A company produces a product for which the variable cost is $12.77 per unit and the fixed costs are $94,000. The product sells for $17.98. Let x be the number of units produced and sold.

(a)

The total cost for a business is the sum of the variable cost and the fixed costs. Write the total cost C (in dollars) as a function of the number of units produced.

C =

(b)

Write the revenue R (in dollars) as a function of the number of units sold.

R =

(c)

Write the profit P (in dollars) as a function of the number of units sold. (Note: P = R − C.)

P =

Answers

Answer 1

The total cost as a function is given by C(x) = 12.77x + 94,000. The revenue is given by R(x) = 17.98x. The profit is given by P(x) = R(x) - C(x) = 17.98x - (12.77x + 94,000).

(a) The total cost C includes both the variable cost and the fixed costs. The variable cost is $12.77 per unit, so the total variable cost for x units produced is 12.77x. The fixed costs remain constant at $94,000. Therefore, the total cost C(x) as a function of the number of units produced x is given by C(x) = 12.77x + 94,000.

(b) The revenue R is the total income obtained from selling the units. Since the product sells for $17.98 per unit, the revenue R(x) as a function of the number of units sold x is given by R(x) = 17.98x.

(c) Profit P is calculated by subtracting the total cost C from the revenue R. Therefore, the profit P(x) as a function of the number of units sold x is given by P(x) = R(x) - C(x) = 17.98x - (12.77x + 94,000). This equation represents the profit made by the company based on the number of units sold.

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Related Questions

Work out the area of the shaded shape.

Answers

Answer:

the answer is 90 i believe

Step-by-step explanation:

Answer:

area = 69 cm²

Step-by-step explanation:

pink figure is a parallelogram ( opposite sides are parallel)

white figure is a rectangle

the shaded area = area of parallelogram - area of rectangle

                            = 10 × 9 - (3 × 7)

                           = 90 - 21

                           = 69 cm²



Which expressions are equivalent?I. cos θ II. cos (-θ) III. sin (-θ)/tan (-θ)}

(F) I and II only (H) I and III only

(G) II and III only (I) I, II, and III

Answers

The equivalent expressions among the given options are (I) I, II, and III. The expressions cos θ, cos (-θ), and sin (-θ)/tan (-θ) are all equivalent.

In trigonometry, cosine is an even function, meaning that cos (-θ) is equal to cos θ. This property holds true for any value of θ.

Similarly, sine and tangent are odd functions, meaning that sin (-θ) and tan (-θ) are equal to -sin θ and -tan θ, respectively. Therefore, sin (-θ)/tan (-θ) is equivalent to -sin θ/-tan θ, which simplifies to sin θ/tan θ.

Hence, all three expressions, cos θ, cos (-θ), and sin (-θ)/tan (-θ), represent the same trigonometric value and are equivalent to each other.

Therefore, the correct option is (I) I, II, and III.

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Solve the equation below and express the answer using set notation. If the answer is no solution, type "no solution". If the answer is all reals, type "R".
2∣4−x∣=7
{___, ____}

Answers

The equation 2∣4−x∣=7 has two solutions: x = -1 and x = 9.

To solve the equation, we isolate the absolute value term and apply the definition of absolute value. We start by dividing both sides of the equation by 2, which gives us ∣4−x∣=7/2. Now, we have two cases to consider:

Case 1: 4 - x = 7/2. Solving for x, we subtract 4 from both sides to get -x = -1/2. Multiplying both sides by -1 gives us x = 1/2. However, since we are dealing with absolute value, we take the negative value as well, so x = -1/2.

Case 2: 4 - x = -7/2. Solving for x, we subtract 4 from both sides to get -x = -15/2. Multiplying both sides by -1 gives us x = 15/2, which simplifies to x = 7.5.

Thus, the solutions to the equation are x = -1/2 and x = 7.5, or in set notation, { -1/2, 7.5 }.

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InΔRST, t=7 ft and s=13ft.Find each value to the nearest tenth.

Find m ∠ R for m ∠ S=70°.

Answers

The m∠ R for m ∠ S=70° is 26.4°.

In the question, it is given that t=7 ft and s=13 ft in ΔRST. To find out what is measure of ∠ R for measure of ∠ S as 70°, we have to make use of a formula which is known as Law of Sines. The law of sine states that, the ratio of the side of the triangle to it's opposite angle is constant.

In this case we have t=7 ft and s=13ft, so the equation becomes:

s / sin(S) = t / sin(R)

13 / sin (70) = 7 / sin (R)

sin(R) = 7/10 * sin (70)

sin(R) = 0.4409

m ∠ R = sin⁻¹(0.4409)

m ∠ R = 26.4°

Therefore, measure of ∠ R when measure of  ∠ S is 70° is 26.4°.

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A man drove 15 miles directly east from his home, made a left turn at an intersection, and then traveled 4 miles due north to his place of work. if a road was made directly from his home to his place of work what is the distance be?

Answers

The direct distance from the man's home to his place of work, if a road was made directly connecting the two points, is approximately √241 miles.

To find the distance from the man's home to his place of work if a road was made directly connecting the two points, we can use the Pythagorean theorem. This theorem relates the sides of a right triangle and allows us to calculate the hypotenuse, which represents the direct distance between the two points.

In this scenario, the man initially travels 15 miles directly east from his home and then makes a left turn, traveling 4 miles due north to his place of work. Let's visualize this as a right triangle:

```

      |\

      | \

   15 |  \ c (direct distance)

      |   \

      |    \

      ------

       4 (north)

```

To find the direct distance (c), we can use the Pythagorean theorem:

c² = a² + b²

Where:

- a represents the distance traveled directly east (15 miles)

- b represents the distance traveled due north (4 miles)

- c represents the direct distance from home to work (unknown)

Substituting the values into the equation, we have:

c² = 15² + 4²

c² = 225 + 16

c² = 241

Taking the square root of both sides, we find:

c = √241

Therefore, the direct distance from the man's home to his place of work, if a road was made directly connecting the two points, is approximately √241 miles.

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A bicycle with 22 -inch diameter wheels is traveling at 18 miles/hour. Find the angular speed of the wheels in radians/minute.

How many revolutions per minute do the wheels make?

Answers

The wheels of the bicycle make approximately 41.5 revolutions per minute.

To find the angular speed of the wheels in radians/minute, we first need to convert the linear speed from miles/hour to inches/minute. We know that 1 mile is equal to 5,280 feet and 1 foot is equal to 12 inches. Therefore, to convert miles/hour to inches/minute, we can multiply the given speed by 5,280 (conversion from miles to feet) and then by 12 (conversion from feet to inches) and divide by 60 (minutes in an hour).

18 miles/hour * 5,280 feet/mile * 12 inches/foot / 60 minutes = 18 * 5,280 * 12 / 60 = 18 * 1,056 = 18,048 inches/minute.

Next, we divide the linear speed in inches/minute by the circumference of the wheels in inches to obtain the angular speed. The circumference of a wheel can be calculated by multiplying the diameter by π (pi).

Circumference = diameter * π = 22 inches * 3.14159 = 69.1157 inches.

Angular speed = linear speed / circumference = 18,048 inches/minute / 69.1157 inches ≈ 260.91 radians/minute.

Finally, to find the number of revolutions per minute, we divide the angular speed in radians/minute by 2π (one revolution in radians).

Revolutions per minute = angular speed / (2π) = 260.91 radians/minute / (2π) ≈ 41.48 revolutions/minute ≈ 41.5 revolutions/minute (rounded to one decimal place).

Therefore, the wheels of the bicycle make approximately 41.5 revolutions per minute.

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Aaron's age is twice ashley's age and one-third of albert's age. if the sum of their ages is 99, what is the difference in age between the oldest and youngest?

Answers

The difference in age between the oldest and youngest is 55 years.

Given that Aaron is twice year old than Ashley and one-third of albert's age, sum of their ages is 99, we need to find the difference in age between the oldest and youngest,

Let's solve the problem step by step, we will use the concept of system of equations to solve this,

Let's assume Ashley's age as x.

According to the given information:

Aaron's age = 2 × Ashley's age = 2x

Albert's age = 3 × Aaron's age = 3 × (2x) = 6x

The sum of their ages is 99:

x + 2x + 6x = 99

9x = 99

x = 11

Now we can find the ages of Aaron and Albert:

Aaron's age = 2x = 2 × 11 = 22

Albert's age = 6x = 6 × 11 = 66

The difference in age between the oldest (Albert) and youngest (Ashley) is:

66 - 11 = 55

Therefore, the difference in age between the oldest and youngest is 55 years.

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What are the solutions of the equation 6x² + 9x - 15=0 ?

(A) 1,-15 . (B) 1,-5/2 . (C) -1,-5 . (D) 3, 5/2 .

Answers

The solutions of the equation 6x² + 9x - 15 = 0 are x = 1 and x = -5/2.

To find the solutions of the equation 6x² + 9x - 15 = 0, we can use the quadratic formula:

The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, a = 6, b = 9, and c = -15.

Substituting these values into the quadratic formula, we have:

x = (-9 ± √(9² - 4(6)(-15))) / (2(6))

x = (-9 ± √(81 + 360)) / 12

x = (-9 ± √441) / 12

x = (-9 ± 21) / 12

Now, we can simplify the solutions:

x₁ = (-9 + 21) / 12 = 12 / 12 = 1

x₂ = (-9 - 21) / 12 = -30 / 12 = -5/2

Therefore, the solutions of the equation 6x² + 9x - 15 = 0 are x = 1 and x = -5/2.

The correct option from the given choices is (B) 1, -5/2.

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let s be the set of all vectors of the form ⎡ ⎢ ⎣ 12 s 14 t − 2 s 19 t 13 s 6 t ⎤ ⎥ ⎦ . find a set of vectors in r 3 whose span is s . use as many of the answer boxes as needed, filling from left to right. leave unneeded boxes empty.

Answers

The set of vectors in ℝ³ whose span is S can be represented by the set:

{(12, 0, -2), (0, 14, 0), (0, 0, 19), (s, t, 0), (0, s, 13), (t, 0, 6)}.

To explain further, the set S is defined as the set of all vectors in the form ⎡ ⎢ ⎣ 12s 14t -2s 19t 13s 6t ⎤ ⎥ ⎦, where s and t can be any real numbers. In order to find a set of vectors in ℝ³ whose span is S, we need to identify vectors in ℝ³ that can be linearly combined to obtain any vector in S.

The vectors in the answer set have been carefully chosen to ensure that any vector in S can be expressed as a linear combination of these vectors. The first three vectors, (12, 0, -2), (0, 14, 0), and (0, 0, 19), are included to cover the constants in S. The remaining vectors, (s, t, 0), (0, s, 13), and (t, 0, 6), incorporate the variables s and t, allowing for flexibility in generating the desired vectors.

By varying the values of s and t, we can obtain different linear combinations of the vectors in the answer set, covering all possible vectors in S. Therefore, the set of vectors {(12, 0, -2), (0, 14, 0), (0, 0, 19), (s, t, 0), (0, s, 13), (t, 0, 6)} forms a set in ℝ³ whose span is S.

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A German worker takes 400 hours to produce a car and 2 hours to produce a case of wine. A French worker takes 600 hours to produce a car and X hours to produce a case of wine.



a) For what values of X will gains from trade be possible? Explain.

b) For what values of X will Germany export cars and import wine? Explain.

Answers

Germany will export cars and import wine when X (the time required to produce a case of wine in France) is less than 3, indicating that France has a comparative advantage in wine production and Germany has a comparative advantage in car production.

a) To determine the values of X for which gains from trade are possible, we need to compare the opportunity costs of car and wine production between Germany and France. The opportunity cost is the ratio of the number of hours required to produce one unit of one good to the number of hours required to produce one unit of the other good.

For Germany, the opportunity cost of producing a car is 400 hours/2 hours = 200 cases of wine per car.

For France, the opportunity cost of producing a car is 600 hours/X hours = 600/X cases of wine per car.

Gains from trade occur when the opportunity costs differ between countries, allowing them to specialize in the production of goods with lower opportunity costs and trade with each other. In this case, Germany has a lower opportunity cost of producing cars compared to wine (200 < 600/X), while France has a lower opportunity cost of producing wine compared to cars (600/X < 200).

To ensure gains from trade, Germany will specialize in car production, and France will specialize in wine production. Therefore, for gains from trade to be possible, the value of X must lie between the opportunity costs of car production for Germany and France, which is 200 < X < 600.

b) Germany will export cars and import wine when it has a comparative advantage in car production (lower opportunity cost) and France has a comparative advantage in wine production (lower opportunity cost).

Since Germany's opportunity cost of producing a car is 200 cases of wine per car, it will export cars if the opportunity cost of wine production in France (600/X) is higher than 200. Therefore, for Germany to export cars and import wine, the value of X must satisfy the condition 600/X > 200, which simplifies to X < 3.

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determine whether the equation represents y as a function of x.
x²+y²=4

Answers

The equation x² + y² = 4 does not represent y as a function of x.

In the given equation, x² + y² = 4, we have a circle with a radius of 2 centered at the origin (0, 0). To determine if y can be expressed as a function of x, we need to check if for every value of x, there is a unique corresponding value of y. However, in this equation, for each value of x, we have two possible values of y due to the ± square root in the equation. For example, when x = 1, we have y = ±√3. This means that for a given x, there are multiple possible values of y, violating the criteria for a function. Therefore, the equation x² + y² = 4 does not represent y as a function of x.

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Based on PG\&E's (the northern California local utility) emissions factor of 0.524lbsCO 2
​ /kWh, how much carbon dioxide (in lbs.) is emitted over the course of a year if a home uses 9,000kWh annually?

Answers

Based on PG&E's emissions factor of 0.524 lbs CO2/kWh, a home that uses 9,000 kWh annually would emit approximately 4,716 lbs of carbon dioxide over the course of a year.

To calculate the amount of carbon dioxide emitted, we multiply the number of kilowatt-hours (kWh) used by the emissions factor. In this case, the emissions factor provided by PG&E is 0.524 lbs CO2/kWh. Therefore, for a home using 9,000 kWh annually, we can calculate the emissions as follows:

Emissions = 9,000 kWh * 0.524 lbs CO2/kWh

          = 4,716 lbs CO2

So, the home would emit approximately 4,716 lbs of carbon dioxide over the course of a year.

It's important to note that this calculation is based on the emissions factor provided by PG&E, which represents the average amount of carbon dioxide emissions associated with each kilowatt-hour of electricity consumed. The actual emissions may vary depending on factors such as the energy mix used by the utility and the efficiency of the home's electrical appliances.

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List the numbers in the eighth row of Pascal's Triangle.

Answers

The numbers in the eighth row of Pascal's Triangle are 1 7 21 35 35 21 7 1.

The numbers in the eighth row of Pascal's Triangle are:

1 7 21 35 35 21 7 1

In Pascal's Triangle, each number is obtained by adding the two numbers directly above it. The first and last numbers in each row are always 1. To generate subsequent rows, we add the adjacent numbers from the previous row to obtain the new numbers.

For example, to generate the eighth row:

Row 7: 1

Row 8: 1  +  7  +  21  +  35  +  35  +  21  +  7  +  1

Therefore, the numbers in the eighth row of Pascal's Triangle are 1 7 21 35 35 21 7 1.

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In this problem, you will use inequalities to make comparisons between the sides and angles of two triangles.


a. Draw three pairs of triangles that have two pairs of congruent sides and one pair of sides that is not congruent. Mark each pair of congruent sides. Label each triangle pair A B C and D E F , where AB ⊕ DE and AC ⊕ DF .

Answers

A. Two pairs of congruent sides can be found in the triangles ABF and ACE.

B. To illustrate the triangles with two pairs of congruent sides and one pair of sides that is not congruent, we can consider the following examples:

Example 1:

Triangle A B F: A B = A F congruent sides, B F ≠ D E not congruent

Triangle A C E: A C = A E congruent sides, C E ≠ D F not congruent

Example 2:

Triangle A B C: A B = A C congruent sides, B C ≠ D E not congruent

Triangle D E F: D E = D F congruent sides, E F ≠ A C not congruent

Example 3:

Triangle A B E: A B = A E congruent sides, B E ≠ D F not congruent

Triangle C D F: C D = C F congruent sides, D F ≠ A C not congruent

In each of these examples, we have two pairs of congruent sides marked as congruent sides and one pair of sides that is not congruent marked as not congruent.

The letters A, B, C, D, E, and F are used to label the vertices of the triangles for clarity.

These examples demonstrate how triangles can have two pairs of congruent sides and one pair of sides that is not congruent, allowing for comparisons to be made using inequalities.

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Use the given inverse of the coefficient matrix to solve the following system. 
7x1 + 3x2 = 9
-6x1 - 3x2 = 2

A^(-1) = {1 1}
{-2 -7/3}



 Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. A. x1 = and x2 =
(Simplify your answers.) B. There is no solution.

Answers

The solution to the system of equations is x1 = 3 and x2 = -1.

We are given the inverse of the coefficient matrix, so we can use it to solve the system of equations. The inverse of the coefficient matrix is:

```

A⁻¹ = [1 1

-2 -7/3]

```

We can multiply the inverse of the coefficient matrix by the column vector of constants to get the solution vector. The column vector of constants is:

```

b = [9

2]

```

Multiplying these two vectors, we get:

```

A⁻¹ * b = [1 1

-2 -7/3] * [9

2] = [3

-1]

```

Therefore, the solution to the system of equations is x1 = 3 and x2 = -1.

To see this, we can substitute these values into the original system of equations. We get:

```

7 * 3 + 3 * (-1) = 9

-6 * 3 - 3 * (-1) = 2

```

Simplifying both sides of these equations, we get:

```

9 = 9

-12 + 3 = 2

```

As we can see, both equations are satisfied. Therefore, x1 = 3 and x2 = -1 is the solution to the system of equations.

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The sum of the measures of the interior angles of a regular polygon is given. Find the number of sides in the polygon.

720

Answers

The number of sides in the polygon is 6

Find the number of sides in the polygon.

From the question, we have the following parameters that can be used in our computation:

Sum of the measures of the interior angles = 720

The sum of the measures of the interior angles is calculated as

Sum = 180(n - 2)

Using the above as a guide, we have the following:

180(n - 2) = 720

So, we have

n - 2 = 4

So, we have

n = 6

Hence, the number of sides is 6

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What is the simplified expression for negative 2 a squared b a squared minus 5 a b 3 a b squared minus b squared 2 (a squared b 2 a b)? a squared minus 9 a b 3 a b squared a squared 9 a b minus b squared 3 a b squared 10 a b a squared minus b squared 3 a b squared a squared minus b squared minus a b

Answers

The simplified expression for the given expression is "a squared minus b squared minus a b."

To simplify the given expression, let's break it down step by step:

- Negative 2 a squared b a squared: This term remains the same in the simplified expression.

- Minus 5 a b: This term remains the same in the simplified expression.

- 3 a b squared minus b squared: This can be simplified as (3 a b squared) - (b squared) = 3 a b squared - b squared.

- 2 (a squared b 2 a b): This can be simplified as 2 (a squared b) - 2 (a b) = 2 a squared b - 2 a b.

Now, combining all the simplified terms, we have:

-2 a squared b a squared - 5 a b + 3 a b squared - b squared + 2 a squared b - 2 a b

Simplifying further, we can group like terms:

-2 a squared b + 2 a squared b - 5 a b - 2 a b + 3 a b squared - b squared

Combining like terms, we get:

0 - 7 a b + 3 a b squared - b squared

Finally, rearranging the terms in decreasing order of degree, we have:

- b squared + 3 a b squared - 7 a b

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A card is drawn from a standard deck of cards. Find each probability, given that the card drawn is black.

P (diamond)

Answers

The probability of drawing a diamond card, given that the card drawn is black, is 0. There are 52 cards in a standard deck of cards, with 26 black cards and 26 red cards.

The black cards are divided into two suits: spades and clubs. There are 13 spades and 13 clubs. There are no black diamond cards. If we draw a black card, there are 26 possible cards that we could have drawn. There are 0 possible cards that we could have drawn that are both black and diamond. Therefore, the probability of drawing a diamond card, given that the card drawn is black, is 0.

To calculate the probability, we can use the following formula:

P(A|B) = P(A and B) / P(B)

where A is the event of drawing a diamond card and B is the event of drawing a black card.

We know that P(A and B) = 0 because there are no black diamond cards. We also know that P(B) = 26/52 = 1/2 because there are 26 black cards in a deck of 52 cards.

Therefore, P(A|B) = 0 / 1/2 = 0.

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Hannah is picking her activities for this year. She wants to play one sport, join one club, participate in one music activity, and volunteer at one place. The sports she can play are lacrosse, basketball, and tennis. The clubs she is considering are the maths club, the science club, the speech club, and the drama club. For music, Hannah can pick piano lessons, orchestra, or jazz band. She can volunteer at the art museum, library, or zoo. How many different combinations of activities can Hannah pick?

Answers

Hannah can pick is 108.Hannah is picking her activities for this year. She wants to play one sport, join one club, participate in one music activity, and volunteer at one place. The sports she can play are lacrosse, basketball, and tennis.

The clubs she is considering are the maths club, the science club, the speech club, and the drama club. For music, Hannah can pick piano lessons, orchestra, or jazz band. She can volunteer at the art museum, library, or zoo.

Hannah has to pick one sport from three, one club from four, one music activity from three, and one place to volunteer from three. To determine the number of different combinations, we have to find the product of all the possibilities:3 (sports) x 4 (clubs) x 3 (music) x 3 (volunteer places)= 108The number of different combinations of activities

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A circle with a diameter of 12 has its center in the second quadrant. The lines y=-4 and x=1 are tangent to the circle. Write an equation of the circle.

Answers

The calculated equation of the circle is (x + 7)² + (y - 2)² = 36

How to determine the equation of the circle

From the question, we have the following parameters that can be used in our computation:

Tangent lines, y = -4 and x = 1

The diameter, d = 12 units

So, we have

radius, r = 12/2

r = 6

The center is in the second quadrant

So, we have center = (-x, y).

Calculating x and y, we have

|-4 - y| = radius and |1 - (-x)| = radius

So, we have

|-4 - y| = 6 and |1 - (-x)| = 6

b = y = 2 and a = x = -7

The equation of a circle is

(x - a)² + (y - b)² = r²

So, we have

(x + 7)² + (y - 2)² = 6²

(x + 7)² + (y - 2)² = 36

Hence, the equation of the circle is (x + 7)² + (y - 2)² = 36

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A bird is flying south at a rate of 45 miles per hour while being pushed east by wind with a speed of 12 miles per hour. What is the magnitude of the bird's resultant vector? Hint: Draw a vector diagram. R = [ ? ] mph Round your answer to the nearest hundredth.

Answers

The magnitude of the bird's resultant vector is 46.57 miles per hour (rounded to the nearest hundredth).

To calculate the magnitude of the bird's resultant vector, we will use Pythagoras' theorem. Let's begin with the vector diagram. The resultant vector (R) can be found by connecting the vectors V1 and V2. To find the magnitude of the resultant vector, we need to use the following formula:

R = √(V1² + V2²) Where V1 is the bird's speed, which is 45 miles per hour in this case, and V2 is the wind's speed, which is 12 miles per hour. R = √(45² + 12²)R = √(2025 + 144)R = √2169R = 46.57 mph

Therefore, the magnitude of the bird's resultant vector is 46.57 miles per hour (rounded to the nearest hundredth).

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The table below gives the drainage area, average precipitation (determined from measurements at meteorological stations), and average streamflow (measured near the mouths) of four major rivers. [10 points] (i) Using water balance equation and assuming no ground-water inputs or outputs, use this information to compute the estimated long-term average evapotranspiration, ET (mm/yr), for each watershed. (ii) How well do your calculated ET values conform to those shown for the same watersheds on the figure below? The figure shows global distribution of average oceanic evaporation and continental transpiration ( cm/ year) from Peixoto and Oort (1992). Please note that the contour interval on figure is 200 or 400 mm/yr, so only coarse comparisons can be made.

Answers

(i) Equation for estimated long-term average evapotranspiration is          ET = P - Q. (ii) The calculated ET values can be compared to the global distribution of average oceanic evaporation and continental transpiration shown on the figure.

(i) To compute the estimated long-term average evapotranspiration (ET) for each watershed, we can use the water balance equation. The equation is as follows:

Precipitation (P) = Streamflow (Q) + Evapotranspiration (ET)

Assuming no groundwater inputs or outputs, we can rearrange the equation to solve for ET:

ET = P - Q

By subtracting the average streamflow (Q) from the average precipitation (P) for each watershed, we can obtain the estimated long-term average evapotranspiration (ET) in millimeters per year (mm/yr).

(ii) The calculated ET values can be compared to the global distribution of average oceanic evaporation and continental transpiration shown on the figure. While the figure provides a coarse comparison due to its contour interval of 200 or 400 mm/yr, it can still give an indication of how well the calculated ET values conform to the values shown.

To assess the conformity, we can compare the calculated ET values for each watershed with the values shown on the figure within the same range. If the calculated ET values fall within the contour intervals or are close to the values depicted on the figure, it suggests a reasonable conformity. However, if the calculated ET values significantly deviate from the values shown, it indicates a disparity between the estimated and observed evapotranspiration patterns.

It's important to note that the figure provides a global representation, and the calculated ET values are specific to the four major rivers considered in the table. Therefore, a coarse comparison is expected, and finer-scale analysis may be required to make more accurate assessments of conformity between the calculated ET values and those shown on the figure.

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Assume a general Cobb-Douglas production function, y=Ax
1
h
1



x
2
b
2



. i) Prove that the above production function is negatively sloped and convex to the origin ii) What signs should the parameters be for the function to be well-behaved? Show your work. iii) Find the equation of the isocline defined by RTS=1, where RTS is the marginal rate of technical substitution.

Answers

i)  The Cobb-Douglas production function y = [tex]Ax^1h^1x^2b^2[/tex] is negatively sloped and convex to the origin. ii) These positive signs ensure that the partial derivatives and second-order partial derivatives are positive or non-negative. iii) This equation represents the isocline defined by RTS = 1 for the given Cobb-Douglas production function.

i) To prove that the Cobb-Douglas production function y = Ax^1h^1x^2b^2 is negatively sloped and convex to the origin, we need to show that the partial derivatives with respect to x1 and x2 are positive, and the second-order partial derivatives are non-negative.

Partial derivatives:

∂y/∂x1 = A *[tex](1 * x^1 * h^1 * x^2b^2) / x1 = A * h^1 * x^2b^2[/tex]

∂y/∂x2 = A *[tex](1 * x^1 * h^1 * x^2b^2) / x2 = A * x^1 * h^1 * b^2 * x2(b^2-1)[/tex]

The partial derivatives are positive since A, h^1, and x^1 are assumed to be positive parameters.

Second-order partial derivatives:

∂^2y/∂x[tex]1^2[/tex] = [tex]A * h^1 * x^2b^2 > 0[/tex]

∂^2y/∂x[tex]2^2[/tex] = [tex]A * x^1 * h^1 * b^2 * (b^2-1) * x2(b^2-2) > 0[/tex]

The second-order partial derivatives are non-negative since A, [tex]h^1,[/tex] and [tex]b^2[/tex] are assumed to be positive parameters.

Therefore, the Cobb-Douglas production function y = [tex]Ax^1h^1x^2b^2[/tex] is negatively sloped and convex to the origin.

ii) For the function to be well-behaved, the parameters A, [tex]h^1,[/tex] and [tex]b^2[/tex] should have the following signs:

- A should be positive, as it represents the overall productivity level of the production function.

-[tex]h^1[/tex] should be positive, as it represents the elasticity of output with respect to the input factor x1.

- [tex]b^2[/tex] should be positive, as it represents the elasticity of output with respect to the input factor x2.

These positive signs ensure that the partial derivatives and second-order partial derivatives are positive or non-negative, leading to a well-behaved and meaningful production function.

iii) The marginal rate of technical substitution (RTS) for a Cobb-Douglas production function is defined as the ratio of the marginal product of one input to the marginal product of the other input:

RTS = (∂y/∂x1) / (∂y/∂x2)

From the partial derivatives calculated earlier, we have:

RTS = [tex](A * h^1 * x^2b^2) / (A * x^1 * h^1 * b^2 * x2(b^2-1))[/tex]

    =[tex](x^2b^2) / (x^1 * b^2 * x2(b^2-1))[/tex]

    = [tex](x^2b^2) / (x^1 * x2(b^2-1))[/tex]

To find the isocline defined by RTS = 1, we set RTS equal to 1:

1 =[tex](x^2b^2) / (x^1 * x2(b^2-1))[/tex]

Simplifying, we get:

[tex]x2(b^2-1) = x^1 * x^2b^2[/tex]

This equation represents the isocline defined by RTS = 1 for the given Cobb-Douglas production function.

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The percentage of adult height attained by girls who are x years old can be modeled by f(x)=62+35log(x−4), where x represents the girl's age (from 5 to 15) and f(x) represents the percentage of her adult height. Use this function to determine approximately what percent of her adult height girls are at age 11.

Answers

Approximately at age 11, girls are at about 78.45% of their adult height based on the given function f(x) = 62 + 35log(x-4), where x represents the girl's age.

We are given the function f(x) = 62 + 35log(x-4), where x represents the girl's age from 5 to 15, and f(x) represents the percentage of her adult height. To determine the approximate percentage of her adult height at age 11, we substitute x = 11 into the function.

f(11) = 62 + 35log(11-4)

= 62 + 35log(7)

Evaluating the logarithm, we find log(7) ≈ 0.8451. Plugging this value into the equation, we get:

f(11) ≈ 62 + 35(0.8451)

≈ 62 + 29.4779

≈ 91.4779

Therefore, at approximately age 11, girls are at about 91.48% of their adult height based on the given function.

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What is the minimum number of integers from 1 through 100 that must be picked in order to be sure of getting one that is divisible by 5?

Answers

If we pick 20 integers from 1 through 100, we can guarantee that at least one of them will be divisible by 5.

To determine the minimum number of integers from 1 through 100 that must be picked in order to be sure of getting one that is divisible by 5, we can analyze the worst-case scenario.

The integers from 1 to 100 can be divided into 20 groups, each containing 5 consecutive integers that are multiples of 5 (e.g., 5, 6, 7, 8, 9). In each group, at least one of the integers will be divisible by 5.

To ensure that we pick at least one integer divisible by 5, we need to pick one integer from each of the 20 groups. Therefore, the minimum number of integers that must be picked is 20.

In other words, if we pick 20 integers from 1 through 100, we can guarantee that at least one of them will be divisible by 5.

Note that in practice, we may pick a number divisible by 5 earlier than the 20th pick, but to ensure that we have at least one such number, we need to pick 20 integers.

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Designs of experiments (DOE) is a tool for analyzing potential reliability problems and weaknesses in a product or process a statistical measure used to determine whether there is a statistical, not random, difference in the means of two groups of data a statistical technique used in Six Sigma to collect, analyze, and interpret data a structured, organized method for determining whether there is a statistical correlation between two variables Productivity is broadly defined as output divided by input the quality-productivity ratio quality cost divided by production cost yield divided by total planned units

Answers

DOE is a statistical tool for analyzing reliability issues, while productivity is a measure of efficiency. Designs of experiments (DOE) is a statistical technique used in Six Sigma to collect, analyze, and interpret data.

It is a structured and organized method for determining whether there is a statistical correlation between two variables. DOE helps in identifying potential reliability problems and weaknesses in a product or process by systematically varying the factors and observing their impact on the output.

Productivity is a measure that broadly defines the efficiency of a process or system. It is calculated by dividing the output by the input. On the other hand, the quality-productivity ratio refers to the relationship between the quality and productivity of a product or process. It can be represented by the ratio of quality cost divided by production cost or the ratio of yield divided by total planned units.

In summary, DOE is a statistical tool for analyzing reliability issues, while productivity is a measure of efficiency. The quality-productivity ratio assesses the relationship between quality and productivity by considering factors such as quality cost, production cost, and yield.

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Find the equation (in terms of x ) of the line through the points (−3,6) and (1,−6)
y =

Answers

The equation of the line passing through the points (-3, 6) and (1, -6) is y = -3x - 3

To find the equation of the line passing through the points (-3, 6) and (1, -6), we can use the slope-intercept form of a linear equation: y = mx + b.

First, let's calculate the slope (m) of the line using the formula:

m = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

Using the coordinates (-3, 6) and (1, -6), we have:

m = (-6 - 6) / (1 - (-3)) = -12 / 4 = -3

Now that we have the slope, we can choose any of the given points to substitute into the equation y = mx + b and solve for the y-intercept (b).

Using the point (-3, 6):

6 = -3(-3) + b

6 = 9 + b

b = 6 - 9

b = -3

Therefore, the equation of the line in terms of x is:

y = -3x - 3

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How is the domain of an ellipse different from the domain of a hyperbola?

Answers

The domain of an ellipse refers to the set of all possible x-values that lie on the ellipse. It can vary depending on the specific characteristics of the ellipse, but it generally spans the entire real number line.

On the other hand, the domain of a hyperbola is more restricted. It consists of two separate intervals on the x-axis, each corresponding to one branch of the hyperbola. These intervals are determined by the asymptotes and the x-intercepts of the hyperbola.

The general formula for the domain of an ellipse is -a ≤ x ≤ a, where 'a' represents the distance from the center to the vertex along the major axis. This accounts for the fact that the ellipse is symmetric with respect to its center.

For a hyperbola, the domain is defined by the equation x < -a or x > a, where 'a' is the distance from the center to the vertex along the transverse axis. This indicates that the hyperbola has two distinct branches, one to the left and one to the right of the center.

In summary, the domain of an ellipse typically covers the entire real number line, while the domain of a hyperbola is split into two separate intervals determined by the asymptotes and x-intercepts of the hyperbola.

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A circle has the equation (x-5)^{2}+ (y+7)^{2}=16 . If the center of the circle is shifted 3 units right and 9 units up, what would be the equation of the new circle? Explain your reasoning.

Answers

The equation of the new circle is (x - 2)² + (y - 2)² = 16

How to determine the equation of the new circle?

From the question, we have the following parameters that can be used in our computation:

(x - 5)² + (y + 7)² = 16

When the center of the circle is shifted 3 units right and 9 units up, we hvae

(x - 5 + 3)² + (y + 7 - 9)² = 16

Evaluate

(x - 2)² + (y - 2)² = 16

Hence, the new equation is (x - 2)² + (y - 2)² = 16

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Julian owns a three-storey house in Yuen Long and wishes to install solar panels on its 250 m2 roof for electricity generation. An engineering company quoted a unit price of $1,800/m2 for the supply and installation of solar panels. This installation could save Julian $38,000 per year on the electricity fee. Based on the additional information provided below, advise on the financial viability of this installation if the discount rate is 3%. - Design life of the house: 80 years - Design life of the solar panels: 30 years (after which no maintenance is required) - Replacement costs: 90% of the initial cost - No. of solar panels installed: 125, each measuring 2mx - 1 m - Annual replacement of solar panels: 5% of the total number of panels at $2,500/ panel (with maintenance still required during the years in which replacements occur) - Maintenance cost: $5,000 (to be paid at the end of each year) - Dismantling costs: $20,000 - Salvage value: $48,000 Three years ago, Yvonne acquired land in Tin Hau and constructed a three-storey house on it to run a staycation business. Each floor contains six rooms of varying sizes, and the total lettable floor space is 250 m2. According to previous accounting records, the average rental price of this three-storey house is $65/ft2/month (based on the lettable floor space), and the occupancy rate is 85%. The yield of similar properties in the region is 2.55%. Considering a change in market conditions, Yvonne has prepared a proposal to redevelop this property into a four-storey hotel. The details are provided below. The redevelopment will cost Yvonne $1.5M for demolishing the existing building and $28M for constructing the hotel, and she will pay a design fee amounting to 6.5% of the construction cost. Because of the change in land use, the government will charge her an additional land premium of $21M. Additionally, the required finance charge is $0.9M, and the loss of income during redevelopment will be $10.5M. Upon completion, Yvonne can rent the property out at $200,000/ floor/month with an expected occupancy rate of 82%. The yield of comparable properties is 2.75%. For both types of development, it is assumed that annual rental incomes are received at the beginning of each year. Advise whether the proposed change is financially feasible. Further to section (b) above, explain possible catalysts that caused Yvonne to realise the change of land use. Kelvin has recently bought an apartment in Hung Hom. He plans to secure a loan of $18M from a bank and repay it in 15 years, with a mortgage rate of 2.5% p.a. If he chooses to extend the repayment period to 20 years, how much more will he need to pay each month and how much will the total interest be?

Answers

Based on the given information, the installation of solar panels on Julian's house appears to be financially viable, considering a discount rate of 3%. Yvonne's proposal to redevelop her property into a 4-storey hotel seems financially feasible, and Kelvin's decision to extend the repayment period of his loan will result in higher monthly payments and increased total interest paid.

For Julian's solar panel installation, the financial viability can be assessed by comparing the present value of cash inflows (savings on electricity fee) with the present value of cash outflows (initial cost, maintenance cost, replacement cost, dismantling cost, and salvage value). By discounting future cash flows at a rate of 3%, the net present value (NPV) can be calculated. If the NPV is positive, it indicates that the project is financially viable.

Yvonne's proposal for property redevelopment involves considering the costs of demolishing the existing building, constructing the hotel, design fees, land premiums, finance charges, and loss of income during redevelopment. The rental income from the hotel, considering the expected occupancy rate and market yield, needs to be compared with the costs to determine the financial feasibility. Calculating the net present value (NPV) of the project by discounting future cash flows can provide insights into its feasibility.

Possible catalysts for Yvonne to consider the change of land use could include market demand for hotels in the area, changes in tourism trends, or the potential for higher rental income from operating a hotel compared to a staycation business.

If Kelvin chooses to extend the repayment period of his loan from 15 years to 20 years, the monthly payments will be higher due to the longer repayment period. The total interest paid will also increase because the loan is extended over a longer duration, resulting in more interest accrual over time. The specific calculations can be performed using the loan amount, interest rate, and respective repayment periods.

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