A sequence of transformations is described below.
A dilation about a point P
A rotation about another point Q
A vertical stretch about the horizontal line PQ
A reflection over a line PQ

Here is the answer-
Neither angle measure nor segment length is preserved. Here's why-
This sequence includes a vertical stretch, which is neither a rigid transformation nor a dilation.

Answer:

B

Step-by-step explanation:

Start at zero.

Go 2 units left to -2.

Then go another 7 units left to add -7.

Answer: B

Answer:

Step-by-step explanation:

See the picture

It should be self-explanatory

The top part of the angle a is:

The bottom part of the angle a is:

The measure of angle a is:

Firstly, draw a line parallel to UT

Something like in the picture

Now,

a = BNU

Also,

BNU + BNM = 165°

Answer:

16.3

Step-by-step explanation:

i just took the quiz

Answer:

16.3 units

Step-by-step explanation:

Helloo, I just took the quiz too and the answer is 16.3

130 is your answer!  Look at line A. 130 degrees. now if A and B are parallel then 5 on line B will also be 130 degrees.

I hope this helps!

Answer:

Dilated pupils

Long periods of wakefulness

Loss of appetite

Overconfidence

Over-excitement

Paranoia

Runny nose or frequent sniffles

White powder around nostrils

Legal issues

Missing or being late to work

Financial problems

Mood swings

Irritability

Depression

Answer:

option d is correct answer

Answer:

[tex]\left(3x+4\right)\left(x-8\right)[/tex]

[tex]a=3x,\:b=4,\:c=x,\:d=-8[/tex]

[tex]=3xx-3\cdot \:8x+4x-4\cdot \:8[/tex]

[tex]=3x^2-20x-32[/tex]

--------------------------

hope it helps...

have a great day!!

Step-by-step explanation:

hope this will help you if it really help you mark me as brinalist friend please

Hello,

[tex]\displaystyle \int {-\dfrac{2}{3} \sqrt{(2-5x)^3}} \, dx \\\\\displaystyle=-\dfrac{2}{3}*\dfrac{-1}{5} \int {-5*(2-5x)^{\frac{3}{2} }} \, dx \\\\\displaystyle=\dfrac{4}{3}*(2-5x)^{\frac{5}{2} }+C[/tex]

Answer:

Look below...

Step-by-step explanation:

Losing 7 cards in a deck: -7. Losing means negative.

Saving $102 in your wallet: 102. You are saving, that means you gain.

336 feet below sea level: -336. Below indicates less than 0,  which is negative.

Depositing $43 into your bank account: 43. Depositing means putting. If you put $43 in YOUR bank account, the bank account gains money. So you gain money. Making it positive.

1,000 feet above sea level: 1,000. Above indicates more than zero. Anything more than zero on a number line is positive.

Hope this helps :)

Step-by-step explanation:

180-68=112

112÷293=3.8620

68÷3.87

18

Answer:

C

Step-by-step explanation:

Let m represent Mark's age and j represent Jeffrey's age.

Mark is five years older than Jeffrey. Hence:

[tex]m=j+5[/tex]

The sum of Mark's age and triple Jeffrey's age is 73. In other words:

[tex]m+3j=73[/tex]

We can substitute:

[tex](j+5)+3j=73[/tex]

Therefore, our answer is C.

Answer:

[tex]{ \boxed{ \tt{m \angle1 = m \angle5}}} \\ { \tt{m \angle1 = 180 \degree - m \angle6}} \\ { \tt{m \angle1 = 180 \degree - 123.5 \degree}} \\ { \bf{m \angle1 = 56.5 \degree}}[/tex]

When a pair of parallel lines is intersected by a transversal, then

Corresponding angles are equal.

∠2 and ∠6 are corresponding angles.

So, m∠2 = m∠6

=> m∠2 = 123.5°

We know that linear pair of angles are supplementary (180°).

∠1 and ∠2 are linear pair of angles.

So, m∠1 + m∠2 = 180°

=> m∠1 + 123.5° = 180°

=> m∠1 = 180° - 123.5°

=> m∠1 = 56.5°

Answer:

#1: (B, D, E)

#2: (D) f(q) = 2q + 3

#3: (C) 1

#4: (B) f(5) = -1

#5: (A) - 8

Step-by-step explanation:

Question 1:

The number inside the parentheses is the input value, or x coordinate, and the output value (the number on the right side of the equal sign) is the y coordinate.

Use basic graph plotting skills to see if the x coordinate has a y coordinate value that's ON the graph line.

Question 2:

The variable "q" is our independent variable, also known as our x variable if you used the y = mx + b formula.

To rewrite 6q = 3s - 9 into function notation, you would solve for variable "s" using basic algebra:

6q = 3s - 9

6q + 9 = 3s

2q + 3 = s

s = 2q + 3 or f(q) = 2q + 3

Question 3:

The number inside the parentheses, -2, is the input value, or the x coordinate. Looking at the table, you can see that when you input -2, you get an ouput of 1.

Question 4:

Use the same process as Question 1.

Question 5:

The number inside the parentheses, 5, is the input value, or the x coordinate. Looking at the table, you can see that when you input 5, you get an ouput of -8.

Hope it helps (●'◡'●)

Answer:

1. (2), (4), (5)

2. (4l

3. (3)

4. (2)

5. (1)

Step-by-step explanation:

1.

g(0) = 0

g(-1) = 1

g(1) = 1

2.

since q is the independent variable s must be dependent on q and hence s must be equal to f(q)

6q = 3s - 9

3s = 6q + 9

s = 2q + 3

f(q) = 2q + 3

that is the last option

3.

= 1

4.

= -1

5.

= -8

Answer:

a =15

b=70

c=400

d=1500

e=5300

Step-by-step explanation:

it will help u

Answer:

height of the tree ≈ 8.42 m

Step-by-step explanation:

The diagram given represents that of two similar triangles. Therefore, the corresponding lengths of the similar triangles are proportional to each other.

height of tree = h

Therefore:

1.45/h = (31.65 - 26.2)/31.65

1.45/h = 5.45/31.65

Cross multiply

h*5.45 = 1.45*31.65

h*5.45 = 45.8925

h = 45.8925/5.45

h ≈ 8.42 m (nearest hundredth)

Answer:

10

Step-by-step explanation:

If you look at it 20 is from EG so if FJ is half of EG then FJ is half of 20

Answer:

y=43/2

Step-by-step explanation:

Answer:No

Step-by-step explanation:

Answer:

No. Try harder next year.

Answer:

48

Step-by-step explanation:

let the number be x and x + 16 the result of adding 16 to it, then

the ratio of the result to the original is

[tex]\frac{x+16}{x}[/tex] = [tex]\frac{4}{3}[/tex] ( cross- multiply )

4x = 3(x + 16)  = 3x + 48 ( subtract 3x from both sides )

x = 48

Given:

The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.

To find:

The length and width of the cucumber field.

Solution:

The area of a rectangle is:

[tex]A=l\times w[/tex]

Where l is length and w is width of the rectangle.

The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.

We need to find the factors of [tex]x^2-4x-21[/tex] to get the length and width.

[tex]A=x^2-4x-21[/tex]

Splitting the middle term, we get

[tex]A=x^2-7x+3x-21[/tex]

[tex]A=x(x-7)+3(x-7)[/tex]

[tex]A=(x-7)(x+3)[/tex]

Area of a rectangle is the product of length and width.

Therefore, the length and width of the rectangle are [tex](x-7)[/tex] units and [tex](x+3)[/tex] units.

Answer:

B. Selling treasury securities

Step-by-step explanation:

I'm taking the quiz

The Federal Reserve can reduce the amount of money available in the economy is buying treasury securities.

Therefore, the correct answer exists as option B. Selling treasury securities.

To learn more about Federal Reserve refer to:

https://brainly.com/question/382312

#SPJ2

Answer:  [tex]\frac{n-m}{n}[/tex]

This is the same as writing (n-m)/n

Don't forget about the parenthesis if you go with the second option.

==================================================

Explanation:

The probability that she wins is m/n, where m,n are placeholders for positive whole numbers.

For instance, m = 2 and n = 5 leads to m/n = 2/5. This would mean that out of n = 5 chances, she wins m = 2 times.

The probability of her not winning is 1 - (m/n). We subtract the probability of winning from 1 to get the probability of losing.

We could leave the answer like this, but your teacher says that the answer must be "in the form of a combined single fraction".

Doing a bit of algebra would have these steps

[tex]1 - \frac{m}{n}\\\\\frac{n}{n} - \frac{m}{n}\\\\\frac{n-m}{n}\\\\[/tex]

and now the expression is one single fraction.

Answer:

[tex]y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}[/tex]

Step-by-step explanation:

Given

[tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]y(1) = 0[/tex]

[tex]y'(1) =e[/tex]

Required

The solution

Differentiate [tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]y' = c_1e^x - c_2e^{-x}[/tex]

Next, we solve for c1 and c2

[tex]y(1) = 0[/tex] implies that; x = 1 and y = 0

So, we have:

[tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]0 = c_1 * e^1 + c_2 * e^{-1}[/tex]

[tex]0 = c_1 e + \frac{1}{e}c_2[/tex] --- (1)

[tex]y'(1) =e[/tex] implies that: x = 1 and y' = e

So, we have:

[tex]y' = c_1e^x - c_2e^{-x}[/tex]

[tex]e = c_1 * e^1 - c_2 * e^{-1}[/tex]

[tex]e = c_1 e - \frac{1}{e}c_2[/tex] --- (2)

Add (1) and (2)

[tex]0 + e = c_1e + c_1e + \frac{1}{e}c_2 - \frac{1}{e}c_2[/tex]

[tex]e = 2c_1e[/tex]

Divide both sided by e

[tex]1 = 2c_1[/tex]

Divide both sides by 2

[tex]c_1 = \frac{1}{2}[/tex]

Substitute [tex]c_1 = \frac{1}{2}[/tex] in [tex]0 = c_1 e + \frac{1}{e}c_2[/tex]

[tex]0 = \frac{1}{2} e+ \frac{1}{e}c_2[/tex]

Rewrite as:

[tex]\frac{1}{e}c_2 = -\frac{1}{2} e[/tex]

Multiply both sides by e

[tex]c_2 = -\frac{1}{2} e^2[/tex]

So, we have:

[tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]y = \frac{1}{2}e^x -\frac{1}{2} e^2 * e^{-x}[/tex]

[tex]y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}[/tex]