A) The magnitude of the average induced electric field is E = (ΔΦ/rΔt). B) The value in N/C is 105 N/C.
What is magnitude?Magnitude is a measure of the size or strength of a physical quantity such as velocity, force, pressure, or energy. It is usually expressed in terms of a numerical value, either relative to a standard reference level or to some other physical quantity. Magnitude is used in various scientific fields, such as physics, engineering, and astronomy, to quantify properties of physical objects or phenomena. In physics, magnitude is used to compare the size or strength of different forces, such as gravity, electricity, and magnetism.
a) The magnitude of the average induced electric field, E, induced in the loop is given by the equation E = (ΔΦ/rΔt), where ΔΦ is the change in flux, r is the radius of the loop, and Δt is the time interval over which the field changes.
b) To calculate the value of E in N/C, we need to use the given values. Substituting B1 = 0.60 T, B2 = 9.5 T, r = 0.2 m, and Δt = 8 s, we get ΔΦ = 8π x (9.5 - 0.6) = 84.4 Wb. Substituting this in the equation, we get E = (84.4/0.2 x 8) = 105 N/C.
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If a cube that has a length, height, and width of 4 cm is broken down into 8 cubes of equal size, what is the surface area of the 8 new cubes?
Answer: When a cube is divided into smaller cubes of equal size, the length, height, and width of each new cube are one-third of the original cube.
So each new cube will have a length, height, and width of 4/3 cm.
To calculate the surface area of each new cube, we need to find the area of each face and then add them up. Each cube has six faces, so we can calculate the surface area of one cube by multiplying the area of one face by six.
The area of one face of the new cube is (4/3)*(4/3) = 16/9 cm².
So the surface area of one new cube is 6*(16/9) = 96/9 cm² = 10.67 cm² (rounded to two decimal places).
Since we have 8 new cubes, the total surface area is 8 times the surface area of one new cube:
Total surface area = 8 * 10.67 cm² = 85.33 cm² (rounded to two decimal places).
Therefore, the surface area of the 8 new cubes is 85.33 cm².
a mass is vibrating on a string. its frequency describes ( )
Answer:
The frequency of a mass vibrating on a string describes the number of complete cycles of vibration that occur per unit of time, usually measured in hertz (Hz).
Explanation:
if five violins sound the same note of 1000Hz, each at the same sound pressure level of 60 dB, what is their total intensity in decibels, compared with the violin alone?
The total sound pressure level of the five violins is 47 dB, which is 13 dB less than the sound pressure level of a single violin at 60 dB.
What is the total intensity?The total intensity of the five violins can be found by summing their individual intensities. The intensity of a sound wave is proportional to the square of the sound pressure level, so we can use the following equation:
I = I0 * 10^(L/10)
where;
I0 is the reference intensity (for sound at the threshold of hearing, I0 = 1e-12 W/m^2), L is the sound pressure level in decibels, and I is the intensity in W/m^2.Since each violin has a sound pressure level of 60 dB, the intensity of each violin can be calculated as follows:
I_violin = I0 * 10^(60/10) = 1e-12 * 1000 = 1e-9 W/m^2
The total intensity of the five violins can then be found by adding the individual intensities:
I_total = 5 * I_violin = 5 * 1e-9 = 5e-9 W/m^2
To find the sound pressure level corresponding to this total intensity, we can use the inverse of the equation above:
L = 10 * log10(I/I0)
L_total = 10 * log10(I_total/I0)
= 10 * log10(5e-9/1e-12)
= 10 * log10(5e3)
= 47 dB
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What is one direct way in which children impact their own acculturation?
Answer: The direct way that children affect their own acculturation is by peer watching and engagement.
Answer:One direct way in which children impact their own acculturation is through language acquisition. Children who are exposed to a new culture and language at a young age have the opportunity to learn and adopt the new language and cultural norms more easily than adults. As children interact with peers and adults in the new culture and use the new language, they develop their own sense of identity and acculturation, which can be different from that of their parents or other family members. Children may also participate in cultural activities or events, such as holidays or festivals, which further shape their understanding and experience of the new culture. Overall, children can actively participate in and shape their own acculturation process through language acquisition and cultural experiences.
Explanation:
A thin rod with length 4.5 m is sitting with one end at the origin. The rod has a non-uniform density that has a quadratic dependence. You know the density at three points. The density of the rod is 3.0 kg/m at the origin, 11.0 kg/m at the other end of the rod, and 3.0 kg/m halfway in between.
How far from the origin is the center of mass of the rod located?
The density of the rod is 3.0 kg/m at the origin,then the center of mass of the rod is located 2.15 m from the origin.
What is center of mass?The center of mass is the point in an object or system of objects where the mass of the object or system can be considered to be concentrated. In other words, it is the point in which an object or system can be balanced and behaves as if all the mass is concentrated at that point.
Evaluating :To find the center of mass of the rod, we need to integrate the product of the density and position of each infinitesimal element of the rod, divided by the total mass of the rod.
We can express the position of each element as x, where x=0 at the origin and x=4.5 m at the other end of the rod.
Let's start by finding the total mass of the rod. We can divide the rod into two parts: one from the origin to the midpoint, and the other from the midpoint to the other end. The mass of each part can be found by integrating the density over its length:
m₁ = ∫(0 to 2.25) 3x² dx = 15.19 kg
m₂ = ∫(2.25 to 4.5) (22.5x - 45.375) dx
= 95.63 kg
The total mass of the rod is then derived as follows:
m = m₁ + m₂ = 110.82 kg
We can now evaluate the location of the centre of mass. We can express the position of the center of mass as xcm, where x=0 at the origin and x=4.5 m at the other end of the rod.
We can use the formula:
xcm = (1/m) ∫(0 to 4.5) ρ(x) x dx
where (x) represents the density at position x.
We can express the density as a quadratic function of x:
ρ(x) = ax² + bx + c
Using the given values of density at the origin, midpoint, and other end, we can solve for the coefficients a, b, and c:
c = 3
a + b + c = 11/4.5
= 2.44
4a + 2b + c = 3
Solving these equations gives:
a = -1.96 kg/m³
b = 7.33 kg/m²
Now we can plug in the expression for ρ(x) and evaluate the integral:
xcm = (1/m) ∫(0 to 4.5) (-1.96x⁴ + 7.33x³ + 3x) dx
Evaluating this integral gives:
xcm = 2.15 m
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A person can jump a horizontal distance of 1.31 m on the Earth. The acceleration of gravity is 12.3 m/s^2.
a) How far could he jump on the Moon, where the free-fall acceleration is 0.258g Answer in units of m.
b) Repeat for Mars, where the acceleration due to gravity is 0.293g. Answer in units of m.
Answer:
a) On the Moon, where the acceleration due to gravity is 0.258g:
First, we need to find the acceleration due to gravity on the Moon:
g_Moon = 0.258g_Earth
g_Moon = 0.258(12.3 m/s^2)
g_Moon = 3.17 m/s^2
Now we can use the range formula for projectile motion to find the distance he could jump:
R = (v^2/g) sin(2θ)
Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:
R = (v^2/g) sin(^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)
R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)
R = 0.191 m
Therefore, he could jump approximately 0.191 m on the Moon.
!
a) On the Moon, where the acceleration due to gravity is 0.258g:
First, we need to find the acceleration due to gravity on the Moon:
g_Moon = 0.258g_Earth
g_Moon = 0.258(12.3 m/s^2)
g_Moon = 3.17 m/s^2
Now we can use the range formula for projectile motion to find the distance he could jump:
R = (v^2/g) sin(2θ)
Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:
R = (v^2/g) sin(
network error
^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)
R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)
R = 0.191 m
Therefore, he could jump approximately 0.191 m on the Moon.
b) On Mars, where the acceleration due to gravity is 0.293g:
Similarly, we need to find the acceleration due to gravity on Mars:
g_Mars = 0.293g_Earth
g_Mars = 0.293(12.3 m/s^2)
g_Mars = 3.61 m/s^2
Using the same formula and rearrangement as in part a, we can find the distance he could jump on Mars:
R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.61 m/s^2) / (12.3 m/s^2)
R = 0.223 m
Therefore, he could jump approximately 0.223 m on Mars.
Which describes how chemical changes are different from physical changes? (2 points) Group of answer choices Chemical changes can be measured, but physical changes cannot. Chemical changes release energy, but physical changes absorb energy. Chemical changes involve the formation of a new substance. Chemical changes cannot be caused by oxygen.
Answer: Both Chemical and physical changes can be measured, chemical changes can be caused by oxygen since its very reactive. Physical Change: There is no addition or deduction of energy during the physical change, but the energy required for completion of change is released when the change is reversed. Chemical Change: Energy like light, pressure, heat energy is required for chemical changes. When physical or chemical changes occur, they are generally accompanied by a transfer of energy. The law of conservation of energy states that in any physical or chemical process, energy is neither created nor destroyed.
Explanation:
A projectile is shot up vertically with a velocity of 100ms-1 .How long does it take the projectile to reach a height of 375m?
Answer:
Explanation:
The motion of the projectile can be modeled using the following kinematic equation:
h = vi*t + (1/2)at^2
where h is the height of the projectile, vi is the initial velocity, a is the acceleration due to gravity (approximately -9.8 m/s^2), and t is the time elapsed.
We want to find the time it takes for the projectile to reach a height of 375 m, so we can set h = 375 and solve for t:
375 = 100t + (1/2)(-9.8)*t^2
Simplifying and rearranging, we get:
4.9t^2 + 100t - 375 = 0
We can solve this quadratic equation using the quadratic formula:
t = (-b ± sqrt(b^2 - 4ac)) / (2*a)
where a = 4.9, b = 100, and c = -375.
Plugging in the values, we get:
t = (-100 ± sqrt(100^2 - 44.9(-375))) / (2*4.9)
Simplifying, we get:
t = (-100 ± sqrt(10000 + 7350)) / 9.8
t = (-100 ± sqrt(17350)) / 9.8
We take the positive value of t, since we are only interested in the time it takes for the projectile to reach a height of 375 m:
t = (-100 + sqrt(17350)) / 9.8
t ≈ 21.43 seconds (rounded to two decimal places)
Therefore, it takes the projectile approximately 21.43 seconds to reach a height of 375 m.
Discuss all the components that make up the group of electromagnetic and electrical control equipment. Make sure you include the
following items: control relays, contactors, and motor starters. State the commonalities and major differences between these three
categories of control mechanisms. Expand your discussion with the implementation and adaptation of solid-state devices and how they
have changed the industrial and commercial electrical fields. Then make sure you integrate your discussion with comments about NEMA
and IEC-rated components.
Electromagnetic and electrical control equipment is used in a wide range of industrial and commercial applications to control the operation of electric motors, lighting, and other electrical loads.
What are the components of electromagnetic control equipment?Control relays, contactors, and motor starters are key components of electromagnetic and electrical control equipment.
They are used to control the operation of electric motors, lighting, and other electrical loads.
Solid-state devices have become increasingly popular in recent years due to their compact size, faster response times, and lower power consumption. NEMA and IEC establish standards for electrical equipment, and electrical components are often rated according to these standards.
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A yo-yo is released from a stationary hand and spins freely without slipping as the string unwinds. Simultaneously, the yo-yo moves downwards 0.70 m. The radius of the yo-yo is 0.008 m, the mass is 0.05 kg, and the rotational inertia is 3.5 * 10 -5kg*m 2 . a. Calculate the initial gravitational potential energy
The initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy an object has due to its motion. Kinetic energy can be calculated by multiplying the mass of an object with the square of its velocity. Kinetic energy is a form of energy that is associated with the movement of objects. It is released when objects collide or when objects are deformed. Kinetic energy can also be converted into other forms of energy, such as thermal energy, sound energy and electrical energy.
The initial gravitational potential energy of the yo-yo is equal to the change in height multiplied by the weight of the yo-yo. The weight of the yo-yo can be calculated using the equation W = m × g, where m is the mass and g is the acceleration due to gravity. Therefore, the initial gravitational potential energy of the yo-yo is equal to 0.05 kg ×9.8 m/s2 ×0.70 m = 0.343 Joules.
b. Calculate the initial rotational kinetic energy of the yo-yo.
The initial rotational kinetic energy of the yo-yo is equal to ½Iω2, where I is the rotational inertia and ω is the angular velocity. The angular velocity can be calculated using the equation ω = v/r, where v is the linear velocity and r is the radius of the yo-yo. Therefore, the initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.
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If an object continues to accelerate, what happens to its speed?
If an object continues to accelerate, the speed of the object will also increase.
What is acceleration?Acceleration is the amount by which a speed or velocity increases (and so a scalar quantity or a vector quantity).
The relationship between acceleration and speed is direct.
If the speed is increasing, the car has positive acceleration. When the car slows down, the speed decreases. The decreasing speed is called negative acceleration
Therefore, as the object continues accelerating, the speed increases.
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Suppose a newly discovered planet has a mass of 7.0 x1024kg and a radius of 5,600
km. What is the gravitational acceleration, g, on this planet, in m/s²?
Gravitational acceleration on the newly discovered planet is calculated to be approximately 26.7 m/s².
What is gravitational acceleration?The acceleration of an object in free fall within a vacuum is known as gravitational acceleration.
As we know, g = G * M / r²
G is the gravitational constant (6.67 x 10⁻¹¹ N*m²/kg²)
M is the mass of the planet
r is the radius of the planet
Plugging in the given values, we get:
g = (6.67 x 10⁻¹¹ N*m²/kg²) * (7.0 x 10²⁴ kg) / (5600 km)²
g = (6.67 x 10^⁻¹¹ N*m²/kg²) * (7.0 x 10²⁴ kg) / (5600 x 1000 m)²
g ≈ 26.7 m/s²
Therefore, the gravitational acceleration on the newly discovered planet is approximately 26.7 m/s².
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20 points!!! Emergency help required.
Florence is spinning a 770 g weight tied to a string over her head. The string is 0.94 m long, and the weight is moving with a speed of 4.24 m/s. What is the centripetal force pulling the weight inward?
14.7 N
20.6 N
11.0 N
19.7 N
The centripetal force pulling the weight inward is 19.7 N. The closest option to this value is option (D), 19.7 N.
What is Centripetal Force?
Centripetal force is a force that acts on an object moving in a circular path, directing it toward the center of the circle. In other words, it is the force required to keep an object moving in a circular path, rather than flying off in a straight line. The word "centripetal" comes from the Latin words "centrum", which means "center", and "petere", which means "to seek or aim for".
The centripetal force, which is the force acting on an object moving in a circular path, is given by the formula:
F = m * v^2 / r
where F is the centripetal force, m is the mass of the object, v is its velocity, and r is the radius of the circular path.
In this case, the mass of the weight is 770 g, or 0.77 kg, the velocity is 4.24 m/s, and the radius is 0.94 m.
F = (0.77 kg) * (4.24 m/s)^2 / 0.94 m
F = 19.7 N
Therefore, the centripetal force pulling the weight inward is 19.7 N. The closest option to this value is option (D), 19.7 N.V
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Help me out with this one
The new speed of the 5kg cart after the collision is 3.6 m/s to the right.
What is momentum?Product of mass with the velocity of an object is referred to as momentum.
As we know that :m1v1i + m2v2i=m1v1f + m2v2f
m1 and m2 are masses of the carts, v1i and v2i are initial velocities of the carts, and v1f and v2f are final velocities of the carts.
m1v1i + m2v2i = (m1 + m2)vf
(5 kg)(10 m/s) + (8 kg)(0 m/s) = (5 kg + 8 kg)(vf)
50 kgm/s = 13 kgvf
vf = 50 kg*m/s / 13 kg
vf = 3.846 m/s
So the final velocity of the combined carts after the collision is 3.846 m/s to the right.
m1v1i + m2v2i = m1v1f + m2v2f
v1i is the initial velocity of 5kg cart, which is 10 m/s to right, and v2f is final velocity of the 8kg cart, which is 4 m/s to right. We know final velocity of the combined carts is 3.846 m/s to the right,
(5 kg)(10 m/s) + (8 kg)(0 m/s) = (5 kg)(v1f) + (8 kg)(4 m/s)
50 kgm/s = 5 kgv1f + 32 kg*m/s
5 kgv1f = 18 kgm/s
v1f = 3.6 m/s to the right
Therefore, the new speed of the 5kg cart after the collision is 3.6 m/s to the right.
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A car of mass 1 120 kg, moving to the right at a velocity of 25 m-s1, collides with the back of a construction vehicle loaded with cement bags and moving in the same direction at a velocity of 6,25 m-s1. After the collision, the car moves at a velocity of 7,45 m-s1 and the construction vehicle moves at a velocity of 8,45 m-s¹. Both move towards their original directions. Assume that the system is isolated.
1. What is the magnitude of the net external force acting on the system above?
2. Calculate the mass of the construction vehicle if the cement bags have a mass of 100 kg.
3. Use calculations to determine whether the collision is elastic or inelastic.
The magnitude of the next external force acting on the system is 0 N.
The mass of the construction vehicle is 2320 kg.
The collision is inelastic.
Momentum problemThe initial momentum of the system is given by:
Pinitial = m1v1 + m2v2
where m1 and v1 are the mass and velocity of the car, and m2 and v2 are the mass and velocity of the construction vehicle.
Pinitial = (1120 kg)(25 m/s) + (m2)(6.25 m/s)
Pinitial = 28000 kg·m/s + 6.25m2
The final momentum of the system is:
Pfinal = (1120 kg)(7.45 m/s) + (m2)(8.45 m/s)
Pfinal = 8364 kg·m/s + 8.45m2
The change in momentum is:
ΔP = Pfinal - Pinitial
ΔP = 8364 kg·m/s + 8.45m2 - (28000 kg·m/s + 6.25m2)
ΔP = -19636 kg·m/s + 2.2m2
According to the impulse-momentum theorem, the change in momentum is equal to the impulse applied to the system. Since the system is isolated, the net external force acting on the system is zero. Therefore, the magnitude of the net external force is 0 N.
To calculate the mass of the construction vehicle, we can use the conservation of momentum principle. Since the system is isolated, the total momentum before the collision is equal to the total momentum after the collision.
The total momentum before the collision is:
Pinitial = m1v1 + m2v2
Pinitial = (1120 kg)(25 m/s) + (m2)(6.25 m/s)
Pinitial = 28000 kg·m/s + 6.25m2
The total momentum after the collision is:
Pfinal = (1120 kg)(7.45 m/s) + (m2)(8.45 m/s)
Pfinal = 8364 kg·m/s + 8.45m2
Setting these equal, we get:
Pinitial = Pfinal
28000 kg·m/s + 6.25m2 = 8364 kg·m/s + 8.45m2
Solving for m2, we get:
m2 = 2320 kg
To determine whether the collision is elastic or inelastic, we can calculate the coefficient of restitution, which is a measure of the "bounciness" of the collision.
The coefficient of restitution, e, is defined as the ratio of the relative velocity of separation to the relative velocity of approach:
e = (v2f - v1f)/(v1i - v2i)
where v1i and v2i are the initial velocities of the two objects, and v1f and v2f are their final velocities.
In an elastic collision, e = 1, meaning that the objects bounce off each other perfectly. In an inelastic collision, e < 1, meaning that some of the kinetic energy is lost and the objects stick together or deform.
Using the given velocities, we can calculate the coefficient of restitution:
e = (8.45 m/s - 7.45 m/s)/(25 m/s - 6.25 m/s)
e = 0.231
Since the coefficient of restitution is less than 1, the collision is inelastic.
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Brandon pushes a 45-newton plate over his head at a distance of 3 meters. What are
the joules of work being put out?
Pls helpp and fast <3 ty lyall
Answer:
The work done can be calculated using the formula:
work = force × distance × cos(theta)
where force is in newtons, distance is in meters, and theta is the angle between the force and the displacement. Assuming that the force is applied vertically upwards and the displacement is also vertically upwards:
work = 45 N × 3 m × cos(0°)
= 135 J
Therefore, the work being put out by Brandon is 135 joules.
Explanation:
9. If you hold a coin above your head while in a
bus that is not moving, the coin will land at
your feet when you drop it. Where will it land
if the bus is moving in a straight line at con-
stant speed? Explain. (4.9)
If you hold a coin above the head while in a bus that is not moving, the coin will land at the feet when we drop it. This is because, the bus is in motion relative to the Earth.
What is Newton's first law of Motion?Newton's first law of Motion states that an object at rest remains at rest, or an object in motion remains in motion at a constant velocity unless and until acted on by an external force.
When the coin is dropped in the bus, it will land on the feet. Relative to the earth, the bus moves and the person move relative to the earth because the person is inside the bus. However, relative to the bus the person is not moving since they are the inertial frame of reference is on the bus, therefore, the coin will land on the feet.
While the bus is stationary and the coin is placed above the head of any passenger, it will drop on the foot of that person as the neither the bus is moving nor that person.
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A 0.140 kg baseball is pitched toward home plate at 30.0 m/s. The batter hits the ball back (opposite direction) to the pitcher at 44.0 m/s. Assume that towards home plate is positive. If the ball was in contact with the bat for 0.002 seconds, what is the average force the bat exerts on the ball?
−9700 N
−1000 N
−4700 N
−5200 N
The average force the bat exerts on the ball is -5200 N. This can be calculated using the equation F = Δp/Δt, where F is the average force, Δp is the change in momentum (pf-pi), and Δt is the time interval. In this case, Δp = m * (vf - vi) = 0.14 kg * (44 m/s - 30 m/s) = 5.4 kgm/s, and Δt = 0.002 s. Thus, F = 5.4 kgm/s / 0.002 s = -5200 N.
Suppose a small comet was on a path to collide with Earth. Its density is 0.5 g/cm3 (500 kg/m3 ). Earth’s radius is 6378 km and Earth’s density is about 5500 kg/m3 (5.5 g/cm3 ). At what height would it disintegrate? (3) Hint: the Roche limit = 2.5 [(density of planet)/(density of moon or other object)]1/3 (radius of planet)
The comet will disintegrate at a height of 70,479,900 m.
Comet's height problemTo find the height at which the comet would disintegrate, we need to determine Earth's Roche limit with respect to the comet.
Roche limit = 2.5 [(density of planet)/(density of moon or other object)]^(1/3) (radius of planet)
Let's assume that the moon has a similar density to the comet, so we can use the Roche limit formula with the following values:
density of planet = 5500 kg/m^3
density of moon or other object = 500 kg/m^3
radius of planet = 6378 km = 6,378,000 m
Roche limit = 2.5 [(5500 kg/m^3)/(500 kg/m^3)]^(1/3) (6,378,000 m)
Roche limit = 76,857,900 m
This means that any object that comes closer to Earth than 76,857,900 m would be torn apart by tidal forces.
Therefore, the comet would disintegrate at a height of 76,857,900 m - 6,378,000 m = 70,479,900 m above Earth's surface.
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The diameter of the asteroid Vesta is of the diameter of the planet Mercury. Mercury has a diameter of 5000 km. Calculate the diameter of Vesta. Show your working.
Answer:
5000 km
Explanation:
Sure, to calculate the diameter of Vesta, we can use the fact that Vesta's diameter is equal to the diameter of Mercury, which is 5000 km.
Therefore, the diameter of Vesta is also 5000 km.
We can show the working by using the following formula:
Diameter of Vesta = Diameter of Mercury
Diameter of Vesta = 5000 km
All elements that found in group or column 12 they have _______________ electrons in last shell
Please help (50 points and Brainly)
The speed of the basketball is 14.4 m/s if its kinetic energy is 109 J.
What is kinetic energy?Kinetic energy is the energy possessed by an object due to its motion. It is defined as the energy that an object has because of its velocity, and it depends on the mass of the object and its speed. The formula for kinetic energy is [tex]K = 1/2 mv^2,[/tex] where K is kinetic energy, m is the mass of the object, and v is its velocity.
The greater the mass and velocity of an object, the more kinetic energy it has. Kinetic energy is a scalar quantity, meaning that it only has magnitude and no direction. It is an important concept in physics and has many practical applications, such as in sports, transportation, and industrial machinery.
The kinetic energy (K) of an object with mass m and speed v is given by:
[tex]K = 1/2 * m * v^2[/tex]
Rearranging this equation, we can solve for v:
[tex]v = sqrt(2K/m)[/tex]
Plugging in the values given in the problem, we get:
[tex]v = sqrt(2*109 J / 0.145 kg) = 14.4 m/s[/tex]
Therefore, the speed of the basketball is 14.4 m/s if its kinetic energy is 109 J.
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What is the effect of applying wax on the floor? Can you walk better on a shiny floor with barefoot?
Answer:
Yes
Explanation:
Floor wax will provide enough grip on the floor to allow people to walk without slipping, even when the floor is wet. In conclusion, A layer of wax will give your workplace more beauty and brightness. It will add sparkle to your home or business and a clean look that will impress the visitor
Answer:
Applying wax on a floor can have several effects, including:
Protection: Wax can protect the surface of the floor from scratches, stains, and other forms of damage.
Shine: Wax can give the floor a shiny, polished look that can enhance its appearance.
Slip-resistance: Some types of wax can improve the slip-resistance of a floor by creating a slightly textured surface.
However, whether or not you can walk better on a shiny floor with barefoot depends on a few factors. If the floor is very smooth and the wax is very slick, it may be more difficult to walk on the surface, especially if your feet are wet or sweaty. On the other hand, if the wax creates a slightly textured surface, it may provide better traction and make it easier to walk on the floor. Additionally, some people may prefer the feeling of walking on a smooth, polished floor, while others may find it uncomfortable or unpleasant. Ultimately, the effect of applying wax on the floor will depend on the type of wax used, the condition of the floor, and the personal preferences of the individual walking on the surface.
Explanation:
The _________________ the two objects are, the____________ gravitational force they have.
The farther apart the two objects are, the weaker gravitational force they have. Conversely, the closer the objects are, the stronger the gravitational force between them.
What is gravitational force?
Gravitational force is the force of attraction between two objects due to their masses. The greater the mass of the objects, the greater the gravitational force between them. Similarly, thethe closer the objects are to each other, the greater the gravitational force between them. This means that if the distance between two objects is doubled, the gravitational force between them is reduced to one-fourth of its original value.To know more about gravitational force, click the link given below:
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Which weighs more, a liter of ice or a liter of water?
Answer:
Water is denser so a liter of water weighs more than a liter of ice
URGENT HELP NEEDED!!!
Two balls are rolling in the positive x-direction. Ball A has a mass of 1 kg, and rolls with velocity vA=4 m/s. Ball B has a mass of 2 kg, and rolls with velocity vB=3 m/s. If those balls were to collide, which of the following outcomes would conserve momentum?
vA=6 m/s, vB=2 m/s
vA=3 m/s, vB=4 m/s
vA=3.5 m/s, vB=3.5 m/s
vA=−2 m/s, vB=6 m/s
vA=10 m/s, vB=0 m/s
vA=−4 m/s, vB=−3 m/s
Answer:
Let's check each option to see if it conserves momentum:
Option 1: p_after = 1 kg * 6 m/s + 2 kg * 2 m/s = 10 kg m/s (conserves momentum)
Option 2: p_after = 1 kg * 3 m/s + 2 kg * 4 m/s = 11 kg m/s (doesn't conserve momentum)
Option 3: p_after = 1 kg * 3.5 m/s + 2 kg * 3.5 m/s = 10.5 kg m/s (doesn't conserve momentum)
Option 4: p_after = 1 kg * (-2 m/s) + 2 kg * 6 m/s = 10 kg m/s (conserves momentum)
Option 5: p_after = 1 kg * 10 m/s + 2 kg * 0 m/s = 10 kg m/s (conserves momentum)
Option 6: p_after = 1 kg * (-4 m/s) + 2 kg * (-3 m/s) = -10 kg m/s (doesn't conserve momentum)
Therefore, options 1, 4, and 5 conserve momentum.
Explanation:
As we've discussed, one model of material deformation links stress and strain by a material constant called a modulus. For a material under lengthwise stress (tension or compression), this is Young’s modulus (Y) and the relation may be stated as:
The data below was collected for five different materials using tools which allowed for the direct measurement of the stress and strain. By applying the model above, rank the Young’s modulus for each of these five materials from largest to smallest.
Young’s modulus for each of these five materials from largest to smallest are mentioned below.
What is Young’s modulus?
Many substances lack linearity and elasticity after very minor deformation. Only materials that are linearly elastic are subject to the constant Young's modulus. In this case, the ratio of stress to strain, which corresponds to the material's stress, determines the Young's modulus.
What is data?
Facts such as numbers, words, measurements, observations, or even simple descriptions of objects are grouped together as data. Both qualitative and quantitative data are possible. Qualitative data is information that is descriptive (describes something), whereas discrete data can only take particular values (like whole numbers).
Therefore, Young’s modulus for each of these five materials from largest to smallest are mentioned above.
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How can a hockey puck explain the transfer of kinetic energy? **Select all that apply.**
A. Kinetic energy transfers through air when materials are close.
B. Kinetic energy is lost when it transfers between materials.
C. Energy transfers from materials through touch.
D. Kinetic energy can move from one item to another.
calculate the distance covered by you if you travel at the speed of 5 meter per second for 3 minutes
Answer: 900 m
Explanation: If you walk at a speed of 5 meters per second for 3 minutes, or 180 seconds, then you will have walked 900 meters. This can be seen in the equation [tex]x=x_{0}+v_{x0}t+\frac{1}{2} a_{x}t^2[/tex]. As the velocity is constant (no acceleration) and the initial position is zero, plugging in known values for v and t, you can solve for x of 900 m.
an electric kettle takes 2kw at 240v. Calculate the current and the resistance of the heating element
The power output is given 2000 watt and voltage is 240 v. Then the current through the heating element is 8.3 A and the resistance is 29 ohms.
What is power ?The power used by an object is the rate of its work done or energy. It is the energy divided by time. The power output in a circuit is the product of the potential difference V and current I.
P = I V
Given,
P = 2 kw = 2000 W
v = 240 V.
Then I = P/v
I = 2000 w/240 v = 8.3 A.
According to Ohm's law, voltage v is the product of the current and resistance through the material.
hence,
V = I R
then, R = V/I
R = 240 V/8.33 A
= 29 Ω.
Therefore, the current and resistance through the heating element are 8.3 A and 29 ohms respectively.
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