A leaky faucet drips 1 fluid ounce every 30 seconds. how many gallons of water will leak from this faucet in 1 year?

Caleb's performance on the unit test was better relative to his class because his z-score is higher than Kyle's.

To determine whose performance on the unit test was better relative to their class, we compare their z-scores.

A z-score measures how many standard deviations a data point is away from the mean. Kyle's test grade of 82 in class A has a z-score of (82 - 77) / 5 = 1, indicating that it is 1 standard deviation above the mean.

Caleb's test grade of 87 in class B has a z-score of (87 - 80) / 7 = 1, which is also 1 standard deviation above the mean. Since Caleb's z-score is higher than Kyle's, it means that his performance was relatively better compared to his class.

Therefore, the correct answer is that Caleb did better because his z-score is higher than Kyle's.

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Kyle and Caleb both performed the same according to their respective classes. Their z-scores, which were both 1, showed they performed 1 standard deviation above their respective class means.

We will find out the z-score for both Kyle and Caleb to determine which individual did better in relation to their respective classes. Z-score is a statistical measurement that describes a value's relationship to the mean of its group. A Z-score of 0 indicates a value is the same as the mean, whereas a positive or negative Z-score indicates how many standard deviations the value is above or below, respectively.

To calculate the z-score, we use the formula: Z = (X - μ) / σ where X is the obtained score, μ is the mean score, and σ is standard deviation.

For Kyle the calculation would be [tex]Z = (82 - 77) / 5 = 1.[/tex] For Caleb the calculation would be [tex]Z = (87 - 80) / 7 = 1.[/tex]

Both Kyle and Caleb have equal z-scores of 1. This means they equally did better than their respective classes by 1 standard deviation. Therefore, both performed the same because their z-scores have the same value.

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The equation for the relationship between x (volume of flour in cups) and y (number of muffins) is y = 4x. This means that for every cup of flour used, Josiah can bake 4 muffins.

The equation for the proportional relationship between the volume of flour (x) and the number of muffins (y) that Josiah bakes can be written as y = kx, where k is the constant of proportionality. In this case, k represents the number of muffins that can be made with one cup of flour.

To solve for the constant of proportionality, we need more information. If Josiah bakes a known number of muffins using a certain amount of flour, we can use that data to find the value of k. For example, if Josiah bakes 12 muffins using 3 cups of flour, we can substitute these values into the equation:

12 = k * 3

To find k, we divide both sides of the equation by 3:

k = 12 / 3

k = 4

So, the equation for the relationship between x (volume of flour in cups) and y (number of muffins) is y = 4x. This means that for every cup of flour used, Josiah can bake 4 muffins.

In summary, the equation y = 4x represents the proportional relationship between the volume of flour (x) and the number of muffins (y) that Josiah bakes. The constant of proportionality, 4, indicates that for every cup of flour, Josiah can bake 4 muffins. This equation can be used to calculate the number of muffins Josiah can bake based on the amount of flour he has available or to determine the amount of flour needed to bake a desired number of muffins.

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To simplify the expression -3x + 14x + 7x² - 3x + 4x(x + 1), we can combine like terms and perform the necessary multiplication.

Combining like terms:

-3x + 14x - 3x = 8x

Now let's simplify the last term, 4x(x + 1), by applying the distributive property:

4x(x + 1) = 4x^2 + 4x

Now we have the simplified expression:

8x + 7x² + 4x^2 + 4x

Combining like terms again:

8x + 4x + 7x² + 4x^2

Simplifying further:

(8x + 4x) + (7x² + 4x^2)

= 12x + 11x²

Therefore, the simplified form of the expression -3x + 14x + 7x² - 3x + 4x(x + 1) is 12x + 11x².

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The given investment model v = 3000(1.0425)^t describes an investment that grows exponentially over time with an initial value of $3000.

The investment model v = 3000(1.0425)^t can be analyzed to determine the characteristics of the investment:

1. The investment has an initial value of $3000: This is evident from the coefficient of 3000 in the equation. It represents the initial investment amount.

2. The investment grows exponentially over time: The term (1.0425)^t represents the growth factor. As t increases, the value of v increases exponentially.

3. The investment growth rate is 4.25% per year: The value 1.0425 is slightly greater than 1, indicating an annual growth rate of 4.25%.

4. The investment does not decrease in value over time: Since the coefficient and exponent are both positive, the investment value will always be positive and will not decrease.

Therefore, the correct statements about the investment described by v = 3000(1.0425)^t are that it has an initial value of $3000, grows exponentially over time, and does not decrease in value.

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Statements 1 and 2 are true statements, the conclusion agrees with the laws of syllogism.

Given,

If two angles are complementary, the sum of the measures of the angles is 90° .

Now,

Complementary angles: The sum of two angles is 90 degrees than the angles are said to be complement of each other .

Complementary angles : ∠1 + ∠2 = 90°

Both angles are complement to each other ,

∠1 = 90 - ∠2

∠2 = 90 - ∠1

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The population likely to respond to the survey would be individuals who are actively engaged in online activities and are willing to participate in surveys.

The survey is using a voluntary response sampling method. This means that individuals choose whether or not to participate in the survey.
One bias in this sampling method is self-selection bias. Since participation is voluntary, only those who are interested or motivated to respond will do so. This can lead to a non-representative sample, as people who spend more time online may be more likely to respond.

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a. For the production function Y = 2L, the returns to scale are constant. If we increase both inputs, L and K, by a certain factor, say x, then the output Y will also increase by the same factor x. In other words, the output is directly proportional to the scale of inputs.

b. For the production function Y = logL, the returns to scale are decreasing. If we increase both inputs, L and K, by a certain factor x, the output Y will not increase by the same factor x. Instead, it will increase at a diminishing rate. This is because the logarithmic function exhibits diminishing marginal returns, and hence, increasing the scale of inputs leads to smaller increases in output.

c. For the production function Y = (2L + 2K)^(1/2), the returns to scale are constant. If we increase both inputs, L and K, by a certain factor x, the output Y will increase by the same factor x. The square root function exhibits constant returns to scale because doubling both inputs results in the square root of the sum of the squared inputs.

d. For the production function Y = 100(K^0.8)(L^0.2), the returns to scale are decreasing. If we increase both inputs, L and K, by a certain factor x, the output Y will increase, but at a diminishing rate. This is because the exponents on L and K are less than 1, indicating diminishing marginal returns to scale.

e. The long-run production function y = 10x^1^2 + 11x^1x^2 + 19x^2^2 exhibits increasing returns to scale. To determine this, we can examine the coefficients of the function. The coefficient of x^1^2 is 10, the coefficient of x^1x^2 is 11, and the coefficient of x^2^2 is 19. When we increase the scale of inputs by a factor x, the output y will increase by a factor x^2, because the largest exponent in the function is 2. This indicates that doubling both inputs will result in a more than proportional increase in output, demonstrating increasing returns to scale.

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Answer:

c

Step-by-step explanation:

Answer:

C = 2π(10.2 in.) = 20.4π in. = about 64.1 in.

The boat is 0.843 nautical miles away from the island at the time the boat towards the island.

From the given information in the question we can note the important points given : ( movement of the boat )

From the above points, we can tell that there's a right-angled triangle formed with the island being on top.

We will solve this question using trigonometry.

As the boat is going in the direction of east of south, the base of the triangle will be the eastward direction and the height of the triangle will be the southward direction.

We will be left with the hypotenuse being the distance of the boat from the island.

By using the concept of trigonometry we can form the equation :

tan(8°) = h / 6

Here h is the hypotenuse of the right-angled triangle.

Now by grouping the known and unknown values we will rearrange the equation as:

h = tan(8°) × 6 miles

h = 0.1405 × 6 miles

h ≈ 0.843 miles

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The solutions for θ with 0 ≤ θ < 2π are θ = 0, θ = π, and θ = π/3.

To solve the equation tan²θ - √3tanθ = 0 for θ with 0 ≤ θ < 2π, we can factor out the common term "tanθ" and set each factor equal to zero. Here's the step-by-step solution:

Factor out "tanθ":

tanθ(tanθ - √3) = 0

Set each factor equal to zero:

tanθ = 0          or         tanθ - √3 = 0

Solve the first equation: tanθ = 0

In the interval 0 ≤ θ < 2π, the solutions are θ = 0 and θ = π.

Solve the second equation: tanθ - √3 = 0

Add √3 to both sides: tanθ = √3

To find the solutions in the given interval, we can use the inverse tangent function (also known as arctan or atan). Taking the arctan of both sides gives:

θ = arctan(√3)

In the interval 0 ≤ θ < 2π, the principal value of arctan(√3) is π/3. Therefore, θ = π/3 is another solution.

Therefore, the solutions for θ with 0 ≤ θ < 2π are θ = 0, θ = π, and θ = π/3.

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The measure of angle ∠6 is 50° .

Given,

ABCD is a rectangle.

Here,

∠1 + ∠2 = 90°

AB is parallel to CD .

AB = CD

AC is parallel to BD .

AC = BD

∠1 + 40° = 90°

∠1 = 50°

The lines parallel to each other subtends equal angle.

So,

∠3 = ∠2 = 40°

∠1 = ∠4 = 50°

Diagonals of rectangle are equal and bisect each other .

Thus,

∠6 = ∠4 = 50°

Hence the measure of angle ∠6 is 50 degrees .

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Any number multiplied by 0 will always result in 0. Therefore, the domain of an inverse function cannot be 0.

Inverse variation, often referred to as inverse proportion, is a relationship between two variables whereby when one variable rises, the other one falls, and vice versa. In mathematics, inverse variation is denoted by the equation y = k/x, where k is the variational constant and y and x are the variables. The collection of input values for which a function is defined and meaningful is known as its domain. The domain in the context of inverse variation denotes the range of possible values for the variable x.

x cannot equal zero when examining the equation y = k/x. This is because division by zero has no established meaning. The equation would change to y = k/0, which is an invalid mathematical action, if x were set to zero. Additionally, it makes obvious that zero cannot be in the domain of an inverse variation from a practical standpoint. If x were zero, the value of y would be infinite which would not be applicable or realistic in a lot of real-world situations. For example, it would not be logical for time to be zero in the case of inverse variation between speed and time as that would imply instantaneous speed.

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To create a fourth-degree polynomial equation with two irrational roots and two imaginary roots, we can use the concept of conjugate pairs.

Let's start by considering the quadratic factor (x² + a) where 'a' is a positive irrational number. This quadratic factor will have two irrational roots, namely √(-a) and -√(-a), which are complex conjugates of each other. Next, we consider the quadratic factor (x² + b) where 'b' is a negative irrational number. This quadratic factor will also have two irrational roots, namely √(-b) and -√(-b), which are complex conjugates of each other.

Multiplying these two quadratic factors together, we obtain a fourth-degree polynomial equation with the desired characteristics:
(x² + a)(x² + b) = (x² + a)(x² - b)
Expanding this equation: x⁴ + bx² + ax² - ab = x⁴ + (a-b)x² - ab

To ensure integer coefficients, we can choose 'a' and 'b' such that a-b and -ab are integers. This can be achieved by selecting 'a' and 'b' as algebraic irrational numbers. For example, let's choose a = √2 and b = -√3. Then the fourth-degree polynomial equation becomes:
x⁴ + (√2 + √3)x² + (√2)(√3)

In this equation, the two irrational roots are √(-a) and √(-b), while the two imaginary roots are -√(-a) and -√(-b). To create a fourth-degree polynomial equation with two irrational roots and two imaginary roots, we utilize the concept of conjugate pairs. By choosing quadratic factors with irrational coefficients and expanding them, we can form a fourth-degree polynomial equation with the desired properties. The irrational roots arise from the square roots of negative numbers, while the imaginary roots occur as the complex conjugates of the irrational roots.

To ensure integer coefficients, we select algebraic irrational numbers as the coefficients of the quadratic factors, resulting in a fourth-degree polynomial equation with integer coefficients and the specified types of roots.

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The solution to the equation 6(n - 4) = 3n is n = 8. When substituted back into the equation, it satisfies the equation.

Distributing 6 to both n and -4, we get 6n - 24 = 3n. Next, we can simplify the equation by subtracting 3n from both sides, which gives us 3n - 24 = 0.

Adding 24 to both sides, we have 3n = 24. Finally, dividing both sides by 3, we find n = 8.

To check if this solution is correct, we substitute n = 8 back into the original equation: 6(8 - 4) = 3(8).

Simplifying, we have 6(4) = 24, which indeed equals 24.

Therefore, the solution to the equation is n = 8, and it checks out when substituted back into the equation.

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After using the number line the calculated length of BD is 6 units.

Basically number line is used to picturise the numbers on a straight line. The left portion of the number line is used to show negative numbers and the right side is used for positive numbers.

Here in the given number line,

We can see E is the middle point showing the number 0.

With the reference, we can say the position of point B is -7.

Similarly, the position of point D is -1.

Obviously, -1 >-7.

∴The distance between B and D,

-1-(-7)=-1+7=6.

Hence, the measurement of BD is 6 units.

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The algebraic expression for the sum of the measures of the angles for a polygon with n sides is given by (n-2) * 180 degrees.

In a polygon, the sum of the measures of the interior angles is determined by the number of sides it has. It is known that the sum of the measures of the angles in a triangle is 180 degrees.

For each additional side added to the polygon, an extra triangle is formed, and therefore, an additional 180 degrees is added to the total sum of the angles.

To express this algebraically, we start with the base case of a triangle (n=3), where the sum of the measures of the angles is (3-2) * 180 = 180 degrees. From here, we can observe that for each additional side (n-2), we multiply by 180 to find the total sum of the angles for the polygon.

Thus, the algebraic expression for the sum of the measures of the angles for a polygon with n sides is (n-2) * 180 degrees.

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They do not have the same radius as the Earth. They are parallel to each other and are measured in degrees, while great circles like the equator divide the Earth into equal hemispheres. Lines of latitude are not great circles.

A great circle is a circle on a sphere whose center coincides with the center of the sphere. It divides the sphere into two equal hemispheres. Examples of great circles are the equator and the lines of longitude.

On the other hand, lines of latitude are not great circles because they do not have the same radius as the Earth. Lines of latitude are parallel to each other and are equidistant from each other. They are measured in degrees, with the equator being 0 degrees latitude and the poles being 90 degrees latitude.

To understand why lines of latitude are not great circles, imagine slicing a sphere at various angles. The slices you make will form circles, but they will not have the same radius as the sphere. They will be smaller as you move away from the equator towards the poles.

In summary, lines of latitude are not great circles because they do not have the same radius as the Earth. They are parallel to each other and are measured in degrees, while great circles like the equator divide the Earth into equal hemispheres.

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The work done during the reversible isothermal compression of the gas is approximately -119.63 Joules. The negative sign indicates that work is done on the system during compression.

To calculate the work done during the reversible isothermal compression of an ideal gas, we can use the formula:

Work = -nRT ln(Vf/Vi)

Where:

- n is the number of moles of the gas

- R is the ideal gas constant (8.314 J/(mol·K))

- T is the temperature in Kelvin

- Vi is the initial volume

- Vf is the final volume

Given:

n = 0.05 mol

R = 8.314 J/(mol·K)

Vi = 12 L

To calculate the work done for the given pressure change, we need to find the final volume (Vf). We can use the ideal gas law to relate pressure, volume, and moles:

PV = nRT

Initial pressure (Pi) = 2.5 atm

Final pressure (Pf) = Pi + pressure change = 2.5 atm + 15 atm = 17.5 atm

Using the ideal gas law, we can solve for Vf:

Vf = (nRT) / Pf

Vf = (0.05 mol * 8.314 J/(mol·K) * T) / (17.5 atm)

Since the process is isothermal, the temperature remains constant. Let's assume it is 298 K:

Vf = (0.05 mol * 8.314 J/(mol·K) * 298 K) / (17.5 atm)

Vf ≈ 8.483 L

Now we can calculate the work done using the equation:

Work = -nRT ln(Vf/Vi)

Work = -(0.05 mol * 8.314 J/(mol·K) * 298 K) * ln(8.483 L / 12 L)

Work = -(0.05 mol * 8.314 J/(mol·K) * 298 K) * ln(8.483 L / 12 L)

Calculating the expression:

Work = -(0.05 mol * 8.314 J/(mol·K) * 298 K) * ln(0.7069)

Using a scientific calculator or math software to evaluate the natural logarithm:

Work ≈ -119.63 J

Therefore, the work done during the reversible isothermal compression of the gas is approximately -119.63 Joules. The negative sign indicates that work is done on the system during compression.

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The correct way to write the given arithmetic series in summation notation is: Σn=1 to 9 (3 + 5(n-1))

The student's attempt to write the arithmetic series 3+8+13+...+43 in summation notation as ΣBn=3(3+5n) is incorrect.

The correct way to write the given arithmetic series in summation notation would be:

Σn=1 to 9 (3 + 5(n-1))

Here's why:

The first term of the series is 3, and the common difference between each pair of consecutive terms is 5. We can use this information to write the general formula for the nth term of the series:

a_n = a_1 + (n-1)d

where a_1 is the first term, d is the common difference, and n is the term number.

Substituting the given values, we get:

a_n = 3 + (n-1)5 = 5n - 2

Now, we need to find the sum of all the terms from the first term (3) to the last term (43). To do this, we can use the formula for the sum of an arithmetic series:

S_n = n/2 * (a_1 + a_n)

Substituting the given values, we get:

S_9 = 9/2 * (3 + 43) = 234

Therefore, the correct way to write the given arithmetic series in summation notation is:

Σn=1 to 9 (3 + 5(n-1))

This expression represents the sum of all the terms in the series from the first term (3) to the ninth term (43).

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Virtual reality has had the most significant impact on de la Pena's journalism career due to its ability to provide a more immersive and engaging news experience and its potential to reach a wider audience.

The question is about the future of news and the impact of virtual reality on de la Pena's journalism career.

In terms of the most significant impact on de la Pena's career, it can be argued that virtual reality has had the most significant impact. This is because virtual reality has revolutionized the way news is presented and consumed.

Virtual reality allows journalists like de la Pena to immerse their audience in a story by providing a more immersive and engaging experience. By using virtual reality, de la Pena has been able to create powerful and impactful stories that allow the audience to experience events and situations firsthand. This has the potential to create a deeper understanding and empathy among viewers.

Furthermore, virtual reality has also expanded the reach of journalism by allowing audiences from different parts of the world to experience stories that they wouldn't have been able to otherwise. This has the potential to foster a more global perspective and increase awareness of important issues.

Overall, virtual reality has had the most significant impact on de la Pena's journalism career due to its ability to provide a more immersive and engaging news experience and its potential to reach a wider audience.

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The given statement "The inverse of a statement p would be written in the form not p" is true.

The inverse of a statement p is written in the form "not p", which is the opposite of p. It is an inversion of the original statement, where all the terms and conditions are reversed. For example, if the original statement is "The sky is blue," then the inverse would be "The sky is not blue."

Therefore, the given statement is True.

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The simplified expression is  [tex]\frac{3\sqrt{3x}}{7x}[/tex].

Given that an expression, 3√(6) / 7 √(2x), we need to simplify it,

So,

√(6) = √2 × √3

√(2x) = √2 × √x

So, we can solve the expression by putting the above simplified terms,

= 3√(6) / 7 √(2x)

= [3 × √2 × √3] / [7 × √2 × √x]

Canceling the common terms,

= 3√3 / 7√x

Rationalizing the denominator,

= [tex]\frac{3\sqrt 3}{7\sqrt{x} } \times \frac{\sqrt{x}}{\sqrt{x}}[/tex]

= [tex]\frac{3\sqrt{3x}}{7x}[/tex]

Hence the simplified expression is  [tex]\frac{3\sqrt{3x}}{7x}[/tex].

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The man's height is approximately 63 inches.

We can solve this problem using trigonometry and the concept of similar triangles. Let's denote the height of the man as h.

From the given information, we have two right triangles: one formed by the man's head, the top of the building, and your position, and the other formed by the man's feet, the top of the building, and your position.

In the first triangle, the angle of elevation to the man's head is 54°. This means that the tangent of the angle is equal to the ratio of the height of the man (h) to the distance between you and the building (45 feet). So we have tan(54°) = h/45.

Similarly, in the second triangle, the angle of elevation to the man's feet is 51°. Again, using the tangent function, we have tan(51°) = (h - x)/45, where x represents the height of the building.

By setting up these two equations, we can solve for h. Rearranging the equations, we get h = 45 * tan(54°) and h - x = 45 * tan(51°).

Substituting the values and performing the calculations, we find that h ≈ 62.99 inches. Rounding to the nearest inch, the man's height is approximately 63 inches.

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The statement "3/4 in. > 5/8 in." is true. To determine the relationship between 3/4 in. and 5/8 in., we can compare their values. In this case, 3/4 in. is greater than 5/8 in.

To compare fractions, we can convert them to a common denominator. The common denominator of 4 and 8 is 8.

Converting 3/4 to an equivalent fraction with a denominator of 8, we multiply the numerator and denominator by 2:

3/4 = (3*2)/(4*2) = 6/8

Now we can compare 6/8 and 5/8. Since the denominators are the same, we only need to compare the numerators. In this case, 6 is greater than 5. Therefore, 3/4 in. is greater than 5/8 in., and the statement "3/4 in. > 5/8 in." is true.

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The solution to the matrix equation X - [-3 2 -1; 6 -7 8] = [-2 3 5; 1 -3 7] is X = [1 1 4; 5 -4 -1].


To solve the matrix equation, we need to isolate the matrix variable X. The equation is given as X - [-3 2 -1; 6 -7 8] = [-2 3 5; 1 -3 7].

To isolate X, we can add [-3 2 -1; 6 -7 8] to both sides of the equation. This yields X = [-2 3 5; 1 -3 7] + [-3 2 -1; 6 -7 8].

Performing the addition, we get X = [-5 5 4; 7 -10 15].

Therefore, the solution to the matrix equation X - [-3 2 -1; 6 -7 8] = [-2 3 5; 1 -3 7] is X = [-5 5 4; 7 -10 15].

(Note: The original question seems to contain a typo, as the given matrices have dimensions of 2x3 and 2x3 respectively, while the equation suggests they should be of the same dimensions. I have provided the answer based on the given matrices, but please verify if the dimensions are correct.)

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When the given lines are executed, the following will be displayed:Error: The line "z combobox.items.add(x y z)" will result in a syntax error.

The first three lines of code define three variables: x, y, and z, all of which are of the data type Double. The variable x is assigned the value 3, and the variable y is assigned the value 1. However, the variable z is declared but not assigned a value.

The line "z = x (y * x)" attempts to assign the result of the expression "x (y * x)" to the variable z. However, there is a syntax error in this line, as it is missing an arithmetic operator between x and (y * x).

After that, the line "x = y" assigns the value of y (which is 1) to the variable x, overwriting the previous value of x.

Finally, the line "z = x" assigns the value of x (which is now 1) to the variable z.

However, the line "z combobox.items.add(x y z)" will result in a syntax error. It seems to be an attempt to add the values of x, y, and z to a ComboBox, but the syntax is incorrect.

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No, 4+i cannot be a zero of the 4th degree polynomial function with zeros at 3 and 5-i.

A polynomial function of degree 4 can have at most 4 distinct zeros. Given that the polynomial has zeros at 3 and 5-i, these are two of the zeros. To determine if 4+i can be a zero, we need to check if it satisfies the polynomial equation.

Let's assume the polynomial function is f(x) and the other two zeros are a and b (not given in the question). Since 4+i is a complex number, its conjugate 4-i must also be a zero if 4+i is a zero of the polynomial. However, the question does not provide the conjugate as a given zero.

Therefore, based on the information given, we cannot confirm that 4+i is a zero of the 4th degree polynomial function with zeros at 3 and 5-i.

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The function y = 2x² + 12x can be rewritten in vertex form as y = 2(x + 3)² - 18, with the vertex at (-3, -18).

To rewrite the function y = 2x² + 12x in vertex form, we complete the square to express it in the form y = a(x - h)² + k, where (h, k) represents the vertex of the parabola.

First, we factor out the common factor of 2 from the quadratic term:
y = 2(x² + 6x)

Next, we add and subtract the square of half the coefficient of x within the parentheses:
y = 2(x² + 6x + 9 - 9)

Then, we rearrange the terms:
y = 2[(x + 3)² - 9]

Finally, we simplify:
y = 2(x + 3)² - 18

Therefore, the function y = 2x² + 12x can be rewritten in vertex form as y = 2(x + 3)² - 18, with the vertex at (-3, -18).

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The expansion of the binomial (1 - 2t)² is:

(1 - 2t)² = 1 - 4t + 4t²

Here, we have,

To expand the binomial (1 - 2t)², we can use the formula for squaring a binomial:

(a - b)² = a² - 2ab + b²

In this case, a = 1 and b = 2t.

Let's substitute the values into the formula:

(1 - 2t)² = (1)² - 2(1)(2t) + (2t)²

Simplifying further:

= 1 - 4t + 4t²

Therefore, the expansion of the binomial (1 - 2t)² is:

(1 - 2t)² = 1 - 4t + 4t²

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