A pair of runners, A and B, are running on separate paths towards point 2 in the image. On both paths, point 1 is the same horizontal distance from point 2. The runners start and end at the same time on their respective paths. Which of the following is true about the runners' average speed and velocity? Select ALL that apply.
A. Both runners have the same velocity since they covered the same distance on the same amount of time.
B. Runner A has a greater speed since a greater distance was covered in the same amount of time
C. Runner B has a greater speed since a greater distance was covered in the same amount of time
D. Runner A has a greater velocity since the total displacement was greater than runner B
E. Runner B has greater velocity since the total displacement was greater than runner A
Answers
Answer:
C. Runner B has a greater speed since a greater distance was covered in the same amount of time.
Explanation:
Given information:
The time taken by both the runners A and B is same.
The horizontal distance (shortest distance or displacement) between point 1 and 2 is equal in both the paths.
From the given figure, the distance between point 1 and 2 in path B is more than that in path A.
Average velocity is the ratio of change in displacement with time and average speed is the ratio of total distance covered with time.
Now, the displacement between point 1 and 2 in both the paths is equal. and hence, the average velocity will also be same.
Average speed of runner B will be more as the distance covered by B is more then that by A.
Therefore, option C. Runner B has a greater speed since a greater distance was covered in the same amount of time is correct.
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The difference between vectors and scalars allows us to find that the correct answers are:
A. Both runners have the same velocity since they covered the same distance on the same amount of time
C. Runner B has a greater speed since a greater distance was covered in the same amount of time
Kinematics studies the movement of bodies, finding relationships between the position, velocity and acceleration of bodies
In general, the magnitudes of kinematics are vectors, which is why they have modulus and direction, therefore vector algebra must be used to perform the sum.
v = [tex]\frac{\Delta s}{\Delta t}[/tex]
The bold letters indicate vectors, v is the velocity, Δs the displacement (vector) and Δt the time (scalar)
In some cases scalar magnitudes are used, in kinematics they are given a different name: distance and speed.
v = [tex]\frac{\Delta s}{\Delta t}[/tex]
Where v is the speed, Δs the distance (scalar) and Δt the time (scalar)
This problem shows the difference between the two types of quantities
Let's look for the velocity of each runner.
They indicate that both leave point 1 and arrive at point 2, regardless of the intermediate paths, the displacement is the same.
They indicate that they arrive at the same time
v = [tex]\frac{\Delta s}{\Delta t}[/tex]
Consequently the velocity is the same for the two runners.
Let's look for speed
From the graph the distance of corridor B is greater than the distance traveled by corridor A
They indicate that the two arrive at the same time
[tex]v_a = \frac{\Delta x_a}{ \Delta t}[/tex]
[tex]v_b = \frac{\Delta x_b}{ \Delta t}[/tex]
[tex]v_a > v_b[/tex]
Let's analyze the different statements
A. True. Vector velocity is the same for both runners
B. False. The speed of corridor a is less
C. True. The speed of runner A is greater than the speed of runner B
D. False. Speed are equal
E. False The speed is the same.
In conclusion with the difference between vectors and scalars we can find that the correct answers are:
A. Both runners have the same velocity since they covered the same distance on the same amount of time
C. Runner B has a greater speed since a greater distance was covered in the same amount of time
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Related Questions
Explain how improving the EXERGY may be as good, if not better than discovering new/oil coal mines.
Answers
Answer:
It is necessary to search for new sources of energy because the sources we have now are non-renewable and exhaustible. The usage of these sources are increasing day by day and if this continues then one day we wlii be left with none so it is necessary to search for new sources of energy
PLEASE MARK ME BRAINLIESTFor a company to develop an effective customer-centric culture, there is always room for:
A. Larger product research and development investment
B. Improvement
C. More customers
D. More accurate market research
Answers
Continuous improvement helps a company to develop an effective customer-centric culture.
Such a company regards its customer experience and satisfaction as a core component of its business vision, mission, and strategies.
In a customer-centric culture, the company's actions and communications will be driven by the need to achieve the highest customer satisfaction.
Thus, there is always room for improvement as the company continuously seeks for opportunities to improve customer satisfaction.
A tourist drags his luggage of mass 20 kg with a force, F at a constant velocity across the floor . The coefficient of kinetics friction between the rollers of the luggage and the floor is 0.40. The luggage is dragged 0.80 m along the floor. Calculate the work done on the luggage by the force, F.
Answers
The work done on the luggage by the force is 62.78 J
The given parameters;
mass of the luggage, m = 20 kg
coefficient of friction, μ = 0.4
distance moved by the object, d = 0.8 m
To find:
the work done on the object by the forceThe work done on the luggage by the force is calculated as;
Work-done = F x d
work done = ma x d
[tex]work -done = m\times \mu \times g \times d\\\\work-done = 20 \times 0.4 \times 9.81 \times 0.8\\\\work-done = 62.78 \ J[/tex]
Thus, the work done on the luggage by the force is 62.78 J
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Rowenda is stopped on the side of the road. She then starts pedaling her bicycle for 15 seconds. Her final
velocity is 9 m/s. What is her acceleration while she is pedaling?
Answers
Explanation:
acceleration = change in velocity / change in time
a = v2-v1
- - - - - -
t
V1 = 0 ( since she stopped)
V2 = 9 m/s
t =15s
a = 9 - 0
- - - -
15
= 0.6m/s^2
Pls help me how to find absolute uncertainties in (M+m)
Answers
Answer:
m uncertainty percentage :
+- 2.5
+- 7.5
+- 12 5
+- 17.5
+- 25
+- 30
M uncertainty percentage = 16.5
m + M uncertainty percentage;
+- 19
+- 24
+- 29
+-34
+- 41.5
+- 46.5
ex 50 × 5 ÷100 = 2.5
If Scobie could drive a Jetson's flying car at a constant speed of 160.0 km/hr across oceans and space, approximately how long would Scoobie take to drive around Earth's equator in days
Answers
Scobie will take 10 days to drive around Earth's equator.
To calculate the time that takes Scobie to drive around Earth's equator we need to find the distance, which is given by the equation of a circumference:
[tex] d = 2\pi r [/tex]
Where:
r: is the Earth's radius = 6371 km
Then, the distance is:
[tex] d = 2\pi r = 2\pi*6371 km = 40030.2 km [/tex]
Now, if we divide the above distance by the speed of the car we can find the time:
[tex] t = \frac{d}{v} = \frac{40030.2 km}{160.0 km/h} = 250.2 h*\frac{1 d}{24 h} = 10 d [/tex]
Therefore, Scobie will take 10 days to drive around Earth's equator.
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Convert the following in to SI units without changing its values a. 4000 g. b. 2.4 km
Answers
#A
[tex]\boxed{\sf 1kg=1000g}[/tex]
[tex]\\ \sf\longmapsto 4000[/tex]
[tex]\\ \sf\longmapsto \dfrac{4000}{1000}[/tex]
[tex]\\ \sf\longmapsto 4kg[/tex]
#B
[tex]\boxed{\sf 1km=1000m}[/tex]
[tex]\\ \sf\longmapsto 2.4km=2.4(1000)[/tex]
[tex]\\ \sf\longmapsto 2400m[/tex]
How long does it take long a light from the sun to reach the earth if it travels a distance of 1.5 × 10^11m? (velocity of light = 3 × 10^8 m/s)
Answers
Answer:
Therefore, light travelling at 3.0x10^8 meters per second takes 500 seconds (8 minutes, 20 seconds) to reach the Earth, which is 1.5x10^11 meters away from the sun
Explanation:
what conditions might a cause scientist to modify or revise a hypothesis
Answers
Answer:
scientists might modify or revise a hypothesis after a trial run that didn't go how they thought.
What is the kinetic energy of a 0.5 kg soccer ball that is traveling at a
velocity of 3 m/s?
What’s the answer
Answers
Answer:
kinetic energy = 1/2mv²
k.E =1/2 X 0.5 X 3²
k.e = 9/4
K.E = 2.25j
Báo cáo thực hành
Bài 1: Sóng trên dây: https://phet.colorado.edu/vi/simulation/wave-on-a-string
Bài 2: Cầu cân bằng: https://phet.colorado.edu/sims/html/circuit-construction-kit-dc-virtual-lab/latest/circuit-construction-kit-dc-virtual-lab_vi.html
Answers
Answer:
which language is this
Explanation:
For each of the problems below, you will need to draw a graph to find the solution.
3. A driver who is moving at 15 m/s, sees a stop light and puts on the brakes 30 m before an intersection.
a) What acceleration will the driver have to have to stop before entering the intersection?
b) How much time will it take to stop the car?
4. A boy standing on a bridge spits into the water below. He hears the splash 1.5 seconds later. How high is the bridge?
5. A ball is thrown upwards at 20.0 m/s.
a) How far has it traveled after 4.0 seconds?
b) What is its velocity at that time?
Answers
Answer:
Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.
Explanation:
When you put water in the ice tray in the freezer, water becomes ice. Ice is more ordered than water. Is this a violation of Second Law of Thermodynamics
Answers
Answer:
No because the heat that moved out of the water to make ice caused an even greater disorder in the environment around it.
Explanation:
A drag racer, starting from rest, speeds up for 402 m with an acceleration of +17.0 m/s2. A parachute then opens, slowing the car down with an acceleration of –6.10 m/s2. How fast is the racer moving 3.50 × 102 m after the parachute opens?
Answers
The racer is running at a speed of approximately 96.943 meters per second at 350 meters after the parachute is opened.
According to this question, the drag race accelerates and later decelerates uniformly and we can determine the final speed of the vehicle by the following kinematic formula:
[tex]v = \sqrt{v_{o}^{2}+2\cdot a\cdot s}[/tex] (1)
Where:
[tex]v_{o}[/tex] - Initial speed, in meters per second. [tex]v[/tex] - Final speed, in meters per second.[tex]a[/tex] - Acceleration, in meters per square second.[tex]s[/tex] - Traveled distance, in meters.Acceleration phase
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 17\,\frac{m}{s^{2}}[/tex] and [tex]s = 402\,m[/tex], then the final speed of the drag racer is:
[tex]v = \sqrt{\left(0\,\frac{m}{s} \right)^{2} + 2\cdot \left(17\,\frac{m}{s^{2}} \right)\cdot (402\,m)}[/tex]
[tex]v \approx 116.910\,\frac{m}{s}[/tex]
Deceleration phase
If we know that [tex]v_{o} \approx 116.910\,\frac{m}{s}[/tex], [tex]a = -6.10\,\frac{m}{s^{2}}[/tex] and [tex]s = 350\,m[/tex], then the final speed of the drag racer is:
[tex]v = \sqrt{\left(116.910\,\frac{m}{s} \right)^{2} + 2\cdot \left(-6.10\,\frac{m}{s^{2}} \right)\cdot (350\,m)}[/tex]
[tex]v \approx 96.943\,\frac{m}{s}[/tex]
The racer is running at a speed of approximately 96.943 meters per second at 350 meters after the parachute is opened.
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28. In 1.2 s, 52 wave crests spaced 0.12 m apart pass a location. What is the frequency of these waves?
f=
Hz
Round your answer to the nearest thousandth if necessary.
Answers
Frequency = (number of waves) / (time)
(52waves) / (1.2 sec) = 43.333 Hz.
Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 x 10-11 m, the expected position of the electron in the atom.
a) 1012 N/C
b) 10-11 NIC
c) 106 N/C
d) 1014 N/C
e) 108 N/C
Answers
e
q/r
2
, so
E=
(5.11×10
−11
m)
2
(8.99×10
9
N.m
2
/C
2
)(1.60×10
−19
C)
=5.51×10
11
N/C∼10
1
2N/C
making (e) the best choice for this question.
The magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 x 10-11 m, the expected position of the electron in the atom will be a) 1012 N/C
What is electric field due to a charge ?Electric field is defined as the electric force per unit charge. The direction of the field is taken to be the direction of the force it would exert on a positive test charge.
electric field = k * q / r^2
given
distance (r) = 5.29 x 10-11 m
q of proton = + 1.602 * 10 ^ -19 C
k = 9 * 10 ^9 Nm^2 / C^2
Electric field = (9 * 10 ^9 Nm^2 / C^2 * 1.602 * 10 ^ -19 C )/ (5.29 x 10-11 m)^2
= 14.418 * 10 ^ (-10) / 27.98 * 10 ^ (-22)
= 0.5153 * 10 ^12 N/C
correct option a) 1012 N/C
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Convert 4 centimeters to meters using dimensional analysis and USE SCIENTIFIC NOTATION. (if you dont your answer is getting one star and reported). Please go step by step as I am having difficulty with this subject. Best answer get Brainliest
Answers
Answer:
[tex]thank \: you[/tex]
Question:-
Convert 4cm to m
Solution:-
Lets do
First note down the below formula
[tex]\boxed{\sf 1m=10^{2}cm}[/tex]
Then
[tex]\boxed{\sf 1cm=10^{-2}cm}[/tex]
Now we are given 4cm
So convert
[tex]\\ \sf\longmapsto 4\times 10^{-2}m[/tex]
If we simplify to decimal
[tex]\\ \sf\longmapsto 4cm=0.04m[/tex]
Hence done .
a 24kg remote control car travels 7 meters in 3 seconds. calculate the car's momentum
Answers
Answer:
Explanation:
ASSUMING that velocity is constant during the 3 seconds,
or that we are satisfied with AVERAGE momentum
p = mv = 24(7/3) = 56 kg•m/s
To qualify for the finals in a racing event, a race car must achieve an average speed of 255 km/h on a track with a total length of 2,200 m. If a particular car covers the first half of the track at an average speed of 213 km/h, what minimum average speed must it have in the second half of the event in order to qualify
Answers
Please find attached photographs of your answer. Hope it helps. Please do comment
4. A car slows down from 36 km.h to stop in 25 s. 4.1 Define "acceleration”. 4.2 Convert 36 km:h-' to m's-1.
Answers
1. Acceleration is the change in velocity of an object per unit time.
2. 36 km/h
= 36000 m/60×60 s
= 36000 m/3600 s
= 10 m/s
Hope it helps! Please do comment
how far will a rubber ball fall in 10 seconds
what would be the final velocity of this and what would be the average velocity
Answers
Answer:
490 meters
Explanation:
hope this helps!
Write the formular of force experienced by charge in electric field
Answers
Answer:
[tex]{ \sf{F=Ee}}[/tex]
Explanation:
F » Force
E » Electric field intensity
e » magnitude of charge
Convert the following statement to the language used by physicists, "I am cold, please turn on the heat."
Answers
Answer:
Explanation:fog
Explain how the lithosphere, hydrosphere, and atmosphere individually and collectively affect the biosphere. (2 points)
Answers
The lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.
What is the lithosphere?The lithosphere is the soil part that composes the Earth's planet (i.e., the soil), the hydrosphere refers to oceans and all water bodies, while the atmosphere is the layer of air. These three layers interact with biotic factors to shape the biosphere.
In conclusion, the lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.
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Fe + Br2 --> FeBr3
How many atoms of iron (Fe) are in the reactants?
How many atoms of bromine (Br) are in the reactants?
How many molecules of bromine are in the reactants?
How many atoms of iron (Fe) are in the products?
How many atoms of bromine (Br) are in the products?
How many particles of iron (III) bromide are in the products?
Is this equation balanced?
If the equation is not balanced, then balance it below :
__Fe + __Br2 ——-> __FeBr3
Answers
Explanation:
121134No2Fe+3Br2-->2FeBr3What is the average velocity if the initial velocity of an object is 10 m/s & the final velocity is 28 m/s
Answers
Answer:
[tex]v_{1} = 19 m/s[/tex]
Explanation:
[tex]v_{1} = \frac{(v_{2} + u)}{2}[/tex], where [tex]v_1[/tex] = avg. velocity, [tex]v_2[/tex] = final velocity, and [tex]u[/tex] = initial velocity.
Which of the following does not represent a question that can be answered by science?a. How much energy is released in a given nuclear chain reaction? b. Can a nuclear chain reaction be controlled? c. Should uncontrolled nuclear reactions be used for military applications?
d. What is the half-life of a waste product of a nuclear reaction?
Answers
Answer:
c. Should uncontrolled nuclear reactions be used for military applications?
Explanation:
The question on wether to use technology for military applications, is not a science question but a moral dilemma
The question that can not be answered by science is the question; "Should uncontrolled nuclear reactions be used for military applications?".
Science is empirical in its approach. This implies that the questions that are answered by science are questions that are testable and can be be verified in a laboratory.
Science does not answer questions that deal with the opinions of various individuals. That is completely outside the purview of scientific investigation.
Hence, science does not answer the question; Should uncontrolled nuclear reactions be used for military applications?
This question deals with moral values and the opinions of people about a matter and not empiricism.
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In a model of the solar system that was about as large as a college campus how large would the Sun be?
About the size of a basketball.
About the size of a marble.
About the size of a softball.
About the size of a small car
Answers
hằng số phổ biến chất khí
Answers
Answer:
please in english......................................
Explanation:
The fastest and longest skydive fell an amazing 19.5 miles. His average speed while falling was 254 mi/hr. How much time did the dive last? Show Work
Answers
We have that the time the dive lasted was
[tex]T=0.076771 hours[/tex]
From the Question we are told that
Fall distance 19.5 miles
Velocity v= 254 mi/hr
Generally the equation for the Time is mathematically given as
[tex]T=\frac{v}{d}\\\\T=\frac{19.5}{254}[/tex]
[tex]T=0.076771 hours[/tex]
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