A city block is 3 times as long as it is wide. If the distance around the city block is 16.8 kilometers, what is the area of the city block?

Answer:

P(x) = 0.7 [tex]x^{4}[/tex] - 4.9x³ + 5.6x² + 11.2x

Step-by-step explanation:

given a polynomial with roots x = a and x = b , then the factors are

(x - a) and (x - b)

If x = a is of multiplicity 2 then factor is (x - a)²

the polynomial is then the product of the factors

p(x) = a(x - a)(x - b) ← a is a multiplier

give x = 4 is a root with multiplicity 2 then (x - 4)² is the factor

x = 0 has factor (x - 0) , that is x

x = - 1 has factor (x - (- 1)) , that is (x + 1)

the polynomial is then the product of the factors

P(x) = ax(x + 1)(x - 4)² ← expand squared factor using FOIL

       = ax(x + 1)(x² - 8x + 16)

       = a(x² + x)(x² - 8x + 16) ← distribute

       = a([tex]x^{4}[/tex] - 8x³ + 16x² + x³ - 8x² + 16x)

      = a([tex]x^{4}[/tex] - 7x³ + 8x² + 16x)

to find a substitute (5, 21 ) into P(x)

21 = a([tex]5^{4}[/tex] - 7(5)³ + 8(5)² + 16(5))

21 = a(625 - 875 + 200 + 80)

21 = 30a ( divide both sides by 30 )

0.7 = a

then

P(x) = 0.7([tex]x^{4}[/tex] - 7x³ + 8x² + 16x) ← distribute parenthesis

P(x) = 0.7[tex]x^{4}[/tex] - 4.9x³ + 5.6x² + 11.2x

Answer:

Hope the picture will help you

Answer:(3-i) - (2 +6i)

Combine like terms:

3-2 = 1

-i  -  6i = -7i

Combine to get 1 -7i

Step-by-step explanation:

Part 1

[tex]\frac{x}{3.2}=\frac{4}{2} \implies x=6.4 \\ \\ \frac{y}{2.4}=\frac{2}{4} \implies y=1.2[/tex]

Part 2

[tex]\frac{x}{3.6}=\frac{10.8}{5.4} \implies x=7.2 \\ \\ \frac{y}{5.4}=\frac{15.2}{10.8} \implies y=7.6[/tex]

THE percent error is, 5

hence,THE percent error is, 5

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Answer: 7y = 38.11111111111   2y = 10.8888888889 the sum of these two equals to 49 so 11-49=-38 Hopefully you understood. But I didn't know what you wanted to know from this?

Step-by-step explanation: 11-(7y+2y)=-38

7y+2y=9y (basic math)

11-9y=-38  then you want to move -38 to the other side, and when you move it to the other side it changes its value then from -38 it becomes 38. Same for the -9y, we move it to the other side and it changes its value so now from -9y its 9y. So now are equation should look like this 11+38=9y.   11+38=49 => y=49÷9   y=5.44444444444   (49÷9) x 7 = 38.1111111111 and (49÷9) x 2 = 10.8888888889      

Answer: im pretty sure the answer is c

Step-by-step explanation:

if the answer is  not c im sorry but i hope this helps! Have a good day!

Solution of the given equation x² -6x +10 =0 using quadratic formula or perfect square method is same in complex number and is equal to   3 + i or 3 - i.

As given in the question,

Given equation is:

x² -6x +10 = 0

Complex number i² = -1

Using perfect square method:

x² -6x + 9 +10 -9 =0

⇒x² -6x +9 =-1

⇒ (x - 3)² = (i)²

⇒x-3 = ± i

⇒ x= 3 ± i

Using quadratic formula,

x = [ -(-6) ±√ (-6)² -4(1)(10)] / 2(1)

  =( 6 ± √-4)/ 2

  = (6± √4i²) /2

  = (6 ± 2i) / 2

  = 3 ± i

Therefore, solution of the given equation x² -6x +10 =0 using quadratic formula or perfect square method is same in complex number and is equal to 3 + i or 3 - i.

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Answer:

94.1224489796

this is the answer

Tony has 10.5 cookies.

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order term, where m is the slope and b is the y-intercept.

Given that, Adam has 6 cookies less than Tony, there are a total of 15 cookies between both of them.

Let the number of cookies Tony has be x,

x+x-6 = 15

2x - 6 = 15

2x = 21

x = 21/2 = 10.5

Hence, Tony has 10.5 cookies.

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Answer:

False

Step-by-step explanation:

using the rule of exponents

[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m-n)}[/tex]

given

[tex]\frac{9x^7}{3x^2}[/tex]

= [tex]\frac{9}{3}[/tex] × [tex]\frac{x^7}{x^2}[/tex]

= 3 × [tex]x^{(7-2)}[/tex]

= 3[tex]x^{5}[/tex]

Step-by-step explanation:

Jim has 65 coins in his pocket. All of the coins are nickels and dimes. If the total value of his coins is $5.10, how many nickels or dimes does he have?

nickels = n

dimes = d

We use:

d + n = 65

0.10d + 0.05n = 5.10

solve for d:

d + n = 65

d + n - n = 65 - n

d = 65 - n

substitute in for the second equation: d = 65 - n

0.10(65 - n) + 0.05n = 5.10

6.5 - 0.10n + 0.05n = 5.10

6.5 - 0.05n = 5.10

6.5 - 0.05n - 6.5 = 5.10 - 6.5

- 0.05n= -1.4

n = 28

so there are 28 nickels

Now, solve for d: when n = 28

d + n = 65

d + 28 = 65

d = 37

so there are 37 dimes

Jim has 28 nickels and 37 dimes in his pocket. which is determined by the substitution method.

The term "equation" refers to mathematical statements that have at least two terms with variables or integers that are equal.

Let the number of nickels would be n

Let the number of dimes would be d

As per the given question,

d + n = 65  ....(i)

0.10d + 0.05n = 5.10  ....(ii)

From equation (i),

d + n = 65

d + n - n = 65 - n

d = 65 - n

Substitute in for the equation(ii): d = 65 - n

0.10(65 - n) + 0.05n = 5.10

6.5 - 0.10n + 0.05n = 5.10

6.5 - 0.05n = 5.10

6.5 - 0.05n - 6.5 = 5.10 - 6.5

- 0.05n = -1.4

n = 28

This means there are 28 nickels

Substitute the value of n = 28 in the equation (i),

d + n = 65

d + 28 = 65

d = 37

So there are 37 dimes

Thus, Jim has 28 nickels and 37 dimes in his pocket.

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By using percentage, it can be calculated that

1) Percentage increase in area = 25 %

2) Percentage increase in area = 60 %

3) Percentage decrease in area = 25 %

4) Percentage decrease in area = 40 %

What is percentage?

Sometimes there is a number and the number has to be expressed as a fraction of 100. The fraction is called percentage.

For example 2% means [tex]\frac{2}{100}[/tex]. Here 2 is expressed as a fraction of 100

1) Original area = 12 sq. yard

   New area = 15 sq. yard

   Increase in area = 15 - 12 = 3 sq. yard

   Percentage increase = [tex]\frac{3}{12}\times 100 \\[/tex]

                                       = 25 %

1) Original area = 15 sq. yard

   New area = 24 sq. yard

   Increase in area = 24 - 15 = 9 sq. yard

   Percentage increase = [tex]\frac{9}{15}\times 100 \\[/tex]

                                       = 60 %

1) Original area = 12 sq. yard

   New area = 9 sq. yard

   Increase in area = 12 - 9 = 3 sq. yard

  Percentage decrease = [tex]\frac{3}{12}\times 100 \\[/tex]

                                       = 25 %

1) Original area = 10 sq. yard

   New area = 6 sq. yard

   Increase in area = 10 - 6 = 4 sq. yard

   Percentage increase = [tex]\frac{4}{10}\times 100 \\[/tex]

                                       = 40 %

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Answer: 0

Step-by-step explanation:

If the dividend and the divisor are the same, the quotient is always 1. If the dividend is the, then the quotient would always be 0. A division equation with 0 dividend and 0 divisor is not valid.

Answer: All real numbers

Step-by-step explanation: Anything that's being divided by 0, is always going to be 0. For example, 0/7 is always 0.

If  the total amount of period costs incurred to sell 9,000 units is closest to: D) $49,500.

First step is to find the variable selling and administrative expense per unit

Sales commissions $ 0.50

Add variable administrative expense 0.50

Variable selling and administrative expense per unit $ 1.00

Now let find the total amount of period costs

Total variable selling and administrative expense $9,000

($1.00 per unit × 9,000 unit)

Add total fixed selling and administrative expense 40,500

Total period cost $ 49,500

Therefore the correct option is D.

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The complete question is:

Shelp Corporation has provided the following information:

Cost per Unit Cost per Period

Direct materials $ 7.15

Direct labor $ 3.35

Variable manufacturing overhead $ 1.40

Fixed manufacturing overhead $ 81,000

Sales commissions $ 0.50

Variable administrative expense $ 0.50

Fixed selling and administrative expense $ 40,500

For financial reporting purposes, the total amount of period costs incurred to sell 9,000 units is closest to:

A) $33,000

B) $9,000

C) $40,500

D) $49,500

Answer:

3

Step-by-step explanation:

first factor out both the numbers

12:2*2*3

39:3*13

find the common ones and multiply them together

they both share only 3, so 3

The statement which is true about the y-values of the graph of the function as required is; Choice B; The y-values are all greater than or equal to 2.

It follows from the task content that the statement which is true regarding the y-values of the graph defined by; f(x) = lx-5l +2 is to be determined.

Therefore, we must recall that expressions enclosed in the absolute value sign upon evaluation are always greater than or equal to zero.

Hence, it can be concluded that we the y-values of the resulting graph to be greater than or equal to 2 (on the occasion that; lx-5l = 0).

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a) An equation relating the miles traveled to gallons of gas used is m = 14g.

b) With 3.7 gallons of gas, one can drive up to 51.8 miles.

An equation is a mathematical statement that makes two mathematical expressions equivalent or equal using the equation symbol (=).

Equations establish the equality of two or more values, variables, or numbers.

The total distance driven on one tank of gas = 168 miles

The quantity of gas used = 12 gallons

The number of miles per gallon of gas = 14 (168/12)

Let m = distance in miles

Let g = gallons of gas used

Equation: m = 14g

Solution:

Gallons of gas used = 3.7

m = 14g

= 14(3.7)

= 51.8 miles

Thus, based on the established equation, with 3.7 gallons of gas used, the driver can cover 51.8 miles.

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In the given circle, the values of required angles are as follow:

a = 51°, b = 28° , c = 31°, and d = 70°.

As given in the question,

In the given circle,

As we know by theorem , angles formed in the same arc are congruent.

Angle a° and angle 51° is formed in the same arc XY .

⇒ Value of a = 51°

Angle b° and angle 28° is formed in the same arc ZY .

⇒ Value of b = 28°

Angle c° and angle 31° is formed in the same arc WX .

⇒ Value of c = 31°

Angle d° and angle 70° is formed in the same arc WZ .

⇒ Value of d = 70°

Therefore, in the given circle the values of required angles are as follow:  a = 51°, b = 28° , c = 31°, and d = 70°.

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There are many things obstructing the route so yes. I cannot give a detailed answer as I have not been given the "distance formula" sorry

Answer: y+7=-4(x-2)

Answer: y+7=-4(x-2)

By using Pythagoras Theorem, it can be verified that

The hypotenuse of a triangle with shorter sides 1 unit each is not an integer

What is Pythagoras Theorem?

Pythagoras Theorem states that in a right angled triangle, the square of the hypotenuse is equal to the square of the sum of Perpendicular and base

According to the question given,

Shorter sides are 1 unit each

Let the length of the hypotenuse be h units

By Pythagoras Theorem,

[tex]h^2 = 1^2 + 1^2\\h^2 = 2\\h = \sqrt{2} \ units[/tex]

[tex]\sqrt{2}[/tex] is not an integer

So the hypotenuse here is not an integer.

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the equation of the perpendicular line is x = 4, as the line vertical and the slope is undefined

The point-slope formula is expressed as

y - y₁ = m( x - x₁ )

The slope intercept formula is expressed as;

y = mx + b

Where m is the slope and b is y-intercept.

Given the data in the question;

First, we determine the slope of the initial line by comparing to the slope intercept form y = mx + b

y = -2

Hence

Slope of initial line m = 0

Slope of the perpendicular line will be negative reciprocal of the initial line

m = -1/0

Slope m is undefined

Therefore, the perpendicular line is vertical and the slope is undefined

Hence.

x = 4.

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Answer:

d is great than -3

Step-by-step explanation:

because negative numbers are less than whole numbers

The number of students who wore School colors are 8/13. If, Ratio of  students who wore School colors to the number of students who didn't are given.

A ratio in mathematics is a comparison of two or more numbers that shows how big one is in comparison to the other. The dividend or number being divided is referred to as the antecedent, and the divisor or number that is dividing is referred to as the consequent. A ratio compares two numbers by division. A ratio in mathematics demonstrates how many times one number is present in another. For instance, if a dish of fruit contains eight oranges and six lemons, the ratio of oranges to lemons is eight to six. The ratio of oranges to the overall amount of fruit is 8:14, and the ratio of lemons to oranges is 6:8.

Given,

Ratio of  students who wore School colors to the number of students who didn't

8:5

Total number of student = 13

Number of students who wore school colors = 8/13

The number of students who wore School colors are 8/13. If, Ratio of  students who wore School colors to the number of students who didn't are given.

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The absolute value of the expression given as -2i  is 2i

From the question, we have the following parameters that can be used in our computation:

Expression = -2i

The absolute value of an expression is represented as

Absolute value = |Expression|

Substitute the known values in the above equation, so, we have the following representation

Absolute value = |-2i|

Evaluate the expression

Absolute value = 2i

Hence, the result of the expression is 2i

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The features of the functions when a quadratic function is given in the form: y = a (x − p) (x − q)

y = value in the y coordinates

a = constant in the equation

p and q = zeros or roots

x = value in the x coordinates

When quadratic equation is written of the form y = a (x − p) (x − q), it is called the factored form of quadratic equation

The other form is ax^2 + bx + c and called standard form of quadratic equation

a in both cases are same and it helps to da if the curve opens upward or downward

when a is positive the curve opens upward but when it is negative the curve opens downward

Expanding the factored form of quadratic equation brings the equation to the standard form

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Answer:

10^3 = 1000

Step-by-step explanation:

10 * 10 * 10 = 1000

Answer:

1000

Step-by-step explanation:

it is ten to the third power so 10*10*10  and then you get the answer of:

1000

I hope this helped!

The lines p and q are parallel.

Alternate Exterior Angles are a pair of angles on the outer side of each of those two lines, but on opposite sides of the transversal.

Given a figure,

Since, ∠ 1 ≅ ∠ 5 and they are alternate exterior angles, then we can conclude that p║q by alternate exterior angles theorem.

Hence, The lines p and q are parallel.

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