The molar mass of the unknown gas is approximately 42.69 g/mol.
To determine the molar mass of the unknown gas, we can use the ideal gas law equation:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, we need to convert the given temperature from Celsius to Kelvin:
T(K) = 53 °C + 273.15 = 326.15 K
Next, we rearrange the ideal gas law equation to solve for n (number of moles):
n = PV / RT
Now, we can substitute the given values into the equation:
P = 0.555 atm
V = 1.24 g/L (density is equivalent to mass/volume, so we can use the density as the mass)
R = 0.0821 L·atm/(K·mol) (ideal gas constant)
T = 326.15 K
n = (0.555 atm) * (1.24 g/L) / (0.0821 L·atm/(K·mol) * 326.15 K)
Simplifying the units:
n = (0.555 atm) * (1.24 g/L) / (0.0821 * 326.15 K) mol
n ≈ 0.02902 mol
Now, to determine the molar mass (M) of the unknown gas, we can use the equation:
M = molar mass (g/mol) / number of moles (mol)
The given density is equivalent to mass/volume, so we can calculate the mass:
mass = density * volume = 1.24 g/L * 1 L = 1.24 g
M = mass / n = 1.24 g / 0.02902 mol ≈ 42.69 g/mol
Therefore, the molar mass of the unknown gas is approximately 42.69 g/mol.
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which of the following statements are true f
The statement that is true is Hyperosmotic solutions may cause the cell to crenate.
Option D is correct.
What is a Hyperosmotic solutions?Hyperosmotic solution is described as solution with an osmotic pressure lower than the other solution.
In a hyperosmotic solution, the concentration of solutes outside the cell is higher than inside the cell which creates an osmotic pressure that draws water out of the cell, causing it to shrink or undergo crenation.
Any hypertonic solution will cause a red blood cell to lose free water and shift it into the hypertonic solution. Because the cell contains more free water than the solution does, this movement happens by osmosis.
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complete question is attached in image
The molecule BrF33 has a dipole moment of 1.19 D. Which of the following geometries are possible?
a) trigonal pyramidal
b) T-shaped
c) trigonal planar
The possible geometry for the BrF₃ molecule with a dipole moment of 1.19 D is T-shaped.
The BrF₃ molecule has a total of 28 valence electrons. When arranged around the central atom (Br), three of these electrons form bonds with the F atoms, while two lone pairs occupy the remaining positions. This arrangement results in a T-shaped molecular geometry, according to the VSEPR theory.
In a T-shaped geometry, the bond dipoles do not cancel each other out, resulting in a net dipole moment. The other geometries, trigonal pyramidal and trigonal planar, do not correctly account for the dipole moment of 1.19 D, as the bond dipoles would either cancel out or the electron arrangement would be different.
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What is the density of a sample of argon gas at 70 ∘C and 785 mmHg ?
What is the density of a sample of argon gas at 70 and 785 ?
1.47 g/L
14.66 g/L
7.18 g/L
1114.19 g/L
The density of argon gas at 70 ∘C and 785 mmHg is 1.47 g/L. Option 1 is Correct.
It can be calculated using the ideal gas law, which relates the pressure, volume, and temperature of a gas. The ideal gas law states that:
PV = nRT
here P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
To solve for the density of the argon gas sample, we need to first convert the pressure and temperature from SI units to Kelvin and molar units. The pressure can be converted to kilopascals (kPa) by dividing it by 101.325 (the molar gas constant in kPa/mol), and the temperature can be converted to Kelvin by subtracting 273.15 from it. The volume can be expressed in moles by dividing it by the number of moles of argon in the sample (which we assume to be 1).
1 atm * 785 mmHg / (1 atm * 0.018297 + 1 mole * 8.314 J/mol * 273.15 K) = 14.66 g/L
Therefore, the density of argon gas at 70 ∘C and 785 mmHg is 14.66 g/L.
To solve for the density at 70 ∘C and 785 mmHg, we can use the ideal gas law in the same way:
P = nRT
here P is the pressure, n is the number of moles of argon, R is the gas constant, and T is the temperature in Kelvin.
Substituting the given values, we get:
1 atm * 785 mmHg / (1 atm * 0.018297 + 1 mole * 8.314 J/mol * 273.15 K) = 1.47 g/L
Therefore, the density of argon gas at 70 ∘C and 785 mmHg is 1.47 g/L.
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ne, hf, c2h6, ch4 which of the substances listed above has the highest boiling point, and why?
Among the substances listed, HF has the highest boiling point due to its strong hydrogen bonding between molecules.
The boiling point of a substance is determined by the strength of the intermolecular forces between its molecules. The stronger the intermolecular forces, the higher the boiling point.
Among the substances listed, Ne (neon) has the lowest boiling point because it is a noble gas with weak van der Waals forces between its atoms. Its boiling point is very low (-246.1 °C).
HF (hydrogen fluoride) has the highest boiling point because it has strong hydrogen bonds between its molecules. Hydrogen bonds are the strongest type of intermolecular force, and they require a lot of energy to break. HF has a boiling point of 19.5 °C.
Between C2H6 (ethane) and CH4 (methane), C2H6 has a higher boiling point because it has a larger number of electrons and more surface area, which results in stronger van der Waals forces between its molecules. CH4 has a boiling point of -161.5 °C, while C2H6 has a boiling point of -88.6 °C.
Therefore, among the substances listed, HF has the highest boiling point due to its strong hydrogen bonding between molecules.
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an atomic view of matter was first proposed approximately how many years ago?
The atomic view of matter was first proposed approximately 2,500 years ago by the ancient Greek philosopher Democritus.
Democritus postulated that matter is composed of indivisible particles called atoms. His concept of atoms, however, was purely philosophical and lacked experimental evidence at that time.
Democritus believed that atoms were tiny, indestructible, and indivisible particles that combine in different ways to form all matter. He proposed that different types of matter had different arrangements and combinations of atoms, which determined their properties.
It is important to note that Democritus' atomic theory was not widely accepted during his time and was overshadowed by other philosophical schools of thought. It was not until much later, in the 19th century, that experimental evidence and advancements in scientific understanding confirmed the existence of atoms and led to the development of modern atomic theory.
In the early 1800s, John Dalton further developed the atomic theory, providing a more comprehensive and scientific understanding of atoms and their behavior. Dalton's work laid the foundation for the modern understanding of matter at the atomic level.
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