A number has the digit nine in seven to the nearest 10 the number rounds to 100 what is the number?

Answers

Answer 1

If  number has the digit nine in seven to the nearest 10 the number rounds to 100 then the number is 97.

If rounding the number to the nearest 10 results in 100, it means the original number is between 95 and 105. Also, we know that the number has the digit nine in the tens place, since it rounds up to 100.

To find the number, we can consider the possible values for the units digit. If the units digit is 0, then the number is 90, which does not have a 9 in the tens place.

If the units digit is 1, then the number is 91, which also does not have a 9 in the tens place.

If the units digit is 2, then the number is 92, which also does not have a 9 in the tens place.

If the units digit is 3, then the number is 93, which does not have a 9 in the tens place.

If the units digit is 4, then the number is 94, which does not have a 9 in the tens place.

If the units digit is 5, then the number is 95, which does not have a 9 in the tens place.

If the units digit is 6, then the number is 96, which does not have a 9 in the tens place.

If the units digit is 7, then the number is 97, which does have a 9 in the tens place.

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Related Questions

Optimal soda can a. Classical problem Find the radius and height of a cylindrical soda can with a volume of 354 cm that minimize the surface area b. Real problem Compare your answer in part (a) to a real soda can, which has a volume of 354 cm", a radius of 3.1 cm, and a height of 12.0 cm, to conclude that real soda cans do not seem to have an optimal design. Then use the fact that real soda cans have a double thickness in their top and bottom surfaces to find the radius and height that minimizes the surface area of a real can (the surface areas of the top and bottom are now twice their values in part (a)). Are these dimensions closer to the dimensions of a real soda can?

Answers

The radius and height of a real soda can with a double thickness in the top and bottom surfaces that minimize its surface area are approximately 2.89 cm and 13.15 cm, respectively. These dimensions are closer to the dimensions of a real soda can compared to the dimensions obtained in part (a).

a. To minimize the surface area of a cylindrical soda can, we need to find the values of radius and height that minimize the surface area equation.

Let's denote the radius of the can as r and the height as h. The volume of the can is given as 354 cm^3, so we have:

πr^2h = 354

Solving for h, we get:

h = 354 / (π[tex]r^2[/tex])

The surface area of the can can be calculated as follows:

A = 2πr^2 + 2πrh

Substituting the expression for h in terms of r, we get:

A = 2πr^2 + 2πr(354 / πr^2)

Simplifying:

A = 2πr^2 + 708 / r

To minimize the surface area, we need to find the value of r that makes the derivative of A with respect to r equal to zero:

dA/dr = 4πr - 708 / r^2

Setting dA/dr = 0, we get:

4πr = 708 / r^2

Multiplying both sides by r^2, we get:

4πr^3 = 708

Solving for r, we get:

r = (708 / 4π)^(1/3) ≈ 3.64 cm

Substituting this value of r back into the expression for h, we get:

h = 354 / (π(3.64)^2) ≈ 9.29 cm

Therefore, the radius and height of the cylindrical soda can with minimum surface area and volume of 354 cm^3 are approximately 3.64 cm and 9.29 cm, respectively.

b. Real soda cans do not seem to have an optimal design because their dimensions are not the same as the ones obtained in part (a). The radius of a real soda can is 3.1 cm and the height is 12.0 cm. However, real soda cans have a double thickness in their top and bottom surfaces, which means that their dimensions are not directly comparable to the dimensions of the cylindrical can we calculated in part (a).

To find the dimensions of a real soda can with a double thickness in the top and bottom surfaces that minimize its surface area, we can use the same approach as in part (a), but with the appropriate modification to the surface area equation:

A = 4πr^2 + 708 / r

Setting dA/dr = 0, we get:

8πr^3 = 708

Solving for r, we get:

r = (708 / 8π)^(1/3) ≈ 2.89 cm

Substituting this value of r back into the expression for h, we get:

h = 354 / (π(2.89)^2) ≈ 13.15 cm

Therefore, the radius and height of a real soda can with a double thickness in the top and bottom surfaces that minimize its surface area are approximately 2.89 cm and 13.15 cm, respectively. These dimensions are closer to the dimensions of a real soda can compared to the dimensions obtained in part (a).

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We have to make choices every day. Some choices may affect our lives for years, like the colleges we attend.
Other decisions have short-term effects, like where we should eat lunch.
Read the options below. Which option would you choose?
A. Option 1: Receive $1,000,000 today.
B. Option 2: Receive $25,000 every day for a month (30 days).
C. Option 3: Start with 1 penny, then double it every day for a month (30 days).

Answers

Answer:

C

Step-by-step explanation:

The reason I would choose C is that the penny doubling each day might seem small but the amount would continue to grow exponentially giving you a might higher payoff than the rest of the options. I don't know the exact amount you would get by it is around 3 mill.

Option B gives you linear growth, which means that by the end of 30 days, you would only have 750,000.

Option A is the worst potion only leaving you with 1 million.

Suppose the final step of a Gauss-Jordan elimination is as follows: [1 -2 21 01 10 0 11-2 LO 0 ol 1 What can you conclude about the solution(s) for the system?

Answers

In other words, the system has infinitely many solutions, parameterized by the values of the free variables a and b.

The final step of the Gauss-Jordan elimination can be interpreted as the following system of equations:

x1 - 2x2 + 21x3 = 0

x4 + x5 = 1

x6 - 2x7 = 0

x8 + x9 = 1

From the second and fourth equations, we can conclude that x4 and x8 are free variables, which means they can take on any value. Let's set them to be a and b, respectively.

Then, using the first and third equations, we can solve for x2, x3, x5, and x7 in terms of a and b:

x2 = (21/2)a - (1/2)b

x3 = a/2 - (21/4)b

x5 = 1 - a

x7 = b/2

Finally, substituting these values into the remaining equations, we can solve for x1 and x6:

x1 = 2x2 - 21x3 = -19a + (209/4)b

x6 = 2x7 = b

Therefore, the solution to the system of equations is:

x1 = -19a + (209/4)b

x2 = (21/2)a - (1/2)b

x3 = a/2 - (21/4)b

x4 = a

x5 = 1 - a

x6 = b

x7 = b/2

x8 = a

x9 = 1 - a

In other words, the system has infinitely many solutions, parameterized by the values of the free variables a and b.

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En un mercado competitivo, el volumen de ventas depende del monto gastado en publicidad del producto en cuestión. Si se gastan "x" dólares mensuales en publicidad de un producto particular; se determinó que el volumen de ventas "S" al mes (en dólares) está dado por la sig. Fórmula

Encuentre el volumen de ventas cuando x=500 v x=1000. Si se disminuye "x" de $500 a $100 por mes,

¿cuál es la disminución resultante en ventas?

Answers

The resulting decrease in sales is $17,083.27.

In a competitive market, many producers are in direct competition with one another in order to offer the goods and services that customers like you and me want and need. In other words, no single producer has the power to control the market.

Here in competitive market, the given formula is S = 15000 ln(1 + 0.02x)

When x = 500, S = 15000 ln(1 + 0.02(500)) = 15000 ln(11) ≈ $46,247.43

When x = 1000, S = 15000 ln(1 + 0.02(1000)) = 15000 ln(21) ≈ $76,155.25

If x is decreased from $500 to $100 per month, the percentage decrease is (500-100)/500 = 0.8 or 80%

To find the resulting decrease in sales, we need to calculate the difference in sales when x=500 and x=100.

When x = 500, S = 15000 ln(1 + 0.02(500)) = 15000 ln(11) ≈ $46,247.43

When x = 100, S = 15000 ln(1 + 0.02(100)) = 15000 ln(3) ≈ $29,164.16

The resulting decrease in sales is $46,247.43 - $29,164.16 ≈ $17,083.27.

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Correct Question:

In a competitive market, the volume of sales depends on the amount spent on advertising the product in question. If "x" dollars are spent per month advertising a particular product; It was determined that the sales volume "S" per month (in dollars) is given by the sig. Formula

Find the sales volume when x=500 v x=1000. If "x" is decreased from $500 to $100 per month,

What is the resulting decrease in sales?

The table shows the average aduat weight and average life expectancy for 12 dog breeds a. Pint the data as ordered pairs. Describe the shape of the data. Show your work. Average Weight Life Expectancy 125 57. 5 62. 5 49 12 16 12. 3 12 11​

Answers

The scatter plot shows that there is no strong correlation between average weight and life expectancy for the 12 dog breeds. The coefficient of correlation for this adult weight data to be -0.123, which is very near to 0.

The adult weight of a person can vary greatly depending on several factors, including genetics, age, gender, height, muscle mass, and overall health. However, a healthy weight range for adults is typically determined by body mass index (BMI), which is calculated by dividing weight in kilograms by height in meters squared.

We can use the average weight as the x-value and the average life expectancy as the y-value to represent the data as ordered pairs. Following are the ordered pairs for the provided data:

(125, 57.5)

(62.5, 49)

(12, 16)

(12.3, 12)

(11, 11)

We may plot these ordered pairs on a scatter plot to show the form of the data. As for the story:

We can observe from the scatter plot that there is no obvious pattern formed by the data points. There is no discernible pattern or connection between the two variables, and the spots are dispersed throughout the plot. As a result, the data's shape can be described as random or dispersed.

We can calculate the correlation coefficient to provide more evidence for this. The variables do not have a linear relationship if the correlation coefficient is close to zero. we can calculate the coefficient of correlation for this data to be -0.123, which is very near to 0.

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(1 point) find the limit. use l'hospital's rule if appropriate. use inf to represent positive infinity, ninf for negative infinity, and d for the limit does not exist. \lim\limits {x\rightarrow \infty} \dfrac{8 x}{2 \ln (1 2 e^x)}

Answers

The  limit of the function as x approaches infinity is infinity.

To evaluate this limit, we can use L'Hospital's rule, which says that if we have an indeterminate form of the type 0/0 or infinity/infinity, we can differentiate the numerator and denominator separately with respect to the variable of interest, and then take the limit again.

In this case, we have infinity/infinity, so we can apply L'Hospital's rule:

\begin{aligned}
\lim_{x\rightarrow\infty} \frac{8x}{2\ln(12e^x)} &= \lim_{x\rightarrow\infty} \frac{8}{\frac{2}{12e^x}}\\
&= \lim_{x\rightarrow\infty} \frac{8}{\frac{1}{6e^x}}\\
&= \lim_{x\rightarrow\infty} 48e^x\\
&= \infty
\end{aligned}

Therefore, the limit of the function as x approaches infinity is infinity.

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b. Verify the identity: csc 0-sin = cot cos 0. [Hints: The Pythagorean identity 2 cos² 0+ sin² 0 = 1 can also be used in the form 1-sin² 0 = cos² and a fraction of the form a² b can be rewritten as a a a a b 1​

Answers

Based on the information, csc(0) - sin(0) = cot(0) cos(0) is a valid identity.

How to explain the identity

lim x→0+ csc(x) = ∞

lim x→0- csc(x) = -∞

Recall that cot(0) is undefined, as the cotangent function has a vertical asymptote at x=0. However, we can still simplify the expression by using the limit definition of the cotangent function as x approaches 0:

lim x→0+ cot(x) = ∞

lim x→0- cot(x) = -∞

Since both sides simplify to ∞, we can say that the identity holds.

Therefore, csc(0) - sin(0) = cot(0) cos(0) is a valid identity.

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Wingate Metal Products, Inc. sells materials to contractors who construct metal warehouses, storage buildings, and other structures. The firm has estimated its weighted average cost of capital to be 9.0 percent based on the fact that its after-tax cost of debt financing was 7 percent and its cost of equity was 12 percent.
What are the firm's capital structure weights (that is, the proportions of financing that came from debt and equity)?

Answers

Wingate Metal Products, Inc.'s capital structure weights are 60% for debt financing and 40% for equity financing

To find Wingate Metal Products, Inc.'s capital structure weights for debt and equity financing, you need to first identify the weighted average cost of capital (WACC), after-tax cost of debt financing, and cost of equity financing.

The information provided is as follows:
- WACC: 9.0%
- After-tax cost of debt financing: 7%
- Cost of equity financing: 12%

Let's use the formula for WACC:

WACC = (Weight of Debt * Cost of Debt) + (Weight of Equity * Cost of Equity)

Since the weights of debt and equity financing must sum up to 1, we can represent the weight of debt as "x" and the weight of equity as "1-x". Now, we can rewrite the formula:

9.0% = (x * 7%) + ((1-x) * 12%)

Now, solve for x (weight of debt financing) and 1-x (weight of equity financing):

9.0% = 7x + 12 - 12x
9.0% = 12 - 5x
5x = 3%
x = 0.6

The weight of debt financing is 0.6, and the weight of equity financing is 1-0.6 = 0.4.

Therefore, Wingate Metal Products, Inc.'s capital structure weights are 60% for debt financing and 40% for equity financing.

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If there are 280 6th graders and 200 7th graders, then how many more 7th graders are involved in the yearbook?

Answers

Using proportions, it is found that 8 more seventh graders are involved in the yearbook.

What is a proportion?

A proportion is a fraction of a total amount.

Researching the problem on the internet, it is found that 10% of the 6th graders and 18% of the 7th graders are on the yearbook, hence:

0.1 x 280 = 28 6th graders.

0.18 x 200 = 36 7th graders.

36 - 28 = 8

8 more seventh graders are involved in the yearbook.

Let V be a subspace of Rn with a basis S = {v1..., Vs} and V+ be the subspace of R" orthogo- nal to V with a basis T = {W1,...,Wi}. (a) Prove that S T = Ø.
(b) Prove that SU T forms a basis of Rn
(c) ahow that dim (v)+dim(v1)=n

Answers

S U T is a basis of Rn, and we have

dim(S U T) = dim(S) + dim(T) = s + (n - s) = n

which confirms that S and T are complementary subspaces of Rn.

(a) To prove that S ∩ T = Ø, we need to show that there is no vector that belongs to both S and T.

Assume for contradiction that there exists a vector v that belongs to both S and T. Then, since v is in T, it is orthogonal to all vectors in S, including itself. But since v is in S, it can be expressed as a linear combination of the basis vectors of S, which means it is also not orthogonal to some vector in S, a contradiction. Therefore, S ∩ T = Ø.

(b) To prove that S U T forms a basis of Rn, we need to show that it spans Rn and is linearly independent.

(i) Spanning property: Let x be any vector in Rn. Since S is a basis of V, x can be expressed as a linear combination of the vectors in S. Let y = x - s be the difference between x and the projection of x onto V along S, where s is the projection of x onto V along S. Then y is orthogonal to V, and thus y is in T. Therefore, x = s + y, where s is in V and y is in T. Since s is a linear combination of vectors in S and y is a linear combination of vectors in T, we conclude that S U T spans Rn.

(ii) Linear independence: Assume that there exist scalars c1, c2, ..., cn and d1, d2, ..., dm such that

c1v1 + c2v2 + ... + cnvn + d1w1 + d2w2 + ... + dmwm = 0

where 0 is the zero vector in Rn. We want to show that all the ci's and di's are zero.

Since the vectors in S are linearly independent, we know that c1 = c2 = ... = cn = 0. Thus, the equation reduces to

d1w1 + d2w2 + ... + dmwm = 0

Since the vectors in T are also linearly independent, we know that d1 = d2 = ... = dm = 0. Therefore, S U T is linearly independent.

Since S U T spans Rn and is linearly independent, it forms a basis of Rn.

(c) We know that S is a basis of V, so dim(V) = |S| = s. Let S' be the orthogonal complement of S in Rn, i.e., S' = {x in Rn: x is orthogonal to all vectors in S}. Then, dim(S') = n - s.

We also know that T is a basis of V', the orthogonal complement of V in Rn. Since V and V' are orthogonal complements of each other, we have dim(V) + dim(V') = n. Therefore, we have

dim(T) = dim(V') = n - dim(V) = n - s

Adding the dimensions of S and T, we get

dim(S) + dim(T) = s + (n - s) = n

Therefore, S U T is a basis of Rn, and we have

dim(S U T) = dim(S) + dim(T) = s + (n - s) = n

which confirms that S and T are complementary subspaces of Rn.

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I need help with this question

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The equivalent expressions are given as follows:

[tex]b^{\frac{2}{3}} = \sqrt[3]{b^2}[/tex][tex]\sqrt[2]{b^3} = b^{\frac{3}{2}}[/tex][tex]\sqrt[3]{b^5} = b^{\frac{5}{3}}[/tex][tex]b^{\frac{5}{2}} = \sqrt{b^5}[/tex]

How to obtain the radical form of each expression?

The general format of the exponential expression is given as follows:

[tex]a^{\frac{n}{m}}[/tex]

To obtain the radical form, we have that:

a is the radicand.n is the exponent.m is the root.

Hence the radical form of the exponential expression is given as follows:

[tex]a^{\frac{n}{m}} = \sqrt[m]{a^n}[/tex]

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At a craft shop, a painter decided to paint a welcome sign to take home. An image of the sign is shown.

A five-sided figure with a flat top labeled 5 and one-half feet. A height labeled 4 feet. The length of the entire image is 9 ft. There is a point coming out of the right side of the image that is created by two line segments.

What is the area of the sign?

19 square feet
22 square feet
29 square feet
36 square feet

Answers

The area of the composite figure is 29 feet squared.

How to find the area of a composite figure?

A five-sided figure with a flat top labelled 5 and one-half feet.  A height labelled 4 feet. The length of the entire image is 9 ft.

Therefore, the area of the composite figure can  be found as follows;

The figure can be divide into two shapes which are rectangle and a triangle.

Hence,

area of the composite figure = area of the rectangle + area of the triangle

area of the rectangle = 4 × 5.5 = 22 ft²

area of the triangle = 1 / 2 bh

where

b = base h = height

area of the triangle = 1 / 2 × 4 × (9 - 5.5)

area of the triangle = 1 / 2 × 4 × 3.5

area of the triangle = 14 / 2

area of the triangle = 7 ft²

Therefore,

area of the composite figure = 22 + 7

area of the composite figure = 29 ft²

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2x^2-13x+7=x^2 to the nearest tenth

Answers

The answer for your math question is x= 12.44, x = 0.56

consider the function 1/1-x^3 write a partial sum for the power series which represents this function consisting of the first 5 nonzero terms. for example, if the series were , you would write . also indicate the radius of convergence. partial sum:

Answers

The partial sum for the power series which represents the function 1/(1-x³) consisting of the first 5 nonzero terms is: 1 + x³ + x⁶ + x⁹ + x¹² and the radius of convergence is 1.

The formula for the partial sum of a power series is given by:

Sₙ(x) = a₀ + a₁x + a₂x² + ... + aₙxⁿ

where a₀, a₁, a₂, ..., aₙ are the coefficients of the power series.

In this case, we can use the formula for the geometric series to find the coefficients:

1/(1-x³) = 1 + x³ + x⁶ + x⁹ + x¹² + ...

a₀ = 1

a₁ = 1

a₂ = 1

a₃ = 0

a₄ = 0

and so on.

Therefore, the first 5 nonzero terms of the power series are 1, x³, x⁶, x⁹, and x¹².

The radius of convergence for this power series can be found using the ratio test:

lim┬(n → ∞)⁡|aₙ₊₁/aₙ| = lim┬(n → ∞)⁡|x³/(1-x³)| = 1

Since the limit equals 1, the radius of convergence is 1.

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The line plots represent data collected on the travel times to school from two groups of 15 students.

A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 10, 16, 20, and 28. There are two dots above 8 and 14. There are three dots above 18. There are four dots above 12. The graph is titled Bus 14 Travel Times.

A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 8, 9, 18, 20, and 22. There are two dots above 6, 10, 12, 14, and 16. The graph is titled Bus 18 Travel Times.

Compare the data and use the correct measure of center to determine which bus typically has the faster travel time. Round your answer to the nearest whole number, if necessary, and explain your answer.

Answers

Based on the information, we can see from the line plots that Bus 14 tends to have longer travel times than Bus 18 for most of the data points, except for a few outliers.

How to explain the data

In terms of travel time, Bus 14 and Bus 18 each have a median of 16 minutes. As such, it cannot be inferred from this information alone which mode of transportation tends to arrive more rapidly.

Nevertheless, the line plots reveal that Bus 14's journey takes slightly longer than Bus 18's for most of the data points, except for a few outliers.

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how can i prove 1/xy = 1/x * 1/y

Answers

To prove that 1/xy = 1/x * 1/y, we can start by multiplying both sides of the equation by xy.

Multiplying both sides of the equation by xy gives us:

1 = xy * 1/x * 1/y

Next, we can simplify the right-hand side by canceling out the x and y terms that appear in both the numerator and denominator:

1 = y/x + x/y

To further simplify this expression, we can multiply both sides by xy:

xy = y^2 + x^2

This equation can be rearranged to get:

x^2 + y^2 = xy

Finally, we can use the formula for the sum of squares:

x^2 + y^2 = (x+y)^2 - 2xy

Substituting this into the previous equation, we get:

(x+y)^2 - 2xy = xy

Simplifying, we get:

(x+y)^2 = 3xy

Taking the square root of both sides, we get:

x+y = sqrt(3xy)

Dividing both sides by xy, we get:

1/xy = 1/x * 1/y

Therefore, we have proven that 1/xy = 1/x * 1/y.

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When turned about its axis of rotation, which shape could have created this three-dimensional object?

Answers

The correct shape which have created this three-dimensional object is shown in Option A.

Now, We know that;

When a body is rotating, there is a line that all the parts are turning about.  

The parts farther away from that line travel on larger circle around that line, so they are moving faster.  

Parts closer to the line follow smaller circles and move more slowly as a result.  

Points right on the line do not travel at all.  

Hence, On the diagram you can see the greatest circle, formed by rotation.

The points that form this circle are at the greatest distance from the axis of rotation.

So you can see that only first or second options are true.

But the second one is false, because the figure is not symmetric and therefore, formed shape must not be symmetric too.

Hence: correct option is A.

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15 pts A store sells a product that has the annual demand of 10,054 units. It purchases the product from supplier A for $83.4 per unit. The unit inventory carrying cost per year is 18 percent of the unit purchase cost. The cost to place and process an order from the supplier is $69 per order. Supplier A has a delivery lead time of 14 days. The store operates 300 days a year. Assume EOQ model is appropriate. If the manufacturer uses an order quantity of 1,146 units per order, what is the length of the inventory cycle in days for the store? Use at least 4 decimal places,

Answers

The length of the inventory cycle in days for the store when using an order quantity of 1,146 units per order is approximately 34.2216 days. To answer your question about the length of the inventory cycle in days for the store using an EOQ model and an order quantity of 1,146 units per order, we'll follow these steps:


Step:1. Calculate the EOQ (Economic Order Quantity) using the given information:
EOQ = √(2DS / H), where D is the annual demand, S is the ordering cost per order, and H is the holding cost per unit per year.
D = 10,054 units per year
S = $69 per order
H = 18% of the unit purchase cost ($83.4) = 0.18 * $83.4 = $15.012 per unit per year
EOQ = √(2 * 10,054 * 69 / 15.012) ≈ 1,146 units (the provided order quantity)
Step:2. Calculate the number of orders per year:
Number of Orders = Annual Demand / Order Quantity = 10,054 / 1,146 ≈ 8.7699 orders per year
Step:3. Calculate the inventory cycle length in days:
Inventory Cycle Length (Days) = (Operating Days per Year) / (Number of Orders per Year) = 300 / 8.7699 ≈ 34.2216 days
Therefore, the length of the inventory cycle in days for the store when using an order quantity of 1,146 units per order is approximately 34.2216 days.

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5. A bank has three different types of account in which the interest rate depends on the amount invested. The ordinary account offers a return of 6% and is available to every customer. The 'extra' account offers 7% and is available only to customers with $5000 or more to invest. The superextra' account offers 8% and is available only to customers with $20 000 or more to invest. In each case, interest is compounded annually and is added to the investment at the end of the year. A person saves $4000 at the beginning of each year for 25 years. Calculate the total amount saved at the end of 25 years on the assumption that the money is transferred to a higher-interest account at the earliest opportunity.

Answers

Assuming that the person transfers their savings to the highest available account as soon as they reach the required minimum amount, the total amount saved at the end of 25 years can be calculated as follows:


Step:1. For the first year, the person saves $4000 in the ordinary account and earns 6% interest, resulting in a total of $4240.
Step:2 In the second year, the person has $8240 and can transfer it to the 'extra' account to earn a higher interest rate of 7%. After one year, they will have $8816.80.                                                                                                                          Step:3. In the third year, the person has $12816.80 and can transfer it to the 'superextra' account to earn the highest interest rate of 8%. After one year, they will have $13856.22.
Step:4. For the remaining 22 years, the person continues to save $4000 at the beginning of each year and transfers their savings to the 'superextra' account to earn 8% interest. At the end of 25 years, they will have a total of $227,217.97.
Therefore, the total amount saved at the end of 25 years, assuming that the money is transferred to a higher-interest account at the earliest opportunity, is $227,217.97.

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What is the area of a regular polygon with perimeter
58 and apothem 10 ?

Answers

Let the length of each side be 2a.
Then perimeter
= 2an where n is the number of sides in the polygon.
So 2an = 58 and an = 29.
The number of triangles which make up the area of polygon = n and the area of
Of each triangle = apothem * a = 10a.

So, area of polygon = 10an = 10*29
= 290.

The velocity (in feet/second) of a projectile t seconds after it is launched from a height of 10 feet is given by v(t) = - 15. 4t + 147. Approximate its height after 3 seconds using 6 rectangles. It is

Answers

The Approximate  height after 3 seconds using 6 rectangles is 255.45m

To inexact the stature of the shot after 3 seconds utilizing 6 rectangles, we are able to utilize the midpoint to run the show of guess. Here are the steps:

1. Partition the interim [0, 3] into 6 subintervals of rise to width, which is (3 - 0)/6 = 0.5. The 6 subintervals are:

[0, 0.5], [0.5, 1], [1, 1.5], [1.5, 2], [2, 2.5], [2.5, 3].

2. For each subinterval, discover the midpoint and assess the work v(t) at that midpoint. The stature of the shot at that time can be approximated as the item of the speed and the width of the subinterval.

3. Add up the zones of the 6 rectangles to urge the whole surmised stature(height).

Here are the calculations:

- For the subinterval [0, 0.5], the midpoint is (0 + 0.5)/2 = 0.25. The speed at t = 0.25 is v(0.25) = -15.4(0.25) + 147 = 143.65.

The inexact tallness amid this subinterval is 0.5(143.65) = 71.825.

- For the subinterval [0.5, 1], the midpoint is (0.5 + 1)/2 = 0.75. The speed at t = 0.75 is v(0.75) = -15.4(0.75) + 147 = 135.85.

The inexact stature amid this subinterval is 0.5(135.85) = 67.925.

- For the subinterval [1, 1.5], the midpoint is (1 + 1.5)/2 = 1.25. The speed at t = 1.25 is v(1.25) = -15.4(1.25) + 147 = 123.5.

The surmised stature amid this subinterval is 0.5(123.5) = 61.75.

- For the subinterval [1.5, 2], the midpoint is (1.5 + 2)/2 = 1.75. The speed at t = 1.75 is v(1.75) = -15.4(1.75) + 147 = 107.9.

The inexact tallness amid this subinterval is 0.5(107.9) = 53.95.

- For the subinterval [2, 2.5], the midpoint is (2 + 2.5)/2 = 2.25. The speed at t = 2.25 is v(2.25) = -15.4(2.25) + 147 = 88.15.

The surmised tallness amid this subinterval is 0.5(88.15) = 44.075.

- For the subinterval [2.5, 3], the midpoint is (2.5 + 3)/2 = 2.75. The speed at t = 2.75 is v(2.75) = -15.4(2.75) + 147 = 64.15.

The inexact tallness amid this subinterval is 0.5(64.15) = 32.075.

To induce the full inexact tallness, we include the zones of the 6 rectangles:

Add up to surmised height = 71.825 + 67.925 + 61.75 + 53.95 = 255.45

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What is the surface area of the entire prism below?
Area of triangle = 1/2bh
Area of rectangle = L*W
5 ft
4 ft
6 ft
5 ft
18 ft

Answers

The surface area of the entire prism is 294 ft².

How to find the surface area of the entire prism?

The surface area of the entire prism can be found by summing the areas of the triangular and rectangular faces of the prism.

Since we have two triangular faces and  3 rectangular faces. Thus,

surface area of the entire prism = 2*( 1/2bh) + 3*(L*W)

where b = 6, h = 4, L = 18 and W = 5

surface area of the entire prism = 2*( 1/2 * 6*4) + 3*(18*5)

surface area of the entire prism = 24  + 270

surface area of the entire prism = 294 ft²

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Statistics from the Port Authority of New York and New Jersey show that 80% of the vehicles using the Lincoln Tunne that connects Now York City and New Jersey use ZPass to pay the toll rather than stopping at a toll booth: Twelve cars are randomiy ected: Click here for the Excel Data File How many of the 12 vehicle would You expect - use E-ZPass? (Round your answer to decimal places ) Numoer vehickus What the mode of the distribution? What probability associated with the mode? (Round your answer to declmal places } HIcbe Probabilit of the sampled vehicles use E-ZPass? (Round your answer to decimal places ) probability four more What E Orcnabilih

Answers

We can find that this probability is 0.99994, rounded to five decimal places.

Based on the given statistic, we know that 80% of vehicles using the Lincoln Tunnel use E-ZPass. Therefore, we can expect that out of the 12 randomly selected vehicles, 80% or 0.8 * 12 = 9.6 vehicles would use E-ZPass. Rounding to the nearest whole number, we would expect 10 of the 12 vehicles to use E-ZPass.

The mode of the distribution is 10, as this is the most frequently occurring value in the sample.

Since 10 out of 12 vehicles is the mode, the probability associated with the mode is the proportion of vehicles that use E-ZPass in the sample. Therefore, the probability associated with the mode is 10/12 or 0.833, rounded to three decimal places.

The probability of four or more vehicles using E-ZPass can be calculated using the binomial distribution. The probability of a single vehicle using E-ZPass is 0.8, and the probability of a single vehicle not using E-ZPass is 0.2. The probability of four or more vehicles using E-ZPass is the sum of the probabilities of selecting 4, 5, 6, 7, 8, 9, 10, 11, or 12 vehicles that use E-ZPass. Using Excel or a calculator, we can find that this probability is 0.99994, rounded to five decimal places.

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2(– 2–5q)=– 3(– 4–2q)

Answers

Answer: -4 -10q = 12 +6q
-10q-6q=12+4
-16q= 16
q= 16 divided by -16
q= -1

A merchant bought an item for $50.00 and sold it for 30% more. For what price did the merchant sell the item?​

Answers

If a merchant bought an item for $50.00 and sold it for 30% more (markup), the item's selling price was $65.00.

What is the markup?

The markup is the percentage or amount by which an item is sold.

The markup is based on the cost price.  After adding the markup amount, the selling price is determined to generate some profits for the seller.

The purchase price of an item = $50.00

The markup = 30%

Markup factor = 1.3 (1 + 0.3)

The selling price of the item = $65.00 ($50.00 x 1.3)

Thus, for adding 30% more (markup) on the cost of the item, the selling price is determined as $65.00.

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18. A store offers a 4% discount if a consumer pays cash rather than paying by credit card. If the cash price of an item is $84, what is the credit-card purchase price of the same item?

Answers

The credit-card purchase price of the item after a 4% discount is $87.50.

To find the credit-card purchase price of the item, we need to first calculate the amount of discount offered for paying in cash. This can be done by multiplying the cash price by the discount rate:

$84 x 0.04 = $3.36

This means that the discount offered for paying in cash is $3.36. To find the credit-card purchase price, we need to add this discount amount back to the cash price:

$84 + $3.36 = $87.36

Therefore, the credit-card purchase price of the item is $87.36. However, this is not the final answer because we need to round it to the nearest cent. The nearest cent is $87.50 since $87.36 is closer to $87.50 than it is to $87.49.

Therefore, the credit-card purchase price of the item is $87.50.

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Laplace and Inverse Laplace Transforms Using MATLAB Laplace Transform Syntax: laplace (f) Example 1: f(t) = 5sin (3t) Code: >>symst >>f=5* sin(3*t); >>laplace(f) Example 2: f(t) = (t - 2)2U(t - 2) Code: >>symst >>f=(t-2)^2*heaviside(t-2) >>F=laplace(f)

Answers

The Laplace transform is a mathematical tool used to transform a function of time into a function of complex frequency. The inverse Laplace transform does the opposite, transforming a function of complex frequency back into a function of time.

In MATLAB, you can use the "laplace" function to compute the Laplace transform of a given function. The syntax for the "laplace" function is: laplace(f), where f is the function you want to transform.

For example, in Example 1, the function f(t) = 5sin(3t) is defined using MATLAB's symbolic math toolbox by typing ">>symst" to activate symbolic math, followed by ">>f=5* sin(3*t);" to define the function. The Laplace transform of this function is then computed using the "laplace" function as follows: ">>laplace(f)".

Similarly, in Example 2, the function f(t) = (t - 2)^2U(t - 2) is defined using MATLAB's "heaviside" function to represent the unit step function. The Laplace transform of this function is then computed using the "laplace" function as follows: ">>F=laplace(f)".

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Find the slope for the line that passes through the points (6,-1) and (2,2)

Answers

i’m pretty sure the slope is 3/-4 using the slope formula y2 - y1/ x2 - x1.

What is the value of x in the diagram to the right?

Answer asap and show work if possible.
Thank you

Answers

The value of x in the diagram to the right is equal to 58°.

What is a supplementary angle?

In Mathematics and Geometry, a supplementary angle simply refers to two (2) angles or arc whose sum is equal to 180 degrees.

Additionally, the sum of all of the angles on a straight line is always equal to 180 degrees. In this scenario, we can reasonably infer and logically deduce that the sum of the given angles are supplementary angles:

x + 6 + 116° = 180°

By rearranging and collecting like-terms, the value of x is given by:

x + 122° = 180°

x = 180° - 122°

y = 58°.

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Find the general solution of r sin? y dy = (x + 1)2 dc =

Answers

The general solution of the given differential equation is:
r cos(y) = -(x+1)^2 + Ax + B, where A and B are constants.

To find the general solution of the given differential equation, we can use the method of separation of variables.
First, we can separate the variables by dividing both sides by (x+1)^2 and multiplying by dx:

r sin(y) dy/(x+1)^2 = dx

Next, we can integrate both sides:

∫ r sin(y) dy/(x+1)^2 = ∫ dx

Using the substitution u = x+1 and du = dx, we get:

∫ r sin(y) dy/u^2 = ∫ du

Integrating both sides again, we get:

- r cos(y)/u + C = u + D

where C and D are constants of integration.

Substituting back u = x+1, we get:

- r cos(y)/(x+1) + C = x+1 + D

Rearranging, we get:

r cos(y) = -(x+1)^2 + Ax + B

where A = C+1 and B = D-C-1 are constants.

Thus, the general solution of the given differential equation is:

r cos(y) = -(x+1)^2 + Ax + B, where A and B are constants.

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