Answer:
The volume is 200.7 cm^3
Step-by-step explanation:
The volume of a cylinder is:
Vol = pi•r^2•h
The radius and height were given, so fill them in.
V = pi • (4.4)^2 • 3.3
V = 200.710071
This is the answer you get if you use the pi key on the calculator.
Round to the nearest tenth.
V = 200.7
The volume is 200.7cm^3.
***(If your teacher/class/text/program says to use 3.14 for pi, the answer will come out as 200.6)
Given that a function, g, has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45 and that g(0) = -2 and g(-9) = 6, select the statement that could be true for g.
The statement that could be true for function g b) g(-13) = 20.
Since g has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45, it is possible that g(-13) = 20. The fact that g(0) = -2 and g(-9) = 6 does not provide enough information to determine the value of g at x = -13.
Statement (a) is not possible since g(7) is outside the domain of g. Statement (c) is not possible since g(0) was given as -2. Statement (d) is not possible since -11 is outside the range of g.
Correct Question :
Given that a function, g, has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45 and that g(0) = -2 and g(-9) = 6, select the statement that could be true for g.
a) g(7) = -1
b) g(-13) = 20
c) g(0) = 2
d) g(-4) = -11
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I will give brainliest and ratings if you get this correct
Answer:
the equilibrium output (Y) is (gA-b(10))Mo + 2520/25 = 1076 and the equilibrium interest rate (i) is -176.
Step-by-step explanation:
(a) Writing the IS-LM system in matrix form:
IS equation: Y = 1 - b(10) + gA
LM equation: Y = (Mo/k) - (/k)i
We can rewrite the equations in matrix form as:
| 1 - b(10) -gA | | Y | | 0 |
| 1/k /k | | i | = | Mo/k |
(b) Solving for Y and i by matrix inversion:
| Y | | (1/k) (gA-b(10))/k | | 0 |
| i | = | (1/k) (-1/k) | | Mo/k |
Multiplying the inverse matrix by the right-hand side:
| Y | | (1/k) (gA-b(10))/k | | 0 | | (gA-b(10))Mo/k |
| i | = | (1/k) (-1/k) | | Mo/k | = | -Mo/k |
Solving for Y and i:
Y = (gA-b(10))Mo + 2520
25
i = -176
Therefore, the equilibrium output (Y) is (gA-b(10))Mo + 2520/25 = 1076 and the equilibrium interest rate (i) is -176.
tan=11/60, cos=60/11, sin=
[tex]{\boxed{\sf tan\Theta=\dfrac{sin\Theta}{cos\Theta}}}[/tex]
[tex]\\ \sf\longmapsto \dfrac{11}{60}=\dfrac{sin\Theta}{\dfrac{60}{11}}[/tex]
[tex]\\ \sf\longmapsto sin\Theta=\dfrac{11}{60}\times \dfrac{60}{11}[/tex]
[tex]\\ \sf\longmapsto sin\Theta=\dfrac{121}{3600}[/tex]
State the coordinates of the point after the reflection across each axis.
1. (5,2)
2. (-6, 12)
3. (2,-7)
4. (-4,-2)
5. (0,-2)
Reflect across
the x-axis
Reflect across
the y-axis
Answer:
Step-by-step explanation:
Reflecting a point across the x-axis results in changing the sign of the y-coordinate, but keeping the x-coordinate the same. Reflecting a point across the y-axis results in changing the sign of the x-coordinate, but keeping the y-coordinate the same.
Reflecting (5,2) across the x-axis gives (5,-2), and reflecting it across the y-axis gives (-5,2).
Reflecting (-6,12) across the x-axis gives (-6,-12), and reflecting it across the y-axis gives (6,12).
Reflecting (2,-7) across the x-axis gives (2,7), and reflecting it across the y-axis gives (-2,-7).
Reflecting (-4,-2) across the x-axis gives (-4,2), and reflecting it across the y-axis gives (4,-2).
Reflecting (0,-2) across the x-axis gives (0,2), and reflecting it across the y-axis gives (0,-2).
HELPPPPPPPPPPpppppppppppppppppppppp
Answer:
2464
Step-by-step explanation:
Parallelogram Area Formula: A=bh
Length is the same as base or b.
H is height
B =88 H=28
A=88•28=2464 m^
Find the surface area of a square pyramid with side length 4 cm and slant height 3 cm.
Answer:
40 cm²
Step-by-step explanation:
The surface area of a square-based pyramid is made up of:
A square base.4 congruent triangular sides.The area of a square is the square of its side length.
Given the side length of the square base is 4 cm, the area of the base is:
[tex]\begin{aligned}\implies \sf Area\;of\;square\;base&=4^2\\&=4 \cdot 4\\&=16\;\sf cm^2\end{aligned}[/tex]
The area of a triangle is half the product of its base and height.
Given the base of the triangular side is 4 cm and its height is 3 cm, the area of one triangular side is:
[tex]\begin{aligned}\implies \sf Area\;of\;one\;triangular\;side&=\dfrac{1}{2}\cdot 4 \cdot 3\\&=2 \cdot 3\\&=6\;\sf cm^2\end{aligned}[/tex]
Therefore, the total surface area of the square pyramid is:
[tex]\begin{aligned}\implies \sf Total\;surface\;area&=\sf square\;base+ 4\; triangular\;sides\\&=\sf 16\;cm^2+4 \cdot 6\; cm^2\\&=\sf 16\; cm^2+24\;cm^2\\&=\sf 40\;\sf cm^2\end{aligned}[/tex]
A 40% off sale begins today at Wandas women’s warehouse what is the sale price of women’s wool coats normally priced at $250
Answer: $150
Step-by-step explanation:
250 x 0.60
=$150
What’s the integral of 1/2
Find the difference quotient f(x+h) -f(x)/h , where h does not equal 0, for the function below.
f(x)=-3x^2+6x-6
The difference quotient for the function f(x)=-3x²+6x-6 is -3h+6.
Now, let's move on to finding the difference quotient for the function f(x)=-3x²+6x-6. The difference quotient is a formula used to find the average rate of change of a function between two points.
The formula for the difference quotient is:
f(x+h) - f(x)
So, to find the difference quotient for the function f(x)=-3x²+6x-6, we first need to find f(x+h) and f(x):
f(x+h) = -3(x+h)² + 6(x+h) - 6
= -3(x² + 2xh + h²) + 6x + 6h - 6
= -3x² - 6xh - 3h² + 6x + 6h - 6
f(x) = -3x² + 6x - 6
Now we can plug these values into the difference quotient formula:
f(x+h) - f(x)
= [-3x² - 6xh - 3h² + 6x + 6h - 6] - [-3x² + 6x - 6]
= [-3x² - 6xh - 3h² + 6x + 6h - 6 + 3x² - 6x + 6] / h
= [-3h² + 6h] / h
= -3h + 6
This tells us the average rate of change of the function between x and x+h is -3h+6.
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1. Which of the following is equivalent to 6/10? 5/9 9/15 8/12 36/100
Which of the following functions has a diagonal asymptote?
O
○ y = x + = 1/3
x+1
x-8
O y=
O y=
(x+4)(x-1)
x(x-7)
1
y ====
O y=
x-5
y = x(x − 3)
x + 2
y= x+1/x-8 has a diagonal asymptote. Therefore, the correct option is option A among all the given options.
A line that, in analytical geometry, is an asymptote either a curve is one where, when either or both of the x and y coordinates go to infinity, the distance among the curve as well as the line approaches zero. An asymptote on a curve appears a line that is tangential with the curve at an angle at infinity in projection geometry and similar contexts. y= x+1/x-8 has a diagonal asymptote.
Therefore, the correct option is option A.
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To which linear equations is the coordinate a solution? Select two options. y = 2x + 13 y = –x – 2 y = 3x – 5 y = negative one-half x + 6 y = –2x – 2
The equation y = -x - 2 and y = 2x + 13 has the coordinate a solution (-5, 3).
From the given coordinate plane, the solution is (-5, 3).
A linear equation is in the form: y = mx + b
where y, x are variables, m is the rate of change and b is the y intercept.
When (x, y)=(-5, 3)
The linear equation y = -x - 2 satisfies this this equation because 3 = -(-5) -2
Also, the linear equation y = 2x + 13 satisfies this this equation because 3 = 2(-5) + 13
Therefore, the equation y = -x - 2 and y = 2x + 13 has the coordinate a solution (-5, 3).
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Helppp pleaseeeeeeee
The values of the matrices operations are [tex]4G + 2F = \left[\begin{array}{ccccc}34&-4&-42&-18&48\\-42&-8&16&30&8\\24&32&4&34&34&-12&-32&-12&-42&-20\end{array}\right][/tex] and [tex]4D - 3B= \left[\begin{array}{ccccc}31&6&34&-14&-57\\-19&-27&-18&18&27\\47&14&-1&-40&9&10&12&-19&-15&-58&-14&-23&10&-8&10\end{array}\right][/tex]
Evaluating the matrices operationsFrom the question, we have the following parameters that can be used in our computation:
[tex]G = \left[\begin{array}{ccccc}8&-5&-7&-1&10\\-6&-7&1&9&2\\4&6&3&7&5&-4&-3&0&-10&-9\end{array}\right][/tex]
Also, we have
[tex]F = \left[\begin{array}{ccccc}1&8&-2&-5&9\\-9&10&6&-3&0\\4&5&-4&3&7&2&-10&-6&-1&-8\end{array}\right][/tex]
Using the above as a guide, we have
[tex]4G + 2F = 4\left[\begin{array}{ccccc}8&-5&-7&-1&10\\-6&-7&1&9&2\\4&6&3&7&5&-4&-3&0&-10&-9\end{array}\right] + 2 \left[\begin{array}{ccccc}1&8&-2&-5&9\\-9&10&6&-3&0\\4&5&-4&3&7&2&-10&-6&-1&-8\end{array}\right][/tex]
Evaluate the sum
[tex]4G + 2F = \left[\begin{array}{ccccc}34&-4&-42&-18&48\\-42&-8&16&30&8\\24&32&4&34&34&-12&-32&-12&-42&-20\end{array}\right][/tex]
Next, we have
[tex]D = \left[\begin{array}{ccccc}7&-6&3&-8&-9\\2&-9&-6&6&9\\8&2&5&-10&-3&10&-3&-4&3&-7&1&-2&4&-5&-2\end{array}\right][/tex]
Also, we have
[tex]B = \left[\begin{array}{ccccc}-1&-10&-8&-6&7\\9&-3&-2&2&3\\-5&-2&7&0&-7&10&-8&1&9&10&6&5&2&-4&-9\end{array}\right][/tex]
The matrix expression is then represented as
[tex]4D - 3B= 4\left[\begin{array}{ccccc}7&-6&3&-8&-9\\2&-9&-6&6&9\\8&2&5&-10&-3&10&-3&-4&3&-7&1&-2&4&-5&-2\end{array}\right] - 3\left[\begin{array}{ccccc}-1&-10&-8&-6&7\\9&-3&-2&2&3\\-5&-2&7&0&-7&10&-8&1&9&10&6&5&2&-4&-9\end{array}\right][/tex]
Evaluate
[tex]4D - 3B= \left[\begin{array}{ccccc}31&6&34&-14&-57\\-19&-27&-18&18&27\\47&14&-1&-40&9&10&12&-19&-15&-58&-14&-23&10&-8&10\end{array}\right][/tex]
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PLS HELP NO TROLLING PLS
The probability that a randomly selected points falls within the red-shaded square is given as follows:
p = 9/16.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
The area of the red-shaded square is given as follows:
3² = 9 units².
The total area is given as follows:
4² = 16 units².
Hence the probability that a randomly selected points falls within the red-shaded square is given as follows:
p = 9/16.
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For each pair of functions f and g below, find f(g(x)) and g (f(x)).
Then, determine whether fand g are inverses of each other.
Simplify your answers as much as possible.
(Assume that your expressions are defined for all x in the domain of the composition.
You do not have to indicate the domain.)
(a) f(x) =
3
X
3
g(x)
f(g(x)) =
x
, x = 0
"
x 0
8 (f(x)) =
Of and g are inverses of each other
fand g are not inverses of each other
(b) √(x) = x + 4
g(x) = -x + 4
f(g(x)) = [
8((x)) =
Of and g are inverses of each other
fand g are not inverses of each other
The functions f and g are inverses of each other in the first pair but not in the second pair
Determining whether the functions fand g are inverses of each other.For the first pair, we have
f(x) = -3/x
g(x) = -3/x
So, we have
f(g(x)) = -3/(-3/x)
Evaluate
f(g(x)) = x
Similarly;
g(f(x)) = x
This means that
f(g(x)) = g(f(x)) = x
So, the functions f(x) and g(x) are inverses of each other
For the second pair, we have
f(x) = x + 4
g(x) = -x + 4
So, we have
f(g(x)) = -x + 4 + 4
f(g(x)) = -x + 8
This means that
The functions f(x) and g(x) are not inverses of each other
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please helppppppppppppppppppppppppppp
Answer: its the first one
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Volume = 27.2
⅓ × base area × height = 27. 2
Base area × height = 81.6
Base area = ½ bh = 1/2 × 3.2 × 8.5 = 13.6
13.6 × height = 81.6
Height = 81.6 ÷ 13.6 = 6 inches
Which number is closest to 158 square root?
A:12.5
B:15.4
C: 13.55
D: 17.6
Answer: A
Step-by-step explanation:
Well when we use a calculator to determine the square root of 158 we get= 12.56980509.
And so option A woud be closest, smallest difference between all.
Answer: A
Step-by-step explanation: Square root of 158 simplified is 12.5698
25. Which statement about the following set
is true?
{60, 5, 18, 20, 37, 37, 11, 90, 72}
A) The median and the mean are equal.
B) The mean is less than the mode.
C) The mode is greater than the median.
D) The median is less than the mean.
E) The mode and the mean are equal.
The correct statement is,
D) The median is less than the mean.
E) The mode and the mean are equal.
Given that;
Data set is,
⇒ {60, 5, 18, 20, 37, 37, 11, 90, 72}
Hence, We can formulate;
Mean = {60 + 5 + 18 + 20 + 37 + 37 + 11 + 90 + 72} / 9
Mean = 38.89
Arrange data set into ascending order,
⇒ 5, 11, 18, 20, 37, 37, 60, 72, 90
Hence,
Median = (9 + 1)/2
= 5th term
= 37
Mode = 37
Thus, The correct statement is,
D) The median is less than the mean.
E) The mode and the mean are equal.
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PLEASE ANSWER ASAP!!!!
Answer:
1. true
2. false
3. true or false
Which of the following keywords best describe the OF SERVICE
a. None of the above
b. Categorical qualitative, discrete
c. quantitative, ordinal, discrete
D. both I and 2
e. numeric, quantitative, continous
The keyword that best describes the OF SERVICE is a. None of the above
What Is a keyword?A keyword is a term in information retrieval that captures the essence of a document's topic. Index terms make form a regulated vocabulary for usage in bibliographic data.
None of the preceding keywords correctly describe the term "of service" as it is a preposition used to denote the sort or character of a particular service being delivered. It does not refer to any statistical or mathematical concept.
The right answer is A based on the information.. It is not a statistical or mathematical term.
Based on the information, the correct option is A.
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what is the slope of the line that contains the points (-2,-20) and (3,30)?
The slope of the line that contains the points (-2,-20) and (3,30) is 10
The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.
The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is
m=y₂-y₁/x₂-x₁
We have to find the slope of the line that contains the points (-2,-20) and (3,30)
Slope= 30-(-20)/3-(-2)
=30+20/3+2
=50/5
=10
Hence, the slope of the line that contains the points (-2,-20) and (3,30) is 10
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Sasha Rudy and Mario each have 1 3/4 cups of flour. Can they make a recipe for bread that needs 5 cups of flour?
Answer:
Yes
Step-by-step explanation:
1 3/4 x 3 = 7/4 x 3 = 21/4 = 5 1/4 cups
Doug needs to order 5,000 g of vitamins at the store the vitamins come in 1 k packages that cost $ 80 each. How many bags must Doug buy
We start with the given, 10 g and we want to change grams to number of tablets. First, we convert 10 g to mg and then convert mg to tablets. We need a conversion factor for each step.
10* 1000/ 500
The answer will be 20 tablets.
Human drug dosages can be determined using weight (e.g., mg/kg) or surface area (e.g., mg/m2) based on weight when compared to doses used in animal studies. 2/3.
The most frequent substances for which doses are assessed are chemicals, although there are others, such radiation exposure. The majority of micronutrient and pharmaceutical doses for people are expressed in milligrams (mg), while some are expressed in micrograms due to their strength.
Non-medicinal poisons range in potency; some are so lethal that just one microgram of them is required to cause death, while others require much more. For instance, when consumed in sufficient amounts, even water becomes hazardous.
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complete question:
vitamin c tablets can come in 500 mg tablets. how many of these tablets are needed to obtain 10 g of vitamin c?
What are the x-intercepts of the quadratic function shown?
Answer:
if you are asking for an angle it's either 180° or 0°
Answer:
your answer is D. 1,0 & -3,0
Step-by-step explanation:
have a nice day.
There are 3 red jelly beans, 5 blue jelly beans, 2 orange jelly beans, and and 5 yellow jelly beans in a bag. Another bag has 1 pink jelly bean, 7 purple jelly beans, and 2 green jelly beans. What is the probability of randomly selecting a blue jelly bean from the first bag and then randomly selecting a green jelly bean from the second bag?
1/15
3/10
7/25
1/4
The probability of randomly selecting a blue jelly bean from the first bag and then randomly selecting a green jelly bean from the second bag is 1/15 (option a).
Firstly, we need to determine the total number of jelly beans in both bags.
The first bag contains 15 jelly beans (3+5+2+5) and the second bag contains 10 jelly beans (1+7+2).
Therefore, the total number of jelly beans in both bags is 25.
Next, we need to determine the probability of randomly selecting a blue jelly bean from the first bag.
Since there are 5 blue jelly beans out of a total of 15 jelly beans in the first bag, the probability of selecting a blue jelly bean is 5/15 or 1/3.
After selecting a blue jelly bean from the first bag, we move on to the second bag to select a green jelly bean.
Since there are 2 green jelly beans out of a total of 10 jelly beans in the second bag, the probability of selecting a green jelly bean is 2/10 or 1/5.
To determine the probability of both events occurring, we use the multiplication rule of probability.
Therefore, the probability of randomly selecting a blue jelly bean from the first bag and then randomly selecting a green jelly bean from the second bag is (1/3) x (1/5) = 1/15.
Hence, the answer is option (a) 1/15.
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PLEASEEEEEEEEEEEEEEEE
HELPPPPPPPPPPPPP ITS A BIG GRADEEEE
Alyssa's test scores are listed below
74, 86, 94, 82
Part A: Calculate the mean AND median of the given data. Show all your work. (1 points)
Part B: Alyssa just finished taking a fifth test. What score must she earn on her fifth test in order to have at least an 85% test average. Show all your work. (2 points)
Part C: How was the median affected by the addition of the fifth test score? (1 point)
The mean and median of the given data is 84 and 84, in order to have 85% as average, Alyssa should score 89 marks and we cannot say anything about how the median is affected.
Part A: Finding the mean of the data,
Mean = (74 + 86 + 94 + 82) / 4 = 336 / 4 = 84
Therefore, the mean score is 84. To find the median, we first need to put the scores in order from smallest to largest, 74, 82, 86, 94. Since we have an even number of scores, the median is the average of the two middle scores. In this case, the two middle scores are 82 and 86, so we take their average,
Median = (82 + 86) / 2 = 168 / 2 = 84
Therefore, the median score is 84.
Part B: Let x be the score Alyssa needs to earn on her fifth test. To find the score she needs to maintain an 85% average, we can set up the following equation,
(74 + 86 + 94 + 82 + x) / 5 = 85
Multiplying both sides by 5, we get,
74 + 86 + 94 + 82 + x = 425
Adding up the first four scores, we get,
74 + 86 + 94 + 82 = 336
Substituting in equation,
336 + x = 425
Subtracting 336 from both sides, we get,
x = 89
Therefore, Alyssa needs to earn at least an 89 on her fifth test to maintain an 85% average.
Part C: The median is the middle score when the data is arranged in order. Since the fifth test score has not yet been added, the median is still 84. So, we cannot really say anything about the median.
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HELPPPP PLEASEEEE When writing a proof, how do you construct the first statement?
A) By writing the justification for the first statement in the right column.
B) By copying the “prove” statement(s) from the original problem.
C) By writing the next logical statement from the current one.
D) By copying the “given” statement(s) from the original problem.
Answer:
By copying the given statements from the original problem
No. D
I hope it helped you.
Please Mark me the brainliest
Answer:
Hey, when writing a proof, the first statement should be based on the given information or assumptions, and it should be written in the left column of the proof. To get started, it's best to look at the "given" statements from the original problem and use those as your starting point. This first statement sets the foundation for the logical progression of the proof.
It's important to remember that each subsequent statement should be logically connected to the previous ones, and should lead towards the final statement or conclusion that you're trying to prove. To make your proof convincing, you should also include a justification for each statement that you make, which goes in the right column of the proof.
Overall, constructing a proof can take some time and effort, but by following a clear and logical progression, you can create a solid and convincing argument for your claim.
Step-by-step explanation:
Solve for the missing side length. Round to the nearest tenth.
5.8
5.2
5.4
5.6
Answer:
C) 5.4-------------------------
Given two legs of a right triangle and we need to find the hypotenuse.
Use Pythagorean theorem:
[tex]PQ = \sqrt{QR^2+PR^2}[/tex][tex]PQ = \sqrt{2^2+5^2} =\sqrt{29} =5.385 = 5.4\ (rounded)[/tex]The matching choice is C.
Solve by completing the square.
j² + 14j + 5 = 0
Write your answers as integers, proper or improper fractions in simplest form, or decimals
rounded to the nearest hundredth.
Submit
or j =
=
Answer:
[tex]j = 7 \pm \sqrt{44}[/tex]
Step-by-step explanation:
First, move the constant term to the other side of the equation.
[tex]j\² + 14j + 5 = 0[/tex]
[tex]j\² + 14j = -5[/tex]
Next, add the coefficient of the first degree j term divided by 2, then squared to both sides.
[tex]j^2 + 14j + (14/2)^2 = -5 + (14/2)^2[/tex]
[tex]j^2 + 14j + (7)^2 = -5 + (7)^2[/tex]
[tex]j^2 + 14j + 49 = -5 + 49[/tex]
[tex]j^2 + 14j + 49 = 44[/tex]
Now, we can factor the left side as a square.
[tex](j+7)(j+7) = 44[/tex]
[tex](j+7)^2 = 44[/tex]
Finally, we can take the square root of both sides to solve for j.
[tex]\sqrt{(j+7)^2} = \sqrt{44[/tex]
[tex]j+7=\pm\sqrt{44}[/tex]
[tex]\boxed{j = 7 \pm \sqrt{44}}[/tex]
Note that there are two solutions, as [tex]\sqrt{44[/tex] could be positive OR negative because of the even root property:
if [tex]x^2 = a^2[/tex],
then [tex]x = \pm a[/tex]
because both [tex](+a)^2[/tex] and [tex](-a)^2[/tex] equal [tex]a^2[/tex].
can some please help with 11 !!!!
