Answer:
Explanation:
Given:
t = (1/3) min = (60/3) s = 20 s
V = 300 m
_______________________
D - ?
Distance:
D = V·t
D = 300·20 = 6 000 m
the salad is chemichal or physical change
Answer:Physical
Explanation:
Answer:
physical change
Explanation:
Making a fruit salad, with raw fruits is considered as physical change because in this process chemical composition of fruits is not changed. It is simply changing the shape of the substance.
Major activity injuries include
Bone breaks
Concussions
Joint Dislocations
All of the above
Explanation:
Major activity injuries include:
Bone breaksConcussionsJoint DislocationsAll of the aboveAnsver:
All of the above
A 2.5 newton weight falls freely from rest from the roof of a building. What is the total distance the weight falls in the first 4.0 seconds?
Answer:
Explanation:
L = g·t² / 2 = 9.8·4.0² / 2 = 78.4 m
if the blocks are released from rest, which way does the 10 kgkg block slide, and what is its acceleration? enter a positive value if 10 kgkg block accelerates up the ramp, and a negative value otherwise.
The acceleration is -0.48m/s².
Explain what an acceleration is.Acceleration is the rate of change in both speed and direction of velocity over time. Anything is said to have been accelerated when it goes faster or slower in a straight line.
Suppose that θ=35°
First, you need to set up equations for both blocks.
Let m₁ be 10kg and m₂ be 5kg and for our computations suppose right is positive and up is positive
For m₁ the solution is:
Sigma Fx = ma
T - m₁gsin35 = m₁a
where T = tension
For m₂
m₂g - T = m₂a
Add the two equations together
m₁a + m₂a = T-m₁gsin35 + m₂g - T
a(m₁ + m₂) = m₂g - m₁gsin35
a= (5×9.8 - 10×9.8×sin35)/(10 + 5)
a= -0.48m/s².
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calculate the height (in m) of a cliff if it takes 2.21 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.01 m/s. (enter a number.) (b) how long (in s) would it take to reach the ground if it is thrown straight down with the same speed? (enter a number.)
The height of the cliff is 6.22 meters and the time taken by the rock to hit the ground if thrown with same speed is 0.81 seconds.
The time taken by the rock to hit the ground when it is thrown up from the the cliff with an initial velocity of 8.01 m/s.
(a) From the equation of motion,
H = ut+1/2at²
H is the height of the cliff,
u is the the initial velocity,
t is the time taken by the rock,
g is the acceleration due to gravity.
Putting values,
H = (8.01)(2.21) + 1/2(-9.8)(2.21)²
H = -6.22m.
The height of the cliff is 6.22 m.
(b) If the rock is thrown down with the same speed,
Then the time taken by it to reach the ground is,
t = u/g
Putting values,
t = 8.01/9.8
t = 0.81 seconds.
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how many high voltage cables supply electrical power to the hv components at the front of the vehicle?
Option B. Can be charged to full capacity by using a special dealer-only high-voltage charger.
Voltage is the strain from an electrical circuit's energy source that pushes charged electrons (modern-day) through and engages in the loop, allowing them to do paintings inclusive of illuminating light. In quick, voltage = strain, and it's far measured in volts (V).
Voltage, also called an electric-powered strain, electric-powered anxiety, or ability distinction is the difference in electric-powered capacity between two factors. In a static electric field, it corresponds to the work needed in step with a unit of charge to move a take a look at the rate among the 2 points.
Voltage, also called electromotive force, is absolutely electricity consistent with unit fee. In different phrases, voltage is the difference in electric-powered capacity among factors. contemporary is just the rate of drift of electrical fee.
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Disclaimer:- your question is incomplete, please see below for the complete question.
how many high-voltage cables supply electrical power to the hv components at the front of the vehicle?
A. Using the ICE to turn the motor/generator to fully charge the HV battery
B. Can be charged to full capacity by using a special dealer-only high-voltage charger
C. Operating the ICE at idle after returning from a trip
if the ball is traveling at 140 km/h just before it reaches the bat, what is the magnitude of the average force exerted by the bat on it if the collision lasts 7.0 ms ?
To find the collision rate, known the magnitude.
What is magnitude?
Magnitude typically refers to size or distance. By comparing the size and motion speed of the thing, we can relate magnitude to movement. The object's or quantity's size determines its magnitude.
What is mean by collision rate?
The frequency of collisions between a single particle of radius m and particles with masses ranging from (m1, m1 + m1) to (m, m1) is proportional to their concentration, n(m1) m1, where (m, m1) is the rate constant for collisions between the two particles of masses m and m1 and depends on the process.
u=140kmph
t=7.oms
v=0
E=M(V-U)/t
⇒m(0-140)/0.007×5/18m/s
⇒5555.55 (m) N
E=(5555.55) (mass) N
Therefore, the collision lasts is 5555.55(m) N.
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A 1,286-kg car is skidding to a stop along a horizontal surface. The car decelerates from 26.9 m/s to rest in 9.36 seconds. How far did the car skid before coming to rest?
Answer:
Explanation:
Given:
M = 1 260 kg
V₀ = 26.9 m/s
V = 0 m/s
Δt = 9.36 s
___________
L - ?
1)
Vehicle acceleration:
a = (V - V₀) / Δt ) = (0 - 26.9) / 9.36 ≈ - 2.87 m/s²
2)
Braking distance of the car:
L = (V² - V₀²) / (2·a)
L = ( 0² - 26.9²) / (2·(-2.87)) ≈ 121 m
cords of connective tissue that connect MUSCLES TO BONES
Answer:
Tendon
Explanation:
Tendons are a type of connective tissue that attach muscle to bone. Hope this helps! :)
a mass m at the end of a massless rod of length l swings as a pendulum with two horizontal springs for negligible mass and spring constants k1 and k2 acting on it. both springs are relaxed when the rod is vertical. what is the period of small oscillations? [from feynman exercises in physics]
The answer is T = 2π/ω
Further complete solution is in png format.
In addition to being insanely adorable, the Klipspringer is known to jump 3.6 meters straight up in the air (that is several times their body height). What is the initial upward velocity required to make this happen?
Answer:
Explanation:
Given:
H = 3.6 m
V = 0 m/s
g = 9.8 m/s²
_________
V₀ - ?
Potential energy = m·g·H
Kinetic energy = m·V₀² / 2
Let's equate:
m·V₀² / 2 = m·g·H
V₀² / 2 = g·H
Starting speed:
V₀ = √ ( 2·g·H )
V₀ = √ (2·9.8·3.6) ≈ 8.4 m/s
a crane lowers a metal beam into place at constant speed. which is true about the work done by the gravitational force (wg) and the work done by the tension in the cable (wt) as the beam is lowered? a) wg>0 and wt>0 b) wg>0 and wt<0 c) wg<0 and wt>0 d) wg<0 and wt<0 e) wg
The work done by gravitational force and tension in the cable is wg > 0 and wt <0. option 2 is correct.
The work done by the force is given as :
W = Fdcosθ
where
F= force
d = displacement
θ = angle between directions of F and d
when force and displacement are parallel then :
θ = 0
cosθ = ±1
so work done is positive
when force and displacement are anti-parallel then :
θ = 180°
cosθ = -1
so work done is negative.
then crane is moving downward. the force is also downward and tension is upward.
The work done by gravitational force and tension in the cable is wg > 0 and wt <0. option 2 is correct.
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A 100.0 g arrow is pulled back 30.0 cm against a bowstring. The bowstring's spring constant is
1250 N/m. What speed will the arrow have when it leaves the bowstring if the arrow is shot horizontally?
Velocity of the arrow while leaving the bow is 33.54 m/s.
What is kinetic energy?Kinetic energy is the energy that an object has when it is in motion. If you want to accelerate an object you have to apply a force. To add strength, we need our work. When the work is done, the energy is transferred to the object and it moves at a new constant speed.
Energy stored in the string = Kinetic energy of the arrow.
1/2(ke²) = 1/2(mv²)
Where k = spring constant of the bowstring
e = extension
m = mass of the arrow
v = velocity of the arrow.
Let's make v the subject of this equation
v = √(ke²/m)
Given: k = 1250 N/m
e = 30 cm or 0.3 m
m = 100 g or 0.1 kg
Substitute the values into the equation:
v = √(1250×0.30²/0.1)
v = √(1125)
v = 33.54 m/s
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which statements are true, concerning jupiter as compared to the other planets in our solar system? (may be more than one correct answer)
Out of all the planets, Jupiter has the most mass. Of all the planets, Jupiter has the strongest magnetic field. Of all the planets, Jupiter rotates the most quickly.
Jupiter rotates most quickly where?With a rotational velocity of 28,273 miles per hour (or 43,000 kilometers per hour), Jupiter's equator rotates a little more quickly than its polar regions. Jupiter's day ranges from 9 hours, 56 minutes near the poles to 9 hours, 50 minutes towards the equator. As the largest planet, Jupiter has the gravitational ability to draw in the most mass as it travels through space, making it the planet with the quickest rotation. Jupiter acquires the angular momentum of whatever mass it comes into contact with, including gas, dust, and rock, in addition to the mass itself. One rotation of Jupiter, for instance, takes 9 hours and 55 minutes, although it rotates at a speed that is 27 times quicker than Earth's at its equator.
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A block of mass m1 = 14.4 kg is on a frictionless table to the left of a second block of mass m2 = 20.2 kg, attached by a horizontal string (see the figure below).
(a) If a horizontal force of 1.53 ✕ 102 N is exerted on the block m2 in the positive x-direction, use the system approach to find the acceleration (in m/s2) of the two blocks.
(b) What is the tension (in N) in the string connecting the blocks?
(a) The acceleration (in m/s²) of the two blocks is 4.42 m/s².
(b) The tension (in N) in the string connecting the blocks is 63.65 N.
What is the acceleration of the blocks?
The acceleration of the blocks is determined by applying Newton's second law of motion as shown below.
F(net) = ma
where;
F(net) is the net force on the blocksm is the mass of the blocksa is the acceleration of the blocksF = m₁a + m₂a
F = a(m₁ + m₂)
a = F/(m₁ + m₂)
where;
a is the common acceleration of the blocksm₁ is the mass of the first block = 14.4 kgm₂ is the mass of the second block = 20.2 kgF is the applied force on the blocks = 153 Na = (153) / (14.4 + 20.2)
a = 4.42 m/s²
The tension (in N) in the string connecting the blocks is calculated as follows;
T = m₁a
T = 14.4 x 4.42
T = 63.65 N
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an astronaut weighs 99 n on the moon, where the acceleration of gravity is 1.62 m/s2. how much does she weigh on earth? group of answer choices 600 n 440 n 61 n 16 n 99 n
On the moon, where gravity accelerates at 1.62 m/s2, an astronaut weighs 99 n, but their weight on Earth is 600 Newton(option a is correct).
Work done = Mass * Acceleration due to gravity
99=m*1.62
m=61.11kg
W=mg 61.11*9.8=598.89N = 600N= Weight on Earth
The acceleration of an item refers to the pace at which its velocity with respect to time varies. The number of accelerations in a vector (in that they have magnitude and direction). An object's acceleration in respect to a net force is determined by the direction of that force. Newton's Second Law states that the combined effects of two elements determine how much an item accelerates:
The amount of this net resultant force is exactly proportional to the size of the net balance of all external forces operating on that item. Depending on the materials used in construction, mass and mass are inversely connected.
Acceleration is measured in meters per second squared (m/s2).
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you pull a box with a constant force of 250 n. the box moves 10 m along a straight path on a rough surface at a constant speed. how much thermal energy is generated in the system of the box and the rough surface?
The thermal energy of the box which is pulled with a force of 250 N to a distance of 10 meters is 2500 J
The force to pull the box = 250 N
The box is moved to a distance of 10 meters
The thermal energy can be found using the formula,
W = F x d
where W is the thermal energy
F is the Force
d is the distance moved
Let us substitute the known values in the above equation, we get
W = 250 x 10
= 2500 J
Therefore, the thermal energy of the box is 2500 J
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One force that acts on a surfer is friction. Another is gravity. Which of these is a non-contact force?
Answer: gravity
Explanation:
Friction requires 2 surfaces in contact with each other. Gravity is a non-contact, universal force.
at what wavelength of light to humans give off the most light if the average human body temperature is approximately 310 k?
Peak thermal radiation for the human body at 310 K has a wavelength of 9.3 mm.
The average body temperature is 310.15 oK. The infrared region is where the radiation peaks as a result. Red light with wavelengths as long as 7,000 Angstroms can be seen by the human eye. Generally speaking, infrared wavelengths are those between 7,000 and 1,000,000 Angstroms.
Light's wavelength is used to measure it (in nanometers). It is typically represented by the Greek letter. Visible light is typically defined as having a wavelength between 400 and 700 nanometers (nm), or one billionth of a meter.
The distance between equivalent places in two consecutive light cycles is known as the wavelength of light, and the frequency of light is the number of light cycles that pass a specific spot in a second.
Atoms or molecules that undergo discrete energy level transitions give rise to narrowband radiation.
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in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's intensity for an outer planet located at a distance 6 r from the sun?
The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.
What is the Inverse Square Law formula?The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as
[tex]\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}[/tex]
Where
I₁ = Intensity at distance 1 (W/m²)I₂ = Intensity at distance 2 (W/m²)d₁ = distance 1 from a light source (m)d₂ = distance 2 from a light source (m)Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?
By using the inverse square law formula, the sun's intensity for an outer planet is
[tex]\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}[/tex]
[tex]\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}[/tex]
[tex]\frac{200 }{I_{2} } = \frac{36r^{2} }{r^{2}}[/tex]
[tex]I_{2} = \frac{200} {36}[/tex]
I₂ = 5.55 W/m²
Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².
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true or false: if an elevated feature near the heel or flanks or a position upwind of the fire affords a good sight line, take advantage of it as long as there is zero possibility that the fire will go there.
An elevated feature near the heel or flanks or a position upwind of the fire affords a good sight line and there is advantage of it as long as there is zero possibility that the fire will go there, which is true statement.
Elevated feature helps to protect the space besides there is a fire present. Elevated feature is the safest and nearest place to not get effected by the fire present in the other side of the elevated feature.
This feature is also created in case of emergency situations to immediately reduce the effect of the fire. This could a technique to reduce the effect of the hazards in the disaster management.
While considering the effect of hazards reduction, there are parameters on which these depends, are shape of elevated feature, elevation of the elevated feature and steepness of the elevated feature.
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An object i aid to be poitively charged if it number of electron i greater than the number of proton
An object I aid to be positively charged if it has a number of electrons i greater than the number of protons. TRUE
If an object has extra protons than electrons, then the internet fee on the item is fantastic. If there are extra electrons than protons, then the net charge at the item is bad. If there are equal numbers of protons and electrons, then the object is electrically impartial.
An electrical price is created while electrons are transferred to or removed from an object. because electrons have a bad charge, while they are added to an item, it turns negatively charged. when electrons are removed from an object, it will become undoubtedly charged.
A positively charged object has misplaced electrons. A definitely charged object has won protons. A negatively charged item has lost protons. If the variety of electrons is greater than the range of protons, the particle is a negative ion, also referred to as an anion.
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An object I aid to be positively charged if it has a number of electrons i greater than the number of a proton. TRUE/FALSE
a 1571-kg submarine rises straight up toward the surface. seawater exerts both an upward buoyant force of 14,848 n on the submarine and a downward resistive force of 947 n. what is the submarine's acceleration?
the submarine's acceleration is 0.95 m/sec²
Total force on submarine = 14848 - (1571 * 9.8 + 947)
= -1494.8 N
=> submarine's acceleration = F/m
= 1494.8/1571
= 0.95 m/sec²
acceleration is the rate of change in both speed and direction of velocity over time. When something moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is constantly shifting, motion on a circle accelerates even when the speed is constant. Both effects add to the acceleration for all other types of motion.
It is a vector quantity because acceleration has both a magnitude and a direction. Another vector quantity is velocity. The velocity vector change over a given period of time, divided by that period of time, is the definition of acceleration. The upper limit of the ratio of velocity change provides instantaneous acceleration (at a specific time and place).
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(a) how many minutes does it take a photon to travel from the sun to the earth? (b) what is the energy in ev of a photon with a wavelength of 558 nm? (c) what is color of light with this wavelength? (d) what is wavelength of a photon with an energy of 1.00 ev? please show the solution.
To known about all the answers, we first known about the photon and wavelength concept.
What is a photon?
A tiny energy packet of electromagnetic radiation is called a photon, referred to as a light quantum. Albert Einstein proposed the existence of discrete energy packets during the transmission of light in his 1905 description of the photoelectric effect, which gave rise to the photon concept.
What is wavelength?
A waveform signal's wavelength is the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or along a wire. This length in wireless systems is typically specified in meters (m), centimeters (cm), or millimeters (mm).
a) Distance between the earth and the sun is
1.5*10^N
Speed of photon = 3*10^8m|s
Time= distance/speed
= 1.5*10^11m/3*10^8m|s
= 0.5*10^3 second
= 500 sec
= 8.3 minutes.
b) energy of the photon is given by
E=hc/⋋
h= planks constant – 4.14* 10^15 eVs
c= Speed of light- 3*10^8 m/s
⋋= 558 nm= 558* 10^9 m
E= 4.14* 10^15 eVs* 3*10^8 m/s /558* 10^9 m
E= 2.23 eV
c) Wavelength color
495–570 nm for green. 570–590 nm for yellow. Orange (590–620 nm). Red: 620-750 nm
d) Let the wavelength be ⋋
We know E=hc/⋋
1 eV= 4.14*10^-15 eVs* 3*10^8m/s/⋋
⋋ = 12.42*10^-7m
⋋ = 1242 nm.
Therefore, Distance between the earth and the sun is 8.3 minutes. Energy of the photon is given by 2.23 eV. Wavelength color is green or yellow. The wavelength be ⋋ is 1242 nm.
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Calculate the initial velocity of a ball thrown vertically into the air reaching a maximum
height of 20 m. (Don't forget: at maximum height the final velocity is zero and the
acceleration is -10 m/s²)
The initial velocity of the ball thrown vertically into the air reaching a maximum height is 20 m/s.
What is velocity?
Velocity can be defined as the ratio of displacement to time.
To calculate the initial velocity of the ball, we use the formula below.
Formula:
v² = u²+2gh............... Equation 1Where:
v = Final velocityu = Initial velocityg = Acceleration due to gravityh = HeightFrom the question,
Given:
v = 0 m/sg = -10 m/s²h = 20 mSubstitute these values into equation 1
0² = u²+[2×20×(-10)]-u² = -400u² = 400u = √400u = 20 m/sHence, the initial velocity of the ball is 20 m/s.
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what is the magnitude of its angular velocity, in radians per second, after a 23 kg child gets onto it by grabbing its outer edge? the child is initially at rest.
The magnitude of the angular velocity of the merry-go-round is equal to 2.39 rad/s after a 23 kg child gets onto it.
What is angular momentum?Angular momentum can be described as the rotational form of linear momentum. It is a physical conserved quantity as the total angular momentum remains constant.
Given, the mass of the child m = 23 Kg
The mass of the merry-go-round M = 125 Kg
The initial speed of the merry-go-round, ω₁ = 0.52 rev/s = 3.27 rad/s
The radius, r = 1.8 m
From the conservation of the angular momentum, we can find the angular velocity:
[tex]I_1\omega_1= (I_1+mr^2)\omega[/tex]
[tex](\frac{1}{2} Mr^2)\omega_1= (\frac{1}{2} Mr^2+mr^2)\omega[/tex]
[tex]\omega =\frac{M.\omega_1}{M+2m}[/tex]
[tex]\omega = \frac{125\times 3.27}{125 +2\times23}[/tex]
ω = 2.39 rad/s
Therefore, the magnitude of its angular velocity after a 23 kg child gets onto it by grabbing its outer edge is 2.39 rad/s.
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Your question was incomplete, but the most probably complete question was,
A playground merry-go-round with a mass of 125 Kg and a radius of 1.8 m is rotating with a frequency of 0.52 rev/s. what is the magnitude of its angular velocity, in radians per second, after a 23 kg child gets onto it by grabbing its outer edge? the child is initially at rest.
Describe the motion of a hockey puck between the instant the puck leaves a player's stick and the instant it hits something. (No "slap shot" allowed, the puck must remain in contact with the ice.)
Answer:
Explanation:
it will have constant friction, or slowing, as it slides along the ice.
a bus traveled 387 km in 5 h.one hour of the trip was in city traffic. the bus's city speed was just half of its speed on open highway. the rest of the trip was on open highway. find the bus'scity speed
The bus'scity speed is 77.4km/hr.
How is speed defined in?What constitutes speed? the speed of a change in an object's position in any direction.
Speed is the rate of change in location of an item, expressed in meters per second. If something starts at the origin and goes three meters in three seconds, for instance, its speed is one meter per second. Like distance divided by time, the equation for speed is straightforward.
A change in an object's position over time is referred to as motion in physics. Displacement, distance, velocity, acceleration, time, and speed all play a role in how motion is defined. Speed is a scalar variable that describes how quickly an object travels through space with regard to time.
speed = distance/time
speed =387/5
speed =77.4km/hr.
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an automobile of mass 1500kg moving at 25.0m/s collides with a truck of mass 4500kg at rest. this time, the car and the truck bounce off each other completely elastically. what is the final velocity of the car (in m/s) after the collision? call the initial direction of the automobile positive.
the final velocity of the car (in m/s) after the collision is 6.25 m/s
12.5 m/s is moving in the initial direction of the car
1. A car of mass 1500 kg moving at a speed of 25.0 m/s collides with a truck of mass 4500 kg at rest. the bumpers of both vehicles lock on impact.
A. Compare the force exerted by the car on the truck with the force exerted by the truck on the car during the collision. Is one force greater than the other, or are they equal in magnitude?
the force exerted by the car on the truck and the force exerted by the truck in the collision.
creates a pair of actions and reactions
are equal in magnitude and opposite in direction according to Newton's third law
b. What is the final speed of the car and the truck just after the collision? show your calculations.
v=m1u1+m2u2/m1+m2=1500*25+0/1500+4500=6.25 m/s
2. the same collision as in the above question occurs, but this time the car and truck bounce off each other completely elastically.
C. Compare the force exerted by the car on the truck with the force exerted by the truck on the car in the collision. is one force greater than the other or are they equal?
the force exerted by the car on the truck and the force exerted by the truck in the collision.
creates a pair of actions and reactions
are equal in magnitude and opposite in direction according to Newton's third law
d. what is the final speed of the car and truck just after the collision?
view the calculation
v1=[m1-m2/m1+m2]u1+[2m2/m1+m2]u2=[1500-4500/6000]*25+[9000/6000]*0=-12.5 m/s
a negative sign means the car is moving backwards at 12.5 m/s
v2=[m2-m1/m1+m2]u2+[2m1/m1+m2]u1=[4500-1500/6000]*0+[3000/6000]25=12.5 m/s
moves in the original direction of the car
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A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?
The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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