A pair of standard since dice are rolled. Find the probability of rolling a sum of 9 with these dice.
P(D1 + D2 = 9) = ---

1. What is the probability a randomly selected bag will have a positive test? Give your answer to four decimal places is 0.1032

2. Given a randomly selected bag has a positive test, what is the probability it actually contains a large amount of liquid is 0.3780

3. Given a randomly selected bag has a positive test, what is the probability it does not contain a large amount of liquid is  0.6219

Let's characterize the taking after occasions:

A: The pack contains huge sums of fluid.

B: The test is positive.

We are given the taking after probabilities:

P(A) = 0.04

P(B | A) = 0.98

P(B | not A) = 0.07

1. To discover the likelihood of a positive test, we are able to utilize the law of adding up to likelihood:

P(B) = P(B | A) P(A) + P(B | not A) P(not A)

= 0.98 * 0.04 + 0.07 * 0.96

= 0.1032

So the likelihood of a haphazardly chosen pack having a positive test is 0.1032 (adjusted to four decimal places).

2. To discover the likelihood that a sack really contains large amounts of fluid given a positive test, we are able to utilize Bayes' hypothesis:

P(A | B) = P(B | A) P(A) / P(B)

= 0.98 * 0.04 / 0.1032

= 0.3780

So the likelihood that a pack really contains expansive sums of fluid given a positive test is 0.3780 (adjusted to four decimal places).

3. To discover the likelihood that a sack does not contain expansive sums of fluid given a positive test, ready to utilize Bayes' hypothesis again:

P(not A | B) = P(B | not A) P(not A) / P(B)

= 0.07 * 0.96 / 0.1032

= 0.6219

So the likelihood that a pack does not contain expansive sums of fluid given a positive test is 0.6219 (adjusted to four decimal places). 

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Answer:

The answer to your problem is, A. 10

Step-by-step explanation:

So first add up all the total number of ‘ X ‘

Which is:

4 + 3 + 2 + 1 = 10

Technically 10 is our answer.

Thus the answer to your problem is, A. 10

Not a 100% sure

Answer:

5, 8, 8, 8, 8, 9, 9, 9, 10, 10

The median of this data set is 8.5, so the correct answer is B.

Step-by-step explanation:

Since there are 10 observations, we are looking for the number halfway between the two middle observations (observations #5 and #6) when the data are arranged in order. Here, observation #5 is 8, and observation #6 is 9, so the median of this data set is (8 + 9)/2 = 8.5. B is the correct answer.

The simplified value of the expression is 12km³.

We have,

[tex]12k^2m^8 \div 4km^5[/tex]

This can be written as:

[tex]\frac{12k^2m^8}{ 4km^5}[/tex]

Canceling common expression.

= 12km³

Thus,

The simplified value of the expression is 12km³.

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The margin of error for a 80% confidence interval for the population mean is  57.82 square feet.

The number of square feet per house are normally distributed with a population standard deviation of 137 square feet and an unknown population mean. To find the margin of error for a 80% confidence interval, we need to use the formula:

Margin of error = z*(σ/√n)

where z is the z-score corresponding to the level of confidence (80% corresponds to z=1.282), σ is the population standard deviation (given as 137), and n is the sample size (given as 19).

Plugging in the values, we get:

Margin of error = 1.282*(137/√19) = 57.82

Therefore, the margin of error for a 80% confidence interval is 57.82 square feet.

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The measure of angle arc CD is 45⁰.

The measure of angle arc VW is 133⁰.

The measure of angle subtended by the arc CD is calculated by applying the following formula.

Based on the angle of intersecting chord theorem, we will have the following equation.

m∠AEB = ¹/₂( AB - CD)

26 = = ¹/₂(97 - CD)

2 x 26 = 97 - CD

52 = 97 - CD

CD = 97 - 52

CD = 45⁰

m∠VYX = ¹/₂( VW - VX)

37 = ¹/₂( VW - 59)

2 x 37 = VW - 59

74 = VW - 59

VW = 74 + 59

VW = 133⁰

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The p-value for the hypothesis test is 0.0314.

To find the p-value for this hypothesis test, we can use a t-test since the population standard deviation is unknown.

The test statistic is calculated as:

t = (x - μ) / (s / √n)

where x is the sample mean, μ is the hypothesized population mean under the null hypothesis, s is the sample standard deviation, and n is the sample size.

In this case, we have:

x = 424

μ = 400

s = 83

n = 53

So the test statistic is:

t = (424 - 400) / (83 / √53) ≈ 2.2071

To find the p-value, we need to compare this test statistic to the t-distribution with n-1 degrees of freedom (df = 52, in this case). Using a t-distribution table or calculator, we find that the probability of getting a t-value as extreme or more extreme than 2.2071 (in either direction) is approximately 0.0157.

Since this is a two-tailed test (Ha: u ≠ 400), we need to double this probability to get the p-value:

p-value = 2 * 0.0157 ≈ 0.0314

Therefore, the p-value for the hypothesis test is approximately 0.0314 (rounded to 4 decimal places).

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Answer:

Please mark me the brainliest

Step-by-step explanation:

To solve the equation (6 – 2x)(3 – 2x)x = 40, we can start by simplifying the left-hand side:

(6 – 2x)(3 – 2x)x = 40

(18x – 12x^2 – 6x + 4x^2)x = 40

(2x^3 – 8x^2 + 18x)x = 40

2x^4 – 8x^3 + 18x^2 = 40

2x^4 – 8x^3 + 18x^2 – 40 = 0

We can try to factor this equation by grouping terms:

2x^4 – 8x^3 + 18x^2 – 40 = 0

2(x^4 – 4x^3 + 9x^2 – 20) = 0

2((x^2 – 2x + 1)(x^2 – 2x – 20)) = 0

2(x – 1)^2(x – 5)(x + 4) = 0

Therefore, the real solutions of the equation are x = 1 (with multiplicity 2), x = 5, and x = -4.

Now, to answer the question, we need to determine whether it is possible to cut squares with sides of 3/2 in. to make a box. We can use the value of x = 3/2 to find the dimensions of the box:

length = 6 – 2x = 6 – 2(3/2) = 3 in.

width = 3 – 2x = 3 – 2(3/2) = 0 in.

height = x = 3/2 in.

Since the width is 0, it is not possible to cut squares with sides of 3/2 in. to make a box. Therefore, the correct answer is:

No. It is not possible to cut squares of this size.

The distance that the plane has flown, c, is 1,683 ft.

The distance of the plane is calculated by applying trigonometry ratio as shown below;

SOH CAH TOA

SOH = sin θ = opposite /hypothenuse side

TOA = tan θ = opposite side / adjacent side

CAH = cos θ = adjacent side / hypothenuse side

The height attained by the plane is the opposite side, while the hypothenuse is the distance travelled by the plane.

sin (12) = h/c

c = h/sin(12)

c = (350 ft ) / sin(12)

c = 1683.4 ft ≈1,683 ft

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As per the unitary method, it would cost $33 for Kelly and her two friends to bowl one game before 4 pm and one game after 4 pm each at Super Strike Bowling.

Bowling is a popular recreational activity enjoyed by many people around the world. Super Strike Bowling charges different rates for games played at different times of the day. To model the cost for one game, we can use a step function, where the value of x represents the number of hours after 12 pm. This function is defined as follows:

Cost per game (C) =

$5 if 1 pm ≤ x < 4 pm

$6 if 4 pm ≤ x < 8 pm

$8 if 8 pm ≤ x ≤ 12 am

Now, let's apply this step function to the scenario of Kelly and her two friends bowling. They each played one game before 4 pm, which cost $5 per game, and one game after 4 pm, which cost $6 per game. Therefore, the total cost for one person to play two games is:

Total cost = ($5 per game) + ($6 per game)

= $11

Since there were three people bowling, we can multiply the total cost by 3 to get the cost for all three to bowl:

Cost for all three to bowl = 3 × $11

= $33

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The difference in the account balances is $138,435.93.

We have,

We can solve this problem by using the formula for the future value of an annuity:

[tex]FV = PMT \times [(1 + r)^n - 1] / r[/tex]

where FV is the future value of the annuity, PMT is the yearly contribution, r is the annual interest rate, and n is the number of years.

Using the given information, we can find the future value of the annuity if the person starts at age 35:

FV1

= $5,000 x [(1 + 0.065)^30 - 1] / 0.065

= $431,874.32

Now we can find the future value of the annuity if the person starts at age 40:

FV2 = $5,000 x [(1 + 0.065)^25 - 1] / 0.065

= $293,438.39

The difference in the account balances is:

FV1 - FV2

= $431,874.32 - $293,438.39

= $138,435.93

Therefore,

The difference in the account balances is $138,435.93.

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A) The same z-score and find the area to the left of it, which is 0.1562.

b) The 75th percentile of the defect length distribution is 33.32 mm.

C) The 15th percentile of the defect length distribution is 19.21 mm.

d)The values that separate the middle 80% of the defect length distribution from the smallest 10% and the largest 10% are 17.95 mm and 38.05 mm, respectively.

(a) To find the probability that the defect length is at most 20 mm, we need to calculate the z-score first:

z = (20 - 28) / 7.9 = -1.0127

Using a standard normal table or a calculator, we can find that the probability of a z-score less than or equal to -1.0127 is 0.1562. Therefore, the probability that the defect length is at most 20 mm is 0.1562.

To find the probability that the defect length is less than 20 mm, we can use the same z-score and find the area to the left of it, which is 0.1562.

(b) To find the 75th percentile of the defect length distribution, we need to find the z-score that corresponds to the area of 0.75 in the standard normal distribution. Using a standard normal table or a calculator, we can find that this z-score is approximately 0.6745.

Then, we can solve for the defect length:

z = (x - 28) / 7.9

0.6745 = (x - 28) / 7.9

x - 28 = 0.6745 * 7.9

x = 33.32

Therefore, the 75th percentile of the defect length distribution is 33.32 mm.

(c) To find the 15th percentile of the defect length distribution, we need to find the z-score that corresponds to the area of 0.15 in the standard normal distribution. Using a standard normal table or a calculator, we can find that this z-score is approximately -1.0364.

Then, we can solve for the defect length:

z = (x - 28) / 7.9

-1.0364 = (x - 28) / 7.9

x - 28 = -1.0364 * 7.9

x = 19.21

Therefore, the 15th percentile of the defect length distribution is 19.21 mm.

(d) To find the values that separate the middle 80% of the defect length distribution from the smallest 10% and the largest 10%, we need to find the z-scores that correspond to the areas of 0.1 and 0.9 in the standard normal distribution. Using a standard normal table or a calculator, we can find that these z-scores are approximately -1.2816 and 1.2816, respectively.

Then, we can solve for the defect lengths:

z = (x - 28) / 7.9

-1.2816 = (x - 28) / 7.9

x - 28 = -1.2816 * 7.9

x = 17.95

z = (x - 28) / 7.9

1.2816 = (x - 28) / 7.9

x - 28 = 1.2816 * 7.9

x = 38.05

Therefore, the values that separate the middle 80% of the defect length distribution from the smallest 10% and the largest 10% are 17.95 mm and 38.05 mm, respectively.

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Given that the function:

[tex]f(x)=x^3+8x^2+x-42[/tex]

The function has zeros located at -7, 2, -3

First, let check f(2) = 0

[tex]2^3+8(2)+2-42=0[/tex]

 [tex]8+16+2-42=0[/tex]

        [tex]42-42=0[/tex]

Therefore, f(2) has a zero, that is (x - 2) is a factor of the polynomial function..

So, divide the given function by (x-2) to get the quadratic function.

[tex]\dfrac{x^3+8x^2+x-42}{x-2} =x^2+10x+21[/tex]

Now, solve the quadratic function.

    [tex]x^2+10x+21=0[/tex]

 [tex]x^2+7x+3x+21=0[/tex]

[tex]x(x+7)+3(x+7)=0[/tex]

[tex]x+7=0 \ \text{and} \ x+3=0[/tex]

       [tex]x=-7 \ \text{or} -3[/tex]

From the explanation above, it shows that -7, 2, and -3 are the roots (zeros) of the given polynomial function.

Thus, the behavior of the function can be described by using the degree and the leading coefficient.

The leading degree is 3 and the leading coefficient is 1.

So since the leading degree is odd (3), the end of the function will point in the opposite direction.

And since the leading coefficient is positive (+1), the graph rises to the right.

Hence, the behavior of the function falls to the left and rises to the right.

Answer:

I assume that "Rud" is a typo and you mean "Sin" instead.

To find the derivative of Sin(x^2) - Cos(x), we need to use the chain rule and the derivative of the trigonometric functions.

The derivative of Sin(x^2) is:

d/dx [Sin(x^2)] = Cos(x^2) * d/dx [x^2] = 2x * Cos(x^2)

The derivative of -Cos(x) is:

d/dx [-Cos(x)] = Sin(x)

Therefore, the derivative of the function Sin(x^2) - Cos(x) is:

2x * Cos(x^2) + Sin(x)

So the answer is option (b) -2xcos(x^2) + sin(x).

The answer is option (b): -2xcos(x^2).

Assuming that "Rud-cost" is a typo and the function is meant to be "Rudin-cost", which is a function defined as:

Rudin-cost(x) = cos(x^2)

To find the derivative of Rudin-cost(x), we can use the chain rule and the power rule for differentiation. Specifically, if we let u = x^2, then we have:

Rudin-cost(x) = cos(u)

Using the chain rule, we get:

Rudin-cost'(x) = -sin(u) * u'

where u' is the derivative of u with respect to x, which is:

u' = d/dx(x^2) = 2x

Substituting this back into the expression for Rudin-cost'(x), we get:

Rudin-cost'(x) = -sin(x^2) * 2x

Therefore, the answer is option (b): -2xcos(x^2).

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Answer: 720

Step-by-step explanation:

there are 6 letters in "choice"

and they must be permuted into 6 word letters:

6P6 = 720 distinct possibilities

The shape of the distributive is such that; it is skewed to the right. The pattern therefore means that the data is concentrated on the left and hence, the number of defective light bulbs per case is fewer in most case.

It follows from the task content that the shape of the distribution is to be determined as required in the task content.

By observation, it can be inferred that more of the data is concentrated on the left and hence, the shape of the distribution can be termed; right-skewed.

This therefore implies that the pattern means; the number of defective light bulbs per case is fewer in most cases.

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The experimental probability of the name Grace being​ chosen = 11/108

The theoretical probability of the name Grace being​ chosen = 1/6

We know that formula for the experimental probability of event A is :

P(A) = (Number of occurance of event A) / (Total number of trials)

Here, a name is chosen 108 times and the name Grace is chosen 11 times.

Let event A: the name Grace being​ chosen

the number of occurance of event A = 11

And the Total number of trials = 108

Using above formula the experimental probability would be,

P(A) = 11/108

Here, six different names were put into a hat.

This means that the number of possible outcomes n(S) = 6

And n(A) = 1

So, the theoretical probability would be,

P = n(A)/n(S)

P = 1/6

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The bush is 26.4 inches tall after 2 weeks. This means it has grown by 14.4 inches since it was first planted and the percentage increase is 120%

To calculate the height of the bush after 2 weeks, we can use the following formula:

New height = initial height + (percent increase/100) * initial height

In this case, the initial height of the bush is 12 inches, and the percent increase is 120%. Plugging in these values, we get:

New height = 12 + (120/100) * 12

New height = 12 + 14.4

New height = 26.4 inches

Therefore, the bush is 26.4 inches tall after 2 weeks. This means it has grown by 14.4 inches since it was first planted.

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Rotter Partners is planning a major investment, and to ensure that the investment is profitable, it is essential to understand the expected profit from the investment. The probability distribution of profits from similar investments indicates that the expected profit (mx) can be calculated as the weighted average of profits, where the weights are the probabilities associated with each profit level.

Based on the given probability distribution, the expected profit (mx) can be calculated as follows:

mx = (1 x 0.1) + (1.5 x 0.2) + (2 x 0.4) + (4 x 0.2) + (10 x 0.1)
mx = 0.1 + 0.3 + 0.8 + 0.8 + 1
mx = 2.7

Therefore, the expected profit from the investment is $2.7 million. This estimate is valuable to Rotter Partners as it can help them make informed decisions about the investment. If the expected profit is lower than the cost of the investment, then the investment may not be worthwhile. On the other hand, if the expected profit is higher than the cost of the investment, then the investment is likely to be profitable. In any case, the expected profit is a useful metric for assessing the potential success of the investment.

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The equation for total cost is The Total cost = (10s + 5m + 8l + 0.5n)  

First, we can  calculate  the total cost plus the both the shipping and the handling charge:

The Small shirts is  10 x $5.00 = $50.00

Medium shirts is  5 x $7.50 = $37.50

Large shirts is 8 x $12.00 = $96.

Lets add  three amounts plus also the  shipping and  the handling charge to the over all total cost:

The Total cost  is  (10 x $5.00) + (5 x $7.50) + (8 x $12.00) + (23 x $0.50)

Total cost = 195.00

Therefore, the equation of  total cost is

The Total cost = (10s + 5m + 8l + 0.5n)  s, m, and l refer to the  prices of small, medium, and large shirts, respectively,  n is the total number of shirts.

let now substitute the  values of s, m, l, and n.

The Total cost = 10 x 5.00 + 5 x 7.50 + 8 x 12.00 + 23 x 0.50)  in  dollars

Therefore, the Total cost = $195.00

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The transformation of the triangle is given by

a) ∠Y → ∠Q

b) ∠X → ∠P

c) YZ → QR

d) XZ → PR

e) ΔZXY → ΔRPQ

Given data ,

Let the first triangle be represented as ΔXYZ

Now , let the second triangle be represented as ΔPQR

Now , a sequence of rigid motions to map ΔXYZ to ΔPQR

So , the series of transformation for the triangle is given by

a) ∠Y → ∠Q

b) ∠X → ∠P

c) YZ → QR

d) XZ → PR

e) ΔZXY → ΔRPQ

Hence , the transformation is solved

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The total change to his score as an integer is -115

The total change in Juan score is calculated as follows;

Let Juan's initial score = x

when Juan finished the next level of his video game, he lost 10 points for each of the two targets he missed.

total points deducted = 20 points.

New score = x - 20

He was also penalized 95 points for taking too long.

His final score;

(x - 20) - 95

= x - 115.

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Answer:

16/22, 24/33, and 40/55

or

72.7272...% = Percentage form

0.7272... = Decimal form

Hope this helps :)

Pls brainliest...

We have shown that f(x) = f(0) for all x ∈ (-1,1).

Since f is continuous at 0, we have:

lim x → 0 f(x) = f(0)

Since f(x) = f(x³) for all x ∈ (-1,1), we can substitute x = x³ and get:

f(x) = f(x³) = f(x⁹) = f(x²⁷) = ...

Since |x| < 1, we have x² < |x| < 1, and thus:

lim x² → 0 f(x²) = f(0)

Therefore, we can apply the limit of the sequence of nested intervals to obtain:

f(x) = f(x³) = f(x⁹) = f(x²⁷) = ... = lim n → ∞ f(x^(3ⁿ)) = lim y → 0 f(y) = f(0)

where we have made the substitution y = x^(3ⁿ), which implies that x = y^(1/(3ⁿ)) → 0 as n → ∞.

Thus, we have shown that f(x) = f(0) for all x ∈ (-1,1).

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Answer:

I believe the answer is $180

Step-by-step explanation:

130+10=140

55+25=80

150

105

160

130

170

155

180

180

The pizza parlor offers 2^48, or approximately 281 trillion, different pizzas.

To calculate the total number of different pizzas offered, we need to consider all possible combinations of pizza sizes and toppings.

For each pizza size, there are 12 options for toppings (including no toppings). Therefore, the total number of pizzas for a single size is 2^12 (2 options for each of the 12 toppings). Since there are four different sizes, the total number of different pizzas offered by the parlor is:

2^12 x 2^12 x 2^12 x 2^12 = 2^(12+12+12+12) = 2^48

Thus, the pizza parlor offers 2^48, or approximately 281 trillion, different pizzas.

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The circle relation C defined on the set of real numbers is not reflexive and transitive but it is symmetric.

(a) C is not reflexive. To be reflexive, for every real number, xCx must hold true, meaning [tex]x^{2} + x^{2}[/tex]= 1. This is false. For example, let x=0. In this case, [tex]x^{2} + x^{2}[/tex] = 0, which does not equal 1. Therefore, C is not reflexive.

(b) C is symmetric.  If xCy then yCx, for all real numbers x and y. If we see the definition of C, this means that if [tex]x^{2} + y^{2}[/tex] = 1, then [tex]y^{2} + x^{2}[/tex] = 1. This is true due to the commutative property of addition ([tex]x^{2} + y^{2} = y^{2} + x^{2}[/tex] for all real numbers x and y). Thus, C is symmetric.

(c) C is not transitive. To be transitive, if xCy and yCz, then xCz must hold true for all real numbers x, y, and z. This means that if [tex]x^{2} + y^{2}[/tex] = 1 and [tex]y^{2} + z^{2}[/tex] = 1, then [tex]x^{2} + z^{2}[/tex]must equal 1. This is not always true. Let's take an example (x, y, z) = (1, 0, -1). Then [tex]x^{2} + y^{2}[/tex] = 1, [tex]y^{2} + z^{2}[/tex]= 1, but [tex]x^{2} + z^{2}[/tex] = 2, not 1. Thus, C is not transitive.

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B. An odd number of data values will always have one middle value is true.

D. An even number of data values will always have two middle numbers is also true.

In an odd set of data, there will always be one exact middle number. But in an even set of data, there will be two middle numbers, and they will be the two numbers closest to the center.

So if the middle of {1, 2, 3, 4, 5} is 3 and the middle of {1, 2, 3, 4} is 2 and 3, the correct statements will be;

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We then use the condition that b is unique to obtain a restriction on the values of a. Solving this restriction, we find that a can take any value except a = 2/3.

Let the given quadratic equation be denoted by f(x) = x^2 + 2bx + (a-b) = 0. Since f(x) has only one real solution, its discriminant must be zero: b^2 = a-b. Rearranging this equation, we get a = b^2 + b.

Substituting this expression for a into the equation for f(x), we obtain:

f(x) = x^2 + 2bx + (b^2 + b - b) = x^2 + 2bx + b^2.

This is a quadratic equation in b with discriminant 4x^2 - 4b^2 = 4(x+b)(x-b). For f(x) to have a unique real solution, this discriminant must be zero, which implies that x = -b. Substituting this value into f(x), we get:

f(-b) = (-b)^2 + 2b(-b) + b^2 = b^2 - 2b^2 + b^2 = 0.

Therefore, -b is a root of f(x), and since f(x) is a quadratic, this means that f(x) is divisible by (x+b). Thus we have:

f(x) = (x+b)(x+(a-b)/b) = (x+b)(x+b+1).

Since b is unique, this implies that (a-b)/b = b+1, or equivalently, a = b^2 + 2b.

Finally, we need to find the values of a for which b is unique. Suppose there are two distinct values of b that satisfy the condition above. Then, their difference satisfies:

(b_1)^2 + 2b_1 - (b_2)^2 - 2b_2 = 0,

which factors as (b_1 - b_2)(b_1 + b_2 + 2) = 0. Since b_1 and b_2 are distinct, the only possibility is that b_1 = -b_2 - 2.

Substituting this into the expression for a, we get:

a = (b_1)^2 + 2b_1 = (-b_2 - 2)^2 - 2(b_2 + 2) = b_2^2 + 2b_2 - 4.

Therefore, a - b_2^2 - 2b_2 + 4 = 0, or equivalently, (a-2)/3 = (b_2+1)^2, which implies that a-2 is a perfect square multiple of 3. Since b_2 can be any real number, this restriction on a is necessary and sufficient.

In summary, the value of a for which the given quadratic equation has a unique real solution is a = b^2 + 2b, where b is any real number except b = -1/2. Equivalently, a can take any value except a = 2/3.

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Answer:

Step-by-step explanation:

I just tried numbers

2     1

2     6           first grid, so 2nd column is 7

or

1  2

3 5        also 7