A periodic wave is produced by a vibrating tuning fork. The amplitude of the wave would be greater if the tuning fork were
A: struck more softly
B: struck harder
C: replaced by a lower frequency tuning fork
D: replaced by a higher frequency tuning fork

Answers

Answer 1

B: struck harder. The amplitude of a wave is directly proportional to the energy input, which in this case is the force with which the tuning fork is struck.

A lower frequency tuning fork would produce a wave with a longer wavelength, but it would not necessarily have a greater amplitude.

When a tuning fork is struck harder, it causes the tines to vibrate with greater intensity. This increased vibration results in a greater amplitude of the produced wave. Options A, C, and D are not directly related to the amplitude of the wave. A lower or higher frequency tuning fork would change the frequency, not the amplitude, and striking the tuning fork more softly would result in a smaller amplitude.

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Related Questions

A geranium is an example of a_______leafed plant.

A. Narrow

B. Broad

Answers

The correct option is B, A geranium is an example of a broad-leaved plant.

Geranium is a common name used for a group of plants in the family Geraniaceae. In chemistry, the term geranium is also used to refer to a class of organic compounds known as geraniols. Geraniols are terpene alcohols that have a rose-like odor and are used extensively in the fragrance industry.

Geraniols are present in many essential oils, including rose, lemon, and citronella oils. They are also found in geranium oil, which is extracted from the leaves and stems of geranium plants. Geranium oil is used in aromatherapy, skincare products, and perfumes due to its pleasant fragrance and potential therapeutic benefits. Geraniols have been studied for their various biological activities, including antimicrobial, anti-inflammatory, and anticancer effects.

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How can most meteors be cometary if most, perhaps all, meteorites are asteroidal?

Answers

The majority of meteors are cometary, coming from cometary debris, whereas the majority of meteorites are asteroidal, coming from the asteroid belt between Mars and Jupiter.

A comet's tail is made of gas and dust that is released when it approaches the sun. Comets are composed of ice, dust, and rocky material. The comet leaves a trail of debris as it travels around the sun. A meteor shower is produced as Earth travels through this debris trail because the particles burn up in the atmosphere. But not all meteors originate from comets. Some came from fragments of asteroids that crashed and split apart. The fragments may then impact the planet as meteorites. Due to the nature of the material that falls to Earth, most meteorites are asteroidal in origin while the majority of meteors are cometary in origin.

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in part a of this experiment you will collaborate with a partner to collect cell potentials for several metals, then exchange data. how many voltaic cells will each partner investigate on their own? hint: it may be helpful to refer to your lab manual and chapter 20 of your text book on voltaic cells and what they comprise of.

Answers

The number of voltaic cells each partner will investigate on their own depends on the experimental setup and the specific instructions given. If the experimental setup involves investigating the cell potential between two different metals, each partner will need to investigate one cell potential.

For example, if one partner investigates the cell potential between copper and zinc, the other partner will investigate the cell potential between zinc and copper.

However, if the experimental setup involves investigating the cell potential between different combinations of metals, each partner may investigate multiple voltaic cells.

For instance, if the experimental setup involves investigating the cell potential between copper and zinc, copper and iron, and zinc and iron, each partner will need to investigate three cell potentials.

Overall, the number of voltaic cells each partner will investigate on their own will depend on the specific instructions and setup of the experiment.

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When a switch in a circuit is closed the current does not go from 0 Amps to the Ohm's Law value because it takes time to accumulate the electric energy the current in the circult. should have It takes time to accumulate the resistive energy the current in the circuit should have It takes time to accumulate the magnetic energy the current in the circuig should have

Answers

When a switch in a circuit is closed, the current does not immediately jump to the Ohm's Law value because of several factors that affect the flow of electric energy in the circuit. One of these factors is the time it takes for the current to accumulate the electric energy it needs to flow through the circuit. This is due to the presence of resistance in the circuit, which slows down the flow of current.

Another factor that affects the current flow is the time it takes to accumulate the resistive energy that the current in the circuit should have. This is because the resistive energy is stored in the form of heat, which takes time to accumulate and dissipate in the circuit.

Lastly, the current flow is also affected by the time it takes to accumulate the magnetic energy that the current in the circuit should have. This is because the magnetic energy is stored in the form of magnetic fields, which take time to build up and stabilize in the circuit.

In summary, the current flow in a circuit is not instantaneous when a switch is closed because of several factors that affect the flow of electric energy, including resistance, resistive energy, and magnetic energy. These factors contribute to the gradual build-up of current in the circuit, which eventually reaches Ohm's Law value.

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A corrosion circuit produces 2 Amperes of current at a driving voltage of 1.6 Volts, what is the resistance of this circuit?
A) 1.8 Ohms
B) 2.8 Ohms
C) 0.8 Ohms
D) 9 Ohms

Answers

In this case, the voltage is 1.6 Volts, and the current is 2 Amperes.R = 1.6 V / 2 A = 0.8 Ohms. Therefore, the correct answer is option C) 0.8 Ohms.

So, the correct answer is C) 0.8 Ohms. The resistance of the corrosion circuit can be calculated using Ohm's law, which states that resistance is equal to voltage divided by current. Therefore, the resistance of the circuit can be calculated as:
Resistance = Voltage / Current
Plugging in the values given in the question, we get:
Resistance = 1.6 V / 2 A
Simplifying this expression, we get:
Resistance = 0.8 Ohms
Therefore, the correct answer is option C) 0.8 Ohms.

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A 61kg astronaut (including spacesuit and equipment), is floating at rest a distance of 10 m from the spaceship when she runs out of oxygen and fuel to power her back to the spaceship. She removes her oxygen tank (3.0 kg) and flings it away from the ship at a speed of 15 m/s relative to the ship. PART A: At what speed relative to the ship does she recoil toward the spaceship? PART B: How long must she hold her breath before reaching the ship?

Answers

PART A:

The total momentum of the system (astronaut + oxygen tank) is conserved, so we can write:

m1v1 = m2v2

where m1 is the mass of the astronaut (including the spacesuit and equipment), v1 is the velocity of the astronaut after the oxygen tank is thrown away, m2 is the mass of the oxygen tank, and v2 is the velocity of the oxygen tank after it is thrown away.

Substituting the given values, we get:

(61 kg) v1 = (3.0 kg) (15 m/s)

Solving for v1, we get:

v1 = 0.74 m/s

Therefore, the astronaut recoils toward the spaceship at a speed of 0.74 m/s relative to the ship.

PART B:

The distance between the astronaut and the spaceship is 10 m, and the astronaut is moving toward the spaceship at a speed of 0.74 m/s. Therefore, the time required to cover this distance can be calculated using the formula:

t = d / v

where t is the time, d is the distance, and v is the speed.

Substituting the given values, we get:

t = 10 m / 0.74 m/s

t = 13.5 s

Therefore, the astronaut must hold her breath for 13.5 s before reaching the spaceship.

The astronaut must hold her breath for approximately 13.51 seconds before reaching the ship

Part A: To find the speed at which the astronaut recoils towards the spaceship, we can use the conservation of momentum principle. The initial momentum is 0, as both the astronaut and the oxygen tank are at rest. After throwing the tank, the momentum must still be 0.

Initial momentum = Final momentum
0 = ([tex]61 kg) × (v_astronaut) - (3.0 kg) × (15 m/s)[/tex]


Solving for v_astronaut:
v_astronaut =[tex](3.0 kg × 15 m/s) / 61 kg ≈ 0.74 m/s[/tex]


The astronaut recoils toward the spaceship at a speed of approximately 0.74 m/s.

Part B: To calculate the time it takes for the astronaut to reach the spaceship, we can use the formula:
distance = speed × time

Rearranging for time:
time = distance / speed

Substituting the given values:
time = 1[tex]0 m / 0.74 m/s ≈ 13.51[/tex] seconds

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Please Help!
show all work, please thank you.

Answers

The magnitude of the force between the two charges is 810 N.

What is the magnitude of force between the two charges?

The magnitude of force between the two point charges is calculated by applying Coulomb's law as follows;

F = kq²/r

where;

k is Coulomb's constantq is the charger is the distance between the charges

F = ( 9 x 10⁹ x 7.5 x 10⁻⁶ x 7.5 x 10⁻⁶) / (25 x 10⁻³)²

F = 810 N

Thus, the magnitude of the force between the two charges is determined by applying Coulomb's law.

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15. The formation of a standing wave requires _____.

A. two waves that have been traveling over a long distance
B. constructive interference between two waves with different frequencies
C. interference between the incoming and reflected waves of the same frequency

Answers

The formation of a standing wave requires interference between the incoming and reflected waves of the same frequency. The correct option is C.

A standing wave is a wave pattern that is formed when waves of equal amplitude and frequency travel in opposite directions and interfere with each other in a confined space. This results in a wave pattern that appears to be stationary, with certain points along the wave appearing to be fixed in place.

Option A is not true because a standing wave is formed by waves that are traveling in opposite directions, not the same direction. Two waves traveling over a long distance would have traveled in the same direction and thus would not form a standing wave.

Option B is not true because constructive interference occurs when waves of the same frequency and amplitude are traveling in the same direction and combine to form a wave with a larger amplitude. This does not result in a standing wave.

Option C is the correct answer because a standing wave is formed by the interference between incoming and reflected waves of the same frequency. When a wave is reflected from a fixed end, it undergoes a phase change of 180 degrees. If the reflected wave meets the incoming wave at the correct phase, they interfere constructively and a standing wave is formed.

Therefore, The correct answer is option C.

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Which statement about electric charges is correct?

(A) An object with a positive charge and an object with a negative charge will repel each other.
(B) An object with a negative charge and an object with a positive charge will attract each other.
(C) Two objects with negative charges will attract each other.
(D) Two objects with positive charges will attract each other.

Answers

Statement (B) is correct: an object with a negative charge and an object with a positive charge will attract each other. This is because electric charges of opposite signs attract each other, while charges of the same sign repel each other. This is known as Coulomb's law, which describes the interaction between electric charges.

The primary clouds in the atmospheres of Jupiter and Saturn are composed of:
a. water vapor
b. iron and nickel
c. frozen ammonia crystals
d. metallic hydrogen
e. frozen alcohol (ready to make cocktails)

Answers

The primary clouds in the atmospheres of Jupiter and Saturn are composed of frozen ammonia crystals. These planets have a gaseous atmosphere made up mostly of hydrogen and helium, but also contain trace amounts of other compounds such as methane and ammonia.

The extreme temperatures and pressures found within the atmospheres of these gas giants cause the ammonia to freeze and form clouds. These clouds are responsible for the unique banding patterns visible on the surface of these planets.

While water vapor may be present in small amounts, it is not a primary component of the cloud cover. Iron, nickel, and metallic hydrogen are found deeper within the planets and do not contribute to the visible cloud formations. Frozen alcohol, while a humorous addition, is not present in significant enough quantities to contribute to the cloud cover.

Overall, the frozen ammonia crystals play a key role in shaping the appearance of Jupiter and Saturn and provide important insights into the complex dynamics of their atmospheres.

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a diverging lens has a focal length of magnitude 15.2 cm. (a) locate the images for each of the following object distances. 30.4 cm distance cm location ---select--- 15.2 cm distance cm location ---select--- 7.6 cm distance cm location ---select--- (b) is the image for the object at distance 30.4 real or virtual? real virtual is the image for the object at distance 15.2 real or virtual? real virtual is the image for the object at distance 7.6 real or virtual? real virtual (c) is the image for the object at distance 30.4 upright or inverted? upright inverted is the image for the object at distance 15.2 upright or inverted? upright inverted is the image for the object at distance 7.6 upright or inverted? upright inverted (d) find the magnification for the object at distance 30.4 cm. find the magnification for the object at distance 15.2 cm. find the magnification for the object at distance 7.6 cm.

Answers

(a) The images will be located at 22.8 cm behind the lens, (b) the third object's image is virtual, (c) the distance of third object is 7.6 cm and (d) the magnification is -3 hence, image is real and enlarged.

The images which have a positive distance will give positive and real images from diverging lenses and the images that have negative distances will give virtual images. The focal length of magnitude  = 15.2 cm

(a) To find the images for each object distance,

1/f = 1/do + 1/di

The first object distance =  30.4 cm

1/15.2 = 1/30.4 + 1/di

di = 22.8 cm

The image is located 22.8 cm away from the lens for an object which has a distance of 30.4 cm. The second object distance = 15.2 cm:

1/15.2 = 1/15.2 + 1/di

di = infinity

The third object distance = 7.6 cm

1/15.2 = 1/7.6 + 1/di

di = -22.8 cm

The image is located 22.8 cm behind the lens.

(b) The first object's distance of 30.4 cm, di = 22.8 cm. It is positive, so the image is real. The second object's distance of 15.2 cm, di = infinity. It is not a finite value, so the image is virtual. The third object's distance of 7.6 cm, di = -22.8 cm. It is negative, so the image is virtual.

(c) For the first object distance = 30.4 cm, The image is inverted. For the second object distance = 15.2 cm, the image is virtual and upright. For the third object distance = 7.6 cm, the image is virtual and upright.

(d) For the first object distance of 30.4 cm:

magnification = -22.8 cm / 30.4 cm = -0.75. The image is smaller than the object and inverted. For the second object distance of 15.2 cm:

m = -infinity / 15.2 cm = 0. The magnification is 0. The image is the same size as the object. For the third object distance of 7.6 cm:

m = -22.8 cm / 7.6 cm = -3

The magnification is -3. The image is larger than the object and inverted.

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The images formed by a diverging lens are virtual, upright, and located at a distance equal to twice the focal length.

Are the images produced by a diverging lens real or virtual?

Diverging lenses have a negative focal length, which means they always form virtual images. The magnitude of the focal length represents the distance at which the virtual image is formed. For an object placed at a distance of 30.4 cm from a diverging lens with a focal length of 15.2 cm, the virtual image is formed at a distance of 15.2 cm on the same side as the object. Similarly, for an object placed at a distance of 15.2 cm or 7.6 cm from the lens, the virtual images are formed at distances of 30.4 cm and 45.6 cm, respectively. The virtual images formed by a diverging lens are always upright, indicating that they have the same orientation as the object.

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make sure your calculator is in radian mode for this problem, and that you switch it back after this problem. there are two particles (1 and 2) that are moving around in space. the force that particle 2 exerts on 1 is given by: where the parameters have the values: , , . we will consider a time interval that begins at and ends at . impulse from 2 on 1, find the component of the impulse from 2 on 1 between and .

Answers

To find the component of the impulse from particle 2 on particle 1 between t=0 and t=pi/6, we first need to calculate the impulse itself.

The impulse is given by the integral of the force over the time interval, so we have:

J = ∫ F dt (from t=0 to t=pi/6)

Plugging in the given values for the parameters, we get:

J = ∫ (6sin(2t) - 2sin(4t)) dt (from t=0 to t=pi/6)

Evaluating the integral gives us:

J = [ -3cos(2t) + (1/2)cos(4t) ] (from t=0 to t=pi/6)

J = (-3cos(pi/3) + (1/2)cos(pi/2)) - (-3cos(0) + (1/2)cos(0))

J = (-3/2 + 1/2) - (-3 + 1/2)

J = -1

So the impulse from particle 2 on particle 1 between t=0 and t=pi/6 is -1. This means that particle 2 is applying a force to particle 1 in the opposite direction of particle 1's motion during this time interval.

It is important to note that we must ensure our calculator is in radian mode for this problem, and switch it back afterwards to avoid any potential errors in future calculations.

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For each quantity listed, indicate dimensions using force as a primary dimension, and give typical SI and English units: a. Power b. Pressure c. Modulus of elasticity d. Angular velocity e. Energy f. Momentum g. Shear stress h. Specific heat i. Thermal expansion coefficient j. Angular momentum

Answers

When working with physical quantities, it is important to understand their dimensions and units of measurement. Understanding the dimensions and units of the quantities can be useful in a variety of scientific and engineering contexts, from designing machines to measuring the properties of materials.

The dimensions and typical units for each quantity:
a. Power:
Dimensions: Force × Length × Time^(-2)
SI units: Watts (W)
English units: Foot-pounds per second (ft·lb/s)

b. Pressure:
Dimensions: Force × Length^(-2)
SI units: Pascals (Pa)
English units: Pounds per square inch (psi)

c. Modulus of elasticity:
Dimensions: Force × Length^(-2)
SI units: Pascals (Pa)
English units: Pounds per square inch (psi)

d. Angular velocity:
Dimensions: Time^(-1)
SI units: Radians per second (rad/s)
English units: Revolutions per minute (rpm)

e. Energy:
Dimensions: Force × Length
SI units: Joules (J)
English units: Foot-pounds (ft·lb)

f. Momentum:
Dimensions: Force × Time
SI units: Kilogram meters per second (kg·m/s)
English units: Pound-seconds (lb·s)

g. Shear stress:
Dimensions: Force × Length^(-2)
SI units: Pascals (Pa)
English units: Pounds per square inch (psi)

h. Specific heat:
Dimensions: Force × Length × Time^(-2) × Temperature^(-1)
SI units: Joules per kilogram per Kelvin (J/(kg·K))
English units: British Thermal Units per pound per degree Fahrenheit (BTU/(lb·°F))

i. Thermal expansion coefficient:
Dimensions: Temperature^(-1)
SI units: Per Kelvin (K^(-1))
English units: Per degree Fahrenheit (°F^(-1))

j. Angular momentum:
Dimensions: Force × Length × Time
SI units: Kilogram meters squared per second (kg·m²/s)
English units: Foot-pound-seconds (ft·lb·s)

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A 0.150-kg rubber stopper is attached to the end of a 1.00-m string and is swung in a circle. If the rubber stopper is swung 2.3 m above the ground and released, how far will the stopper travel horizontally before hitting the ground?

Answers

The stopper travels approximately 4.5 meters horizontally before hitting the ground.

We can use conservation of energy to solve this problem. At the highest point of the stopper's motion, all of its energy is in the form of potential energy, and at the lowest point (when it hits the ground), all of its energy is in the form of kinetic energy.

The potential energy of the stopper at the highest point is:

Ep = mgh

where m is the mass of the stopper, g is the acceleration due to gravity, and h is the height above the ground. Plugging in the values given in the problem, we get:

Ep = (0.150 kg) * (9.81 m/s²) * (2.3 m) ≈ 3.2 J

At the lowest point, all of the potential energy has been converted to kinetic energy:

Ek = (1/2) * mv²

where v is the speed of the stopper just before it hits the ground. Since the stopper is released from rest, we can use conservation of energy to equate the potential energy at the highest point to the kinetic energy just before hitting the ground:

Ep = Ek

mgh = (1/2) * mv²

Solving for v, we get:

v = √(2gh)

where h is the height from which the stopper was released. Plugging in the values given in the problem, we get:

v = √(2 * 9.81 m/s² * 2.3 m) ≈ 6.6 m/s

Now we can use the time it takes for the stopper to fall to the ground to calculate the horizontal distance it travels. The time is given by:

t = √(2h/g)

Plugging in the values given in the problem, we get:

t = √(2 * 2.3 m / 9.81 m/s²) ≈ 0.68 s

During this time, the stopper travels a horizontal distance given by:

d = vt

Plugging in the values we just calculated, we get:

d = (6.6 m/s) * (0.68 s) ≈ 4.5 m

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Two trains sound identical horns of frequency 410 Hz. One train is stationary. The other is moving away from an observer, who heats a beat frequency of 35 Hz. How fast is the moving train going?

Answers

The speed of the moving train is approximately 33.5 m/s.

The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:

[tex]f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}[/tex]

where [tex]f_b[/tex] is the beat frequency, [tex]f_s[/tex] is the horn frequency, v is the speed of sound, [tex]v_o[/tex] is the observer's speed, and [tex]v_s[/tex] is the speed of the source.

We know that [tex]f_s[/tex] = 410 Hz and [tex]f_b[/tex] = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, [tex]v_o[/tex] = 0.

Solving for [tex]v_s[/tex], we get:

[tex]v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v[/tex]

[tex]v_s[/tex] = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s

[tex]v_s[/tex] = 33.5 m/s

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newton'slaw tells us what happens in the absence of a force, and newton'slaw describes the effects of applying a force to an object.
true or false

Answers

True. Newton's Laws of Motion are fundamental principles that describe the relationship between force and motion. The first law, also known as the Law of Inertia, states that an object at rest will stay at rest, and an object in motion will stay in motion with a constant velocity in the absence of a net external force. This means that without any forces acting on it, an object will continue its current state, whether that's being stationary or moving.

The second law, also known as the Law of Acceleration, describes the effects of applying a force to an object. It states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, this can be represented as F = ma, where F is the net force, m is the mass, and a is the acceleration.

The third law, also known as the Law of Action and Reaction, states that for every action, there is an equal and opposite reaction. This means that when a force is applied to an object, the object exerts an equal force back in the opposite direction.

In summary, Newton's Laws of Motion describe both what happens in the absence of a force and the effects of applying a force to an object. Therefore, the statement is true.

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which of the following accurately describe some aspect of gravitational waves? select all the statements that are true. -The existence of gravitational waves is predicted by Einstein's general theory of relativity.
-The first direct detection of gravitational waves came in 2015.
-Gravitational waves carry energy away from their sources of emission.
-Gravitational waves are predicted to travel through space at the speed of light.

Answers

All of the provided statements are true and accurately describe various aspects of gravitational waves.

Here are the statements that accurately describe some aspects of gravitational waves:
1. The existence of gravitational waves is predicted by Einstein's general theory of relativity.
2. The first direct detection of gravitational waves came in 2015.
3. Gravitational waves carry energy away from their sources of emission.
4. Gravitational waves are predicted to travel through space at the speed of light.

All of the provided statements are true and accurately describe various aspects of gravitational waves.

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How does the kinetic energy of cart 2 change, if cart 1 has the initial energy K1,i = 120J ?
Express your answer to two significant digits and include the appropriate units. Enter positive value if the energy increases and negative value if the energy decreases.
As a result of an elastic collision between carts 1 and 2, the kinetic energy of cart 1 increases four times.

Answers

The kinetic energy of cart 2 increases by 360 J to two significant digits.

The kinetic energy of cart 2 will increase by a factor of 4 and will have a final energy of K2,f = 480 J. This is because kinetic energy is conserved in an elastic collision, meaning that the total kinetic energy before the collision (K1,i + K2,i) is equal to the total kinetic energy after the collision (K1,f + K2,f).

Since K1,f = 4K1,i = 480 J,

we can rearrange the equation to solve for K2,

f, which is equal to K2,f = K1,i + K2,i - K1,f = 120 J + K2,i - 480 J = -360 J + K2,i

. Therefore, K2,f = 480 J. The kinetic energy of cart 2 increases by 360 J.
In an elastic collision, the total kinetic energy is conserved. If the initial kinetic energy of cart 1 is K1,i = 120 J and its kinetic energy increase four times after the collision, the final kinetic energy of cart 1 becomes K1,f = 4 * K1,i = 480 J.

Since the total kinetic energy is conserved, the change in kinetic energy of cart 2, ΔK2, can be found using the equation:

ΔK2 = K1,f - K1,i = 480 J - 120 J = 360 J

Therefore, the kinetic energy of cart 2 increases by 360 J to two significant digits.

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calculate the temperature for which the minimum escape energy is 12 times the average kinetic energy of an oxygen molecule. answer in units of k.

Answers

The temperature for which the minimum escape energy is 12 times the average kinetic energy of an oxygen molecule is 444.44 K (in units of kelvin).

To begin with, let's define the terms escape energy, kinetic energy, and temperature:
Escape energy: The minimum amount of energy required for a particle to escape from the gravitational field of a planet or other celestial body.
Kinetic energy: The energy an object possesses due to its motion.
Temperature: A measure of the average kinetic energy of the particles in a system.
Now, we know that the minimum escape energy (Eesc) is 12 times the average kinetic energy (Ekin) of an oxygen molecule:
Eesc = 12 Ekin
We also know that the average kinetic energy of a molecule is related to its temperature (T) by the equation:
Ekin = (3/2) kT
where k is the Boltzmann constant.
Substituting this equation into the first one, we get:
Eesc = 12 (3/2) kT
Simplifying, we get:
Eesc = 18 kT
Finally, we can solve for the temperature (T):
T = \frac{Eesc }{(18 k)}
Plugging in the values of Eesc and k, we get:
T = \frac{(12 times the average kinetic energy of an oxygen molecule) }{ (18 * 1.38 * 10^{-23} J/K)}
T = 444.44 K
Hence, the temperature for which the minimum escape energy is 12 times the average kinetic energy of an oxygen molecule is 444.44 K (in units of kelvin).

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The four forces acting on an airplane in flight are
A.
weight, thrust, power, and drag.
B.
pitch, roll, yaw, and thrust.
C.
thrust, drag, weight (gravity), and lift.

Answers

Answer:

C. thrust, drag, weight, and lift.

Explanation:

1. Thrust- It is the force generated by the engine of an airplane for forward motion.

2. Drag- It is the resistance force faced by an airplane as it moves through the air.

3. Weight- It is the gravitational pull of the earth on an airplane.

4. Lift- It is the force generated by the wings of the plane as it moves through the air.

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The power; P , dissipated when a 5-volt battery is put across a resistance of R ohms is given by 25 P = R What is the rate of change of power with respect to resistance? rate of change Vlohm?

Answers

The rate of change of power with respect to resistance is -25/[tex]R^2[/tex] watts per ohm (W/Ω).



The power P dissipated by a 5-volt battery across a resistance of R ohms is given by the formula P = (25/R). To find the rate of change of power with respect to resistance, we need to differentiate the power equation with respect to R. Using the power rule for differentiation, we have:

dP/dR = -(25/[tex]R^2[/tex])

The negative sign indicates that as the resistance increases, the power dissipation decreases, which is consistent with Ohm's law. Therefore, the rate of change of power with respect to resistance is -25/[tex]R^2[/tex] watts per ohm (W/Ω). This means that for every unit increase in resistance, the power dissipation will change at a rate inversely proportional to the square of the resistance.

This relationship demonstrates the diminishing power dissipation as the resistance increases, highlighting the importance of considering resistance in electronic circuits and systems.

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A car goes around a curve traveling at constant speed. Which of the following statements is correct? Check all that applya. The acceleration of the car is zero.b.The net force on the car is zero.c.The net force on the car is not zero.d.The acceleration of the car is not zero.

Answers

When a car goes around a curve at a constant speed, the following statements are correct: The acceleration of the car is not zero and The net force on the car is not zero. Therefore option C and D is correct.

The acceleration of the car is not zero: Although the car is moving at a constant speed, it is changing its direction of motion. Acceleration is the rate of change of velocity, which includes changes in direction as well. Therefore, the car experiences centripetal acceleration directed toward the center of the curve.

The net force on the car is not zero: According to Newton's second law of motion, the net force acting on an object is equal to its mass multiplied by its acceleration. Since the car has non-zero acceleration towards the center of the curve, there must be a net force acting on it to cause this acceleration.

This net force is provided by the friction between the tires and the road, which provides the centripetal force required to keep the car moving in a curved path.

Therefore, both the acceleration and net force on the car are not zero when it goes around a curve at a constant speed.

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Question 1
What is a Static Load
A. is a load at rest like the weight of an object the structure is supporting or the weight of the structure itself.
B. in between radio stations
C. Aload in Motion
D. A force that is equal

Answers

A. A static load is a load at rest like the weight of an object the structure is supporting or the weight of the structure itself.

Sketch the curve with the given vector equation. Indicate with an arrow the direction in which t� increases.
r(t)=⟨t2−1,t⟩

Answers

The curve with the given vector equation r(t) = ⟨[tex]t^2 - 1, t[/tex]⟩ is a parabola that opens to the right, and the arrow indicating the direction of increasing t points to the right.

To sketch the curve with the given vector equation r(t) = ⟨[tex]t^2 - 1, t[/tex]⟩, we can plot points for various values of t. For example, when t = 0, r(0) = ⟨-1, 0⟩; when t = 1, r(1) = ⟨0, 1⟩; when t = -1, r(-1) = ⟨0, -1⟩. We can continue to plot points for other values of t and connect them to form a smooth curve.

To indicate the direction in which t increases, we can draw an arrow along the curve that points in the direction of increasing t. In this case, we can see that as t increases, the curve moves to the right, so the arrow should point to the right.

   *

        |

        |

 *------*------*

        |

        |

        *

The arrow indicating the direction in which t increases can be drawn tangent to the curve at any point, such as the point (0, -1) where t = -1. This arrow would point to the right, since t increases as we move from left to right along the curve.


Hence, the given vector equation has a curve which is parabolic in nature.

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Mixed wave frequencies presented together produce:

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Mixed wave frequencies presented together produce a phenomenon called interference, which can result in either constructive or destructive interference, depending on the alignment of the waves' phases.

Mixed wave frequencies presented together can produce interference patterns that can either amplify or cancel out certain frequencies. This is known as the principle of superposition. The resulting pattern is determined by the amplitude and phase of each wave. This phenomenon can be observed in a variety of natural phenomena, such as sound waves and light waves. In the case of sound waves, interference can lead to the creation of beats or harmonics, while in the case of light waves, interference can produce colorful patterns such as those seen in soap bubbles or oil slicks.
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a cylinder is pushing with a 3 square inch piston and a 1 square inch rod is pushing a 1,162 lb load up an inclined plane at an angle of 17 degrees. the initial speed is 60 ft/min and the deceleration distance is 0.25 in. the coefficient of friction between the load and the surface is 0.3. what force (in lbs) is required to decelerate the load and bring it to a stop when it is traveling up the hill?

Answers

The force required to decelerate the load and bring it to a stop when traveling up the hill is approximately 1,858.8 lbs.

To determine the force required, we need to consider the forces acting on the load. The main forces involved are the gravitational force, the force applied by the cylinder, and the frictional force opposing the motion.

First, let's calculate the gravitational force acting on the load. The weight of the load can be calculated using the formula: weight = mass × acceleration due to gravity.

Since the weight is given as 1,162 lbs, we can assume the mass is also 1,162 lbs (since weight = mass × acceleration due to gravity, and the acceleration due to gravity is approximately 32.2 ft/s²).

Next, we need to calculate the force due to the inclined plane. The force exerted by the inclined plane is equal to the weight of the load multiplied by the sine of the angle of the incline.

So, the force exerted by the inclined plane is 1,162 lbs × sin(17°).

The deceleration distance of 0.25 inches can be converted to feet (0.25/12 ft) and the initial speed of 60 ft/min can be converted to ft/s (60/60 ft/s).

Now, let's calculate the frictional force. The frictional force is equal to the coefficient of friction (0.3) multiplied by the normal force, which is the weight of the load multiplied by the cosine of the angle of the incline.

So, the frictional force is 0.3 × (1,162 lbs × cos(17°)).

The total force required to decelerate the load and bring it to a stop is the sum of the force exerted by the inclined plane and the frictional force, minus the force applied by the cylinder.

Therefore, the force required is approximately (1,162 lbs × sin(17°)) + (0.3 × (1,162 lbs × cos(17°))) - (3 square inches/1 square inch) = 1,858.8 lbs.

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Where does the evidence for dark matter come from?

Answers

The evidence for dark matter comes from observations of the gravitational effects it has on visible matter and cosmic microwave background radiation.

The existence of dark matter was first proposed to explain the observed gravitational effects on visible matter, such as stars in galaxies and clusters of galaxies, that could not be accounted for by the visible matter alone. These observations suggested the presence of a large amount of matter that is not visible, hence the term "dark" matter. Additional evidence for dark matter comes from observations of the cosmic microwave background radiation, which is the remnant radiation from the Big Bang. The patterns of the cosmic microwave background radiation suggest that dark matter played a critical role in the formation of the large-scale structure of the universe. While the nature of dark matter is still unknown, its presence is inferred from its gravitational effects on visible matter and radiation.

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a person travels along a straight road for the first half of total time with a velocity v1 and the second half of total time with a velocity v2. thus the average velocity v is given by

Answers

Therefore, the person's average velocity is given by (v1 + v2) / 2.

When content is loaded, it means that information or data is being stored or displayed. In this scenario, a person is traveling along a straight road and changing their velocity halfway through the total time. The first half of the total time is spent with a velocity of v1, and the second half is spent with a velocity of v2.

To find the average velocity, we use the formula:

v = (total displacement) / (total time)

Since the person is traveling along a straight road, the total displacement is just the difference between the starting and ending points. However, we don't have enough information to calculate the displacement in this problem.

Instead, we can use the fact that the average velocity is equal to the total displacement divided by the total time. Since the person is traveling for the same amount of time with each velocity, we can say that the total time is just twice the time spent at either velocity:

total time = time spent at v1 + time spent at v2 = 2 * (total time / 2) = total time

Now we can write the formula for the average velocity:

v = (total displacement) / (total time) = (d) / (total time)

To find d, we can use the fact that the person traveled the first half of the distance with velocity v1 and the second half with velocity v2. Since distance is equal to velocity times time, we can say:

d = (v1)(total time / 2) + (v2)(total time / 2)

Now we can substitute this into the formula for v:

v = (d) / (total time) = [(v1)(total time / 2) + (v2)(total time / 2)] / (total time)

Simplifying this expression, we get:

v = (v1 + v2) / 2

This means that the average velocity is just the average of the two velocities. So if the person travels at 10 m/s for the first half of the time and 20 m/s for the second half of the time, the average velocity is:

v = (10 m/s + 20 m/s) / 2 = 15 m/s

Therefore, the person's average velocity is given by (v1 + v2) / 2.

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Which of the following statements are true? (select multiple if there are several right answers)

A. The period of a wave is measure in seconds.
B. The symbol used for the period of a wave is T
C. The SI unit for frequency is meters.
D. To find the frequency of a wave, divide the wave speed by the period.

Answers

The true statements are;

A. The period of a wave is measure in seconds.

B. The symbol used for the period of a wave is T

What is the period of a wave?

The period of a wave is the time taken for a wave to complete a cycle.

The period of a wave is measured in seconds.

T = 2πd/V

where;

V is the speed of the waved is the distance of the wave

The frequency of a wave is the number of cycles completed by the wave in a given time.

F = 1/T (measured in Hz)

The relationship between speed, wavelength and frequency of a wave is given as;

V = Fλ

where;

λ is the wavelength

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of the five masses in orbit around the central mass, the one that would require the most energy to escape from its orbit is

Answers

The energy required to escape an orbit is dependent on the mass of the object and the velocity at which it orbits.

Therefore, the mass that would require the most energy to escape from its orbit is the one with the greatest mass and the fastest velocity.

In this case, we know that there are five masses orbiting a central mass. Assuming that they are all at the same distance from the central mass, the mass that would require the most energy to escape its orbit would be the one with the greatest mass.

This is because the gravitational force between two masses is proportional to the product of their masses. The greater the mass of an object, the greater the gravitational force it exerts on other objects.

Therefore, the object with the greatest mass would require the most energy to overcome its gravitational pull and escape its orbit.

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