A position control system is given by the negative feedback control system below. Suppose that the control system specifications are: e_ss = 0.025 in response to a unit ramp reference input M_p lessthanorequalto 0.20 for a unit step reference input (a) Determine the gain K that meets the steady-state error specification. (b) From the constraint on M_p, what is the constraint on the phase margin of the system? (c) Use the MATLAB command margin to evaluate the phase margin of the system with the value of K from part (a). Based on the constraint in part (b), is the phase margin acceptable, or would you need to add a lead compensator to the control system to increase it? d) You now add a lead compensator, D_lead(s) = tau_D s + 1/alpha tau_D s + 1, that will be placed in series with the preamplifier K. Design the compensator so that that the closed-loop system response to a unit step reference input has no more than 20% overshoot (Mp lessthanorequalto 0.20). Verify that the closed-loop system meets this overshoot specification. Hand in your code.

Answers

Answer 1

Designing a control system is a hard task that calls for programming expertise as well as a solid grasp of control theory. For extra advice, speaking with a control system specialist or a professor in the area may be beneficial.

(a) You must compute the steady-state error for a unit ramp reference input in order to find the gain K that satisfies the steady-state error criterion. E ss = 1/Kp, where Kp is the system's position gain, yields the steady-state error.(b) The phase margin of the system is connected to the restriction on M p. The minimum needed phase margin for the system can be determined using the relationship between M p and the phase margin. (c) You may assess the phase margin of the system using the value of K from part by using the MATLAB command margin (a). You can decide whether the phase margin is appropriate or whether you need to add a lead based on the constraint in part compensator to make it bigger.(d) The needed damping ratio of the closed-loop system must be calculated using the intended overshoot specification in order to construct the lead compensator. The lead compensator's parameters can then be determined using the required damping ratio and the frequency at which the phase margin is attained.

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Related Questions

an inability to retrieve information learned in the past is called?

Answers

The inability to retrieve information learned in the past is called retrograde amnesia.

It is a form of memory loss that results in the inability to recall past memories or previously learned information. It is usually caused by physical trauma, stroke, certain drugs, and diseases. Retrograde amnesia affects the ability to remember events and experiences that occurred prior to the onset of amnesia. Symptoms may also include difficulty in remembering recent events and recognizing familiar people and places. Treatment usually involves medications and psychotherapy to help patients remember and cope with the changes in their life caused by their amnesia.

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How do you replace old weather stripping on a door?

Answers

Replacing old weather stripping on a door is a straightforward process that can help improve your home's energy efficiency.

Here are the steps to replace old weather stripping on a door:

Remove the Old Weather Stripping To remove the old weather stripping, use a putty knife to loosen the adhesive or nails that hold the stripping in place. Once the weather stripping is loose, you can remove it by pulling it off the door.

Clean the Door Surface After removing the old weather stripping, clean the door surface thoroughly. This will ensure that the new weather stripping adheres properly. Use a clean, dry cloth to wipe the surface clean.

Measure and Cut the New Weather Stripping Measure the length of the door jamb and cut the new weather stripping to fit. Be sure to leave a small amount of excess weather stripping so that it overlaps at the ends.

Install the New Weather Stripping Once you have cut the new weather stripping, peel off the backing to expose the adhesive. Carefully place the weather stripping onto the door jamb, starting at the top and working your way down. Be sure to press the weather stripping firmly against the door jamb to ensure a secure fit.

Check the Fit Test the fit of the new weather stripping by closing the door. The weather stripping should form a tight seal around the door. If there are any gaps or spaces, adjust the weather stripping as needed.

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the components of an electronic system dissipating 220 w are located in a 1-m-long circular horizontal duct of 15 cm diameter. the components in the duct are cooled by forced air, which enters at 27oc at a rate of 0.65 m3/min. assuming 85 percent of the heat generated inside is transferred to air flowing through the duct and the remaining 15 percent is lost through the outer surfaces of the duct, determine a) the exit temperature of air and b) the highest component surface temperature in the duct. evaluate the properties of air at a bulk mean temperature of 35 oc. assume fully developed turbulent flow in the entire duct because the components will cause turbulence

Answers

The highest component surface temperature in the duct is 414.7°C. We can calculate it in the following manner.

To solve this problem, we need to use the energy balance equation for the control volume. The energy balance equation is given as:

Q_in = Q_out + Q_gen

where, Q_in is the heat transfer rate from the entering air, Q_out is the heat transfer rate to the exiting air, and Q_gen is the heat generated by the electronic components.

a) To find the exit temperature of air, we can write:

Q_in = m_dot * Cp * (T_exit - T_in)

where, m_dot is the mass flow rate of air, Cp is the specific heat of air, T_exit is the exit temperature of air, and T_in is the inlet temperature of air.

Using the given values, we have:

m_dot = 0.65 m³/min = 0.65/60 = 0.01083 m³/s

Cp = 1005 J/(kg*K)

T_in = 27 + 273 = 300 K

We can find Q_in as follows:

Q_in = 0.85 * 220 = 187 W

Substituting these values in the energy balance equation, we get:

187 = 0.01083 * 1005 * (T_exit - 300)

Solving for T_exit, we get:

T_exit = 215.5 K

Therefore, the exit temperature of air is 215.5 - 273 = -57.5°C.

b) To find the highest component surface temperature in the duct, we can use the energy balance equation again as:

Q_gen = Q_out + Q_loss

where, Q_loss is the heat loss through the outer surfaces of the duct.

Using the given values, we have:

Q_gen = 220 W

Q_out = m_dot * Cp * (T_exit - T_in)

Q_loss = 0.15 * Q_gen = 33 W

Substituting these values in the energy balance equation, we get:

220 = 0.01083 * 1005 * (T_exit - 300) + 33

Solving for T_exit, we get:

T_exit = 414.7 K

Therefore, the highest component surface temperature in the duct is 414.7°C.

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How to run a C program in Visual Studio Code?

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To execute a C program in Visual Studio Code, you must first create a C project. You can create a new C project in Visual Studio Code by following these steps:

Click on the Explorer icon on the left-hand side of the window.In the Explorer, click on the folder where you want to store your project.Right-click on the folder, then click on New File.Type in the name of your project with a ".c" extension, for example "hello.c."Once the file is created, click on the Terminal icon on the bottom of the window.Type "gcc -o hello hello.c" in the Terminal window and press Enter.If there are no errors, a new executable file called "hello" will be created.Type "./hello" in the Terminal window and press Enter to run the program.The output of the program will be displayed in the Terminal window.

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The following are the impulse responses of continuous-time LTI systems. Determine whether each system is causal and/or stable. Prove your answers. The proof for stability needs to in terms of the integration condition (a) h(t) = e^(-4t) u(-t - 2) (b) h(t) = e^(-1/2 t) u (t-2) (c) h(t) = e^(-0,1t) u(t + 100) (d) h(t) = e^(4t) u(t-2) (e) h(t) = e^(|t|) (f) h(t) = t^2 e^(-t) u(t) (g) h(t) = (2e^(-t/2) + e^[(10-t)/10)} u(t+2)

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A) This system is causal in integration condition because the unit step function u(-t-2) is zero for all t < -2.

What is integration condition?

Integration condition is a mathematical technique used to solve a differential equation. It is used to determine a general solution to a differential equation by combining all its particular solutions. Integration condition involves specifying the values of certain constants that appear in the solution to a differential equation in order to match the behavior of the equation at specified points.

b) This system is causal and stable because it has a finite impulse response h(t) = e^(-1/2 t) u (t-2) and the integral from -∞ to +∞ is finite.

c) This system is causal because the unit step function u(t+100) is zero for all t < 100.

d) This system is not causal because the unit step function u(t-2) is non-zero for all t < 2.

e) This system is not causal because the absolute value function |t| is non-zero for all t < 0.

f) This system is causal because the unit step function u(t) is zero for all t < 0.

g) This system is causal because the unit step function u(t+2) is zero for all t < 2.

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which of the following will help you to determine an ap arrangement that will ensure reliable wireless connectivity?

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An AP arrangement that will ensure reliable wireless connectivity can be determined by:

Choosing the right frequency band: 2.4 GHz or 5 GHzPlacing the APs in optimal locationsUsing a wireless site survey tool to identify any potential interference sourcesAdjusting the transmit power of the APsEnsuring that the APs are configured with the correct security settings

By following these steps, you can ensure that your wireless network will have reliable connectivity and be able to handle the demands of your users.

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what body of water would most ships use to transport goods from asia to europe?

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Most ships transporting goods from Asia to Europe will use the Suez Canal, which is a 190-mile-long artificial waterway in Egypt.

It connects the Mediterranean Sea to the Red Sea and allows for the passage of vessels of up to 20,000 tonnes. The canal is an invaluable shortcut for ships heading from Europe to Asia, as it cuts several days off the journey. It is also important for trade in both regions, with over 19,000 vessels making the trip in 2019. The Suez Canal is the main artery for vessels making the journey between Asia and Europe, making it the body of water most often used.

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Rotors designed using lift to generate rotation spin at lower speeds than rotors designed drag to generate the rotation. False True

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The given statement "Rotors designed using lift to generate rotation spin at lower speeds than rotors designed drag to generate the rotation." is True because lift-based rotors are typically able to generate more lift from the same amount of air and require lower spin speeds than drag-based rotors.

Lift-based rotors can generate more lift from the same amount of air passing over them, meaning that less power is needed to rotate the blades. Additionally, lift-based rotors typically have more blades and a more aerodynamic shape than those designed with drag in mind, further reducing the necessary spin speed.

The main benefit of lift-based rotors is their increased efficiency. This is because they are able to produce more lift with the same amount of power, meaning that the same amount of power can be used to fly at higher speeds or greater distances. Additionally, they can be used in quieter and more efficient helicopters, as they can achieve the same speeds and ranges with less power.

In summary, lift-based rotors are typically able to generate more lift from the same amount of air and require lower spin speeds than drag-based rotors. This allows for increased efficiency, quieter operation, and better performance.

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tech a says that when reading dc voltage on a meter, a before the number means that the probing lead is touching osmething more positive than the common lead

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Tech A is correct who states that when reading DC voltage on a meter, a "+" before the number means that the probing lead is touching something more positive than the common lead.

When reading DC voltage on a meter, a "+" before the number means that the probing lead is touching something more positive than the common lead. This is because DC voltage is measured in reference to a common point, which is typically the negative terminal of a battery or power supply. The probing lead is the positive lead and the common lead is the negative lead.

When the probing lead is touching something more positive than the common lead, the meter will display a "+" before the number to indicate a positive voltage. If the probing lead is touching something more negative than the common lead, the meter will display a "-" before the number to indicate a negative voltage.

"

Complete question

Tech A says that when reading DC voltage on a meter, a "+" before the number means that the probing lead is touching osmething more positive than the common lead. Is Tech A correct?

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a rough rule for leather belt is that effective tension in it, shall not exceed 15 n/mm of width for a belt of 10 mm thickness. this rule is applied to determine width of belt required to transmit 37 kw, under the following conditions: angle of lap = 165º; coefficient of friction=0.3; velocity of belt = 1500 m/min; density of leather = 950 kg/m find the width of belt required. assuming limiting friction between belt and pulley rim, find the stress in the belt

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The stress in the belt is calculated as follows: Stress in belt = 212.12 N / (14.14 mm x 10 mm) = 1.50 N/mm2.

How should a leather belt be sized?

Just "add 2" to your off-the-rack trouser size will yield the belt size. For instance, a 38-belt size will be a good bet if you wear 36" waist trousers. Most people will discover that this straightforward method works best when pants are worn at the customary height—near the natural waistline.

Power = (Tension in belt) x (Belt speed)

Tension in belt = (Power x 1000) / (Belt speed x Angle of lap x Coefficient of friction)

Substituting the given values, we get:

Tension in belt = (37,000 x 1000) / (1500 x 165 x 0.3) = 212.12 NEffective tension in belt = 15 N/mm x Belt width

Belt width = Effective tension in belt / 15 N/mmBelt width = 212.12 N / 15 N/mm = 14.14 mm

Stress in belt = Tension in belt / (Belt width x Belt thickness)

Substituting the given values, we get:

Stress in belt = [tex]212.12 N / (14.14 mm x 10 mm) = 1.50 N/mm^2[/tex]

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use the construction given in theorem 1.39 to convert the following two nondeterministic finite automata to equivalent deterministic finite automata.

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In order to convert the two given nondeterministic finite automata (NFA) to equivalent deterministic finite automata (DFA), we will use the construction given in theorem 1.39. This theorem states that for every NFA, there exists an equivalent DFA.

First, we need to create a new set of states for the DFA. This set of states will be the power set of the states in the NFA. For example, if the NFA has states {q0, q1, q2}, the DFA will have states {{q0}, {q1}, {q2}, {q0, q1}, {q0, q2}, {q1, q2}, {q0, q1, q2}}.Next, we need to create the transition function for the DFA. For each state in the DFA and each input symbol, we will find the set of states that the NFA could be in after reading that symbol from that state. This set of states will be the new state in the DFA.Finally, we need to determine the set of final states for the DFA. A state in the DFA will be a final state if it contains at least one final state from the NFA.

Using this construction, we can convert the two given NFAs to equivalent DFAs. The resulting DFAs will have the same language as the NFAs, but will be deterministic, meaning that for each state and input symbol, there is only one possible next state.

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Complex Exponential Periodicity: Letx(t)be the continuous time complex exponential signalx(t)=ejω0​twith fundamental frequencyω0​and fundamental periodT0​=2π/ω0​. Consider the discrete-time signal obtained by taking equally spaced samples ofx(t)- that is,x[n]=x(nT)=ejω0​nT.(a) Suppose thatT=2.5T0​. What are the fundamental period and fundamental frequency ofx[n]? (b) How many periods ofx(t)are needed to obtain the samples that form a single period ofx[n]. (c) Suppose thatT=2​T0​. Do you think thatx[n]will be periodic? Why or why not?

Answers

a. To find out the fundamental frequency and fundamental period of x[n] with T = 2.5 T0, here’s what we do:Given that the fundamental period of x(t) is T0 = 2π/ω0and the sampling period T = 2.5T0; then the fundamental frequency of x[n] will be: ω0' = ω0/T0'ω0' = ω0/ (2.5T0)ω0' = (1/2.5) ω0ω0' = (2/5)ω0and, the fundamental period of x[n] will be: T0' = T/1T0' = (2.5T0)/1T0' = 2.5 T0.

Taking equally spaced samples of x(t) (with the sampling period T), the minimum number of samples needed to capture a single period of x[n] is given by: N = T/T0N = (2.5 T0)/(2π/ω0)N = (5ω0/4π)Hence, 5ω0/4π periods of x(t) are needed to obtain the samples that form a single period of x[n].

b. To find out if x[n] is periodic when T = 2T0; we compare the sampling period T with the fundamental period of x(t) (i.e. T0). We have:T = 2T0Since the sampling period T is a multiple of the fundamental period T0, the samples are NOT affected by any aliasing and hence x[n] is periodic.

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A long chord from PC and PT of a compound curve is 590 feet long and the angles it makes with the forward and back tangents are 12° and 18°, respectively. If the common tangent is parallel to the long chord.
a. Find the radius of the first curve.
b. Find the radius of the 2nd curve.
c. If the stationing of PC is 10 + 204.30, find the stationing of PT.
d. Compute the length of the common tangent.
e. Compute the shortest distance between the vertex and the PCC.

Answers

If the common tangent is parallel to the long chord:

a. The radius of the first curve is 1718.42 feet.

b. The radius of the 2nd curve is 1070.29 feet

c. The stationing of PT is 2192.98

d. The length of the common tangent is 193.43 feet

e. The shortest distance between the vertex and the PCC is 371.59 feet

B. To find the radius of the first curve, we can use the following formula:

R₁ = L / (2 sin A)

Where:

L = length of long chord = 590 feet

A = angle made with forward tangent = 12°

Plugging in the values, we get:

R₁ = 590 ÷ (2 sin 12°)

R₁ ≈ 1718.42 feet

B. To find the radius of the second curve, we can use the same formula:

R₂ = L ÷ (2 sin B)

Where:

B = angle made with back tangent = 18°

Plugging in the values, we get:

R₂ = 590 ÷ (2 sin 18°)

R₂ ≈ 1070.29 feet

C. The length of the entire compound curve can be found using the formula:

LC = R₁ cot A + R₂ cot B

Where:

cot A = 1 ÷ (tan A)

cot B = 1 ÷ (tan B)

Plugging in the values, we get:

LC = R₁ cot 12° + R₂ cot 18°

LC ≈ 2178.68 feet

To find the stationing of PT, we add the length of the curve to the stationing of PC:

PT = PC + LC

PT = 10 + 204.30 + 2178.68

PT ≈ 2192.98

D. The length of the common tangent can be found using the formula:

[tex]CT = (R_1 + R_2)* tan (\frac{B-A}{2})[/tex]

Plugging in the values, we get:

[tex]CT = (R_1 + R_2)* tan (\frac{(18\textdegree-12\textdegree)}{2})[/tex]

CT ≈ 193.43 feet

E. The shortest distance between the vertex and the PCC can be found using the formula:

d = R₁ sin A

Plugging in the values, we get:

d = R₁ sin 12°

d ≈ 371.59 feet

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A physicist would like to inspect the linac vault for voids, cracks, and defects. What detector should be used for inspection? Optically stimulated luminescence detector (OSLD) Geiger-Mueller counter Thermoluminescent dosimeter (TLD)
Ionization chamber

Answers

The best detector for inspecting a linac vault for voids, cracks, and defects would be an Optically Stimulated Luminescence Detector (OSLD).

This type of detector uses a light source to measure the intensity of light emitted from a material when exposed to a beam of gamma radiation. It is able to detect and measure small defects that may be missed by other types of detectors. Other types of detectors such as Geiger-Mueller counters, Thermoluminescent dosimeters (TLDs), and Ionization Chambers may also be used, but may not be as effective as an OSLD.

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technician a says that all of the brakes must be backed off using the slack adjusters before servicing a brake system. technician b says that spring brakes should be caged on all axles to place the park brakes in a released position when serviced. who is correct?

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Both Technician A and Technician B are correct as there statement "all of the brakes must be backed off using the slack adjusters before servicing a brake system" and "spring brakes should be caged on all axles to place the park brakes in a released position when serviced" are correct.

When parking or in an emergency situation when your service brakes fail, spring brakes are intended to function. The operation and purpose of the spring brake subsystem are described in this chapter.

If the service brake system fails, all vehicles equipped with air brakes must have a backup plan for stopping. Most automakers pair this emergency braking system with a parking-brake system that employs spring brakes.

Unlike service brakes, spring brakes are not air applied. When air pressure in the brake chamber decreases, they engage and when it increases, they disengage.

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technician a says that disc brakes are self-adjusting, and the brake pedal height should not become lower as the disc brake pads wear. technician b says that as the disc brake pads wear, the level of brake fluid in the master cylinder reservoir drops. which technician is correct?

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Both Technician are correct as the statement "disc brakes are self-adjusting and the brake pedal height should not become lower as the disc brake pads wear" and "the disc brake pads wear, the level of brake fluid in the master cylinder reservoir drops" are true.

In disc brakes, the brake pads attached to the brake callipers clamp on the rotating brake rotors to stop or slow down the wheels. Friction is created by the brake pads pressing against the rotors, which turns kinetic energy into thermal energy.

Disc brakes are typically used in passenger cars, but they are gradually making their way into the commercial vehicle market where drum brakes were previously preferred for their longer lifespan due to their stable performance at higher speeds and resistance to brake fade. Akebono is committed to meeting the rising customer demand for higher quality products with a longer lifespan through continued improvement of the disc brake's dependability.

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what limitation of alternating treatment designs:
o it is susceptible to multiple treatment interference,
o rapid back-and-forth switching of treatments does not reflect the typical manner in which interventions are applied and may be viewed as artificial and undesirable.
o It is limited to maximum of four different treatment conditions

Answers

ATDs can be a useful tool for researchers but it is important to bear these limitations in mind

Alternating Treatment Designs (ATDs) have a few limitations which must be taken into consideration when designing a study. Firstly, it is susceptible to multiple treatment interference, which is when the effects of multiple treatments interact with each other. This can invalidate results or lead to incorrect conclusions. Secondly, rapid back-and-forth switching of treatments does not reflect the typical manner in which interventions are applied and may be viewed as artificial and undesirable. Finally, it is limited to a maximum of four different treatment conditions, meaning that complex interventions are difficult to evaluate.

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If a polymer has a bandgap energy of 1.8 eV, what color would its emission be?Answer Choices:A- OrangeB- BlueC- RedD- Green

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If a polymer has a bandgap energy of 1.8 eV, it will emit blue light. The answer to this question is B - Blue.

Bandgap energy is a term used in the field of solid-state physics and semiconductor technology. It refers to the energy difference between the highest occupied energy level (valence band) and the lowest unoccupied energy level (conduction band) in a semiconductor material. The emission color of a polymer or semiconductor material is determined by its bandgap energy. When an electron transitions from the conduction band to the valence band, it emits a photon of energy equivalent to the bandgap energy.

This photon's energy corresponds to the frequency and wavelength of the emitted light, determining its color. According to the spectrum of electromagnetic radiation, shorter wavelengths are associated with higher energies, and longer wavelengths are associated with lower energies. Polymers with a bandgap energy of 1.8 eV would emit blue light, as blue light has a wavelength of around 400-500 nm and an energy of approximately 2.44 eV.

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The acceleration of a particle traveling along a straight line is a=16s1/2m/s2, where s is in meters.If v = 0, s = 4 m when t = 0, determine the particle's velocity at s = 5 m.

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The required formula to calculate velocity of a particle is v² = u² + 2as,

where

v is the final velocity of the particle,u is the initial velocity of the particle,a is the acceleration of the particle and,s is the distance traveled by the particle

.Let's calculate the final velocity of the particle, given that a = 16s^1/2 m/s^2, s = 5 m and u = 0m/s.v² = u² + 2asv² = 0 + 2(16s^1/2)(5)v² = 160s^1/2v = (160s^1/2)^1/2v = 4(10s)^1/2 m/sTherefore, the final velocity of the particle is 4(10s)^1/2 m/s when the particle's position is at s = 5 m.

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it is important to identify specific coding statements that should execute in a particular sequence for achieving _____.

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It is important to identify specific coding statements that should execute in a particular sequence for achieving a specific output or result.

In programming, it is important to understand the sequence of execution in order to ensure that the program runs correctly and produces the desired result. Identifying specific coding statements and their sequence of execution can help to avoid bugs and errors in the program.

It can also help to improve the efficiency and performance of the program by ensuring that the code is executed in the most optimal way.

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T/F in a forecasting model using simple moving average, the shorter the time span used for calculating the moving average, the closer the average follows volatile trends.

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In a forecasting model using a simple moving average, the shorter the time span used for calculating the moving average, the closer the average follows volatile trends. The statement is True.

A simple moving average (SMA) is a technical analysis indicator that averages the price of a stock or commodity over a specified period of time. SMA is calculated by adding the closing price of the security for the specific period and dividing it by the total number of periods. Simple moving averages (SMA) are commonly utilized to create forecasts by analysts and technical traders.

A forecasting model using SMA examines the past performance of security to anticipate future prices. The simple moving average helps to forecast the probable trend direction and change points by examining trends over a specified period. The shorter the time period used in the SMA formula, the closer the average is too volatile trends. SMA is computed on a fixed basis and is more reactive to market trends when the time frame is short. In comparison, SMA is less sensitive to price changes when the time frame is long.

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What is the purpose of the PATH variable?a. Set the PATH variable and place it in the environment so it causes theshell to search the following directories in order:• /usr/local/bin• /usr/bin• /bin• /usr/kerberos/bin• The bin directory in your home directory• The working directoryb. If there is an executable file named doit in /usr/bin and another file withthe same name in your ~/bin directory, which one will be executed?c. If your PATH variable is not set to search the working directory, how canyou execute a program located there?d. Which command can you use to add the directory /usr/games to the endof the list of directories in PATH?

Answers

The PATH variable sets the directories the shell searches for executables, and you can add directories using "export PATH=$PATH:/usr/games".

The PATH variable is an environment variable in Unix-based operating systems that contains a colon-separated list of directories. Its purpose is to provide the shell with a search path for executable files so that they can be easily found and executed from the command line. By default, the PATH variable includes several directories, such as /usr/local/bin, /usr/bin, and /bin, among others.

If there is an executable file named doit in both /usr/bin and ~/bin directories, the one located in /usr/bin will be executed first because that directory comes first in the PATH variable.

If the PATH variable is not set to search the working directory, the program located there can be executed by specifying the full path to the executable file, such as "./program" where "./" indicates the current working directory.

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given the variable pricepercase, write an expression corresponding to the price of a dozen cases. 1 enter your code

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the expression corresponding to the price of a dozen cases, given the variable pricepercase, is `pricepercase * 12`.

To find the price of a dozen cases, we need to multiply the price per case by the number of cases in a dozen. A dozen is equal to 12, so the expression for the price of a dozen cases would be:

`pricepercase * 12`

This will give us the total price of a dozen cases. So, if the price per case is $5, the price of a dozen cases would be:

`5 * 12 = 60`

The price of a dozen cases would be $60.

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What is sequence to sequence in machine learning?

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Sequence-to-sequence (seq2seq) in machine learning refers to a type of model that processes sequences of variable length and produces output sequences of variable length.

It is a type of neural network that can handle tasks such as language translation, text summarization, and speech-to-text conversion. Seq2seq models consist of an encoder and a decoder. The encoder processes the input sequence and produces a fixed-length vector, which is a summary of the entire sequence. The decoder then takes this summary vector and generates the output sequence, one element at a time.

One of the most common applications of seq2seq models is a machine translation. In this case, the input sequence is a sentence in one language, and the output sequence is a sentence in another language. The encoder processes the input sentence and produces a summary vector that captures the meaning of the sentence. The decoder then takes this summary vector and generates the corresponding sentence in the target language. Overall, sequence-to-sequence models are a powerful tool in machine learning for handling sequence data of varying lengths and generating meaningful output sequences.

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Conduction heat transfer in the positive x-direction is (select all that are correct): A. Directly proportional to the thermal conductivity. B. Directly proportional to the thickness of the material. C. Directly proportional to the temperature difference, D. Inversely proportional to the area.

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The conduction heat transfer in the positive x-direction is directly proportional to the thermal conductivity and temperature difference.

Conduction heat transfer in the positive x-direction is directly proportional to the thermal conductivity, and temperature difference. So, options A and C are correct. Let's understand each option:

A. Directly proportional to the thermal conductivity: Conduction heat transfer is directly proportional to the thermal conductivity of the material. The greater the thermal conductivity, the higher the conduction heat transfer.B. Directly proportional to the thickness of the material: Conduction heat transfer is inversely proportional to the thickness of the material. This means that as the thickness of the material increases, the heat transfer decreases.C. Directly proportional to the temperature difference: Conduction heat transfer is directly proportional to the temperature difference between the two ends of the material. As the temperature difference increases, the heat transfer also increases.D. Inversely proportional to the area: Conduction heat transfer is inversely proportional to the area perpendicular to the heat flow direction. As the area increases, the heat transfer decreases.

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3.9 Do the following:
(a) Show that the discrete transformation function given in Eq. (3-15) for histogram equalization satisfies conditions (a) and (b) stated at the beginning of Section 3.3. (b) * Show that the inverse discrete transformation in Eq. (3-16) satisfies conditions (a) and (b) in Section 3.3 only if none of the intensity levels rk, kL =− 012 1 , , , , , … are missing in the original image.

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T(r) satisfies both conditions (a) and (b) in Section 3.3. and T⁻¹(s) satisfies condition (b) in Section 3.3 only if none of the intensity levels rk, k = 0, 1, 2, ..., L-1 are missing in the original image.

(a) The discrete transformation function for histogram equalization is given by:

s = T(r) = (L-1) ∑_{j=0}^{r} p_j

where L is the number of intensity levels in the image, r is an intensity level, and p_j is the normalized histogram value for intensity level j.

Condition (a) in Section 3.3 states that the transformation function must be monotonically increasing. To show that T(r) is monotonically increasing, we can take the derivative with respect to r:

d T(r)/d r = (L-1) d/d r ∑_{j=0}^{r} p_j

= (L-1) p_r

Since p_r is non-negative, the derivative is non-negative as well, which means T(r) is monotonically increasing.

Condition (b) in Section 3.3 states that the transformation function must map the smallest and largest intensity levels to 0 and L-1, respectively. To show that T(r) satisfies this condition, we can evaluate T(0) and T(L-1):

T(0) = (L-1) ∑_{j=0}⁰ p_j = 0

T(L-1) = (L-1) ∑_{j=0}⁽l⁻¹⁾ p_j = L-1

Therefore, T(r) satisfies both conditions (a) and (b) in Section 3.3.

(b) The inverse discrete transformation for histogram equalization is given by:

r = T⁻¹(s) = argmin_r |T(r) - s|

To show that T⁻¹(s) satisfies condition (a), we need to show that it is monotonically increasing. However, this is not necessarily true if some of the intensity levels rk, k = 0, 1, 2, ..., L-1 are missing in the original image. In this case, T(r) will have plateaus where the cumulative distribution function remains constant, resulting in multiple possible values of r for a given s. This violates the monotonicity condition since the inverse transformation function must have a unique inverse for every s. To show that T⁻¹(s) satisfies condition (b), we need to show that it maps 0 to the smallest intensity level and L-1 to the largest intensity level. This is true regardless of whether any intensity levels are missing in the original image, since the transformation function T(r) always maps 0 to the first intensity level and L-1 to the last intensity level. Therefore, T⁻¹(s) satisfies condition (b) in Section 3.3 only if none of the intensity levels rk, k = 0, 1, 2, ..., L-1 are missing in the original image.

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in expressions with different types of operators, determines the order of evaluation. assignment operator placement data types of operands short circuit precedence

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The order of evaluation in expressions with different types of operators is determined by operator precedence.

Operator precedence is a set of rules that dictate the order in which operations are performed in an expression. The operators with higher precedence are evaluated before those with lower precedence. For example, multiplication and division have higher precedence than addition and subtraction, so they are performed first in an expression. The order of evaluation can also be affected by parentheses, which have the highest precedence and can be used to override the default order of evaluation. Additionally, the short circuit operators (&& and ||) have special rules for evaluation, in which the second operand is only evaluated if necessary. The assignment operator (=) has the lowest precedence and is always performed last. The placement and data types of operands do not affect the order of evaluation.

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Find the MPOS for the given K-map

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(A' + B' + C') (A' + B' + C) (A + B + C') (A + B' + C) is the MPOS for the given K-Map.

What is the K-map formula?

The number of input variables determines how many cells there are in the K-map, which is formally represented as two to the power of the number of variables, or 2n, If there are n input variables in total. Hence, a K-map with 4 (= 22) cells is needed in order to simplify a logical statement with two inputs.

What does Mcq use K-map for?

The correct POS expression for creating a circuit to create the truth table can be created using a Karnaugh map.

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to construct an eight-inch-thick masonry wall, concrete block might be selected instead of brick because it is

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To construct an eight-inch-thick masonry wall, concrete block might be selected instead of brick because it is more economical.

Concrete blocks are typically larger than bricks and therefore require fewer blocks to construct a wall of the same size. This means that the cost of materials is lower and the construction process is faster. Additionally, concrete blocks are often stronger and more durable than bricks, making them a better choice for structural walls.

Therefore, the answer to this question in comaprison to brickis, concrete block is  more economical and stronger to be used.

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The financially important reaction to produce the valuable product B (not the real name) was carried out in Jesse Pinkman's garage. This breaking bad, fly-by-night company is on a shoestring budget and has very little money to purchase equipment. Fortunately, cousin Bemie has a reactor surplus company and get reactors for them. The reaction AB+C takes place in the liquid phase. Below is the Levenspiel plot for this reaction. You have up to $10,000 to use to purchase reactors from those given below. Reactor Type Number Volume (dm) Cost CSTR 2 2 $1.000 CSTR 4 $2,000 PFR $2.000 CSTR $4,000 CSTR 58.000 01 02 03 04 05 06 07 08 0.9 PER 2 12 56,000 What reactors do you choose, how do you arrange them, and what is the highest conversion you can get for S10,000? Approximately what is the corresponding highest conversion with your arrangement of reactors? Scheme and sketch your reactor volumes.

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The chosen reactors and their arrangement can achieve the highest possible conversion within the given budget of $10,000.

To achieve the highest conversion with a budget of $10,000, we need to choose the reactors with the lowest cost per volume and arrange them in a way that maximizes the conversion. From the given options, the CSTR reactors with a cost of $1,000 and $2,000 have the lowest cost per volume. We can purchase two of the $1,000 CSTR reactors and one of the $2,000 CSTR reactors for a total cost of $4,000. We can then use the remaining $6,000 to purchase three of the $2,000 PFR reactors.

The arrangement of the reactors should be as follows:
- The two $1,000 CSTR reactors should be placed in series to achieve a higher conversion.
- The $2,000 CSTR reactor should be placed in series with the two $1,000 CSTR reactors to further increase the conversion.
- The three $2,000 PFR reactors should be placed in series with the CSTR reactors to achieve the highest possible conversion.

The highest conversion that can be achieved with this arrangement of reactors is approximately 0.8, as shown in the Levenspiel plot. The corresponding highest conversion with this arrangement of reactors is approximately 0.8.

The reactor volumes can be sketched as follows:
CSTR (2 dm) -> CSTR (2 dm) -> CSTR (4 dm) -> PFR (2 dm) -> PFR (2 dm) -> PFR (2 dm)

Overall, the chosen reactors and their arrangement can achieve the highest possible conversion within the given budget of $10,000.

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