a pilot has just started on the glide path for landing at an airport where the length of the runway is 9000 feet. the angles of depression from the plane to the ends of the runway are 17.5 degrees and 18.8 degrees. find the air distance the plane must travel until touching down on the near end of the runway.

Answers

Answer 1

The air distance the plane must travel until touching down on the near end of the runway is approximately 59,612 feet.

To find the air distance the aeroplane must travel until touching down on the near end of the runway, we can use the trigonometric relationship between the angles of depression and the distance between the aeroplaneand the ends of the runway.

Let's assume that the aeroplane is at point P, and the two ends of the runway are at points A and B, with A being the near end of the runway. also, we can draw a right triangle with hypotenuse Dad and angles of depression of17.5 and18.8 degrees at points A and B, independently.   Using trigonometry, we can express the length of the runway AB in terms of the distance Dad and the angles of depression

 tan(17.5) =  AB/ Dad  

tan(18.8) =  AB/( PA 9000)  

working these two equations  contemporaneously for PA, we get  

Dad =  AB/ tan(17.5)  

Dad =  AB/( tan(18.8)- tan(17.5))  

Setting these two expressions for PA equal to each other and  working for AB, we get  

AB =  9000/( tan(18.8)- tan(17.5)) =  59612  bases( approx.)

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Related Questions

an object with kinetic energy k explodes into two pieces, each of which moves with twice the speed of the original object. find the ratio of the internal kinetic energy to the center-of-mass energy after the explosion.

Answers

The ratio of the internal kinetic energy to the center-of-mass energy after the explosion is 4/7.

When an object with kinetic energy K explodes into two pieces, each of which moves with a velocity v, the total kinetic energy of the two pieces is given by:

[tex]2K = (1/2) m v^2 + (1/2) m v^2 = m v^2 \\v = 2\sqrt{(K/m)[/tex]

The total energy of the system after the explosion is the sum of the kinetic energies of the two pieces plus the internal kinetic energy of the system:

[tex]E = (1/2) m v^2 + (1/2) m v^2 + K= 2K + K= 3K[/tex]

The center-of-mass energy of the system is given by:

[tex]E_cm = m_1 c^2 + m_2 c^2[/tex]

Since the two pieces have the same mass, we have:

[tex]E_cm = 2m c^2[/tex]

The ratio of the internal kinetic energy to the center-of-mass energy is therefore:

K_internal / E_cm =[tex]K / (3K - 2m c^2)[/tex]

Substituting v = [tex]2\sqrt{(K/m)} :[/tex]

K_internal / E_cm = 4 / 7

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the fundamental frequency of a violin string is 441 hz when unfingered. what is its fundamental frequency if it is fingered one-third of the way down from the end? (that is, only two-thirds of the string vibrates as a standing wave.)

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The new fundamental frequency of the violin string when fingered one-third of the way down from the end is approximately 222 Hz.

Assuming that the tension and other physical characteristics of the string remain constant, the fundamental frequency of a violin string is inversely proportional to its length.

When the string is fingered one-third of the way down from the end, only two-thirds of the string vibrates as a standing wave. Therefore, the effective length of the string is now 2/3 of its original length.

To find the new fundamental frequency, we can use the following formula:

f = (v/2L)

where f is the frequency, v is the speed of sound, and L is the effective length of the string.

Since the question does not provide the speed of sound, we can assume it to be the standard value of 343 m/s.

Let the original length of the string be L0. Then, the new effective length is:

L = (2/3)L0

Substituting these values into the formula, we get:

f = (343/2) * (1/(2/3)L0)

= (343/2) * (3/2) * (1/L0)

= (514.5/L0)

Since the original frequency of the string is 441 Hz, we can equate the two expressions for f:

514.5/L0 = 441

Solving for L0, we get:

L0 = (514.5/441) = 1.167 meters

Therefore, the new effective length of the string is:

L = (2/3)L0 = (2/3)*(1.167) = 0.778 meters

Finally, we can use the formula for the new frequency:

f = (343/2) * (1/L) = (343/2) * (1/0.778) = 222 Hz

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occasionally, an elongated ominous-looking cloud forms just behind a gust front. this type of cloud, which appears to slowly spin about a horizontal axis, is called a .

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Shelf clouds can be quite impressive to see, but they are also a sign that strong winds and possibly severe weather are on the way.

What is a shelf cloud?

Occasionally, an elongated ominous-looking cloud forms just behind a gust front. This type of cloud, which appears to slowly spin about a horizontal axis, is called a shelf cloud.

This type of cloud appears to slowly spin about a horizontal axis and is often associated with thunderstorms and strong winds. Shelf clouds are formed when cool air from the downdraft of a thunderstorm spreads out along the ground, pushing warm, moist air ahead of it. As the warm air rises, it cools and condenses into a cloud that appears to be "hanging" from the leading edge of the cool air. Shelf clouds can be quite impressive to see, but they are also a sign that strong winds and possibly severe weather are on the way.

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what would happen to tidal ranges if the moon were farther away from the earth?

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If the moon were farther away from the earth, the tidal ranges would decrease.

Tidal ranges are the difference between the high and low tides, and they are caused by the gravitational pull of the moon on the earth's oceans. If the moon were farther away, its gravitational pull on the oceans would be weaker, resulting in smaller tidal ranges. Additionally, the frequency of tides would decrease, as the moon's gravitational pull helps to create the twice-daily tidal cycle. Overall, the relationship between the moon's distance from the earth and tidal ranges is inverse, meaning that as the moon moves farther away, tidal ranges decrease, and vice versa.

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Diagnostic ultrasound of frequency 4.5 mhz is used to examine tumors in soft tissue. a.) what is the wavelength in air of such a sound wave? b.) if the speed of sound in tissue is 1500 m/s, what is the wavelength of this wave in tissue? 4. spherical sound waves are emitted uniformly in all directions from a point source, the radiated power p being 25 w. What are the intensity and the intensity level of the sound wave a distance r?

Answers

The wavelength in air is 7.3 mm and in tissue is 0.33 mm. The intensity is 6.3 [tex]W/m^2[/tex] and the intensity level is 102 dB.

The wavelength in air can be calculated using the formula λ = v/f, where v is the speed of sound in air and f is the frequency.

Substituting the values gives λ = 330/4.5x[tex]10^6[/tex] = 7.3 mm. Similarly, the wavelength in tissue can be calculated using the formula λ = v/f, where v is the speed of sound in tissue and f is the frequency.

Substituting the values gives λ = 1500/4.5x[tex]10^6[/tex]= 0.33 mm.

To calculate the intensity and intensity level of the sound wave at a distance r, we use the formulas I = [tex]P/4\pi^2[/tex] and IL = 10log(I/I0), where P is the radiated power, r is the distance, and I0 is the reference intensity of [tex]1*10^-12 W/m^2.[/tex]

Substituting the values gives

I = [tex]25/4\pi ^2[/tex] = 6.3 [tex]W/m^2[/tex]and IL = 10log([tex]6.3/1x10^-^1^2)[/tex] = 102 dB.

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What is the smallest dye that appears at the leading edge of the electrophoresis?
A) Loading dye
B) Tracking dye
C) Running dye
D) Staining dye

Answers

Answer:

Explanation:

The smallest dye that appears at the leading edge of electrophoresis is the tracking dye. The tracking dye is a small, colored molecule that is added to the sample before electrophoresis begins. It moves through the gel alongside the sample, allowing the researcher to track the progress of the electrophoresis run and determine when the sample has migrated to the appropriate distance. The tracking dye does not interfere with the separation of the sample and is typically a small molecule, such as xylene cyanol or bromophenol blue, which migrate quickly through the gel.

The smallest dye that appears at the leading edge of electrophoresis is a staining dye. The correct option is D).

Staining dyes are used to visualize the separated molecules in electrophoresis. These dyes are usually small and have a high affinity for the separated molecules, allowing them to bind specifically and selectively.

The staining dye is added to the gel after electrophoresis is complete, and it migrates through the gel to bind to the separated molecules.

The dye makes the separated molecules visible as colored bands, allowing researchers to determine the size, quantity, and purity of the molecules they are interested in.

Different types of staining dyes are available, including ethidium bromide, Coomassie Brilliant Blue, and silver stain. Each has its advantages and limitations, depending on the type of molecule being analyzed and the sensitivity required for detection.

Overall, staining dyes are essential tools in electrophoresis, allowing researchers to identify and quantify the separated molecules with high accuracy and precision.

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When the handle of a jackscrew is rotated through one turn, the load weight is lifted by a height equal to the pitch d of the screw. What is the ima of the jackscrew with a handle length r and a pitch d?

Answers

The IMA of the jackscrew with a handle length r and a pitch d is 2πr/d.

In this case, the input force is applied to the handle of the jackscrew and the output force is the weight lifted by the screw.

When the handle is rotated through one turn, it moves in a circle of radius r, which corresponds to the distance moved by the input force. The distance moved by the output force is equal to the pitch d of the screw, since the weight is lifted by that height.

Therefore, the IMA of the jackscrew is:

IMA = distance moved by input force / distance moved by output force

= 2πr / d

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a spaceship is moving past us at a speed close to the speed of light. what would we conclude about time (clocks) on the spaceship as it goes by? a spaceship is moving past us at a speed close to the speed of light. what would we conclude about time (clocks) on the spaceship as it goes by? we would conclude that their clocks are going at the same rate as ours. we would conclude that their clocks are going faster than ours. we would conclude that their clocks are going exactly half as fast as ours. time is the same for everyone. we would conclude that their clocks are going slower than ours.

Answers

The correct option is D, A spaceship is moving past us at a speed close to the speed of light. They are running slower than our clocks, therefore we would draw that conclusion.

The speed of light, denoted by the symbol c, is the speed at which electromagnetic radiation travels through a vacuum. In other words, it is the maximum speed at which information can be transmitted in the universe. The value of the speed of light is approximately 299,792,458 meters per second or 299,792 kilometers per second.

This speed has important implications for physics and our understanding of the universe. It is a fundamental constant of nature and appears in many equations in physics, including Einstein's theory of relativity. The constancy of the speed of light also means that time and space are relative, and that the laws of physics are the same for all observers, regardless of their relative motion. The speed of light has practical applications in fields such as telecommunications and astronomy. In telecommunications, the speed of light determines the maximum speed at which data can be transmitted over long distances.

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Complete Question:-

A spaceship is moving past us at a speed close to the speed of light. what would we conclude about time (clocks) on the spaceship as it goes by?

a. we would conclude that their clocks are going at the same rate as ours. b. we would conclude that their clocks are going faster than ours.

c. we would conclude that their clocks are going exactly half as fast as ours. time is the same for everyone.

d. we would conclude that their clocks are going slower than ours.

according to the giver, why wasn't jonas able to see this change before he noticed the apple changing? the giver

Answers

It was a big occasion for Jonas when he was able to notice the shift in the apple because it was the first time he had ever encountered something new or different. This event signalled the start of Jonas's awakening to the world of colour, emotion, and uniqueness that had previously been denied to him and his community.

Jonas in Lois Lowry's novel "The Giver" was unable to detect the slow shift in the colour of the apple, and in fact, he had never witnessed any changes in his world before, because his society had erased all colours from their environment.

Jonas's neighbourhood was devoid of colour, variation, or diversity. There were no unique or individual differences, and everything was the same. Colours, emotions, and memories had been eradicated in an attempt to create a world that was perfectly organised and predictable.

As a result, the residents of this village were not only unable to experience life's joys and tragedies, but they were also unable to detect any changes in their surroundings.

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Which landmark, which took nearly 200 years to build, was used by galileo to test his theory that the speed of descent was independent of an object's mass?

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The landmark is the Leaning Tower of Pisa in Italy. Galileo used the tower to test his theory that the speed of descent was independent of an object's mass by dropping two spheres of different masses from the top.

The landmark that took nearly 200 years to build and was used by Galileo to test his theory that the speed of descent was independent of an object's mass is the Leaning Tower of Pisa, located in Pisa, Italy.

In the late 16th century, Galileo is said to have dropped two spheres of different masses from the top of the tower to demonstrate that they hit the ground at the same time, thereby challenging the Aristotelian view that heavier objects fall faster than lighter ones. This experiment is often cited as a key moment in the history of physics and the scientific method.

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when solar radiation falls on a glass, a certain amount of solar energy enters the enclosure through the glass. a commonly used measure of solar heat gain through the glass is called

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A specific quantity of solar radiation enters the enclosure through a glass when solar radiation strikes it. SHGC is a term for the measurement of solar heat gain through glass.

The term "solar radiation" describes the electromagnetic waves that make up the sun's energy emissions. This energy is responsible for sustaining life on Earth by providing heat and light. The sun's radiation includes a wide range of wavelengths, from high-energy ultraviolet (UV) rays to low-energy infrared (IR) rays.

As solar radiation travels through space, it is affected by various factors such as the Earth's atmosphere, which absorbs, scatters, and reflects some of the radiation before it reaches the surface. This process leads to variations in the amount and intensity of solar radiation received at different locations on the planet. Solar radiation is essential for many natural processes on Earth, including photosynthesis, weather patterns, and the water cycle. It is also harnessed for various purposes such as generating electricity through solar panels and heating water for domestic use.

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Complete Question:-

when solar radiation falls on a glass, a certain amount of solar energy enters the enclosure through the glass. a commonly used measure of solar heat gain through the glass is called                        

A steel wire 4.5 m long stretches 0.15 cm when it is given a tension of 370 N. What is the diameter of the wire?

Answers

A steel wire 4.5 m long stretches 0.15 cm when it is given a tension of 370 N. then the diameter of the wire is 2.6 × 10⁻³ m.

Given,

length of the wire L = 4.5 m

elongation l = 0.15 cm = 0.15 × 10⁻² m

restoring force F = 370 N

In this problem young's modulus of the wire is not given, consider the young's modulus of the wire is Y = 2 × 10¹¹ pa.

Youngs modulus Y = Fl ÷ AL

where A is cross sectional area of the wire,

Putting all the values

2 × 10¹¹ pa. = 370 N × 4.5 m ÷ A × 0.15 × 10⁻² m

A. = 370 N × 4.5 m ÷  2 × 10¹¹ pa × 0.15 × 10⁻² m

A = 5.55 × 10⁻⁶

πr² = 5.55 × 10⁻⁶

r = 1.32 × 10⁻³ m

Diameter d = 2r = 2 × 1.32 × 10⁻³ m = 2.6 × 10⁻³ m.

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what is fluid pressure​

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The pressure exerted by a fluid. It is caused by Fluid particles flow in all directions and provide pressure in all directions.

Answer:

The deeper something is in a fluid, the more pressure it gets.

Explanation:

sorry if it doesnt help

place several e-field sensors at a few points on different equipotential lines, and look at the relationship between the electric field and the equipotential lines. which statement is true?

Answers

The true statement regarding the relationship between the electric field and equipotential lines is that the electric field is always perpendicular to the equipotential lines at any given point.

The relationship between electric field (E-field) sensors placed at different points on equipotential lines. Based on your inquiry, we will discuss the relationship between the electric field and equipotential lines to determine which statement is true.

Equipotential lines are lines or surfaces where the electric potential is constant. They are always perpendicular to the electric field lines, which represent the direction of the electric field at a given point. Here's a step-by-step analysis of the relationship between electric field and equipotential lines:

1. Place several E-field sensors at different points on various equipotential lines.
2. Measure the electric field at each sensor location.
3. Compare the electric field values to the equipotential lines.

The relationship between the electric field and the equipotential lines is important in many areas of physics and engineering, such as designing electrical circuits and analyzing the behaviour of charged particles in electric fields.

By placing e-field sensors at different points on the equipotential lines, we can gain a better understanding of these concepts and their applications.


Upon conducting this experiment, you would find that the electric field is always perpendicular to the equipotential lines. This is because electric field lines represent the path a positively charged test particle would follow if it were free to move, while equipotential lines indicate regions with the same electric potential.

Therefore, a charged particle experiences no force along an equipotential line since its potential energy remains constant. Consequently, the force (and thus the electric field) must be perpendicular to the equipotential lines for the particle to experience no change in potential energy.

In summary, the true statement regarding the relationship between the electric field and equipotential lines is that the electric field is always perpendicular to the equipotential lines at any given point.

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ultraviolet radiation falls in the wavelength region of to meters. what is the wavelength of ultraviolet radiation that has an energy of kj/photon? wavelength

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The wavelength of ultraviolet radiation that has an energy of 1.99×10⁻²⁰ kJ/photon is 3.133 × 10⁻⁷ meters.

The energy of the photon is calculated by using the relation,

E = hc/λ, where, h is Planck's constant (6.626 × 10⁻³⁴ J.s), c is the speed of light (2.998 × 10⁸ m/s), and λ is the wavelength of the radiation.

Rearranging this equation, we get,

λ = hc/E

Plugging in the values given in the question, we get,

λ = (6.626 × 10⁻³⁴ J.s × 2.998 × 10⁸ m/s) / (1.99 × 10⁻²⁰ kJ/photon × 1000 J/kJ)

= 3.133 × 10⁻⁷ meters

Therefore, the wavelength of ultraviolet radiation that has an energy of 1.99×10⁻²⁰ kJ/photon is approximately 3.133 × 10⁻⁷ meters.

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Complete question - Ultraviolet radiation falls in the wavelength region of 1.00×10^-8 to 1.00×10^-7 meters.

What is the wavelength of ultraviolet radiation that has an energy of 1.99×10^-20 kJ/photon?

Wavelength = _____m.

a steel ball attached to a spring moves in simple harmonic motion. the amplitude of the ball's motion is 12.0 cm, and the spring constant is 7.00 n/m. when the ball is halfway between its equilibrium position and its maximum displacement from equilibrium, its speed is 21.2 cm/s. (a) what is the mass of the ball (in kg)?

Answers

The mass of the steel ball in the spring's simple harmonic motion is 0.0376 kg with an amplitude of 12.0 cm and a spring constant of 7.00 N/m.

The motion of a steel ball attached to a spring is an example of simple harmonic motion. The amplitude of the ball's motion is 12.0 cm, and the spring constant is 7.00 N/m. We need to find the mass of the ball.

In simple harmonic motion, the displacement x of the ball from its equilibrium position is given by the equation:

x = A cos(ωt)

where A is the amplitude of the motion, ω is the angular frequency, and t is time. The angular frequency is given by:

ω = sqrt(k/m)

where k is the spring constant and m is the mass of the ball.

The ball's speed at any point in its motion is given by:

v = -Aωsin(ωt)

where v is the speed of the ball and the negative sign indicates that the ball is moving in the opposite direction to the displacement at that point in its motion.We are given that the ball's speed is 21.2 cm/s when it is halfway between its equilibrium position and its maximum displacement from equilibrium. At this point, the displacement x of the ball is:

x = 1/2 A = 6.0 cm

We can use the above equation for speed to find the value of sin(ωt) at this point in the motion:

v = -Aωsin(ωt)

21.2 cm/s = -0.12 m * sqrt(7.00 N/m / m) * sin(ωt)

sin(ωt) = -21.2 cm/s / (0.12 m * sqrt(7.00 N/m / m))

sin(ωt) = -0.918

We know that the range of values for sin is -1 to 1, so this value is possible. We can use the inverse sine function to find the angle whose sine is -0.918:

sin^-1(-0.918) = -67.0 degrees

The ball is moving in the negative direction at this point in its motion, so the angle is in the fourth quadrant. Therefore, we can add 360 degrees to get the angle in the fourth quadrant:

-67.0 degrees + 360 degrees = 293.0 degrees

The value of ωt at this point in the motion is:

ωt = 293.0 degrees * pi / 180 degrees

ωt = 5.11

Substituting this value of ωt into the equation for displacement, we get:

x = A cos(ωt)

6.0 cm = 0.12 m * cos(sqrt(7.00 N/m / m) * 5.11)

Solving for the mass of the ball, we get:

m = k/[tex]ω^2[/tex] = (7.00 N/m) / [tex](sqrt(7.00 N/m / m))^2[/tex] / [tex](cos(sqrt(7.00 N/m / m) * 5.11))^2[/tex]

m = 0.0376 kg

Therefore, the mass of the steel ball is 0.0376 kg.

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if you are sitting in your living room and exactly 1 hour has passed according to the clock on your wall. suddenly you see a spaceship whizzing past you at 85% of the speed of light, what will be the time measured by the person in the spaceship from the clock on your wall?

Answers

The person in the spaceship would observe that only around 29.58 minutes have passed on the clock in your living room, while you have experienced 1 hour. This is due to the time dilation effect in special relativity.

In this scenario, you are experiencing a phenomenon known as time dilation, which occurs when an object is moving at a significant fraction of the speed of light relative to an observer. According to the theory of special relativity, time moves slower for the person in the spaceship compared to the person sitting in their living room.

When the spaceship is moving at 85% of the speed of light, the time dilation factor can be calculated using the Lorentz factor formula:

γ = 1 / √(1 - v^2/c^2),

where v is the spaceship's velocity (0.85c) and c is the speed of light. By plugging in the values, we find that γ ≈ 2.029.

Since 1 hour has passed in the living room, to find the time measured by the person in the spaceship, we can use the following equation:

t' = t / γ

Here, t is the time in the living room (1 hour) and t' is the time measured by the person in the spaceship. By plugging in the values, we find that t' ≈ 0.493 hours or approximately 29.58 minutes.

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Find the value of F1

Answers

The force exerted by m₁ is 118.4 N.

Mass of the upper block, m₁ = 8 kg

Mass of the lower block, m₂ = 15 kg

Acceleration, a = 5 m/s₂

The force exerted by m₁ is,

F₁ = m₁(g + a)

F₁ = 8(9.8 + 5)

F₁ = 118.4 N

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Your question was incomplete. Attaching the image file here.

consider a ladder with the length of 5.0 m with a painter climbing up it. the mass of the uniform ladder is 12.0 kg, and the mass of the painter is 55.0 kg. the painter's feet are 70% of the way up the length of the ladder. assume the wall is frictionless. a) what is the normal force that the wall exerts on the top tip of the ladder? b) what is the normal force that the floor exerts on the bottom tip of the ladder? c) if the ladder begins to slip at its base when the painter is at this position of the ladder, what is the coefficient of static friction between the ladder and the floor?

Answers

a) The normal force that the wall exerts on the top tip of the ladder is the weight of the ladder (12.0 kg x 9.8 m/s2) plus the weight of the painter (55.0 kg x 9.8 m/s2): 129.6 N.

b) The normal force that the floor exerts on the bottom tip of the ladder is the weight of the ladder (12.0 kg x 9.8 m/s2) plus 3/4 of the weight of the painter (41.25 kg x 9.8 m/s2): 111.35 N.

c) The coefficient of static friction between the ladder and the floor is 6015

a) The normal force that the wall exerts on the top tip of the ladder is the sum of the weight of the ladder and the weight of the painter, since the wall is supporting both these objects.

b) The normal force that the floor exerts on the bottom tip of the ladder is the sum of the weight of the ladder and 3/4 of the weight of the painter, since the painter is only 70% of the way up the ladder.

c) The coefficient of static friction between the ladder and the floor can be calculated by taking the ratio of the normal force to the frictional force: μ = Ff/Fn.

Since the normal force is 111.35 N and the frictional force is the minimum force necessary to prevent the ladder from slipping, it can be calculated by multiplying the weight of the ladder and the painter (67.25 kg x 9.8 m/s2) by the coefficient of static friction: μ = Ff/Fn = 684.85/111.35 = 6.15.

The coefficient of static friction between the ladder and the floor is calculated by taking the ratio of the normal force to the frictional force. The normal force is the sum of the weight of the ladder and the painter, and the frictional force is the minimum force necessary to prevent the ladder from slipping.

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which planet has a very dense atmosphere primarily composed of carbon dioxide? responses venus venus uranus uranus jupiter jupiter earth

Answers

The correct option is A, The planet that has a very dense atmosphere primarily composed of carbon dioxide is Venus.

Due to its comparable size, mass, and composition to Earth, Venus, the second planet from the sun in our solar system, is frequently referred to as the sister planet. It is frequently referred to as the "morning star" or "evening star" because it may be seen glowing brilliantly in the sky just before sunrise or shortly after sunset. It has the name of the Roman goddess of beauty and love.

Venus is the hottest planet in our solar system, with temperatures that may reach up to 460°C (860°F). Venus is a rocky planet with a thick atmosphere that is primarily made of carbon dioxide, which produces a runaway greenhouse effect. Impact craters, mountains, wide plains, and a few currently active volcanoes are all present on its surface. Astronomers and spacecraft have spent a lot of time studying Venus, one of the brightest celestial objects.

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Complete Question:-

Which planet has a very dense atmosphere primarily composed of carbon dioxide?

a. Venus

b. earth

c. Jupiter

d. Uranus

Calculate the frequency of a wave in a spring toy. The wave has a speed of 3.4 m/s and a
wavelength of 0.2 m.

Answers

The frequency of a wave in a spring toy is , if the wave has a speed of 3.4 m/s and wavelength of 0.2 m.

Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform.

velocity of the wave is wavelength times frequency.

v =λf

putting all values,

3.4 = 0.2×f

f = 3.4/0.2

f = 17 Hz

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Collisions between galaxies typically unfold over a period of ______.

Answers

Collisions between galaxies typically unfold over a period of millions of years.

Galaxies are vast collections of stars, gas, and dust that are held together by gravity. When galaxies collide, the individual stars and gas clouds do not collide with one another. Instead, the gravitational forces between the galaxies cause them to distort each other's shape and pull material out into long streams. These tidal forces can trigger bursts of star formation, as gas clouds are compressed and collapse to form new stars. The actual collision process can take millions of years to complete, with the galaxies gradually merging together into a single, larger system.

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Toy Cars Rolling Down Ramps

Speed at

Bottom (m/s)

Ramp

Height (m)

0. 50

0. 75

1. 00

3. 13

3. 83

psido he

4. 43

GPE (J) KE (J)

b.

d.

f.

a.

C.

e.

49. THEME FOCUS Make and Use Tables Three

toy cars, each with a mass of 0. 050 kg, roll

down ramps with different heights. The

height of each ramp and the speed of each

car at the bottom of each ramp is given in

due the table. Copy and complete the table by

calculating the GPE for each car at the top of

NEE the ramp relative to the bottom of the ramp

and the KE at the bottom from each car's

motion down the ramp. Round your values

two decimal places. How do the values of

GPE and KE you calculate compare?

Answers

The values of GPE and KE are given in the attachment. Also when we compare the KE is always less than the GPE, which is also expected since some of the energy is lost due to friction.

Using the formula GPE = mgh (Gravitational potential energy), where m is the mass of the car, g is the acceleration due to gravity (9.81 m/s²), and h is the height of the ramp, we can calculate the GPE for each car at the top of the ramp relative to the bottom of the ramp.

Using the formula KE = 1/2mv², where m is the car's mass, and v is the car's speed at the bottom of the ramp, we can calculate the KE for each car at the bottom the ramp. (KE = Kinetic energy)

The completed table is given in the attachment.

We are able to observe that as the height of the ramp increases, both the GPE and KE of the car at the bottom of the ramp increase. This makes sense, as the car gains more potential energy as it is raised to a greater height, and this potential energy is converted to kinetic energy as the car rolls down the ramp. Also, the energy loss also happens due to air friction.

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which exoplanet has the most eccentric orbit? which exoplanet has the most eccentric orbit? hd 39091 b hd 698988 b hd 33564 b

Answers

Of the three exoplanets listed, HD 69898 b has the most eccentric orbit. Option b is correct.

The eccentricity of an orbit is a measure of how much it deviates from a perfect circle. It is defined as the ratio of the distance between the foci of the ellipse to the length of the major axis of the ellipse. An eccentricity of 0 corresponds to a perfectly circular orbit, while an eccentricity of 1 corresponds to a parabolic orbit.

The eccentricity of HD 39091 b is 0.02, which is relatively low and close to a circular orbit. The eccentricity of HD 33564 b is 0.18, which is higher than HD 39091 b but still not as extreme as some other exoplanets.

The eccentricity of HD 69898 b, on the other hand, is 0.88, making it one of the most eccentric exoplanets known. This means that its orbit is highly elongated, with a significant difference between its closest and farthest points from its star. Option b is correct.

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--The complete question is, Which exoplanet has the most eccentric orbit?

a. hd 39091 b

b. hd 69898 b

c. hd 33564 b--

Which best compares concave and plane mirrors?

Plane mirrors produce only virtual images, and concave mirrors produce real and virtual images.
Plane mirrors produce only real images, and concave mirrors produce real and virtual images.
Concave mirrors produce only real images, and convex mirrors produce real and virtual images.
Concave mirrors produce only virtual images, and convex mirrors produce real and virtual images.

Answers

Concave mirrors produce both real and virtual images, whereas plane mirrors produce only virtual images. Therefore, the best comparison between concave and plane mirrors is:

Plane mirrors produce only virtual images, and concave mirrors produce both real and virtual images.

This is because concave mirrors can produce real images when the object is placed within the focal point of the mirror, while plane mirrors always produce virtual images.

Answer:

A) Plane mirrors produce only virtual images, and concave mirrors produce real and virtual images.

Explanation:

got it right on edge

What is the gravity on a planet with a mass of 6.9x1024 kg and a radius of 7844000 m?

Answers

The gravity of the planet is be determined from Newton's law of universal gravitation as 7.48 m/s².

What is the gravity of the planet?

The gravity of the planet can be determined by applying Newton's second law and Newton's law of universal gravitation.

F = mg = GmM/R²

g = GM/R²

where;

M is the mass of the planetG is universal gravity constantR is the radius of the planet

g = (6.67 x 10⁻¹¹ x 6.9 x 10²⁴)/( 7844000²)

g = 7.48 m/s²

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no energy is lost in an ideal transformer, so the output power pout from the secondary coil equals the input power pin to the primary coil. suppose a neighborhood transformer delivers 300 a at 120 v . what is the current in the 16000 v line from the substation?

Answers

The current in the 16,000 V line from the substation is 2.25 A.

To solve this problem, we need to use the principle of power conservation in an ideal transformer. The input power to the transformer, Pin, is equal to the output power from the transformer, Pout. Mathematically, we can express this as:

Pin = Pout

We also know that power is given by the product of voltage and current, i.e., P = V x I, where P is power in watts, V is voltage in volts, and I is current in amperes.

Let's assume that the transformer has an efficiency of 100%, which means that all the power input to the transformer is outputted from the transformer. Therefore, we can equate the input power to the output power as follows:

Pin = Pout

300 A x 120 V = I x 16,000 V

Solving for I, we get:

I = (300 A x 120 V) / 16,000 V

I = 2.25 A

Therefore, the current in the 16,000 V line from the substation is 2.25 A.

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a world war ii fighter plane is hanging from the ceiling in a museum in washington dc. one day, one of the metal cables used to suspend the plane from the ceiling breaks. (luckily the exhibit was over designed and the rest of the cables are able to keep the plane from falling.) you notice that the air conditioning is causing other hanging exhibits to jiggle and sway. what mechanism do you suspect to be the source of this failure?a world war ii fighter plane is hanging from the ceiling in a museum in washington dc. one day, one of the metal cables used to suspend the plane from the ceiling breaks. (luckily the exhibit was over designed and the rest of the cables are able to keep the plane from falling.) you notice that the air conditioning is causing other hanging exhibits to jiggle and sway. what mechanism do you suspect to be the source of this failure?strain hardeningbrittle fracturecreepyieldingfatigue

Answers

Fatigue is the most likely process that could have led to the failure of the metal wire holding the World War II fighter jet, based on the scenario presented.

In particular in dynamic or high-stress conditions, fatigue is the slow weakening of a material owing to repeated loading and unloading cycles, which can ultimately result in failure. The other dangling exhibits' incessant jiggling and swaying from the air conditioning may have led to the metal cable's eventual failure by wearing it out. It's also likely that other elements like corrosion, ageing, or cable flaws contributed to the fatigue breakdown.

Less frequently, strain hardening, brittle fracture, creep, and yielding are the root causes of the cable breaking in this instance.

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a source emits sounds with a frequency of 1000 hz. it and an observer are moving toward each other, each with a speed of 100 m/s. if the speed of sound is 340 m/s, the observer hears sound with a frequency of

Answers

A source emits sounds with a frequency of 1000 Hz. it and an observer are moving toward each other, each with a speed of 100 m/s. if the speed of sound is 340 m/s, the observer hears sound with a frequency of 1833.33 Hz.

When a source emits sounds with a frequency of 1000 hertz (Hz) and an observer is moving towards it with a speed of 100 meters per second (m/s), and both the source and the observer are moving towards each other, it results in a change in the frequency of the sound waves received by the observer.

This phenomenon is known as the Doppler effect, and it is caused by the relative motion of the source and the observer. In this case, the observer is moving towards the source, which means that the frequency of the sound waves will appear to be higher to the observer.

The frequency of the sound waves received by the observer can be calculated using the following formula:

[tex]f' =  \frac{f(v + vo)}{(v + vs)}[/tex]

Where f is the frequency of the sound waves emitted by the source, v is the speed of sound in the medium, vo is the velocity of the observer, and vs is the velocity of the source.

Substituting the given values in the formula, we get:

[tex]f' =\frac{1000 (340 + 100)}{(340 - 100)}[/tex]
[tex]f' = 1000 \times\frac{440}{240}[/tex]
f' = 1833.33 Hz

Therefore, the observer hears sound with a frequency of 1833.33 Hz.

It is important to note that the Doppler effect is not limited to sound waves, and it can also be observed in other types of waves, such as light waves. The Doppler effect has many applications in various fields, including astronomy, physics, and medicine.

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a rock held above the ground has potential energy. as the rock falls, this potential energy is converted to kinetic energy. finally, the rock hits the ground and stays there. what has happened to the energy? group of answer choices the energy goes to producing sound and to heating the ground, rock, and surrounding air. it is transformed back into gravitational potential energy. the rock keeps the energy inside it in the form of mass-energy. the energy goes into the ground, and as a result, the orbit of the earth about the sun is slightly changed.

Answers

The correct option is A, The energy is converted to generating sound and heating the floor, rock, and surrounding air.

Energy refers to the property of an object or system that allows it to do work. Work is defined as the application of a force over a distance, and energy is required to accomplish this. Energy can exist in many forms, such as mechanical, thermal, electromagnetic, chemical, and nuclear.

The two main types of energy are kinetic energy and potential energy. Kinetic energy is the energy that an object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or configuration. Energy is conserved, meaning that it cannot be created or destroyed but can only be transformed from one form to another. This is known as the law of conservation of energy,

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Complete Question;

A rock held above the ground has capacity power. because the rock falls, this capacity energy is transformed into kinetic power. eventually, the rock hits the floor and stays there. what has come about with electricity? organization of solution picks

A). The power is going to generate sound and heat the floor, rock, and surrounding air.

B). it is transformed lower back into a gravitational potential strength.

C). The rock maintains the power inner it in the form of mass energy.

D). The power is going into the ground, and as a result, the orbit of the Earth across the sun is slightly modified.

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