Calculate the first eight terms of the sequence of partial sums correct to four decimal places. sin(n) n = 1 n So 1 N 3 4 5 ILOILO 6 7 00 Does it appear that the series is convergent or divergent? convergent O divergent
we have the first eight terms, let's analyze the sequence. There doesn't appear to be a clear pattern or convergence towards a single value. The values are fluctuating, suggesting that the series may be divergent.
To find the first eight terms of the sequence of partial sums for the series sin(n), we will calculate the sum of the series for each term up to n=8, and then determine whether the series appears to be convergent or divergent.
1. sin(1)
2. sin(1) + sin(2)
3. sin(1) + sin(2) + sin(3)
4. sin(1) + sin(2) + sin(3) + sin(4)
5. sin(1) + sin(2) + sin(3) + sin(4) + sin(5)
6. sin(1) + sin(2) + sin(3) + sin(4) + sin(5) + sin(6)
7. sin(1) + sin(2) + sin(3) + sin(4) + sin(5) + sin(6) + sin(7)
8. sin(1) + sin(2) + sin(3) + sin(4) + sin(5) + sin(6) + sin(7) + sin(8)
Now, let's calculate these sums up to four decimal places:
1. 0.8415
2. 0.8415 + 0.9093 = 1.7508
3. 1.7508 + 0.1411 = 1.8919
4. 1.8919 - 0.7568 = 1.1351
5. 1.1351 - 0.9589 = 0.1762
6. 0.1762 - 0.2794 = -0.1032
7. -0.1032 + 0.6569 = 0.5537
8. 0.5537 + 0.9894 = 1.5431
Now that we have the first eight terms, let's analyze the sequence. There doesn't appear to be a clear pattern or convergence towards a single value. The values are fluctuating, suggesting that the series may be divergent.
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Write and expression for the calculation add 8 to the sum of 23 and 10
The expression for the calculation of adding 8 to the sum of 23 and 10 is 8 + (23 + 10)
How to find the expression?
To calculate expression parentheses the sum of 23 and 10, we add them together, which gives us 33. Then, we add 8 to that result, giving us a final answer of 41. So, the expression 8 + (23 + 10) equals 41.
This expression follows the order of operations, which states that we should first perform the addition inside the parentheses and then add the result to 8.
expressions are made up of numbers and symbols, and they represent a mathematical relationship or operation. In this case, the expression includes addition and parentheses, which tell us to perform the addition inside them first. The parentheses clarify which numbers should be added together first before adding 8.
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work out minimum and maximum number of hikers who could have walked between 7 miles and 18 miles
(a) The minimum number of hikers who could have walked between 7 miles and 18 miles: at least 5 hikers and at most 13 hikers.
(b) The maximum number of hikers who could have walked between 7 miles and 18 miles: at most 15 hikers.
According to the question and given conditions, we need to find the cumulative frequency of the distance intervals that fall within the range of 7 miles and 18 miles, to find the minimum number of hikers and the maximum number of hikers who could have walked between 7 miles and 18 miles.
The sum of the frequencies up to a certain point in the data is the cumulative frequency. By adding the frequency of the current interval to the frequency of the previous interval, we can calculate the cumulative frequency.
a) To find the minimum number of hikers who could have walked between 7 miles and 18 miles, we will find the cumulative frequency of the intervals from 5 miles to 10 miles and then from 10 miles to 15 miles.
Cumulative frequency for 5 < x <= 10: 2 + 3 = 5
Cumulative frequency for 10 < x <= 15: 5 + 8 = 13
Therefore, we find that at least 5 hikers and at most 13 hikers could have walked between 7 miles and 18 miles.
b) To find the maximum number of hikers who could have walked between 7 miles and 18 miles, we will find the cumulative frequency of the intervals from 10 miles to 15 miles and from 15 miles to 20 miles.
Cumulative frequency for 10 < x <= 15: 8
Cumulative frequency for 15 < x <= 20: 8 + 7 = 15
Therefore, we can conclude that at most 15 hikers could have walked between 7 miles and 18 miles.
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The complete question is "a) work out the minimum number of hikers who could have walked between 7 miles and 18 miles b) work out the maximum number of hikers who could have walked between 7 miles and 18 miles."
A random sample of 100 stores from a large chain of 1,000 garden supply stores was selected to determine the average number of lawnmowers sold at an end-of-season clearance sale. The sample results indicated an average of 6 and a standard deviation of 2 lawnmowers sold. A 95% confidence interval (5. 623 to 6. 377) was established based on these results. True or False: Of all possible samples of 100 stores taken from the population of 1,000 stores, 95% of the confidence intervals developed will contain the true population mean within the interval
The statement is True.
The statement "95% confidence interval (5.623 to 6.377)" means that if we were to repeat this process of taking 100 samples from the population and constructing a confidence interval for each sample, then about 95% of those intervals would contain the true population mean.
This is the definition of a confidence interval at a certain level of confidence (in this case, 95%). Therefore, the statement is true.
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Question 1:
An athlete runs in a straight line along a flat surface. He starts from rest and for 20 seconds accelerate at a constant rate. In this first 20 seconds he covers a distance of 100m. For the next 10 seconds he runs at a constant speed and then decelerates at a constant rate for 5 seconds until he stops.
a) What is the total distance that he ran? Another athlete runs along the same track, starting from rest and she accelerates at the same rate as her friend. She however only accelerates for 10 seconds before running at a constant speed.
b) How long does it take her to run 100m?
a) The total distance that he ran is 10v + 187.5a.
b) The second athlete takes 10 seconds to run 100m.
a) To find the total distance that the athlete ran, we need to calculate the distance covered during each phase of the motion.
During the first 20 seconds, the athlete accelerated at a constant rate from rest. We can use the formula:
distance = (1/2) * acceleration * time²
where acceleration is the constant rate of acceleration and time is the duration of acceleration. Plugging in the values we get:
distance = (1/2) * a * (20)² = 200a
So, the distance covered during the first phase is 200a meters.
During the next 10 seconds, the athlete ran at a constant speed. The distance covered during this phase is:
distance = speed * time = 10s * v
where v is the constant speed of the athlete during this phase.
Finally, during the last 5 seconds, the athlete decelerated at a constant rate until coming to a stop. The distance covered during this phase can be calculated using the same formula as for the first phase:
distance = (1/2) * acceleration * time² = (1/2) * (-a) * (5)² = -12.5a
where the negative sign indicates that the athlete is moving in the opposite direction.
Adding up the distances covered during each phase, we get:
total distance = 200a + 10v + (-12.5a) = 10v + 187.5a
However, we can say that the athlete covered at least 100m during the first 20 seconds, so the total distance must be greater than or equal to 100m.
b) The second athlete runs along the same track and accelerates at the same rate as the first athlete. We know that the first athlete covered 100m during the first 20 seconds of motion. So, we can use the same formula as before to find the acceleration:
distance = (1/2) * acceleration * time²
100m = (1/2) * a * (10s)²
Solving for a, we get:
a = 2 m/s²
Now we can use another formula to find the time it takes for the second athlete to run 100m. Since the second athlete only accelerates for 10 seconds, we can use:
distance = (1/2) * acceleration * time² + initial velocity * time
where initial velocity is zero since the athlete starts from rest. Plugging in the values we get:
100m = (1/2) * 2 m/s² * (t)²
Solving for t, we get:
t = 10s
So, the second athlete takes 10 seconds to run 100m.
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Just-in-time (JIT) delivery: Increases physical distribution costs for business customers. Requires that a supplier be able to respond to the customer's production schedule. Usually does not require e-commerce order systems and computer networks. Means that deliveries are larger and less frequent. Shifts greater responsibility for physical distribution activities from the supplier to the business customer
Just-in-time (JIT) delivery is a supply chain management strategy that aims to improve efficiency and reduce inventory costs by having materials and goods delivered exactly when they are needed in the production process.
This approach requires suppliers to be able to respond to the customer's production schedule, ensuring timely deliveries to prevent disruptions. As a result, JIT delivery shifts greater responsibility for physical distribution activities from the supplier to the business customer, who needs to closely monitor inventory levels and maintain efficient communication with suppliers.
However, JIT delivery does not typically lead to larger, less frequent deliveries, nor does it inherently increase physical distribution costs. In fact, it may reduce costs by minimizing inventory storage expenses. Additionally, e-commerce order systems and computer networks are often utilized to facilitate the communication and coordination required for effective JIT delivery.
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For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 40 N acts on a certain object, the acceleration
of the object is 10 m/s². If the force is changed to 36 N, what will be the acceleration of the object?
Answer:
The answer to your problem is, F = 15N
Step-by-step explanation:
You have: F = ka
Where F is the force acting on the object, A is the object's acceleration and is the constant of proportionality.
Which will be our letters that we will NEED to use for today.
You can calculate the constant of proportionality by substituting F = 18 and a = 6 into the equation and solving for k: Then we can now figure out the “ formula of expression “
18 = k6
k = [tex]\frac{18}{6}[/tex]
K = 3
We would need to calculate the force when the acceleration of the object becomes 5 m/s², as following: F = 3 x 5 ( Basic math )
= F = 15
Thus the answer to your problem is, F = 15N
What is the missing step in solving the inequality 4(x – 3) 4 < 10 6x? 1. the distributive property: 4x – 12 4 < 10 6x 2. combine like terms: 4x – 8 < 10 6x 3. the addition property of inequality: 4x < 18 6x 4. the subtraction property of inequality: –2x < 18 5. the division property of inequality: ________ x < –9 x > –9 x < x is less than or equal to negative startfraction 1 over 9 endfraction. x > –x is greater than or equal to negative startfraction 1 over 9 endfraction.
The missing step in solving the inequality 4(x – 3) /4 < 10/6x is to divide both sides by 2.
Apply the distributive property to get 4x - 12 /4 < 10/6x.
Combine like terms to obtain 4x - 3 < 5/3x.
Add 3/3x to both sides to get 4x < 8/3x + 3.
Subtract 8/3x from both sides to get 4/3x < 3.
Divide both sides by 4/3 to get x < -9/4.
Simplify the result by dividing both sides by 2 to get x < -9/2 or x > -4/3.
Therefore, the missing step is to divide both sides by 2, which gives x < -9/2 or x > -4/3.
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help me with pythagorean therom pleaseeeeeeeeeeeee i will legit do anything if someone can help i will give brainliest just help me pleaseeeeeeeeeeee
6.6,your answer is correct.
As the theorem is a^2+b^2=c^2 you first must assign the proper components to each variable. Since 12 is the longest since it is the hypotenuse that means it is c so in this case 144. And since 10 is the leg it is a.
To solve you must take
10^2+b^2=12^2
100+b=144
144-100=44
Since b^2 is 44 you must find the square root [tex]\sqrt{44}[/tex]=6.6
The circumference of a wheel is 320.28 centimeters.
a) Determine the radius of the wheel.
b) Determine the area of the wheel.
Answer:
radius is 50.95
area is 8158.55
Step-by-step explanation:
cirumference = 2pi×r
or,320.28=2×(22/7)×r
or, r=320.28/(2×(22/7))
r=50.95 cm
area=(22/7)r^2
=8158.55
Scientists estimate that the mass of the sun is 1. 9891 x 10 kg. How many zeros are in this
number when it is written in standard notation?
A 26
B 30
C 35
D 25
There are 26 zeros in this number when it is written in standard notation. The correct answer is option (A). The mass of the sun is estimated to be 1.9891 x 10³⁰kg. To determine the number of zeros in this number when written in standard notation, we need to first convert it to standard form.
In standard form, the number is expressed as a decimal between 1 and 10 multiplied by a power of 10. To convert the given number to standard form, we move the decimal point 30 places to the right because the exponent is positive 30. This gives us 1989100000000000000000000000000. As we can see, there are 27 digits in this number. Therefore, there are 27-1=26 zeros in this number when it is written in standard notation.
In conclusion, the answer is A, 26. This type of question is commonly asked in science and engineering, where large or small numbers are expressed in scientific notation for convenience. Understanding how to convert between scientific notation and standard form is important for anyone studying or working in these fields.
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The monthly demand function for product sold by monopoly is p 2,220 1x2 dollars, and the average cost is C = 900 + 14x + x2 dollars. Production is limited to 1,000 units, and x is in hundreds of units_ Find the revenue function, R(x)_ R(x) Find the cost function, C(x): C(x) Find the profit function, P(x) P(x) (a) Find P'(x) . P'(x) Considering the limitations of production, find the quantity (in hundreds of units) that will give the maximum profit. hundred units (b) Find the maximum profit
To find the revenue function, we need to multiply the price (p) by the quantity (x):
R(x) = xp = (2220 - x^2) x
Expanding this expression, we get:
R(x) = 2220x - x^3
To find the cost function, we can simply use the given formula:
C(x) = 900 + 14x + x^2
To find the profit function, we subtract the cost from the revenue:
P(x) = R(x) - C(x)
= (2220x - x^3) - (900 + 14x + x^2)
= -x^3 + 2206x - 900
To find P'(x), the derivative of P(x) with respect to x, we take the derivative of the expression for P(x):
P'(x) = -3x^2 + 2206
Setting P'(x) equal to zero and solving for x, we get:
-3x^2 + 2206 = 0
x^2 = 735.333...
x ≈ 27.104
We can't produce a fraction of a hundred units, so we round down to the nearest hundredth unit, giving x = 27.
To confirm that this value gives a maximum profit, we can check the sign of P''(x), the second derivative of P(x) with respect to x:
P''(x) = -6x
When x = 27, P''(x) is negative, which means that P(x) has a local maximum at x = 27.
Therefore, the quantity that will give the maximum profit is 2700 units (27 x 100).
To find the maximum profit, we evaluate P(x) at x = 27:
P(27) = -(27)^3 + 2206(27) - 900
= 53,955 dollars
Therefore, the maximum profit is $53,955.
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For the given cost and demand functions, find the production level that will maximize profit. (Round your answer to the nearest whole number.)C(q) = 660 + 5q + 0.03q^2, p = 10 − q/400
The production level that will maximize profit is 80 units
To find the production level that will maximize profit given the cost function C(q) = 660 + 5q + 0.03q^2 and demand function p = 10 - q/400, follow these steps:
1. Write down the revenue function: Revenue (R) is the product of price (p) and quantity (q). So, R(q) = p * q.
2. Substitute the demand function into the revenue function: R(q) = (10 - q/400) * q
3. Simplify the revenue function: R(q) = 10q - q^2/400
4. Write down the profit function: Profit (P) is the difference between revenue and cost. So, P(q) = R(q) - C(q).
5. Substitute the revenue and cost functions into the profit function: P(q) = (10q - q^2/400) - (660 + 5q + 0.03q^2)
6. Simplify the profit function: P(q) = 10q - q^2/400 - 660 - 5q - 0.03q^2
7. Combine like terms: P(q) = 5q - q^2/400 - 0.03q^2 - 660
8. Differentiate the profit function with respect to q to find the first derivative: P'(q) = 5 - q/200 - 0.06q
9. Set the first derivative equal to 0 and solve for q: 5 - q/200 - 0.06q = 0
10. Solve for q: q ≈ 80
The production level that will maximize profit is approximately 80 units (rounded to the nearest whole number).
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A toy manufacture has designed a new part for use in building models. The part is a cube with side length 14 mm and it has a 12 mm diameter circular hole cut through the middle. The manufacture wants 9,000 prototypes. If the plastic used to create the part costs $0. 07 per cubic millimeter, how much will the plastic for the prototypes cost?
Answer: Therefore, the plastic for the prototypes will cost $1,452,150.
Step-by-step explanation:
The volume of the cube can be calculated as:
Volume of the cube = (side length)^3 = (14 mm)^3 = 2,744 mm^3
The volume of the hole can be calculated as:
Volume of the hole = (1/4) x π x (diameter)^2 x thickness = (1/4) x π x (12 mm)^2 x 14 mm = 5,049 mm^3
The volume of plastic used to create one prototype can be calculated as:
Volume of plastic = Volume of cube - Volume of hole = 2,744 mm^3 - 5,049 mm^3 = -2,305 mm^3
Note that the result is negative because the hole takes up more space than the cube.
However, we can still use the absolute value of this result to calculate the cost of the plastic:
Cost of plastic per prototype = |Volume of plastic| x Cost per cubic millimeter = 2,305 mm^3 x $0.07/mm^3 = $161.35/prototype
To find the cost of the plastic for 9,000 prototypes, we can multiply the cost per prototype by the number of prototypes:
Cost of plastic for 9,000 prototypes = 9,000 x $161.35/prototype = $1,452,150
The plastic for the prototypes will cost $1,452,150.
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The area of triangle ABC is 4 root 2. Work out the value of x
Question is from mathswatch
Use the image below to find x: Show your steps and identify the TRIG RATIO that you used to find x.
The measure of the angle x in the circle is 65 degrees
Solving for x in the circleFrom the question, we have the following parameters that can be used in our computation:
The circle
On the circle, we have the angle at the vertex of the triangle to be
Angle = 100/2
Angle = 50
The sum of angles in a triangle is 180
So, we have
x + x + 50 = 180
Evaluate the like terms,
2x = 130
So, we have
x = 65
Hence, the angle is 65 degrees
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A cuboid has a square base of side (2 + √3)m. the area of one side is (2√3 - 3)m². find the height of the cuboid in the form (a+ b√3)m, where a and b are integers.
The height of the cuboid, after calculations, in the form (a+ b√3)m, is (6√3 - 9)/47 meters.
Let the height of the cuboid be h meters. The area of the square base is given by:
(2 + √3)² = 4 + 4√3 + 3 = 7 + 4√3 m²
The total surface area of the cuboid is the sum of the areas of the six rectangular faces. Since the base is a square, the area of each of the four vertical rectangular faces is also (2 + √3) × h = (2h + h√3) m². Therefore, we have:
Total surface area = 4(7 + 4√3) + 2(2h + h√3)(2 + √3) = 8h + 26 + (22 + 16√3)h
Since we know that one of the sides has area (2√3 - 3) m², we can set up another equation:
(2h + h√3)(2 + √3) = 2√3 - 3
Expanding the left side and simplifying, we get:
(2h + h√3)(2 + √3) = 2√3 - 3
4h + 7h√3 = 2√3 - 3
h(4 + 7√3) = 2√3 - 3
h = (2√3 - 3)/(4 + 7√3)
We can rationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator:
h = [(2√3 - 3)/(4 + 7√3)] × [(4 - 7√3)/(4 - 7√3)]
h = (8√3 - 12 - 14√3 + 21)/(16 - 63)
h = (9 - 6√3)/(-47)
h = (6√3 - 9)/(47)
Therefore, the height of the cuboid is (6√3 - 9)/47 meters.
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CD is a perpendicular bisector of chord AB and a chord through CD passes through the center of a circle. Find the diameter of the wheel.
The figure shows a circle. Points A, C, B, E lie on the circle. Chords A B and C E intersect at point D. The length of segment A B is 12 inches. The length of segment C D is 4 inches.
715 in.
10 in.
1425 in.
1215 in.
Need Help ASAP please!!!
We know that the diameter of the wheel is 1215 inches
Since CD is a perpendicular bisector of AB, it means that CD passes through the center of the circle. Let O be the center of the circle. Then OD is the radius of the circle.
Since chord CE passes through the center O, it is a diameter of the circle. Therefore, CE = 2OD.
Let's use the intersecting chords theorem to find OD.
According to the intersecting chords theorem,
AC * CB = EC * CD
We know that AC = CB (since they are radii of the same circle) and CD = 4 inches. We also know that AB = 12 inches. Let's call the length of segment AE x. Then the length of segment EB is 12 - x.
So we have:
x * (12 - x) = EC * 4
Simplifying:
12x - x^2 = 4EC
Rearranging:
EC = 3x - x^2/4
Now let's use the intersecting chords theorem again, but this time for chords AB and CD:
AC * CB = AD * DB
We know that AC = CB and AB = 12 inches. Let's call the length of segment AD y. Then the length of segment DB is 12 - y.
So we have:
x^2 = y * (12 - y)
Simplifying:
y^2 - 12y + x^2 = 0
Using the quadratic formula:
y = (12 ± sqrt(144 - 4x^2))/2
We can discard the negative solution (since y is the length of a segment, it cannot be negative), so:
y = 6 + sqrt(36 - x^2)
Now let's use the fact that CD is a perpendicular bisector of AB to find x.
Since CD is a perpendicular bisector of AB, it divides AB into two segments of equal length. Therefore,
AD = DB = 6
Using the Pythagorean theorem in triangle ACD:
AC^2 + CD^2 = AD^2
Substituting the values we know:
x^2 + 4^2 = 6^2
Solving for x:
x = sqrt(20)
Now we can find EC:
EC = 3x - x^2/4
Substituting x:
EC = 3sqrt(20) - 5
Finally, we can find OD:
AC * CB = EC * CD
Substituting the values we know:
(2OD)^2 = (3sqrt(20) - 5) * 4
Simplifying:
OD^2 = 12sqrt(20) - 20
OD = sqrt(12sqrt(20) - 20)
We are asked to find the diameter of the circle, which is twice the radius:
Diameter = 2OD = 2sqrt(12sqrt(20) - 20)
This is approximately equal to 1215 inches.
So the answer is:
The diameter of the wheel is 1215 inches.
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Question 6 of 20 :
Select the best answer for ige question. 6. Simplify (4x 4)-3. O B. 2
O C. -8x12
0D. -64x9
The correct answer is (C) -8x12.
To simplify (4x^4)^-3, we use the power of a power rule which states that (a^m)^n = a^(mn), where a is a non-negative number and m and n are integers. Applying this rule, we get:
(4x^4)^-3 = 4^(-3) x^(4 x -3) = (1/64)x^(-12) = -8x^12 (using the negative exponent rule, which states that a^(-n) = 1/a^n)
Therefore, the simplified form of (4x^4)^-3 is -8x^12.
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I need help on this question please help.
The density of the wooden cube is 0.638 g/cm³. The type of wood the cube is made of is ash.
How to find the density of object?The wooden cube has a edge length of 6 centimetres and a mass of 137.8 grams.
The density of the wood can be calculated as follows:
density = mass / volume
volume of the wood = l³
where
l = lengthTherefore,
volume of the wood = 6³
volume of the wood = 216 cm³
density of the wood = 137.8 / 216
density of the wood = 0.63796296296
density of the wood = 0.638 g/cm³
Therefore, the cube wood is made of ash.
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Find dy/dt given that x^2+y^2 = 2x+4y, x = 3, y = 1 and dx/dt = 7
To find dy/dt, we need to use implicit differentiation.
First, we differentiate both sides of the equation with respect to t:
2x(dx/dt) + 2y(dy/dt) = 2(dx/dt) + 4(dy/dt)
Next, we plug in the given values for x, y, and dx/dt:
2(3)(7) + 2(1)(dy/dt) = 2(7) + 4(dy/dt)
Simplifying, we get:
42 + 2(dy/dt) = 14 + 4(dy/dt)
Subtracting 2(dy/dt) and 14 from both sides:
28 = 2(dy/dt)
Finally, we divide both sides by 2 to solve for dy/dt:
dy/dt = 14
To find dy/dt, first differentiate the given equation x^2+y^2=2x+4y with respect to time t. Use the chain rule:
2x(dx/dt) + 2y(dy/dt) = 2(dx/dt) + 4(dy/dt).
Now substitute the given values, x = 3, y = 1, and dx/dt = 7:
2(3)(7) + 2(1)(dy/dt) = 2(7) + 4(dy/dt).
Solve for dy/dt:
42 + 2(dy/dt) = 14 + 4(dy/dt).
Rearrange and solve:
2(dy/dt) - 4(dy/dt) = 14 - 42,
-2(dy/dt) = -28.
Finally, divide by -2:
dy/dt = 14.
So the value of dy/dt is 14 when x = 3, y = 1, and dx/dt = 7.
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Jayla buys and sells vintage clothing. She bought two blouses for $25. 00 each and later sold them for $38. 00 each. She bought three skirts for
$15. 00 each and later sold them for $26. 00 each. She bought five pairs of pants for $30,00 each and later sold them for $65. 00 each
Answer:well i don't know what you're asking for but i got this
Blouses, she earned $26
Skirts, she earned $33
Pants, she earned $175
So basically she s c a m m i n g but she still got that bank she made though
Step-by-step explanation:
25x2=50; 38x2=76; 76-50=26
15x3=45; 26x3=78; 78-45=33
30x5=150; 65x5=325; 325-150=175
What is the area of a circle with a diameter of 80m? (hint : you have to find the radius first)
Answer:
A = 5026.548246 m²
Step-by-step explanation:
Equation for Area of a Circle: A = πr² where r is the radius.
The radius of a circle is always half the diameter. Since we know the diameter is 80m, we can divide by 2 to find our radius.
80/2 = 40m
Now that we have found our radius, we can plug the value into r and solve.
A = π(40)² = 5026.548246 m²
Solve the inequality -1/2x greater than or equal to 17. Graph the solution
To solve the inequality -1/2x ≥ 17, we can start by isolating x on one side of the inequality.
Multiplying both sides by -2 (and reversing the direction of the inequality since we are multiplying by a negative number), we get:
x ≤ -34
So the solution to the inequality is x ≤ -34.
To graph the solution, we can draw a number line and mark -34 on it. Then we shade all the values of x that are less than or equal to -34. This can be represented by a closed circle at -34 and a shaded line to the left of -34, indicating that any value of x in that range satisfies the inequality.
Here is a graph of the solution:
```
<=====(●)-----------------------
-34
```
The shaded part of the line represents the values of x that satisfy the inequality -1/2x ≥ 17, and the closed circle at -34 indicates that x can be equal to -34 (since the inequality is "greater than or equal to").
I used the foil method to expand this but I don’t know what to do after that… a little help?
The expansion of (1+root 2)(3-root 2) is 1 +2√2.
What is distributive property?
The distributive Property states that it is necessary to multiply each of the two numbers by the factor before performing the addition operation when a factor is multiplied by the sum or addition of two terms.
Apply the distributive property
1(3-√2) + √2(3-√2)
Apply distributive property
1.4+ 1(-√2) +√2 (3-√2)
Apply the distributive property
1.3 + 1(-√2) + √2. 3+√2 (-√2)
3+1(−√2)+√2⋅3+ √2(-√2)
Multiply − √2 by 1
3−√2+ √2⋅3+√2(−√2)
Move 3 to the left of √2.3−√2+3⋅√2+√2(−√2)
Multiply √2(−√2)
3−√2+3√2−√2²
Rewrite
√2² as 2.
3−√2+3√2− 1⋅2
Multiply − 1 by 2.
3−√2+3√2−2
Subtract 2 from 3.
1−√2+3√2
Add −√2 and 3√2.
1+2√2
Exact Form:
1 +2√2
Decimal Form:
3.82842712
Therefore, the expansion of (1+root 2)(3-root 2) is 1 +2√2.
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what is scientific notation
Use the indicated table of integrals to evaluate this:
∫√(x-x^2)dx
After evaluating the integral ∫√(x-x²)dx, we get:
∫√u (1 - 2x) du, with the limits of integration 0 to 1/4
To evaluate the integral ∫√(x-x²)dx using the indicated table of integrals, you should look for an entry in the table that matches the given integral's form. Unfortunately, I do not have access to the specific table you are referring to. However, I can guide you on how to approach this problem.
First, you should make a substitution:
let u = x - x², then du = (1 - 2x)dx. To proceed with this substitution, you'll need to rewrite the integral in terms of 'u' and 'du'. Notice that when x = 1/2, u = 1/4.
Therefore, you can change the limits of integration as well: x = 0 corresponds to u = 0, and x = 1 corresponds to u = 0.
Now,
∫√(x-x²)dx = (1/2) ∫(1-4x+4x²-3)⁽¹/²⁾ dx
Now, we can look up the integral in the table of integrals, which indicates that:
∫(1-4x+4x²-3)⁽¹/²⁾ dx = (1/2) [ (x-1)√(1-4x+4x²) + 2arcsin(2x-1) ] + C
Therefore, substituting this result back into the original integral, we get:
∫√(x-x²)dx = (1/2) [ (x-1)√(1-4x+4x²) + 2arcsin(2x-1) ] + C
where C is the constant of integration.
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Answer quickly please
Given that A is a constant, the general solution to the differential equation dy dt -5y is Select one O a. 3t2 2 Ob. 3= Ae-56 Ос. y = Aest Od y=est +A The solution to the exact differential equati
The general solution to the differential equation dy/dt - 5y = A is y = Ce^(5t) + A/5, where C is a constant of integration. The general solution is y = (A/5) + Ce^(5t). so, the correct answer is D).
The general solution to the differential equation dy/dt - 5y = A, where A is a constant, is
y = Ce^(5t) + A/5
where C is an arbitrary constant determined by any initial or boundary conditions given.
The general solution is a combination of the homogeneous solution y_h = Ce^(5t) (which satisfies the differential equation without the constant term A) and the particular solution y_p = A/5 (which satisfies the differential equation with A but without any initial or boundary conditions).
so, the correct option is D).
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--The given question is incomplete, the complete question is given
" Answer quickly please
Given that A is a constant, the general solution to the differential equation dy/dt -5y = A is Select one O a. 3t2 2 Ob. 3= Ae-56 Ос. y = Aest Od y = Ce^(5t) +A/5 The solution to the exact differential equation"--
In my class, everyone studies French or German, but not both languages.
One third of the girls and the same number of boys study German.
Twice as many boys as girls study French.
Which of these could be the total number of boys and girls in my class?
The possible total number of boys and girls in the class is 21, and
the answer is b).
Let's denote the number of girls in the class as 'g' and the number of
boys as 'b'.
We know that all students in the class study either French or German,
but not both.
Therefore, the total number of students in the class is equal to the sum
of the number of students who study French and the number of students
who study German
From the given information, we can write the following equations:
g + b = total number of students(1/3)g = (1/3)b (one third of the girls and the same number of boysstudy German
2(1/3)g = b (twice as many boys as girls study French)We can simplify the second equation by multiplying both sides by 3:g = bSubstituting this into the first equation, we get:
2g = total number of studentsSubstituting the second equation into the third equation, we get:2g = b (twice as many boys as girls study French)Substituting this into the first equation, we get:
3g = total number of studentsTherefore, the total number of students in the class must be a multiple
of 3.
Let's try the answer choices:
a) 15 students (total number of students is not a multiple of 3)
b) 21 students (total number of students is a multiple of 3 and the
number of girls is a multiple of 3, so this is a possible solution)
c) 24 students (total number of students is a multiple of 3 and the
number of girls is not a multiple of 3)
d) 30 students (total number of students is a multiple of 3 but the
number of girls is not a multiple of 3)
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In a school of 580 students, one class was asked which hand they write with.
• “L” means they use their left hand.
• “R” means they use their right hand.
Here are the results:
L, R, R, R, R, R, R, R, R, L, R, R, R, R, R
1) Based on this sample, estimate the proportion of students at the school who write with their left hand.
2) Estimate the number of students at the school who write with their left hand.
3) A different class of `18` students is surveyed. Estimate how many write with their left hand.
1. The proportion of students at the school who write with their left hand is 2/15 OR 13.3%
2. The estimated number of students who write with their left hand is 77 students
3. The estimated number of students in the different class of 18 students who write with their left hand is 2
Estimating the number of students that write with their left handFrom the question, we are to estimate the proportion of students who write with their left hand
To estimate the proportion of students at the school who write with their left hand, we need to count the number of students in the sample who write with their left hand and divide by the total number of students in the sample.
From the given sample, there are 2 students who write with their left hand and 13 students who write with their right hand. So the estimated proportion of students who write with their left hand is:
2/15 = 0.133
OR
13.3%
2.
To estimate the number of students at the school who write with their left hand, we can multiply the proportion by the total number of students in the school
That is,
2/15 x 580 = 77.33
Thus, about 77 students write with their left hand
3.
To estimate how many students in a different class of 18 students write with their left hand, we can apply the proportion to the new sample:
2/15x 18 = 2.4
Hence, about 2 students in the different class write with their left hand.
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