A resistor, an inductor, and a capacitor are connected in series to an ac source. What is the condition for resonance to occur?.

It should be noted that duty-based ethics is the intent of an action while outcome-based ethics means the outcome of an action.

It should be noted that ethics are the moral principles that govern a person's behaviour or the conducting of an activity.

Here, duty-based ethics are what people are talking about when they refer to the principle of the thing.

Also, duty-based ethics teaches that some acts are right or wrong based on how they're viewed in the society.

It should be noted that outcome-based ethics simply dictates that the decision to act in a particular way should be beneficial to the people and have a positive impact on them. In this case, the focus is on the result.

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Based upon the Von Mises theory, the safety factor for points A and B are 2.77 and 6.22 respectively.

From the diagram of this bar made of AISI 1006 cold-drawn steel shown in the image attached below, we can logically deduce the following parameters:

At point A, the stress is given by this equation:

σx = Mc/I + P/Area

[tex]\sigma_x = \frac{Fl(\frac{d}{2}) }{\frac{\pi d^2}{64} } +\frac{P}{\frac{\pi d^2}{4} } \\\\[/tex]

σx = 32Fl/πd³ + 4P/πd²

Substituting the given parameters into the formula, we have;

σx = 32(550)(0.1)/π(0.02)³ + 4(800)/π(0.02)²

σx = 95.49 MPa.

Next, we would determine the torque:

Mathematically, torque can be calculated by using this formula:

τxy = Tr/J = 16T/πd³

τxy = 16(30)/π(0.02)³

τxy = 19.10 MPa.

From Von Misses theory, we have:

σVM = √(σx² + 3τxy²)

σVM = √(95.49² + 3(19.10)²)

σVM = 101.1 MPa.

Now, we can calculate the safety factor for point A:

n = Sy/σVM

n = 280/101.1

n = 2.77.

At point B, the stress is given by this equation:

σx = 4P/πd²

σx = 4(800)/π(0.02)²

σx = 25.47 MPa.

Next, we would determine the torque:

Mathematically, torque can be calculated by using this formula:

τxy = Tr/J = 16T/πd³ + 4V/3A

τxy = 16(30)/π(0.02)³ + 4(550)/3π(0.02)³

τxy = 21.43 MPa.

From Von Mises theory, we have:

σVM = √(σx² + 3τxy²)

σVM = √(25.47² + 3(21.43)²)

σVM = 45.02 MPa.

Now, we can calculate the safety factor for point B:

n = Sy/σVM

n = 280/45.02

n = 6.22.

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Answer: Compact Disc

a. The maximum thickness of the copper nozzle is 3.3 mm

b. The maximum thickness of the steel nozzle is 0.054 mm

The question has to do with heat transfer

Heat transfer is the movement of heat energy from one body to anotrher.

Since the rate of heat loss by the gas equal rate of heat gain by the metal.

The rate of heat loss by gas is P = -hA(T - T') where

The rate of heat gain by metal is given by P' = kA(T - T")/t where

Since P = P', we have that

-hA(T - T') =  kA(T - T")/t

Making t subject of the formula, we have

t = -k(T - T")/h(T - T')

Given that for copper

Substituting the values of the variables into t, we have

t = -k(T - T")/h(T - T')

t = -378 W/m-K(540°C - 150°C)/[2 × 10⁴ W/m²-K(540°C - 2750°C)]

t = -378 W/m-K(390°C)/[2 × 10⁴ W/m²-K(-2210°C)]

t = 147420 W/m/4420 × 10⁴ W/m²

t = 147420 W/m/44200000 W/m²

t = 0.0033 m

t = 3.3 mm

So, the maximum thickness of the copper nozzle is 10.71 cm

Given that for steel

Substituting the values of the variables into t, we have

t = -k(T - T")/h(T - T')

t = -23.2 W/m-K(980°C - 150°C)/[2 × 10⁴ W/m²-K(980°C - 2750°C)]

t = -23.2 W/m-K(830°C)/[2 × 10⁴ W/m²-K(-1770°C)]

t = 19256 W/m/3540 × 10⁴ W/m²

t = 19256 W/m/35400000 W/m²

t = 0.0000544 m

t = 0.0544 mm

t ≅ 0.054 mm

So, the maximum thickness of the steel nozzle is 0.054 mm

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