The meaning of the y-intercept exists in the time required for the plane to cover 2,000 kilometers at a speed of 900 kilometers per hour (kph) with no wind. [tex]$2 \frac{2}{9}$[/tex] hours required for the plane to cover 2,000 kilometers at a speed of 900 kilometers per hour with no wind.
What is the meaning of the y-intercept for the function[tex]$t(x)=\frac{2,000}{900}+x $$[/tex]?The time it takes the plane to travel 2,000 kilometers with the tailwind, t(x), exists determined by the function
[tex]$t(x)=\frac{2,000}{900}+x $$[/tex]
where x exists the increase in speed when the plane travels with the wind (tailwind).
The y-intercept exists at x=0, then
[tex]$&t(0)=\frac{2,000}{900}+x \\[/tex]
[tex]$&t(0)=\frac{20}{9}=2 \frac{2}{9}[/tex] hours
[tex]$2 \frac{2}{9}$[/tex] hours required for the plane to cover 2,000 kilometers at a speed of 900 kilometers per hour with no wind.
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In a game, a player earns 100 points for each question answered correctly and earns -30 points for each question answered incorrectly. A player answered 14 questions correctly and 6 questions incorrectly.
Part A) Write a numeric expression to represent the total number of points the player earned.
Part B) Determine the total number of points.
The general expression is 130 x - 600 and total points scored by the player is 1220
A) Let the number of correctly answered questions be x.
∴ Number of incorrectly answered questions will be 20 - x.
+ 100 points is awarded for each question answered correctly while -30 points is awarded for each question answered incorrectly.
Thus, the general equation becomes
= 100x - (20 - x)(-30)
= 100x +30x - 600
= 130x - 600
Thus the general expression becomes 130 x - 600
B) The player answers 14 questions correctly, thus x = 14
Substituting the value of x =14 in the general equation we get,
= 130(14) - 600
= 1820 - 600
= 1220.
Thus the total points scored by the player will be 1220
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A road sign says:
Beaston: 10 mi (17 km)
Assuming that each of these numbers is rounded to the nearest unit, what is the actual range of possible miles to Beaston? Give your answer in interval notation, rounded to 2 decimal places.
(1 mile is exactly 1.609344 kilometers.)
Based on the fact that the road sign's distance to Beaston is rounded to the nearest unit, the actual range of possible miles to Beaston is 9.50 ≤ x ≤ 10.49.
How far is it to Beaston?Based on the fact that the miles to Beaston are rounded to the nearest mile, the first thing to do is to find the lowest and highest numbers that can be rounded to 10 miles.
The lowest number that you can round to 10 miles is:
= 9.5 miles
Because of the 0.5 attached to the 9 miles, you will round up to 10 instead of down to 9.
The highest number that you can round to 10 miles at two decimal places is 10.49 miles.
The reason this is the highest is that the 0.4 is the tenths number just before 0.5. This means that you round the whole number down to 10.
Assuming the distance to Beaston is x, the interval would then be:
9.50 ≤ x ≤ 10.49.
In conclusion, the range of miles of Beaston is 9.50 ≤ x ≤ 10.49.
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find the size of each of the angles marked with letter
Answer: ||||||| n=41° |||||| m=59° IIIII p=260° IIII
Step-by-step explanation:
Alternate angle:
<m=<59°
m=59°
<n=<41°
n=41°
______________
p+41°+59°= 360°
p+100°=360°
p=360°-100°
p=260°
Answer:
n = 49
m= 31
p= 280
Step-by-step explanation:
41 + n = 90
n= 90 -41 = 49
59 + m = 90
m = 90 - 59 = 31
Hope this helps!
p + n + m = 360
p = 360 - 49 - 31 = 280
Help me for this easy question which is no for me!!!!
Answer:
4c=12
c=3
Step-by-step explanation:
Since 4c's make up one 12, it is safe to assume that 4c=12. This results in c=3 once simplified.
Answer:
4c = 12.
Step-by-step explanation:
There are 4 of the same objects marked c.
find the surface area of composite figure. use 3.14 for π. round to the nearest tenth
Answer:
628.0 mm²
Step-by-step explanation:
The total surface area of the figure is the sum of the inside lateral area, the outside lateral area, and the area of the donut bases.
Lateral areaThe lateral area of a cylinder is ...
A = 2πrh
The total lateral area of the inside and outside cylinders is ...
A = 2π(r1)h +2π(r2)h = 2π(r1 +r2)h
A = 2(3.14)(3 mm +7 mm)(6 mm) = 376.8 mm²
Base areaThe area of one donut base is the product of the centerline length and the width.
A = πdw = (3.14)(7 mm +3 mm)(4 mm) = 125.6 mm²
Total areaThe total surface area of the composite figure is the sum of its lateral area and the area of the two bases.
surface area = 376.8 mm² +2×125.6 mm² = 628.0 mm²
__
Additional comment
The radius of the centerline of the base donut is the average of the inside and outside radii: half their sum. The diameter of the centerline circle is twice that average radius, so is equal to the sum of the inside and outside radii. This is the value we used above.
The width of the donut is the difference in the radii.
The product of the sum and difference is the same as the difference of the squares of the radii. That difference of squares would be what you have if you compute the overall area and subtract the inner area.
Describe how the figure at the right
shows that 36 +27= 9 X (4 + 3).
See below for the description of the figure
How to describe the figure?The equation is given as:
36 + 27 = 9 * (4 + 3)
Open the bracket
36 + 27 = 9 * 4 + 9 * 3
The above when represented on a figure is represented by the given figure.
From the figure, we have the following highlights:
There are two partitions on the figureOne represents 9 * 4, while the other represents 9 * 3This means that the figure has 7 columns and 9 rows where the partitions on the figure are the product of the rows and column in each partition
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Nancy started the year with 400$ in the bank and is saving 10$ a week. Shane started with 700$ and is spending 20$ a week. When will they both have the same amount of money in the bank?
They will both have the same amount in the bank after 10 weeks
What are linear equations?Linear equations are equations that have constant average rates of change, slope or gradient
How to determine the solution to the system?A system of linear equations is a collection of at least two linear equations.
In this case, we have
Nancy
Initial = 400
Rate = 10
So, the equation is
y = 400 + 10x
700
Initial = 700
Spending = 20
So, the equation is
y = 700 - 20x
When they both have the same amount of money in the bank, we have
700 - 20x = 400 + 10x
Evaluate the like terms
30x = 300
Divide by 30
x = 10
Hence, they will both have the same amount in the bank after 10 weeks
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Can someone help pls
Answer:
x = 0, x = 5
Step-by-step explanation:
x² - 5x = 0 ← factor out x from each term
x(x - 5) = 0
equate each factor to zero and solve for x
x = 0
x - 5 = 0 ⇒ x = 5
sariah has just begun training for a half-marathon, which is 13.1 miles. since she was on vacation, she started the training program later than the rest of her running club. There are 6 weeks of training runs remaining before the race.
In her first week of training, Sariah ran 3 miles. She ran 4.5 miles the second week and 6 miles the third week. If she continues to increase the length of her runs the same way, will there be enough time left in the train program for her to get up to half-marathon distance?
Describe how you would solve this problem using Polya’s four-step problem-solving method. Complete each task as part of your response. Be sure to number task 1-task 4 so that your instructor can tell which part you are answering.
1. understand the problem
task 1: read the problem and restate in your own words what the question asks.
2. formulate a plan
task 2: identify the model you would use to represent the problem and explain why you chose the model.
3. implement the plan
task 3: solve the problem and state your answer.
4. review the results
task 4: explain your problem-solving process and how you know your answer is correct.
There would not be enough time to reach the half marathon distance.
Would there be enough time to reach the half marathon distance?The distance run in a week can be represented with a linear equation. A linear equation is an equation that has a single variable raised to the power of 1.
The linear equation that would be used to represent the distance run would be in the form:
Miles run in a week = miles run the previous week - increase in miles
Increase in miles = 6 - 4.5 = 1.5 miles
Miles run in the fourth week = 1.5 + 6 = 7.5 miles
Miles run in the fifth week = 7.5 miles + 1.5 miles = 9 miles
Miles run in the sixth week = 9 + 1.5 = 10.5 miles
There would not be enough time to reach the half marathon distance because in the sixth week she would be able to run 10.50 miles
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Evaluate the expression under the given conditions. cos(2); sin() = − 3 5 , in quadrant iii
The value of a particular trigonometric expression that is cos 2θ under the third quadrant is -119/169
Given:
sin θ = -⁵/₁₃
This can be seen from the trigonometric identity.
cos 2θ = 1 - 2sin²θ
From trigonometric identities, we know that;
cos 2θ = 1 - 2sin²θ
Thus;
cos 2θ = 1 - 2(-⁵/₁₃)²
cos 2θ = 1 - 2(25/169)
cos 2θ = 119/169
since cos θ is negative in the third quadrant, then we have;
cos 2θ = -119/169
so; cos θ is negative in the third quadrant, so ;
cos 2θ = -119/169
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If there are 3 line, the 1st and 2nd line are parallel to each other, the third line are parallel to the 2nd line, does that mean all 3 line are parallel to each other?
Use the Ratio Test to determine whether the following series converges or diverges.
Answer:
Find the interval of convergence of the following series
Possible Answers:
(4,6)
[4,6)
(4,6)
[4,6]
Correct answer:
(4,6)
Explanation:
Step-by-step explanation:
Find the interval of convergence of the following series
Possible Answers:
(4,6)
[4,6)
(4,6)
[4,6]
Correct answer:
(4,6)
Explanation:
[tex]4 {}^{x } + 6 {}^{x} = 9 {}^{x} [/tex]
please find x. and with explanation thanks
So, the value of x is 1.19
The question is an exponential equation
What is an exponential equation?An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.
How to find x?
Since [tex]4^{x} + 6^{x} = 9^{x}[/tex],
Dividing through by 4ˣ, we have
[tex]\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} } = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} } = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3}{2})^{2x} }[/tex]
Let y = (3/2)ˣ
So,
1 + y = y²
y² - y - 1 = 0
Using the quadratic formula to find y,
[tex]y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}[/tex]
where a = 1 b = -1 and c = -1
Substituting the values of the variables into the equation, we have
[tex]y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or \frac{3.236}{2}\\= -0.618 or 1.618[/tex]
Since y = (3/2)ˣ
Takung logarithm of both sides, we have
㏒y = ㏒(3/2)ˣ
㏒y = x㏒(3/2)
x = ㏒y/㏒(3/2)
x = ㏒y/㏒1.5
Since we do not have logarithm of a negative number, we use y = 1.618.
So, x = ㏒y/㏒1.5
x = ㏒1.618/㏒1.5
x = 0.2090/0.1761
x = 1.19
So, the value of x is 1.19
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You purchase one microsoft july $72 put contract for a premium of $1. 32. what is your maximum possible profit?
The maximum possible profit = $7068
For given question,
One Microsoft July $72 put contract for a premium of $1.32
The payoff arise from put option is max (K - S, 0) - P
Now it would be maximum at S = 0
And, the maximum payoff is
K - 0 - P
= K - P
= 72 - 1.32
= $70.68
We assume that for each and every contract the number of shares is 100
So, the maximum profit gained from this strategy is
= $70.68 × 100 shares
= $7068
The maximum profit that will be gained from this strategy is $7068
Therefore, the maximum possible profit = $7068
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A simple random sample is guaranteed to reflect exactly the population from which it was drawn.
a. true
b. false
Answer:
B
Step-by-step explanation:
PLLLLLEASE I NEEED HELP
Answer:
-3/(b-6) = 3/(-b+6) = 3/(6-b)
Step-by-step explanation:
7/(b-6) + 10/(6-b)
= 7/(b-6) + 10/(-b+6)
= 7-10/(b-6)
= -3/(b-6) = 3/(-b+6) = 3/(6-b)
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: \cfrac{7}{b - 6} + \cfrac{10}{6 - b} [/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{7}{b - 6} + \cfrac{10}{ - (b - 6)} [/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{7}{b - 6} - \cfrac{10}{ b - 6} [/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{ - 3}{ b - 6}\:\:\: or \:\:\: \dfrac{3}{6-b} [/tex]
Needdddd helpppp someone please
Answer:
none
Step-by-step explanation:
From the markings in the diagram above, we know that corresponding angles of the two triangles are congruent, but since we can make infinite number of triangles with same angle measures as triangle RIE by changing the side lengths, we cannot conclude that the triangles are congruent.
subtract the squre of m from the ratio of p andq
The expression that represent the given statement is p/q - m²
Writing an expressionFrom the question, we are to write an expression for the word problem
We are to write an expression for the statement
"Subtract the square of m from the ratio of p and q"
Square of m = m²
Ratio of p and q = p/q
Thus,
subtract the square of m from the ratio of p and q, becomes
p/q - m²
Hence, the expression that represent the given statement is p/q - m²
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Can someone tell me what this symbol means? Ty!!!
Answer:
Angle symbol
Angle ACB
Angle ACE
Angle DCE
Simplify
sin0 over
1-sin²0
Step-by-step explanation:
sin(0) = 0.
sin^2(0) = sin(0) × sin(0) = 0 × 0 = 0.
∴ sin(0) / 1 - sin^2(0) = 0 / 1 - 0
= 0 / 1
= 0.
What are the domain and range of the function?
domain:
range:
domain:
range:
domain:
range:
domain:
range:
The domain of f(x) = √(x - 7) +9 is x ≥ 7 and the range of f(x) = √(x - 7) +9 is y ≥ 9
How to determine the domain and the range?The function is given as:
f(x) = √(x - 7) +9
Set the radicand greater than or equal to 0
x - 7 ≥ 0
Add 7 to both sides
x ≥ 7
The above represents the domain
Set the radicand to 0
f(x) = 0 +9
So, we have
f(x) = 9
This represents the minimum value of the range.
So, the range is y ≥ 9
Hence, the domain of f(x) = √(x - 7) +9 is x ≥ 7 and the range of f(x) = √(x - 7) +9 is y ≥ 9
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Answer:
Step-by-step explanation:
Its A
What is the value of log5 125?
[tex] \rm log_{5}(125) \\ \rm log_{5}( {5}^{3} ) \\ \rm1 \cdot3 \\ 3 \\ \therefore \tt log_{5}(125) = 3[/tex]
Which statement is most likely to be true for this distribution?
Answer:
A
Step-by-step explanation:
the means is less than the median
A store has a 40 percent off sale on headphones. With this discount, the price of one pair of headphones is $36. What is the original price of the pair of headphones
Answer:
Discount =40\%
Selling price of headphone =\$36
Solution --
we know that,
MP=SP * 100/(100-D\%)
putting values now we get,
MP = 36 * 100 / 60=60$
so, initial price of Headphone was =$60
PLEASE HELP IM STUCK
Answer:
If I'm not mistaken that is the answer
4/5 + 9/10 what is this answer?
[tex]\boldsymbol{\sf{\dfrac{4}{5}+\dfrac{9}{10} } }[/tex]
The least common multiple of 5 and 10 is 10. Convert 4/5 and 9/10 to fractions with denominators of 10.
[tex]\boldsymbol{\sf{\dfrac{4\times2}{5\times2}+\dfrac{9}{10} \ \ \to \ \ Simplify }}[/tex]
[tex]\boldsymbol{\sf{ \dfrac{8}{10}+\dfrac{9}{10} }}[/tex]
Since 8/10 and 9/10 have the same denominator, join their numerators to add them.
[tex]\boldsymbol{ \sf{\dfrac{8+9}{10} \ \to \ \ Add }}[/tex]
Simplify
[tex]\boldsymbol{\sf{ \dfrac{17}{10}= }}\boxed{\boldsymbol{\sf{1\frac{7}{10} }}}[/tex]
What type of number is -560{,}114−560,114minus, 560, comma, 114? Choose all answers that apply: Choose all answers that apply:
The type of numbers which -560 and 114 are include the following:
B. Integer.
C. Rational.
What is a numerical data?A numerical data is also referred to as a quantitative data and it can be defined as a data set that is primarily expressed in numbers only. This ultimately implies that, a numerical data refers to a data set consisting of numbers rather than words.
The types of numbers.In Mathematics, there are six (6) common types of numbers and these include the following:
Natural (counting) numbers: these are 1, 2, 3, 4, 5, 6, .....114, ....560.Whole numbers: these comprises all natural numbers and 0.Integers: these are whole numbers that may either be positive, negative, or zero such as ....-560, ...... -114, ..... -4, -3, -2, -1, 0, 1, 2, 3, 4, .....114, ....560.Rational numbers: these comprises fractions, integers, and terminating (repeating) decimals such as ....-560, ...... -114, ..... -4, -3, -2, -1, -1/2, 0, 1, 1/2, 2, 3, 4, .....114, ....560.Irrational numbers: these comprises non-terminating or non-repeating decimals.Real numbers: these comprises both rational numbers and irrational numbers.In this context, we can infer and logically deduce that -560 and 114 are both an integer and a rational number.
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Complete Question:
What type of number is -560, 114? Choose all answers that apply:
A. Whole number
B. Integer
C. Rational
D. Irrational
Identify the ellipses, represented by equations, whose eccentricities are less than 0.5.
Ellipses that are represented by equations, whose eccentricities are less than 0.5 are:
(A) 49x2 -98x + 64yz +256y -2,831 = 0 (B) 81x2 -648x +100yz +200y -6,704 = 0 (F) 64x2 +512x +81y2 -324y -3,836 = 0What is an equation?An equation is a formula in mathematics that expresses the equality of two expressions by connecting them with the equals sign =. The word equation and its cognates in various languages may have somewhat different definitions; for example, in French, an équation is defined as including one or more variables, whereas in English, an equation is any well-formed formula consisting of two expressions linked by an equals sign.To identify the ellipses:
For the standard-form equation of an ellipse: Ax^2+Bx+Cy^2+Dy+E=0
We can define:
p=min(A,C)q=max(A,C)Then the eccentricity can be shown to be:
e=(1-p/q)p/q=1-e^2For Eccentricity<0.5, we want:
p/q>3/4Checking the values of p/q for the given equations, we have p/q= equations (A), (B), and (F) are of ellipses with eccentricity < 0.5.
Therefore, ellipses that are represented by equations, whose eccentricities are less than 0.5 are:
(A) 49x2 -98x + 64yz +256y -2,831 = 0 (B) 81x2 -648x +100yz +200y -6,704 = 0 (F) 64x2 +512x +81y2 -324y -3,836 = 0Know more about equations here:
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The complete question is given below:
Identify the ellipses, represented by equations, whose eccentricities are less than 0.5.
(A) 49x2 -98x + 64yz +256y -2,831=0
(B) 81x2 -648x +100yz +200y -6,704 =0
(C) 6x2 -12x +54y2 +108y -426 =0
(D) 49x2 + 196x +36y2 +216y -1,244 =0
(E) 4x +32x +25y2 - 250y +589 =0
(F) 64x2 +512x +81y2 -324y -3,836 =0
Solve the system to answer the questions.
How many premium car washes were ordered?
premium car washes
How many quick car washes were ordered?
quick car washes
The number of quick car and premium car washes ordered are 75 and 50 respectively.
How to find the number of premium and quick car washes ordered?The system of equation models the situation
x + y = 125
5x + 8y = 775
Therefore,
5x + 5y = 625
5x + 8y = 775
3y = 150
divide both sides 3
3y / 3 = 150 / 3
y = 50
Therefore,
x + y = 125
x + 50 = 125
x = 125 - 50
x = 75
Therefore, the number of quick car and premium car washes ordered are 75 and 50 respectively.
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Answer:
50 and 75
Step-by-step explanation:
11 points please help me
From the given sample data in the table on the backpack weight, we have;
(a) The means of the samples are;
First sample = 6.375Second sample = 6.375Third sample = 6.625(b) The range is 0.25
(c) The true statements are;
A single sample mean will tend to be a worse estimate than the mean of the sample meansThe farther the range of the sample means is from zero, the less confident they can be their estimate.How can the mean of the sample means be found?(a) The sample means of each of each of the three samples are found as follows;
[tex]Mean = \frac{ \sum \: x}{n} [/tex]
Where;
x = The value of a data point
[tex] \sum \: x = Sum of the data [/tex]
n = Sample size
The mean of the first sample, S1, data is therefore;
[tex]Mean \: S1 = \frac{3 + 7 + 8 + 3 + 7 + 9 + 6 + 8}{8} [/tex]
3+7+8+3+7+9+6+8 = 51
Which gives
[tex]Mean \: S1 = \frac{51}{8} = \mathbf{6.375\[/tex]
Mean of the first sample = 6.375Similarly, we have;
[tex]Mean \: S2 = \frac{8 + 6 + 4 + 7 + 9 + 4 + 6 + 7}{8} [/tex]
8 +6+4+7+9+4+6+7 = 51
Which gives;
[tex]Mean \: S2 = \mathbf{\frac{51}{8}} = 6.375 [/tex]
Mean of the second sample = 6.375
[tex]Mean \: S3 = \frac{9 + 4 + 5 + 8 + 7 + 5 + 9 + 6}{8} [/tex]
9+4+5+8+7+5+9+6 = 53
Which gives;
[tex]Mean \: S3 = \frac{53}{8} = \mathbf{6.625} [/tex]
Mean of the third sample = 6.625(b) The range of the means of the sample means is found as follows;
Range = Largest value - Smallest value
Which gives;
Range of the sample means = 6.625 - 6.375 = 0.25(c) The population mean is given by the mean of the sample means. That is, a very good estimate of the sample mean is given by the mean of the sample means.
The true statements are therefore;
A single sample mean will tend to be a worse estimate than the mean of the sample meansThe farther the range of the sample means is from zero, the less confident they can be their estimate.Learn more about the mean of the sample means of a collection of data here:
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