After 15 hours, 3/4 or 75% of the container will be filled with water.
The faucet drips at an average rate of 4 drops per half hour, which means that the faucet drips at a rate of 8 drops per hour. Each drop is about 1 cm^3 in volume.
The volume of the plastic container is 5 cm x 4 cm x 8 cm = 160 cm^3.
So, for every hour, the faucet drips 8 drops x 1 cm^3/drop = 8 cm^3 of water.
Therefore, in 15 hours, the faucet will drip 15 hours x 8 cm^3/hour = 120 cm^3 of water into the container.
The fraction of the container that is filled after 15 hours can be found by dividing the volume of water that drips into the container (120 cm^3) by the volume of the container (160 cm^3):
Fraction of container filled = 120 cm^3 / 160 cm^3 = 0.75
So, after 15 hours, 3/4 or 75% of the container will be filled with water.
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suppose you ask 200 people whether they like the taste of beer. beer companies would like to claim that 55% of the population likes the taste of beer. in testing whether this sample represents such a population, what would the expected frequency values ( ) be for this study?
The null hypothesis would be that the population proportion of those who like the taste of beer is 55%
To determine the expected frequency values for this study, we need to use the given population proportion of 55% and the sample size of 200 people. The expected frequency for those who like the taste of beer would be 55% of the sample size, which is 0.55 x 200 = 110. The expected frequency for those who do not like the taste of beer would be 45% of the sample size, which is 0.45 x 200 = 90.
Expected frequency values are the predicted number of observations in a given category based on the assumption that the population proportion is true. In hypothesis testing, we use these expected frequency values to calculate the chi-square statistic, which helps us determine whether the observed data deviates significantly from what we would expect if the null hypothesis were true.
In this case, the null hypothesis would be that the population proportion of those who like the taste of beer is 55%. If the observed data significantly deviates from our expected frequency values, we may reject the null hypothesis and conclude that the population proportion is not 55%.
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Mr. cruz is selling coupons for a carnival. he has 2745 food coupons and some game coupons. he sells 639 of the food coupons. now he has 1372 food coupons than game coupons left. how many game coupons does he have?
Mr. cruz is selling coupons for a carnival. he has 2745 food coupons and some game coupons. Mr. Cruz has 734 game coupons.
Let's start by setting up some equations based on the information given:
Mr. Cruz has 2745 food coupons and some game coupons.
He sells 639 of the food coupons, so he has 2745 - 639 = 2106 food coupons left.
He has 1372 more food coupons than game coupons. Let's call the number of game coupons "x". Then, the number of food coupons he has left is x + 1372.
Putting these equations together, we can create the following equation:
x + 1372 = 2106
To solve for x, we can subtract 1372 from both sides:
x = 2106 - 1372
x = 734
Therefore, Mr. Cruz has 734 game coupons.
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Uhhhhhhhhh?????!???!?
Answer:
35
Formula used:
Sum of intereior angles of a polygon = (n-2) * 180, where n=number of sides
Step-by-step explanation:
Sum of interior angles = 540
12x+120=540
12x=420
x=35
3. Find the circumference and area, correct to the nearest tent
of a circle with diameter 5.3 Use π =
= 3.14.
C=
A =
The circumference and area, correct to the nearest tent of a circle with diameter are:
C = 16.6 units.
A = 22.1 square units.
How to calculate the circumference of a circle?In Mathematics and Geometry, the circumference of a circle can be determined by using the following mathematical equations:
C = πD or C = 2πr
Where:
C represents the circumference of a circle.D represents the diameter of a circle.r represents the radius of a circle.By substituting the given parameters into the formula for the circumference of a circle, we have the following;
Circumference of circle, C = 3.14 × 5.3
Circumference of circle, C = 16.6 units.
In Mathematics and Geometry, the area of a circle can be calculated by using this formula:
Area of circle = πd²/4
Area of circle = 3.14 × 5.3²/4
Area of circle = 22.1 square units.
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what is 5 to the tenth power times 8 to the tehth power
Answer: 1083507449
Step-by-step explanation: do the multiplication one by one
Answer:
Step-by-step explanation:[tex]5^{10}\times8^{10}[/tex]is the given question. If we expand the equation then we get [tex]5\times5\times...\times 5\times8\times8...\times8=(5\times8)^{10}=40^{10}=1048576\times10^{10}[/tex]
Final Answer: So the final answer of this question is [tex]1048576\times10^{10}[/tex].
9 A bag contains only red marbles and blue marbles. The number of red marbles in the bag can be represented by x. The number of blue marbles is 12 more than 3 times the number of red marbles. There are a total of 48 marbles in the bag. What is x, the number of red marbles in the bag? AS B 12 C 9 D 15 ere used create the following figure. (7.11A)
Answer: 3
Step-by-step explanation: 345
kevin has 5-cent coins, 10-cent coins, and 25-cent coins. he needs exactly 90 cents. what is the fewest number of coins kevin can use to make exactly 90 cents?
The fewest number of coins that Kevin can use to make exactly 90 cents is six coins: three 25-cent coins and three 5-cent coins.
To determine the fewest number of coins that Kevin can use to make exactly 90 cents, we need to consider the values of the coins and how they can add up to 90 cents. We want to use the fewest number of coins possible, so we should start with the highest-value coins first. In this case, the highest-value coin is the 25-cent coin.
Since Kevin needs exactly 90 cents, he could use three 25-cent coins, which would give him 75 cents. He would then need 15 more cents to make 90 cents. The only coins that he has left are 5-cent coins and 10-cent coins. If he were to use two 10-cent coins, he would have to use three 5-cent coins to make up the remaining 5 cents, for a total of five coins. However, if he uses three 5-cent coins instead of two 10-cent coins, he will have used six coins in total, which is the fewest number of coins possible. Therefore, the fewest number of coins that Kevin can use to make exactly 90 cents is six coins: three 25-cent coins and three 5-cent coins.
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Let Z represent a standard normal random variable. P(Z>0) is equal to
0.0
0.5
0.45
0.9
A standard normal random variable (Z) has a mean of 0 and a standard deviation of 1. The probability of Z being greater than 0 is equal to the area under the normal curve to the right of 0, which is exactly half of the total area under the curve (since the curve is symmetric around the mean of 0). Therefore, P(Z>0) is equal to 0.5.
A standard normal random variable, like Z in your question, follows a standard normal distribution, which is a special type of normal distribution with a mean of 0 and a standard deviation of 1. Now, you're asked to find the probability P(Z > 0).
Since the standard normal distribution is symmetrical around the mean (0), the probability of Z being greater than 0 is equal to the probability of Z being less than 0. In other words, half of the distribution is on the right side of the mean, and the other half is on the left side.
Therefore, P(Z > 0) = 0.5, which is your answer.
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put the following critical values in order for the most area in the tails of the distribution. (a) z0.10 (b) t0.10 with 25 degrees of freedom (c) 0.10 with 40 degrees of freedom. (This is a reading assessment question. Be certain of your answer because you only get one attempt on this question.) Choose the correct answer below. (a), (c), (b) (b), (c)(a) (c), (b), (a) (c), (a), (b) (b), (a), (c) (a), (b), (c)
To order the critical values for the most area in the tails of the distribution, we need to look at the degrees of freedom and the type of test. the correct order is (b), (c), (a).
For a one-tailed test, we want to find the critical value that cuts off the highest percentage of the distribution, and for a two-tailed test, we want to find the critical values that cut off equal percentages in both tails.
(a) z0.10 is the critical value for a one-tailed test with alpha = 0.10. It cuts off 10% in the upper tail, so we want to place it last.
(b) t0.10 with 25 degrees of freedom is the critical value for a one-tailed t-test with alpha = 0.10 and 25 degrees of freedom. It cuts off more than 10% in the upper tail, so we want to place it first.
(c) 0.10 with 40 degrees of freedom is the critical value for a two-tailed t-test with alpha = 0.10 and 40 degrees of freedom. It cuts off 5% in each tail, so we want to place it in the middle.
Therefore, the correct order is (b), (c), (a).
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The blue triangle is a dilation of the black triangle. what is the scale factor of the dilation? a) 1 3 b) 1 2 c) 2 d) 3
The answer is not one of the options given, but the correct scale factor is 1.5.
To find the scale factor of the dilation from the black triangle to the blue triangle, we need to compare the corresponding side lengths of both triangles.
Looking at the black triangle, we can see that the length of the side opposite the right angle is 6 cm, while the length of the shorter adjacent side is 2 cm.
In the blue triangle, the corresponding side opposite the right angle is 9 cm, while the shorter adjacent side is 3 cm.
We can see that the length of the corresponding sides in the blue triangle are 1.5 times the length of the corresponding sides in the black triangle. Therefore, the scale factor of the dilation from the black triangle to the blue triangle is:
9 cm / 6 cm = 3/2 = 1.5
So the answer is not one of the options given, but the correct scale factor is 1.5.
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the empire state building in new york city is 1250 feet (or 381 meters) tall. a standard nickel is 2 millimeters thick and 21 millimeters across. assuming you could actually make a stack of nickels as tall as the empire state building, how many nickels would it take
the final answer is 5,807 nickels to make a stack as tall as the Empire State Building.
To calculate the number of nickels required to make a stack as tall as the Empire State Building, we first need to convert the height of the building from feet to millimeters. Since 1 foot is equal to 304.8 millimeters, the height of the building in millimeters would be 381 x 304.8 = 11613.8 millimeters.
Next, we need to calculate the thickness of a single nickel in millimeters, which is 2 millimeters.
To find the number of nickels required, we divide the total height of the building (11613.8 millimeters) by the thickness of a single nickel (2 millimeters). This gives us a total of 5,806.9 nickels.
However, since we cannot have a fraction of a nickel, we need to round up to the nearest whole number. Therefore, the final answer is 5,807 nickels to make a stack as tall as the Empire State Building.
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find a cartesian equation for the curve and identify it. r = 2 csc(θ)
The cartesian equation of the curve [tex]r=2 \hspace{0.1cm} csc \hspace{0.1cm} \theta[/tex] is [tex]y=2[/tex].
A Cartesian equation is essential in mathematics. It corresponds to a mathematical formula that expresses the connection between elements as a function of their positions on a plane known as Cartesian.
A two-dimensional coordinate scheme called the Cartesian plane employs a horizontal x-axis and an upward y-axis to identify locations in space.
Given that, [tex]r=2 \hspace{0.1cm} csc \hspace{0.1cm} \theta[/tex].
So, [tex]csc\hspace{0.1cm}\theta=cosec \hspace{0.1cm}\theta[/tex].
The equation becomes as follows:
[tex]r=2cosec\hspace{0.1cm} \theta[/tex]
By using the trigonometric equation [tex]cosec\hspace{0.1cm} \theta=\frac{1}{sin\hspace{0.1cm}\theta}[/tex], we get
[tex]r= \frac{2}{sin \hspace{0.1cm} \theta}[/tex]
Multiplying both sides by [tex]sin\hspace{0.1cm}\theta[/tex], we get
[tex]r \hspace{0.1cm}sin\hspace{0.1cm}\theta =2\hspace{0.1cm}\frac{sin\hspace{0.1cm}\theta}{sin\hspace{0.1cm}\theta}[/tex]
[tex]rsin\hspace{0.1cm}\theta=2[/tex]
By the parametric equations [tex]x=rcos\hspace{0.1cm}\theta[/tex] and [tex]y=rsin\hspace{0.1cm}\theta[/tex], we get
[tex]y=2[/tex]
It is a horizantal line.
Hence, the cartesian equation of the curve [tex]r=2 \hspace{0.1cm} csc \hspace{0.1cm} \theta[/tex] is [tex]y=2[/tex].
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The cartesian equation for the curve is: y = 2 This is a horizontal line passing through the point (0,2).
To find a Cartesian equation for the curve given by the polar equation r = 2 csc(θ), we will convert the polar coordinates (r, θ) into Cartesian coordinates (x, y) using the following relationships:
x = r * cos(θ)
y = r * sin(θ)
Step 1: Express r in terms of θ
r = 2 csc(θ)
Step 2: Since csc(θ) = 1 / sin(θ), rewrite the equation as
r = 2 / sin(θ)
Step 3: Express x and y in terms of r and θ
x = r * cos(θ)
y = r * sin(θ)
Step 4: Substitute r from Step 2 into the y equation
y = (2 / sin(θ)) * sin(θ)
Step 5: Simplify the equation
y = 2
The Cartesian equation for the given polar equation is y = 2, which represents a horizontal line passing through the point (0, 2).
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A sales manager for an advertising agency believes there is a relationship between the number of contacts that a salesperson makes and the amount of sales dollars earned. A regression ANOVA shows the following results. ANOVA df SS MS F Significance F Regression 1.00 13,591.17 13,591.17 156.38 0.00 Residual 8.00 657.95 86.68 Total 9.00 14,249.12 What is the value of the coefficient of determination?
Multiple Choice
−0.9538
0.9766
0.6344
0.9538
The coefficient of determination, denoted by R^2, is a measure of how well the regression model fits the data. It represents the proportion of the total variation in the dependent variable (sales dollars) that is explained by the independent variable (number of contacts).
In this case, we can use the formula:
R^2 = SS_regression / SS_total
where SS_regression is the sum of squares of the regression (13,591.17) and SS_total is the total sum of squares (14,249.12).
Thus,
R^2 = 13,591.17 / 14,249.12
R^2 = 0.953
Therefore, the coefficient of determination is 0.953 or 95.3%. This means that 95.3% of the variation in sales dollars can be explained by the number of contacts made by the salesperson, and the remaining 4.7% is due to other factors not included in the model.
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write an integral that quantifies the increase in the volume of a sphere as its radius r quadruples from r unit to 4r units.
The expression of the integral that quantifies the increase in volume of a sphere as its radius r quadruples from r to 4·r is therefore;
∫dV/dr, r, r, 4·r = 84·π·r³
What is an integral?An integral is a function which when differentiated, yields a specified function.
The volume of the sphere with radius r is V = (4/3) × π × r³
The increase in volume with a change in radius from r to 4·r is the difference between the volume at r and the volume with a radius of 4·r, as follows;
ΔV = ∫dV/dr, r, r, 4·r = [tex]V_{final}[/tex] - [tex]V_{initial}[/tex]
Therefore;
ΔV = ∫dV/dr, r, r, 4·r = ∫4·π·r², r, r, 4·r = (4/3) × π × (4·r)³ - (4/3) × π × r³ = 84·π·r³
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Kruskal's MST algorithm finds an MST by first putting all of the edges into a PQ. The next edge is then repeatedly removed from the PQ and added to the MST as long as: a.its edge weight is unique within the MST b.its edge weight is non-negative c.it doesn't create a cycle d.it doesn't break a cycle
The next edge is then repeatedly removed from the PQ and added to the MST as long as: c. it doesn't create a cycle.
Kruskal's MST algorithm is a greedy algorithm that finds the minimum spanning tree of a graph.
Kruskal's MST algorithm finds an MST by first putting all of the edges into a PQ. The next edge is then repeatedly removed from the PQ and added to the MST as long as: c. it doesn't create a cycle. This condition ensures that the resulting graph remains a tree and connects all vertices with the minimum possible total edge weight.
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The length of the hypotenuse of a right triangle is 10 m and the length of one of the legs is 8 m
The length of the other leg of the right triangle is 6 m.
The length of the hypotenuse of a right triangle is 10 m and the length of one of the legs is 8 m.
We can use the Pythagorean theorem to find the length of the other leg of the triangle:
a^2 + b^2 = c^2
where a and b are the lengths of the legs of the triangle and c is the length of the hypotenuse.
Substituting the given values, we get:
8^2 + b^2 = 10^2
64 + b^2 = 100
b^2 = 36
b = 6
Therefore, the length of the other leg of the right triangle is 6 m.
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The tip of a pendulum of 40 cm describes an arc of 20 cm. Though what angle does the pendulum swing
Answer:
90/π degree
Step-by-step explanation:
length of arc, l= 20cm
length of pendulum, r= 40cm
let the angle be a:
we know that , r *a=l
40*a=20
a= 20/40=1/2 radian
= 1/2*(360/2π)=90/ π degree
Please answer ASAP for notes
Use the image to determine the type of transformation shown
A. Vertical translation
B. Reflection across the X-axis
C.180° counterclockwise rotation
D. Horizontal Translation
The type of transformation shown is given as follows:
A. Vertical translation.
What are transformations on the graph of a function?Examples of transformations are given as follows:
Translation: Lateral or vertical movements.Reflections: A reflection is either over one of the axis on the graph or over a line.Rotations: A rotation is over a degree measure, either clockwise or counterclockwise.Dilation: Coordinates of the vertices of the original figure are multiplied by the scale factor, which can either enlarge or reduce the figure.For this problem, the function was moved down, keeping the same orientation and inclination, hence it underwent a vertical translation.
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Population is changing exponentially. The amount of people in thousands each year of a city can be represented by the expression 25.75(1.025)
The amount of people in the city after 2 years is 27.05 thousands
From the question, we have the following parameters that can be used in our computation:
The expression 25.75(1.025)
Express as a function
So, we have
P(x) = 25.75(1.025)ˣ
In two years, we have
x = 2
Substitute the known values in the above equation, so, we have the following representation
P(2) = 25.75(1.025)²
Evaluate
P(2) = 27.05
Hence, the population is approximately 27.05 thousands
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Find the percent of discount. Round to the nearest tenth. original price $23,505; selling price $16,295
The percent of discount, rounded to the nearest tenth, is approximately 30.7%.
To find the percent of discount, we need to calculate the difference between the original price and the selling price, and then divide that by the original price. Finally, we multiply by 100 to express it as a percentage.
Discount = Original Price - Selling Price = $23,505 - $16,295 = $7,210
Percent of Discount = (Discount / Original Price) * 100 = ($7,210 / $23,505) * 100 ≈ 30.7%
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which row would you normally consult to find your chi-square results in a chi-square test for independence all assumptions being met? select one: a. n of valid cases b. fisher's exact test c. linear-by-linear association d. pearson chi-square
To find your chi-square results in a chi-square test for independence, you would normally consult the d. Pearson chi-square.
Why the Pearson chi-square row ?Providing both the chi-square statistic value and its related p-value, this row can be utilized to identify if there is a remarkable relationship between two dissimilar categorical variables.
Albeit not pertinent to the chi-square test for independence, the remaining options denote other statistical tests or measurements. "N of valid cases" describes the amount of cases in the dataset containing genuine facts about the tested variables.
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If Two Nonzero Vectors Point In The Same Direction, Their Dot Product Must Be Zero. True Or False?
False, If two nonzero vectors point in the same direction, their dot product is equal to the product of their magnitudes, which is nonzero. If two nonzero vectors are orthogonal (perpendicular), then their dot product is zero.
If two nonzero vectors point in the same direction, their dot product must be zero. The statement is false.
Recall the definition of the dot product: A · B = |A||B|cos(θ), where A and B are the two vectors, |A| and |B| are their magnitudes, and θ is the angle between them.
When two nonzero vectors point in the same direction, the angle between them, θ, is 0 degrees.
The cosine of 0 degrees is 1.
Since the vectors are nonzero, their magnitudes are nonzero as well.
Therefore, the dot product A · B = |A||B|cos(0) = |A||B| * 1, which is not equal to zero as long as both vectors have nonzero magnitudes.
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At the gift shop, they sell small greeting cards and large greeting cards. The cost of a small greeting card is $1.25 and the cost of a large greeting card is $4.50. How much would it cost to get 5 small greeting cards and 4 large greeting cards? How much would it cost to get
�
x small greeting cards and
�
y large greeting cards?
The cost of 5 small greeting cards and 4 large greeting cards is given by $24.25.
Total cost of x small greeting cards and y large greeting cards is given by $(1.25x + 4.5y).
Given that the cost of each small cards = $1.25
the cost of each big cards = $4.50
So the cost of 5 small cards = $1.25*5 = $6.25
the cost of 4 large greeting cards = $4.5*4 = $18
So total cost to get 5 small greeting cards and 4 large greeting cards = 6.25 + 18 = $24.25
Cost of x small greeting cards = $1.25x
Cost of y large greeting cards = $4.5y
Total cost of x small greeting cards and y large greeting cards = $(1.25x + 4.5y).
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Mai poured liters of water into a partially filled pitcher. The pitcher then contained liters.
The amount of water that Mai poured into the pitcher is (y) - (x) liters.
One possible way to find the amount of water that Mai poured into the pitcher is to subtract the initial volume of the partially filled pitcher from the final volume of the pitcher after the water has been added. The amount of water that Mai poured into the pitcher is therefore (final volume) - (initial volume) liters.
Let's assume that the initial volume of the partially filled pitcher is x liters and the final volume of the pitcher after Mai has poured in water is y liters. Then, the amount of water that Mai poured into the pitcher can be found using the expression:
(final volume) - (initial volume) = (y) - (x) liters.
Therefore, the amount of water that Mai poured into the pitcher is (y) - (x) liters.
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Fill the Blank ; A distribution in which all the values have the same frequency is called a(n) ______ distribution.
A distribution in which all the values have the same frequency is called a uniform distribution. This type of distribution is characterized by an equal probability of each value occurring within a given range or interval.
In a uniform distribution, the probability density function is a constant value, indicating that all values have the same chance of occurring.
Uniform distributions are often used in statistical analyses and probability theory, particularly in cases where there is no reason to expect one value to occur more frequently than any other. For example, rolling a fair die would result in a uniform distribution, with each of the six possible outcomes having an equal chance of occurring.
Uniform distributions can be visualized using histograms or probability density functions, which display the frequency or likelihood of each value occurring. In practice, many real-world distributions are not perfectly uniform, but they may approximate a uniform distribution in certain circumstances.
Overall, uniform distribution is an important concept in statistics and probability theory, helping to understand the likelihood and frequency of different values occurring within a given data set or range.
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any list of five real numbers is a vector in set of real numbers r superscript 5ℝ5.
Yes, any list of five real numbers can be considered a vector in the set of real numbers with dimension 5, denoted as ℝ5.
A vector is a mathematical object that represents a quantity with both magnitude and direction. In the case of ℝ5, this set includes all possible lists of five real numbers, which can be thought of as five-dimensional vectors. Each number in the list represents a component or coordinate of the vector, indicating how far it extends in each of the five dimensions.
Therefore, any list of five real numbers can be considered a vector in the set of real numbers with dimension 5, denoted as ℝ5.
In mathematics, a vector is an element of a vector space, which is a set of objects that can be added together and multiplied by scalars (real numbers). The set ℝ⁵ is a vector space consisting of all 5-tuples (lists) of real numbers, written as (a₁, a₂, a₃, a₄, a₅), where each element aᵢ is a real number. Any list of five real numbers forms a vector in ℝ⁵ because it satisfies the required conditions to be an element of the vector space.
A list of five real numbers is indeed a vector in the set of real numbers ℝ⁵, as it meets the necessary criteria to be a part of the vector space.
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he wins 2 blue ball and lose 3 red balls, after 5 days he has the same amount of blue and red balls how many red balls have in the start?.
If someone wins 2 blue balls and loses 3 red balls every day for 5 days, and ends up with the same number of blue and red balls, then they must have started with 25 red balls.
Explanation:
Let x be the number of red balls the person started with. After 5 days, they would have won 2 × 5 = 10 blue balls and lost 3 × 5 = 15 red balls. So, the person would have a total of (x - 15) red balls and (10 + 2 × 5) = 20 blue balls. We know that the person ends up with the same number of blue and red balls, so we can set up the equation:
x - 15 = 20
Solving for x, we get:
x = 35
Therefore, the person started with 35 red balls. However, this does not satisfy the condition that the person ends up with the same number of blue and red balls, since 35 - 15 = 20 ≠ 20 blue balls. So, we made a mistake in our assumption that the person started with x red balls. Let's try again:
Let y be the number of red balls the person started with. After 5 days, they would have won 2 × 5 = 10 blue balls and lost 3 × 5 = 15 red balls. So, the person would have a total of (y - 15) red balls and 20 blue balls. We know that the person ends up with the same number of blue and red balls, so we can set up the equation:
y - 15 = 20
Solving for y, we get:
y = 35
Therefore, the person started with 35 red balls and ended up with 20 blue balls and 20 red balls, satisfying the given condition. So, the answer is that the person started with 25 red balls.
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2. a food snack manufacturer samples 41 bags of pretzels off the assembly line and weighs their contents. if the sample mean is 12.7 oz. and the sample standard deviation is 0.60 oz., find the 98% confidence interval of the true mean. (10 points)
we can be 98% confident that the true mean weight of pretzel bags produced by the manufacturer lies between 12.47 and 12.93 ounces.
To finder lies between produce by the 98% confidence interval of the true mean, we can use the formula:
CI = x ± z* (σ/√n)
where x is the sample mean, σ is the population standard deviation (which we don't know), n is the sample size, and z* is the z-score corresponding to the desired level of confidence (98% in this case).
Since we don't know the population standard deviation, we can use the sample standard deviation as an estimate. The z-score corresponding to 98% confidence level is 2.33 (from the standard normal distribution table). Thus, the 98% confidence interval for the true mean is:
CI = 12.7 ± 2.33 * (0.60/√41)
CI = 12.7 ± 0.23
CI = (12.47, 12.93)
Therefore, wewe can be 98% confident that the true mean weight of pretzel bags produced by the manufacturer lies between 12.47 and 12.93 ounces.
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Given that one container of caramel sauce makes 20 banana splits, how much would it cost for the caramel sauce on one banana split?
2 containers of caramel sauce for $6.40
Answer:
$0.16
Step-by-step explanation:
It is 16 cents because a singular jar of caramel sauce is modeled by 6.4/2=3.2 then you multiply 1/20 x 3.2 and you get 0.16, so it costs 16 cents in caramel sauce to make one banana.
