy6 or x2y6. Answer: d) x2y6

The empirical formula of a molecular compound has a lower ratio of atoms than the molecular formula. The molecular formula has the actual number of atoms of each element in one molecule of the compound. The difference between molecular formula and empirical formula is that the molecular formula is the actual formula of the molecule, whereas the empirical formula is the simplified version of the molecular formula.

If the empirical formula is xy3, the molecular formula could be xy6 or x2y6. Answer: d) x2y6. That means that in the simplest form, the ratio of x to y is 1:3. A possible molecular formula can be figured out using the molecular weight of each element in the compound. Suppose we use x as one molecular weight unit and y as another molecular weight unit. So we can say that the empirical formula for the compound is (x)(y3), which can be simplified to XY3. So, the molecular formula for the compound must be X2Y6 because the ratio of atoms between the two elements should remain 1:3. So, this ratio can only be achieved by multiplying the molecular formula by 2 (1x2) and 2 (3x2) times, resulting in X2Y6.

Learn more problems on empirical formula at https://brainly.com/question/1603500

#SPJ11

For each pair of compounds, state which compound is the better 52 a) 2-methyl-1-iodopropane or tert-butyl iodide b) cyclohexyl bromide or l-bromo-1-methylcyclohexane c) 2-bromobutane or isopropyl bromide d) I-chloro-2.2-dimethylbutane or 2-chlorobutane e) l-iodobutane or 2-iodopropane

Answers

For each pair of compounds, the better compound can be determined by checking for factors such as the branching in the molecule, which can affect the reactivity of the compound, its stability, and its ease of reaction. a) 2-methyl-1-iodopropane is better than tert-butyl iodide.

The reason for this is that 2-methyl-1-iodopropane is less sterically hindered than tert-butyl iodide. Therefore, 2-methyl-1-iodopropane is more reactive and less stable compared to tert-butyl iodide.b) 1-bromo-1-methylcyclohexane is better than cyclohexyl bromide. 1-bromo-1-methylcyclohexane is more reactive than cyclohexyl bromide due to the presence of the primary carbon atom which is directly attached to the bromine atom. This results in the ease of nucleophilic substitution. c) Isopropyl bromide is better than 2-bromobutane. Isopropyl bromide is a primary alkyl halide whereas 2-bromobutane compound is a secondary alkyl halide.

The secondary carbon atom in 2-bromobutane is surrounded by more alkyl groups than the primary carbon atom in isopropyl bromide. The higher the number of surrounding alkyl groups, the less the reactivity. Therefore, isopropyl bromide is more reactive than 2-bromobutane.d) 2-chlorobutane is better than 1-chloro-2.2-dimethylbutane. 2-chlorobutane is a primary alkyl halide which is more reactive compared to 1-chloro-2.2-dimethylbutane, which is a tertiary alkyl halide and less reactive.e) 2-iodopropane is better than 1-iodobutane. 2-iodopropane is a secondary alkyl halide while 1-iodobutane is a primary alkyl halide. The reactivity of secondary alkyl halides is usually higher than that of primary alkyl halides. Therefore, 2-iodopropane is more reactive than 1-iodobutane.

To know more about compound visit:

https://brainly.com/question/14117795

#SPJ11

draw the products formed when β -d-galactose reacts with ethanol and hcl .

Answers

When β-d-galactose reacts with ethanol and HCl, the products that are formed are ethyl-β-d-galactopyranoside and water.

β-d-galactose, ethanol, and HCl react to produce ethyl-β-d-galactopyranoside and water. The reaction that occurs between these chemicals is a condensation reaction, whereby a molecule of water is removed to produce the desired product. Ethanol acts as a catalyst in this reaction, and HCl helps in the removal of water.

Here is the equation for this reaction:C12H22O11 + C2H5OH → C14H26O6 + H2Oβ-d-galactose has a cyclic structure, so it undergoes a ring-opening reaction with ethanol, resulting in ethyl-β-d-galactopyranoside and water. The cyclic structure of β-d-galactose is shown in the diagram below: The reaction between β-d-galactose and ethanol results in the formation of ethyl-β-d-galactopyranoside, which has the following structure:

To know more about galactose reacts visit:

https://brainly.com/question/31819544

#SPJ11

A possible mechanism for the overall reaction br2 (g) + 2no (g) → 2nobr (g) is no (g) + br2 (g) nobr2 (g) (fast) nobr2 (g) + no (g) k2→ 2nobr (slow) the rate law for formation of nobr based on this mechanism is rate = ________.

Answers

The rate law for the formation of NOBr based on the mechanism no(g) + Br2(g) NOBr2(g) (fast) NOBr2(g) + no(g) K2→ 2NOBr(slow) is

Rate = k[NO][Br2].

The rate-determining step in this reaction is the slow step, which is the second step.

We can identify the rate-determining step in a mechanism by comparing the rate laws for the forward and reverse reactions of each step.

The overall balanced equation of the reaction is given by:

Br2(g) + 2NO(g) → 2NOBr(g)

The slow step of the reaction isNOBr2(g) + NO(g) K2 → 2NOBr(g)

The mechanism involves two steps, which are:

Step 1: NO(g) + Br2(g) → NOBr2(g) (fast)

Step 2: NOBr2(g) + NO(g) → 2NOBr(g) (slow)

The rate law for the reaction is given by:

Rate = k[NOBr2] [NO]

So, the rate law for the formation of NOBr based on the given mechanism is Rate = k[NO][Br2].

Learn more about the rate law:

brainly.com/question/16981791

#SPJ11

at constant pressure, the combustion of 15.0 g of c2h6(g) releases 777 kj of heat. what is δh for the reaction given below? 2 c2h6(g) 7 o2(g) → 4 co2(g) 6 h2o(l)

Answers

ΔH for the given reaction is 3114 kJ/mol. This indicates the heat released per mole of reaction occurring.

To determine ΔH for the given reaction, we need to use the stoichiometric coefficients and the heat released for the combustion of 15.0 g of [tex]C_{2}H_{6}[/tex].

The molar mass of [tex]C_{2}H_{6}[/tex] is calculated as follows:

2 mol of C = 2 × 12.01 g/mol = 24.02 g/mol

6 mol of H = 6 × 1.01 g/mol = 6.06 g/mol

Total molar mass of C2H6 = 24.02 g/mol + 6.06 g/mol = 30.08 g/mol

Now, we can calculate the moles of [tex]C_{2}H_{6}[/tex]: moles of [tex]C_{2}H_{6}[/tex] = mass / molar mass = 15.0 g / 30.08 g/mol ≈ 0.498 mol

From the balanced equation, we can see that the stoichiometric coefficient of [tex]C_{2}H_{6}[/tex] is 2. Therefore, the heat released for the combustion of 0.498 mol of [tex]C_{2}H_{6}[/tex] is: ΔH = (777 kJ / 0.498 mol) × 2 = 3114 kJ/mol

Thus, ΔH for the given reaction is 3114 kJ/mol. This indicates the heat released per mole of reaction occurring.

To know more about stoichiometric coefficients, refer here:

https://brainly.com/question/14465605#

#SPJ11

Please, someone help me.

Answers

The mass of the ammonium nitrite that is needed is 6.4 g

What is the stoichiometry?

Stoichiometry is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. Therefore, the total mass of the reactants must be equal to the total mass of the products.

The equation of the reaction is;

[NH4]NO2 → N2 + 2H2O

We have the pressure is;

97.8 kPa - 2.5 Kpa = 95.3 kPa or 0.94 atm

PV = nRT

n = PV/RT

n = 0.94 * 2.58/0.082 * 294

n = 0.1 moles

If the reaction 1:1, mass  of the ammonium nitrite is;

0.1 moles * 64 g/mol

= 6.4 g

Learn more about stoichiometry:https://brainly.com/question/28780091

#SPJ1

what is δ for the reaction at body temperature (37.0 °c) if the concentration of a is 1.6 m and the concentration of b is 0.65 m ?

Answers

The δ for the reaction at body temperature (37.0 °c) if the concentration of a is 1.6 m and the concentration of b is 0.65 m is given by the formula below: ΔG° = −RT ln K, where R is the gas constant, T is the temperature, and K is the equilibrium constant of the reaction.

The δ for the reaction at body temperature (37.0 °c) if the concentration of a is 1.6 m and the concentration of b is 0.65 m is given by the formula below: ΔG° = −RT ln K, where R is the gas constant, T is the temperature, and K is the equilibrium constant of the reaction. For the equation below, a and b are reactants while c and d are products.

aA + bB ⇌ cC + dD

The equilibrium constant Kc is given by the formula below; Kc = ([C]^c x [D]^d) / ([A]^a x [B]^b)

where [A] is the concentration of A, [B] is the concentration of B, [C] is the concentration of C, and [D] is the concentration of D and a, b, c, and d are the stoichiometric coefficients of A, B, C, and D respectively. For the given equation, the ΔG° can be calculated as shown below.ΔG° = −RT ln Kc, where R = 8.314 J/mol. K is the gas constant and T = 37.0°C + 273.15 = 310.15 K is the temperature. The concentration of A is 1.6 M and the concentration of B is 0.65 M. If the stoichiometric coefficients are not given, they are assumed to be 1. Therefore, the equilibrium constant Kc is calculated as follows: Kc = ([C]^c x [D]^d) / ([A]^a x [B]^b)

Kc = ([C]^1 x [D]^1) / ([A]^1 x [B]^1)Kc = ([C] x [D]) / ([A] x [B])

Since a mole of A reacts with a mole of B to produce a mole of C and D each, the balanced chemical equation is; aA + bB → cC + dD1 mole of A reacts with 1 mole of B to produce 1 mole of C and 1 mole of D each. Therefore, a = 1, b = 1, c = 1, and d = 1. Substituting these values into the equation for Kc gives;

Kc = ([C] x [D]) / ([A] x [B])Kc = ([1] x [1]) / ([1.6] x [0.65])Kc = 0.9615R = 8.314 J/mol. K and T = 310.15 K (at body temperature)ΔG° = −RT ln KcΔG° = −(8.314 J/mol. K × 310.15 K) ln (0.9615)ΔG° = 7786.9 J/mol. Hence, the ΔG° for the reaction at body temperature (37.0 °c) if the concentration of a is 1.6 m and the concentration of b is 0.65 m is 7786.9 J/mol.

To know more about concentration visit: https://brainly.com/question/3045247

#SPJ11

the value of ksp for pbcl2 is 1.6 ×10-5. what is the lowest concentration of cl-(aq) that would be needed to begin precipitation of pbcl2(s) in 0.010 m pb(no3)2 ? (use a calculator on this question.)

Answers

The lowest concentration of Cl-(aq) needed to begin precipitation of PbCl2(s) in 0.010 M Pb(NO3)2 is approximately 1.27 × 10-4 M.

What is the minimum concentration of Cl-(aq) required for precipitation of PbCl2 in 0.010 M Pb(NO3)2?

To determine the lowest concentration of Cl-(aq) that would initiate the precipitation of PbCl2, we need to compare the ion product (Q) with the solubility product constant (Ksp). The balanced chemical equation for the dissolution of PbCl2 is:PbCl2(s) ⇌ Pb2+(aq) + 2Cl-(aq)

The solubility product expression for PbCl2 is:Ksp = [Pb2+][Cl-]^2

In the given solution, the concentration of Pb2+ is 0.010 M. To find the minimum concentration of Cl-(aq), we can rearrange the Ksp expression:

[Cl-] = √(Ksp / [Pb2+])Substituting the values into the equation:

[Cl-] = √(1.6 × 10^-5 / 0.010)

        = √1.6 × 10^-3

        ≈ 1.27 × 10^-4 M

Therefore, the lowest concentration of Cl-(aq) required to initiate the precipitation of PbCl2 in a solution with 0.010 M Pb(NO3)2 is approximately 1.27 × 10^-4 M.

Learn more about concentration

brainly.com/question/12265114

#SPJ11

Of the following gases, ______ will have the greatest rate of effusion at a given temperature. A) NH3. B) CH4. C) Ar. D) HBr. E) HCl.

Answers

Of the following gases, [tex]NH_3[/tex] will have the greatest rate of effusion at a given temperature. Option A) is correct.

Fusion is a process of gas moving from a container with high pressure to the container with low pressure through a small opening or small hole. The rate of effusion depends on the velocity of the gas molecules which in turn depends on their mass and the temperature of the gas. Gases with lower molecular weight will have higher rates of effusion than gases with higher molecular weight.

According to Graham's law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. The molar mass of [tex]NH_3[/tex] (ammonia) is 17 g/mol. The molar mass of CH4 (methane) is 16 g/mol. The molar mass of Ar (argon) is 40 g/mol. The molar mass of HBr (hydrogen bromide) is 80 g/mol. The molar mass of HCl (hydrogen chloride) is 36.5 g/mol.

Therefore, [tex]NH_3[/tex] has the smallest molecular weight (and smallest molar mass) among the given gases. Hence, it will have the greatest rate of effusion at a given temperature. Option A) is correct.

To know more about  Temperature refer here :

https://brainly.com/question/4735135

#SPJ11

In the nitrogen cycle, nitrification occurs in which of the following steps?
A) Step 1 (N2 -> Organic nitrogen)
B) Step 2 (Organic nitrogen -> Ammonium)
C) Step 3 (Ammonium -> Nitrate & nitrite)
D) Step 4 (Nitrate & Nitrite -> N2)

Answers

In the nitrogen cycle, nitrification occurs in Step 3 (Ammonium -> Nitrate & nitrite). The correct option is C.

Because it is a crucial component of amino acids, proteins, and nucleic acids, nitrogen is necessary for all living things. The movement of nitrogen from the environment to living things is referred to as the nitrogen cycle. The nitrogen cycle has four primary stages: assimilation, denitrification, nitrogen fixation, and nitrification.

The process of converting atmospheric nitrogen into ammonium is known as nitrogen fixation. Nitrification is the process by which the ammonium produced is converted into nitrite and nitrate.

There are two steps in the nitrification process. Bacteria convert ammonium into nitrite in the first step, which is then converted into nitrate in the second step. The process by which nitrogen enters living things is called assimilation.

To know more about nitrogen cycle:

https://brainly.com/question/25419904

#SPJ11

the passage describes some glycolysis reactions. select the appropriate term for each blank to complete the passage.

Answers

The glycolysis reaction is the process of the breakdown of glucose by enzymes. In this process, glucose is broken down into pyruvate, which results in the release of energy in the form of ATP (Adenosine Triphosphate) molecules. The process of glycolysis involves ten different enzymes, each of which catalyzes a specific step in the reaction.

Glycolysis reactions occur in the cytoplasm of cells. The reaction is a sequence of ten steps, with the first five being an energy-consuming process while the second five steps are energy-generating. During the first five steps, two molecules of ATP are consumed, while during the second five steps, four molecules of ATP are generated along with two molecules of NADH (Nicotinamide Adenine Dinucleotide).

The glycolysis reaction results in a net gain of two ATP molecules. The overall reaction can be represented as follows: Glucose + 2NAD+ + 2ADP + 2Pi → 2 pyruvate + 2NADH + 2ATP + 2H2O + 2H+.

The glycolysis reaction occurs in almost all living organisms and is the first step in both aerobic and anaerobic respiration.

Glycolysis is a complex process consisting of a series of ten reactions that occur in the cytoplasm of cells. The first five reactions are energy-consuming while the second five reactions are energy-generating. In the first five reactions, two ATP molecules are used up, while in the second five reactions, four ATP molecules are produced.

The reaction sequence results in the breakdown of glucose into pyruvate, with the release of energy in the form of ATP. This is why the process of glycolysis is considered to be a form of energy metabolism. Glycolysis is a vital process that occurs in almost all living organisms. It is the first step in both aerobic and anaerobic respiration.

The overall reaction can be represented as Glucose + 2NAD+ + 2ADP + 2Pi → 2 pyruvate + 2NADH + 2ATP + 2H2O + 2H+. Thus, it can be concluded that the process of glycolysis plays an important role in the energy metabolism of cells.

To know more about glycolysis reaction visit:

https://brainly.com/question/2107563

#SPJ11

Determine the equilibrium constant for the following reaction at 298 K. CIO(g) + O2(g) → Cl(g) + O3(8) AG° = 34.5 kJ/mol 0.986 4.98 x 10-4 8.96 x 10-7 5.66 x 105 1.12 x 106

Answers

the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.

The equilibrium constant for the given reaction, CIO(g) + O2(g) → Cl(g) + O3(g), at 298 K can be determined using the Gibbs free energy of the reaction and the following equation:ΔG° = - RT lnK

where ΔG° is the standard Gibbs free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

The equation can be rearranged to solve for K:K = e^(-ΔG°/RT)where e is the natural logarithmic base, and all other variables are the same as in the previous equation.Substituting the given values,

we have:ΔG° = 34.5 kJ/molR = 8.314 J/(mol·K)T = 298 K

Using these values, we get:-

ΔG°/RT = (-34.5 × 10^3 J/mol) / (8.314 J/(mol·K) × 298 K)

= -13.19e^(-ΔG°/RT) = e^(-13.19) = 8.96 × 10^-7

Therefore, the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.

learn more about equilibrium constant here

https://brainly.com/question/3159758

#SPJ11

The most likely decay mode (or modes) of the unstable nuclide 1l C would be: A. positron production B. either positron production or electron capture, or both. C. B-particle production D. electron capture E. c.-particle production

Answers

The most likely decay mode (or modes) of the unstable nuclide 11C would be either positron production or electron capture, or both.

Radioactive isotope of carbon that is produced in particle accelerators and has a half-life of 20.334 minutes. It decays by positron emission, turning into the stable isotope boron-11. How does an unstable nuclide undergo decay An unstable nuclide undergoes decay through various processes. The most common modes of decay are alpha decay, beta decay, and gamma decay.

Positron production, electron capture, and c-particle production are also possible.Here, the unstable nuclide is 11C, which is a radioactive isotope of carbon. The most likely decay mode (or modes) of this unstable nuclide would be either positron production or electron capture, or both.

To know more about nuclide visit :

https://brainly.com/question/32298051

#SPJ11

Other Questions
Sucrose and naphthalene are both organic molecules. Did you find significant differences in their solubilities? If so, explain why these molecules did not exhibit identical solubility. Vinegar is a 5% solution of acetic acid in water. Explain why salad dressings composed of olive oil and vinegar separate into two layers. Which of the following is correct? O a. A binding minimum wage can either benefit or hurt a worker O b. A binding price ceiling on the rental price can only hurt a tenant but never benefit him/her. OC. A binding price ceiling on the rental price can either benefit or hurt the landlord. Od. A binding minimum wage can either benefit or hurt an employer. in what form of key management is recovery of a key possible An object weighs 80 N in air and 60 N in water. If the density of water is po the density of the object p is Po a) 1.3 Po b) 6.0 po c) 4.0 Po d) 0.75 po e) 8.0 po What is "credibility?" Think of someone who is credible to you.Why is he/she credible? What does he/she do to make them a crediblesource? Now, think of someone who has no credibility to you. Why is Impermissibility of using conventional applications of Ointerest in financial transactions . A conventional interest paying mortgage would not be ShariaOa compliant . With regards to house purchase , four Islamically acceptable techniques are available : Murabaha , Ijara wa latina , Diminishing Musharaka and stisna a Explain how one could purchase a house via one of the modes mentioned above Find the interest on the following loan. S1450 at 8.5% for 3 months The interest is $7 (Round to the nearest cent needed.) 1. The chapter demonstrates how to prepare a statement of cash flows from information on the balance sheet and income statement. If this is possible, why are managers required to provide a statement of cash flows? What does the statement of cash flow tell you that the income statement and balance sheet do not?2. Common-size analysis is a simple way to make financial statements of different firms comparable. What are possible shortcomings of comparing two different firms using common-size analysis?3. Analysts can compare ROCEs across companies but should not compare basic EPSs despite the fact that both ratios use net income to the common shareholders in the numerator. Explain. The non-bank private sector holds $250 of currency and $8,000 in deposits. Banks hold $1,000 in currency as reserves. In this economy, the money multiplier is O 6.3 O 6.6 7 O None of the above. Questi The results of a recent study regarding smoking and three types of illness are shown in the following table. Illness Non-Smokers Smokers Totals Emphysema 50 150 200 Heart problem 50 150 200 Cancer 100 500 600 Totals 200 800 1000 (1) If we are interested in determining whether or not illness is independent of smoking. a. State the null and alternative hypotheses to be tested. b. Show the contingency table of the expected frequencies and determine the test statistic. C. Use critical value approach to test for determining if illness is independent of smoking (a=0.05). What do you conclude? (Give test statistic, rejection rule, and conclusion) (2) If we are interested in determining if the proportions of smokers in the three categories are equal. a. State the null and the alternative hypotheses to be tested. b. Use p-value approach to test for determining if the proportions of smokers in the three categories are equal (a=0.05). What do you conclude? (Give test statistic, rejection rule, and conclusion) During stress, the adrenals release norepinephrine, which activates what? O A. Sympathetic nervous system O B. Parasympathetic nervous system O C. Enteric nervous system O D. Human-Psychological Axis Jin buys 200 shares of a stock at $40 per share in his margin account. Refer to the margin requirements below to answer the following questions. (Assume that he incurs no additional costs.) a. What is his margin requirement in dollars? b. What is his return on investment if the stock price rises to $50 per share and he sells his shares? c. If the stock price decreases to $20 and Jin decides to sell the stock, what is his return on investment? What is the most amount of money that he could lose on this investment? what would buy you the most health gained for the least cost? Computer equipment was acquired at the beginning of the year at a cost of $73,600 that has an estimated residual value of $3,800 and an estimated useful life of S years. a. Determine the depreciable cost. b. Determine the straight-line rate. c. Determine the annual straight-line depreciation. which of the following statements about energy pyramids is true? group of answer choices the smallest proportion of organisms are found in the top level. the largest proportion of organisms are found in the top level. producers are most likely to be found in the top level. carnivores are most likely to be found in the bottom level. if s'(t) = v(t) thne s(t) is the posiiton of the runner at time t processes form mountains due to deformation at a plate boundary. A.Taphogenic B.Omogenic C.Epirogenic D.Viscolatatid 126 Poi Question 12 List two advantages and two disadvantages of using each of these for advertising: TV, Radio, Magazines, and Newspapers. Use the editor to format your answer the temperature and pressure gauge on a circulated boiler is a i really need help with this one questiojn