A set of data has a normal distribution with a mean of 50 and a standard deviation of 8. Find the percent of data within each interval.

greater than 34

Answers

Answer 1

To find the percent of data within a specific interval, we can use the properties of the standard normal distribution.

Since we are given a normal distribution with a mean of 50 and a standard deviation of 8, we can transform it into a standard normal distribution with a mean of 0 and a standard deviation of 1 using the z-score formula: z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation. To calculate the percentage of data greater than 34, we need to find the area under the standard normal curve to the right of the z-score corresponding to 34.

We can use a standard normal distribution table or a statistical software to find the corresponding z-score, which is approximately -2.25. Once we have the z-score, we can determine the percentage of data greater than 34 by calculating the area under the curve to the right of -2.25. This can be done by subtracting the cumulative probability corresponding to -2.25 from 1. The cumulative probability for -2.25 is approximately 0.9878. Subtracting this value from 1 gives us 0.0122, which is equivalent to 1.22%.

Therefore, approximately 1.22% of the data falls to the right of 34 in a normal distribution with a mean of 50 and a standard deviation of 8.

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Related Questions



Find (a) the sample proportion, (b) the margin of error, and (c) the 95% confidence interval for the population proportion.

In a simple random sample of 500 people, 342 reported using social networking sites on the Internet.

Answers

A. Margin of error = Z * sqrt((p_hat * (1-p_hat)) / n)

B. The margin of error is approximately 0.0401.

C. The 95% confidence interval for the population proportion is approximately 0.6449 to 0.7231.

To find the sample proportion, you divide the number of individuals with a certain characteristic by the total sample size. In this case, the sample proportion of people who reported using social networking sites on the Internet can be calculated as:

(a) Sample proportion = Number of people who reported using social networking sites / Total sample size

= 342 / 500

= 0.684

The sample proportion is 0.684.

To calculate the margin of error, we can use the formula:

Margin of error = Z * sqrt((p_hat * (1-p_hat)) / n)

Where:

Z is the z-score corresponding to the desired confidence level (for 95% confidence level, Z value is approximately 1.96)

p_hat is the sample proportion

n is the sample size

(b) Margin of error = 1.96 * sqrt((0.684 * (1-0.684)) / 500)

= 1.96 * sqrt(0.209856 / 500)

= 1.96 * sqrt(0.000419712)

≈ 1.96 * 0.020488

≈ 0.040078

The margin of error is approximately 0.0401.

To calculate the confidence interval, we can use the formula:

Confidence Interval = Sample proportion ± Margin of error

(c) Confidence Interval = 0.684 ± 0.0401

The 95% confidence interval for the population proportion is approximately 0.6449 to 0.7231.

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What does round to one more decimal place than the largest number of decimal places given in the data mean?

Answers

It means rounding the answer to one additional decimal place beyond the largest number of decimal places in the given data.

We have,

"Round to one more decimal place than the largest number of decimal places given in the data" means that you should determine the number in the data that has the most decimal places and then round your answer to one additional decimal place beyond that.

For example, let's say you have a set of numbers with varying decimal places:

1.23

0.456

5.6789

In this case, the number with the most decimal places is 5.6789, which has four decimal places.

To comply with the instruction to round to one more decimal place than the largest number of decimal places given, you would round your answer to five decimal places.

So, if your final result is 3.1415926535, you would round it to 3.14159.

Thus,

It means rounding the answer to one additional decimal place beyond the largest number of decimal places in the given data.

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Which of the following three data sets is Cross sectional? a. BCAD data and links b. Demographic data c. Code cases

Answers

Among the three options provided, the cross-sectional data set is the demographic data. Correct option is B).

Cross-sectional data refers to a type of data that captures information about different individuals, entities, or units at a specific point in time. It provides a snapshot of a population or sample at a particular moment, allowing for comparisons and analysis of various characteristics or variables. In the case of demographic data, it typically includes information about individuals' age, gender, education level, income, and other demographic attributes. This data set does not capture changes or trends over time but rather provides a snapshot of the population's characteristics at a specific time.

On the other hand, the BCAD data and links could refer to data related to building codes, regulations, and their corresponding references, while code cases may refer to specific instances or examples of code violations or compliance. These data sets may be specific to certain incidents or cases and do not necessarily capture information about a population or sample at a particular point in time, making them less likely to be considered cross-sectional data.

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Determine whether each function is an example of exponential growth or decay. Then, find the y -intercept. y=2.25(1/3) x

Answers

The y-intercept of the function [tex]y = 2.25(1/3)^x[/tex] is 2.25.

We have,

To determine whether the function [tex]y = 2.25(1/3)^x[/tex] represents exponential growth or decay, we can examine the base of the exponent.

In this case, the base is (1/3).

If the base is between 0 and 1, the function represents exponential decay.

If the base is greater than 1, the function represents exponential growth.

Since the base (1/3) is between 0 and 1, the function [tex]y = 2.25(1/3)^x[/tex]represents exponential decay.

Now, let's find the y-intercept.

The y-intercept occurs when x = 0.

Plugging in x = 0 into the function:

[tex]y = 2.25(1/3)^0[/tex]

y = 2.25(1)

y = 2.25

Therefore,

The y-intercept of the function [tex]y = 2.25(1/3)^x[/tex] is 2.25.

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Given directed line segment qs, find the coordinates of r such that the ratio of qr to rs is 3:5. plot point r. q(8,-5) s(-10,3)

Answers

The coordinates of R between points Q and R are (5/4, -2)

How to determine the coordinates of R

From the question, we have the following parameters that can be used in our computation:

Q(9, -5) and S(-10, 3)

We have the partition to be

m : n = 3 : 5

The coordinate is then calculated as

R = 1/(m + n) * (mx₂ + nx₁, my₂ + ny₁)

Substitute the known values in the above equation, so, we have the following representation

R = 1/8 * (3 * -10 + 5 * 8, 3 * 3 + 5 * -5)

Evaluate

R = (5/4, -2)

Hence, the coordinate is (5/4, -2)

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EXTENDED RESPONSE The degree measures of minor are \widehat{A C} and major arc \widehat{A D C} are x and y , respectively.

(b) Find x and y .

Answers

The arc values are x=130° and y=50°.

We know that,  the angle substituted by an arc is twice the angle substituted by it on the circumference.

∴From the figure, ∠AOC=2∠ADC.

Also, in the figure given, ∠AOC=100°.

∴100°=2∠ADC

⇒∠ADC=100×[tex]\frac{1}{2}[/tex] °=50°,

We also know that, for any cyclic quadrilateral the sum of the opposite angle is 180°.

⇒∠ADC+∠ABC=180°.

⇒∠ABC=180-50=130°.[As ∠ADC=50°]

Again it's given that, [tex]\widehat{ABC}=x[/tex] and [tex]\widehat {ADC}=y[/tex].

Hence, we get x=130° and y=50°.

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The complete question is, "The degree measures of minor arc \widehat{A B C} and major arc \widehat{A D C} are x and y, respectively. the measure of arc ABC is 100 ° in the picture. Find x and y."

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Which expression is equivalent to 12x⁻⁴/4x⁻⁸?

F. 1/3x⁴

G. 3x⁴

H. 8 x²

J. x⁴/3

Answers

Expression equivalent to 12x⁻⁴/4x⁻⁸ is  3x⁴.

Hence option G is correct.

To simplify 12x⁻⁴/4x⁻⁸,

We first need to combine the x-terms in the denominator.

We can do this by remembering that x⁻⁸ is the same as 1/x⁸.

So, our expression becomes:

12x⁻⁴ / 4x⁻⁸ = 3x⁻⁴ / x⁻⁸

Now, we can simplify further by dividing the coefficients (the numbers in front of the x-terms) and subtracting the exponents:

3x⁻⁴ / x⁻⁸ = 3x⁻⁴( x⁸ )

               = 3x⁴

Therefore, the equivalent expression to 12x⁻⁴/4x⁻⁸ is G. 3x⁴.

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A horizontal line has points A , E, D. A line extends vertically from point E to point C and forms a right angle at C E D. A line extends up and to the left from point E to point B.
Which statement is true about the given information?

∠CED measures 45°.
∠CED measures 180°.
∠AEC measures 90°.
∠AEC measures 45°

Answers

Answer:

C. ∠AEC measures 90°

Step-by-step explanation:

The given information describes a horizontal line with points A, E, and D. A vertical line extends from point E to point C and forms a right angle at CED. A line extends up and to the left from point E to point B. The statement that is true about the given information is that ∠AEC measures 90° 1. Therefore, the correct answer is C. ∠AEC measures 90°.

Answer:

AEC measures 90°

Step-by-step explanation:

just did the review

If θ is in Quadrant I and sinθ=3/5 , what is an exact value of sin 2θ ?

(F) 9/25 (G) 24/25 (H) 6/5 (I) 73.7

Answers

An exact value of sin2θ is 24/25. Therefore, the correct answer is option (G).

The sin of an angle in Quadrant I is positive, so sinθ = 3/5. To find the exact value of sin 2θ, we can use the double-angle formula sin 2θ = 2(sinθ)(cosθ). Since θ is in Quadrant I, cosθ = 4/5. Plugging those values into our double-angle formula, we have:

sin 2θ = 2(3/5)(4/5)

= 24/25

Therefore, the correct answer is option (G).

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If you invest $900 in a bank where it will earn 8 percent compounded annually, how much will it be worth at the end of seven years? Complete the steps below using cell references to given data or previous calculations. In some cases, a simple cell reference is all you need. To copy/paste a formula across a row or down a column, an absolute cell reference or a mixed cell reference may be preferred. If a specific Excel function is to be used, the directions will specify the use of that function. Do not type in numerical data into a cell or function. Instead, make a reference to the cell in which the data is found. Make your computations only in the green cells highlighted below. In all cases, unless otherwise directed, use the earliest appearance of the data in your formulas, usually the Given Data section. Given Data: Annual Interest Rate 8% Number of years 7 Money available for investing S900.00 Value of investment after 7 years

Answers

The investment will be worth approximately $1,546.45 at the end of 7 years. To calculate the value of the investment after 7 years, we can use the formula for compound interest:

Value = Principal * (1 + interest rate)^time

Given Data:

Principal (P) = $900

Annual Interest Rate (r) = 8% or 0.08

Number of years (t) = 7

Substituting the values into the formula, we have:

Value = $900 * (1 + 0.08)^7

Calculating the exponent:

(1 + 0.08)^7 = 1.08^7 ≈ 1.718279

Now we can calculate the value of the investment:

Value = $900 * 1.718279 ≈ $1,546.45

Therefore, the investment will be worth approximately $1,546.45 at the end of 7 years.

In this calculation, we used the compound interest formula, which takes into account the initial principal, the annual interest rate, and the number of compounding periods (in this case, 7 years). The interest is compounded annually, meaning that at the end of each year, the interest earned is added to the principal for the next year's calculation.

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At 12.5 percent interest, how long does it take to triple your money? Multiple Choice 11.53 years 10.36 years 9.33 years 10.56 years 14.33 years

Answers

To calculate the time it takes to triple your money at a 12.5 percent interest rate, we can use the formula for compound interest and we obtain the answer as 9.33(Approximately)

FV = PV * (1 + r)^n

Where FV is the future value, PV is the present value, r is the interest rate, and n is the number of compounding periods.

In this case, we want to find the value of n when the future value (FV) is three times the present value (PV). Let's assume the initial amount is $1.

3 * 1 = 1 * (1 + 0.125)^n

Simplifying the equation, we have:

3 = 1.125^n

To solve for n, we need to take the logarithm of both sides of the equation:

log(3) = n * log(1.125)

n = log(3) / log(1.125)

Using a calculator, we find that n is approximately 9.33 years.

Therefore, the correct answer is: 9.33 years.

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Read each question. Then write the letter of the correct answer on your paper. A and B are mutually exclusive events. Pa.= 1/3 and Pb.= 1/2 . What is P(A or B). ? a. 1/6 b. 2/3 c. 5/6 d. 1

Answers

Answer:

Step-by-step explanation:

To calculate the probability of the union of mutually exclusive events A and B (P(A or B)), we can use the formula:

P(A or B) = P(A) + P(B)

However, since events A and B are mutually exclusive, meaning they cannot occur simultaneously, the probability of their union is simply the sum of their individual probabilities.

Given that P(A) = 1/3 and P(B) = 1/2, we can calculate the probability of their union:

P(A or B) = P(A) + P(B)

         = 1/3 + 1/2

         = 2/6 + 3/6

         = 5/6

Therefore, the correct answer is c. 5/6.

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Consider the following LP: maxz=
s.t. ​
5x 1

+3x 2

4x 1

+2x 2

≤12
4x 1

+x 2

≤10
x 1

+x 2

≤4
x 1

,x 2

≥0

(a) Solve the LP graphically. (b) Solve the LP using the Simplex Method. (c) Identify all basic feasible solutions corresponding to each tableau of the Simplex Method and find the corresponding point in the graph. (d) Is the LP degenerate? Why? (e) Is the LP unboundend, does it have multiple optimal solutions or is the optimal solution unique? Use the final tableau to establish your answer.

Answers

By analyzing the final simplex tableau, we can establish whether the LP is unbounded, has multiple optimal solutions, or has a unique optimal solution.

(a) Solving the LP graphically:

First, let's graph the constraints:

5x1 + 3x2 ≤ 12

4x1 + 2x2 ≤ 10

x1 + x2 ≤ 4

x1, x2 ≥ 0

Plotting these constraints will create a feasible region bounded by the lines and the non-negativity constraints.

Next, we need to identify the corner points of the feasible region. To do this, we can solve each pair of intersecting lines to find the intersection points.

Once we have the corner points, we can evaluate the objective function z = 5x1 + 3x2 at each corner point to determine the optimal solution point that maximizes z.

(b) Solving the LP using the Simplex Method:

The initial simplex tableau is formed by adding slack variables to the constraints and setting up the objective function row.

After performing the simplex iterations, we can obtain the final simplex tableau and read the optimal solution from it.

(c) Identifying all basic feasible solutions corresponding to each tableau of the Simplex Method and finding the corresponding point in the graph:

In each tableau of the Simplex Method, the basic feasible solutions correspond to the variables that have a value of zero in the objective row.

For each tableau, we can identify the basic feasible solutions and their corresponding points in the graph by setting the non-basic variables to zero and solving for the basic variables.

(d) Determining if the LP is degenerate:

An LP is considered degenerate if there are multiple solutions that give the same optimal objective function value.

To determine if the LP is degenerate, we need to examine the final simplex tableau and check if there are multiple solutions with the same optimal objective function value.

(e) Establishing if the LP is unbounded, has multiple optimal solutions, or has a unique optimal solution:

We can determine if the LP is unbounded, has multiple optimal solutions, or has a unique optimal solution by examining the final simplex tableau.

If there is a column in the objective row with all negative values or a row with all non-positive values, the LP is unbounded.

If the optimal objective function value appears multiple times in the objective row, the LP has multiple optimal solutions.

If the optimal objective function value appears only once and there are no other non-positive values in the objective row, the LP has a unique optimal solution.

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Write an equation for each translation. x²+y²=49 ; right 3 units and up 2 units

Answers

The translated equation of x² + y² = 49, moving right 3 units and up 2 units, is (x - 3)² + (y - 2)² = 49.



To translate the equation right 3 units and up 2 units,

we subtract 3 from the x-coordinate and 2 from the y-coordinate.

This is reflected in the translated equation by replacing x with (x - 3) and y with (y - 2). The equation (x - 3)² + (y - 2)² = 49 represents a circle with.

its center shifted 3 units to the right and 2 units up from the original circle x² + y² = 49.

The radius remains the same, as indicated by the constant value of 49.

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Reasoning Suppose lines l₁ and l₂ intersect at the origin. Also, l₁ has slope (y/x)(x>0, y>0) and l₂ has slope -x/y . Then l₁ contains (x, y) and l₂ contains (-y, x) .

c. What must be true about a+b ? Why?

Answers

The value of a+b must be equal to zero because lines l₁ and l₂ intersect at the origin (0, 0).

Since line l₁ has a slope of (y/x) where both x and y are positive, it implies that line l₁ passes through the point (x, y).

Similarly, line l₂ has a slope of -x/y, suggesting that it passes through the point (-y, x).

Given that lines l₁ and l₂ intersect at the origin (0, 0), we can conclude that the sum of the x-coordinates and the sum of the y-coordinates of their respective points of intersection must be zero.

Therefore, the equation is a+b = x + (-y) = 0.

Consequently, the sum of a and b must equal zero based on the understanding that lines l₁ and l₂ intersect at the origin and their respective point coordinates.

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a. Write three trigonometric equations each with the complete solution π+2 π n .

Answers

The three trigonometric equations are:

1. Equation: sin(x) = -1

2. Equation: cos(x) = 0

3. Equation: tan(x) = 1

The three trigonometric equations, each with the complete solution of π + 2πn:

1. Equation: sin(x) = -1

  Solution: x = π + 2πn, where n is an integer.

2. Equation: cos(x) = 0

  Solution: x = π/2 + 2πn, where n is an integer.

3. Equation: tan(x) = 1

  Solution: x = π/4 + πn, where n is an integer.

In each equation, the solutions are given in the form π + 2πn, where n represents any integer.

This form accounts for all possible solutions that satisfy the equation.

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Consider the function f(x)=10x-x². What type of function is f? Group of answer choices a linear function. an exponential function. a quadratic function. a logarithmic function.

Answers

The function f(x) = 10x - x² is a quadratic function.

A quadratic function is a polynomial function of degree 2, which means the highest power of the variable is 2. In the given function, the variable x is raised to the power of 1 in the term 10x, and it is raised to the power of 2 in the term -x². This indicates that the function is a quadratic function.

The general form of a quadratic function is f(x) = ax² + bx + c, where a, b, and c are constants. In the given function, a = -1, b = 10, and c = 0 (since there is no constant term). So, the function f(x) = 10x - x² fits the form of a quadratic function.

Quadratic functions are known for having a graph in the shape of a parabola. In this case, the parabola opens downward because the coefficient of the x² term is negative (-1). The graph of the function will have a vertex at the maximum point, which in this case is (5, 25).

Therefore, the function f(x) = 10x - x² is indeed a quadratic function.

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What is the solution of 1<2x+3<9?

(A) -1>x<2 (B)2

Answers

The solution to the inequality 1 < 2x + 3 < 9 is x > -1 and x < 2. Option (A) -1 > x < 2 is the correct answer.

To solve the inequality 1 < 2x + 3 < 9, we need to isolate the variable x.

First, subtract 3 from all parts of the inequality:

1 - 3 < 2x + 3 - 3 < 9 - 3

-2 < 2x < 6

Next, divide all parts of the inequality by 2, ensuring to flip the inequality signs when dividing by a negative number:

-2/2 > 2x/2 > 6/2

-1 > x > 3

Therefore, the solution to the inequality is x > -1 and x < 3. In the given options, option (A) -1 > x < 2 matches the solution, while option (B) 2 is not a valid solution to the inequality. Thus, the correct answer is option (A) -1 > x < 2.

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Why does an oblique solid not have a slant height?

Answers

An oblique solid, such as a prism or a pyramid, can indeed have a slant height.

The slant height refers to the distance between the apex (or top point) of the solid and any point on the lateral surface. It is commonly used when calculating the lateral area or total surface area of the solid.

However, it's important to note that the term "slant height" is more commonly associated with right solids, such as right pyramids or right cones. In these cases, the slant height specifically refers to the distance between the apex and a point on the lateral surface along a slanted line that is perpendicular to the base.

For oblique solids, instead of using the term "slant height," you might often encounter the terms "height" or "altitude" to describe the perpendicular distance between the base and the apex.

The height or altitude is used to calculate the volume and other properties of the solid. So while the term "slant height" may not be commonly used for oblique solids, they still possess a height or altitude measurement to describe their geometric properties.

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Can a pair of angles be supplementary and congruent? Explain your reasoning.

Answers

No, a pair of angles cannot be both supplementary and congruent.

Supplementary angles are two angles whose measures add up to 180 degrees. If two angles are supplementary, their sum is 180 degrees.

Congruent angles, on the other hand, have the same measure. If two angles are congruent, their measures are equal.

If a pair of angles were both supplementary and congruent, it would mean that their measures are equal and their sum is 180 degrees. However, this is not possible because if two angles have the same measure, their sum cannot be 180 degrees unless both angles are right angles (90 degrees).

In summary, a pair of angles cannot be both supplementary and congruent, as the conditions of being supplementary and congruent are contradictory.

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Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 4 to the power of negative two.

Answers

The value of the given expression is approximately 0.5926

To evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 4 to the power of negative two, we can simplify the expression step by step.
The expression can be written as:
[tex](3^2 * 3^(-5)) / (4^(-2))[/tex](3^2 * 3^(-5)) / (4^(-2))
To simplify this, we can use the laws of exponents.
First, let's simplify the exponents:
[tex]3^2[/tex] = 3 * 3 = 9
[tex]3^(-5) = 1 / (3^5)[/tex]
Next, let's simplify the denominator:
[tex]4^(-2) = 1 / (4^2) = 1/16[/tex]
Now, we can substitute the simplified values back into the expression:
[tex](9 * 1 / (3^5)) / (1/16)[/tex]
To divide fractions, we can multiply by the reciprocal of the second fraction:
[tex](9 * 1 / (3^5)) * (16/1)[/tex]
Now, let's simplify further:
9 * 16 = 144
[tex]3^5 = 3 * 3 * 3 * 3 * 3 = 243[/tex]
Substituting the values back into the expression:
(144 / 243) = 0.5926

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Q and R are independent events. Find P(Q and R) . P(Q)=1/3, P(R)=6/7

Answers

The probability of the independent  events Q and R both occurring, P(Q and R)  is [tex]\dfrac{2}{7}[/tex] .

The possibility of occurrence of an event is called probability. Probability lies between 0 and 1.

[tex]Probability of an Event = \dfrac{Number of Favorable Outcomes}{ Total Number of Possible Outcomes}[/tex]

The events whose occurrence does not dependent on any other event are called  Independent events.

Example : If we flip a coin, we get either head or tail, here if we flip it again the next outcome is independent of the previous one.

According to question ;

[tex]P(Q and R) = P(Q) \times P(R)[/tex]

Substitute the values of [tex]P(Q) and P(R)[/tex]

[tex]P(Q and R) = \dfrac{1}{3} \times\dfrac{6}{7}[/tex]

On solving, we get,

[tex]P(Q and R) = \dfrac{6}{21}[/tex]

In lowest form, we get

[tex]P(Q and R) = \dfrac{2}{7}[/tex]

Therefore, the probability of the events Q and R both occurring, P(Q and R), is[tex]\dfrac{2}{7}[/tex].

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Solve each equation using the Quadratic Formula. 2 x²+5 x=7 .

Answers

The solutions of a quadratic equation are,

⇒ x = 1 and x = - 7/2

We have to give that,

A quadratic equation is,

⇒ 2x² + 5x = 7

Now, By using the Quadratic formula, we get;

⇒ 2x² + 5x = 7

⇒ 2x² + 5x - 7 = 0

⇒ 2x² + 7x - 2x - 7 = 0

⇒ x (2x + 7) - 1 (2x + 7) = 0

⇒ (x - 1) (2x + 7) = 0

This gives two solutions,

⇒ x - 1 = 0

⇒ x = 1

⇒ 2x + 7 = 0

⇒ 2x = - 7

⇒ x = - 7/2

Therefore, The solutions are,

⇒ x = 1 and x = - 7/2

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three cards are drawn without replacement from the 12 face cards (jacks, queens and kings) of an ordinary deck of 52 playing cards. let x be the number of kings selected and y the number of jacks selected.

Answers

The joint probability distribution function are;

P (Y = 3 | X = 1) = 1/55

P (Y = 2 | X = 2)  = 3/55

P (Y = 1 | X = 3)  = 12/55

P (Y = 0 | X = 4) = 1/220

To determine the joint probability distribution function, we have to find the probability of each possible outcome (x,y) for the random variables X and Y.

If X = 1, then select three cards of the same kind, that can only be a set of three jacks or three queens or three kings, or three aces.

P (Y = 3 | X = 1) = 4/220 = 1/55

If X = 2, then we are selecting two cards of one kind and one card of another kind. The first kind can be any of the four face card denominations, and the second kind can be any of the remaining three face card denominations. So, the number of possible sets is 4 × 3 = 12.

P (Y = 2 | X = 2) = 24/220 = 3/55

If X = 3, then we are selecting one card of each of three different kinds. The first kind could be any of the four face card denominations, the second kind could be any of the three remaining face card denominations, and the third kind can be any of the two remaining face card denominations.

P (Y = 1 | X = 3) = 1536/220 = 12/55

Finally, if X = 4, then we are selecting one card of each of the four different kinds, which could only be the four jacks.

P (Y = 0 | X = 4) = 1/220

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The complete question is

Three cards are drawn without replacement from the 12 face cards of an ordinary deck of 52 playing cards. Let X be the number of kinds selected and Y be the number of jacks selected. Find the joint probability distribution function.

To receive eredit, you must show some work for every problem even if the calculations are very simple. An answer without any work will receive 40 " points. To receive partial eredit, your work must be clearly organized and easy to read. If work is not well organized, neat and labeled, no credit will be awarded. A. LOPEZ PLASTICS CO. (25 pts) Lopez Plastics Co. (LPC) issued $200,000 of 10% callable bonds on February 1,2021 , dated January 1,2021 and due on January 1, 2026. The interest is to be paid twice a year on January 1 and July 1 . The bonds were sold to yield 8% effective annual interest. LPC incurred $5,000 in bond issue costs. LPC closes its books annually on December 31. Instructions (a) Complete the following amortization schedule for the dates indicated. (Round all answers to the nearest dollar.) Use the effective-interest method. Prepare the joumal entry for bond issuance.

Answers

The effective interest method is used to amortize the bond premium. The carrying value of the bond increases by the effective interest each period, and the premium is amortized over the life of the bond. The journal entry for bond issuance is as follows: Dr. Cash 205,000, Dr. Premium on Bonds Payable 5,000, Cr. Bonds Payable 210,000

The effective interest method is a method of amortizing bond premium or discount that takes into account the time value of money. The effective interest is the interest that would be earned if the bond were purchased at its market value and held to maturity. The carrying value of the bond increases by the effective interest each period, and the premium is amortized over the life of the bond.

The journal entry for bond issuance records the proceeds from the sale of the bonds, the premium on bonds payable, and the bonds payable. The proceeds from the sale of the bonds are equal to the face value of the bonds plus the premium.

The premium on bonds payable is a liability that represents the excess of the issue price of the bonds over their face value. The bonds payable account is a long-term liability that represents the amount that the company owes to the bondholders.

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Emily rented a truck to move her belongings from her old apartment to her new apartment. The company charges a flat rental fee of $21.50 with an additional $0.50 for each mile driven. If the total cost was at most $121, how far did Emily drive to move her belongings to her new apartment?
A.
at least 199 miles
B.
at most 199 miles
C.
at least 60.5 miles
D.
at most 242 miles

Answers

To solve this problem, we can use the given information to set up an equation. Let's assume Emily drove x miles.

The cost of renting the truck is $21.50, and she is charged an additional $0.50 for each mile driven. So, the total cost can be expressed as:

Total cost = $21.50 + ($0.50 * x)

According to the question, the total cost was at most $121. Therefore, we can write the inequality:

$21.50 + ($0.50 * x) ≤ $121

Now, let's solve for x:

$0.50 * x ≤ $121 - $21.50
$0.50 * x ≤ $99.50
x ≤ $99.50 / $0.50
x ≤ 199

So, Emily drove at most 199 miles. Therefore, the correct answer is B.

Answer:

B.

at most 199 miles

Step-by-step explanation:

To find how many miles Emily drove, we need to use the equation

Total cost = flat fee + miles driven * cost per mile

Substituting in the numbers

121 ≥ 21.50 + m * .5

121≥ 21.50 +.50m

Subtract 21.50 from each side.

99.50 ≥ .5m

Divide each side by .5

199 ≥m

Emily drove less than or equal to 199 miles

A pilot drops a bomb from a plane flying horizontally. where will the plane be located when the bomb hits the ground? group of answer choices

Answers

Neglecting air resistance, when the bomb hits the ground the horizontal location of the plane will be over the bomb.

Neglecting air resistance, when the bomb is dropped from a plane flying horizontally at a constant speed, the bomb will have both horizontal and vertical velocities. The horizontal velocity of the bomb will be the same as the plane's velocity since the bomb inherits the initial velocity of the plane. As a result, the bomb will continue moving horizontally with the same speed as the plane.

Since the plane and the bomb are moving together horizontally at the same speed, when the bomb hits the ground, the plane will be directly above the bomb.

Therefore, the horizontal location of the plane will be over the bomb.

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The complete question is:

A pilot drops a bomb from a plane flying horizontally at a constant speed. Neglecting air resistance, when the bomb hits the ground the horizontal location of the plane will

Answer

depend of the speed of the plane when the bomb was released.

depend of the mass of the bomb when it was released.

be behind the bomb.

be over the bomb.

be in front of the bom

If ac=150,BC=x,AB=2x what is the value of x

Answers

Answer:x=50

Step-by-step explanation:

Math puzzle please help​

Answers

The complete letter sequence is: B, H, I, J, O, T, U, V

How to complete the sequence?

The given sequence is:

_, H, I, _, O, T, _, V

Now, the last in the 26 alphabets we know that after T comes U and then V. Thus, the third blank space will be U.

Now, after O, we have, P, Q, R, S and then T. This means that 4 letters are skipped before T.

This means that 4 letters will also be skipped before H.

We have, A, B, C, D, E, F, G and then H. Therefore, after B, skipping 4 letters will lead to H. Thus, the first missing letter is B.

The second missing letter will be J because H, I, J

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The scores on an exam are normally distributed, with a mean of 85 and a standard deviation of 5 . What percent of the scores are between 85-95 ?

Answers

We can use the standard normal distribution, where the mean is 0 and the standard deviation is 1, and then convert our values to this standard distribution.

To convert the values, we use the formula:

z = (x - μ) / σ

where:

z is the z-score

x is the raw score

μ is the mean

σ is the standard deviation

For the lower value of 85:

z1 = (85 - 85) / 5 = 0

For the upper value of 95:

z2 = (95 - 85) / 5 = 2

Now we need to find the area under the standard normal curve between z1 = 0 and z2 = 2. We can use a standard normal distribution table or a calculator to find this value.

Using a standard normal distribution table or a calculator, we can find that the area to the left of z = 2 is approximately 0.9772.

Since we want the area between z1 and z2, we subtract the area to the left of z1, which is 0.5, from the area to the left of z2:

area = 0.9772 - 0.5 = 0.4772

To convert this area to a percentage, we multiply by 100:

percentage = 0.4772  100 = 47.72%

Therefore, approximately 47.72% of the scores fall between 85 and 95.

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