A game of tug-of-war, in which two teams pull on opposite ends of a rope is shown here. What needs to happen to make the center of the rope go in one direction?


The ground needs to provide more friction for both teams.


Both teams have the same amount of people.


The rope needs to have no mass of its own.


One team pulls with more force than the other.

Answer: sediments

Explanation: Weathering of volcanic ash and pumice is unique regarding minerals formed and mineral formation. These minerals include allophane, imogolite, opaline silica, and some halloysites, and have distinctive structures and properties. Mar 10, 1987

Erosion and weathering transform boulders and even mountains into sediments, such as sand or mud. A dissolution is a form of weathering—chemical weathering. With this process, water that is slightly acidic slowly wears away the stone. These three processes create the raw materials for new, sedimentary rocks.

a) KCN = Potassium cyanide

b) NaBrO2 = Sodium bromite

c) Sr(OH)2 = Strontium hydroxide

d) CoTe = Cobalt telluride

e) Fe2(CO3)3 = Iron (III) Carbonate

f) Cr(NO3)3 = Chromium(III) nitrate

g) (NH4)2SO3 = Ammonium Sulfite

h) NaH2PO4 = Sodium dihydrogen phosphate

i) KMnO4 = Potassium permanganate

j) Ag2Cr2O7 = Silver dichromate

A chemical molecule known as an ionic compound in chemistry is one that contains ions bound together by the electrostatic forces known as ionic bonding. Despite having both positively and negatively charged atoms, or cations and anions, the compound is generally neutral.

These can be either polyatomic species, like the ammonium (NH+ 4) and carbonate (CO2 3) ions in ammonium carbonate, or straightforward ions, like the sodium (Na+) and chloride (Cl) in sodium chloride.

Learn more about Potassium

https://brainly.com/question/13321031

#SPJ1

Answer:

First, we need to calculate the amount of heat required to raise the temperature of ice from -21°C to 0°C:

q1 = m × C_solid × ΔT = 31 g × 2.09 J/g·°C × (0°C - (-21°C)) = 1341.09 J

Next, we need to calculate the amount of heat required to melt the ice at 0°C:

q2 = m × ΔH_fusion = 31 g × 334 J/g = 10354 J

Then, we need to calculate the amount of heat required to raise the temperature of the liquid water from 0°C to 42°C:

q3 = m × C_liquid × ΔT = 31 g × 4.18 J/g·°C × (42°C - 0°C) = 5201.56 J

Finally, we need to calculate the amount of heat required to vaporize the liquid water at 100°C:

q4 = m × ΔH_vaporization = 31 g × 2260 J/g = 70060 J

The total amount of heat required is the sum of all four steps:

q_total = q1 + q2 + q3 + q4 = 86857.65 J

Converting to kJ:

q_total = 86.85765 kJ

Therefore, the amount of heat required to convert 31 g of ice at -21°C to liquid water at 42°C is approximately 86.9 kJ.

Explanation:

Accοrding tο the equatiοn 0.4006 mοl οf PF₃ will be required tο prοduce 27.5 grams οf PF₃.

Mοl is a unit οf measurement fοr the amοunt οf a substance. It is used tο measure the amοunt οf a particular element οr cοmpοund in a sample. Mοl is equal tο the number οf atοms, mοlecules, οr οther units in a sample. The size οf a mοl is determined by Avοgadrο's number, which is 6.022 x 10²³.

We first need tο calculate the mοlecular weight οf PF₃. This is dοne by adding up the atοmic masses οf the three atοms in the mοlecule.

                        P: 30.97 g/mοl

                            F: 18.99 g/mοl

Therefοre, PF₃ has a mοlecular weight οf:

                        30.97 + 18.99 + 18.99

                              = 68.95 g/mοl

Tο calculate the mοles οf PF₃ required tο prοduce 27.5 grams οf PF₃, we divide the mass οf PF₃ (27.5 g) by the mοlecular weight οf PF₃ (68.95 g/mοl):

                          27.5 g / 68.95 g/mοl

                        = 0.4006 mοl οf PF₃

Therefοre, 0.4006 mοl οf PF₃ will be required tο prοduce 27.5 grams οf PF₃,

To learn more about mol :

brainly.com/question/15356425

#SPJ1

Answer:

4.42 x 10^22 molecules

Explanation:

1 mole of CO2 has 6.022 x 10^23 molecules

=> 0.0734 x 6.022 x 10^23 = 4.420148 x 10^22 or 4.42 x 10^22

Answer:

Explanation:

One system available in the industry for the detection of foreign substances in cotton is the High Volume Instrument (HVI) system. The HVI system measures several properties of cotton fibers, such as length, strength, micronaire, color, and foreign matter content. The foreign matter content measurement detects and quantifies any extraneous materials present in the cotton fibers, such as dirt, seed coat fragments, and leaf particles. The HVI system is widely used in the cotton industry for quality control and grading purposes.

nitrogen = N

sodium = Na

chromium = Cr

Including the title, abstract, introduction, techniques & materials, results, commentary, conclusion, & references, a lab report is divided into eight components.

This lab is equipped with all the tools required for sample preparation as well as the standards needed for a variety of fluid and solid sample analyses. Glassware, exhaust fans, a muffled furnace, centrifuges, aggregate mills, and ovens are among the conventional equipment found in the lab.

It gives you an opportunity to put your knowledge to use while reinforcing the topics you have studied in class. You will gain knowledge of certain crucial experimental skills that are required if you want to work as a successful chemist.

To know more about labs visit:

https://brainly.com/question/29296260

#SPJ1

The pressure of the substance from the problem we have here is  3.8 atm

The ideal gas equation, also known as the equation of state for an ideal gas, is given by:

PV = nRT

where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the absolute temperature of the gas.

This equation relates the pressure, volume, temperature, and amount of gas in a closed system assuming that the gas behaves as an ideal gas.

We know that;

PV = nRT

P = nRT/V

P = 0.3 * 0.082 * 313/2

p = 3.8 atm

Learn more about ideal gas:https://brainly.com/question/28257995

#SPJ1

Explanation:

We can use the formula for calculating the heat absorbed by a substance to find its specific heat:

q = mcΔT

where q is the heat absorbed, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.

We can first calculate the change in temperature:

ΔT = 124.2 °C - 28.1 °C = 96.1 °C

Next, we can substitute the given values into the formula and solve for c:

1585 J = (45.58 g) c (96.1 °C)

c = 1585 J / (45.58 g × 96.1 °C)

c = 0.357 J/g⋅∘C

Therefore, the specific heat of the substance is 0.357 J/g⋅∘C.

Answer:

The first step is to convert the given mass of HCl to moles:

moles of HCl = mass of HCl / molar mass of HCl

moles of HCl = 7.68 g / 36.46 g/mol

moles of HCl = 0.2103 mol

Next, we need to convert the given volume of solution to liters:

volume of solution = 253 mL = 0.253 L

Now we can calculate the molarity of the solution:

molarity = moles of solute / volume of solution

molarity = 0.2103 mol / 0.253 L

molarity = 0.831 M

Therefore, the molarity of the HCl solution is 0.831 M.

Explanation:

The standard enthalpy change of reaction for the given reaction is -46.9 kJ/mol. Since the enthalpy change is negative, it indicates that the reaction is exothermic and releases energy in the form of heat.

What is Enthalpy?

Enthalpy (H) is a thermodynamic property that describes the total heat content of a system at constant pressure. It is a measure of the internal energy of a system, which includes the energy required to create or destroy the system as well as the energy required to maintain its temperature and pressure.

The standard enthalpy change of reaction (ΔHr0) can be determined using the standard enthalpies of formation (ΔHf0) of the reactants and products.

2HCl(aq) + Ca(OH)2(s) → CaCl2(s) + 2H2O(l)

The standard enthalpy change of reaction can be calculated using the following equation:

ΔHr0 = Σ(nΔHf0(products)) - Σ(nΔHf0(reactants))

ΔHf0(HCl(aq)) = -167.2 kJ/mol

ΔHf0(Ca(OH)2(s)) = -986.1 kJ/mol

ΔHf0(CaCl2(s)) = -795.8 kJ/mol

ΔHf0(H2O(l)) = -285.8 kJ/mol

Substituting the values into the equation, we get:

ΔHr0 = [2(ΔHf0(H2O(l))) + ΔHf0(CaCl2(s))] - [2(ΔHf0(HCl(aq))) + ΔHf0(Ca(OH)2(s))]

ΔHr0 = [2(-285.8 kJ/mol) + (-795.8 kJ/mol)] - [2(-167.2 kJ/mol) + (-986.1 kJ/mol)]

ΔHr0 = (-571.6 kJ/mol - 795.8 kJ/mol) - (-334.4 kJ/mol - 986.1 kJ/mol)

ΔHr0 = -1367.4 kJ/mol + 1320.5 kJ/mol

ΔHr0 = -46.9 kJ/mol

Therefore, the standard enthalpy change of reaction for the given reaction is -46.9 kJ/mol. Since the enthalpy change is negative, it indicates that the reaction is exothermic and releases energy in the form of heat.

Learn more about Enthalpy  from given link

https://brainly.com/question/14047927

#SPJ1

The presence of water droplets on the cool upper portion of the test tube after heating the compound suggests that water molecules are trapped within its crystal structure. If the substance were a real hydrate, heating it would have caused all of the water molecules to evaporate, leaving behind an anhydrous substance.

What do you mean by crystalline compound?

The presence of water droplets on the cool upper portion of the test tube after heating the compound suggests that water molecules are trapped within its crystal structure. If the substance were a real hydrate, heating it would have caused all of the water molecules to evaporate, leaving behind an anhydrous substance.

However, the residue created a yellow-brown solution after being further dissolved in water, which is a certain sign of contaminants. When dissolved in water, true hydrates always produce a clear, colourless solution. Thus, the fact that the residue resulted in a coloured solution implies that the compound had impurities.

Together, the water stains and contaminants in the leftovers indicate that the original substance was not a genuine hydrate, but rather a mixture of the anhydrous substance and water, which may have been non-stoichiometrically trapped inside the crystal lattice or adsorbed onto the surface of the crystals.

Learn more about crystalline compound click here:

https://brainly.com/question/28972400

#SPJ1

Answer:

35.4g

Explanation:

Na = 23 g/mol

NaN3 = 23 + 3(14) = 65 g/mol

2NaN3 -> 3N2 + 2Na

=> 2 moles of NaN3 will produce 2 moles of Na

or 1 mole of NaN3 will produce 1 mole of Na

the moles of NaN3 with mass of 100.0 g is 100/65 moles

so mass of Na is: (100/65) x 23 = 35.38 or 35.4g

The complete and balanced reaction equation is: CuSO3(s) -> CuO(s) + SO2(g)

The reaction between HCI (hydrochloric acid) and CuSO3 (copper(II) sulfite) is not a valid chemical equation.

Copper(II) sulfite is not a stable compound, and it decomposes readily in air to form copper(II) oxide (CuO) and sulfur dioxide (SO2) according to the following equation:

CuSO3(s) -> CuO(s) + SO2(g)

The balanced equation for this reaction is: https://brainly.com/question/14258973

CuSO3(s) -> CuO(s) + SO2(g)

The gas formed in this reaction is sulfur dioxide (SO2).

More on balancing reactions can be found here: https://brainly.com/question/14280002

#SPJ1

No, using hydrochloric acid (HCl) to dissolve copper metal in the Preparation of Copper (I) Chloride experiment is not recommended because it would result in the formation of copper (II) chloride rather than copper (I) chloride.

How to prepare Copper (l) Chloride?

Copper metal reacts with hydrochloric acid to form copper (II) chloride and hydrogen gas:

Cu (s) + 2HCl (aq)

→ CuCl2 (aq) + H2 (g)

In contrast, when copper metal reacts with nitric acid, it is oxidized to copper (II) ions by the nitric acid. These copper (II) ions then react with copper metal to form copper (I) ions, which react with chloride ions to form copper (I) chloride:

Cu (s) + 4HNO3 (aq) → Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O (l)

Cu(NO3)2 (aq) + 2Cu (s) → 3Cu2+ (aq) + 2NO3- (aq)

3Cu2+ (aq) + 2Cl- (aq) → Cu3Cl2 (s)

Therefore, to obtain copper (I) chloride, it is necessary to use nitric acid in the first reaction.

To learn more about hydrochloric acid (HCl), visit: https://brainly.com/question/23260126

#SPJ1

Answer:

3

Explanation:

Answer:

2 moles of H3PO4 reacts with 3 moles of FeBr2

Explanation:

Hope this helps :)

The volume of the balloon is 12 it reaches this then  it is fully cooled by my refrigerator.

What is volume ?

Space is occupied by every three-dimensional object. Its volume serves as a gauge for this area. The area contained by an object's limits in three-dimensional space is referred to as its volume. Another name for it is an object's capacity.

What is temperature ?

The movement of these particles likewise increases with rising temperature. A thermometer or a calorimeter are used to measure temperature.

Therefore, The volume of the balloon is 12 it reaches this then  it is fully cooled by my refrigerator.

Learn more about volume from the given link.

https://brainly.com/question/463363

#SPJ1

Answer:

This might be a scam because it is a common tactic used by scammers to evoke sympathy from their targets. By appealing to the target's emotions, they may be more likely to overlook any warning signs and take action without thinking. Additionally, the urgency of the request (i.e., the tickets could go to waste) may pressure the target to act quickly without considering the potential risks. Scammers may use similar tactics to obtain personal information or money from their targets, so it's always important to be cautious when receiving unsolicited requests.

Explanation:

Taking into account the ideal gas law, there are 182.93 moles of gas in a 15 L scuba canister if the temperature of the canister is 200 K and the pressure is 200 atm.

An ideal gas is called a hypothetical or theoretical gas, which is composed of particles that move randomly and without interacting with each other.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law. This equation relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar gas constant:

P×V = n×R×T

You know:

Replacing in the ideal gas law:

200 atm× 15 L = n× 0.082 (atmL)÷(molK)× 200 K

Solving:

(200 atm× 15 L) ÷ (0.082 (atmL)÷(molK)× 200 K)= n

182.93 moles= n

Finallt, there are 182.93 moles of gas.

Learn more about ideal gas law:
https://brainly.com/question/4147359

#SPJ1

The overall energy change for the combustion of one mole of methane according to given chemical equation is 2648 kJ/mole.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The combustion involves reactants that is 413×4 +498×2=2648 kJ.

Thus, overall energy change for the combustion of one mole of methane according to given chemical equation is 2648 kJ/mole.

Learn more about chemical equation,here:

https://brainly.com/question/19626681

#SPJ1

Answer:

The rearrangement of atoms is a chemical change.

Explanation:

Answer:

(a) GaF3, gallium(III) fluoride

(b) LiH, lithium hydride

(c) AlI3, aluminum(III) iodide

(d) K2S, potassium sulfide

The molar quantity must be multiplied by Avogadro's number to be converted to moles or atoms.

How can a scientist use Avogadro's number?

One of the basic constants in chemistry is Avogadro's number. When the same amount of atoms or molecules are being compared, it allows comparison of the various atoms or molecules of a given substance.

A material's mole is equivalent to 6.022 x 10²³of that substance (such as atoms, molecules, or ions). The term "Avogadro's number" or "Avogadro's constant" refers to the integer 6.022*10²³. The mole idea can be used to convert between particle mass and number.

To learn more about Avogadro's number use:

https://brainly.com/question/14138110

#SPJ1

IV. Acetylene is a hydrocarbon molecule composed of two carbon atoms and two hydrogen atoms. It is a flammable gas, and when ignited with a spark, it produces an extremely hot flame.

Molecule is a unit of matter composed of two or more atoms bonded together. Atoms are the basic building blocks of all matter, and molecules are collections of atoms. Molecules can range in size from diatomic molecules composed of two atoms, to large macromolecules made up of hundreds of atoms. Molecules can vary in shape and complexity, and can consist of a variety of different elements. Molecules can be found in all physical states, including solids, liquids, and gases.

Ethylene is a hydrocarbon molecule composed of two carbon atoms and four hydrogen atoms. It is a gas with a sweet odor and is found naturally in plants, fruits, and vegetables.

I.

a. Cr2O3 (Chromium (III) oxide);

b. NH4H2PO4 (Ammonium dihydrogen phosphate);

c. CaSO4 (Calcium sulfate).

II.

a. Iron(II) Chloride

b. Barium Hydroxide

c. Lithium Cyanide

d. Lead(II) Chloride

To learn more about molecule

https://brainly.com/question/26388921

#SPJ1

1. When 36.0 g of H₂O is mixed with 67.0g of Fe, the moles of Fe₃O₄ produced by each reactant will be;

2. Fe is the limiting reactant.

3. H₂O is the excess reactant

4. The theoretical Yield amount in mol Fe₃O₄ is 0.4 moles

5. The actual yield is obtained from the lab

6. The mass of excess reactant is 7.2 g

Equation of the reaction: 3 Fe + 4 H₂O ---> Fe₃O₄ + 2 H₂

Molar mass of Fe = 56 g

Molar mass of H₂O = 18 g

Molar mass of Fe₃O₄ = 232 g /mol

Molar mass of H₂ = 2.0 g

1. When 36.0 g of H₂O is mixed with 67.0g of Fe, the moles of Fe₃O₄ produced by each reactant will be;

H₂O:

moles of Fe₃O₄ produced= 36/18 * 1/4

moles of Fe₃O₄ produced = 0.5 moles

Fe:

moles of Fe₃O₄ produced = 67/56 * 1/3

moles of Fe₃O₄ produced = 0.40 moles

Fe is the limiting reagent while H₂O is the excess reagent.

Moles of H₂O required = 36/18 - 0.4 * 4

Moles of H₂O required = 0.4 moles

The mass of excess reagent = 0.4 * 18

The mass of excess reagent = 7.2 g

Learn more about limiting reagents at: https://brainly.com/question/26905271

#SPJ1

12% is the mass percentage of calcium in calcium oxide and calcium phosphate​.

Mass percent is the means to indicate a concentration. Moreover, it specifies the element in a certain composition. A mass percentage can be used to understand the solution's composition.

It displays the amount of solute in a certain amount of solution. The solute's concentration is specified in terms of mass or moles.

mass percentage=(mass  of calcium/ mass of calcium phosphate)×100

                           = (40/310.18)×100

                           =12%

Therefore, 12% is the mass percentage of calcium in calcium oxide and calcium phosphate​.

To know more about mass percentage, here:

https://brainly.com/question/28998211

#SPJ9

Answer:

Explanation:The statement that is true about dilute and concentrated solutions is: Dilute solutions have a higher solvent-to-solute ratio than concentrated solutions.

Explanation:

In dilute solutions, the amount of solute is relatively low compared to the amount of solvent. Conversely, in concentrated solutions, the amount of solute is relatively high compared to the amount of solvent.

For example, if you add a teaspoon of sugar to a cup of water, you have a dilute solution. If you add five teaspoons of sugar to the same cup of water, you have a concentrated solution.

So, the correct statement is that dilute solutions have a higher solvent-to-solute ratio than concentrated solutions.

Answer:

Among the options you provided, the correct answer would be Double chemo-therapy gloves and Protective gown, as administering oral liquid to a patient carries a risk of splashing or splattering, and healthcare workers may want to avoid any contact with the patient's body fluids or the medication. However, it is important to note that this may depend on the specific policies and regulations in the healthcare setting, and healthcare workers should always follow the appropriate protocols and guidelines. Respiratory protection is not typically necessary for administering oral liquid. Single chemo-therapy gloves may be used for standard precautions, but the use of double gloves may provide additional protection.

Explanation:

Answer:

Explanation:

We can solve this problem using the combined gas law:

(P1V1) / T1 = (P2V2) / T2

where P is the pressure, V is the volume, and T is the temperature, measured in kelvins (K). The amount of gas is assumed to be constant.

We need to convert the initial and final temperatures to kelvins by adding 273.15 to each temperature:

T1 = 173 + 273.15 = 446.15 K

T2 = 567 + 273.15 = 840.15 K

Substituting the given values into the equation and solving for V2, we get:

(1V1) / T1 = (1V2) / T2

V2 = (T2/T1) * V1

V2 = (840.15/446.15) * 12.4 cm3

V2 = 23.3 cm3 (rounded to one decimal place)

Therefore, the final volume of the gas will be 23.3 cubic centimeters.