a) The induced emf in the rectangular coil can be expressed as ε = BLv
b) Substituting the given values, we get ε = (1120)(2.50 T)(0.088 m)(0.055 m)(10.6 m/s) = 109.2 V
In part a), the formula for induced emf is given as ε = NBLv, where N is the number of turns in the coil, B is the magnetic field strength, L is the length of the coil, a is the width of the coil, and v is the velocity of the coil. In part b), we are given the values for N, B, L, a, and v, and asked to calculate the induced emf.
We substitute these values into the formula and solve for ε, which is found to be 109.2 V. This means that as the coil moves through the magnetic field, an emf of 109.2 volts is induced across its ends.
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While traveling in the same medium, sound A has a wavelength of 5 meters, while sound B has a wavelength of 10 meters. Which
sound will have a higher pitch? (1 point)
O sound A, because it has a higher frequency
O sound B, because it has a lower frequency
O sound B, because it has a higher frequency.
O sound A, because it has a lower frequency
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Answer:
sound A, because it has a higher frequency
took on connexus, it's correct.
How is the acceleration of a falling object calculated
Answer:
F=w=ma OR by using equations of motions vf=vi-at : a=vf-vi/t eq 1 s=vit+1/2at squre eq 2 2as=vf squre - vi squre eq 3
Explanation:
where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.
Need help solving this question.
(a) The magnitude of the angular momentum of the system is 5,252 kg m²/s.
(b) The rotational energy of the system is 2,826 J.
(c) The new moment of inertia is 31.25 Kgm².
(d) The new speed of each astronaut is 420.15 m/s.
(e) The new rotational energy of the system is 65.82 kJ.
(f) The work is done by the astronauts in shortening the rope -45,317,098 KJ.
(a) To calculate the magnitude of the angular momentum of the system, we can use the following equation:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Since we are treating the astronauts as particles, we can assume they are point masses and use the formula for the moment of inertia of a point mass:
I = mr²
where m is the mass of each astronaut and r is the distance between them. The angular velocity can be found from the linear velocity and the distance between the astronauts:
ω = v/r
Putting in the given values, we get:
r = 5.00 m
m = 90.5 kg
v = 5.80 m/s
I = 2(mr²) = 2(90.5 kg)(5.00 m)²
= 4,525 kg m²
ω = v/r = 5.80 m/s / 5.00 m
= 1.16 rad/s
L = Iω = (4,525 kg m²)(1.16 rad/s)
= 5,252 kg m²/s
Therefore, the magnitude of the angular momentum of the system is 5,252 kg m²/s.
(b) To calculate the rotational energy of the system, we can use the following equation:
E = (1/2)Iω²
Putting in the values for I and ω that we found in part (a), we get:
E = (1/2)(4,525 kg m²)(1.16 rad/s)²
= 2,826 J
Therefore, the rotational energy of the system is 2,826 J.
(c) When the distance between the astronauts is shortened to 5.00 m, the moment of inertia of the system changes. We can calculate the new moment of inertia using the parallel axis theorem:
I = Icm + md²
where Icm is the moment of inertia about the center of mass (which remains the same), m is the mass of each astronaut, and d is the distance between each astronaut and the center of mass (which is half the original distance, or 2.50 m).
The new moment of inertia is:
I = Icm + 2md²
= 2(m(2.50 m)²)
= 31.25 kg m²
Therefore the new moment of inertia is 31.25 Kgm².
(d) To find the new speeds of the astronauts, we can use the conservation of angular momentum:
L = Iω = L'
where L is the initial angular momentum (which we found in part (a)) and L' is the new angular momentum (which we can find using the new moment of inertia and the new distance between the astronauts, which is 5.00 m).
Solving for ω', we get:
ω' = L' / I = L / I'
Putting in the values, we get:
L' = L = 5,252 kg m²/s
I' = 31.25 kg m²
ω' = 5,252 kg m²/s / 31.25 kg m² = 168.06 rad/s
The new speed of each astronaut is the tangential velocity at a distance of 2.50 m from the center of mass, which can be found using the formula:
v = ω'r
where r is the distance from the center of mass. Putting in the values, we get:
v = 168.06 rad/s * 2.50 m = 420.15 m/s
Therefore, the new speed of each astronaut is 420.15 m/s.
(e) To find the new rotational energy of the system after the astronauts have shortened the rope to 5.00 m, we can use the conservation of angular momentum:
L = Iω
where L is the angular momentum of the system, I is the moment of inertia of the system, and ω is the angular speed of the system. Since the rope is assumed to have negligible mass, we can treat the system as two point masses moving in a circle around their center of mass. The moment of inertia of this system can be calculated as:
I = 2mr²/5
where m is the mass of each astronaut and r is the distance between them. Initially, the moment of inertia of the system is:
I = 2 * 90.5 kg * (10.0 m / 2)² / 5
= 3638 kg m²
The initial angular momentum of the system is:
L = Iω = 3638 kg m² * (5.80 m/s) / (10.0 m / 2)
= 4213.6 kg m²/s
After the astronauts have shortened the rope to 5.00 m, the moment of inertia of the system is:
I' = 2 * 90.5 kg * (5.00 m / 2)² / 5
= 1352.5 kg m²
Since the angular momentum of the system is conserved, the new angular speed of the system is:
ω' = L/I' = 4213.6 kg m²/s / 1352.5 kg m² = 3.115 rad/s
E' = (1/2)I'ω'² = (1/2) * 1352.5 kg m² * (3.115 rad/s)²
= 65,817.6 J
= 65.82 kJ
Therefore, the new rotational energy of the system is 65.82 kJ.
(f) The work done by the astronauts in shortening the rope is:
W = ∫F dl = (F' - F) ∫dl
= (6,043,064.25 N - 630.56 N) * (-7.50 m)
= -45,317,098 KJ
Therefore, the work is done by the astronauts in shortening the rope -45,317,098 KJ.
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You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answer:
C.) The book's inertia carried it forward.
The book was at rest on the bus seat and had a tendency to stay at rest due to its inertia. When the bus stopped suddenly, the seat and the book accelerated forward due to the force applied by the bus. However, the book still had the tendency to stay at rest due to its inertia. This means that the book remained at its initial position for a brief moment while the seat and the bus moved forward. As a result, the book slid off the seat and moved forward with the same acceleration as that of the bus. So, it was the book's inertia, i.e. the resistance to change in its state of rest, that caused it to slide forward.
Answer:
C) The book's inertia carried it forward.
An object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and direction, unless acted upon by an unbalanced force. In this case, the book was initially at rest on the seat, but when the bus stopped suddenly, the book's inertia kept it moving forward in the same direction and speed as the bus was moving before it stopped, causing it to slide off the seat.
Explanation:
Shown below is the PV-diagram for a clockwise cycle. Determine the work done during the cycle, the heat flow during the cycle, & the change in internal energy during the cycle.
The work done during the cycle, the heat flow during the cycle, & the change in internal energy during the cycle.
W = 19.63 J
Q = 19.63 J
ΔU = 0 J
How to calculate the work doneSince the cycle is clockwise, the system expands at higher pressure and contracts at lower pressure.
Hence, net work done will be positive.
Magnitude of work is given by the area bound by the PV diagram.
The PV curve makes a circle.
Radius of the circle (r) = 8.5 - 6 = 2.5
Area of circle = πr2 = π*2.52 = 19.63 J
Work done = 19.63 J
Again, since the process is cyclic, ΔU = 0 and hence,
l
Q = ΔU + W = 19.63 J
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HELP!!! WILL MARK BRAINLIEST
For this assignment you are going to make a “Report” on one source of natural radioactivity. Use the Internet, the library, or other resources to learn more about one natural source of radioactivity. As you do your research, look for answers to the following questions. State in your own words.
• What is the source of the radioactivity?
• What type of radiation does it produce?
• Is this source most common in any particular areas? If so, where?
• Is this radiation source dangerous to people? If so, who is at the highest risk of exposure? How can people protect themselves from the radiation?
• Do people use the radiation source for anything? If so, what?
Your report must include information on all references you use. You should consult at least three different sources to prepare your report.
One natural source of radioactivity is radon gas, which is produced from the decay of uranium in rocks and soil.
It emits alpha particles, which are stopped by a sheet of paper but can be dangerous if inhaled. Radon is most common in areas with high concentrations of uranium and can accumulate in poorly ventilated buildings, particularly in basements. Long-term exposure to radon is a significant cause of lung cancer, particularly among smokers.
To protect themselves, people can test their homes for radon levels and install mitigation systems if necessary. However, radon is also used in some medical treatments and as a tracer in scientific research. Sources for this report include the United States Environmental Protection Agency, the World Health Organization, and the National Cancer Institute.
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Drag the mass slider to give the skateboarder the largest mass possible. Drag and drop him on the three ramps, one at a time. Watch the kinetic energy bar as he travels down the ramps. Click the pause button right before he exits the ramp to freeze the action. Which ramp gives the skateboarder the greatest amount of kinetic energy? Which gives him the least? Now look at the speed dial. How does his speed relate to his kinetic energy?
1. Ramp 2. He gains the maximum kinetic energy from the steepest ramp.
2. Ramp 3 which is the flattest ramp should give him the least.
3. The greater his speed, the more kinetic energy he generates.
How is kinetic energy produced?
The simplest way to explain how kinetic energy is produced is; Motion produces kinetic energy. When there is some sort of movement, there is a likelihood of kinetic energy being produced.
Mechanical, thermal, electrical, and chemical energies can all produce kinetic energy.
For example, when Mechanical labor is done, a force acts on an item and causes it to move. This action then turns into kinetic energy.
Also, When an item is heated, the particles in it gain kinetic energy, raising its temperature.
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Answer:
The steepest ramp gives the greatest amount of kinetic energy. The flattest ramp gives the least amount of kinetic energy. The middle ramp is in between. As the skateboarder’s speed increases, so does his kinetic energy.
Explanation:
pluto
Find the vector whose magnitude is 36 and inclination is 60°.
The vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.
The inclination of a vector is the angle between the vector and a reference line. In this case, the reference line is the horizontal axis. Let the components be x and y. We know that the magnitude of the vector is 36, so,
magnitude = √(x² + y²) = 36
Squaring both sides of this equation, we get,
x² + y² = 1296
We also know that the inclination is 60°. The tangent of 60° is √(3), which is equal to the ratio of the vertical component to the horizontal component of the vector,
tan(60°) = y/x
y/x= √(3)
Multiplying both sides by x, we get,
y = √(3)x
Now we can substitute y in terms of x in the equation x² + y² = 1296,
x² + (√(3)x)² = 1296
Simplifying this equation, we get,
4x² = 1296
x² = 324
Taking the square root of both sides, we get,
x = +/- 18
Since the vector is making an angle of 60° with the horizontal, it must be in the first or fourth quadrant, where x is positive. Therefore, we take x = 18. Using y = √(3)x, we get,
y = sqrt(3)18
y = 18√(3)
So the vector is,
v = <18, 18√(3)>
Therefore, the vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.
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Which of the following best defines reversed polarity?
A. A daily fluctuation in true north.
B. A magnetic field aligned with the earth's present-day magnetic field.
C. A magnetic field aligned in the opposite direction as the earth's present-day magnetic
field.
D. A physical movement of the North Pole southward.
The statement which best describes reversed polarity is
A magnetic field aligned in the opposite direction as the earth's present-day magnetic field.
What is magnetic field?A magnetic field is described as a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.
On the other hand, reversed polarity is described as to a period in the Earth's history when the orientation of the Earth's magnetic field was the opposite of its present-day orientation.
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In an experiment two identical rocks are simultaneously thrown from the edge of a cliff a distance h0 above the ground. Rock A is thrown vertically upward with speed v0
and rock B is thrown vertically downward with speed v0. Rock A and rock B strike the ground at times tA and tB, respectively. Consider the positive vertical direction to be upward.
Question: Rock B hits the ground at time tB. Derive an equation for the time tA it takes rock A to hit the ground in terms of v0,tB, and physical constants, as appropriate.
Answer:
We can use the kinematic equations of motion to derive an equation for the time tA it takes rock A to hit the ground in terms of v0, tB, and physical constants. Since rock A is thrown vertically upward, we can use the equation:h = v0t - (1/2)gt^2where h is the initial height of the rock, v0 is the initial velocity, g is the acceleration due to gravity (9.8 m/s^2), and t is the time. When rock A hits the ground, its final height is zero. So we can set h = 0 and solve for t:0 = v0tA - (1/2)gtA^2tA = (2v0)/gThis is the equation for the time it takes rock A to hit the ground. It is in terms of v0 and g, which are physical constants, and does not explicitly involve tB. However, we can use the fact that rock B hits the ground at time tB to relate tB to tA. Since rock B is thrown vertically downward, we can use the same kinematic equation with a negative value for g:h = -v0t + (1/2)gt^2When rock B hits the ground, its final height is also zero, so we can set h = 0 and solve for tB:0 = -v0tB + (1/2)gtB^2tB = (2v0)/gThis equation is identical to the equation we derived for tA. Therefore, we can conclude that both rocks hit the ground at the same time, regardless of the direction in which they were thrown.Therefore, the equation for the time tA it takes rock A to hit the ground in terms of v0, tB, and physical constants is:tA = (2v0)/gwhere v0 is the initial velocity and g is the acceleration due to gravity.
Explanation:
The time it takes for rock A to hit the ground after being thrown upwards can be calculated using the equation tA = (v0 / g) + sqrt((v0 / g)^2 + 2h0 / g). By substituting the time it takes for rock B to hit the ground (tB), we receive tA = tB + sqrt((tB^2) + 2h0 / g) with g as the acceleration due to gravity.
Explanation:In Physics, the time it takes for an object to hit the ground after being thrown upwards may be calculated with the equation tA = (v0 / g) + sqrt((v0 / g)^2 + 2h0 / g), where 'g' is the acceleration due to gravity. This equation emerges from the relationship of time and displacement in free fall motion. 'v0' was the initial upwards velocity, 'h0' is the height of the cliff, and 'g' stands for gravitational acceleration which is a constant 9.8m/s².
The time that it takes rock B (which was thrown downwards) to hit the ground may be calculated from the equation, tB = sqrt((2h0) / g). Knowing that tA equals tB, we can substitute tB into the equation for tA, which results in tA = tB + sqrt((tB^2) + 2h0 / g).
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