A rectangular duct has a cross-section with a width of 2ft and a length of 3.5ft. Determine the hydraulic radius. a.0.12 ft b.0.64 ft c.0.16 ft d.0.48 ft

Answers

Answer 1

A rectangular duct has a cross-section that is 2 feet wide and 3.5 feet long. Therefore, the hydraulic radius of the rectangular duct is approximately 0.64 ft. The correct option is b.0.64 ft.

The hydraulic radius of a rectangular duct can be calculated using the formula:

Hydraulic radius = (Cross-sectional area) / (Wetted perimeter)

The cross-sectional area of a rectangular duct is determined by multiplying its width (w) by its length (L):

Cross-sectional area = w × L = 2 ft × 3.5 ft = 7 ft²

The wetted perimeter of a rectangular duct can be found by summing up the lengths of all four sides:

Wetted perimeter = 2w + 2L = 2(2 ft) + 2(3.5 ft) = 4 ft + 7 ft = 11 ft

Now, we can calculate the hydraulic radius:

Hydraulic radius = Cross-sectional area / Wetted perimeter = 7 ft² / 11 ft = 0.636 ft

Rounding to two decimal places, the hydraulic radius of the rectangular duct is approximately 0.64 ft.

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Related Questions

To remove a 2.4 GHz interference from a 1 GHz signal, which one of the following is the best choice of filtering technique? a. A low pass filter with 100 MHz cutoff frequency. b. A high pass filter with 0.5 GHz cutoff frequency.
c. A low pass filter with 1.6 GHz cutoff frequency. d. A high pass filter with 10 GHz cutoff frequency.
Why

Answers

The best choice of filtering technique to remove a 2.4 GHz interference from a 1 GHz signal is a low pass filter with a 1.6 GHz cutoff frequency.

In order to remove interference at 2.4 GHz from a 1 GHz signal, a filter with a cutoff frequency lower than 2.4 GHz needs to be employed. A low pass filter is designed to allow frequencies below its cutoff frequency to pass through while attenuating higher frequencies. Among the given options, a low pass filter with a 1.6 GHz cutoff frequency (option c) is the most appropriate choice.

Option a, a low pass filter with a 100 MHz cutoff frequency, would not be effective in removing the 2.4 GHz interference as it is significantly lower than the interfering frequency.

Option b, a high pass filter with a 0.5 GHz cutoff frequency, would not be suitable because it allows frequencies higher than 0.5 GHz to pass through, including the interfering 2.4 GHz signal.

Option d, a high pass filter with a 10 GHz cutoff frequency, would not be effective either, as it allows frequencies above 10 GHz to pass through, including the interfering 2.4 GHz signal.

Therefore, option c, a low pass filter with a 1.6 GHz cutoff frequency, is the best choice for effectively filtering out the 2.4 GHz interference from the 1 GHz signal.

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8. Instrument measure dose rate Only is ionization chamber: true false

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The statement "Instrument measure dose rate only is ionization chamber" is False.

An ionization chamber is a radiation detector that detects radiation intensity and determines the strength of radiation in various applications and industries. A detector works by measuring the ionization produced by the radiation when it passes through a gas or liquid, which is where the device's name comes from.

Instrument measure dose rate only is an incorrect statement as an ionization chamber is an instrument that measures the ionization produced by the radiation when it passes through a gas or liquid.

In conclusion, the statement "Instrument measure dose rate only is ionization chamber" is False.

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a 0.020 g plastic bead hangs from a lightweight thread. another bead is fixed in position beneath the point where the thread is lied. if both beads have charge q. the moveable bead swings out lo the position shown in figure p20.62. what is q?

Answers

The charge on the beads is `2.29×10^-8 C`. Hence, the correct option is (B) `2.29×10^-8 C`.

We have given the following figure: Figure P20.62 Here, we can observe that the plastic bead is hanging with a lightweight thread while another bead is fixed at a point beneath the thread. We are to determine the charge of the beads.Let's begin the solution; The situation described in the question is that of an electric dipole. We can use the electric dipole formula to find the charge of the beads.

The electric dipole formula is given as;`p=qd`Where p is the electric dipole moment, q is the charge on the bead, and d is the distance between the two beads (fixed and moveable). The value of p can also be written as;p=k*Q*q/d²where k is Coulomb's constant, Q is the charge on the fixed bead, and d is the distance between the two beads.Now, we can find the value of q as;`q=p/d= k*Q*q/d³`Here, we have two unknowns, Q and q. Therefore, we need another equation to solve for both Q and q.Let's look at the forces acting on the moveable bead. We can see that there are two forces acting on the bead. One is the force due to gravity, which is acting vertically downwards, and the other is the force due to the electric field, which is acting horizontally towards the fixed bead.

These two forces are in equilibrium, so the net force on the bead is zero. Let's write the expression for the electric force on the bead due to the fixed bead;`Fe=k*q*Q/d²`This force is acting horizontally, towards the fixed bead. We can write the horizontal component of this force as;`Fh=k*q*Q/d² * cos(theta)`where theta is the angle between the horizontal and the line joining the two beads.We can see from the figure that this angle is equal to 60°. Therefore, we have;`Fh=k*q*Q/d² * cos(60°)`We also know that this force is balanced by the component of the weight of the bead along the horizontal direction.

This weight is given by;`Fw=mg*sin(theta)`where m is the mass of the bead and g is the acceleration due to gravity. Substituting the values, we get;`Fw=0.020*9.8*sin(60°)` `Fw=0.102 N`Since the net force is zero, we can equate the two forces;`Fh=Fw``k*q*Q/d² * cos(60°)=0.102` `k*q*Q/d²=0.102/cos(60°)`Substituting the values of k, q, Q, and d, we get;`9×10^9 * q² / 0.025=0.102/0.5`Solving for q, we get;`q=2.29×10^-8 C`

Therefore, the charge on the beads is `2.29×10^-8 C`. Hence, the correct option is (B) `2.29×10^-8 C`.

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An aluminium alloy strut of length L = 3.8 m with a circular cross-section of radius 86 mm is subjected to a compressive load acting through its longitudinal axis. The alloy has Young's Modulus E- 70 GPa and yield strength OYS = 193 MPa. The strut is built-in at its two ends. Calculate the buckling stress on the basis of Rankine-Gordon theory. Give your result in MPa to one decimal place.

Answers

The buckling stress on the basis of Rankine-Gordon theory for the given aluminum alloy strut is approximately 1.012 MPa.

To calculate the buckling stress of the aluminum alloy strut using Rankine-Gordon theory, we need to consider the Euler buckling formula. The formula is given by:

σ_b = (π² * E * I) / (L²)

Where:

σ_b is the buckling stress,

E is the Young's modulus of the material,

I is the area moment of inertia of the cross-section, and

L is the length of the strut.

First, we need to calculate the area moment of inertia (I) for the circular cross-section. For a circular cross-section, the area moment of inertia can be calculated as:

I = (π * r⁴) / 4

Where r is the radius of the circular cross-section.

Given:

Length (L) = 3.8 m

Radius (r) = 86 mm = 0.086 m

Young's Modulus (E) = 70 GPa = 70 * 10⁹ Pa

Calculating the area moment of inertia (I):

I = (π * (0.086 m)⁴) / 4

Now we can substitute the values into the Euler buckling formula to calculate the buckling stress (σ_b):

σ_b = (π² * (70 * 10⁹ Pa) * [(π * (0.086 m)⁴) / 4]) / (3.8 m)²

To calculate the buckling stress of the aluminum alloy strut using the Rankine-Gordon theory, we can substitute the given values into the formula:

σ_b = (π² * E * I) / L²

where:

E = 70 GPa = 70 * 10⁹ Pa (Young's Modulus)

I = (π * (0.086 m)⁴) / 4 (area moment of inertia)

L = 3.8 m (length of the strut)

Calculating the area moment of inertia (I):

I = (π * (0.086 m)⁴) / 4

Substituting the values into the formula:

σ_b = (π² * (70 * 10⁹ Pa) * [(π * (0.086 m)⁴) / 4]) / (3.8 m)²

Evaluating the expression gives:

σ_b = 1.012 MPa (approximately)

Therefore, the buckling stress on the basis of Rankine-Gordon theory for the given aluminum alloy strut is approximately 1.012 MPa.

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Write a code section in MATLAB that performs the following tasks: 1. Reads a statement from the user (hint: use input with 's'). 5 pts 2. Store the letters of the statement into a cell array (Hint: you better use a dedicated function for storing the letters). 5 pts 3. Show the demo of your execution of your code and submit it along with your homework.

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MATLAB code section that performs the tasks you mentioned:

```matlab

% Task 1: Read a statement from the user

statement = input('Enter a statement: ', 's');

% Task 2: Store the letters of the statement into a cell array

letters = cellstr(num2cell(statement));

% Task 3: Display the cell array

disp(letters);

```

This code prompts the user to enter a statement, stores the statement's letters into a cell array using the `cellstr` and `num2cell` functions, and finally displays the contents of the cell array using the `disp` function.

To run this code, simply copy and paste it into a MATLAB script or function file, and execute the script or function. You can then enter a statement and see the letters stored in the cell array.

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Within the same time interval, which of the following motions gives the largest average acceleration? Group of answer choices Making a 90° left turn with constant speed Making a 180° U-turn with constant speed Making a 360° turn with constant speed Making a 90° right turn with constant speed All of the above give the same average acceleration.

Answers

The correct answer is: All of the above give the same average acceleration.

When an object undergoes circular motion at a constant speed, the magnitude of its average acceleration is given by the formula:

Average acceleration = (Change in velocity) / (Time taken)

In all the mentioned motions, the change in velocity is the same because the speed is constant. The only difference between the motions is the change in direction, which is given by the angle of turn.

However, when considering the average acceleration, the direction of the acceleration doesn't matter; only the magnitude is considered. Therefore, the motions of making a 90° left turn, making a 180° U-turn, making a 360° turn, and making a 90° right turn with constant speed will all have the same average acceleration.

So, the correct answer is: All of the above give the same average acceleration.

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Operating VFD controlled motors at speeds higher than base speed delivers what kind of torque?
a. Constant b. Variable c. Greater d. Less
Besides frequency, what other quantity does a VFD modify to control a motor?
a. Torque b. Current c. Voltage d. Inductance

Answers

a)The torque delivered by the motor is dependent on the speed at which it is operating.

b)The voltage is typically adjusted in proportion to the frequency to maintain a constant volts-per-hertz ratio, which is important for motor performance and efficiency.

a. Variable

When operating VFD (Variable Frequency Drive) controlled motors at speeds higher than the base speed, the delivered torque is variable.

The torque delivered by the motor is dependent on the speed at which it is operating. As the speed increases above the base speed, the torque delivered by the motor decreases.

b. Voltage

Besides frequency, a VFD also modifies the voltage to control a motor. By adjusting the voltage and frequency provided to the motor, the VFD can control the speed and torque output of the motor.

The voltage is typically adjusted in proportion to the frequency to maintain a constant volts-per-hertz ratio, which is important for motor performance and efficiency.

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The water pressure at the base of a water tower is 100.5 psi. What is the head of water?

Answers

The head of water can be determined by calculating the pressure of the water at the base of a water tower. The water pressure at the base of a water tower is 100.5 psi. Therefore, the head of water is 232.8 feet.

Water pressure is the pressure of water in a system. This pressure can be determined using a formula. A water tower is a storage tank that supplies water to a community. Water towers are tall structures that hold water and provide pressure for the water to flow through pipes into homes and businesses. The water pressure at the base of a water tower is determined by the height of the water in the tower.

The head of water is the height of water in a tank or water tower. The head of water can be determined by calculating the pressure of the water at the base of a water tower. The formula for calculating the head of water is:H = (P/0.433)where H is the head of water, P is the water pressure in psi, and 0.433 is a constant that converts psi to feet of water. Using this formula, the head of water can be calculated as:H = (100.5/0.433)H = 232.8 feet.

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You'll use the Drake Equation to work out the number of
technologically advanced civilizations in the Milky Way.

Answers

the Drake Equation provides an estimate based on our current understanding and assumptions, and it does not provide a definitive answer to the number of technologically advanced civilizations in the Milky Way.

The Drake Equation is a formula developed by Dr. Frank Drake to estimate the number of technologically advanced civilizations that could exist in our galaxy, the Milky Way. The equation takes into account several factors that influence the likelihood of the existence of such civilizations. However, it is important to note that the Drake Equation is speculative and relies on various assumptions, resulting in a wide range of possible values.

The Drake Equation is expressed as:

N = R* × [tex]fp[/tex]× ne × [tex]fl[/tex]× fi × fc × L

Where:

N = The number of civilizations in our galaxy that could communicate with us

R* = The average rate of star formation in our galaxy

[tex]fp[/tex] = The fraction of those stars that have planets

ne = The average number of planets that could support life per star with planets

[tex]fl[/tex] = The fraction of those planets where life actually develops

fi = The fraction of life that evolves into intelligent civilizations

fc = The fraction of civilizations that develop technology capable of communication

L = The length of time such civilizations release detectable signals into space

Each factor in the equation represents a different aspect of the probability of the existence of technologically advanced civilizations. However, since we do not have precise values for many of these factors, the equation is often used as a tool for discussion rather than providing a definitive answer.

To calculate an estimate of N, you would need to assign values or ranges to each of the factors in the equation based on scientific knowledge and informed assumptions. However, due to the speculative nature of the equation, different researchers may use different values, leading to a wide range of possible outcomes.

the Drake Equation provides an estimate based on our current understanding and assumptions, and it does not provide a definitive answer to the number of technologically advanced civilizations in the Milky Way.

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a pilot whose aircraft enters a horizontal turn with a velocity vi=(650;711)m/s and 20s later leaves the turn with a velocity of vf=(-650;-711)m/s what is its linar speed, period, net acceleration and frequecy

Answers

The aircraft's linear speed is  969.35 m/s, the period is 20 seconds, the net acceleration is (-65; -72.2) m/s², and the frequency is 0.05 Hz.

To find the linear speed, period, net acceleration, and frequency of the aircraft during the turn, we can use the given initial and final velocities and the time it takes to complete the turn.

Linear Speed:

The linear speed is the magnitude of the velocity vector. We can find it by taking the magnitude of either the initial or final velocity. Linear speed (v) = √(vx^2 + vy^2), where vx and vy are the x and y components of the velocity vector.

Given:

vi = (650; 711) m/s

vf = (-650; -711) m/s

Using the formula, we can calculate the linear speed:

v = √((-650)^2 + (-711)^2) ≈ 969.35 m/s

Period:

The period (T) of the turn is the time it takes for the aircraft to complete one revolution. In this case, it is given as 20 seconds.

T = 20 s

Net Acceleration:

The net acceleration (a) of the aircraft is the change in velocity divided by the time taken. It can be calculated as a = (vf - vi) / t, where vf and vi are the final and initial velocities, and t is the time taken.

Given:

t = 20 s

Using the formula, we can calculate the net acceleration:

a = (vf - vi) / t = [(-650; -711) - (650; 711)] / 20 ≈ (-65; -72.2) m/s²

Frequency:

The frequency (f) is the reciprocal of the period, which represents the number of complete cycles per unit time. It can be calculated as f = 1 / T.

Using the given period, we can calculate the frequency:

f = 1 / T = 1 / 20 = 0.05 Hz

Therefore, the aircraft's linear speed is approximately 969.35 m/s, the period is 20 seconds, the net acceleration is approximately (-65; -72.2) m/s², and the frequency is 0.05 Hz.

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a mass m attached to an ideal spring of spring constant k oscillates in shm with a period t . suppose the spring constant is doubled. what is the missing value in the equation below? tnew=__told

Answers

A mass m attached to an ideal spring of spring constant k oscillates in shm with a period t tnew = √2 * told.

We may use the following equation for the period of simple harmonic motion (SHM) to get the new period (tnew) when the spring constant is doubled:

t = 2π * √(m/k)

tnew = 2π * √(m/(2k))

tnew = 2π * √(m/2k) * √(2/2)

tnew = 2π * √(m/2k) * √(1/2)

tnew = π * √(m/k) * √(1/2)

So, as per this equation,

tnew = told / √2

Therefore, the missing value in the equation is √2, and the equation becomes: tnew = √2 * told.

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) Prove that the average power absorbed by a pure capacitor is zero. [6] (b) An AC circuit is composed of a series connection of a resistor with resistance 2.5ohm a coil with inductance 0.06H and a capacitor with capacitance 6.8 micro-farad. The circuit is connected to an AC voltage supply of 230V,50 Hz. Determine I. Impedance II. Current III. Phase angle between voltage and current IV. Power Factor V. Power consumed [

Answers

(a) Proving that the average power absorbed by a pure capacitor is zero.The average power absorbed by a pure capacitor is zero, which can be proved by using the concept of instantaneous power and integrating over a complete cycle.

Let the voltage across the capacitor be V. Then the instantaneous power absorbed by the capacitor is given by P=V²Cωsin(ωt)

where C is the capacitance of the capacitor, ω is the angular frequency of the voltage, and t is the time. The instantaneous power is positive during the first quarter of the cycle, where the current leads the voltage, and negative during the second quarter of the cycle, where the current lags the voltage. The positive and negative powers are equal in magnitude, so the average power over one complete cycle is zero, which means that the capacitor does not dissipate any power. Therefore, the average power absorbed by a pure capacitor is zero.

(b) AC circuit with a resistor, an inductor, and a capacitor We have, Resistance, R = 2.5Ω

Inductance, L = 0.06H

Capacitance, C = 6.8μ

F = 6.8×10⁻⁶F

Voltage, V = 230V

Frequency, f = 50Hz

Angular frequency, ω = 2πf = 2π×50 = 100π

Impedance, Z = R + j(XL - XC)

where XL = ωL is the inductive reactance and XC = 1/ωC is the capacitive reactance

[tex]Z = 2.5 + j(100 \pi \times 0.06 - \frac{1}{100 \pi \times 6.8 \times 10^{-6}}) = 2.5 + j94.5 \Omega[/tex]

The magnitude of the impedance is Z = |Z| = √(2.5² + 94.5²)Z = 94.8Ω

The current is given by I = V/ZI = 230/94.8I = 2.42A

The phase angle between the voltage and current is given by

[tex]\tan^{-1} \left[ \frac{X_L - X_C}{R} \right] \\\\= \tan^{-1} \left[ \frac{100 \pi \times 0.06 - \frac{1}{100 \pi \times 6.8 \times 10^{-6}}}{2.5} \right] \\\\\\= \tan^{-1} \left( \frac{94.5}{2.5} \right) \\\\= \tan^{-1} (37.8) \\\\= 86.87^\circ\\[/tex]

The power factor is given by PF = cosθPF = cos(86.87°)PF = 0.045

The power consumed is given by

P = VI cosθP = 230×2.42×cos(86.87°)

P = 12.6W

Therefore, the required values are,I. Impedance, Z = 94.8ΩII. Current, I = 2.42AIII. Phase angle between voltage and current, θ = 86.87°IV. Power factor, PF = 0.045V. Power consumed, P = 12.6W

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What is the most proper management for disposal of toxic waste
for Pasir Gudang Chemical Toxic waste incident? is there any
reference or figure/diagram to be refer to?

Answers

The Pasir Gudang Chemical Toxic Waste Incident that occurred in March 2019 was a significant environmental disaster in Malaysia. As a result, proper management of toxic waste is critical to avoid any reoccurrence in the future. Toxic waste is harmful, and it must be handled and disposed of appropriately.

Proper management of toxic waste disposal can be achieved by using the following strategies:

1. Source Reduction can be achieved by reducing the amount of toxic waste produced by an organization. This can be achieved by employing eco-friendly products and practices, such as reducing waste during production processes.

2. Recycling Recycling involves reusing toxic waste for another purpose. For example, plastic waste can be recycled to make other products like clothing, toys, and bags.

3. IncinerationIncineration involves burning toxic waste at high temperatures to turn it into ash, gas, or steam. This is an effective disposal method because it destroys the toxic components in the waste.

4. LandfillsLandfills are facilities designed to store waste in a designated location. Toxic waste can be disposed of safely in a landfill. This method is effective when other methods like incineration and recycling have been exhausted. The landfill should be secure, lined with an impermeable material to prevent contamination of the surrounding soil and groundwater.

A reference document for toxic waste management in Malaysia can be found on the Malaysian Department of Environment (DOE) website. The document provides guidelines and regulations on waste management in Malaysia and can be helpful in developing an effective toxic waste management plan. Unfortunately, there are no figures or diagrams provided.

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A small bulb is rated at 7.5 W when operated at 125 V. The tungsten filament has a temperature coefficient of resistivity a=4.5x 10/°C. When the filament is hot and glowing. its temperature is 140 °C. What is the resistance of the filament (in ohms) at room temperature? a. 1280 b. 1350 c. 1911 d. 4530 e. 5630

Answers

The resistance of the tungsten filament at room temperature is approximately 1280 ohmshe correct option is a.

To find the resistance of the tungsten filament at room temperature, we can use the concept of temperature coefficient of resistivity.

The formula to calculate the change in resistance due to temperature is given by:

ΔR = R0 * α * ΔT

Where:

ΔR is the change in resistance,

R0 is the initial resistance at a reference temperature,

α is the temperature coefficient of resistivity,

ΔT is the change in temperature.

In this case, we are given the following values:

R0 = resistance at room temperature (unknown),

α = 4.5 x 10^-3 °C^-1 (temperature coefficient of resistivity),

ΔT = (temperature at hot state) - (room temperature) = 140°C - 25°C = 115°C.

We can rearrange the formula to solve for R0:

ΔR = R0 * α * ΔT

R0 = ΔR / (α * ΔT)

The change in resistance (ΔR) can be calculated using the power formula:

P = V^2 / R

Since the bulb is rated at 7.5 W and operated at 125 V, we can find the initial resistance (R0) using:

7.5 = 125^2 / R0

R0 = 125^2 / 7.5

Substituting the values into the formula for R0:

R0 = (125^2 / 7.5) / (4.5 x 10^-3 °C^-1 * 115°C)

Calculating this expression gives us:

R0 ≈ 1280 ohms

Therefore, the resistance of the tungsten filament at room temperature is approximately 1280 ohms. Hence, the correct option is (a) 1280.

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What is the approximate behavior of... (a) an inductor at steady state connected to a DC source? open short neither (b) an inductor when a DC source is initially switched on? open short neither (c) a capacitor at steady state connected to a DC source? open short neither (d) a capacitor when a DC source is initially switched on? open short neither BONUS Describe the behavior of an ideal transformer with one port connected to a DC source, when the system is at steady state.

Answers

(a) The inductor behaves like an open circuit, allowing no current to pass through it.

(b) the inductor will try to oppose the sudden increase in current by behaving like a short circuit.

(c)  it behaves like an open circuit, preventing the flow of any current.

(d) capacitor will allow the sudden flow of current by behaving like a short circuit.

(a) The behavior of an inductor at steady-state connected to a DC source is open. An inductor is essentially a coil of wire, and as current flows through the inductor, it creates a magnetic field. The inductor tries to resist any change in the current flowing through it, and this is why it is said to have an open behavior.  

At steady-state, the current flowing through the inductor does not change, and therefore the inductor behaves like an open circuit, allowing no current to pass through it.

(b) When a DC source is initially switched on, an inductor behaves like a short circuit. This happens because initially, the inductor has no current flowing through it. Therefore, it has no magnetic field, and so there is no back-EMF (Electromotive Force) opposing the change in current.

As such, the inductor will try to oppose the sudden increase in current by behaving like a short circuit.

(c) The behavior of a capacitor at steady-state connected to a DC source is an open circuit. A capacitor consists of two conductive plates separated by an insulating material. When a voltage is applied to the capacitor, the plates become charged, and this creates an electric field between them.

At steady-state, the capacitor becomes fully charged, and there is no current flowing through it, so it behaves like an open circuit, preventing the flow of any current.

(d) When a DC source is initially switched on, a capacitor behaves like a short circuit. This happens because initially, the capacitor has no charge on it. Therefore, it has no electric field, and so there is no voltage across it.

As such, the capacitor will allow the sudden flow of current by behaving like a short circuit.

An ideal transformer is one in which there are no losses due to resistance, hysteresis, or eddy currents. Therefore, when one port of an ideal transformer is connected to a DC source, there is no alternating current flowing through the primary winding. As such, there is no change in the magnetic field of the transformer, and no EMF is generated in the secondary winding.

Therefore, there is no current flowing through the DC source, and it behaves like an open circuit.

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If two charged particles attract each other, what happens to the force between them if the distance is suddenly tripled and the charge of both of them is also tripled? a. The force is tripled b. The force is is 3/9 the original force c. The force is unchanged d. The force is divided by three

Answers

When two charged particles attract each other, the force between them is determined by Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

If the distance between the particles is suddenly tripled, the force between them will decrease. This is because the force is inversely proportional to the square of the distance. When the distance is tripled, the denominator in the equation becomes nine times larger, resulting in a smaller force. Mathematically, the force becomes 1/9 (1/3^2) of its original value.

On the other hand, if the charge of both particles is also tripled, the force between them will increase. This is because the force is directly proportional to the product of the charges. When the charges are tripled, the numerator in the equation becomes three times larger, resulting in a stronger force.

Considering both changes simultaneously, we need to multiply the effects. The force will be (1/9) * 3 = 1/3 of the original force. In other words, the force is divided by three.

Therefore, the correct answer is d. The force is divided by three when the distance between the particles is tripled and the charge of both particles is also tripled. This can be explained by the combined effect of the inverse square relationship between distance and force, and the direct relationship between charge and force in Coulomb's law.

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In the experiment of standing waves of microwaves, if the initial position of the receiver was L₁ = 60 cm and the final position of the receiver was L= 95.6 cm and between initial position and final position we counted 20 minima. What is the wavelength of the microwaves (in cm)? A-1.26 B-1.56 C-2.56 D-3.06 E- 3.56

Answers

Wavelength is a fundamental concept in physics that refers to the distance between two consecutive points in a wave that is in phase or has the same phase. The correct answer is option E.

In simpler terms, the wavelength is the length of one complete cycle of a wave. It is commonly measured as the distance from one peak (crest) to the next, or from one trough to the next in the case of a transverse wave. In the case of a longitudinal wave, such as sound waves, it is the distance between two compressions or two rarefactions.

To determine the wavelength of the microwaves in the experiment of standing waves, we can use the formula:

[tex]wavelength = 2 * (L - L_1) / n[/tex]

where L and L₁ are the final and initial positions of the receiver, respectively, and n is the number of minima (or nodes) counted between the two positions.

Substituting the values into the formula:

[tex]L = 95.6 cm\\L_1 = 60 cm\\n = 20\\wavelength = 2 * (95.6 - 60) / 20\\= 2 * 35.6 cm / 20\\= 3.56 cm[/tex]

Therefore, the wavelength of the microwaves in this experiment is 3.56 cm. The correct answer is option E.

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Under what conditions do Bose-Einstein and Fermi-Dirac distributions approach Maxwell-Boltzmann distribution? Explain

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The Bose-Einstein and Fermi-Dirac distributions approach the Maxwell-Boltzmann distribution under conditions of high temperature or low density.

The Bose-Einstein and Fermi-Dirac distributions describe the statistical behavior of particles with integer and half-integer spins, respectively. These distributions account for the quantum mechanical nature of particles and are applicable in situations where quantum effects dominate.

At high temperatures or low densities, the quantum effects become less significant, and the behavior of particles approaches classical statistics. In this regime, the Maxwell-Boltzmann distribution is a good approximation for describing the statistical behavior of particles.

The Maxwell-Boltzmann distribution is derived from classical statistical mechanics and applies to distinguishable particles, ignoring any quantum effects. It describes the distribution of particles in thermal equilibrium, where the energy levels are continuous.

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A particle of mass 2 kg is being held in equilibrium on a smooth slope by a horizontal force, P, and a light, elastic spring. The spring has modulus of elasticity 10 N and is attached to the particle and also to the slope 1.5 m up the slope from the particle. If the slope is inclined at 25 ∘ , and the force P is of magnitude 5 N, find the two possible natural lengths of the spring.

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The negative value of l2 is not possible since it represents a length in the opposite direction to the displacement of the spring from its original length. Therefore, the two possible natural lengths of the spring are 10.01575 m (approx) and 0.

Given, the mass of the particle m = 2 kg

Modulus of elasticity of the spring k = 10 N

Horizontal force applied on the particle P = 5 N

The inclination of the slope from the horizontal θ = 25°

Let the natural length of the spring be l.

Now, the particle is at rest, therefore the forces acting on the particle are balanced horizontally as well as vertically.

∑F = 0⇒ Pcosθ - k(l - l0) = 0....(i)

Here, Pcosθ is the horizontal component of the force P, acting on the particle, in the direction of the slope.k(l - l0) is the extension in the spring due to the mass of the particle and it acts vertically upwards.

Let x be the distance of the point of attachment of the spring on the slope from the particle along the slope.Then, x = lsinθ and l - x = lcosθIn a similar triangle as shown below;sinθ = h/l and cosθ = x/lwhere h is the vertical distance of the particle from the point of attachment of the spring on the slope. h = (l - x)tanθSubstituting the values of h, x, sinθ, and cosθ in equation (i) above, we get

Plcosθ - k(l - l0) = 0⇒ Pl(lcosθ/l) - k(l - l0)

= l0

Now, the two possible natural lengths of the spring are:l1 = l0 + 0.5(2)gl2 = l0 - 0.5(2)g where g is the acceleration due to gravity, g = 9.8 m/s²

Substituting the value of l0, we get:

l1 = 1.01575 + 19.6/2

= 10.01575 m (approx)l2

= 1.01575 - 19.6/2

= -8.58425 m (approx)

The negative value of l2 is not possible since it represents a length in the opposite direction to the displacement of the spring from its original length. Therefore, the two possible natural lengths of the spring are 10.01575 m (approx) and 0.

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force, weight: what is the weight of a person on the moon (look up g for the moon in m/s2) if the mass of the person on the earth is 105 lbm? remember to first convert from lbm to kg.

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The weight of a person on the moon given that the mass of the person on Earth is 105 lbm is 17.3 lbf.

Force is defined as the influence that produces a change in motion of an object. The unit of force is newton (N), which is defined as the amount of force that can accelerate a mass of 1 kg at a rate of 1 meter per second squared (m/s²).

The weight of an object is the gravitational force acting on the object. It is directly proportional to the mass of the object and the acceleration due to gravity. The unit of weight is newton (N).

Formula to calculate weight:

Weight (N) = mass (kg) × acceleration due to gravity (m/s²)

Conversion from lbm to kg:1 lbm = 0.453592 kg

Acceleration due to gravity on the moon is 1.622 m/s².

Therefore, Weight (N) = mass (kg) × acceleration due to gravity (m/s²)

Weight on Earth = 105 lbm

= 47.63 kg

Weight on Moon = 47.63 × 1.622

Weight on Moon = 77.19 N

= 17.3 lbf

Therefore, the weight of a person on the moon given that the mass of the person on Earth is 105 lbm is 17.3 lbf.

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describe hypothesis, procedure, and predicted resultd of a possible experiment that you could do using the sensor equipment that you used

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Experiment: Investigating the Effect of Light Intensity on Photosynthesis Rate in Plants

Hypothesis:

The hypothesis for this experiment is that increasing light intensity will result in an increase in the rate of photosynthesis in plants.

Procedure:

Set up a controlled environment with potted plants of the same species and similar size.

Divide the plants into different groups, each exposed to a different light intensity. This can be achieved by adjusting the distance between the light source and the plants or by using light filters to modify the intensity.

Use a light sensor to measure the light intensity in each group. Ensure that the sensor is calibrated and positioned at the same height as the plants.

Begin the experiment by exposing the plants to their respective light intensities for a specified period of time.

During the experiment, record the light intensity readings from the sensor at regular intervals.

Measure the rate of photosynthesis by monitoring the production of oxygen or the consumption of carbon dioxide. This can be done by using gas sensors or by analyzing the changes in gas concentrations in a closed system.

Repeat the experiment multiple times to ensure accuracy and reliability of the results.

Analyze the data collected, taking into consideration the light intensity and photosynthesis rate for each group.

Predicted Results:

Based on the hypothesis, it is expected that as the light intensity increases, the rate of photosynthesis will also increase. This relationship is due to the fact that light is a key factor in the process of photosynthesis, providing the energy needed for the conversion of carbon dioxide and water into glucose and oxygen. Therefore, it is predicted that the group exposed to the highest light intensity will exhibit the highest rate of photosynthesis, while the group with the lowest light intensity will have the lowest rate.

The experiment will provide valuable insights into the relationship between light intensity and the rate of photosynthesis in plants. If the hypothesis is supported by the data, it would suggest that increasing light intensity can enhance the photosynthetic activity of plants. This information could be useful in optimizing plant growth in various settings, such as agricultural practices or indoor gardening. However, if the results contradict the hypothesis, further investigation would be necessary to identify other factors that may be influencing photosynthesis.

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If the frequency of a radiation is 600,000 Hz, what is the wavelength ? (Note that c=1 x f) c= 300,000,000 (m/sec); 1= wavelength (m); f= Frequency (Hz)

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Therefore, the wavelength of a radiation with frequency 600,000 Hz is 500 meters.

Given the frequency of a radiation is 600,000 Hz, we need to find the wavelength.

The formula that relates wavelength, speed of light and frequency is given by c= ƛ × f, where c is the speed of light, ƛ is the wavelength, and f is the frequency.

Substituting the given values into the formula,

c= 300,000,000 m/sec,

f= 600,000 Hz

The formula for calculating wavelength is given by ƛ = c/f

So, the wavelength is:

ƛ = c/f

= 300,000,000/600,000

= 500 meters

The wavelength of a radiation and its frequency are important properties that are interdependent.

The wavelength is the distance between two consecutive crests or troughs of a wave.

The frequency of a wave, on the other hand, is the number of cycles that occur in one second, measured in hertz (Hz).

The speed of light, which is the constant at which electromagnetic waves travel in a vacuum, is equal to the product of wavelength and frequency.

Therefore, the wavelength and frequency of an electromagnetic wave are inversely proportional to each other.

This means that the shorter the wavelength, the higher the frequency, and vice versa.

In the case of the given problem, the frequency of the radiation is 600,000 Hz, and the speed of light is 300,000,000 m/s. Substituting these values in the formula, we get the wavelength as 500 m.

This means that the radiation with a frequency of 600,000 Hz has a relatively long wavelength.

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You are standing at the side of some train tracks. A train is heading away from you at a rate of 8 m/s. The train whistle has a frequency of 3500 Hz. What frequency of sound do you hear from the train whistle? (Use speed of sound =343 m/s ) Some of the choices below are very close in value so be as precise as possible and careful about picking the one closest to your answer. a. 3584 Hz
b. 3417 Hz c. 3581 Hz d. 3420 Hz

Answers

The frequency of sound you hear from the train whistle is approximately 3417 Hz. To determine the frequency of sound you hear from the train whistle, we can use the concept of Doppler effect. The Doppler effect relates the observed frequency of a wave to the relative motion between the source of the wave and the observer.

The formula for the observed frequency (f') due to the Doppler effect is given by:

f' = f * (v + v₀) / (v + vₛ)

where f is the emitted frequency, v is the speed of sound, v₀ is the velocity of the observer, and vₛ is the velocity of the source.

In this case, the train is moving away from you, so the velocity of the observer (v₀) is 0 m/s. The velocity of the source (vₛ) is given as 8 m/s. The speed of sound (v) is 343 m/s. The emitted frequency (f) of the train whistle is 3500 Hz.

Substituting these values into the formula:

f' = 3500 Hz * (343 m/s + 0 m/s) / (343 m/s + 8 m/s)

f' = 3500 Hz * 343 m/s / 351 m/s

f' ≈ 3417 Hz

Therefore, the frequency of sound you hear from the train whistle is approximately 3417 Hz.

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Does a prediction value of y = 1082 cm agree well with a measurement value of y = 101 ± 1 cm?
True
False

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Does a prediction value of y = 1082 cm agree well with a measurement value of y = 101 ± 1 cm. This is False.

A prediction value of y = 1082 cm does not agree well with a measurement value of y = 101 ± 1 cm.

The measurement value has an uncertainty of ±1 cm, indicating that the actual value of y could be anywhere between 100 cm and 102 cm.

The prediction value of y = 1082 cm is significantly outside this range and does not fall within the uncertainty of the measurement value. Therefore, the prediction value does not agree well with the measurement value.

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A parallel plates capacitor is composed of two plates in form of a square of side a = 2.0 cm each, and separated by distance 1.5 mm. The insulator between the two plates is the vacu ay stored in this capacitor, in unit "p" (pico Joule) if it is connected to a battery of potential difference AV-5.0 V7 r your answer as positive decimal number with 1 digit after the decimal point.

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The energy stored in the capacitor is 0.4 pJ (to one decimal place).Hence, the correct option is 0.4.

Given that the side length of the square plates is a = 2.0 cm and the separation distance between the plates is d = 1.5 mm = 0.15 cm. The insulator between the two plates is the vacuum.

The capacitance of a parallel plate capacitor is given by the equation: C=ϵ0A/d Where, C is the capacitance,ϵ0 is the permittivity of the vacuum, A is the area of the plates, and d is the separation distance between the plates. Substitute the given values in the above equation, we get:C=8.85 × 10^-12 × (2.0 × 10^-2)^2/1.5 × 10^-3=1.57 × 10^-10 F When the capacitor is connected to a battery of potential difference V = 5.0 V, the energy stored in the capacitor is given by the equation: U = (1/2)CV²Substitute the values of C and V in the above equation, we get:U = (1/2) × 1.57 × 10^-10 × (5.0)²=3.93 × 10^-10 J= 0.4 pJ

Therefore, the energy stored in the capacitor is 0.4 pJ (to one decimal place).Hence, the correct option is 0.4.

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A variable with a final value equal to its simple lower or upper bound and a reduced cost of zero indicates that a. an alternate optimal solution exists. b. an error in formulation has been made. c. the right hand sides should be increased. d. the objective function needs new coefficients.

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The correct answer is option (a). A variable with a final value equal to its simple lower or upper bound and a reduced cost of zero indicates the possibility of an alternate optimal solution.

In linear programming, a variable's final value is determined by the optimization process, which aims to maximize or minimize an objective function while satisfying a set of constraints. When a variable reaches its lower or upper bound as its final value and has a reduced cost of zero, it suggests the potential existence of an alternate optimal solution. An alternate optimal solution refers to another feasible solution that achieves the same optimal objective function value.

This situation arises due to the nature of linear programming, where there can be multiple combinations of variables that yield the same optimal objective function value. It indicates that there are different ways to allocate resources or make decisions while achieving the same level of optimization. This information can be valuable as it allows decision-makers to explore different scenarios and options that meet their requirements. Therefore, option (a) "an alternate optimal solution exists" is the correct answer in this case.

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three pith balls supported by insulating threads hang from a support. we know that ball x is positively charged. when ball x is brought near balls y and z without touching them, it attracts y and repels z. since pith is an insulating material, we can conclude that

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As pith is an insulating material, we can conclude that balls y and z are not charged.

When ball x is brought near balls y and z without touching them, it attracts y and repels z. Since pith is an insulating material, it means it does not transfer charge from one body to another, which means that the insulating material can not charge or get charged. In this case, since the balls are supported by insulating threads, we can conclude that the balls y and z are not charged. When ball x is brought near balls y and z, ball y is attracted towards ball x since they carry opposite charges (x is positively charged and y is neutral).On the other hand, ball z is repelled since both ball x and ball z carry a positive charge. Therefore, the balls y and z are not charged.


From this experiment, it can be concluded that since pith is an insulating material, it can not transfer charge from one body to another. So, the balls y and z were not charged.

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Consider a thin square plate on the z = 0 plane with mass density given by o(x, y) = C ((x - 1)²y² + x^y²), (4) and whose total mass is M. The plate has a side length of two meters, and its center lies at the origin. The infinitesimal mass element is given by: dM = 0 o(x, y)dxdy 1. What are the units of C? Find an expression for C in terms of M. 2. Find the coordinates of the center of mass XCM. 3. Find the moment of inertia around the z-axis: 1 = I ²² - [ [ ²o(x, y)dxdy (6) You may leave your final answer as the sum of two fractions. 4. Now find the moment of inertia along the (x = 2, y = 0) axis.

Answers

1. The units of C are (kilograms per meter to the power of 6).

2. The center of mass, XCM, is located at (x, y) = (1, 0).

3. The moment of inertia around the z-axis is given by the expression I = (11/15)M.

4. The moment of inertia along the (x = 2, y = 0) axis is zero.

1. To determine the units of C, we analyze the given mass density equation o(x, y) = C ((x - 1)²y² + x^y²). The units of mass density are typically expressed as mass divided by volume. In this case, the units of o(x, y) are (mass)/(length^2). The integral expression for the total mass, M, involves the integration of o(x, y) over the plate, which is a double integral of o(x, y)dxdy. Since the units of M are kilograms, we can equate the units and solve for C. Integrating o(x, y) over the plate gives the units of C as (kilograms per meter to the power of 6).

2. The center of mass coordinates, XCM = (xCM, yCM), can be determined using the formula xCM = (1/M) * ∫∫(x * o(x, y))dxdy and yCM = (1/M) * ∫∫(y * o(x, y))dxdy. Substituting the given mass density equation and performing the integrations, we find that xCM = 1 and yCM = 0. Therefore, the center of mass is located at (x, y) = (1, 0).

3. The moment of inertia around the z-axis is given by the expression I = ∫∫(r² * o(x, y))dxdy, where r represents the distance from the z-axis to the infinitesimal mass element. Substituting the given mass density equation and evaluating the integral, we obtain the moment of inertia as I = (11/15)M. This represents a fractional value of the total mass M.

4. The moment of inertia along the (x = 2, y = 0) axis can be calculated by integrating the expression r² * o(x, y) with respect to x and y, while considering that x = 2 and y = 0 along the axis. However, upon evaluating the integral, we find that the result is zero. This indicates that the moment of inertia along this particular axis is negligible or non-existent.

In summary, the units of C are (kilograms per meter to the power of 6). The center of mass, XCM, is located at (x, y) = (1, 0). The moment of inertia around the z-axis is given by the expression I = (11/15)M. Lastly, the moment of inertia along the (x = 2, y = 0) axis is zero.

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two wires x and y are made from the same material and have the same length. wire x has double the diameter of wire y. what is the ratio (resistance of wire x)/(resistance of wire y)?

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The ratio of the resistance of two wires made from the same material and having the same length is equal to the ratio of the squares of their radii. What is resistance?

A property that opposes the flow of electrical current is known as resistance. The more resistance an object has, the more difficult it is for electricity to flow through it. Resistance is measured in ohms, and it is represented by the symbol R.What is the formula for calculating resistance?

Resistance is defined as the voltage divided by the current that flows through a circuit element.Resistance (R) = Voltage (V) / Current (I)What is the relationship between diameter and resistance?Wire diameter has a direct relationship with resistance. The thinner the wire, the greater the resistance.

The thicker the wire, the less resistance it has. Doubling the diameter of a wire reduces its resistance by a factor of four. Because the formula for wire resistance is directly related to the cross-sectional area of the wire.

Conclusion:Two wires X and Y made from the same material and having the same length. Wire X has double the diameter of wire Y. The ratio of the resistance of wire X to the resistance of wire Y is 1:4. Therefore, the resistance of wire X is one-fourth the resistance of wire Y.

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A 400A 380V cable supply with wire resistance 0.03 ohm and supply impedance 0.01 ohm before the main switch. Evaluate: a) The 3 phase short circuit fault level immediate after the switch
b) The earth fault level after the switch if the wire resistance and earth resistance are 0.05 ohm and 0.6 ohm respectively. c) The breaking capacity of the main switch and justify if earth fault relay required.

Answers

An earth fault relay is not required.  The earth fault level after the switch if the wire resistance and earth resistance are 0.05 ohm and 0.6 ohm respectively.The breaking capacity of the main switch is 348.35 kA, and an earth fault relay is not required.

The 3 phase short circuit fault level immediate after the switch:The formula to find the 3 phase short circuit fault level is given by the expression:Fault level (Isc) = (Supply Voltage) / (Total Impedance)Fault level = 400 A / (0.03 Ω + 0.01 Ω)Fault level = 8000 ABreaking capacity is the maximum value of current that a switch is able to interrupt without getting damaged, and it is given by the formula:

Breaking Capacity = (Rated Voltage * Rated Current) / (Power Factor * √3).

Here, the given values are rated current (400A), rated voltage (380V), and power factor (assumed to be 0.8, which is typical of most industrial applications).Breaking Capacity = (380V * 400A) / (0.8 * √3),

Breaking Capacity = 348.35kA (Approximately)The switch's breaking capacity is 348.35 kA, which is greater than the fault level of 8 kA.

As a result, an earth fault relay is not required.

The earth fault level after the switch if the wire resistance and earth resistance are 0.05 ohm and 0.6 ohm respectively.

The formula to determine the earth fault level is given by the equation:Fault level (Isc) = (Supply Voltage) / (Total Impedance)The resistance of the earth (RE) is equal to 0.6 Ω, while the wire resistance (RW) is equal to 0.05 Ω. Zs is equal to the total impedance of the system.

The formula to determine the impedance is:Zs = √ (RW^2 + (Xw + RE)^2)Zs = √ ((0.05^2) + (2π*50*0.6)^2)Zs = 0.72 ΩFault level = 400 A / 0.72 ΩFault level = 555.55 A,

Breaking Capacity = (Rated Voltage * Rated Current) / (Power Factor * √3).Breaking Capacity = (380V * 400A) / (0.8 * √3)Breaking Capacity = 348.35 kA (Approximately)The fault level is 555.55 A, whereas the breaking capacity is 348.35 kA. As a result, an earth fault relay is not required.

The breaking capacity of the main switch and justify if earth fault relay required.

The breaking capacity of the main switch is 348.35 kA, which is greater than both the 3 phase short circuit fault level and the earth fault level.

As a result, the use of an earth fault relay is not required. the breaking capacity of the main switch is 348.35 kA, and an earth fault relay is not required.

The given problem is related to the study of electrical circuits. In this problem, a 400A 380V cable supply with a wire resistance of 0.03 ohm and supply impedance of 0.01 ohm is given.

We are required to evaluate three parameters, namely, the 3 phase short circuit fault level immediate after the switch, the earth fault level after the switch if the wire resistance and earth resistance are 0.05 ohm and 0.6 ohm respectively, and the breaking capacity of the main switch and justify if an earth fault relay is required.

We begin by calculating the fault level for the 3 phase short circuit using the formula Fault level (Isc) = (Supply Voltage) / (Total Impedance). We found out that the fault level is 8000A. Next, we calculated the breaking capacity of the main switch using the formula Breaking Capacity = (Rated Voltage * Rated Current) / (Power Factor * √3).

We found out that the breaking capacity is 348.35kA. We then moved to evaluate the earth fault level after the switch if the wire resistance and earth resistance are 0.05 ohm and 0.6 ohm respectively using the formula Fault level (Isc) = (Supply Voltage) / (Total Impedance). We calculated that the earth fault level is 555.55A.

We concluded that the breaking capacity of the main switch is 348.35kA, which is greater than both the 3 phase short circuit fault level and the earth fault level. Therefore, the use of an earth fault relay is not required.

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What is the effective annual rate if interest is compounded continuously? Write a C program using POSIX Shared Memory with two processes namely a Writer and Reader to implement the following tasks. Let the Writer write 'n' bytes (read from stdin) into the shared memory and the reader be reading the same. Subsequently let the Writer change the contents of bytes '5 to 10'to -...-' and terminate itself. Finally, let the Reader read the updated contents of the shared memory and present them on stdout. Note: The following task shall be completed in a single execution of the Writer process and Reader process. 2. Implement the tasks mentioned in Question 1 using a Writer thread and reader thread. #include #include #include #include #include #include char *inputString(FILE* fp, size_t size){ [/The size is extended by the input with the value of the provisional char *str, int ch; size_t len = 0; str = realloc(NULL, sizeof(char)*size)://size is start size if(str)return str. while(EOF!=(ch=fgetc(fp)) && ch != '\n'){ strlen++]=ch; if(len==size){ str = realloc(str, sizeof(char)*(size+=16)); if(str)return str; } } str[len++]='\0'; return realloc(str, sizeof(char)*len): } int main() { /* the size (in bytes) of shared memory object */ const int SIZE = 4096; name of the shared memory object */ const chart name = 'SHARED"; char *line; for) { /*Display message enter line to be added to the shared memory location: printf("enter line to be added to the shared memory location:"); /* Taking input into the string line using inputString function line = inputString(stdin, 10); /* shared memory file descriptor */ int shm_fd; /* pointer to shared memory obect */ void ptr; /* create the shared memory object */ shm_fd = shm_open(name, O_CREATIO_RDWR, 0666); /* configure the size of the shared memory object */ ftruncate(shm_fd, SIZE): /* memory map the shared memory object */ ptr = mmap(0, SIZE, PROT_WRITE, MAP_SHARED, shm_fd, 0) /* write to the shared memory object */ sprintf(ptr, "%s\n", line): ptr += strlen(line); if(!strcmp (line, "End")) { break; > free(line); } return 0; } Mention 2 roles the masquerade groups played in maintaining peace in traditional Igbo society. JAVA LANGUAGEARRAYS CANNOT BE USED SINCE WE DIDNT LEARN ABOUT ARRAYS IN PUR CLASS YETYou are going to write a program that will read the contents of a scientific log that contains several series of elements to chemical compounds. You will write a program that will combine the elements on each individual line of the file to create their chemical formulas. These formulas will then be named or identified as unknown and a summary will be printed as a report that is written to a file.Program DevelopmentYou must break your program into a minimumof 3 methods, including the main. Each method should accomplish a specific task and be appropriately named.I recommend writing the program without the file output to start. Once you get that part working, then print it to the file instead of the console.Creating FormulasEach line of the file will contain some number of periodic elements each separated by a space.Elements are guaranteed to be grouped together when there are several of the same element.You need to count the number of grouped elements by counting the number of occurrences of that element and then include that count after the element in the formula, except when there is only one.For example:H H O Oshould become H2O2 because there are two H's followed by two O's.andK H C C C C H H H H O O O O O Oshould become KHC4H4O6 combining the C's H's and O'sNaming the CompoundAfter you construct the formula for a given line in the log, you should then determine if the common name of that compound is known or unknown. Your program is not very smart and only knows the following six compounds:NaHCO3 is Baking SodaH2O2 is Liquid BleachKHC4H4O6 is Cream of TartarN2O is Laughing GasNaCl is SaltC12H22O11 is SugarAll other compound formulas are unknownYour program should compare the formula you created to these known compounds, printing the compound name if known and "UNKNOWN FORMULA" followed by the formula if the compound is unknown.Writing the summary to a fileAs you analyze each line, you should print a summary to a new file called report.txt using a PrintStream. The summary should includethe name of the compound (if known) orUNKNOWN FORMULA followed by the formula created for that entry (if unknown).The file should end witha total count of formulas processed, as well asthe count of the total and the percentage of unknown formulas. Note that the percentage is printed to the screen without any decimal places.RRAYS CANNOT BE USED SINCE WE DIDNT LEARN ABOUT ARRAYS IN PUR CLASS YETfile.txtN N O Na Cl N N O Na Cl K H C C C C H H H H O O O O O O C C C C C C C C C C C C H H H H H H H H H H H H H H H H H H H H H H O O O O O O O O O O O N N O O O O O N N O Na H C O O O H H O O Malang Rave Tel me what you want to do content you need to fit to stay in Protected View Enable Editing ICS 100 - Object-Oriented Programming Lab Test Goes the bryder that has the Ids of students who are taking the and the bary MATHI.dor" that has Ide of students who are taking the course Write program that create a new feath" that has the Ide of students both Sample rules PHYSIOTH 111 31 33 77 999 Expected Out that w links . Could an organism be Methyl red and Voges-Proskauer positive?Explain.