The correct option is B, the distance between mass reduces to half then gravitation force increases by four times.
According to newton's law of gravitation,
Force between two masses F = GMm / r^2
If distance is halved r = r/2
F' = GMm / (r / 2)^2 = 4GMm / r^2 = 4F
Gravitation force is a fundamental force of nature that exists between any two objects with mass. This force is responsible for keeping objects like planets, stars, and galaxies in motion, and is essential for the formation and stability of the universe. The force of gravity is proportional to the mass of the objects and the distance between them, according to the famous equation proposed by Sir Isaac Newton: F = G(m1m2)/d^2.
The force of gravity is an attractive force, meaning it pulls objects towards each other. This force is why objects fall to the ground when dropped and why planets orbit around their suns. The gravitational force also affects the flow of time and the curvature of space, as explained by Einstein's theory of general relativity.
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Complete Question: -
A planet is attracted to the sun with a certain force. if the distance from the sun to the planet is reduced by one half, what would happen to the force?
A. decreased by two times
B. increased by four times
C. increased by two times
D. decreased by four times
An incandescent light bulb filament produces light with a peak wavelength of 950 nm. Calculate the temperature of this filament.
Your answer:
Visible light is 400 – 700 nm. What part of the spectrum is this light bulb producing most of its light:
Your answer:
Since the peak isn’t visible light, why do you see it glowing? (A graph may help here.)
Your answer:
The temperature of the filament in an incandescent bulb that produces light with a peak wavelength of 950 nm is approximately 3042 Kelvin. This is calculated using Wien's Law, which states that the peak wavelength of light emitted is inversely proportional to its temperature. Although the bulb's peak output is in the infrared spectrum, it still emits light in the visible spectrum, giving it a warm white glow.
Explanation:To calculate the temperature of the filament in an incandescent bulb, we use Wien's Law which states that the peak wavelength of light emitted by a black body (here, the filament) is inversely proportional to its temperature. Mathematically it stands as λ_max = b/T, where λ_max is the peak wavelength, b is Wien's displacement constant (approximately 2.9*10^-3 m.K), and T the temperature in Kelvin.
Remember that the wavelength must be in meters, so convert 950 nm to meters, (which gives 950*10^-9 m).
Upon substituting these values: T = b / λ_max, you get T approximately equal to 3042 Kelvin. So, the filament's temperature would be around 3042 Kelvin.
The reason you see an incandescent bulb glowing despite its peak output being in the infrared spectrum (700nm - 1mm) is that it still emits light in the visible spectrum, but just not at its peak energy output. When viewed as a whole, the combined visible light appears as a warm white glow.
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an object is found to be moving in a circle with a constant speed. is there a force acting on the particle? if so, in what direction is this force. if not, why not? explain your reasoning.
Because the object's motion is moving in the same direction as the velocity vector, the velocity vector is also pointed in a tangent direction to the circle.
While it moves in a circle, an object constantly changes its direction. The path of the object is always perpendicular to the circle. Given that its direction matches the motion of the item, the velocity vector is also oriented tangent to the circle. While it moves in a circle, an object constantly changes its direction. The path of the object is always perpendicular to the circle. Given that its direction matches the motion of the item, the velocity vector is also oriented tangent to the circle. Within, there is force.
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tree is placed 15 cm of converging mirror the radius of curvature is 20 cm calculate the distance of image
A tree is placed cm from the converging mirror, and the radius of curvature is 20 cm. The distance of the image is 30 cm.
What is a converging mirror?A converging mirror is also known as a concave mirror, whose inner side has a reflecting surface. They are called converging mirror because it converges all parallel beam of light incident on them.
u = -15cm, object distance
R = -20cm (Converging mirror)
f = R/2 = -10 cm focal length
1/v + 1/u = 1/f
1/v + 1/-15 = 1/-10
1/v – 1/15 = -(1/10)
1/v = 1/15 – 1/10 = (2 -3)/30 = - (1/30)
v = - 30 cm
Therefore, the image is formed 30 cm in front of the mirror.
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a golfer hits an iron shot with a new club as she approaches the green. she is pretty sure, based on past experience, that she hit the ball with a speed of 50 m/s , but she is not sure at what angle the golf ball took flight. she observed that the ball traveled 100 m before hitting the ground. what angle did she hit the ball?
θ = 49.3° at this angle she hit the ball.
The initial velocity of the ball can be broken down into its x and y components:
Vₓ = 50 * cos(θ)
Vy = 50 * sin(θ)
The ball's position can be found using the kinematic equations for constant acceleration due to gravity:
[tex]X = V_{x} * t\\Y = V_{y}* t - (\frac{1}{2}) * 9.81 * t^{2}[/tex]
Since we know the ball's final position is 100 m, we can set these equations equal to 100 and solve for t:
[tex]100 = V_{x} * t\\100 = V_{y} * t - (\frac{1}{2}) * 9.81 * t^{2}[/tex]
From here, we can solve for the angle θ. Rearranging the initial velocity equation:
Vy = 50 * sin(θ)
We can substitute this into the equation for Y, and solve for θ:
θ = [tex]arcsin\frac{(2*(100 + (\frac{1}{2})*9.81*t^{2}))}{(50*t)}[/tex]
After solving the equations for t, we can plug that value into this equation for θ and get the angle at which the ball was hit.
The answer is θ = 49.3°
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A 4.7 kg cart is rolling down a ramp. Neglecting any friction and drag from impending motion, what is the magnitude of the normal force acting on the cart?
A. 45.1 N
B. 9.58 N
C. 46.1 N
D. 0.98 N
Since there is no friction, the normal force must be equal in magnitude and opposite in direction to the weight. Therefore, the magnitude of the normal force is also 46.06 N or 46.1 N.
What is force?The normal force is the force exerted by a surface perpendicular to the object in contact with the surface. In this case, the cart is rolling down the ramp, and the normal force is exerted by the ramp on the cart. Since the ramp is inclined, the normal force will be less than the weight of the cart, which is given by:
[tex]W = m*g[/tex]
where m is the mass of the cart and g is the acceleration due to gravity.
In this problem, the mass of the cart is given as 4.7 kg, and the acceleration due to gravity is approximately [tex]9.8 m/s^2.[/tex]
Therefore, the weight of the cart is:
[tex]W = 4.7 kg * 9.8 m/s^2 = 46.06 N[/tex]
Since there is no friction, the normal force must be equal in magnitude and opposite in direction to the weight. Therefore, the magnitude of the normal force is also 46.06 N.
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what is the surface charge density of the second sphere sigma 2 after they are connected in coulombs per square
The surface charge density of the second sphere (σ2) after they are connected is equal to the sum of the surface charge density of the first sphere (σ1) and wire (σ0)
The surface charge density of the second sphere (σ2) after they are connected is given by the equation
[tex]\sigma2 =\sigma1 + \sigma0[/tex]
where σ1 is the surface charge density of the first sphere and σ0 is the surface charge density of the connecting wire. Therefore, the surface charge density of the second sphere (σ2) after they are connected is equal to the sum of the surface charge density of the first sphere (σ1) and the surface charge density of the connecting wire (σ0).
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a drag chute must be designed to reduce the speed of a 3000-lb dragster from 220 mph to 50 mph in 4 sec. assume that the drag force is proportional to the velocity.what value of the drag coefficient k is needed to accomplish this?how far will the dragster travel in the 4-sec interva
Assuming that the drag force is proportional to the velocity, the dragster will travel approximately 392 meters during the 4-second interval.
To find the value of the drag coefficient k, we can use the following formula:
F = kv
where F is the drag force, k is the drag coefficient, and v is the velocity of the dragster.
At the initial velocity of 220 mph, the drag force is given by:
F₁ = kv₁
where v₁ is the initial velocity of 220 mph. Similarly, at the final velocity of 50 mph, the drag force is given by:
F₂ = kv₂
where v₂ is the final velocity of 50 mph.
During the 4-second interval, the average velocity of the dragster is:
vavg = (v₁ + v₂)/2 = (220 mph + 50 mph)/2 = 135 mph
Converting to SI units:
vavg = 60.54 m/s
The change in velocity during the 4-second interval is:
Δv = v₂ - v₁ = 50 mph - 220 mph = -170 mph
Converting to SI units:
Δv = -76.02 m/s
The acceleration of the dragster during the 4-second interval is:
a = Δv/t = (-76.02 m/s)/4 s = -19.01 m/s²
The drag force acting on the dragster is:
F = ma
where m is the mass of the dragster, which is given as 3000 lb, or 1360.78 kg (converting to SI units). Substituting the given values, we get:
F = (1360.78 kg)(-19.01 m/s²) = -25,874.8 N
At the initial velocity of 220 mph, the drag force is:
F₁ = kv₁ = k(220 mph) = 97.97 kN
Similarly, at the final velocity of 50 mph, the drag force is:
F₂ = kv₂ = k(50 mph) = 22.37 kN
Using the given information, we can set up the following system of equations:
F₁ - F₂ = -25,874.8 N
(97.97 kN) - (22.37 kN) = -25,874.8 N
Solving for k, we get:
k = (-25,874.8 N)/(170 mph) = (-25,874.8 N)/(76.02 m/s) ≈ -340.83 Ns²/m
Therefore, the drag coefficient k that is needed to reduce the speed of the dragster from 220 mph to 50 mph in 4 seconds is approximately -340.83 Ns²/m.
To find how far the dragster will travel in the 4-second interval, we can use the formula for distance traveled under constant acceleration:
d = vi × t + (1/2)at²
where vi is the initial velocity, t is the time interval, a is the acceleration, and d is the distance traveled.
Substituting the given values, we get:
d = (220 mph)(4 s) + (1/2)(-19.01 m/s²)(4 s)²
Converting the initial velocity to SI units:
d = (98.10 m/s)(4 s) + (1/2)(-19.01 m/s²)(16 s²) ≈ 392 m
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a motorist traveling at 11m/s encounters a deer in the road 41 m ahead. if the maximum acceleration the vehicle's brakes are capable of is -7m/s^2, what is the macimum reaction time of the motorist that will allow her or him to avoid hitting the deer? answer in units of s
The maximum reaction time of the motorist that will allow her or him to avoid hitting the deer is 1.57s
The maximum reaction time of the motorist will be the time it takes for the vehicle to come to a complete stop. To find this, we can use the equation:
Vf^2=Vi^2+2ad
Where Vf is the final velocity (0 m/s), Vi is the initial velocity (11 m/s), a is the acceleration (-7 m/s^2) and d is the distance (41 m).
We can rearrange this equation to solve for t, the time it takes for the vehicle to come to a complete stop:
t=-(Vi+Vf)/a
Plugging in our values, we get:
t=-(11+0)/(-7)
t= 1.57 s
Therefore, the maximum reaction time of the motorist will be 1.57 seconds in order to avoid hitting the deer.
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What is the change of GPE for a 8.0 kg object which is lowered from an initial height of 10 m above the floor to a final height of 4.0 m above the floor?
The change in gravitational potential energy, GPE for the 8 Kg object which is lowered from a height of 10 m to 4 m is -470.4 J
How do I determine the change in potential energy of the object?We'll begin by obtaining the initial potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₁) = 10 mAcceleration due to gravity (g) = 9.8 m/s² Initial potential energy (PE₁) = ?PE₁ = mgh₁
PE = 8 × 9.8 × 10
PE = 784 J
Next, we shall determine the final potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₂) = 4 mAcceleration due to gravity (g) = 9.8 m/s² Final potential energy (PE₂) = ?PE₂ = mgh₂
PE = 8 × 9.8 × 4
PE = 313.6 J
Finally, we shall determine the change in the potential energy. This is shown below:
Initial potential energy (PE₁) = 784 JFinal potential energy (PE₂) = 313.6 JChange in potential energy (ΔPE) =?ΔPE = PE₂ - PE₁
ΔPE = 784 - 313.6
ΔPE = -470.4 J
Thus, the change in potential energy is -470.4 J
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a standing 80 kg man steps off a 4.0 m high diving platform and begins to fall from rest. the man comes to rest 2.0 seconds after reaching the water. what average force did the water exert on him?
Weight of the man = m * g = 80 kg * 9.81 m/s^2 = 784.8 N
Potential energy of the man = mgh = 80 kg * 9.81 m/s^2 * 4.0 m = 3139.2 J
Using the formula for work done by a force, the average force exerted by the water on the man can be calculated as: F = (mgh) / d = 3139.2 J / 2.0 s = 1569.6 N.
Therefore, the average force exerted by the water on the man is 1569.6 N.
What is the mass of the man who steps off the diving platform in this scenario?The mass of the man who steps off the diving platform is given as 80 kg in this scenario. Mass is a fundamental property of an object that describes the amount of matter present in it. In this case, the man is considered as a single object with a mass of 80 kg. This mass value is important in calculating the force exerted by the water on the man as he comes to rest. The mass of an object is an essential parameter in many physical calculations such as the calculation of kinetic energy, potential energy, and force.
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why do these two magnets attract each other
The force that magnets use to either attract or repel one another is known as magnetism. Electric charges in motion are what generate magnetism.
What is Magnetism?The smallest building blocks of matter are called atoms. There are electrons in every atom, which are charged particles. The electrons that make up an atom's nucleus, or core, spin like tops.
The magnetism of most things is cancelled out by the equal amounts of electrons that spin in opposing directions. Because of this, substances like fabric and paper are referred to as weakly magnetic.
Most electrons in materials like iron, cobalt, and nickel spin in the same direction. The atoms in these become this way.
Therefore, The force that magnets use to either attract or repel one another is known as magnetism. Electric charges in motion are what generate magnetism.
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Words that sound the same but have different meanings are called
Words that sound the same but have different meanings are called
synonyms.
homophones.
antonyms.
Option homophones is the correct option.
Words that sound the same but have different meanings are called homophones.
A term that has the same pronunciation as another word but a different meaning is called a homophone. Moreover, a homophone's spelling may vary. The two words can have the same spelling, as in rose and rose, or they can have a distinct spelling, as in rain, reign, and rein.
A homophone is defined as "one of two or more words pronounced alike but different in meaning, derivation, or spelling" by the Merriam-Webster Dictionary. Homophones are described as "words having various meanings which are spoken in the same way but are spelt differently" by the Collins Dictionary.
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Note: The correct question would be as bellow,
Words that sound the same but have different meanings are called
synonyms.
homophones.
antonyms.
The soil sample was contaminated with equal amounts of caesium-137 and
iodine-131
Explain how the risk linked to each isotope has changed between 1986 and 2018
Both isotopes emit the same type of radiation.
Both caesium-137 and iodine-131 emit ionizing radiation, which can damage living tissue and increase the risk of cancer.
What are isotopes?Isotopes are members of the same element's family but have variable numbers of neutrons despite having the same number of protons.
Iodine-131 and caesium-137 both produce ionizing radiation, which can harm living things and raise the risk of cancer.
Due to their varied half-lives and processes of decay, each isotope's danger has changed between 1986 and 2018 despite this.
Caesium-137 degrades gradually over time since it has a longer half-life of roughly 30 years. Iodine-131, on the other hand, degrades swiftly because of its significantly lower half-life of only around 8 days.
Thus, the risk has diminished over time as a result of radioactive decay.
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a simple bob pendulum has a length of 1.05 meters. what would be the period of the pendulum on earth were the acceleration do to gravity is 9.81m/s2?
The time period of the simple bob pendulum on earth is found to be 0.21 seconds.
Explain the time period for simple bob pendulum?The length of a basic pendulum is: It is symbolised by the letter "T" and is defined as the amount of time needed for the pendulum to complete one full oscillation.
The simple pendulum's amplitude: The distance the pendulum travels from its equilibrium point to one side is how it is defined.At amplitudes less than around 15o, a mass m suspended by such a wire of length L behaves like a simple pendulum and experiences simple harmonic motion. The length of the string is L, and the acceleration caused by gravity is g, hence the period of the a simple pendulum.Acceleration due to gravity g = 9.81m/s2.
Length of the simple bob pendulum l = 1.05 meters.
Time period T ;
T = 2π√l/g
T = 2*3.14*√(1.05/9.81)
T = 0.2055
T = 0.21
Thus, the time period of the simple bob pendulum on earth is found to be 0.21 seconds.
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what is the frequency of the oscillation? express your answer to two significant figures and include the appropriate units.
The frequency of the oscillation can be calculated as the inverse of the period: f = 1 / T = 1 / 4 units.
Based on the description, we can see that the waveform has a period of 4 units on the x-axis since it completes one full cycle over that distance.
Therefore, the frequency of the oscillation can be calculated as the inverse of the period:
f = 1 / T = 1 / 4 units
Expressing the frequency to two significant figures and including the appropriate units, we get:
f = 0.25 [tex]units^{-1}[/tex]
The frequency of this wave can be calculated by measuring the distance between two consecutive points of maximum amplitude, which in this case is one complete cycle.
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when a radiologist reads an mri or ct scan do they check everything visible or just the area in question?
While radiologists do review all the images in a study, they will typically give more attention to the area of interest in order to provide an accurate diagnosis and ensure that the patient receives the best possible care.
When a radiologist reads an MRI or CT scan, they typically review all the images in the study, not just the area of interest. This is because other areas of the body may contain important incidental findings that could impact a patient's overall health and require further investigation or treatment.
The radiologist will typically focus their attention on the area of the body that has been requested for imaging. They will thoroughly examine the relevant region, and looking for any abnormalities, injuries, or other issues that may be present.
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a baseball is thrown by the center fielder (from shoulder level) to home plate it is caught (on the fly at shoulder level) by the catcher. at what point is the magnitude of the acceleration at a minimum?
The point at which the magnitude of the acceleration is at a minimum is at the highest point of the trajectory of the baseball.
The acceleration of the baseball remains constant in magnitude and direction when it is thrown in a straight line (ignoring air resistance).
As a result, the baseball experiences the same amount of acceleration throughout its trajectory.
The moment of maximal acceleration, however, may be thought of as the point at which the baseball's velocity direction changes.
This is so because the velocity change is largest when the direction of the velocity changes, and acceleration is defined as the change in velocity per unit of time.
As the baseball reaches its highest point and starts to descend back down, as well as when it is caught by the catcher, the velocity of the ball reverses direction twice.
Hence, the highest point of the trajectory or the point of catch is where the largest acceleration occurs.
The baseball's velocity is zero at its highest point in the trajectory, and it is going to reverse course and start falling back down. Thus, this is the moment of maximum acceleration.
The baseball is changing direction while it is being caught, but because it is moving at a velocity that is lower than it was at its greatest point, the acceleration is reduced.
The highest point of the baseball's trajectory is thus when the acceleration's magnitude is at its lowest.
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Would the field representation of a positive or negative charge be a better representation for the gravitational field around one mass? why?
Copernicus said that the rotation of the Earth on its axis caused the
A. phases of the Moon.
B. retrograde motion of the planets.
C. eclipses of the Moon
D. motion of the Sun along the ecliptic.
E. daily motions in the heavens.
According to this theory, the Sun lies at the center of the solar system and the Earth's rotation around its own axis is what causes the days and nights to alternate. Thus, option C is correct.
What is the rotation of the Earth on its axis cause?Day and darkness are created by the Earth's axis rotating. Only half of the Earth faces the sun at any given time due to rotation. Daylight is present on the side facing the sun, while darkness is present on the side facing the sun (night).
To share his theory of the cosmos with his pals, Copernicus wrote a book by hand. In it, he put out the theory that the sun rather than Earth was the centre of the universe.
Therefore, Copernicus said that the rotation of the Earth on its axis caused the eclipses of the Moon.
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the small metal sphere has a mass of 5 grams. what is the gravitational force acting on it from the earth?
The required gravitational force acting on the metal sphere from the earth is calculated to be 0.049 N.
The mass of the sphere is given as 5 g = 5/1000 = 0.005 kg
We know the relation for gravitational force as,
F = G M m/r²
where,
G is the gravitational constant (6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²)
M is the mass of the earth (6 × 10²⁴ kg)
m is the mass of the object
r is the radius of the earth (6.4 × 10⁶ m)
Entering the values into the above equation,
F = G M m/r² = (6.67 × 10⁻¹¹ ×6 × 10²⁴ × 0.005)/(6.4 × 10⁶)² = (0.2001× 10¹³)/(40.96 × 10¹²) = 0.049 N
Thus, the gravitational force is calculated to be 0.049 N.
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calculate the height (in m) of a cliff if it takes 2.24 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.04 m/s.
The height of the cliff is 13.2 meters. We can solve this problem using the kinematic equations of motion. The key equation that we need to use is the equation that relates the final velocity (vf), initial velocity (vi), acceleration (a), displacement (d), and time (t): [tex]vf = vi + at[/tex]
If we assume that upward is the positive direction, then the acceleration due to gravity (g) is negative (-9.81 m/s^2), and the initial velocity of the rock is +8.04 m/s. We want to find the height of the cliff, which is the displacement of the rock when it hits the ground. We can use the equation above to solve for the time it takes for the rock to reach its maximum height, and then use this time to calculate the height of the cliff.
Step 1: Find the time it takes for the rock to reach its maximum height
At the maximum height, the final velocity of the rock is zero, so we can set vf = 0 in the equation above and solve for the time, t:
[tex]vf = vi + at\\0 = 8.04 m/s - 9.81 m/s^{2}*t\\t =\frac{ 8.04 m/s }{ 9.81 m/s^{2}}\\t = 0.82 s[/tex]
So, it takes 0.82 seconds for the rock to reach its maximum height.
Step 2: Find the displacement of the rock when it hits the ground
Since the rock was thrown straight up, it will take the same amount of time to reach its maximum height as it will take to fall back to the ground. So, the total time of flight is 2*t = 1.64 s. During this time, the displacement of the rock is equal to the height of the cliff. We can use the equation that relates displacement to initial and final velocity and time:
[tex]d = vit + \frac{1}{2}a*t^{2}[/tex]
To use this equation, we need to find the final velocity of the rock just before it hits the ground. Since the rock was thrown straight up, its velocity when it hits the ground is equal in magnitude but opposite in direction to its initial velocity:
vf = -8.04 m/s
Now we can plug in the values and solve for the displacement:
[tex]d = vit +\frac{ 1}{2}at^{2}\\d = 8.04 m/s * 1.64 s +\frac{1}{2}(-9.81 m/s^2)*(1.64 s)^{2}\\d = 13.2 m\\[/tex]
Therefore, the height of the cliff is 13.2 meters.
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(a) Why the maximum tidal range (spring tide) occurs during a new moon and full moon phases?(b) Why the minimum tidal range (neap tide) occurs at first-quarter and third-quarter moons?
(a) The maximum tidal range (spring tide) occurs during a new moon and full moon phases because the sun and moon's gravitational pulls are aligned and amplified.
(b) The minimum tidal range (neap tide) occurs at first-quarter and third-quarter moons because the sun and moon's gravitational pulls are at right angles.
(a) As the sun and moon's gravitational pulls are aligned and amplified during the new moon and full moon phases, the maximum tidal range, or spring tide, occurs during these periods. With the moon and sun on opposing sides of the Earth, the sun, moon, and Earth are all in a straight line during a new moon. Due to the moon's proximity to Earth, its gravitational pull on the planet is at its greatest. Due to its alignment with the moon and Earth, the sun's gravitational pull also contributes to this. A broader tidal range results from the seas bulging due to this alignment, which also generates higher peak tides and lower low tides.
(b) As the sun and moon's gravitational pulls are at right angles during the first and third quarters of the moon, the shortest tidal range, or neap tide, occurs at these periods. With the sun and moon on opposing sides of the Earth, the sun, Earth, and moon make a straight angle during a first-quarter moon. The gravitational pull of the sun partially cancels out the gravitational pull of the moon on Earth, reducing the tidal range. When the moon is quartered, the same thing takes place. There is a narrower tidal range at these periods because the high tides are lower and the low tides are higher.
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Referring to the information PEI received through March 2010 from the Stop the Static Campaign
reading, what were some other important data points PEI reported?
Answer: a new and dynamic data portal that provides an overview of the key design and implementation aspects of economic inclusion programs globally.
Explanation:
plato
(a)6an electron is to be accelerated from 3.00 * 106 m>s to 8.00 * 10 m>s. through what potential difference must the electron pass to accomplish this? (b) through what potential differ- ence must the electron pass if it is to be slowed from 8.00 * 106 m>s to a halt?
The work-energy theorem may be able to shed some light on the forces when an object's motion is known but the magnitudes of one or more of the forces acting on it are unknown. The work-energy theorem is applicable to forces that are both constant and variable.
What is the work energy theorem?The work-energy theorem states that the total work done by forces acting on an item is equal to the change in kinetic energy.
This theorem states that the net work performed on a body is equal to the change in the body's kinetic energy. The Work-Energy Theorem describes this. Kf - Ki = W is a representation of it.
(A)
from work energy theorem,
work done = change in kinetic energy
[tex]w = \frac{1}{2} mv^2 - \frac{1}{2} m u^2[/tex]
[tex]ev= \frac{1}{2} mv^2 - \frac{1}{2} m u^2[/tex]
[tex]V = \frac{1}{2e} [mv^2- mu^2][/tex]
[tex]V = \frac{1}{2(1.60\times 10^-19C)} [(9.11\times 10^-31kg) (8.00\times 10^6\frac{m}{s})^2- [(9.11\times 10^-31kg) (3.00\times 10^6\frac{m}{s})^2][/tex]
[tex]=157v[/tex]
The potential difference of electron is 157V.
(B)
[tex]w = \frac{1}{2} mv^2 - \frac{1}{2} m u^2[/tex]
[tex]ev= \frac{1}{2} mv^2 - \frac{1}{2} m u^2[/tex]
[tex]V = \frac{1}{2e} [mv^2- mu^2][/tex]
[tex]V = \frac{1}{2(1.60\times 10^-19C)} 0 - [(9.11\times 10^-31kg) (3.00\times 10^6\frac{m}{s})^2][/tex]
[tex]= 25.6V[/tex]
The potential difference of electron is 25.6V
Therefore, for (a) potential difference of electron is 157V and for (b) potential difference of electron is 25.6V
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The crests on a long surface waterwave are 20m apart and in 1 minute 10 crests pass by. What is the speed of this wave
The speed of this surface water wave is 3.33 meters per second.
The speed of a surface water wave depends on the wavelength and the frequency of the wave.
The speed of a surface water wave can be determined by the equation:
speed = wavelength × frequency
Here, the wavelength is given as 20 meters (the distance between two successive crests), and the frequency can be calculated by dividing the number of crests passing by in one minute (60 seconds) by the time taken for them to pass:
frequency = 10 crests / 1 minute = 10/60 Hz = 1/6.0 Hz
Put values:
speed = 20 meters × (1/6.0 Hz) = 3.33 meters/second
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In which state of matter, do the particles have the maximum energy?
A
Solid
B
Liquid
C
Gas
D
None of these
a solid ok thank you
hope it helps
d.if a third type of charge existed, how would it affect the two oppositely charged strips in this activity?
Because it would attempt to draw in all the sides at once, it would probably spiral out of control.
Electrostatics is the study of electric charges in a stationary state (static electricity). Certain materials, like amber, have been known to collect light particles after rubbing since antiquity. The Greek word for amber, v, was used to create the English word "electricity". Electrostatic phenomena are caused by the interactions between electric charges. Such forces are described by Coulomb's law.
Although certain a electrostatic forces are relatively powerful, electrostatically generated forces often appear to small. The gravitational force between two objects is about 36 orders of magnitude weaker than the force between an electron and a to proton, which make up a hydrogen atom.
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An object slides at constant speed on the frictionless surface. What forces act on the object? What work is done by each force?
There are two main forces acting on an object sliding at a constant speed on a frictionless surface: gravity and the normal force. No force happens in the direction of displacement of the object because the object is sliding at a constant speed.
Gravity is the force that pulls the object downward, while normal force is the force that pushes the object upward to counteract gravity. Since the object is sliding at a constant speed, these two forces are equal and opposite, which means that they cancel each other out. As a result, there is no net force acting on the object, and therefore no work is being done by either force.
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A 65kg bicyclist (including the bicycle), initially at rest, pedals to the right, generating 200N of force for 6s. During this time, they experience 40N drag. Neglect any
additional friction impeding their motion. Their net force on the bicycle is
A. 240 N
B. 160 N
C. 305 N
which two changes would decrease the dencity of ocean water
The two changes that would decrease the density of ocean water are increasing its temperature and Decreasing it's salinity.
What is density?
Density is a measure of how much mass is contained in a given unit of volume. It is usually expressed in g/cm3 or kg/m3. It is a measure of how tightly the molecules of a substance are packed together. Density is an important physical property of a material because it affects how it interacts with other materials, how it behaves under different conditions, and how it is affected by forces such as gravity.
The density of seawater is determined by its temperature and salinity. As the temperature of seawater increases, the density of the water decreases. This is because the molecules of water expand and move farther apart as they are heated, resulting in a decrease in the mass per unit volume of water. Similarly, as the salinity of seawater decreases, the density of the water also decreases. This is because the salt in seawater increases the mass per unit volume of water, making the water denser. If the amount of salt in the water decreases, then the water will be less dense.
Therefore, increasing its temperature and Decreasing it's salinity decrease the density of ocean water.
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