a parallel-plate capacitor with a dielectric inserted is connected to a battery and allowed to fully charge. a second identical capacitor but with a dielectric of only half the dielectric constant as the previous is connected to an identical battery and allowed to fully charge. how do the two capacitors compare in terms of capacitance, electric potential, charge stored, and energy stored? justify with reasoning.

Answers

Answer 1

The capacitance and electric potential of the two capacitors are identical.

The charge stored and energy stored are also identical, as are the two capacitors' dielectrics.

The reason for this is that both capacitors have the same area, which is equal to the product of their radii multiplied by the distance between them. The two capacitors also have the same charge per unit area. So when you divide one by the other, you get a ratio of 1:1. This means that regardless of which capacitor you choose, it will store an equal amount of energy.

Additionally, if you choose to measure your capacitance by dividing your electric potential by your charge per unit area, then again, both capacitors will have identical values for this metric as well.

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Related Questions

what is the relation between the current through the resistor and the voltage drop across the resistor

Answers

By way of Ohm's Law, the voltage drop is proportional to the cutting-edge flowing thru a resistor. (So in numerous collection resistors with the same resistance, the drop across each one is identical, because the present day throughout each one is equal).

The connection between the current, voltage, and resistance is expressed through Ohm's regulation. This states that the modern-day flowing in a circuit is at once proportional to the implemented voltage and inversely proportional to the resistance of the circuit, provided the temperature stays steady.

Resistors in the collection deliver identical cutting-edge, however, the voltage drop throughout them isn't the same as their man or woman resistance values will create one-of-a-kind voltage drops across every resistor as decided by way of Ohm's regulation ( V = I*R ).

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The kinetic energy of a baseball that with a mass of 0.140kg is 7 J. What is the baseballs velocity?

Answers

Answer:

10 m/s

Explanation:

Kinetic energy= [tex]\frac{1}{2}[/tex]mv² where m is mass and v is velocity.

We have to make v the subject so we should rearrange the equation

K=[tex]\frac{1}{2}[/tex]mv²

v²= [tex]\frac{K}{0.5*m}[/tex] (use algebra)

v²= 7/0.5×0.140

v²=100

v=√100

v=10 m/s

We can confirm this by using the kinetic energy formula.

K=[tex]\frac{1}{2}[/tex]×0.140×10²

K= 7 J

Hence it is proved that velocity is 10 m/s

AP physics 1: Extra points!!

Answers

The weight of box 2 and box 3 is 33.72N and 15.32N

According to Lami's Theorem, if three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two forces. The magnitudes of concurrent, coplanar, and non-collinear forces that keep an object in static equilibrium are all related to Lami's Theorem. This theorem also aids in the analysis of most mechanical and structural systems. For all three forces used in Lami's Theorem, the proportionality constant is the same.

Given box1 weighs 31N

Given two angles 63 and 24

So the third angle will be

180 – 87

= 93

By using Lamis theorem

T_2/(SIN 93)=T_3/(SIN (90+63))=T_1/(SIN (90+24))

Here T1 = 31N

Weight of box 2 = w2 = 31/cos24 x sin 93

= 33.72

Weight of box 3 = w3 = 31/cos24 x cos 63

= 15.32

Therefore the weight of box 2 and box 3 is 33.72N and 15.32N

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Compare the use of an electric bicycle with a normal bicycle used
to cycle a 5 km uphill route. The cyclist does not pedal when using
the electric bike to cycle uphill.
Information about the two bikes is given in Table 1.
Table 1
Information
power of the motor
force used to drive the
bicycle forward
weight of bicycle
battery life
time to travel 5 km
Electric bicycle
350 W
50 N
190 N
25 minutes
12 minutes
Ordinary bicycle
no motor
47 N
120 N
no battery
13 minutes
Your answer should contain descriptions of work done, energy
transfers, and power.

Answers

The work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.

W = F d cos θ

P = W / t

W = Work done

F = Force

d = Distance

P = Power

t = Time

θ = 0

d = 5 km = 5000 m

For Electric bicycle

F = 50 N

t = 12 min = 720 s

W = 50 * 5000 * cos 0

W = 250000 J

W = 250 KJ

P = 250 / 720

P = 0.35 KW

For ordinary bicycle,

F = 47 N

t = 13 min = 780 s

W = 47 * 5000 * cos 0

W = 235000 J

W = 235 KJ

P = 235 / 780

P = 0.3 KW

Therefore, the work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.

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a 3 kg block starts from rest at the top of a 30 degree incline and slides a distance of 2 m down the incline in 1.50 seconds. find the magnitude of the acceleration of the block. find the coefficient of kinetic friction between the block and the ramp.

Answers

The magnitude of the acceleration of the block is 1.78m/s².

The coefficient of kinetic friction between the block and the ramp is  0.368.

How can I calculate the coefficient of kinetic friction?

The resistive force of friction (Fr), which pushes the objects together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. The following formula represents it: fr = Fr/N.

Given,

m=3.00kg, θ=30° ,

x= 2.00m, t=1.50s.

constant rate of acceleration,

[tex]X_{f} = v_{i} t[/tex] + 1/2at²

solving,

a = 2([tex]X_{f}[/tex]-[tex]v_{i} t[/tex])/t²

a = 2(2-0)/(1.5)²

a = 1.78m/s².

We have neither a burrowing-in nor a taking-off action when Newton's law is applied in the y direction, which is perpendicular to the inclination. The y component of acceleration is then equal to zero:

 ∑ [tex]F_{y}[/tex]=n–mgcosθ=0

Thus n=mgcosθ

Because  f=[tex]\mu_{k}[/tex]n

[tex]\mu_{k}[/tex] = f/mgcosθ

[tex]\mu_{k}[/tex] = 9.37/3×9.8×cos30°

[tex]\mu_{k}[/tex] = 0.368.

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3. The average human walks at a speed of 5 km per hour. If your PE teacher asks you to
walk for
40 minutes in
gym class, how far would you walk (km)?

Answers

The average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.

What is Average speed?

The average speed is the  displacement of a particle divided into a time in which the displacement occurs. Instead, instantaneous speed is the limit of the average speed as the time interval approaches zero.

Usually,

Speed = Distance/ Time

Assuming you also walk with the average human walking speed of 5 km/h. We know the above formula of speed and now making distance the subject, distance is a product of speed and time.

Here, time is 40 minutes and if expressed in hours can be converted as,

40/60 = 0.6 hours.

Distance = 5 × 0.6

             = 3 km

Thus,the average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.

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what is the purpose of the frets on a guitar. in terms of the frequency of the vibration of the strings

Answers

To learn frequency to known frequency and frets of guitar.

What is frequency?

The number of waves that pass a fixed point in a unit of time is referred to as frequency in physics. It also describes how many vibrations or cycles a body in periodic motion makes in a given amount of time.

What is the purpose of frets?

Frets, which determine the positions for the proper notes, make it much simpler for a player to achieve an acceptable standard of intonation. Furthermore, playing chords accurately is made simpler by a fretted fingerboard.

Frequency of the vibrations of the strings.

f=2LnmT, where T is the tension in the string, L is the length, and n is the number of harmonics, gives the frequency of vibration of a string.

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everyday application: suppose a yo-yo has a center shaft that has a 0.250 cm radius and that its string is being pulled. (a) if the string is stationary and the yo-yo accelerates away from it at a rate of , what is the angular acceleration of the yo-yo? (b) what is the angular velocity after 0.750 s if it starts from rest? (c) the outside radius of the yo-yo is 3.50 cm. what is the tangential acceleration of a point on its edge?

Answers

If it starts at rest, the angular velocity after 0.750 is 5.1. The symbol for angular velocity in SI units is s1.

Explain about the angular velocity?

When an object rotates or circles around an axis, its angular velocity is the rate at which the angle between the two bodies changes. The angle that is made by a line on one body and a line on the other in the illustration represents this displacement.

Examples of angular velocity include a roulette ball on a wheel, a race car travelling in a circle, and a Ferris wheel. In addition, the object's angular displacement with respect to time is represented by the angular velocity of the object.

Since the radian is a dimensionless quantity and the SI unit of angular velocity is radians per second.

Angular acceleration

a = a /r

 = 1.7/0.250

a =6.8

Angular velocity

omega = a*t

            = 6.8 *0.75

           =5.1

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Highlight (1) calculator
Species
0 0
Harbor seals live off the coast of New England and feed on various fish, squid, shrimp, and other marine life. A sea
approaches a school of fish consisting of mackerel, herring, and harbor pollock. The population of each species is
shown in the table.
mackerel
herring
harbor pollock
What is the probability the seal catches a mackerel?
You may use the calculator.
25%
20%
15%
33%
Elag for Review Normal Color Scheme
Population
15
23
37

Answers

There is 20% probability that the seal catches a mackerel.

What is probability?

How likely something is to occur is known as its probability.

To determine probability, divide the total number of possible outcomes by the number of possible ways an event could occur. There are differences between probability and odds. Odds are calculated by dividing a situation's likelihood of occurring by its likelihood of not occurring.

Given,

mackerel 15

herring 23

harbor pollock 37

probability = possible event/ no. of event

probability = 15/ 15+23+37

probability = 15/ 75

probability = 0.2

∴ probability is 20%

For numbers less than 1 out of 1,000 (such as 0.20 out of 1,000), it is clearer to recast them as “200 out of 10,000” (“2 out of 10,000,” for instance).

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what is the speed of the 0.100 kg sphere when it has moved 0.400 m to the right from its initial position?

Answers

6.01 × 10⁻⁵ m/s is speed of 0.100 kg sphere when it has moved 0.400 m to right from its initial position.

What is conservation of energy?

The conservation of energy principle states that in a closed system, the energy of interacting objects or particles remains constant. Kinetic energy, sometimes known as the energy of motion, was the first type of energy to be identified. The sum of the kinetic energy of the particles before collision and the sum of the kinetic energy of the particles after collision are equal in some particle collisions, known as elastic collisions. Progressively, more types of energy were added to the definition of energy.

We have from the conservation of energy,

[tex]E_{i}[/tex] = [tex]E_{f}[/tex]

[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.4}[/tex] - [tex]\frac{G(10*0.1)}{0.6}[/tex]

[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.8}[/tex] - [tex]\frac{G(10*0.1)}{0.2}[/tex] + 1/2 × 0.1v²

∵ [tex]E_{i}[/tex] = [tex]E_{f}[/tex]

= 1/2 × 0.1 × v² = G (5×0.1) (1/0.8 - 1/0.4) + G (10 × 0.1) (1/0.2 - 1/0.6)

∴ v = 6.01 × 10⁻⁵ m/s

Speed of the object moved from its initial position is 6.01 × 10⁻⁵ m/s.

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a flight attendant pulls her 2 kg flight bag a distance of 23 m along a level airport floor at a constant velocity. the force she exerts is 8 n at an angle of 30 degrees above the horizontal. find the work she does on the flight bag.

Answers

Work done on the flight bag will be 182.20 J.

Work done defined as the product of force and distance covered due to applied force.

The mass of flight bag m = 2 kg

Therefore the weight of the bag will be 2*g = 2*10 = 20 N

(g = acceleration due to gravity = 9.81 m/s2)

The distance covered by the bag is, d = 23 m.

The magnitude of force exerted on bag is, F = 8 N.

The angle of inclination with horizontal = [tex]\alpha[/tex] = 8°

The work done on the flight bag is given by the equation:

W = F * d *Cos [tex]\alpha[/tex]

W = 8 * 23 * Cos8

W = 182.20 J

Thus, the work done by the attendant on the flight bag is 182.20 J.

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a 1500 kg vehicle is traveling on a curved, icy road. the road is banked at an angle of 10.0 degrees and has a radius of curvature of 400 m. the velocity of the car necessary to travel on the icy road without sliding is .

Answers

The vehicle speed required to drive on an icy road without sliding is 28.3 m/s.

The weight of the car is m = 1500 kg

The angle at which the road is inclined is θ = 10

The radius of curvature is r = 400m

The expression for the speed of the car required to travel on the road without sliding is V =[tex]\sqrt{rgtan}[/tex]

V =[tex]\sqrt{400*9.8*tan10}[/tex]

V = 28.3 m/s

Velocity is the rate of change in direction of an object in motion measured by a specific time standard and observed from a specific reference point (for example, 60 km/h north). A key idea in kinematics, the branch of classical mechanics that studies the motion of bodies, is velocity.

The definition of velocity requires both its magnitude and its direction, since it is a physical vector quantity. Velocity is a coherently derived unit that is measured in the SI (metric system) as meters per second (m/s or m/s1). Velocity is a scalar absolute value (magnitude) of speed.

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what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h .)

Answers

She will pull her ripcord 22.9 s after the dive and her speed at 490 m will be 112.66 m/s.

What is free-fall?

Free fall, any motion of a object where gravity is the only force acting upon it. In the context of general relativity, where gravity is reduced to the curvature of spacetime, there are no forces acting on bodies in free fall.

For the given case,

s = ut + 1/2 at²

s = Displacement  (3000 - 420 = 2580 m) it is the distance she will free fall

a = Acceleration due to gravity  (9.8 m/s²)

u = Initial velocity (0 m/s)

t = Time taken

2580 = 0×t + 1/2 9.8 t²

2580 = 4.9 t²

t = 22.9 s

Now her speed at 490 m will be

v = d/t

v = speed

d = 2580 m

t = 22.9 s

v = 2580/22.9

v = 112.66 m/s

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The given question is incomplete so the complete question is as follows:

"if there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3100 m to an altitude of 490 m , where she will pull her ripcord? what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h)"

Which variable is NOT shown on a velocity-time graph?

Answers

Acceleration is the variable that is NOT shown on a velocity-time graph

Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is

acceleration = change in velocity / time

hence , the derivative of velocity is acceleration

which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph

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a mass m is attached to an ideal massless spring. when this system is set in motion with amplitude a, it has a period t. how does the period of the motion change if the amplitude of the motion is increased to 2a? explain.

Answers

System is set in motion with an amplitude of a and a period of T. If the amplitude of the motion is increased to 2a, the period of the motion changes.

A straightforward harmonic oscillator's period is independent of its amplitude. with the graphs of acceleration and velocity produced by the time derivatives. These oscillators also show how kinetic and potential energy can be transferred.

The acceleration of the mass increases proportionally with the increase in force, causing the mass to travel farther in the same amount of time. Therefore, increasing the amplitude has no overall impact on the oscillation's period.

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Stan argues that momentum cannot be conserved when a collision is not a head-on collision. Rachel insists it is conserved because each body receives an impulse of equal magnitude. Rachel is correct because.

Answers

Rachel is correct because she said that is body receive equal magnitude of impulse which completely satisfy the law of conservation of linear momentum.

According to law Conservation of Linear Momentum, if there is no external force working on the system, then the linear momentum remains conserved before and after the collision.

We know that,

Momentum is nothing but the product of force and the time taken for the contact period of the colliding bodies.

We assume that during the head on collision of the body, the body is remain in contact for such a short period of time that there is no external force all the impulse created due to the external force is neglected.

So, because the impulse imparted on both the bodies are equal to each other.

We know that impulse is nothing but the change in momentum.

So, from here we conclude that bodies received equal magnitude of impulse.

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a 70 kg man is floating at rest near his spaceship. he throws a 1.5 kg wrench away from the ship at a speed of 10 m/s in order to move himself toward it. with what speed does he move toward the ship?

Answers

0.218 m/s speed does he move toward the ship.

use the formula from conservation of Momentum

mu  + MV  =  (m-M)V'

u  =  o

so

MV  =  (m-M)V'

V'  =  (1.5 * 10)/(70-1.5)

V'  =  0.218 m/s

What is speed?

The most crucial scientific notion is measurement. Base or physical fundamental units are used to quantify a wide range of quantifiable quantities. One such measurable metric is speed, which calculates the ratio between the distance an object travels and the time needed to cover that distance. Let's explore speed in-depth in this session.

The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

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four resistors having a value of 100 ohms each are connected in parallel. what is the total resistance of the circuit?

Answers

The total resistance of the circuit is 25 ohms.

How can the resistance of a circuit with four resistors in parallel be determined?

In the same way, if three or more resistors of the same value are connected in parallel, the equivalent resistance will be equal to R/n, where R is the resistor's value and n is the total number of resistors in the arrangement.

How do you calculate a parallel resistor's total resistance?

The total current flowing from the source is the sum of the currents through each of the paths. Using the following formula, you can get the overall resistance in a parallel circuit: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... Even if one of the parallel channels breaks, current will still flow.

[tex]R_{total}[/tex] = 100/4 = 25ohms

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a lawn roller is rolled across a lawn by a force of 115 n along the direction of the handle, which is 22 above the horizontal. if george develops 64.6 w of power for 90.0 s, what distance is the roller pushed?

Answers

The distance roller pushed is 54.7 meter when a lawn roller is rolled across a lawn by a force of 115 N along the direction of the handle.

What is distance and force and what distance is the roller pushed ?Distance is the quantity representing the product of speed and time of the motion under given time period.Force is a newtonian quantity representing the product of mass and acceleration .Here the lawn roller is rolled across a lawn by force 115 N , the force along the horizontal would be F = 115 cos 22 = 106.60.Power = force x speed, P = 115 x speed, 64.6 = 115 x speed , speed = 64.6/115 = 0.56 m/s.Distance = speed x time = 0.56 x 90 = 54.7 meters, hence the distance roller pushed is 54.7 meters.Therefore when a lawn roller across a lawn by force of 115 N the distance roller pushed will be 54.7 meter.

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The rising concern among athletic trainers and health advocates (and parents) regarding concussions and multiple concussions among high school football players has prompted numerous studies of the effectiveness of protective head gear and the forces and accelerations experienced by players. One study suggested that there is a 50% chance of concussions for impacts rated at 75 g's of acceleration (i.e., 75 multiplied by 9.8 m/s/s). The average head impact in football results in 22 to 24 g's of acceleration ... but not all head impacts are equal.

If a player's head mass (with helmet) is 5.41 kg and considered to be a free body, then what net force would be required to produce an acceleration of 75 g's?

Answers

Answer:

Explanation:

Given:

m = 5.41 kg

g = 9.8 m/s² - acceleration of gravity

a = 75·g = 75·9.8 ≈ 735 m/s²

__________________

F - ?

Newton's second law:

F = m·a

F = 5.41·735 ≈ 3 980 N

a string is under a tension of 760.0 n. a 1.7 m length of the string has a mass of 4.8 grams. what is the speed of a transverse wave of wavelength 0.50 m in this string? what is the frequency of the wave?

Answers

The number of waves that pass by each second is the frequency of a wave, which is expressed in Hertz (Hz). For instance, a sound wave may have a frequency of 450 Hz.

Explain about the frequency of wave?

The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second. When two waves of equal amplitude and frequency are compared, the higher frequency wave has greater energy.

Divide the wave's velocity by its wavelength to determine its frequency. The unit for frequency is Hertz (Hz), so use that while writing your response. The frequency will be the inverse of the time, or 1 divided by T, if you need to determine it from the amount of time it takes for a wave cycle to complete, or T.

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If you know the acceleration and time, how can you calculate the average velocity?.

Answers

The average velocity in terms of acceleration and time is 1/2at².

Average velocity:

Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

Assume the acceleration a is uniform then:

v(t) = u + at

u = initial velocity

By average velocity v we mean average over time than strictly speaking:

v = 1/t [tex]\int\limits^t_0 {v(t)} \, dt[/tex]

  = 1/t [tex]\int\limits^t_0 {(u + at)} \, dt[/tex]

  = 1/t ( ut + 1/2 at²)

 v = u + 1/2at²

If u =0, then we have

v = 1/2 at²

Therefore the average velocity is 1/2at².

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the bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity at g. the bucket is pinned at e (figure 1).

Answers

Answer:

1200

Explanation:

a 0.13- kg block on a wooden table is given a sharp blow with a hammer. the block then slides across the table to a stop. the coefficient of friction between the block and table is 0.33. the hammer's force on the block as a function of time is well approximated by an isosceles triangle with it's base on the horizontal time axis. the length of the base is 0.0067 s and the maximum force is 37.6 n. how far does the block go? use a graphical technique

Answers

The length of the base is 0.0067 s and the maximum force is 37.6 n.1.45 ×10^-1 m far does the block go.

When we use graphical method then we can feel that, here the area of the isosceles triangle will give us the change in the momentum, also as here the initial velocity is zero,

so that let the final velocity is V then,

we have

m*V= area of the triangle

or

0.13* V = area of the triangle = 1/2 * base * height                             =0.5*0.0067*37.6= 0.1258 kg m/s

so V = 0.968 m/s

the frictional force is = mg(0.33)

let the distance required is X then using conservation of energy here we have

KINETIC ENERGY = FRICTIONAL ENERGY.

1/2mV2 = mg(0.33) *X

X= V^2 / ( 2g*0.33) = 0.1450 m = 1.45 ×10^-1 m

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an art student is designing a large mobile with the dimensions shown below. object c has a mass of 1 kg, and objects b and c are in balance. what does the mass of object a need to be to balance objects b and c?

Answers

The mass of object a need to be to balance objects b and c is 12kg

Find man of b

1=[tex]\frac{m_{c}}{m_{b}+m_{c}}[/tex]×4

1=[tex]\frac{1}{1+m_{b} }[/tex]×4

[tex]m_{b}[/tex]=3kg

1=[tex]\frac{(m_{b}+m_{c} )}{m_{a} +(m_{b} +m_{c} )}[/tex]  ×4

1=4×4/[tex]m_{a}[/tex]+4

[tex]m_{a}[/tex]=12kg

As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilogram is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one-kilogram times one square meter per second. The kilogram is determined by precise measurements of Planck's constant, while the second and metre are previously defined in terms of other physical constants.

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a charged particle, passing through a certain region of space, has a velocity whose magnitude and direction remain constant. if it is known that the external electric field is zero everywhere, then can you conclude that the external magnetic field is also zero? ignore gravity.

Answers

YES, if it is known that now the external electric field equals zero everywhere, then you can infer that external magnetic field also is zero.

In plain terms, how is a magnetic field?

The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.

What are the workings of the magnetic field?

The vicinity of a magnet that exhibits magnetic force is known as the magnetic field. South and north poles are found on every magnet. The opposite poles are drawn to one another, whereas the same poles are drawn away from one another. The atoms in iron have north-seeking poles that line up in the exact direction when it is rubbed against a magnet.

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A basketball hoop is 3.05 m above the playing surface. A basket is made. The ball reached a maximum height that was 2.00 m above the height of the basket hoop. The basketball was launched from a height of 1.95 m. If the ball traveled a horizontal distance of 5.20 m in 2.00 seconds, what was the initial velocity of the basketball?

Answers

Answer:

In this question, we have given a basketball hoop that is 3.05 m above the playing surface and the basket is made. The basketball was launched from a height of 1.95 And if the ball travels the original distance of 5.2 m in two seconds, then we have to find the initial velocity of the basketball. So we can find given data is we have given the horizontal distance traveled, that is d is equals to 5.2 m Per meter. And we have given the time taken to cover this distance, that is T equals to two seconds. So we can find the original velocity. So we can see that horizontal velocity that is three X is equal to, this is 5.2 upon two, and this will come out to be 2.6 meter per second. Now we can see that as we have given That the basketball hoop is 3.05 m above the playing surface. So we can say that the height covered, that is delta edges 3.5 minus 1.95. And this will comes out to be 1.10 m. So, using the equation of motion, we can find the vertical velocity Y. So we can say that that is is, we can apply in and wind direction. So we can say that delta edge is equals to this is initial velocity in y direction into time, T plus half into exhalation in y direction into T square. So we can say this is equals to 1.10, that is we're not y and to time is two seconds blood half into disease. Here, exploration is the gravitational acceleration and it is acting downwards. So this is equal to -3, which is -9.8 into two square. So from here we can find the value of velocity in the Y direction. That is 10.35 m/s. So we have the velocity in X direction and velocity in the Y direction. So we can see that the initial velocity that is we note is equal to this under root of we're not in extraction plus we're not wise square. So we can say this is equal to under root of 2.60 sq Plus 10.35 ft sq. And this will comes out to be 10.67 m/s. But this is the answer of arguing cushion. Thank you.

How many g are in a pack containing 10 tablets of 500 mg each? *
5g
50g
100g
500g​

Answers

Answer:

5 g

Explanation:

500 mg x 10 = 5000 mg

5000 x 10^-3 g = 5 g

Hello..!

To solve the problem and calculate the number of pills in the package, we will use the conversion factor.

The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.

Find out that 1 gram has a total of 1000 mg.

Problem:

How many g are in a carton containing 10 tablets of 500 mg each?

According to the previous text we can say that the conversion factor would be:

[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]

Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:

[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]

We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:

[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]

We conclude that one box contains 5 grams of tablet, option 1.

[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]

consider a 20 kg sphere with a 10 cm radius. what weight would a scale read if the sphere was totally submerged in water?

Answers

The weight the scale would read if the sphere of mass 20 kg with a 10 cm radius was totally submerged in water is 155.1 N

Fg = m g

Fb = ρ V g

Fg = Force of gravity

Fb = Buoyant force

m = Mass

g = Acceleration due to gravity

ρ = Density of medium

V = Volume of object

m = 20 kg

g = 9.8 m / s²

ρ = 1000 kg / m³

r = 10 cm = 0.1 m

Fg = 20 * 9.81

Fg = 196.2 N

Fb = ρ ( 4 / 3 π r³ ) g

Fb = 1000 * 4 / 3 * 3.14 * 0.1³ * 9.8

Fb = 41.1 N

N = Fg - Fb

N = Scale reading

N = 196.2 - 41.1

N = 155.1 N

Therefore, the scale reading if the sphere was totally submerged in water is 155.1 N

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If the man pulls the sled with a 10 N
force, what is the horizontal component
of force? Refer to chapter 4, mechanics if
you do not remember how to resolve a
force into its components.

Answers

Answer:

   

Explanation:

The horizontal component of force is Fcosθ if the man pulls the sled with a 10 N force.  Force has both a magnitude and a direction since it is a vector quantity.

What is force?

A force is an external cause that, when applied, alters or has the potential to alter a body's condition. The body comes to rest while it is moving, and it moves when it is at rest.

The body's orientation, form, size, etc. may also alter as a result. An illustration would be to push or forcefully shove a door. Force has both a magnitude and a direction since it is a vector quantity. If the man pulls the sled with a 10 N force then the horizontal component of force is Fcosθ. Your training at this level should place a major emphasis on the idea that a push or even a pull was referred to as an force.

Therefore, the horizontal component of force is Fcosθ if If the man pulls the sled with a 10 N force.

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