a particle undergoes simple harmonic motion of amplitude and frequency . what is the average speed of the particle during one oscillation?

The magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.

Each location in space where a charge exists in any form can be considered to have an electric field attached to it. The electric force per unit charge is another name for an electric field. Variable magnetic fields or electric charges are frequently the cause of electric fields. Volts per metre (V/m), a unit used in the SI, is used to express electric field strength. The force acting on the positive charge is assumed to be exerted in the direction of the pitch. The electric field is directed radially inwards towards negative point charge and radially outwards from positive charge.

Electric field = 1.20 n/c

r= 1.60 m

[tex]E=\frac{q}{4\pi E_{o}*r^{2} } \\q=4\pi E_{o}*E*r^{2} \\=\frac{(1.20 n/c)((1.60m)^{2} }{8.99*10^{9}N.\frac{m^{2} }{C^{2} } } \\=0.341*10^{-9} C[/tex]

Therefore, the magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.

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If we replaced the three resistors with a single resistor,  the resistance req of this resistor is  R1​+R2​+R3.For the series combination of resistances, here the second end of each resistance is attached to the first end  of the following resistance and the setting goes  so on

In a series circuit of resistors, the current that runs through every one of them is identical and is equivalent to the current provided by the battery. Since the resistances are distinct and the same current flows through each one, the potential difference  between the different resistors will be different.

let the three resistors R1, R2, and R3 are arranged in a series circuit with a  battery providing a potential difference V. The current I supplied  by  the battery to this combination is then shared between the three resistors.Consider V1, V2 and V3 be the  potential difference acrross resistance  R1,R2,R3 ends V=V1​+V2​+V3​   ........(1).

Considering the replaced  resistance be R,  by ohm's law V=IR,V1​=IR1​,V2​=IR2​,V3​=IR3​, so substituing those in equation 1 we get :

I=IR1​+IR2​+IR3​

IR=I(R1​+R2​+R3​)

R=R1​+R2​+R3​

In conclusion, the replaced resistor resistance  is the sum of the individual  resistances

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Weight Density 1 = 38107 N/m³

Weight Density 2 = 38107 N/m³

The formula for volume of cylinder is:

V = πr²l

where,

V = Volume

r = radius

l = length of cylinder

So, if length has the 3 significant figures which is least in all values, Then the volume must also be in 3 significant figures. The formula for weight density is:

Weight Density = Weight/Volume

Here, the volume has the least significant figures of 3, therefore, the weight densities must also have 3 significant figures:

Weight Density 1 = 38123 N/m³

Weight Density 1 = 38124 N/m³

Weight Density 1 = 38107 N/m³

Weight Density 2 = 38123 N/m³

Weight Density 2 = 38124 N/m³

Weight Density 2 = 38107 N/m³

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They both had the same potential energies. This is because everyone can be found in the same location.

Describe potential energy.

An object or set of things may have potential energy stored in them depending on their size, form, location, or even the material they are constructed of. Find out what potential energy is and the various kinds that an object might have.

There was a difference in the average amount that the box slid after catching the marble when comparing the marbles. The more kinetic energy I have, the greater the impact it has and, as a result, the further the box will slide away. At the end of the ramp, the kinetic energy between them is NOT equal. Because of its greater mass, kinetic energy has larger potential. Distance reveals the outcome.

My data indicate that both of my hypotheses for each experiment are true. My theory for the initial trial was that moving the box by 40 cm would be the most effective. Considering that the average distance was the greatest of all, this was in fact true. The second experiment was conducted similarly. My hypothesis for the second experiment was that the more the marole's mass, the greater the box's distance.

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The two types of forces that act on a fluid element is body forces and surface forces.

A body force is a force that acts throughout the volume of a body.( 1) Forces due to graveness, electric fields and glamorous fields are exemplifications of body forces. Body forces discrepancy with contact forces or face forces which are wielded to the face of an object.

Normal forces and shear forces between objects are superficial forces as they're wielded to the face of an object. All cohesive face magnet and contact forces between objects are also considered as face forces.

Face force denoted fs is the force that acts across an internal or external face element in a material body. face force can be perished into two vertical factors normal forces and shear forces. A normal force acts typically over an area and a shear force acts parenthetically over an area.

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If a body puts a 400 N force on a rope, the rope likewise exerts a 400 N force on the body. As a result, the tension in the rope is 400N.

This is determined by whether both persons are tugging in the same direction against a fixed object or against each other. When both forces are applied in the same direction, the total force is 300 N + 300 N = 600 N. If two persons pull on the rope at the same time, the total force in the rope is 300 N, or a net of zero. Newton's third law of motion deals with these two forces, which are known as action and reaction forces. The rope is used to transfer forces in this activity. The action force is the first team to tug, generating the draw on the rope; as the response force, the opposing team's rope end "feels" the pull.

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A piece of rope is pulled by two people in a tug-of-war. each pulls with 400 n of force, the tension in the rope is 400N.

Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable. Tension can be defined as an action-reaction pair of forces acting at each end of the said elements.

If one of the forces exerting an object is a rope, cable or chain, you can call it tension. Cables and Ropes can be used for exerting forces since they can efficiently transfer a force over a specific distance (e.g. the rope length). Please note that tension is the pulling force since ropes cannot push effectively.

This is determined by whether both persons are tugging in the same direction against a fixed object or against each other. When both forces are applied in the same direction, the total force is 300 N + 300 N = 600 N.

The SI unit of Surface Tension is Newton per Meter or N/m.

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Seawater has sound travelling at a substantially higher speed than air. The speed of sound in air is roughly 343 metres per second at a temperature of 25 °C.

The sound speed in the oceans fluctuates between 1,450 and 1,570 metres per second (or 4,760 and 5,150 feet per second). With every 1 °C increase in temperature and every 1 psu increase in salinity, it grows by around 4.5 metres (about 15 feet) and 1.3 metres (about 4 feet) every second, respectively.

In water, sounds move more quickly than in the air. Because the particles are considerably closer together, They may quickly transfer vibrational energy from one particle to the next because of the water. Sound generally travels through water four times more quickly than through air.

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Answer:

  6 units

Explanation:

You want the gravitational force between two objects after both the mass of one object and the distance between them triples, if it is initially 18 units.

Let F represent the initial force between the objects. Newton's law of gravitational attraction tells us ...

  F = GmM/r²

When one mass is tripled, and the distance between the objects is tripled, the new force is ...

  F' = G(3m)M/(3r)² = 3/9(GmM/r²) = F/3

Given the initial force is 18 units, the new force of attraction is ...

  F' = (18 units)/3 = 6 units

The new gravitational force of attraction between the objects is 6 units.

It takes 2.07 seconds for the car to cover a distance of 50.0 meters while accelerating at a uniform rate of 4.00 m/s^2.

We can use the kinematic equation to solve for the time required to cover the distance.

Here's the kinematic equation that we'll use:

d = vi * t + 1/2 * a * t^2

where:

d = distance traveled (in meters)

vi = initial velocity (in meters per second)

a = acceleration (in meters per second squared)

t = time (in seconds)

We want to solve for t, so we'll rearrange the equation to isolate t:

d = vi * t + 1/2 * a * t^2

50.0 m = 20.0 m/s * t + 1/2 * 4.00 m/s^2 * t^2

50.0 m = 20.0 m/s * t + 2.00 m/s^2 * t^2

Now we have a quadratic equation in the form of ax^2 + bx + c = 0, where:

a = 2.00 m/s^2

b = 20.0 m/s

c = -50.0 m

We can use the quadratic formula to solve for t:

t = (-b ± sqrt(b^2 - 4ac)) / 2a

Plugging in the values for a, b, and c, we get:

t = (-20.0 ± sqrt(20.0^2 - 4(2.00)(-50.0))) / 2(2.00)

t = (-20.0 ± sqrt(400 + 400)) / 4.00

t = (-20.0 ± 28.28) / 4.00

We have two solutions because of the ± sign. However, we know that time cannot be negative, so we'll take the positive solution:

t = (-20.0 + 28.28) / 4.00

t = 2.07 seconds

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When two sources of waves with the same frequency are active, the path length difference must be equal to some whole multiple of the wavelength plus one half the wavelength for the waves to interfere destructively.

This is because in order for two waves to interfere destructively, they must be exactly out of phase with each other. When waves are out of phase, the crest of one wave lines up with the trough of the other, resulting in a cancellation of the waves. This occurs when the path length difference between the two waves is equal to an odd multiple of half wavelengths. For example, if the distance between the two sources is exactly one wavelength, then the waves will interfere constructively, resulting in a stronger wave. However, if the distance is increased to one and a half wavelengths, then the waves will interfere destructively, resulting in a weaker or canceled wave. This pattern repeats for all odd multiples of half wavelengths.

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The post-collision velocity of the first billiard ball is 272 cm/s.

Velocity is a vector quantity that describes an object's speed and direction of motion.

We can solve this problem by using the law of conservation of momentum, which states that the total momentum of an isolated system remains constant.

The momentum of an object is defined as the product of its mass and velocity:

p = m * v

The total initial momentum of the system is the sum of the momenta of the two billiard balls before the collision:

p_initial = m * v1 + m * v2

where m is the mass of each billiard ball, v1 is the initial velocity of the first billiard ball, and v2 is the initial velocity of the second billiard ball.

After the collision, the first billiard ball will rebound with a velocity v1', and the second billiard ball will rebound with a velocity v2'. The total final momentum of the system is the sum of the momenta of the two billiard balls after the collision: p_final = m * v1' + m * v2'

Since the law of conservation of momentum applies, we can set the initial momentum equal to the final momentum

p_initial = p_final

Substituting the given values, we get:

m * v1 + m * v2 = m * v1' + m * v2'

Simplifying, we get:

v1' = (m * v1 + m * v2 - m * v2') / m

v1' = v1 + (v2' - v2)

Plugging in the given values, we get:

v1' = 154 cm/s + (72 cm/s - (-46 cm/s))

v1' = 272 cm/s

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a) The energy stored in the capacitor is 5.10 × 10⁻¹⁰ J.

b) The energy stored in the capacitor with the dielectric inserted is 1.04 × 10⁻⁹ J.

c)  The energy stored in the capacitor with the dielectric inserted and the battery disconnected is 2.14 × 10⁻¹⁰ J.

The energy stored in a parallel-plate capacitor is given by the formula:

U = [tex]\frac{1}{2}CV^2[/tex]

where U is the energy stored, C is the capacitance, and V is the voltage across the capacitor.

(a) The capacitance of a parallel-plate capacitor is given by the formula:

C = [tex]\frac{\epsilon_0A}{d}[/tex]

where [tex]\epsilon_0[/tex] is the permittivity of free space, A is the area of the plates, and d is the distance between them.

Substituting the given values, we have:

C =[tex]\frac{(8.85 \times 10^{-12} \textrm{ F/m})(2.00 \times 10^{-4} \textrm{ m}^2)}{5.00 \times 10^{-3} \textrm{ m}} = 7.08 \times 10^{-12} \textrm{ F}[/tex]

The voltage across the capacitor is given by the battery voltage, which is 12.0 V. Substituting these values into the formula for energy, we have:

U = [tex]\frac{1}{2}(7.08 \times 10^{-12} \textrm{ F})(12.0 \textrm{ V})^2 = 5.10 \times 10^{-10} \textrm{ J}[/tex]

(b) When a dielectric is inserted between the plates, the capacitance increases. The new capacitance is given by the formula:

[tex]C' = \kappa C[/tex]

where [tex]\kappa[/tex] is the dielectric constant of the material.

Substituting the given values, we have:

[tex]C' = (2.56)(7.08 \times 10^{-12} \textrm{ F}) = 1.82 \times 10^{-11} \textrm{ F}[/tex]

The voltage across the capacitor remains the same, so the energy stored in the capacitor becomes:

[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(12.0 \textrm{ V})^2 = 1.04 \times 10^{-9} \textrm{ J}[/tex]

(c) If the battery is disconnected before the dielectric is inserted, the charge on the plates remains the same. However, the voltage across the capacitor decreases due to the increased capacitance. The new voltage is given by the formula:

[tex]V' = \frac{V}{\kappa}[/tex]

Substituting the given values, we have:

[tex]V' = \frac{12.0 \textrm{ V}}{2.56} = 4.69 \textrm{ V}[/tex]

The energy stored in the capacitor becomes:

[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(4.69 \textrm{ V})^2 = 2.14 \times 10^{-10} \textrm{ J}[/tex]

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The largest object in the asteroid belt is ceres with a radius of 470 km and a mass of [tex]9.384*10^2^0 kg[/tex]. The weight of a 160. kg astronaut standing on ceres is 43.2 N.

The weight of the astronaut on Ceres can be calculated using the formula:

w = m * g

here,

w is weight of the astronaut,

m is mass of the astronaut, and

g is gravitational acceleration on Ceres.

The gravitational acceleration on Ceres:-

[tex]F = G * (m1 * m2) / r^2[/tex]

here,

F is gravitational force between two objects,

G is gravitational constant,

m₁ & m₂ are masses of the two objects, and

r is distance between them.

For an object of mass m near the surface of a spherical object of mass M and radius R, the distance r can be approximated as (R + h).

For Ceres, the gravitational acceleration:-

[tex]g = G * M / R^2[/tex]

here,

G is gravitational constant,

M is mass of Ceres, and

R is radius of Ceres.

Reserving values given:-

[tex]g = (6.67430 × 10^-^1^1^ ^m^3/(kg s^2)) * (9.384 × 10^20 kg) / (470000 m)^2[/tex]

[tex]g = 0.27 m/s^2[/tex]

Now, weight of the astronaut as:

w = m * g

[tex]w = 160 kg * 0.27 m/s^2[/tex]

w = 43.2 N

Therefore, the weight of a 160 kg astronaut standing on Ceres is approximately 43.2 newtons.

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The graph of an accelerating object shows the increase in velocity with time. The object which is not accelerating is having a constant velocity with out any change in direction or magnitude.

Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.

The change in direction or magnitude or in both of velocity leads to an acceleration on the object. The object moving through a circular curvature is having a change in its direction of velocity. Hence, the object  is accelerating.

For an object moving without a change in velocity and no change in direction, the object is not accelerating at all as seen in the graph 2.

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A π bond is formed from the overlap of two parallel p orbitals that are adjacent to each other. When two such p orbitals overlap, the regions of overlapping electron density create a bonding molecular orbital with a nodal plane between the nuclei of the bonding atoms.

Two parallel p orbitals that are near each other combine to form pi bonds. A metallic bond fundamentally consists of two or more atoms sharing the same pair of electrons. In contrast to a sigma bond, which has its electronegativity focused between the atoms, a pi bond has its electron density concentrated both above and below the internuclear axis. A zone of negative electrode is produced by this charge distribution dispersion, which can interact with other molecules' and atoms' positive ions.

Along with s and d orbitals, atomic orbitals are one of the three types of orbitals that an electron can occupy in an atom. P orbitals consist of two prongs that are wedge-shaped in alignment. There are three there. Three are three mutually perpendicular p orbitals that can exist in an atom, each labeled as px, py, and pz.

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The particle has a charge of 2.44 x 10-8 C. when electric field at a point 27 cm from a charged particle is 105 N

The electrical properties of particles like electrons and protons are described by charge, a fundamental property of matter. Particles with the same electric charge repel one another while those with the opposite charge attract one another. Electric charge can be positive or negative. The Coulomb (C) is the charge measurement unit, and particles' charges are typically measured in Coulombs.

E is equal to kQ/r₂, where k is the Coulomb constant, r is the distance from the particle to the point where the electric field is being measured, Q is the charge on the particle, and E is the electric field.

The electric field at a distance of 27 cm from the particle is calculated to be 105 N/C in the particle's direction. We now have:

By substituting these values into the equation for the electric field, we obtain: E = 105 N/C r = 27 cm = 0.27 m

105 N/C = (8.99 x 10⁹ N m²/C²) × Q / (0.27 m)²

Solving for Q, we get:

Q = (105 N/C) × (0.27 m)² / (8.99 x 10⁹ N m²/C²)

Q = 2.44 x 10⁻⁸ C

Therefore, the charge on the particle is 2.44 x 10⁻⁸ C.

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The central will a listener be at the first  minimum and thus have difficulty hearing the sound is 41.2 m.

As with all waves, the relationship between sound speed, frequency, and wavelength can be described by the equation where stands for sound speed, stands for sound frequency, and represents the wavelength.

Perpendicular to the speaker and spaced  from the central should make up the initial minimum.

Therefore,

100m/[(0.300m)(3000Hz)/(343m/s)]²-1

= 41.2 m

Therefore, the central  will a listener be at the first minimum and thus have difficulty hearing the sound is 41.2 m.

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The statement "A structural fragment with three adjacent non equivalent protons would give rise to a characteristic triplet-quartet pattern in the 1H NMR spectrum" is true.

This is because the three protons are magnetically coupled to each other, resulting in a triplet signal, and they are also coupled to a neighboring proton, resulting in a quartet signal.

The relative intensities of the triplet and quartet signals are in a 1:3 ratio, which is characteristic of this type of structural fragment.

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The distance between two pool balls are separated by 0.0424 m.

The gravitational pull draws any two mass-containing things together. It mentions the gravitational force. The force will always be applied along the line joining the two masses in the direction of the other mass, according to the formula F=Gm1m2r2.

The following formula can be used to determine the gravitational force between two objects:

F = G * (m1 * m2) / r²

where F is the gravitational force's strength, G is the gravitational constant (6.67 x 10-11 N×m2/kg), m1 and m2 are the objects' masses, and r is the separation between them.

To determine the separation between the two pool cues To account for r, we can rearrange this expression as follows:

Represents the objects' masses, while r denotes the separation between their mass centres.

Rearranging this formula to solve for r will allow us to get the distance between the two pool balls:

r = √(G × m1 × m2 / F)

Substituting the given values, we get:

r = √(6.67 x 10⁻¹¹ N*m²/kg² × 0.300 kg × 0.400 kg / 8.92 x 10⁻¹¹ N)

r = 0.0424 m

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The net electric potential at point P due to the four particles would be Vtotal=5.5625×10−4Nm/C.

Electric field is a vector quantity, while electric potential is a scalar quantity. So, in order to find the electric potential on a point due to several other point charges, we will make a sum of their individual electric potential with respect to the point charge. So, to find the electric potential on point P due to the other point charges, we can find the electric potential of each point charge on P and add them, V=V1+V2+V3+V4

The electric potential of charges at either side of point P on P will be given by,

V1=V2=k(+q)d

In the same way, the electric potential on point P, due to the third charge,

V3=k(−q)2d

And the electric potential on point P due to fourth charge will be,

V4=k(−q)d

We know that electric potential is a scalar quantity, thus the total electric potential on point P is simply the sum of all the electric potentials on point P, V=V1+V2+V3+V4

Vtotal=k(+q)/d+k(+q)/d+k(−q)/2d+k(−q)/d

Vtotal=kq[(+1)/d+(+1)/d+(−1)/2d+(−1)/d]

Substituting the value of k=1/4πε0

and solving,

Vtotal=   [ (2+2−1−2)/2d]

Vtotal=   [(1)/2d]

We also know that the q=5.00fC=5×10⁻¹⁵C

, d=4.00cm=4×10⁻²m

and the value of the electrostatic constant, k=1/4πε0=8.996×10⁹Nm2C−2

Vtotal=8.996×10⁹Nm2C−2×5×10⁻¹⁵C[(1)2×4×10⁻²m]

Solving for Vtotal

we get,

Vtotal=5.5625×10⁻⁴Nm/C.

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the heat removed from the steam is 128000 J.

When steam is condensed into water, its temperature decreases from 128°C to 0°C. During this process, heat is removed from the steam and transferred to the surrounding environment. This heat transfer can be calculated using the equation:

q = m * c * ΔT

where q is the heat transferred, m is the mass of the steam, c is the specific heat capacity of water, and ΔT is the change in temperature.

For steam, the specific heat capacity is about 4.184 J/g°C. For water, the specific heat capacity is about 4.184 J/g°C as well.

Plugging in the values, we have:

q = 250 g * 4.184 J/g°C * (128°C - 0°C)

q = 250 * 4.184 * 128

q = 128000 J

The stored energy that can be used to do work is called Potential energy

while the energy of motion used to do work is called kinetic energy.

Potential energy is simply stored energy that, depending on its surroundings or circumstances, a thing may use. Potential energy is the energy that is held inside a system of physically interacting things, to use terminology more closely related to physics.

Kinetic energy, often known as the energy of motion, may be seen in the motion of things and subatomic particles. Kinetic energy may be found in all particles and moving objects. Examples of kinetic energy in action include a person walking, a baseball flying through the air, food tumbling off a table, and a charged particle in an electric field. Everything contains kinetic and potential energy. Kinetic energy is the ability to move anything (KE). Energy is a potential form of energy (PE).

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The angular velocity of the wheel is 0.9286 radians/sec and the number of revolutions per minute is 8.84 rpm

The angular velocity of the wheel in radians per second is given by the formula:

ω = v/r where ω is the angular velocity in radians per second, v is the linear velocity in cm/s, and r is the radius of the wheel in cm.

Therefore, the angular velocity of the wheel is:

ω = 13 cm/s / 14 cm = 0.9286 radians/sec

To calculate the revolutions per minute (rpm), we use the formula:

rpm = ω * 60 / (2π)

where 2π is the number of radians in a full revolution.

Therefore, the wheel will spin at a rate of:

rpm = 0.9286 radians/sec * 60 / (2π) = 8.84 rpm

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A seesaw is one type of lever, and it features a long beam attached to a pivot known as the fulcrum. The beam drops to the ground as soon as you sit on one side of it and put weight on one of its ends.

  is the distance from the center is the lighter child sitting.

The seesaw maintains its balance if the total torques that drive it to revolve in one direction—clockwise—equal the total torques that cause it to rotate in the opposite—counterclockwise. For an object at rest with no net forces acting on it, this is analogous to Newton's First Law.

This is due to the weight of your body being pulled downward by the force of gravity as well as the beam.

Two children with masses of 22 kg and 38 kg are sitting on a balanced seesaw, the heavier child is sitting 0.45 m,

the force by both, as shown below,

the distance as the seesaw is in equilibrium,

Therefore,   is the distance from the center is the lighter child sitting.

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Plants get the energy to make their food through the flowers and is therefore denoted as option B.

This is referred to as the process in which green plants manufacture their food in the presence of sunlight and is the reason why they are referred to as primary producers.

Plants have flowers and leaves which help to trap sunlight from the sun through the chlorophyll. The chlorophyll is a green pigment which is present in the chloroplast and they are all found in the flowers of plants which is therefore the reason why it was chosen as the correct choice.

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It would take approximately 81.3 Moons to equal the mass of the Earth.

Iron and oxygen make up the majority of the Earth's mass. Each of these makes up around 32% of the mass of the planet. Calcium, aluminum, and nickel make up roughly 1.5% of the total, followed by magnesium and silicon, which each contribute another 15%.

The mass of the Earth is approximately 5.97 x 10^24 kilograms, while the mass of the Moon is approximately 7.35 x 10^22 kilograms.

To determine how many Moons would be required to equal the mass of the Earth, we can divide the mass of the Earth by the mass of the Moon:

5.97 x 10^24 kg / 7.35 x 10^22 kg = 81.3

Therefore, it would take approximately 81.3 Moons to equal the mass of the Earth.

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Although being a fossil fuel, natural gas is cleaner and more effective than other conventional fuels. According to the Center for Liquefied Natural Gas, natural gas emits fewer greenhouse gases and pollutants than its competitors. Thus, it is true.

The methane and other hydrocarbon molecules in the decomposing organisms contain chemical energy that was previously obtained by photosynthesis from the sun. Burning natural gas can provide power as well as heat homes.

Methane makes up the majority of natural gas, but it also includes ethane, propane, and heavier hydrocarbons. Moreover, it has trace amounts of water, nitrogen, carbon dioxide, and hydrogen sulphide.

Therefore, it is true that therm is a unit that is generally used to measure the energy contained in natural gas.

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This can be calculated by the formula - CD=FD12ρAv2Explanation:Air resistance, or drag, is dependent on a number of factors including the density of the air, the area of the object, its velocity, and other properties of the object. The units for the force of air resistance are in Newtons (N).

The magnitude of the drag force is characterized by the dimensionless drag coefficient CD , given by CD=FD12ρAv2, C D = F D 1 2 ρ A v 2.

Where ρ is the density of the fluid (in this case, air), A=(1/4)πD2 A = ( 1 / 4 ) π D 2 is the cross-sectional area of the object, and v is the object's speed.

Therefore,  Air resistance can be calculated by taking air density times the drag coefficient times area all over two, and then multiply by velocity squared.

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Nichrome is used as a heating element in electric irons

High resistance: Nichrome has a high electrical resistance, which means that it converts electrical energy into heat energy efficiently. This makes it ideal for use in heating elements where heat generation is the primary requirement.

Good temperature stability: Nichrome has a high melting point and a low coefficient of thermal expansion. This means that it can maintain its structural integrity even at high temperatures and does not deform or break easily.

Corrosion resistance: Nichrome is resistant to corrosion, which makes it suitable for use in electrical appliances that are exposed to moisture, such as electric irons.

Long lifespan: Nichrome has a long lifespan and does not degrade easily even with repeated use. This makes it a reliable and durable choice for heating elements.

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