A circular loop of radius r carries a current i. at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop?

When the player strikes the ball, kinetic energy is at its greatest.

Kinetic energy = 1/2*m*[tex]v^{2}[/tex]

where m denotes mass and v denotes velocity.

Therefore, kinetic energy is inversely correlated with square of velocity.

When a player strikes the ball, velocity is at its highest.

Thus, when the player strikes the ball, kinetic energy is at its highest.

It is the energy that a body has because it is moving.

Kinetic energy comes in five different forms:

Kinetic energy is measured in Joules.

Importance of kinetic energy:

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The resistance value of the sliding rheostat is 15 ohms.

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms.

The total resistance of the circuit can be calculated from the total current in the circuit and the total voltage in the circuit.

R = V/I

R = 50 /2

R = 25 ohms

The resistance value of the sliding rheostat is calculated as follows;

R(rheostat) = 25 ohms - 10 ohms = 15 ohms

Thus, the resistance value of the sliding rheostat is 15 ohms.

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The frequency of the oscillation is (f)=  284.21Hz

To calculate the frequency we used the formula,

[tex]f=\frac{\omega}{2\pi }[/tex]

Here , we are given,

I= The peak current across an ac generator = 0.50 A.

V= The peak Voltage across an ac generator = 8.0 V.

C= The capacitance of the capacitor = 35 μf.

We have to find the angular frequency of  an ac generator [tex]\omega[/tex].

We know, The maximum charge of the generator is,

[tex]Q=CV[/tex]

Or,[tex]Q=(35\times 10^{-6}) \times 8.0[/tex]

Or, [tex]Q=28\times 10^{-5} C[/tex]

So, The maximum charge of the generator is (Q)= [tex]28\times 10^{-5} C[/tex]

Now, for the angular frequency we can write that,

[tex]I=\omega\times Q[/tex]

Or,[tex]\omega=\frac{I}{Q}[/tex]

Now we put the value of [tex]\omega[/tex] in the first equation , we can find that

[tex]f=\frac{\omega}{2\pi }[/tex]

Or,[tex]f=\frac{1}{2\pi } \times \frac{I}{Q}[/tex]          [Note: from above[tex]\omega=\frac{I}{Q}[/tex]]

Or,[tex]f=\frac{1}{2\pi } \times \frac{0.50}{28\times 10^{-5} }[/tex]

Or, [tex]f=284.21 Hz[/tex]

Therefore, from the above calculation we can conclude that the frequency of the oscillation is 284.21 Hz.

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The 3kg of 20% of salt brine at 65 degrees Celsius has more enthalpy than the 5kg of 20% salt brine at 50 Degrees Celsius.

Enthalpy is defined as the total heat content of a system. The enthalpy is a measure of the total work which the system can do plus the internal energy of the system.

The enthalpy of the given solutions can be calculated as follows:

For the 3kg of 20% of salt brine at 65 degrees;

mass of salt = 3 * 20%  = 0.6 kg

specific heat capacity = 3.56kJ/kg*C

temperature change = 65°C

Enthalpy = 0.6 * 3.56 * 65

Enthalpy = 232 kJ

For the 5kg of 20% salt brine at 50 Degrees Celsius;

mass of salt = 5 * 20%  = 1 kg

specific heat capacity = 3.56kJ/kg*C

temperature change = 50°C

Enthalpy = 1 * 3.56 * 50

Enthalpy = 178 kJ

Therefore, the 3kg of 20% of salt brine at 65 degrees Celsius has more enthalpy.

In conclusion, the enthalpy or heat content of the solutions depends on the mass and temperature change.

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Betelgeuse is the 10th brightest star in the night sky comparing to other stars. And it is the second brightest in Orion's constellation.

Betelgeuse is the tenth brightest star in the night sky and, after Rigel, the second brightest in Orion's constellation. it is a distinctly reddish semiregular variable star with the widest apparent magnitude range of any first-magnitude star, ranging from +0.0 to +1.6. Betelgeuse is the brightest star in the night sky at near - infrared wavelengths. Its Bayer name is Orionis, which is Latinized to alpha Orionis and abbreviated alpha Ori or Ori

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The total magnification will be 200x.

It quantifies the comparison of the image's size to that of the object's size. In terms of how big or little the picture is produced, it informs us about the image. The height of the picture divided by the height of the object is known as magnification. m=hiho.

Objective lens - An essential component of the microscope's optics is the objective lens. The sample, specimen, or item being examined is situated close to the microscope's objective. It plays a crucial part in imaging since it creates the initial magnified picture of the sample.

Ocular lens - The component of the microscope known as the eyepiece, or ocular lens, is responsible for enlarging the picture created by the objective so that it can be viewed by the human eye.

20x objective lens was used by specimen

10x ocular lens was also used by him.

we have to find the total magnification.

For calculating the total magnification we 'll simply do multiplication

Total Magnification = 20 × 10x

Total Magnification = 200x

So , the total magnification will be 200x .

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Segment

The space between two waves is known as a segment in an ECG. Beginning at the end of the P wave and ending at the beginning of the QRS complex is the PR segment. Beginning at the end of the QRS wave and ending at the beginning of the T wave is the ST segment.

An electrocardiogram (ECG) is a quick test that can be used to examine the electrical activity and rhythm of your heart. The electrical signals that your heart beats out each time it beats are picked up by sensors that are affixed to your skin.

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The mural paintings at Dura-europos suggested narrative scenes were part of the component of the decoration of many late antique synagogues in this type of context.

This refers to a type of graphic work which is usually done on walls, ceilings etc. This is usually done by a professional known as a painter and uses different techniques to get the right shades and shape.

This type of painting was used at Dura-europos in which different narrative scenes served as a component for the many late antique synagogues in this aspect and context of artwork present during that period of time.

This therefore makes narrative scenes the most appropriate choice.

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If I moved filter 3 to be centred on a wavelength of 1000 nm, The red ball (d) will appear black if you looked through filter 3 with your eyes.

An optical filter is a device that selectively transmits light of different wavelengths, usually implemented as a glass plane or plastic device in the optical path, which are either dyed in the bulk or have interference coatings. The optical properties of filters are completely described by their frequency response, which specifies how the magnitude and phase of each frequency component of an incoming signal is modified by the filter.

Filters mostly belong to one of two categories :

The simplest, physically, is the absorptive filter; then there are interference or dichroic filters. Many optical filters are used for optical imaging and are manufactured to be transparent; some used for light sources can be translucent.

Optical filters selectively transmit light in a particular range of wavelengths, that is, colours, while absorbing the remainder. They can usually pass long wavelengths only (long pass), short wavelengths only (short pass), or a band of wavelengths, blocking both longer and shorter wavelengths (band pass). The pass band may be narrower or wider; the transition or cut-off between maximal and minimal transmission can be sharp or gradual. There are filters with more complex transmission characteristic, for example with two peaks rather than a single band;[2] these are more usually older designs traditionally used for photography; filters with more regular characteristics are used for scientific and technical work.

Optical filters are commonly used in photography (where some special effect filters are occasionally used as well as absorptive filters), in many optical instruments, and to colour stage lighting. In astronomy optical filters are used to restrict light passed to the spectral band of interest, e.g., to study infrared radiation without visible light which would affect film or sensors and overwhelm the desired infrared. Optical filters are also essential in fluorescence applications such as fluorescence microscopy and fluorescence spectroscopy.

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The unit vectors along the three co-ordinate axes are described as. i > j > k > 1. is D. i = j = k = 1

A vector that has a volume of 1 is a unit vector. It is also known as a direction vector because it is generally used to denote the direction of a vector. The vectors i, j, k, stand the unit vectors along the x-axis, y-axis, and z-axis respectively.

There are three essential unit vectors which are commonly employed and these are the vectors in the direction of the x, y and z-axes. The unit vector in the direction of the x-axis is i, the unit vector in the direction of the y-axis is j and the unit vector in the demand of the z-axis is k.

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The change in Potential energy is =  662,292.459  J.

Here, to calculate the potential energy change we use the formula,

[tex]W= F \times d \times cos\theta[/tex]

Or, [tex]W= m\times g \times d \times cos\theta[/tex]

Here we are given,

d= Distance the car makes = 62. 2 m.

[tex]\theta[/tex] = Angle that the car make along the hill =  28. 3°

F= The amount of force affect on the car = [tex]m\times g[/tex] .

m= Mass of the car = 1234 kg.

g= Acceleration of gravity = 9.8 [tex]m/s^2[/tex]

Now we substitute the known values in the above equation,

[tex]W= m\times g \times d \times cos\theta[/tex]

Or, [tex]W= 1234 \times 9.8 \times 62.2 \times cos(28.3)[/tex]

Or, [tex]W= 662,292.459 J[/tex]

From the above calculation we can conclude that the amount of work done on the car is, 662,292.459 J.

We know, from the work energy theorem that,

The change in Potential energy = The work done on the mass.

So, From the above theorem the change in potential energy is 662,292.459 J.

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If a comet were to orbit the sun with a highly eccentric orbit and an average (semimajor axis) distance of 1 au, we might use Kepler's third law of planetary motion to determine that each orbit would take one year to complete.

To find the answer, we need to know about the Kepler's third law of planetary motion.

                       [tex]a=1AU\\T=(1)^{3/2}=1 year[/tex]

Thus, we can conclude that, If a comet were to orbit the sun with a highly eccentric orbit and an average (semimajor axis) distance of 1 au, we might use Kepler's third law of planetary motion to determine that each orbit would take one year to complete.

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The torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

Given

Let Torque = т

P = т * ω

т = P/ ω

т = 17500 / 450 = 388.88 Nm (approx. 389 Nm)

Hence , the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. It represents the capability of a force to produce change in the rotational motion of the body.

We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines is given in terms of Horsepower (hp), which is approximately equal to 745.7 watts.

Angular speed is the speed of the object in rotational motion.

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Answer:

1/8

Explanation:

2R is the same as 1D, so you are a full diameter above yhe earth. The diameter of the earth is 12,742km, space starts at 100km so it probably isn't a third or a quarter. it is most likely an 1/8 or 1/9. if I had to guess it would be 1/8

shifting of the frequency will take place by 1.674 × 10¹² Hz.

Frequency is a unit of measurement for how frequently a recurrent event, like a wave, takes place over a specified period of time. A cycle is one repetition of the repeating pattern. Frequency only exists in moving waves that change their places throughout time. Frequency is one way to define how fast a wave moves.

Δλ/λ₀ = v/c

Relativistic doppler effect,

[tex]v' = v_{0} \frac{ \sqrt{ 1 - v/c}}{ \sqrt{ 1 + v/c}}[/tex]

[tex]\frac{v}{c}= \frac{7.16}{3000}[/tex]

[tex]v'= 6.91 * 10^{14} * \frac{\sqrt{1 -\frac{7.16}{3000} } }{\sqrt{1-\frac{7.16}{3000} } }[/tex]

[tex]v'=6.893 * 10^{14}[/tex]

[tex]|v'-v_{0}|= 1.647 * 10^{12}[/tex]

shifting of the frequency will take place by 1.674 × 10¹² Hz.

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Potential difference required in an electron microscope to give an electron wavelength of 4. 5 nm will be 0.063 V.

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other is called potential difference.

The wavelength of an electron is calculated for a given energy (accelerating voltage) by using the de Broglie relation between the momentum p and the wavelength λ of an electron

lambda = 4.5 nm = 4.5 * [tex]10^{-9}[/tex] m

h = [tex]6.626 * 10^{-34}[/tex]  J s

e = 1.6 * [tex]10^{-19}[/tex] C

m = 9.1 * [tex]10^{-31}[/tex] kg

Energy = eV

lambda = h / [tex]\sqrt{2mE}[/tex] = h / [tex]\sqrt{2m(eV)}[/tex]

[tex](lambda)^{2}[/tex] = [tex]h^{2}[/tex] / (2m (eV))

V = [tex]h^{2}[/tex] / (2 m e  [tex](lambda)^{2}[/tex] )

V  =  [tex](6.626 * 10^{-34} )^{2}[/tex] /  2 * 9.1 * [tex]10^{-31}[/tex] *  1.6 * [tex]10^{-19}[/tex]  * [tex](4.9 * 10^{-9}) ^{2}[/tex]

V = 0.063 V

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A Final statement or concluding statement

The aspect of lighting that refers to the relative intensity of illumination is called Lightning Quality.

Based on the luminosity function, luminous intensity is a measure of the  wavelength-weighted power emitted by a light source in a specific direction per unit solid angle.

Photometry is the science of measuring visible light as it is experienced by human eyes.

The human eye can only sense light in the visible range and is sensitive to different wavelengths of light within that spectrum.

The eye is most sensitive to greenish-yellow light at 555 nm when it is acclimated for bright settings (photopic  vision).

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A photon of blue light has a higher frequency and a lower wavelength than a photon of red light.

The wavelength of light is the distance between corresponding points in two adjacent light cycles, and the frequency of light is the number of cycles of light that pass a given point in one second.

Wavelength is typically represented by λ, the lowercase Greek letter lambda, while frequency is represented by ν, the lowercase Greek letter nu

Red light has a wavelength of ~700 nm, and a frequency of ~4.3*[tex]10^{14}[/tex] Hz. Visible light makes up just a small part of the full electromagnetic spectrum.

Wavelength of blue light: 450nm and  frequency of blue light 6.66 * [tex]10^{14}[/tex] Hz

Blue light has higher frequency, shorter wavelength and more energy.

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The magnitude and direction of the electrostatic torce is - 0.00712 x 10^9N towards left direction

Given:

q1 = +2 uC

q2 = -2 uC

q3 = +4 uC

To Find:

magnitude le and direction of the electrostatic torce

Solution: Electric force is a vector quantity. The electric force is proportional to the product of the magnitude of the charges. It is inversely proportional to the square of the distance between the charges. The electric force is calculated by,

F = kqQ/r^2

Force between q1 and q2

F1 = +2 x -2 x k/50 x 50 = - 0.0016k

Force between q1 and q3

F2 = +2 x +4 x k/100 x 100 = + 0.0008k

Net force on charge at origin is F1 + F2

F(net) = F1 + F2 = - 0.0016k + 0.0008k

F(net) = - 0.0008 x 8.9 x 10^9 = - 0.00712 x 10^9N

So, force on charge at origin is - 0.00712 x 10^9N and towards left direction

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From the core concept introduced by Al-Haytham, modern cameras are created.

To find the answer, we have to know about the Camera Obscura.

Thus, we can conclude that, from the core concept introduced by Al-Haytham, modern cameras are created.

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Answer:

They have the SAME momentum ....see below

Explanation:

Momentum = m v

3       3kg * 2 m/s =   6  kg-m/s

2        2kg * 3 m/s =   6 kg - m/s        

Its Scalar projection [tex]\sqrt{2}[/tex] and Vector projection 1 (i+0j+k).

We have been given two vectors <1 -1 1> and vector <1 0 1> , we are to find out the scalar and vector projection of vector <1 -1 1> onto vector <1 0 1>

We have vector a = <1 -1 1>  and vector b = <1 0 1>

The scalar projection of vector a onto vector b means the magnitude of resolved component of vector a in the direction of vector b and is given by

The scalar projection of vector a onto vector b = [tex]\frac{vector b . vector a}{|vector b| }[/tex]

                                                                             = [tex]\frac{(1-1+1)(1+0+1)}{\sqrt{1^{2} }+0+1^{2} }[/tex]

                                                                             =[tex]\frac{1^{2} + 1^{2} }\sqrt{2}[/tex]

                                                                             = [tex]\sqrt{2}[/tex]

The Vector projection of vector a onto vector b means the resolved component of vector a in the direction of vector b and is given by

The vector projection of vector a onto vector b .

                                    = [tex]\frac{vector b . vector a}{| vector b|^{2} }[/tex] (i+0j+k)

                                   = [tex]\frac{(1-1+1)(1+0+1)}{{1^{2} }+0+1^{2} }[/tex]. (i+0j+k)

                                   =  [tex]\frac{1^{2} + 1^{2} }{\sqrt{2} }[/tex] (i+0j+k)

                                   = 1 (i+0j+k).

Thus from the above conclusion we can say that scalar projection scalar projection [tex]\sqrt{2}[/tex] and vector projection 1 (i+0j+k).  

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Only P-waves reach the side of Earth that is opposite the focus because P-waves option 4:  can travel through liquids and S-waves cannot.

A P wave is known to be a compressional wave. This is seen as  a kind of a seismic body wave that often moves or shakes the ground a lot in the same direction and also in its opposite direction as the  wave moving direction.

Note that the P waves can be able to move via liquid and solids and gases, but the S waves can only move through solids.

Hence, Only P-waves reach the side of Earth that is opposite the focus because P-waves option 4:  can travel through liquids and S-waves cannot.

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When the government intervenes in markets with external costs, it does so in order to protect the interests of bystanders. An externality is either an external cost or external benefit that spills over to bystanders.

Government can play a role in reducing negative externalities by taxing goods when their production generates spillover costs. This taxation effectively increases the cost of producing such goods. The higher cost, then, better reflects the true cost of production because it includes the spillover costs of, say, pollution.

So, such taxation attempts to make the producer pay for the full cost of production. The use of such a tax is called internalizing the externality. When the government intervenes in markets with external costs, it does so in order to: protect the interests of bystanders. An externality is either an external cost or external benefit that spills over to bystanders.

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[tex]x = \frac{at {}^{2} }{2} + vt + x(0)[/tex]

[tex]x = \frac{20 \times (10) {}^{2} }{2} + 0 + 0 = \frac{2000}{2} = 1000 \: meters[/tex]

The kinetic energy is 1.8 × 10^ -1 J.

Rolling items each rotate and have linear (or translational) movement. consequently, they've both linear and rotational kinetic power. since the rotational kinetic strength of a rolling object depends at the inertia of the item.

The only kinetic energy involved here is rotational kinetic energy.

Kinetic Energy (Rotational) = 1/2Iω²

I = Moment of Inertia of a thin hoop =(Mass)(Radius)2

Mass = 3.0 kg

Radius = 10 cm = 0.10 m

ω = angular speed = 3.5 rad/s

Kinetic Energy (Rotational) = 1/2 * 3 * 12.25 J.

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The Kinetic energy is of thin hoop can be found out using the formulas of Rotational Kinetic Energy. The Kinetic Energy of the hoop is 18.375J.

Rolling items rotate and have linear or translational movement. consequently, they have both linear and rotational kinetic power. Since the rotational kinetic strength of a rolling object depends on the Inertia of the item.

The only kinetic energy involved here is Rotational Kinetic Energy.

Rotational Kinetic Energy = 1/2Iω²

where, I = Moment of Inertia of a thin hoop =(Mass)(Radius)²

              where, Mass of hoop, m = 3.0 kg

                           Radius of loop, R = 10 cm = 0.10 m

                           Angular speed, w= 3.5 rad/s

Since, Rotational Kinetic Energy = 1/2 × 3 × 12.25 J.

             Rotational Kinetic Energy = 18.375J

Hence, Rotational Kinetic Energy is 18.375J

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The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

                      [tex]Q=\frac{\pi Pr^4}{8\beta l}[/tex]

where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, [tex]\beta[/tex] is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.

                [tex]Q=8*10^{-6}m^3/s\\diameter=30mm, thus,\\r=15mm\\l=100m\\\beta =0.95[/tex]

                [tex]P=\frac{8Q\beta l}{\pi r^4} =\frac{8*8*10^{-6}*0.95*100}{3.14*(15*10^{-3})^4} \\\\P=3.824*10^4Pascals.[/tex]

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4 Pascals.

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Answer:

1. Vector, base

2. Vector, derived

3. Vector, ?

4. Scalar, derived

5. scalar, base

The application of faraday's law to the existence (not the sign) of the induced voltage before you energize the primary coil

The magnitude of the emf generated in a circuit is proportional to the rate of change with time t of the magnetic flux that cuts across the circuit emf, according to this relationship, also known as Faraday's law of induction (to distinguish it from his laws of electrolysis).

According to Faraday's law of induction, when a magnetic field changes, a voltage results. This difference in electric potential can induce electric currents to flow.

The first faraday's law states that the amount of chemical change caused by a current at an electrode-electrolyte interface is proportional to the amount of electricity used, while the second law states that different substances can undergo different amounts of chemical change when the same amount of electricity is applied to them.

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