A rectangular circuit of wire in free space connects the points A(0,1,1), B(0,3,1), C(0,3,4)
and D(0,1,4) to A. The wire carries a current of 6 mA flowing in the direction from B to C.
A 15 A filamentary current flows along the z-axis in the -direction. a) find the
force on side BC. b) Find the force on side AB. c) Find the total force in the loop.

Answers

Answer 1

a) The force on side BC is zero.

b) The force on side AB is zero.

c) The total force in the loop is zero.

To calculate the magnetic force on each side of the rectangular circuit, we can use the formula:

F = I * L * B * sin(θ)

Where:

F is the force on the wire,

I is the current flowing through the wire,

L is the length of the wire,

B is the magnetic field,

and θ is the angle between the wire and the magnetic field.

Let's calculate the forces on each side of the rectangular circuit:

a) Force on side BC:

The length of side BC is given by the distance between points B and C:

[tex]L_{BC} = |C - B|[/tex]

[tex]= \sqrt{((3 - 3)^2 + (4 - 1)^2)[/tex]

[tex]= \sqrt{(3^2 + 3^2)[/tex]

[tex]= \sqrt{(18)[/tex]

[tex]= 3\sqrt{2} units[/tex]

The magnetic field experienced by side BC is due to the filamentary current along the z-axis. For a current I_z = 15 A, the magnetic field at a point (x, y, z) due to a filamentary current along the z-axis is given by:

[tex]B_z = (u_0 * I_z) / (2\pi * r)[/tex]

Where μ₀ is the permeability of free space and r is the distance from the filamentary current.

Since side BC is parallel to the y-axis, the distance r is the difference in y-coordinates between side BC and the filamentary current:

r = 3 - 1 = 2 units

Plugging in the values, we have:

[tex]B_z = (4\pi * 10^{(-7)} T*m/A * 15 A) / (2\pi * 2)[/tex]

[tex]= (6 * 10^{(-3)} A) * (3\sqrt{2 units}) * (2 * 10^{(-6)} T) * (0)[/tex]

= 0 N

The angle θ between side BC and the magnetic field B_z is 0 degrees because they are parallel. Therefore, sin(θ) = sin(0) = 0.

Using the formula for the force, we have:

[tex]F_{BC} = I_{BC} * L_{BC} * B_z * sin(θ)[/tex]

[tex]= (6 * 10^{(-3)} A) * (3\sqrt{2} units) * (2 * 10^{(-6)} T) * (0)[/tex]

= 0 N

b) Force on side AB:

The length of side AB is given by the distance between points A and B:

[tex]L_{AB} = |B - A|[/tex]

[tex]= \sqrt{((3 - 1)^2 + (1 - 1)^2)[/tex]

[tex]= \sqrt{(2^2 + 0^2)[/tex]

= 2 units

The magnetic field experienced by side AB is also due to the filamentary current along the z-axis. Using the same value for B_z as calculated above, the angle θ between side AB and the magnetic field B_z is 0 degrees because they are parallel.

Therefore, sin(θ) = sin(0) = 0.

Using the formula for the force, we have:

[tex]F_{AB} = I_{AB} * L_{AB} * B_z * sin(\theta)[/tex]

[tex]= (6 * 10^{(-3)} A) * (2 units) * (2 * 10^{(-6)} T) * (0)[/tex]

= 0 N

c) Total force in the loop:

Since the forces on sides BC and AB are zero, the total force in the loop is the sum of the forces on the remaining sides.

The forces on sides CD and DA will have equal magnitude and opposite directions, canceling each other out.

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The complete question is:

A rectangular circuit of wire in free space connects the points A(0,1,1), B(0,3,1), C(0,3,4) and D(0,1,4) to A. The wire carries a current of 6 mA flowing in the direction from B to C. A 15 A filamentary current flows along the z-axis in the -direction.

a) Find the force on side BC.

b) Find the force on side AB.

c) Find the total force in the loop.


Related Questions

Graded problem 2 (10 pt) Cold air is dry because the saturation water vapor pressure of air decreases rapidly as temperature decreases. It is harmful to introduce dry, cold air directly into lungs. To prevent it, the respiratory system in our body warms up the inhaled air to body temperature and moisturizes it to 100% relative humidity before it reaches lungs. Some of the water and heat in our body are "consumed" during this process. Thus, the exposure to cold air for a prolonged period will put a lot of stress on our body. In this problem, we will see how much water and heat are taken from a human body in a single inhalation of dry, cold air. In a particular cold morning, air temperature is at 0∘C(32∘F), and the absolute humidity of the air is 3.4 g/kg. A person inhales 0.65 L of this cold air, which weighs 0.74 g. The atmospheric pressure is 101.3kPa, and the molar mass of water is 18 g/mol (a) What is the mass of water vapor in the 0.65 L of the cold air? (2pt) As the inhaled air goes through the airways, its temperature increases to 37∘C of the body temperature. (b) Using c=1.0 J/(g∘C) for the heat capacity of the inhaled air, calculate how much heat transfers from the body to the inspired air when its temperature rises from 0∘C to 37∘C. (2pt) As the temperature of the inhaled air increases, its volume increases as well, while the pressure remains the same as the atmospheric pressure. (c) According to Charles' law, what volume does the inhaled air increase to at 37∘C ?

Answers

(a) The mass of water vapor in the 0.65 L of the cold air can be determined as follows:We know that the absolute humidity of air (Ah) is the mass of water vapor (mw) in grams per kg of dry air (ma).So, Ah = mw/maSubstituting the values:3.4 = mw/1000gmw = 3.4×0.74=2.516 g

Therefore, the mass of water vapor in the 0.65 L of the cold air is 2.516 g.(b) The amount of heat transferred from the body to the inspired air when its temperature rises from 0 ∘C to 37 ∘C can be determined as follows:We know that,Q = mcdTwhereQ = amount of heat transferredm = mass of the air breathed in (taken as 0.74 g) c = specific heat capacity of the air taken as 1.0 J/(g°C)dT = change in temperature = 37 - 0 = 37°C

Substituting the given values,Q = (0.74 g) (1.0 J/g°C) (37°C) = 27.38 JTherefore, the amount of heat transferred from the body to the inspired air when its temperature rises from 0 ∘C to 37 ∘C is 27.38 J.(c) According to Charles' law, the volume that the inhaled air increases to at 37 ∘C is given by,V/T = constantwhere V is the volume, and T is the absolute temperature.Substituting the given values, we have;V/273 = 0.65/1000 => V = (0.65/1000)×273×(310/273) = 0.77LTherefore, the volume that the inhaled air increases to at 37 ∘C is 0.77 L.

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A 7 HP, 97% efficient, three-phase synchronous motor is connected to a 208 V, 60 Hz power supply. At rated conditions, the motor runs at 1800 rpm and presents a 0.97 lagging power factor to the power supply. The per-phase armature reactance is 95%. Armature resistance is negligible, as are all other sources of power loss. Under rated conditions: a. Calculate Vų, Eand Ia. b. Draw a single-phase equivalent circuit that shows V., Ea, Xs, and IA ) C. Draw a phasor diagram showing Bnet, B., B., IA, O and 8

Answers

(a) Rated power (output) of motor = 7 HP x 0.746 kW/HP = 5.22 kWEfficiency = 97%So input power = Output power / Efficiency = 5.22 / 0.97 = 5.38 kW Three-phase power supplied to the motor = 5.38 kVA (kilo Volt-Amps)So, per-phase power supplied to the motor = 5.38 / 3

= 1.79 kVA

= 1790 VA

For a 97% efficient motor, per-phase losses

= 0.03 x 1.79 kVA

= 53.7 W

So, per-phase input power to the motor = 1.79 kVA + 53.7 W

= 1.843 kVA

= 1843 VA

Reactance per phase = 95%So reactance per phase = Xs = 0.95 * 1.843 kVA / (1800 rpm / 60) = 5.85 Ω

So, per-phase current

= Ia

= 1790 / 208 / √3

= 5.83 AAC

voltage per phase

Vų = 208 / √3

= 120.27 V

For synchronous motor, Eb = VųSo,

per-phase voltage = Ea

= Eb

= Vų

= 120.27 V

Power factor = 0.97 laggingSo, cos Φ = 0.97, cos Φ = P / SWhere P is the active power (watts), and S is the apparent power (VA).So,

active power = P

= 1.79 * 0.97

= 1.735 kW

Apparent power = S

= Vų × Ia

= 120.27 × 5.83

= 700.63 VA

Reactive power = Q

= √(S² - P²)

= √(700.63² - 1735²)

= 686.7 VAR

(b)For single-phase equivalent circuit of the three-phase synchronous motor, 3 times the impedance is taken for the per-phase impedance of the motor.Single-phase equivalent circuit is shown in the image below:Therefore, per-phase impedance Z = j Xs = j 5.85 Ω

(c)Phasor diagram is shown in the image below:Therefore,

B = Vų

= 120.27 V, ∠ 0°.

Bnet = Bcos Φ + jBsin Φ

= 120.27 × 0.97 + j 120.27 sin cos⁡(- 24.01⁰)

= 116.67 - j 49.98 V.Ia

= 5.83 A, ∠ - 24.01°Ea

= Bnet + jIaZ

= (116.67 - j 49.98) + j (5.83)(5.85)

= 116.67 + j 32.13 V(O)

Phasor angle is the reference for the phase angles of the other phasors. So, ∠ O = 0°.S = |B| |Ia| = 120.27 x 5.83 = 700.63 VA

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If a measurement can be explained by more than one theory, then the measurement is not useful for distinguishing between the two theories
True False

Answers

True. If a measurement can be explained by more than one theory, then the measurement is not useful for distinguishing between the two theories. In this scenario, a measurement is not helpful in distinguishing between two hypotheses since either one may explain the data accurately.

To differentiate between hypotheses, a measurement must be able to establish one or the other.To put it another way, a measurement's inability to distinguish between hypotheses is proof that it is a weak method of testing hypotheses. As a result, the inability to differentiate between two hypotheses undermines a measurement's capacity to evaluate competing hypotheses.

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DIRECTION. Analyze the problem / case and follow what to do. Write your answer on a clean paper with your written name and student number. Scan and upload in MOODLE as ONE pdf document before the closing time. Q1. An event has spacetime coordinates (x,t)=1,300 m,3.0 s in reference frame S. What are the spacetime that moves in the negative x - direction at 0.03c ? (1) Spacetime coordinates (Point System; 4 marks) (2) Use Lorentz transformation equation to answer the question (Rubric 4 marks)

Answers

The spacetime coordinates of an event moving in the negative x-direction at 0.03c relative to reference frame S are (x', t') = (0.996, 3.0) meters and seconds, respectively.

In this problem, we are given an event with spacetime coordinates (x, t) = (1,300 m, 3.0 s) in reference frame S. We need to determine the spacetime coordinates (x', t') of the event when it moves in the negative x-direction at 0.03c.

To solve this problem, we can use the Lorentz transformation equation, which relates the spacetime coordinates in one reference frame to another. The equation is:

[tex]x' = γ(x - vt)t' = γ(t - vx/c^2)[/tex]

Where:

x' and t' are the spacetime coordinates in the moving reference frame.

x and t are the spacetime coordinates in the stationary reference frame.

v is the relative velocity between the two reference frames.

c is the speed of light in a vacuum.

γ is the Lorentz factor, given by γ = 1 / sqrt(1 - (v^2 / c^2)).

In this case, the event is moving in the negative x-direction, so the velocity v is -0.03c. Plugging the values into the Lorentz transformation equations, we get:

[tex]x' = γ(x - vt) = γ(1,300 - (-0.03c)(3.0))t' = γ(t - vx/c^2) = γ(3.0 - (-0.03c)(1,300)/c^2)[/tex]

Simplifying the equations, we find:

x' = 0.996 meters

t' = 3.0 seconds

Therefore, the spacetime coordinates of the event moving in the negative x-direction at 0.03c are (x', t') = (0.996, 3.0) meters and seconds, respectively.

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A mass m, attached to the end of a spring of spring constant k, is released from rest at t=0
from an extended position xmax. After a time t1 has elapsed (before the spring has returned to its
equilibrium position) the speed of the mass is measured to be v1. The position xmax equals (sqrt(m/k))*v1)/sin(sqrt(k/m))*t1)). what is the total energh of the system?

Answers

The total energy of the system is m * v1² * (1/2 + 1/2sin²(sqrt(k/m) * t1)).

To calculate the total energy of the system, we need to consider both the potential energy stored in the spring and the kinetic energy of the mass.

The potential energy of a spring is given by the equation:

PE = (1/2) * k * x²

Where:

PE is the potential energy,

k is the spring constant,

x is the displacement from the equilibrium position.

In this case, the displacement from the equilibrium position is xmax.

The kinetic energy of an object is given by the equation:

KE = (1/2) * m * v²

Where:

KE is the kinetic energy,

m is the mass of the object,

v is the velocity of the object.

In this case, the mass is m, and the velocity is v1.

Now, let's calculate the potential energy and the kinetic energy:

Potential energy (PE) = (1/2) * k * xmax²

Kinetic energy (KE) = (1/2) * m * v1²

Total energy (E) = PE + KE

= (1/2) * k * xmax² + (1/2) * m * v1²

Substituting the value of xmax from the given equation:

xmax = (sqrt(m/k) * v1) / sin(sqrt(k/m) * t1)

We have:

E = (1/2) * k * ((sqrt(m/k) * v1) / sin(sqrt(k/m) * t1))² + (1/2) * m * v1²

Simplifying further:

E = (1/2) * k * (m/k * v1²) / sin²(sqrt(k/m) * t1) + (1/2) * m * v1²

E = (1/2) * m * v1² / sin²(sqrt(k/m) * t1) + (1/2) * m * v1²

E = m * v1² * (1/2 + 1/2sin²(sqrt(k/m) * t1))

Therefore, the total energy of the system is m * v1² * (1/2 + 1/2sin²(sqrt(k/m) * t1)).

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what is the maximum power consumption of a 3.0- v portable cd player that draws a maximum of 300 ma of current?

Answers

Power consumption of a 3.0-V portable CD player that draws a maximum of 300 mA of current can be calculated using the formula:

P=V × I

Where,

P = Power in Watts

V = Voltage in Volts

I = Current in Amperes

Therefore, the maximum power consumption of a 3.0-V portable CD player that draws a maximum of 300 mA of current is:

P = 3.0 V × 0.3 AP

= 0.9 W

Therefore, the maximum power consumption of a 3.0-V portable CD player that draws a maximum of 300 mA of current is 0.9 W.

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Let S be the spin operator of a spin 1 particle. (a) Show that [S², S3] = 0. What is the physical significance of this result? (b) Denote the simultaneous eigenstates of S^2 and S3 by 1 m). Write down the matrix representation of the operator S₂ using the states |1 m) as the orthonormal basis. (c) Solve the eigenvalue problem S₂|xλ) = λh|xλ), and express the states |xλ) in terms of the basis states [1 m). (Make sure that the states |xλ) are properly normalised).

Answers

The commutation relation [S², S₃] = 0 indicates that the square of the spin and the z-component of the spin can be measured simultaneously without uncertainty. The matrix representation of the operator S₂ in terms of the basis states |1 m) can be constructed by applying the operator to the basis states. Solving the eigenvalue problem for S₂ yields the eigenvalues -1, 0, 1, and the corresponding eigenstates |xλ) can be expressed in terms of the basis states |1 m).

(a) To show that [S², S₃] = 0, we start by expressing the spin operators in terms of the ladder operators. The spin squared operator is given by S² = S₁² + S₂² + S₃², and the z-component of the spin operator is S₃. Now, we calculate the commutator:

[S², S₃] = [S₁² + S₂² + S₃², S₃]

         = [S₁², S₃] + [S₂², S₃] + [S₃², S₃]

         = 0 + 0 + 0

         = 0.

This result shows that the operators S² and S₃ commute, meaning they have a common set of eigenstates.

The physical significance of this result is that it allows us to simultaneously determine the values of the spin squared and the z-component of the spin for a spin 1 particle. Since these operators commute, there exists a set of simultaneous eigenstates |1 m) that diagonalize both operators. This implies that we can precisely measure the square of the spin and the z-component of the spin of a spin 1 particle simultaneously, without any uncertainty arising from the measurement process.

(b) To write down the matrix representation of the operator S₂ using the states |1 m) as the orthonormal basis, we apply the operator S₂ to the basis states:

S₂|1 m) = √(2/3) |1, m+1) + (-1/3) |1, m) + √(2/3) |1, m-1).

This equation represents the action of the S₂ operator on the basis states, where the coefficients determine the weights of the resulting states. By calculating the matrix elements of S₂ in this basis, we can construct the matrix representation of the operator.

(c) To solve the eigenvalue problem S₂|xλ) = λh|xλ), we substitute the expression for S₂ from part (b):

√(2/3) |1, m+1) + (-1/3) |1, m) + √(2/3) |1, m-1) = λh|xλ).

Solving this equation yields the eigenvalues λ = -1, 0, 1, and the corresponding eigenstates |xλ) can be expressed in terms of the basis states |1 m) as:

|x-1) = (-1/√3) |1, -1),

|x0) = (√2/√3) |1, 0) - (1/√3) |1, 1) ,

|x1) = (1/√3) |1, 1).

It is important to ensure that the states |xλ) are properly normalized, which can be achieved by dividing each state by its norm.

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A wheel of radius R is rolling on a flat ground, with the centre of mass velocity v. At a given instant, P is the point on the circumference of the wheel, which is at a height R from the ground. What is the magnitude of the linear velocity of P at this instant? a. 0 b. 2v C. V d. e. V R √2v

Answers

The magnitude of the linear velocity of point P at the given instant is V R √2v.

The answer to this question is d. V R √2v. When a wheel of radius R is rolling on a flat ground, with the center of mass velocity v, the magnitude of the linear velocity of P at a given instant when P is the point on the circumference of the wheel, which is at a height R from the ground can be found using the following formula: VP = √(v² + R²ω²)whereVP = velocity of point P (linear)v = velocity of center of massω = angular velocityR = radius At the given instant, P is at a height R from the ground. Therefore, the velocity of point P, VP is equal to the product of the angular velocity and the radius of the wheel. Mathematically,VP = RωWe also know that the center of mass velocity v is equal to the product of the angular velocity and the radius of the wheel.

Mathematically,v = RωSo,ω = v/RSubstitute the value of ω in the equation VP = √(v² + R²ω²) to get the linear velocity of point PVP = √(v² + R²(v/R)²)VP = √(v² + v²)VP = √2v²VP = V R √2v

Therefore, the magnitude of the linear velocity of point P at the given instant is V R √2v.

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A 93.2 MHz carrier is frequency modulated by a 5-KHz sine wave. The resultant FM signal has a frequency deviation of 40 KHz.
(a) Find the carrier swing of the FM signal.
(b) Determine the highest and lowest frequencies attained by the modulated signal.
(c) What is the modulation index of the FM wave
(d) Calculate the percent modulation?
(e) Determine the bandwidth using Carson’s Rule

Answers

The carrier swing of the FM signal is 40 KHz. The highest frequency would be 93.2 MHz + 40 KHz, and the lowest frequency would be 93.2 MHz - 40 KHz. The modulation index of the FM wave is 5 KHz. The percent modulation is 4.29%. The bandwidth using Carson’s Rule is 90 KHz.

To solve the given problem related to frequency modulation (FM), we can use the following formulas and concepts:

(a) The carrier swing is equal to the frequency deviation, which is given as 40 KHz.

(b) The highest and lowest frequencies attained by the modulated signal can be calculated by adding and subtracting the frequency deviation from the carrier frequency, respectively. So, the highest frequency would be 93.2 MHz + 40 KHz, and the lowest frequency would be 93.2 MHz - 40 KHz.

(c) The modulation index (m) can be calculated using the formula: m = (frequency deviation / modulating frequency). In this case, the frequency deviation is given as 40 KHz, and the modulating frequency is given as 5 KHz.

(d) The percent modulation can be calculated using the formula:

Percent modulation = (Frequency deviation / Carrier frequency) * 100

Given:

Frequency deviation = 40 KHz = 40 × 10³ Hz

Carrier frequency = 93.2 MHz = 93.2 × 10⁶ Hz

Percent modulation = (40 × 10³ Hz / 93.2 × 10⁶ Hz) * 100

= (40 × 10³ Hz / 93.2 × 10⁶ Hz) * 100

= (40 / 93.2) * (10³ / 10⁶) * 100

= 0.42918454935 * 0.001 * 100

= 0.042918454935

Therefore, the result of the expression (40 × 10^3 Hz / 93.2 × 10^6 Hz) * 100 is approximately 0.042918454935, or 4.29%.

(e) Carson's Rule states that the bandwidth of an FM signal can be approximated by:

Bandwidth ≈ 2 * (Frequency deviation + Modulating frequency)

Given:

Frequency deviation = 40 KHz = 40 × 10³ Hz

Modulating frequency = 5 KHz = 5 × 10³ Hz

Bandwidth ≈ 2 * (40 × 10^3 Hz + 5 × 10³ Hz)

= 2 * (45 × 10³ Hz)

= 2 * 45 × 10³ Hz

= 90 × 10³ Hz

Therefore, the result of the expression Bandwidth ≈ 2 * (40 × 10³ Hz + 5 × 10³ Hz) is 90 × 10³ Hz, or 90 KHz.

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Illustrate the working of differential pressure transmitter with neat diagram.

Answers

A differential pressure transmitter measures the difference in pressure between two points in a fluid system. It consists of a diaphragm that deflects based on the pressure difference, and this deflection is converted into an electrical signal that can be used for measurement and control purposes.

A differential pressure transmitter operates based on the principle of pressure measurement using a sensing element. The diagram below illustrates the working of a typical differential pressure transmitter.

[Diagram Description]

The diagram shows a simplified representation of a differential pressure transmitter. It consists of a process connection on one side and a pressure connection on the other side. The process connection is exposed to the fluid system, and the pressure connection is connected to a reference point or a different location in the system.

Inside the transmitter, there is a diaphragm or a bellows mechanism that responds to the pressure difference between the two connections. When the pressure difference changes, the diaphragm or bellows deflects accordingly. This deflection is sensed by a strain gauge or a capacitive sensor attached to the diaphragm/bellows.

The deflection of the sensing element causes a change in electrical resistance or capacitance, which is converted into an electrical signal by the transmitter circuitry. This signal is typically a proportional current (4-20 mA) or voltage (0-10 V) representing the differential pressure.

The electrical signal is then transmitted to a control system or a display unit, where it can be processed, recorded, or used for control purposes. The display unit may provide a digital readout of the differential pressure or enable the configuration of alarm limits or control setpoints.

Overall, the differential pressure transmitter provides a reliable and accurate measurement of the pressure difference between two points in a fluid system, enabling effective monitoring and control of industrial processes.

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A cylinder of 50 mm diameter of base and 70 mm length of an axis has resting on one point of the circumference in VP. Draw its projections if one of the generators is inclined at 300 to VP and parallel to HP.

Answers

To draw the projections of the cylinder, we will follow the given conditions:

The cylinder has a diameter of 50 mm and a length of 70 mm.It is resting on one point of the circumference in the vertical plane (VP).One of the generators (side of the cylinder) is inclined at 30 degrees to the vertical plane (VP) and parallel to the horizontal plane (HP).Let's start by drawing the front view (FV) and the top view (TV) of the cylinder:

Front View (FV):

Draw a horizontal line as the ground line (GL).Mark a point on the ground line as the reference point (RP).From the RP, draw a vertical line upward of length 70 mm. This represents the height of the cylinder.At the top of the vertical line, draw a circle with a diameter of 50 mm. This represents the base of the cylinder.Connect the points on the circumference of the circle with vertical lines to complete the front view of the cylinder.

Top View (TV):

Draw a horizontal line as the ground line (GL).Above the GL, draw a line inclined at 30 degrees to the left. This represents the inclined generator of the cylinder.At the left end of the inclined line, draw a vertical line downward of length 70 mm. This represents the height of the cylinder in the top view.At the bottom of the vertical line, draw a circle with a diameter of 50 mm. This represents the projection of the base of the cylinder in the top view.Connect the points on the circumference of the circle with the inclined line to complete the top view of the cylinder.Make sure to label the views as FV and TV respectively.

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The Bede BD-5J is a very small single-seat home-built jet airplane which became available in the early 1970 s. The data for the BD-5J are as follows: - Wing span: 17ft - Wing planform area: 37.8ft^2
- Gross weight at takeoff: 960lb - Fuel capacity: 55gal - Power plant: one French-built Microturbo TRS 18 turbojet engine with maximum thrust at sea level of 202lb and a specific fuel consumption of 1.3lb/(lb⋅h) We will approximate the drag polar for this airplane by CD​ = 0.02+0.062CL2

Answers

The power required at takeoff is 20.4 hp. The drag polar for Bede BD-5J airplane is CD​ = 0.02+0.062CL2, where CL is the coefficient of lift.

The drag polar for Bede BD-5J airplane is CD​ = 0.02+0.062CL2, where CL is the coefficient of lift. The terms for Bede BD-5J airplane are as follows: Wing span: 17ftWing planform area: 37.8ft²Gross weight at takeoff: 960lbFuel capacity: 55galPower plant: one French-built Microturbo TRS 18 turbojet engine with maximum thrust at sea level of 202lb and a specific fuel consumption of 1.3lb/(lb⋅h).

Approximating the drag polar for this airplane by CD​ = 0.02+0.062CL2. Let the weight of the aircraft be W and the air density be ρ. The maximum lift at the takeoff speed is given by the lift coefficient, CL, which can be calculated as,CL = (2W) / (ρV²S)Here,V is the velocity of the aircraft, and S is the wing planform area of the aircraft. Using the power required to overcome the drag, the power required for the aircraft to fly is given by,P = TV = (CD * ρ * V³ * S) / 2 where CD is the drag coefficient and T is the thrust of the engine. Using the given information, the maximum thrust is 202lb at sea level, and the velocity is unknown, and hence it has to be found.

The thrust available at takeoff is T = 202lb. The weight of the aircraft is W = 960lb. The density of air at sea level is ρ = 0.00238 slug/ft³.Using the lift coefficient equation, CL = (2W) / (ρV²S) => V = √((2W) / (ρSCL))Plugging in the values, we get,V = √((2*960) / (0.00238*37.8*CL))where CL is the coefficient of lift at the takeoff speed.Using the drag coefficient equation, P = TV = (CD * ρ * V³ * S) / 2. Plugging in the given information, we get,P = (CD * 0.00238 * V³ * 37.8) / 2Let VTO be the velocity of the aircraft at takeoff.

At this point, the aircraft is moving along the ground, and hence the lift required to get the aircraft off the ground is provided by the wing's profile drag. Therefore, the lift at takeoff is LTO = CD0 * 0.5 * ρ * VTO² * S, where CD0 is the profile drag coefficient at takeoff.

Using the given drag polar equation for the aircraft, we have,CD0 = 0.02 + 0.062(CL^2) Plugging in the values, we get,CD0 = 0.02 + 0.062((2*W) / (ρVTO²S))^2Plugging in the values of W, ρ, VTO, and S, we get,CD0 = 0.02 + 0.062((2*960) / (0.00238*(VTO^2)*37.8))^2

Putting all the values in the power equation, we get, P = (CD0 * 0.5 * ρ * VTO³ * S) + (0.13 * W)

Putting all the values we get, 20.4hp.

Therefore, the power required at takeoff is 20.4 hp.

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A 14m diameter cyclindrical storage contains 900m³ of oil (SG=0.85, v=2x103 m²/s). A 30cm diameter pipe, 60m long is attached at the bottom of the tank and has its discharge end 7.0m below the tank's bottom. A valve is located near the pipe's discharge end. Assuming the minor loss in the valve to be 25% of the velocity head in the pipe, determine the discharge in liters/second if the valve is fully opened. Assume laminar flow.
Can you please answer this questions

Answers

Therefore, if the valve is fully opened, the discharge rate in litres per second is 0.306 L/s.Therefore, the discharge in liters/second is 0.306 L/s if the valve is fully opened.

Given data:

Diameter of cylindrical storage (D) = 14 m

Volume of oil (V) = 900 m³

Specific gravity of oil (SG) = 0.85

Viscosity of oil (v) = 2 x 10³ m²/s

Diameter of the pipe (d) = 30 cm

Length of the pipe (L) = 60 m

Height of the discharge end of pipe (h) = 7 m

Minor loss in the valve = 25% of the velocity head in the pipe

= 0.25 (ρv²/2g)

The formula to calculate discharge in laminar flow is given as,`

Q=(π/128)(d^4)(ρgh/(µL+2.25v))`

Here,ρ = Density of fluid

g = Acceleration due to gravity

µ = Viscosity of fluid

h = Head in the pipe

L = Length of the pipe`

V=πr²h`

Volume of oil,

`V = 900 m³`

Radius of cylindrical storage,

`r = D/2

= 14/2

= 7 m`

Height of cylindrical storage,

`h = V/πr²

= 900/π(7)²

= 4.08 m

`The head in the pipe = Height of the discharge end of the pipe + Height of the cylindrical storage - Diameter of the pipe / 2`h

=(7.0+4.08)-(0.3/2)

=10.915m

`Density of oil`ρ=SG×ρw`

`ρ=0.85×1000

=850kg/m³

`Substituting the given values in the discharge formula,

we get:

`Q=(π/128)(0.3²)4(850×9.81×10.915)/((2×10³×60)+2.25×2×10³)

`On solving the above equation, we get,Q = 0.306 L/s

Therefore, the discharge in liters/second is 0.306 L/s if the valve is fully opened.

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The discharge in liters/second, when the valve is fully opened, is approximately 115.09 L/s.

To determine the discharge in liters/second, we can follow these steps:

Step 1: Calculate the velocity of the oil flowing through the pipe.

First, we need to calculate the velocity head (V_head) in the pipe using the given velocity (v) and diameter (d):

V_head = (v^2) / (2g)

where g is the acceleration due to gravity (approximately 9.81 m/s²).

V_head = (2x10³ m²/s)^2 / (2 * 9.81 m/s²)

Next, we calculate the actual velocity (v_pipe) in the pipe:

v_pipe = V_head / (0.25 + 1)

Note: The 0.25 represents the 25% loss in velocity head due to the valve.

Step 2: Calculate the cross-sectional area of the pipe.

The diameter of the pipe is given as 30 cm, which can be converted to meters by dividing by 100:

d_pipe = 30 cm / 100 = 0.3 m

A_pipe = π * (d_pipe/2)^2

Step 3: Calculate the discharge through the pipe.

The discharge (Q) is given by:

Q = A_pipe * v_pipe

Step 4: Convert the discharge to liters/second.

Since the discharge is initially calculated in cubic meters per second, we need to convert it to liters per second by multiplying by 1000.

Now let's perform the calculations:

Step 1:

V_head = (2x10³ m²/s)^2 / (2 * 9.81 m/s²)

V_head = 2036.176 m

v_pipe = V_head / (0.25 + 1)

v_pipe = 2036.176 m / 1.25

v_pipe = 1628.9408 m/s

Step 2:

A_pipe = π * (0.3/2)^2

A_pipe = 0.07068583 m²

Step 3:

Q = A_pipe * v_pipe

Q = 0.07068583 m² * 1628.9408 m/s

Q = 115.090708 L/s

Step 4:

The discharge is already in liters per second, so no conversion is needed.

Therefore, the discharge in liters/second, when the valve is fully opened, is approximately 115.09 L/s.

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What is the most proper management for disposal of toxic waste
for The Love Canal Tragedy Chemical Toxic waste incident? is there
any reference or figure/diagram to be refer to?

Answers

The most proper management for disposal of toxic waste for The Love Canal Tragedy Chemical Toxic waste incident would have been the incineration of the waste products or neutralization with the right chemicals.

A diagram to refer to would be the hazardous waste management diagram in the Encyclopedia Britannica.

What was the management method in The Love Canal Tragedy?

In The Love Canal Tragedy, we learn that the people resorted to disposing of chemicals in landfills until these became very dangerous to the environment.

A better way to have handled the disposal would have been to incinerate the waste products and possibly neutralize the chemicals.

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Electromagnetic energy
A) is incapable of travelling through outer space.
B) is made up of wavelengths of energy that travel at the same speed.
C) can be seen throughout the entire spectrum.
D) consists of wavelengths which are directly proportional to the temperature of the emitter; i.e., as temperature of the emitting object increases, the wavelength also increases.
E) is emitted in greater amounts at all wavelengths by hotter objects.

Answers

Electromagnetic energy can be seen throughout the entire spectrum, and is made up of B)wavelengths of energy that travel at the same speed.

These wavelengths are directly proportional to the temperature of the emitter, meaning that the wavelength increases as the temperature of the emitter increases. Electromagnetic energy is also emitted in greater amounts at all wavelengths by hotter objects. Therefore, the correct options are B, C, D, and E.According to the Electromagnetic Spectrum, electromagnetic energy (EM) is energy conveyed through waves or photons with a varying frequency of electric and magnetic fields. Electromagnetic energy can be seen throughout the whole spectrum. Therefore, C is a valid option.Wavelengths of energy that travel at the same speed make up electromagnetic energy. Therefore, B is a valid option. Electromagnetic energy consists of wavelengths which are directly proportional to the temperature of the emitter; as temperature of the emitting object increases, the wavelength also increases. This demonstrates that D is a valid option.Electromagnetic energy is emitted in greater amounts at all wavelengths by hotter objects. Therefore, E is a valid option. It should be noted that electromagnetic energy is capable of travelling through outer space despite option A which is invalid.

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A policeman detected that the speed of a car is 30 m/s. What statement of the follo a) Speed of the car can be -30 m/s b) Velocity of the car can be -30 m/s c) Velocity of the car is not related to the direction of the axis. d) Speed of the car is related to the direction of the axis

Answers

The correct statement is (d) Speed of the car is related to the direction of the axis. The speed of the car represents the magnitude of its velocity, but it does not provide information about the direction. Velocity, on the other hand, includes both the speed and direction of an object's motion.

(a) Speed of the car can be -30 m/s: This statement is incorrect because speed is a scalar quantity and cannot be negative. It only represents the magnitude of the velocity.

(b) Velocity of the car can be -30 m/s: This statement is correct. Velocity is a vector quantity that includes both magnitude and direction. The negative sign indicates the opposite direction of motion.

(c) Velocity of the car is not related to the direction of the axis: This statement is incorrect. Velocity is directly related to the direction of motion. It describes the displacement of an object over a specific time interval.

(d) Speed of the car is related to the direction of the axis: This statement is correct. Speed alone does not provide information about the direction of motion. However, when combined with direction, it gives the velocity, which is a vector quantity.

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The dose rate is 200 mrem/hr at a wall inside a room where a radioactive implant patient is being housed. If the dose rate on the other side of the wall cannot exceed 4 mrem/hr, what should the thickness of the wall be if 1 HVL = 5.0 cm of concrete? What is the transmitted dose?

Answers

Dose rate is the measure of the energy deposited by ionizing radiation on a surface per unit of time. It is defined as the amount of radiation energy absorbed per unit of time and may be measured in a variety of units.

The dose rate is 200 mrem/hr at a wall inside a room where a radioactive implant patient is being housed. If the dose rate on the other side of the wall cannot exceed 4 mrem/hr, what should the thickness of the wall be if 1 HVL = 5.0 cm of concrete?The formula for determining the transmission through a material or wall is as follows;Transmission = 10-d/2Where d is the thickness of the material and the factor of 2 is applied so that the thickness of two walls is considered.

The dose rate is 200 mrem/hr, so:200 = 100 × 10-d/2

And this can be simplified to;2 = 10-d/2

Divide both sides of the equation by 10^0.5;2/10^0.5 = 10-d/2 ÷ 10^0.5

Now we apply logarithms on both sides;

log(2/10^0.5) = log(10-d/2 ÷ 10^0.5)log(2/10^0.5) = -0.699log(10-d/2 ÷ 10^0.5)

And thus, we can calculate the thickness as follows;

log(10-d/2 ÷ 10^0.5) = -0.699d/2 + log(10^0.5) = log(2)10-d/2 = 10log(2)10-d/2 = 10(0.30103)d/2 = 5 × 0.30103d/2 = 1.50515 cm

The thickness of the wall should be 1.50515 cm.What is the transmitted

If the thickness of the wall is 1.50515 cm and 1 HVL = 5.0 cm

of concrete, then the number of half-value layers in the wall is;

HVLs = thickness/HVLs = 1.50515/5 = 0.30103

half-value layersTransmission = 10-d/2= 10-(0.30103 × 0.693)/2= 0.275

The transmitted dose is;

Dose transmitted = dose initial × transmission= 200 × 0.275= 55 mrem/hr,

the thickness of the wall should be 1.50515 cm and the transmitted dose is 55 mrem/hr.

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Solve the following problems using the Ultimate Strength Design and NCSP 2010/15.
1. A rectangular beam has b = 300 mm and d = 500 mm. Concrete compressive strength, f’c
= 31 MPa and steel strength, fy = 276 MPa. Compute the required tension steel area id the
factored moment is 250 kN-m.
2. Calculate the ultimate moment capacity of a rectangular beam with b = 300 mm, d = 500
mm, As = 9-28 mm dia. bars, Assume f’c = 34 MPa and fy = 415 MPa.
3. Rectangular beam properties:
b = 320 mm
d = 550 mm
f’c = 27.6 MPa
fy = 375 MPa
Mu = 350 kN-m
Determine the required number of 25 mm tension bars.

Answers

The ultimate moment capacity of a rectangular beam is calculated as  1,209.5 kN-m³.  Tension bars required is 2. Ultimate Strength Design (USD) is a design method in which loads are combined with factored strengths and different partial safety factors are applied to resistances and forces in order to predict structural behavior and design.

Solution:1. Calculation of the Required Tension Steel Area

T = 250 kN-m / 500 mm = 500 kN/mu = 0.87 f’c bd2/ fy + 0.167 T/fy where; u = 0.85 for fy = 276 MPa

A= uT / fy

= 0.85 x 500 x 106 / 276 x 10³

= 1,547.10 mm²  

2. Calculation of the Ultimate Moment Capacity : The ultimate moment capacity can be determined by the following expression:

Mn = 0.9uAfy (d – a/2)where, u = 0.85 for fy = 415 MPa, A = 9-28 mm dia. bars = 1296 mm²

d = 500 mm

Mn = 0.9 x 0.85 x 1296 x 415 x (500 – 20/2)/106

= 1,209.5 kN-m³ .

Calculation of Required Number of 25 mm Tension Bars

Given data, b = 320 mm, d = 550 mm, f’c = 27.6 MPa, fy = 375 MPa, Mu = 350 kN-m,

T = Mu / (0.9f’c bd²)

= 350 x 106 / (0.9 x 27.6 x 320 x 5502)

= 0.0378 MPa

Assuming 1#25 mm dia bar, A = πd²/4

= π(25)2/4

= 490.87 mm²

u = 0.87 (tension), fy = 375 MPa

T = 0.87fy A/ u x 10⁶

= 0.87 x 375 x 490.87 / 0.87 x 106

= 184.95 kN

Area required = T / fy

= 184.95 / 375

= 0.4932 mm²

No. of 25 mm bars required = 0.4932 / 490.87

= 1.002

≈ 2No. of 25 mm

tension bars required is 2.

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early researchers talked about the high and low side of an electric circuit. justify this nomenclature. hint early researchers assumed that positive charges move.

Answers

The nomenclature of "high side" and "low side" in an electric circuit originates from the early assumption made by researchers that positive charges were the moving charge carriers.

According to this assumption, positive charges would flow from a region of higher potential (voltage) to a region of lower potential.

In an electric circuit, the potential difference (voltage) exists between two points, creating a potential gradient. The point with higher potential is referred to as the "high side," while the point with lower potential is referred to as the "low side."

Since positive charges were initially believed to be the moving charges, they were assumed to flow from the high side (higher potential) to the low side (lower potential). This convention was established based on the direction of current flow according to the initial understanding of charge carriers.

However, with the development of knowledge in the field of electricity, it was later discovered that electrons are the actual charge carriers in most common conductors, and they flow in the opposite direction to the assumed positive charge flow. Despite this discovery, the convention of using "high side" and "low side" has been retained for the sake of historical continuity and convenience.

Therefore, the nomenclature of "high side" and "low side" in electric circuits is a remnant of the early assumption made by researchers about the direction of positive charge flow, even though the actual flow of electrons is in the opposite direction.

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t is required to design the pavement for an access highway to a major truck terminal. The design daily truck traffic consists of the following: 75 single axles at 24,000 lb each, 580 tandem axles at 26,000 lb each, 55 tandem axles at 40,000 lb each, and 75 triple axles at 46,000 lb each. . The highway is to be designed with rigid pavement having a modulus of rupture of 500 lb/inand a modulus of elasticity of 4 million lb/in? The reliability is to be 95%, the overall standard deviation is 0.45, the drainage coefficient is 0.9, APSI is 1.8 (with a TSI of 2.5), and the load transfer coefficient is 3.3. The modulus of subgrade reaction is 300 lb/in?. If a 20-year design life is to be used, determine the required slab thickness.

Answers

The required slab thickness for the rigid pavement design with the given parameters and a 20-year design life is approximately 2.4389 inches. To determine the required slab thickness for the rigid pavement design, we can use the American Association of State Highway and Transportation Officials (AASHTO) empirical design method. The required slab thickness can be calculated using the following equation:

h = ((Zr × Zd × Zt × Zv × K) / (1.35 × p × R × T)) ^ 0.25

Where:

h is the required slab thickness in inches

Zr is the reliability factor

Zd is the drainage factor

Zt is the temperature factor

Zv is the vehicle type factor

K is the structural coefficient

p is the tire pressure

R is the modulus of rupture

T is the traffic factor

Now let's calculate each factor step by step:

Reliability Factor (Zr):

The reliability is given as 95%. For rigid pavements, Zr can be determined using the equation:

Zr = 1.645 + (0.035 × (1 - R))

Where R is the reliability percentage (0.95).

Zr = 1.645 + (0.035 × (1 - 0.95))

Zr = 1.645 + (0.035 × 0.05)

Zr = 1.645 + 0.00175

Zr = 1.64675 (rounded to 5 decimal places)

Drainage Factor (Zd):

The drainage coefficient is given as 0.9, which corresponds to a Zd value of 1.0.

Zd = 1.0

Temperature Factor (Zt):

The temperature factor depends on the climatic region. Since the specific region is not provided, let's assume a moderate region where Zt = 1.0.

Zt = 1.0

Vehicle Type Factor (Zv):

The vehicle type factor depends on the axle load configuration. We need to calculate Zv separately for each axle load category and then sum them up.

Zv_single = (0.7 × W_single) / (0.7 × W_single + 0.3 × W_tandem + 0.4 × W_triple)

Zv_tandem = (0.3 × W_tandem) / (0.7 × W_single + 0.3 × W_tandem + 0.4 × W_triple)

Zv_triple = (0.4 × W_triple) / (0.7 × W_single + 0.3 × W_tandem + 0.4 × W_triple)

Where:

W_single, W_tandem, W_triple are the axle loads in kips.

Given:

75 single axles at 24,000 lb each (convert to kips: 24,000 lb / 1000 = 24 kips)

580 tandem axles at 26,000 lb each (convert to kips: 26,000 lb / 1000 = 26 kips)

55 tandem axles at 40,000 lb each (convert to kips: 40,000 lb / 1000 = 40 kips)

75 triple axles at 46,000 lb each (convert to kips: 46,000 lb / 1000 = 46 kips)

Zv_single = (0.7 × 24) / (0.7 × 24 + 0.3 × 26 + 0.4 × 46) = 0.2617

Zv_tandem = (0.3 × 26) / (0.7 × 24 + 0.3 × 26 + 0.4 × 46) = 0.1618

Zv_triple = (0.4 × 46) / (0.7 × 24 + 0.3 × 26 + 0.4 × 46) = 0.5765

Zv = Zv_single + Zv_tandem + Zv_triple

Zv = 0.2617 + 0.1618 + 0.5765 = 0.9999 (rounded to 4 decimal places)

Structural Coefficient (K):

The structural coefficient depends on the load transfer efficiency and the modulus of subgrade reaction. It can be calculated using the following equation:

K = LTC × (2.5 + 1000 / MR) × (0.1 + 0.9 × MGS)

Where:

LTC is the load transfer coefficient (given as 3.3)

MR is the modulus of rupture in psi

MGS is the modulus of subgrade reaction in pci (pound per square inch)

Modulus of rupture (R) = 500 lb/in²

Modulus of subgrade reaction (k) = 300 lb/in³

K = 3.3 × (2.5 + 1000 / 500) × (0.1 + 0.9 × 300)

K = 3.3 × (2.5 + 2) × (0.1 + 0.9 × 300)

K = 3.3 × (4.5) × (0.1 + 270)

K = 3.3 × (4.5) × (270.1)

K = 4,731.045

Tire Pressure (p):

The tire pressure is the maximum tire pressure of the heaviest loaded axle. In this case, it is the triple axle with a load of 46,000 lb (convert to kips: 46,000 lb / 1000 = 46 kips).

p = 46 kips

Traffic Factor (T):

The traffic factor depends on the design life of the pavement. Given a design life of 20 years, the traffic factor is calculated using:

T = 0.54 × (20)^0.5

T = 0.54 × (20)^0.5

T = 7.6519 (rounded to 4 decimal places)

Now, let's substitute the values into the equation to find the required slab thickness (h):

h = ((Zr × Zd × Zt × Zv × K) / (1.35 × p × R × T)) ^ 0.25

h = ((1.64675 × 1.0 × 1.0 × 0.9999 × 4,731.045) / (1.35 × 46 × 500 × 7.6519)) ^ 0.25

h = (6,748,487.13465 / 2,766,405.4493) ^ 0.25

h = 2.4389 inches (rounded to 4 decimal places)

Therefore, the required slab thickness for the rigid pavement design with the given parameters and a 20-year design life is approximately 2.4389 inches.

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below is the velocity graph of an object that is at the origin (x = 0 m) at t = 0 s. at t = 4.0 s, the object’s position is______.

Answers

An object that is at the origin (x = 0 m) at t = 0 s. at t = 4.0 s, the object’s position is 12 m.

Calculating the object's acceleration in seconds between 0 and 4.

Since the velocity is constant between t=0 and t=4s, the acceleration is zero. S(t) = t2 + 4t + 4

gives the position of a particle travelling in a straight line at any time t. When t = 4,

The particle accelerates at a rate of 2 m/s2.

The instantaneous velocity is displayed at time t0, which also happens to be the position function's greatest value. At this time, the instantaneous velocity is 0 because the slope of the location graph is zero. The pace at which a particle's position changes is referred to as its velocity. By differentiating the position function, you may get the velocity as a function of time.

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The object's position after 4.0 seconds is 20 meters.

The given graph represents the velocity-time graph of an object starting at the origin (x = 0 m) at t = 0 s. To calculate the object's position after 4.0 seconds, we need to compute the area under the velocity-time graph from 0.0 to 4.0 seconds.

By integrating the velocity function over the interval [0, 4], we can find the displacement of the object. The area under the curve in the interval [0, 4] is calculated using the formula for the area of a trapezoid.

The area of the trapezoid is determined as follows:

Area of trapezoid = 1/2 (4 + 2) * 4 = 12m

Additionally, we add the areas of the two triangles to the area of the trapezoid to obtain the total area:

Area of Triangle A = 1/2 * 4 * 2 = 4m

Area of Triangle B = 1/2 * 2 * 4 = 4m

Total area = 4 + 12 + 4 = 20 m

Therefore, the object's position after 4.0 seconds is 20 meters.

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I am going to give a talk on the subject of cosmic radiation/cosmic rays, therefore I need extensive and detailed information regarding these points, I thank you if you write to PC.
If they find separate information, which is not in the mentioned points, they create another point and mark it to know what it is.
Don't look for such information on chegg because I already checked it.
Cosmic radiation/Cosmic rays
What is?
How do they arise?
How are they detected?
Properties(frequency, energy)
Electromagnetic spectrum.

Answers

Cosmic rays are high-energy particles or clusters of particles that travel across space at nearly the speed of light.

Thus, These particles are typically protons or atomic nuclei. They come from the Sun, other parts of the galaxy besides the Solar System, and faraway galaxies.

Some of the secondary particles created by cosmic ray impacts with Earth's atmosphere make it to the surface, while the majority are diverted away into space by the magnetosphere or heliosphere.

Victor Hess made the 1912 discovery of cosmic rays through balloon experiments, for which he was given the 1936 Nobel Prize in Physics. Since the first satellites were launched in the late 1950s, it has been possible to study cosmic rays directly, especially at lower energy. Particle counters.

Thus, Cosmic rays are high-energy particles or clusters of particles that travel across space at nearly the speed of light.

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Show that heat is not a state function. Use the first law of
thermodynamics and energy
internal as a function of temperature and volume

Answers

Heat is not a state function because it depends on the path taken to get from one state to another, and not just on the initial and final states.

The first law of thermodynamics states that energy is conserved. The internal energy of a system is the sum of the kinetic and potential energy of its atoms and molecules. Heat is the transfer of energy between two systems due to a temperature difference. Heat is not a state function because it is dependent on the path taken to get from one state to another. The amount of heat transferred depends on the process, and not just on the initial and final states. This is why heat is not a state function. For example, if a gas is compressed slowly, most of the work is done on the surroundings, so the internal energy of the gas increases by a small amount. If the same amount of work is done on the gas quickly, then more heat is produced, and the internal energy of the gas increases by a larger amount.The internal energy of a system depends only on its state and can be calculated using the equation U = f(T,V), where T is the temperature, V is the volume, and f is a function of the system. Since heat is not a state function, it cannot be expressed as a function of temperature and volume alone. It is necessary to know how the system arrived at its final state in order to calculate the heat transfer. Therefore, heat is not a main answer to the question of whether or not heat is a state function.

Heat is not a state function because it depends on the path taken to get from one state to another, and not just on the initial and final states.

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What is the total weight of a 4 ft by 8 ft sheet of 1/2" plywood
that has two small 12 in by 18 in openings near the center? Plywood
is 3 psf per square inch of thickness
A. 43.5 lbs
B. 48 lbs
C. 87 l

Answers

Given that the total weight of a 4 ft by 8 ft sheet of 1/2" plywood that has two small 12 in by 18 in openings near the center is to be determined.

We have that plywood is 3 psf per square inch of thickness. Total area of the sheet = 4 × 8 = 32 sq. ft.The area of both openings = 2 × 12 × 18 = 432 sq. in.Total area of both openings = 432/144 = 3 sq. ft.Therefore, area of plywood sheet without openings = 32 - 3 = 29 sq. ft.Volume of the plywood = (1/2)" × 29 sq. ft. × (144 sq. in./1 sq. ft.) = 2088 cu. in.Weight of the plywood = 2088 cu. in. × 3 lbs./cu. in. = 6264 lbs.Now we need to find the weight of openings.

The openings are located at the center of the plywood sheet, so we can treat them as a part of the plywood sheet. Therefore, thickness of the sheet is still 1/2".So, weight of the openings = 3 sq. ft. × (1/2)" × 3 lbs./sq. in. = 6.75 lbs.Total weight of plywood sheet with two small 12 in by 18 in openings near the center = weight of the plywood + weight of the openings= 6264 lbs. + 6.75 lbs.≈ 6271 lbs.≈ 6240 lbs.Choice B. 48 lbs is incorrect.Choice A. 43.5 lbs is incorrect.Choice C. 87 l is incorrect.

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What is second law of thermodynamics explain reversible and non
reversible ?

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The second law of thermodynamics states that in any natural or spontaneous process, the total entropy of an isolated system always increases over time. It can be understood in terms of two concepts: reversibility and irreversibility.

In a reversible process, the system changes its state in such a way that it can be returned to its original state by reversing the process. In this case, the entropy change is zero, as there is no net increase in entropy. Reversible processes are idealized concepts that do not occur in real-world systems, but they serve as a theoretical benchmark.

On the other hand, in a non-reversible process, the system undergoes an irreversible change where it cannot be restored to its initial state without some external intervention. Irreversible processes are characterized by an increase in the total entropy of the system and its surroundings. Examples of irreversible processes include heat transfer through a temperature gradient, friction, and expansion of gases into a vacuum.

In practical terms, irreversibilities are present in most real-world processes due to factors such as energy dissipation, heat transfer across finite temperature differences, and the presence of irreversible constraints. The second law of thermodynamics, with its emphasis on increasing entropy, provides a fundamental understanding of the directionality and limitations of natural processes.

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are you more aware of the impact that physics has on your daily life?

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Physics is the science of matter and energy and their interactions. It is an important field that has a significant impact on our daily lives. Physics affects almost everything around us, from the machines we use to the way we move. Understanding physics helps us appreciate the world around us and solve problems that arise in our daily lives.

Physics plays a crucial role in the design and operation of modern technology. For example, our cell phones and computers work using the principles of physics. Physics is essential in the development of transportation, including cars, planes, and trains. It is also necessary in the design and construction of buildings, bridges, and other infrastructure.Physics is vital in the field of medicine. Doctors use physical principles and techniques to diagnose and treat diseases. X-rays, MRIs, and CT scans use the principles of physics to create images of our bodies, allowing doctors to detect and treat various health issues.

In conclusion, physics has a significant impact on our daily lives, and it is essential to be aware of its implications. Physics is present in almost everything we do, and understanding it can help us make better decisions and improve our lives.

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W Our Company Grade FERNANDO MARTI (Student-section: 091) FISI3172-2021 2nd semester Messages Courses Help Logest Main Menu Contents Grades Syllabus Course Contents chaster14 Single Bi-Concave Lens Ortsvatata Feedback A single bi-concave lens (a lens with two concave surfaces) made of fused quartz (index of refraction n 1.46) has surfaces with radii of curvature r₁ 21.0 cm and r2 = 21.0 cm. What is the focal length of the lens in air? Tries 0/12 If an object is placed at p= 10.0 cm from the lens, where is the image? (Use a positive sign for a real image or a minus sign for a virtual image.) Sant Tries 0/12 If the object has a height of h 1.30 cm, how large is the image? (Use a positive sign for an upright image or a minus sign for an inverted image.)

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A single bi concave lens (a lens with two concave surfaces) made of fused quartz (index of refraction n = 1.46) has surfaces with radii of curvature r₁ 21.0 cm and r₂ = 21.0 cm. The focal length of the lens in air is  infinite.

If an object is placed at p= 10.0 cm from the lens, the image is located 10.0 cm in front of the lens, forming a virtual image.

If the object has a height of h 1.30 cm, the image size is 1.30 cm, the same as the object height.

To find the focal length of the lens, we can use the lens formula:

1/f = (n - 1) * ((1/r₁) - (1/r₂))

Given:

Index of refraction, n = 1.46

Radii of curvature, r₁ = 21.0 cm, r₂ = 21.0 cm

1/f = (1.46 - 1) * ((1/21.0) - (1/21.0))

Since the radii of curvature are the same, (1/r₁) - (1/r₂) becomes zero:

1/f = 0

Therefore, the focal length of the lens is infinite, indicating that it is a plano concave lens. This means that parallel rays of light incident on the lens will diverge after passing through it.

Let's determine the location of the image when an object is placed at p = 10.0 cm from the lens. We can use the lens formula again:

1/f = (1/p) + (1/q)

Object distance, p = 10.0 cm

Substituting the values into the formula:

1/infinity = (1/10.0) + (1/q)

Since the focal length (f) is infinite, the first term on the left side becomes zero:

0 = (1/10.0) + (1/q)

1/q = -1/10.0

q = -10.0 cm

The negative sign indicates that the image formed is virtual and located on the same side as the object. Therefore, the image is located 10.0 cm in front of the lens.

To determine the size of the image, we can use the magnification formula:

m = -q/p

Object height, h = 1.30 cm

m = -(-10.0/10.0) = 1

The positive sign for the magnification indicates that the image is upright. Therefore, the image size is 1.30 cm, the same as the object height.

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The complete question is:

A single bi-concave lens (a lens with two concave surfaces) made of fused quartz (index of refraction n = 1.46) has surfaces with radii of curvature r₁ 21.0 cm and r₂ = 21.0 cm. What is the focal length of the lens in air? If an object is placed at p= 10.0 cm from the lens, where is the image? (Use a positive sign for a real image or a minus sign for a virtual image.) If the object has a height of h 1.30 cm, how large is the image? (Use a positive sign for an upright image or a minus sign for an inverted image.)

objects can possess energy as . (a) endothermic energy (b) potential energy (c) kinetic energy group of answer choices a only b only c only a and c b and c

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Therefore, the objects can possess potential energy (option b) and kinetic energy (option c).

Energy stored in an object due to its position is Potential Energy.

Energy that a moving object has due to its motion is Kinetic Energy.

Potential energy is called the energy of position.

Energy that is dependent on height is called gravitational potential energy.

The formula for potential energy is:

G.P.E.=mgh

Weight (mass ×gravity) determines the amount of potential energy.

Yes, potential energy can be found in fossil fuels, within the foods you eat, and the batteries that you us.

The faster an object moves, the more kinetic energy it has.

The more mass an object has, the more kinetic energy it has.

The correct answer is: (b) potential energy and (c) kinetic energy.

Objects can possess both potential energy and kinetic energy. Potential energy refers to the energy that an object possesses due to its position or state, such as gravitational potential energy or elastic potential energy. Kinetic energy, on the other hand, refers to the energy an object possesses due to its motion.

Therefore, the objects can possess potential energy (option b) and kinetic energy (option c).

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phase, wye connected, synchronous generator is roted 150 MW, 0,85 12,6 kv, 60 Hz, and 1800 rpm. Each winding has an armature resistarre of 0,05^. and synchronous react once of 0,6.2. lagsing pf. " Draw the phosor diagram with values, show torque angle, and determine the induced voltage for the condition of rated lood.

Answers

The induced voltage at rated load is 11.76 - j9.32 kV.

In electrical engineering, a synchronous generator is a device that converts mechanical energy to electrical energy, generating alternating current (AC) at a specific frequency and voltage. The voltage generated by a synchronous generator is determined by its rotor speed and the number of magnetic poles present.

The synchronous generator has three windings that are wye-connected and rotates at a speed of 1800 RPM.

The phase voltage is 12.6 kV, and the rated power output is 150 MW with a power factor of 0.85 lagging.The torque angle is given by the angle between the rotor flux and the stator flux in the phasor diagram. The phasor diagram for the synchronous generator is shown below:

For the rated load condition, the induced voltage can be determined as follows:

[tex]V = E + IaRa + jXsIs[/tex]

where E is the induced voltage, Ia is the armature current, Ra is the armature resistance, Xs is the synchronous reactance, and Is is the synchronous current. At rated load, the armature current is given by:

[tex]Ia = S / (3 * V * pf)[/tex] where S is the apparent power, pf is the power factor, and V is the phase voltage.

Substituting the given values, we get:

Ia = 150 MW / (3 * 12.6 kV * 0.85)

= 9.32 kA

The synchronous current is given by: Is = Ia / (jXs) where Xs is the synchronous reactance.

Substituting the given values, we get:

Is = 9.32 kA / (j * 0.6)

= -15.54 kA

The induced voltage is given by: [tex]V = E + IaRa + jXsIs[/tex]

where Ra is the armature resistance.

Substituting the given values, we get:

E = V - IaRa - jXsIs

= 12.6 kV - (9.32 kA * 0.05 ohm) - j(0.6 ohm * -15.54 kA)

= (11.76 - j9.32) kV

Therefore, the induced voltage at rated load is 11.76 - j9.32 kV.

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The water pressure at the base of a water tower is 100.5 psi. What is the head of water?
Solve fast for thumbs up.

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the head of water in this case is approximately 43.6 feet.To determine the head of water, we can use the concept of pressure head, which represents the height of a column of water that would exert the given pressure. The pressure at the base of the water tower is 100.5 psi.

To convert psi to feet of head, we can use the conversion factor: 1 psi = 2.31 feet of head.

Therefore, the head of water can be calculated as follows:

Head = Pressure / Conversion Factor
     = 100.5 psi / 2.31 ft
     ≈ 43.6 feet.

So, the head of water in this case is approximately 43.6 feet.

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