Answer:
Correct answer is option C
70.0 g HNO3 and 30.0 g water
The following reaction: HF(aq) <--> H+(aq) + F-(aq) has an equilbirum constant (K) value of 7.2 x 10-4. This means that the reaction proceeds essentially to completion.
Group of answer choices
True
False
Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.
What is the equilibrium constant?In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.
On the other hand, when we have a case that the equilibrium constant is small and is not so large, then the reaction does not proceed essentially to completion.
Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.
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State whether the following liquids are miscible with water (H2O) by entering "yes" or "no".
1) Benzene, C6H6
2) Methanol, CH3OH
3) Chloroform, CHCl3
What would you need to do to calculate the molality of 0.2 kg of NaCl in 3 kg
of water?
A. Convert the 3 kg of water to moles of water.
B. Convert the 3 kg of water to liters of water.
C. Convert the 0.2 kg of NaCl to grams of NaCl.
D. Convert the 0.2 kg of NaCl to moles of NaCl
Answer:
D. Convert the 0.2 kg of NaCl to moles of NaCl
Explanation:
The molality equation looks like this:
Molality = moles of solute / mass (kg) of solvent
In this case, the solute is NaCl and the solution is water. So, if you have been given NaCl in kg, you need to convert it to grams and then to moles in order to plug it into the equation.
What is a catalyst?
Group of answer choices
A. A substance that speeds up the reaction by increasing the activiation energy.
B. A substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.
C. A substance that slows down the reaction by lowering the activation energy.
D. A substance added to the reaction that raises the activation energy by providing an alternate pathway for the reactions to go to completion.
A catalyst is a substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.
A catalyst is a substance that accelerates a chemical response, or lowers the temperature or strain needed to begin one, with out itself being ate up at some stage in the response. Catalysis is the procedure of adding a catalyst to facilitate a response.
Catalysts may be categorized as homogeneous, heterogeneous, or enzymatic. Homogeneous catalysts exist inside the identical phase as the reactants, whereas heterogeneous catalysts exist in a exclusive section than the reactants.
Catalysts are basically categorised into 4 kinds.Homogeneous, Heterogeneous, Heterogenized homogeneous catalyst and Biocatalysts. Homogeneous catalyst: In homogeneous catalysis, reaction mixture and catalyst both are gift inside the equal segment.
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round off each of the following numbers to two significant figure 0.436 and 9.000
Answer:
0.436 ⇒ 0.44
9.000 ⇒ 9.0
Concept:
Significant figures are where each of the digits of a number are used to express it to the required degree of accuracy, starting from the first nonzero digit.
Therefore, in the context of this question, two significant figure means that two digits of numbers are kept, from left to right, starting from the first nonzero digit.
Solve:
PART I: Rounding 0.4360.436 has 3 significant digits in total starting from left to right
Thus, the last digit should be rounded up / down
Since the last digit is 6, it is greater than 5, so it should be rounded up.
Therefore, a rounded 0.436 is [tex]\Large\boxed{0.44}[/tex]
PART II: Rounding 9.0009.000 has 4 significant digits in total starting from left to right
Thus, the last two digits should be rounded up / down
Since the last two digits are 0, it is less than 5, so it should be rounded up (or remained).
Therefore, a rounded 9.000 is [tex]\Large\boxed{9.0}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
What is the mass of a 5.00cm3 piece of copper having a density of 8.96g/cm3
Answer:
44.8 grams
Explanation:
The density exists as a ratio comparing the mass of a piece of copper per 1 cm³. Since you have been given a new volume, you can set up a proportion to find the new mass.
[tex]\frac{8.96 grams}{1.00 cm^3} =\frac{?grams}{5.00cm^3}[/tex] <----- Proportion
[tex]44.8 = (1.00cm^3)(?grams)[/tex] <----- Cross-multiply
[tex]44.8= ?grams[/tex] <----- Divide both sides by 1.00
what is the acid dissociation constant of an monoprotic acid if a concentration of 0.3M solution has a pH of 3?
The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
What is the acid dissociation constant?The acid dissociation constant (Ka) is the equilibrium constant for an acid dissociation reaction.
Let's consider the acid dissociation of a generic weak acid.
HA(aq) = H⁺(aq) + A⁻(aq)
Step 1. Calculate [H⁺].The pH of the solution is 3.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -3 = 1 × 10⁻³ M
Step 2. Calculate the acid dissociation constant (Ka).The concentration of the acid (Ca) is 0.3 M. For a weak monoprotic acid, we can calculate the acid dissociation constant using the following expression.
[H⁺] = √(Ca × Ka)
Ka = [H⁺]² / Ca
Ka = (1 × 10⁻³)² / 0.3 = 3 × 10⁻⁶
The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
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Convert the following measurement
The correct answer would be 0.034 g/L.
Unit conversionWhat we are trying to do here is to convert from milligram to gram and from deciliter to liter.
First, let's do the milligram to gram conversion.
1 mg = 0.001 g
Therefore,
3.4 mg = 3.4 x 0.001 = 0.0034 g
In order to convert from deciliter to liter.
1 deciliter = 0.1 L
Thus, 3.4 mg/dL = 0.0034g/0.1 L = 0.034 g/L
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What is the average dose of radiation that most people are exposed to every year not including dental or medical personnel dealing
with X-rays?
OA. 40 uSv
OB. 1000 u Sv
OC. 2400 u Sv
OD. 100,000 u Sv
C. The average dose of radiation that most people are exposed to every year not including dental or medical personnel dealing with X-rays is 2400 u Sv.
What is x-ray?
X-rays are a form of electromagnetic radiation, similar to visible light used for medical treatment and other forms of x ray inspection.
An X-ray, or, much less commonly, X-radiation, is a penetrating form of high-energy electromagnetic radiation.
The average dose of radiation that most people are exposed to every year not including dental or medical personnel dealing with X-rays is 2400 u Sv or 2.4 m u Sv.
Thus, the average dose of radiation that most people are exposed to every year not including dental or medical personnel dealing with X-rays is 2400 u Sv.
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Give the answer the problem below to the correct number of significant figures. Explain your results.
(329.5/0.45)-23.2
The correct number of significant figures gotten from the result of (329.5/0.45)-23.2 is infinite because there is no uncertain digit as a result of the answer being 709.022222222 when calculated.
What is a Significant figure?These refers to the digits which contributes to the degree of accuracy of a value and is usually counted starting from the non zero digits. In cases where the zero is between other numbers it is regarded as being significant such as 70.0111 in which the number of significant figures is six.
The result gotten from the expression (329.5/0.45)-23.2 is 709.022222222 which has a recurring decimal thereby making it difficult to calculate the number of recurring decimal.
Therefore it has infinitely many significant figures because there is no uncertain digit.
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How many mL of a 0.193 M aqueous solution of ammonium bromide, , must be taken to obtain 8.42 grams of the salt?
Answer:
445 mL NH₄Br
Explanation:
(Step 1)
Convert grams ammonium bromide (NH₄Br) to moles using its molar mass.
Molar Mass (NH₄Br): 14.007 g/mol + 4(1.008 g/mol) + 79.904 g/mol
Molar Mass (NH₄Br): 97.943 g/mol
8.42 grams NH₄Br 1 mole
----------------------------- x ------------------------ = 0.0860 moles NH₄Br
97.943 grams
(Step 2)
Calculate the volume of NH₄Br using the molarity equation. Then, convert liters (L) to milliliters (mL).
Molarity (M) = moles / volume (L)
0.193 M = 0.0860 moles / volume
(0.193 M) x volume = 0.0860 moles
volume = 0.445 L
1,000 mL = 1 L
0.445 L NH₄Br 1,000 mL
------------------------ x ------------------ = 445 mL NH₄Br
1 L
Both flowering and nonflowering plants possess specialized structures that help them in reproduction. Conifers are nonflowering plants that possess special
to carry out reproduction. When conifers reproduce using these special structures, it is a form of
.
Conifers are non flowering plants that possess special cones to carry out reproduction. When conifers reproduce using these special structures, it is a form of Sexual reproduction.
How do conifers reproduce?Conifers are among the oldest living gymnosperms.These are a group of cone bearing seed plants.Typically, conifers are evergreen trees with needle-like leaves. E.g.: pine treesFlowering plants and conifers can reproduce by 2 main ways: sexual reproduction by means of seeds and asexual reproduction by means of separating and rooting part of a plant.However, seed production in conifers differs from that in flowering plants as conifers do not have showy petals like flowering plants. For sexual reproduction, conifers have male cones which produce pollen and female cones which contain ovules that develop into seeds. Gymnosperms (conifers) do not have their seeds enclosed in a fruit, unlike flowering plants. Instead, their seeds lie uncovered between a female cone's scales.Learn more about gymnosperms here:
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Is HCI an acid or a base?
Answer:
Strong Acid
Explanation:
Hope this helps! :)
Which best explains the effect of chemicals on the environment?
O A. Chemicals are only harmful to the environment.
OB. Chemicals do not affect the environment.
C. Chemicals are only helpful to the environment.
OD. Chemicals can be helpful or harmful to the environment.
The best effect of chemicals on the environment is that Chemicals can be helpful or harmful to the environment.
Environmental chemical compounds seek advice from a chemical compound or chemical element present in air, water, meals, soil, dust, or other environmental media which includes customer merchandise.
Chemical substances can be toxic due to the fact they are able to harm us after they enter or touch the frame. exposure to a poisonous substance together with fuel can have an effect on your fitness. due to the fact that drinking gas can motive burns, vomiting, diarrhea and, in very huge amounts, drowsiness or dying, it's far poisonous.
Nutrient loading from over-fertilization can bring about runoff that causes damaging consequences in aquatic ecosystems. sizable publicity to, or misuse of, insecticides can damage non-centered plants and animal, as well as lead to improvement of pesticide-resistant pest species.
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What volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid?
The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L
Data obtained from the questionFrom the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 15.7 MVolume of diluted solution (V₂) = 12 L Molarity of diluted solution (M₂) = 0.156 M Volume of stock solution needed (V₁) = ?How to determine the volume of the stock solution needed
The volume of the stock solution needed can be obtained by using the dilution formula as shown below:
M₁V₁ = M₂V₂
15.7 × V₁ = 0.156 × 12
15.7 × V₁ = 1.872
Divide both side by 15.7
V₁ = 1.872 / 15.7
V₁ = 0.12 L
Thus, the volume of the stock solution needed to prepare the solution is 0.12 L
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please answer the question so i can make sure I got them right! thank you :)
pH = pKa + log [conj.base]/[acid]
Let the concentration of the conjugate base = x
=> The concentration of the acid is also x (As the acid concentration is equivalent to that of the conjugate base)
for CH₃COOH=0.50 M and CH₃COO=0,25 M
pH = pKa + log [salt]/[acid]
pKa = -log Ka = -log 1.8x10-5 = 4.74
pH = 4.74 + log (0.50 M/1.0 M) = 4.74 + log 0.5 = 4.74 + (-0.3)
pH = 4.74 - 0.3
pH = 4.44
For0.20 M Na2CO3
pH=−log[H+]
=−log (1.54×10−12)
=11.8
for HNO₂
Kb = 2.17X10^-11 = x^2 / 0.148
x = [OH-] = 1.79X10^-6
pOH = 5.747
pH = 14.000 - pOH = 8.253
for HPO₄³⁻
= [HPO₄³⁻] [PO₄³⁻] [H +]/×10⁻³
=[PO₄³⁻]5.464×10⁻¹⁸
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In order to dilute 40.0 mL of 0.600 M HCl to 0.200 M, the volume of water that would need to be added would be 200 mL. 80.0 mL. O 160 mL. 120 mL. 100 mL.
Answer:
80 ml
Explanation:
Moles to start = .04 L * .6 M/L = .024 moles
this is how much must be in the final dilution
.2 moles / liter * x liter = .024 moles
x = .024 / .2 = .12 liter final volume
start with . 040 then add .080 to get .12 liter
.080 liter = 80 ml
A 75.1 L sample of gas at 33.2 ºC and 365.7 mm Hg expands to 242.9 L at 6.5 ºC. What is the new gas pressure?
Answer:
103 mmHg
Explanation:
To find the new pressure, you need to use the Combined Gas Law:
P₁V₁ / T₁ = P₂V₂ / T₂
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. You can find the new pressure (P₂) after converting the temperatures from Celsius to Kelvin.
P₁ = 365.7 mmHg P₂ = ? mmHg
V₁ = 75.1 L V₂ = 242.9 L
T₁ = 33.2 °C + 273.15 = 306.35 K T₂ = 6.5 °C + 273.15 = 279.65 K
P₁V₁ / T₁ = P₂V₂ / T₂ <----- Combined Gas Law
(365.7 mmHg)(75.1 L) / 306.35 K = P₂(242.9 L) / 279.65 K <----- Insert values
89.649 = P₂(242.9 L) / 279.65 K <----- Simplify left side
25070.433 = P₂(242.9 L) <----- Multiply both sides by 279.65
103 = P₂ <----- Divide both sides by 242.9
The volume of a gas at 0 degrees Celsius is 100 L. If the volume of the gas is increased to 200 L at a constant temperature, what is the new temperature of the gas in Kelvin?
The new temperature of the gas in Kelvin, given the data from the question is 273 °C
Data obtained from the questionFrom the question given above, the following data were obtained:
Initial volume (V₁) = 100 LInitial temperature (T₁) = 0 °C = 0 + 273 = 273 KPressure = ConstantNew volume (V₂) = 200 LNew temperature (T₂) =? How to determine the new temperatureThe new temperature of the gas can be obtained by using the Charles' law equation as illustrated below:
V₁ / T₁ = V₂ / T₂
100 / 273 = 200 / T₂
Cross multiply
100 × T₂ = 273 × 200
Divide both side by 100
T₂ = (273 × 200) / 100
T₂ = 546 K
Subtract 273 to obtain answer in °C
T₂ = 546 – 273 K
T₂ = 273 °C
Thus, new temperature of the gas is 273 °C
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Which of the following materials is the least porous?
loosely packed gravel
unsorted sand and rock
large pebbles and boulders
sorted sand and rock
Answer:
The answer is The unsorted sand and rock is the least porous.
Answer:
large pebbles and boulders
balance the following nuclear reactions
Answer:
1.) ⁴₂He
2.) ⁶₂He
3.) ²⁴²₉₄Pu
4.) ¹₀n
Explanation:
The superscript represents the mass number, which is the total amount of protons and neutrons in an element.
The subscript represents the atomic number, which is the total amount of protons in an element.
You can identify the element based on the atomic number. For instance, all atoms with a subscript/atomic number of 2 must always be helium (He). An element with an atomic number of 0 is represented by the symbol "n". The mass number and atomic numbers must be equal on both sides of the reaction.
1.) ¹₁H + ³₁H → ⁴₂He
-----> Mass Number: 1 + 3 = 4
-----> Atomic Number: 1 + 1 = 2
2.) ⁹₄Be + ¹₁H → He + ⁶₂He
-----> Standard helium (He) has a mass number of 4 and an atomic number of 2
-----> Mass Number: 9 + 1 - 4 = 6
-----> Atomic Number: 4 + 1 - 2 = 2
3.) ²³⁹₉₂U + ⁴₂He → ²⁴²₉₄Pu + ¹₀n
-----> Mass Number: 239 + 4 - 1 = 242
-----> Atomic Number: 92 + 2 - 0 = 94
4.) ²⁷₁₃Al + ¹₀n → ²⁴₁₁Na + ⁴₂He
-----> Mass Number: 24 + 4 - 27 = 1
-----> Atomic Number: 11 + 2 - 13 = 0
100.0 mL of a 0.695 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution?
Answer:
0.116 M
Explanation:
(Step 1)
Calculate the amount of moles using the molarity ratio.
100.0 mL / 1,000 = 0.1000 L
Molarity = moles / volume
0.695 M = moles / 0.1000 L
0.0695 = moles
(Step 2)
Calculate the new molarity using the moles and new volume.
500.0 mL / 1,000 = 0.5000 L
Molarity = moles / volume
Molarity = 0.0695 moles / (0.1000 L + 0.5000 L)
Molarity = 0.0695 moles / (0.6000 L)
Molarity = 0.116 M
what is the correct iupac name for the following structure:CH2=CH-CH2-CH3
The correct IUPAC name of the following structure CH2=CH2-CH-CH3 is But - 1 - ene
IUPAC rules for alkene nomenclatureThe parent alkene is picked because it has the longest carbon chain with the double bond between carbon atoms.The suffix "ane" of the alkane is transformed to "ene."Depending on whether a double bond appears twice or three times in the parent chain, an alkene is referred to as a diene or triene.the positions of double bonds or side chains, indicated by the numerals 1, 2, 3, etc.Because it is the longest chain and is numbered from that end, the carbon atom in the double bond, which is written just before the suffix "ene," has the lowest number.The carbon chain is numbered so that the substituent receives the lowest number if both sides of a double bond receive the same number.Hence the structure CH2=CH-CH2-CH3 is named on the basis of the above rule as but - 1 - ene.
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A sample of carbon dioxide occupies 200 L at 22°C and 1.0 atm. At what temperature will
it expand to 1000 L at 0.90 atm?
Answer:
1328 K or 1055 °C
Explanation:
To find the new temperature, you need to use the Combined Gas Law:
P₁V₁ / T₁ = P₂V₂ / T₂
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. After converting the temperature (T₁) from Celsius to Kelvin, you can plug the values into the equation and simplify.
P₁ = 1.0 atm P₂ = 0.90 atm
V₁ = 200 L V₂ = 1000 L
T₁ = 22 °C + 273.15 = 295.15 K T₂ = ? K
P₁V₁ / T₁ = P₂V₂ / T₂
(1.0 atm)(200 L) / 295.15 K = (0.90 atm)(1000 L) / T₂
0.6776 = (0.90 atm)(1000 L) / T₂
(0.6776) x T₂ = (0.90 atm)(1000 L)
(0.6776) x T₂ = 900
T₂ = 1328 K
T₂ = 1055 °C
select the common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous
The common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.
What are hazardous statements?Hazardous statements are those words or phrases that are labelled against chemicals which shows the degree of how dangerous the chemical are.
The common words that are used as hazardous statements which shows that a chemical is dangerous include the following:
Danger,Caution andWarning.Therefore, the common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.
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Write equations that show NH3 as both a conjugate acid and a conjugate base.
Answer:
hope this helps
Explanation:
˙˚ʚ(´◡`)ɞ˚˙
How many grams of NaOH are needed to make a 250.0 mL or a 4.2 M NaOH solution?
Group of answer choices
A. 1.05 grams NaOH
B. 42,000 grams NaOH
C. 42 grams NaOH
D. 1050 grams NaOH
42 grams of NaOH are needed to make a 250.0 mL or a 4.2 M NaOH solution (option C).
How to calculate mass?The mass of a substance can be calculated by multiplying the number of moles by its molar mass.
However, the number of moles of NaOH can be calculated using the following formula;
Molarity = no of moles ÷ volume
no of moles = 0.250L × 4.2 = 1.05mol
Hence, the mass of NaOH can be calculated as follows:
mass = 1.05 mol × 40g/mol = 42g
Therefore, 42 grams of NaOH are needed to make a 250.0 mL or a 4.2 M NaOH solution.
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How many grams of Nitrogen gas are found in 22.4 L of Nitrogen gas?
Group of answer choices
A. 20 g
B. 14 g
C. 56 g
D. 28 g
Answer:
The answer is 28 gram.
28 gram of Nitrogen gas are found in 22.4 l in Nitrogen gas
You have a 473 mL glass of lemonade with a concentration of 2.37 M.
The lemonade sits out on your counter for a couple of days, and 150 mL of water evaporates from the glass.
What is the new concentration of the lemonade?
The new concentration of the lemonade solution, given the data from the question is 3.47 M
Data obtained from the questionFrom the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 2.37 MVolume of stock solution (V₁) = 473 mLVolume of water that evaporated = 150 mLVolume of new solution (V₂) = 473 - 150 = 323 mL Molarity of new solution (M₂) =? How to determine the molarity of the new solutionThe molarity of the new solution can be obtained by using the dilution formula as shown below:
M₁V₁ = M₂V₂
2.37 × 473 = M₂ × 323
1121.01 = M₂ × 323
Divide both side by 323
M₂ = 1121.01 / 323
M₂ = 3.47 M
Thus, the concentration of the new solution is 3.47 M
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What is the structure of polypropylene
The Structure of polypropylene(C3H6)n is linear.
The chemical formula for polypropylene is (C3H6)n.It is a polymer with complex structure and also known as polypropene. Polypropylene is similar to polyethylene which belongs to polyolefin groups. Generally the polymers are synthesized from the polymerization process.What is polymerization?The process in which atom or small molecules joined together repeatedly to form a polymer with complex structure is called as polymerization.
The repeated unit of atom or small molecule is called monomer
Structure of polypropylenePolypropylene is synthesized from the polymerization of propylene which is the monomer unit.
It has a linear structure made of propylene hydrocarbon units.
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