The number of particles in a substance can be calculated by multiplying the number of moles of the substance by Avogadro's Number ~ 6.02 × 10²³ particles/mol. Therefore to find the number of moles based on the number of particles, you would divide the number of moles by Avogadro's Number.
Since # of particles of H₂O = 5.3×10¹² particles
then # of moles of H₂O = 5.3×10¹² particles ÷ 6.02 × 10²³ particles/mol
= 8.804 × 10⁻¹² moles
A student following the reaction seen here calculated a theoretical yield of 38.3g C₆H₅Cl but when he did the experiment in the lab he actually produced 36.8 g of C₆H₅Cl. What is the percent yield? *
Answer:
96.1 %
Explanation:
Which teacher do you have lol
The concentration of hydroxide ions is greater than the concentration of hydronium ions for acidic solution. True or false.
Answer: False
Explanation:
An acid is defined as the substance which looses hydrogen ion or hydronium ions when dissolved in water.
A base is defined as the substance which looses hydroxide ions when dissolved in water.
If the solution has higher hydronium ion concentration as compared to the hydroxide ion concentration, then the pH will be low and the solution will be acidic.
If the solution has low hydronium ion concentration as compared to the hydroxide ion concentration then the pH will be high and the solution will be basic.
Which of the following is the correct definition of conduction?
A.
the transmission of heat across empty space
B.
the electromagnetic radiation from the surface of an object which is due to the object's temperature
C.
the transfer of heat by currents within a liquid or gas
D.
the transmission of heat across matter
Answer:
the transmission of heat across matter
Explanation:
Conduction is the transmission of heat across matter. Even though heat flows across matter during conduction, the matter itself does not flow.
A solution has a [H3O+] of 1x 10-5 M. What is the [OH-] of the solution? (5 points)
9M
14M
1x 10-'M
1x 10-14M
Answer:
1x10^–9 M
Explanation:
From the question given,
Concentration of hydronium ion, [H3O+] = 1x10^-5 M.
Concentration of Hydroxide ion, [OH-] =..?
The concentration of the hydroxide ion, [OH-] can be obtained as follow:
[H3O+] x [OH-] = 1x10^–14
1x10^-5 M x [OH-] = 1x10^–14
Divide both side by 1x10^-5
[OH-] = 1x10^–14 / 1x10^-5
[OH-] = 1x10^–9 M
The [OH⁻] concentration of the solution is 1 * 10⁻⁹M.
What is pH value ?pH value is the measure of the acidity and alkalinity of a solution , The pH value has the range of 0 to 14, where 0-7 is the range for acid , 7 is for neutral solution , 7-14 is for alkaline solution.
[H3O⁺] = 1* 10⁻⁵ M
We can calculate the value of OH⁻ concentration by using the formula
[H⁺][OH⁻] = 1* 10⁻¹⁴
1* 10⁻⁵ * [OH⁻] = 1* 10⁻¹⁴
[OH⁻] = 1 * 10⁻⁹
Therefore the [OH⁻] concentration is 1 * 10⁻⁹M .
To know more about pH value
https://brainly.com/question/1503669
#SPJ5
Which 1.0 M solution has the lowest pH?
A.
HCN
B.
H3PO4
C.
H2C2O4
D.
HCl
HELP PLEASE You may select a topic from the list below, or choosese a topic about our solar system
Answer:
ok i see it
Explanation:
Answer: the planets, gravity, the galaxies
Explanation:
Write anything you want about it .
For example, there are 8 planets and their names
Why is a telephone considered an example of matter?
Answer:
Matter is anything that is made up of atoms. Whether its a computer, a drink, a suitcase, a telephone, whatever.
If it has mass, if it occupies space, and if it has volume, then it is matter.
Also, matter comes in the form of solids, liquids, and gasses.
In this case, the telephone is a solid.
plzzz mark me brainliest if this helped :)
I need 3 more brainliests to become an expert
Answer:
Matter is anything that is made up of atoms.
Explanation:
If it has mass, occupies space, and has volume, then it is matter. Also, matter comes in the form of solids, liquids, and gasses. The telephone is a solid.
HELP ME PLEASE 40 POINTS You may select a topic from the list below, or choose your own.
black hole
oort cloud
star types (supergiant, red dwarf, white dwarf)
supernovae
planetary nebulae
Andromeda galaxy
quasar
Use the library and other resource materials to research and understand your topic. Remember that nasa.gov is a web site that has reliable information as well that you may use for your research. Now write a 300-word report on what you have learned in the essay box below.
Answer:
Do black hole
Explanation:
How much faster will Xenon escape out and opening than carbon dioxide gas?
gas with the smallest amount of molecular weight will effuse the quickest
Can someone help me with this?
Answer:
D) condensing C) boiling
Chloroform is a commonly used anesthetic with a density of 1.483 g/mL. Determine the volume of chloroform needed to deliver a 9.37 g sample of the anesthetic
Answer:
The correct answer is 6.32 ml
Explanation:
We have the following data:
Mass : m = 9.37 g
Density : d= 1.483 g/mL
The density a substance is equal to the mass of the substance divided into its volume. So, we calculate the volume (V) of chloroform from the mass and density as follows:
[tex]d=\frac{m}{V}[/tex] ⇒ [tex]V = \frac{m}{d} = \frac{9.37 g}{1.483 g/ml} = 6.32 ml[/tex]
A gas has a volume of 3.25 liters at 54 C and 231 kPa of pressure. At what temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa?
Answer: 318 K
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 231 kPa
[tex]P_2[/tex] = final pressure of gas = 168 kPa
[tex]V_1[/tex] = initial volume of gas = 3.25 L
[tex]V_2[/tex] = final volume of gas = 4.35 L
[tex]T_1[/tex] = initial temperature of gas = [tex]54^oC=273+54=327K[/tex]
[tex]T_2[/tex] = final temperature of gas = ?
Now put all the given values in the above equation, we get:
[tex]\frac{231\times 3.25}{327}=\frac{168\times 4.35}{T_2}[/tex]
[tex]T_2=318K[/tex]
At 318 K of temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa
Which of the following statements is NOT true?
A. The corn that we grow today has not changed since prehistoric times.
B. Early humans planted seeds from corn plants with large kernels.
C. It took many generations for corn plants to change.
D. Humans have selectively bred many different types of crops.
Answer:
A. Corn has changed over time due to selective breeding.
Hope this helps :)
Where is the blood first filtered?
W
X
Y
Z
Answer:
in w
Explanation:
first blood enter renal artery which enter glomerous( where blood is filtrated) and then to Bowman carpusle(take the filtrated blood)
and then to proximal tubular(absorbed salt) and then to loop of hanle (y)(absorb water) and then to distal tubule then to ureter (z) and then to renal vein(x)(to go to urinary bladder)
For the reaction: 2 H3PO4 + 3 Ca(OH)2 → Ca3(PO4)2 + 6 H2O If you have 59.8 mL of 1.60 M phosphoric acid, how many mL of 0.500 M calcium hydroxide do you need to neutralize the acid?
Answer:
V = 127.57 mL
Explanation:
In this case, we are having an acid base titration, and this, according to the overall reaction:
2H₃PO₄ + 3Ca(OH)₂ -----> Ca₃(PO₄)₂ + 6H₂O
This reaction was neutralized, so, it's a neutralization reaction, therefore, we can use the following expression for neutralization reactions:
n₁ = n₂ (1)
This is because, in the equivalence point, both moles of the reagents are the same. Now we need to do a relation between this and the actual moles that we have according to the overall reaction.
In this case, we have 2 moles of acid reacting with 3 moles of base, so, the equation (1) is re-written like this:
2n₁ = 3n₂ (2)
Knowing this, and that we have values of concentrations and volume, we can write the expression of moles in terms of molarity and volume:
n = M * V replacing in (2):
2M₁V₁ = 3M₂V₂ From here, we can solve for V₂ which is the volume of the base:
V₂ = 2M₁V₁ / 3M₂ (3)
Now, all we have to do is replace the given values to obtain the volume of the base:
V₂ = 2 * 1.6 * 59.8 / 3 * 0.5
V₂ = 127.57 mLAnswer:
[tex]V_{Ca(OH)_2}=0.287L=287mL[/tex]
Explanation:
Hello,
In this case, given the reaction:
[tex]2 H_3PO_4 + 3 Ca(OH)_2 \rightarrow Ca_3(PO_4)_2 + 6 H_2O[/tex]
We first compute the moles of phosphoric acid that are actually reacting given the volume (must be in litres) and the molarity:
[tex]n_{H_3PO_4 }=1.60\frac{mol}{L}*59.8mL*\frac{1L}{1000mL} =0.0957molH_3PO_4[/tex]
Next, we compute the moles of calcium hydroxide that are reacting by using the 3:2 molar ratio with phosphoric acid:
[tex]n_{Ca(OH)_2}=0.0957molH_3PO_4*\frac{3molCa(OH)_2}{2molH_3PO_4} =0.144molCa(OH)_2[/tex]
Finally, by knowing the 0.500 M of the calcium hydroxide solution we compute the required volume:
[tex]V_{Ca(OH)_2}=\frac{n_{Ca(OH)_2}}{M_{Ca(OH)_2}}=\frac{0.144mol}{0.500\frac{mol}{L} } \\ \\V_{Ca(OH)_2}=0.287L=287mL[/tex]
Best regards.
Stabiliţi numerele de oxidare ale tuturor elementelor prezente în următoarele substanţe chimice, ţinând cont de principalele reguli de stabilire a NO: ⦁ NaNO3 ⦁ AlPO4 ⦁ CaCO3 ⦁ KMnO4 ⦁ K2Cr2O7 ⦁ HClO4 (acid percloric) ⦁ HClO3 (acid cloric) ⦁ HClO2 (acid cloros) ⦁ HClO (acid hipocloros)
Answer:
a.
N = +2
O = -2
b.
Na = +1
O = -2
N = +5
c.
O = -2
Al = +3
P = +5
d.
O = -2
Ca = +2
C = +4
e
O = -2
Mn = +7
K = +1
f.
O = -2
K = +1
Cr = +6
g.
O = -2
Cl = +7
Cr = +1
h.
O = -2
H = +1
Cr = +5
i.
O = -2
H = +1
Cr = +3
k.
O = -2
H = +1
Cr = +1
Explanation:
A. NU
Numărul de oxidare a azotului = +2
Numărul de oxidare a oxigenului = -2
b. NaNO₃
Numărul de oxidare de Na = +1
Numărul de oxidare de O = -2
Numărul de oxidare de N = +5
c. AlPO₄
Numărul de oxidare de O = -2
Numărul de oxidare al Al = +3
Numărul de oxidare al P = +5
d. carbonat de calciu
Numărul de oxidare de O = -2
Numărul de oxidare de Ca = +2
Numărul de oxidare de C = +4
e. KMnO₄
Numărul de oxidare de O = -2
Numărul de oxidare al Mn = +7
Numărul de oxidare al lui K = +1
f. K₂Cr₂O₇
Numărul de oxidare de O = -2
Numărul de oxidare al lui K = +1
Numărul de oxidare al Cr = +6
g. HClO₄
Numărul de oxidare de O = -2
Numărul de oxidare al Cl = +7
Numărul de oxidare al Cr = +1
h. HClO₃
Numărul de oxidare de O = -2
Numărul de oxidare al lui H = +1
Numărul de oxidare al Cr = +5
i. HClO₂
Numărul de oxidare de O = -2
Numărul de oxidare al lui H = +1
Numărul de oxidare al Cr = +3
k. HClO
Numărul de oxidare de O = -2
Numărul de oxidare al lui H = +1
Numărul de oxidare al Cr = +1.
In a titration how much 0.50 M HCl is needed to neutralize 1 liter of a 0.75 M solution of NaOH?
1.5 L
2.25 L
1.0 L
0.75 L
Answer:
1.5 L
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
HCl + NaOH —> NaCl + H2O
From the balanced equation above, The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Step 2:
Data obtained from the question. This includes the following:
Molarity of acid (Ma) = 0.5M
Volume of acid (Va) =..?
Volume of base (Vb) = 1L
Molarity of base (Mb) = 0.75M
Step 3:
Determination of the volume of the acid needed for the reaction.
Using the formula:
MaVa/MbVb = nA/nB
The volume of the acid needed for the reaction can be obtained as follow:
0.5 x Va / 0.75 x 1 = 1
Cross multiply
0.5 x Va = 0.75 x 1
Divide both side by 0.5
Va = 0.75 /0.5
Va = 1.5 L
Therefore, the volume of the acid, HCl needed for the reaction is 1.5L
which term names a small icy object that orbits the sun?
Answer:
It a comet
Explanation:
that why they are also called dirty snowballs
Answer:
A comment
Explanation:
Because I took the test and that 100 and because comets are icy and sometimes lead tale of water droplets behind them
Several atmospheric gases contribute to global warming: carbon dioxide, methane, and nitrous oxide. Considering this, which choice would do the LEAST to directly reduce atmospheric carbon dioxide.
Answer:
A
help u and it's A
Explanation:
Could u please balance this equation
Explanation:
I don't know how to explain
How much percent of the earth is water?
Answer:70%
Explanation:
Answer:
71%
Explanation:
71% of the earth is covered by water and oceans hold about 96 percent of the water
How many grams of CO2 are produced from the burning of 1.0 mol of amyl alcohol, C5H11OH?
Answer:
220g of CO2
Explanation:
Step 1:
The balanced equation for the reaction.
2C5H11OH + 15O2 —> 10CO2 + 12H2O
Step 2:
Determination of the number of mole of CO2 produced by burning 1 mole of C5H11OH.
From the balanced equation above,
2 moles of C5H11OH produced 10 moles CO2.
Therefore, 1 mole of C5H11OH will produce = (1 x 10)/2 = 5 moles of CO2.
Therefore, 5 moles of CO2 is produced from the reaction.
Step 3:
Conversion of 5 moles of CO2 to grams.
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Number of mole of CO2 = 5 moles
Mass of CO2 =...?
Mass = mole x molar mass
Mass of CO2 = 5 x 44
Mass of CO2 = 220g.
Therefore, 220g of CO2 were obtained from the reaction.
Which word describes the amount of matter an object contains?
O altitude
Odensity
O mass
O pressure
Explain how atomic interactions determine a material to be transparent and opaque
Answer:
The materials are opaque or crystalline from a client to the orientation and type of union between their atoms, forming two types of structures.
These two structures can be crystalline or amorphous.
In the case of being crystalline, these unions do not allow light to pass through the medium of the object or body of said compound, making it totally refract and giving the appearance of OPAQUE.
On the other hand, in those compounds that we call amorphous, the atoms are located in a different way that makes light pass through them, without absorbing or identifying any light beam, so they look transparent.
Explanation:
Example: A glass cup has an amorphous structure, while a porcelain or porcelain plate has a crystalline structure.
How many moles of gold are Cleveland to 1.204×1024 atoms
Answer:
10
Explanation:
ye
Answer:
2
Explanation:
Given:
CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ/mol
How much energy is released when 59.7 grams of methane (CH4) reacts with oxygen?
The combustion of 59.7 grams of methane releases ____ kilojoules of energy
Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄ [tex]= \frac{59.7}{16} = 3.73125 \ moles[/tex]
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Answer:
The combustion will release -3,321 KJ/mol of energy
Explanation:
Ca(OH)2
Name this compound according to IUPAC nomenclature.
A) calcium hydroxide
B) calcum oxide hydride
C) calcium (II) hydroxide
D) calcium (II) oxide hydride
* I’ll give you BRAINLIST * ( have to get it right ) Joshua has learned that the human body is made up of many body systems that work together to function for life. Which of the following does NOT
provide an example of two human body systems working together?
Answer:
Kidney & lungs
heart & bladder
bladder & lungs
Explanation:
HOPE THIS HELPS
What Newton’s law is this a example of:
When a bullet is fired from a rifle through a small explosion. The rifle shooting the bullet is pushed backwards after the explosion.
Answer:
Newton's third law
Explanation:
every action has an equal and opposite reaction.
Picture of 2010 Todd Abronowitz Gas Laws problems, super fun if you’re in AP chem. Can you help a pre-AP struggling student out please?
Answer:
1. 0.422 atmospheres
2. 633281.25 Pascals
3. (a) Move up
(b) 868 mmHg
4. 868 mmHg
5. 775 mmHg
6. Partial pressure of He is 0.64 atm.
Partial pressure of oxygen is 1.29 atm.
Partial pressure of N is 2.57 atm.
7. 445.72 torr.
Explanation:
1. To convert 321 torr to atmospheres
1 atmosphere = 760 torr
∴ 1 torr = 1/760 atmospheres
Hence, 321 torr = 321 × 1/760 = 321/760 atmospheres = 0.422 atmospheres
2. To convert 6.25 atmospheres to Pascals, we have;
1 atmosphere = 101325 Pascals
∴ 6.25 atmospheres = 6.25 × 101325 Pascals = 633281.25 Pascals
3. (a) Here we have, given that the value of the pressure on the bottle = 830 mmHg, when the valve is opened, the mercury in the open-end arm will move up because the pressure of the gas inside the flask is more than the pressure on the other side of the open-end arm
(b) After the mercury stops moving the difference between the two columns will be the difference between the two pressures, that is 830 mmHg - 745 mmHg = 85 mmHg
4. From the diagram, it is seen that the differenc beteen the two columns is 123 mm, therefore, the pressure in the flask is 123 mmHg more than the external pressure, hence the pressure of the as in the flask = 745 mmHg + 123 mmHg = 868 mmHg
5. Here we have that the height of the mercury in the open-end is less than the height of the mercury on the arm closer to the flask, therefore, the pressure of the gas in the flask = 825 mmHg - 50 mmHg = 775 mmHg
6. Number of moles of He = 1 mole
Number of moles of oxygen, O = 2 mole
Number of moles of nitrogen, N = 4 mole
From Dalton's law of partial pressure we have that, the total pressure of a given mass of gas is equal to the partial pressure of the individual gases
[tex]That \ is \ \chi _i = \frac{n_i}{n_{total}} \ and \ P_i = \chi_i \cdot P_{total}[/tex]
Hence;
Total number of moles = 1 + 2 + 4 = 7 moles
Mole fraction of He = 1/7
Partial pressure of He = 1/7×4.5 = 0.64 atm.
Mole fraction of oxygen, O = 2/7
Partial pressure of oxygen= 2/7×4.5 = 1.29 atm.
Mole fraction of N = 4/7
Partial pressure of N = 4/7×4.5 = 2.57 atm.
7. From Boyle's law
P₁×V₁ = P₂×V₂
Hence;
P₂ = P₁×V₁/V₂
Where:
P₁ = Initial pressure = 2.57 atm
V₁ = Initial volume =1.57 liters
V₂ = New volume = 6.88 liters
P₂ = New pressure = 2.57×1.57/6.88 = 0.59 atm.
To convert 0.59 atm. to torr, we multiply by 760 thus;
0.59 atm. = 0.59 × 760 torr = 445.72 torr.
