The rate constant of the first-order decomposition reaction is approximately 0.0242 yr^(-1).
In a first-order decomposition reaction, the rate of decay of a substance is proportional to its concentration. The half-life of a reaction is the time required for half of the reactant to undergo decomposition. To find the rate constant (k) of the reaction in units of yr^(-1), we can use the equation: t(1/2) = ln(2) / k
Given that the half-life (t(1/2)) is 28.6 years, we can rearrange the equation to solve for the rate constant: k = ln(2) / t(1/2)
Substituting the values into the equation: k = ln(2) / 28.6 yr
Using a calculator, we find that the rate constant is approximately 0.0242 yr^(-1). This means that the concentration of the reactant will decrease by half every 28.6 years in this first-order decomposition reaction. The rate constant provides a quantitative measure of the reaction rate and allows us to predict the extent of decomposition over time.
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the volume of an irregular solid was determined by difference using a 100 ml graduated cylinder. the initial volume was 25.2 ml. after the solid was added to cylinder the volume reading was 52.08 ml. if the mass of the irregular solid is 38.221 g, calculate the density of the irregular solid.
The mass of the irregular solid is 38.221 g, and the initial volume of the graduated cylinder was 25.2 ml, and the final volume after adding the solid was 52.08 ml, we can find the volume of the solid by taking the difference between the final and initial volumes. The density of the irregular solid is 1.42 g/cm^3.
To calculate the density of the irregular solid, we can use the formula:
Density = Mass/Volume.
Given that the mass of the irregular solid is 38.221 g, and the initial volume of the graduated cylinder was 25.2 ml, and the final volume after adding the solid was 52.08 ml, we can find the volume of the solid by taking the difference between the final and initial volumes.
Volume of the solid = Final volume - Initial volume
= 52.08 ml - 25.2 ml
= 26.88 ml.
Now, we can calculate the density using the formula:
Density = Mass/Volume.
Density = 38.221 g / 26.88 ml.
To convert ml to cm³, we can use the fact that 1 ml is equal to 1 cm³.
Density = 38.221 g / 26.88 cm³.
Therefore, the density of the irregular solid is 1.42 g/cm³.
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In an acidic solutionthe number of H+ is less than the number of OH-.
A. the number of H+ is greater than the number of OH-.
B. the number of H+ is equal to the number of OH-.
C. the number of H+ is 3 times less than the number of OH-.
D. the number of H+ is 10 times less than the number of OH-.
When a solution is acidic, the concentration of H+ ions increases, which leads to a decrease in the number of OH- ions. Therefore, the number of H+ is greater than the number of OH-.A solution is considered acidic when its pH is below 7. The pH scale ranges from 0 to 14, with 7 being neutral.
pH stands for the power of hydrogen, which is the concentration of hydrogen ions (H+) in the solution. When a solution is acidic, its hydrogen ion concentration increases, and the pH value drops below 7. The higher the concentration of H+ ions, the lower the pH value, which means that the solution is more acidic.
Therefore, in an acidic solution, the number of H+ ions is greater than the number of OH- ions (option A). The ratio of H+ to OH-ions in an acidic solution is less than 1, while in a basic solution, the ratio is greater than 1. The strength of an acid depends on its ionization constant, which measures the degree to which it dissociates in water. Strong acids ionize completely in water, while weak acids only partially dissociate, which means that they have a lower concentration of H+ ions.
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