Answer:
The sampling distribution of the sample mean is approximately normal with mean 72 and standard deviation 1.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Normally distributed with mean 72 and standard deviation 6.
This means that [tex]\mu = 72, \sigma = 6[/tex]
A random sample of size 36
This means that [tex]n = 36, s = \frac{6}{\sqrt{36}} = 1[/tex]
The sampling distribution of the sample mean is
By the Central Limit Theorem, it is approximately normal with mean 72 and standard deviation 1.
Solve this equation log3X + log3(x-6) = log3 7
Hello!
log₃(x) + log₃(x - 6) = log₃(7) <=>
<=> log₃(x * (x - 6)) = log₃(7) <=>
<=> log₃(x² - 6x) = log₃(7) <=>
<=> x² - 6x = 7 <=>
<=> x² - 6x - 7 = 0 <=>
<=> x² + x - 7x - 7 = 0 <=>
<=> x * (x + 1) - 7 * (x + 1) = 0 <=>
<=> (x + 1) * (x - 7) = 0 <=>
<=> x + 1 = 0 and x - 7 = 0 <=>
<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>
<=> x = 7
Good luck! :)
The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.
Answer:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 5x + 1[/tex]
Required
Complete the table (see attachment)
When x = -5
[tex]f(-5) = 5 * -5 + 1 = -24[/tex]
When x = -1
[tex]f(-1) = 5 * -1 + 1 = -4[/tex]
When x = 2
[tex]f(2) = 5 * 2 + 1 = 11[/tex]
When x = 3
[tex]f(3) = 5 * 3 + 1 = 16[/tex]
When x = 4
[tex]f(4) = 5 * 4 + 1 = 21[/tex]
So, the table is:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Which operation will solve the following word problem? Jaylene bought a blouse for $20.00. The next day she returned the blouse and got 90% of her money back, she was charged a restocking fee of 10%. How much money did she get back?
Division
Addition
Subtraction
Multiplication
Answer:
division is right i hope you understand
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Answer:
Multiplication
Step-by-step explanation:
The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.
Jaylene got back ...
90% × $20 = $18
whitch numbre produces a rational number when multiplied by 1/3 ?
Answer:
Step-by-step explanation:
multiplication of two rational numbers produce a rational number.
Please help Ladder question!!
A 6 ft ladder, resting against a wall, begins to slip down the wall. When the angle of the ladder is 45 degrees, the bottom of the ladder is moving away from the wall at 0.5 m/s. At that moment, how fast is the top of ladder moving down the wall?
Answer:
Step-by-step explanation:
This is a related rates problem from calculus using implicit differentiation. The main equation is going to be Pythagorean's Theorem and then the derivative of that. Pythagorean's Theorem is
[tex]x^2+y^2=c^2[/tex] where c is the hypotenuse and is a constant. Therefore, the derivative of this with respect to time, and using implicit differentiation is
[tex]2x\frac{dx}{dt}+2y\frac{dy}{dt}=0[/tex] and dividing everything by 2 to simplify a bit:
[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex]. Upon analyzing that equation, it looks like we need values for x, y, [tex]\frac{dx}{dt}[/tex], and [tex]\frac{dy}{dt}[/tex]. And here's what we were given:
[tex]\theta=45[/tex] and [tex]\frac{dx}{dt}=.5[/tex] In the greater realm of things, that's nothing at all.
BUT we can use the right triangle and the angle we were given to find both x and y. The problem we are looking to solve is to
Find [tex]\frac{dy}{dt}[/tex] at the instant that [tex]\frac{dx}{dt}[/tex] = .5.
Solving for x and y:
[tex]tan45=\frac{x}{6}[/tex] and
6tan45 = x ( and since this is a 45-45-90 triangle, y = x):
[tex]6(\frac{\sqrt{2} }{2})=x=y[/tex] so
[tex]x=y=3\sqrt{2}[/tex] and now we can fill in our derivative. Remember the derivative was found to be
[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex] so
[tex]3\sqrt{2}(\frac{1}{2})+3\sqrt{2}\frac{dy}{dt}=0[/tex] and
[tex]\frac{3\sqrt{2} }{2}+3\sqrt{2} \frac{dy}{dt}=0[/tex] and
[tex]3\sqrt{2}\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}[/tex] and multiplying by the reciprocal of the left gives us:
[tex]\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}(\frac{1}{3\sqrt{2} })[/tex] so
[tex]\frac{dy}{dt}=-\frac{1}{2}\frac{m}{s}[/tex]
how many integers from 1 through a
Answer:
sorry but I don't understand
Step-by-step explanation:
please forgive me
comment if I am forgiven
What is the correct line graph for y=3x+5?
Answer:
The equation y=−3x+5 is in slope intercept form, and represents a straight line in which -3 is the slope, and 5 is the y -intercept.
The number 55 is attached to a two-digit number to its left and the formed 4-digit number is divisible by 24. What could be the 2-digit number? List all options.
Given:
The number 55 is attached to a two-digit number to its left and the formed 4-digit number is divisible by 24.
To find:
The 2-digit numbers.
Solution:
Let the two digit number be [tex]ab[/tex]. Then the 4 digit number will be [tex]55ab[/tex].
We know that the number [tex]55ab[/tex] lies in the range 5500 to 5599.
Now,
[tex]5500=229\times 24+4[/tex]
It means, [tex]5500-4=5496[/tex] is divisible by 24. So, the numbers lie in the range 5500 to 5599 and divisible by 24 are:
[tex]5496+24=5520[/tex]
[tex]5520+24=5544[/tex]
[tex]5544+24=5568[/tex]
[tex]5568+24=5592[/tex]
Therefore, the possible 2-digit numbers are 20, 44, 68, 92.
Help please and thanks !!
Answer:
4th option
Step-by-step explanation:
tanZ = [tex]\frac{opposite}{adjacent }[/tex] = [tex]\frac{XY}{ZY}[/tex]
Find the distance from the vertices of AABC to the corresponding vertices of the other three triangles, and enter them in the table. For AJKL-
you'll need to use the distance formula da (01 – 12) + (y1 - y2) . Verify your calculations using the tools available in GeoGebra.
Answer:
See explanation
Step-by-step explanation:
The question is incomplete, as the vertices of the triangle are not given.
A general explanation is as follows;
To calculate distance between two points, we use:
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]
Take for instance;
[tex]A = (1,4)[/tex]
[tex]B = (3,-2)[/tex]
Distance AB is:
[tex]AB = \sqrt{(1 - 3)^2 + (4 - -2)^2}[/tex]
[tex]AB = \sqrt{(- 2)^2 + (4 +2)^2}[/tex]
[tex]AB = \sqrt{(- 2)^2 + (6)^2}[/tex]
Evaluate the exponents
[tex]AB = \sqrt{4 + 36}[/tex]
[tex]AB = \sqrt{40}[/tex]
[tex]AB = 6.32[/tex]
Answer:
for edmentum
Step-by-step explanation:
A professor is interested in whether or not college students have a preference (indicated by a satisfaction score) for reading a textbook that has a layout of one column or layout of two columns. In the above experiment, what is the dependent variable
Answer:
Satisfaction score
Step-by-step explanation:
The dependent variable may be described as the variable which is being measured in a research experiment. In the scenario described above, the dependent variable is the satisfaction score which is used to measure preference for a one or two column textbook. The dependent variable can also seen as the variable which we would like to predict, also called the predicted variable . The predicted variable here is the satisfaction score.
Given: CD is an altitude of triangle ABC.
Prove: a^2 = b^2 +c^2 = 2bccos A
Answer:
Step-by-step explanation:
Statements Reasons
1). CD is an altitude of ΔABC 1). Given
2). ΔACD and ΔBCD are right 2). Definition of right triangles.
triangles.
3). a² = (c - x)² + h² 3). Pythagoras theorem
4). a² = c² + x² - 2cx + h² 4). Square the binomial.
5). b² = x² + h² 5). Pythagoras theorem.
6). cos(x) = [tex]\frac{x}{a}[/tex] 6). definition of cosine ratio for an angle
7). bcos(A) = x 7). Multiplication property of equality.
8). a² = c² - 2c(bcosA) + b² 8). Substitution property
9). a² = b² + c² - 2bc(cosA) 9). Commutative properties of
addition and multiplication.
X^2-y^2=k need the answer
Answer:
Let's solve for k.
x2−y2=k
Step 1: Flip the equation.
k=x2−y2
Answer:
k=x2−y2
Step-by-step explanation:
what tearm means per hundred
a.base b.percent c.percentage d.rate
the term per hundred means percent
hope it helps
Answer:
C. Percent
Explanation:
per hundred means 1 in 100. percent is referring to the unit that is 1 in 100 of another value
1ex. 1% of 100 (1 percent of 100)
2ex. 49% of 235 (49 percent of 235)
The center of the circle is located (3'8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle
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Answer:
x² +y² -6x -16y +48 = 0
Step-by-step explanation:
Given:
circle center: (3, 8)circle radius: 5Find:
general form equation for the circle
Solution;
The standard form equation for the circle is ...
(x -h)² +(y -k)² = r² . . . . . circle with radius r centered at (h, k)
(x -3)² +(y -8)² = 5²
Subtracting 25 and expanding this will give the general form.
x² -6x +9 +y² -16y +64 -25 = 0
x² +y² -6x -16y +48 = 0
_____
Additional comment
"General form" of an equation is usually the form f(x,y) = 0, where f(x, y) is written in "standard form," with terms in lexicographical order and decreasing degree.
Matthew participates in a study that is looking at how confident students at SUNY Albany are. The mean score on the scale is 50. The distribution has a standard deviation of 10 and is normally distributed. Matthew scores a 65. What percentage of people could be expected to score the same as Matthew or higher on this scale?
a) 93.32%
b) 6.68%
c) 0.07%
d) 43.32%
Answer:
b) 6.68%
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The mean score on the scale is 50. The distribution has a standard deviation of 10.
This means that [tex]\mu = 50, \sigma = 10[/tex]
Matthew scores a 65. What percentage of people could be expected to score the same as Matthew or higher on this scale?
The proportion is 1 subtracted by the p-value of Z when X = 65. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{65 - 50}{10}[/tex]
[tex]Z = 1.5[/tex]
[tex]Z = 1.5[/tex] has a p-value of 0.9332.
1 - 0.9332 = 0.0668
0.0668*100% = 6.68%
So the correct answer is given by option b.
What are the coordinates of vertex F" of ΔF"G"H"?
Which choice is equivalent to √3 *√8*√5
A. 2√30
B. 4√30
C. 10√12
D. 24√5
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { A. \:2 \sqrt{30} }}}}}}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}[/tex]
[tex] = \sqrt{3} \times \sqrt{8} \times \sqrt{5} [/tex]
[tex] = \sqrt{3 \times 2 \times 2 \times 2 \times 5} [/tex]
[tex] = \sqrt{ ({2})^{2} \times 2 \times 3 \times 5} [/tex]
[tex] = 2 \sqrt{2 \times 3\times 5} [/tex]
[tex] = 2 \sqrt{30} [/tex]
Note:[tex] \sqrt{ ({a})^{2} } = a[/tex]
[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]
Answer:
A. 2√30
Step-by-step explanation:
[tex] \small \sf \: \sqrt{3} \times \sqrt{8} \times \sqrt{5} \\ [/tex]
split √8
[tex] \small \sf \leadsto \sqrt{3 × 2 × 2 × 2 × 5} [/tex]
[tex] \small \sf \leadsto \: 2 \sqrt{2 \times 3 \times 5} [/tex]
[tex] \small \sf \leadsto \: 2 \sqrt{30} [/tex]
calculate and find the area of the figure below 10m 8m 8m 2m 2m 2m 2m 2m
Answer:
can you be more specific?
Step-by-step explanation:
someone pls help me!!
Answer:
170
Step-by-step explanation:
rititifigkgkrkfjdjfjtjgjgg
Find the 11th term of the sequence
3, -6, 12, -24,...
3072
6144
-6144
-3072
Answer:
-3072
Step-by-step explanation:
A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. A recent sample of 1,000 adults showed 410 indicating that their financial security was more than fair. Suppose that just a year before, a sample of 1,200 adults showed 420 indicating that their financial security was more than fair.
Required:
a. State the hypotheses that can be used to test for a significant difference between the population proportions for the two years.
b. Conduct the hypothesis test and compute the p-value. At a 0.05 level of significance, what is your conclusion?
c. What is the 95% confidence interval estimate of the difference between the two population proportions?
d. What is your conclusion?
Answer:
b) Then z(s) is in the rejection region for H₀. We reject H₀. The p-value is smaller than α/2
c)CI 95 % = ( 0.00002 ; 0.09998)
Step-by-step explanation: In both cases, the size of the samples are big enough to make use of the approximation of normality of the difference of the proportions.
Recent Sample
Sample size n₁ = 1000
Number of events of people with financial fitness more than fair
x₁ = 410
p₁ = 410/ 1000 = 0.4 then q₁ = 1 - p₁ q₁ = 1 - 0.4 q₁ = 0.6
Sample a year ago
Sample size n₂ = 1200
Number of events of people with financial fitness more than fair
x₂ = 420
p₂ = 420/1200 p₂ = 0.35 q₂ = 1 - p₂ q₂ = 1 - 0.35 q₂ = 0.65
Test Hypothesis
Null Hypothesis H₀ p₁ = p₂
Alternative Hypothesis Hₐ p₁ ≠ p₂
CI 95 % then significance level α = 5% α = 0.05 α/2 = 0.025
To calculate p-value:
SE = √ (p₁*q₁)/n₁ + (p₂*q₂)/n₂
SE = √ 0.4*0.6/1000 + 0.65*0.35/1200
SE = √ 0.00024 + 0.000189
SE = 0.021
z(s) = ( p₁ - p₂ ) / SE
z(s) = ( 0.4 - 0.35 )/0.021
z(s) = 0.05/ 0.021
z(s) = 2.38
We find p-value from z-table to be p-value = 0.00842
Comparing
p-value with α/2 = 0.025
α/2 > p-value
Then z(s) is in the rejection region for H₀. We reject H₀
CI 95 % = ( p₁ - p₂ ) ± 2.38*SE
CI 95 % = ( 0.05 ± 2.38*0.021 )
CI 95 % = ( 0.05 ± 0.04998)
CI 95 % = ( 0.00002 ; 0.09998)
CI 95 % does not contain the 0 value affirming what the hypothesis Test already demonstrate
For the diagram below, which equation is the correct use of the distance
formula?
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Answer:
D
Step-by-step explanation:
Any equation that does not have y2 as the first term in the second set of parentheses will be incorrect.
The correct usage is shown in equation D.
Find the slope of the line that passes through the two points 2,-4 & 4,-1
Answer:
Step-by-step explanation:
I have this saved on my computer in notepad b/c this type of question get asked sooo often :/
point P1 (-4,-2) in the form (x1,y1)
point P2(3,1) in the form (x2,y2)
slope = m
m = (y2-y1) / (x2-x1)
My suggestion is copy that above and save it on your computer for questions like this
now use it
Point 1 , P1 = (2,-4) in the form (x1,y1)
Point 2 , P2 = (4,-1) in the form (x2,y2)
m = [ -1-(-4) ] / [ 4-2]
m = (-1+4) / 2
m = 3 / 2
so now we know the slope is 3/2 :)
To teach computer programming to employees, many firms use on the job training. A human resources administrator wishes to review the performance of trainees on the final test of the training. The mean of the test scores is 72 with a standard deviation of 5. The distribution of test scores is approximately normal. Find the z-score for a trainee, given a score of 82.
Answer:
The z-score for the trainee is of 2.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The mean of the test scores is 72 with a standard deviation of 5.
This means that [tex]\mu = 72, \sigma = 5[/tex]
Find the z-score for a trainee, given a score of 82.
This is Z when X = 82. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{82 - 72}{5}[/tex]
[tex]Z = 2[/tex]
The z-score for the trainee is of 2.
I need help with three
Answer:
A and F
Step-by-step explanation:
A and F both represent instances of division of 14/5
B represent multiplication
C represent the reciprocal of the problem, 5/14
D represent addition
Need help on this problem
Answer:
Step-by-step explanation:
[tex]2(x-2)^2=8(7+y)\\2(x-2)^2=56+8y \Rightarrow y={1\over{8}}[2(x-2)^2-56]={1\over{4}}(x-2)^2-7\\finally\\y={1\over{4}}(x-2)^2-7\\let ~change~x~and~y\\x={1\over{4}}(y-2)^2-7\\x+7={1\over{4}}(y-2)^2\\4(x+7)=(y-2)^2\\y-2=\pm\sqrt{4(x+7)}\\\\y=2\pm\sqrt{4x+28}[/tex]
A 27% solution ( 27mg per 100 mL of solution) is given intravenously. Suppose a total of 1,36 L of the solution is given over a 10 -hour period. Complete parts (a) through (c) below.
a. What is the flow rate in units of mL/hr?
nothing mL/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)
What is the flow rate in per hour?
nothing mg/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)
b. If each mL contains 13 drops (the drop factor is expressed as gtt/mL), what is the flow rate in units of 13gtt/hr?
nothing gtt/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)
c. During the 10 -hour period, how much is delivered?
nothing mg (Type an integer or decimal rounded to the nearest thousandth as needed.)
Answer:
Step-by-step explanation:
a.
(1.36 L)/(10 hr) = (0.136 L)/(hr)
Flow rate = (0.136 L)/(hr) × (1000 mL)/L = (136 mL)/(hr)
136 mL × (27 mg)/(100 mL) = 36.72 mg
Delivery rate = (36.72 mg)/(hr)
b.
(136 mL)/(hr) × (13 gtt)/(mL) = (1868 gtt)/(hr)
c.
10 hr × (36.72 mg)/)hr) = 367.2 mg
Find the value of x in the kite below.
60°
O
x = [?]
Answer:
30
Step-by-step explanation:
The given is right triangle with angle measure 90-60 and 30 degrees as we can see on the image.
I need help please and thank you.
Answer:
option a.
[tex] + - \frac{13}{5} [/tex]
Step-by-step explanation:
[tex]25x^2\: - \:169 = 0 [/tex]
[tex]25x^2 = 169[/tex]
[tex] {x}^{2} = \frac{169}{25} [/tex]
[tex]x = + - \sqrt{ \frac{169}{25} } [/tex]
[tex]x = + - \frac{13}{5} [/tex]
