A set of data items is normally distributed with a mean of 90 and a standard deviation of 8. Convert 86 to a z-score.
Answers
Explanation
We are to find the z-score for the given data
To do so, we will use the formula:
[tex]z=\frac{x-\mu}{\sigma}[/tex]where
[tex]\begin{gathered} x=observed\text{ mean=86} \\ \mu=90 \\ \sigma=8 \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} z_{86}=\frac{86-90}{8}=-\frac{4}{8}=-0.5 \\ \\ z_{86}=-0.5 \end{gathered}[/tex]The z-score is -0.5
Related Questions
Find the difference of 8/15 and 1/6?
Answers
We find the LCM of the denominators as follows;
The multiples of 15 are;
[tex]15,30,45,60,75\ldots[/tex]The multiples of 6 are;
[tex]6,12,18,24,30,36,42,48\ldots[/tex]Thus, the lowest common multiple of 15 and 6 is;
[tex]30[/tex]Then,
[tex]\begin{gathered} \frac{8}{15}-\frac{1}{6}=\frac{\frac{30}{15}(8)-\frac{30}{6}(1)}{30} \\ \frac{8}{15}-\frac{1}{6}=\frac{2(8)-5(1)}{30} \\ \frac{8}{15}-\frac{1}{6}=\frac{16-5}{30} \\ \frac{8}{15}-\frac{1}{6}=\frac{11}{30} \end{gathered}[/tex]Thus, the difference is;
[tex]\frac{11}{30}[/tex]Triangle A is being rotated 90 degrees counter clockwise. Determine which triangle, would be the image of triangle A after the rotation II II IV
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You know that the rotation of a point in the plane 90 degrees counterclockwise is given by
[tex](x,y)\rightarrow(-y,x)[/tex]So, iIf triangle A has as coordinates
[tex]\begin{gathered} (-2,2), \\ (-6,8)\text{ and} \\ (-10,2) \end{gathered}[/tex]Its rotation 90 degrees counterclockwise, will have the coordinates
[tex]\begin{gathered} (-2,2)\rightarrow(-2,-2) \\ (-6,8)\rightarrow(-8,-6) \\ (-10,2)\rightarrow(-2,-10) \end{gathered}[/tex]Which correspond to triangle D in quadrant III.
You are buying sodas for a friends birthday party . You buy 50 packs . Cherry which costs $4.50 per pack, and vanilla which cots $5.00 per pack . In total you spent $238.50 on soda . Write the system of equations for this scenario.
Answers
Number of packs of Cherry soda: C
Number of packs of Vanilla soda: V
You buy 50 packs:
[tex]C+V=50[/tex]Cherry soda cost $4.50 per pack and Vanilla soda $5.00 per pack. In total you spent $238.50 on soda:
[tex]4.50C+5.00V=238.50[/tex]Then, the system of equations for the given scenario is:
[tex]\begin{gathered} C+V=50 \\ 4.50C+5.00V=238.50 \end{gathered}[/tex]To solve the system of equations:
1. Solve one of the variables in the first equation:
[tex]C=50-V[/tex]2. Substitute the C in the second equation by the value of C you get in step 1:
[tex]4.50(50-V)+5.00V=238.50[/tex]3. Solve V:
[tex]\begin{gathered} 225-4.50V+5.00V=238.50 \\ 225+0.5V=238.50 \\ 0.5V=238.50-225 \\ 0.5V=13.5 \\ V=\frac{13.5}{0.5} \\ \\ V=27 \end{gathered}[/tex]4. Use the value of V you get in step 3 and solve C:
[tex]\begin{gathered} C=50-V \\ C=50-27 \\ C=23 \end{gathered}[/tex]Then, you bought 23 packs of Cherry soda and 27 packs of Vanilla sodaThe series that corresponds to the sequence 2n + 9 is:
Answers
Answer:
The sequence is given below as
[tex]2n+9[/tex]step 1:
When n=1
[tex]\begin{gathered} 2n+9 \\ 2(1)+9 \\ =2+9 \\ =11 \end{gathered}[/tex]Step 2:
When n=2
[tex]\begin{gathered} 2n+9 \\ =2(2)+9 \\ =4+9 \\ =13 \end{gathered}[/tex]Step 3:
When n=3
[tex]\begin{gathered} 2n+9 \\ =2(3)+9 \\ =6+9 \\ =15 \end{gathered}[/tex]Step 4:
When n=4
[tex]\begin{gathered} 2n+9 \\ =2(4)+9 \\ =8+9 \\ =17 \end{gathered}[/tex]Step 5:
When n=5
[tex]\begin{gathered} 2n+9 \\ =2(5)+9 \\ =10+9 \\ =19 \end{gathered}[/tex]Step 6:
When n=6
[tex]\begin{gathered} 2n+9 \\ =2(6)+9 \\ =12+9 \\ =21 \end{gathered}[/tex]Hence,
The final answer is 11, 13, 15, 17,19, 21
Given the following geometric sequence, find the common ratio: (16, 64, 256,
Answers
Solution
Step 1:
Write the sequence
16, 64, 256,
Step 2
[tex]\begin{gathered} common\text{ ratio of a geometric sequence = }\frac{2^{nd}term}{1^{st}term}\text{ = }\frac{3^{rd}term}{2^{nd}term} \\ common\text{ ratio = }\frac{64}{16}\text{ = }\frac{256}{64}\text{ = 4} \end{gathered}[/tex]Final answer
Common ratio = 4
The line that contains the points (1,5) and (-3, 3). What is the equation of the line?
Answers
Given the following points that pass through a line:
Let,
Point A : (-3, 3)
Point B : (1, 5)
Let's determine the equation of the line in Slope-Intercept Form: y = mx + b
Step 1: Let's determine the slope of the line (m).
[tex]\text{ m = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]=\text{ }\frac{5\text{ - 3}}{1\text{ - (-3)}}\text{ = }\frac{5\text{ - 3}}{1\text{ + 3}}[/tex][tex]m\text{ = }\frac{2}{4}\text{ = }\frac{1}{2}[/tex]Step 2: Let's determine the y-intercept (b). Substitute m = 1/2 and x,y = 1,5 in y = mx + b.
[tex]\text{ y = mx + b}[/tex][tex]\text{ 5 = (}\frac{1}{2})(1)\text{ + b}[/tex][tex]5\text{ - }\frac{1}{2}\text{ = b}[/tex][tex]\frac{10}{2}\text{ -}\frac{1}{2\text{ }}\text{ = b}[/tex][tex]\text{ }\frac{9}{2}\text{ = b}[/tex]Step 3: Let's complete the equation. Substitute m = 1/2 and b = 9/2 in y = mx + b.
[tex]\text{ y = (}\frac{1}{2})x\text{ + (}\frac{9}{2})[/tex][tex]\text{ y = }\frac{1}{2}x\text{ + }\frac{9}{2}[/tex]Therefore, the equation of the line is y = 1/2x + 9/2.
2) 5x- 2y = 4 3x + y = 9 4) x - y = 2 4x - 3y = 12instructions: Solve by graphing. please show ur work and explain please??
Answers
On solving the system of equations graphically , we get the solution as x = 2 , and y = 3 .
In the question ,
the system of equations is given as
5x- 2y = 4
and 3x + y = 9
which can be written as
y = 9 - 3x
putting y = 9 - 3x in 5x- 2y = 4
we get
5x - 2(9 - 3x) = 4
5x - 18 +6x = 4
11x -18 = 4
11x = 18 + 4
11x = 22
x = 2
and y = 9-3(2) = 9 - 6 = 3
the solution is x=2 and y=3 .
From the graph given below , we can se that the point of intersection of the two lines is (2,3) , which is also the required solution .
Therefore , On solving the system of equations graphically , we get the solution as x = 2 , and y = 3 .
The given question is incomplete , the complete question is
Solve the system of equations graphically ,
5x- 2y = 4
and 3x + y = 9
Show your work and explain ?
Learn more about Equations here
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RecommendationsSkill plansMathLanguage artsScienceSocial studiesEE TX StandardsAlgebra 1> U.11 Solve a system of equations using elimination: word problems NHRYou have prizes to reveal! Go to your gaWrite a system of equations to describe the situation below, solve using elimination, and fill inthe blanks.A camp counselor for a summer day camp sometimes buys lunch for her campers at a nearbyfast food restaurant. On Monday, she purchased 6 hamburger kid meals and 7 chicken nuggetkid meals, for a total of $39. On Thursday, she spent $42 on 8 hamburger kid meals and 6chicken nugget kid meals. How much does each type of meal cost?Each hamburger meal costs $and each chicken nugget meal costs $Submit
Answers
Let x be the cost of a hamburger kid meal and y the cost of a chicken nugget kid meal
Monday: 6 hamburger kid meals and 7 chicken nugget kid meals for a total of $39:
[tex]6x+7y=39[/tex]Thursday: $42 on 8 hamburger kid meals and 6 chicken nugget meals:
[tex]8x+6y=42[/tex]System of equations:
[tex]\begin{gathered} 6x+7y=39 \\ 8x+6y=42 \end{gathered}[/tex]To solve by elimination:
1- Multiply first equation by 4 and second equation by -3
[tex]\begin{gathered} 4(6x+7y=39) \\ 24x+28y=156 \\ \\ -3(8x+6y=42) \\ -24x-18y=-126 \end{gathered}[/tex]2- Add both equations you get in step 1:
[tex]10y=30[/tex]3- Use the equation you get in step 2 to solve y:
[tex]\begin{gathered} 10y=30 \\ \text{Divide both sides of the equation into 10} \\ \frac{10}{10}y=\frac{30}{10} \\ \\ y=3 \end{gathered}[/tex]4- Use the value of y to solve x:
[tex]\begin{gathered} 6x+7y=39 \\ \\ 6x+7(3)=39 \\ 6x+21=39 \\ \\ \text{Subtract 21 in both sides of the equation:} \\ 6x+21-21=39-21 \\ 6x=18 \\ \\ \text{Divide both sides of the equation into 6:} \\ \frac{6}{6}x=\frac{18}{6} \\ \\ x=3 \end{gathered}[/tex]Solution:
[tex]\begin{gathered} x=3 \\ y=3 \end{gathered}[/tex]Each hamburger meal costs $3 and each chicken nugget meal costs $3Maya has 60 caramel apples to sell. Each caramel apple iscovered with one topping.1/3 of the caramel apples are covered with only peanuts. 1/5 are covered with only chocolate chips.• The rest are covered with only sprinkles How many of the caramel apples are covered with onlysprinkles?
Answers
Let:
T = total apples
P = apples covered with only peanuts
C = are covered with only chocolate chips
S = apples covered with only sprinkles
[tex]\begin{gathered} S=T-P-C \\ \text{where:} \\ T=60 \\ P=\frac{1}{3}\cdot60=20 \\ C=\frac{1}{5}\cdot60=12 \\ S=60-20-12=28 \end{gathered}[/tex]------------------------------------------------------
Let's evaluate each value:
[tex]\begin{gathered} -\frac{1}{2}x+3\ge5 \\ \text{for x=-6} \\ -\frac{1}{2}(-6)+3=3+3=6>5 \\ \text{This value satisfies the inequality.} \\ \text{for x=-4} \\ -\frac{1}{2}(-4)+3=2+3=5\ge5 \\ \text{This value satisfies the inequality.} \\ \text{for x=-3} \\ -\frac{1}{2}(-3)+3=4.5<5 \\ \text{This value doesn't satisfy the inequality} \\ \text{for x=1} \\ -\frac{1}{2}(1)+3=2.5<5 \\ \text{This value doesn't satisfy the inequality} \\ \text{for x=0} \\ -\frac{1}{2}(0)+3=3<5 \\ \text{This value doesn't satisfy the inequality} \\ \text{for x=2} \\ -1+3=2<5 \\ \text{This value doesn't satisfy the inequality} \end{gathered}[/tex]-6 and -4 only
50 pts! Help ASAP, will make brainliest
2. Graph the piecewise function f(x)= { 3x-5≤ if x≤-1 -2+3 if -1
Answers
See graph below
Explanation:f(x) = 3x - 5
for interval x ≤ -1
This means x is equal to -1 or less than - 1
values of x = -1, -2, -3,....
when x = -1
f(x) = 3(-1) - 5 = -8
when x = -2
f(x) = 3(-2) - 5 = -11
when x = -3
f(x) = 3(-3) - 5 = -14
f(x) = -2x + 3
for interval -1 < x < 4
Interval shows x is greater than -1 but less than 4
x = 0, 1, 2, 3
when x = 0
f(x) = -2(0) + 3 = 3
when x = 1
f(x) = -2(1) + 3 = 1
when x = 2
f(x) = -2(2) + 3 = -1
when x = 3
f(x) = -2(3) + 3 = -3
f(x) = 2 if the the interval is x ≥ 4
This means for x greater than or equal to 4, the function will be constant. we will have only 2
Sketching the graph of the piece wise function:
There is an equal sign attached to -1 in the first function, so the circle at x = -1 is shaded
The ends of the second function is open as there is no equal sign attached to the inequalities
There is an equal sign attached to 4 in the third function, so the circle at x = 4 is shaded
The arrows in function 1 and 3 indicate the line doesn't end
Find the unknown lights in the right triangle. If necessary, approximate the length to the nearest thousandth
Answers
In the given right triangle
Applying the Pythagorean Theorem
[tex]74^2=70^2+x^2[/tex]Solve for x
[tex]\begin{gathered} x^2=74^2-70^2 \\ x^2=576 \\ x=24\text{ ft} \end{gathered}[/tex]Therefore
The answer is 24 ft11) A scanner can scan 36 pages in 4 minutes. Choose a table below to show how many pages it can scan in 2 minutes. a) (Table below) c) (Table below) pages 36 18 9 pages 36 9 4 minutes 4 2 1 minutes 4 1 b) (Table below) d) (Table below) pages 4 N 1 pages 36 72 144 minutes 36 189 minutes 4 8 16
Answers
Table A is the correct choice that shows number of scanned pages in 2 minutes
Here, we want to select a table that best displays the number of pages that can be scanned in 2 minutes
Firstly, we need to get the rate at which the scanner is working per minute. This refers to the number of pages it can scan per minute
We have this as;
[tex]\frac{36\text{ pages}}{4\text{ minutes}}\text{ = 9 pages per minute}[/tex]What this mean is that it scans 9 pages in a minute
In two minutes, the number of scanned pages will be;
[tex]2\text{ minutes }\times\text{ 9 pages per minute = 18 pages}[/tex]So the correct table is the one that has;
a) 36 pages for 4 minutes
b) 18 pages for 2 minutes
c) 9 pages for 1 minute
The correct table is the first tableOptio
Slope is -2/7 and (-14,-5) is on the line.
Answers
The equation of a line
There are several forms in which a line can be expressed. One of the most-used is the point-slope form. Its equation is as follows:
[tex]y-k=m\mleft(x-h\mright)[/tex]Here, m is the slope of the line, and (h,k) is the point it passes through.
We are given the slope m=-2/7 and the point (-14,-5). Substituting into the given equation, we have:
[tex]y-(-5)=-\frac{2}{7}(x-(-14))[/tex]Please note both coordinates are negative and they will become positive when multiplied by the preceding sign.
Operating:
[tex]y+5=-\frac{2}{7}(x+14)[/tex]This is the equation of the line in point-slope form
We are required to use the slope-intercept form.
To convert to the required form, we need to eliminate the parentheses and simplify
Identify the pairs of corresponding angles and the pair of corresponding sides of the similar triangles below
Answers
SOLUTION
Two triangles are similar if their corresponding angles are equal and the corresponding sides are in proportion.
Hence from the triangles in the question,
[tex]\begin{gathered} \measuredangle A\text{ }\cong\measuredangle D \\ \measuredangle C\text{ }\cong\measuredangle F \\ \measuredangle B\cong\measuredangle E \end{gathered}[/tex]Then the sides
[tex]\begin{gathered} |AB|\text{ corresponds to|ED|} \\ |BC|\text{ correspounds to |EF|} \\ |AC|\text{ correspounds to |DF|} \end{gathered}[/tex]
Write your answers in simplified, rationalized form. DO NOT ROUND
Answers
We can use the cosine trigonometric reason to find the hypothenuse WX:
[tex]\begin{gathered} \cos 45=\frac{4}{WX} \\ WX=\frac{4}{\cos45}=\frac{4}{\frac{\sqrt[]{2}}{2}}=\frac{8}{\sqrt[]{2}}\cdot\frac{\sqrt[]{2}}{\sqrt[]{2}}=\frac{8\sqrt[]{2}}{2}=4\sqrt[]{2} \end{gathered}[/tex]We can use the tangent function to find the leg XY.
[tex]\begin{gathered} \tan 45=\frac{XY}{4} \\ XY=\tan 45\cdot4 \\ XY=1\cdot4 \\ XY=4 \end{gathered}[/tex]At last, we use the interior angles theorem to find angle X, which states that the sum of all three interior angles of a triangle must sum 180°.
[tex]\begin{gathered} m\angle X+45+90=180 \\ m\angle X=180-90-45 \\ m\angle X=45 \end{gathered}[/tex]what is 1.5×0.9×0.6=and can you pls show how you slove it
Answers
Evaluate the value of expression.
[tex]\begin{gathered} 1.5\times0.9\times0.6=1.35\times0.6 \\ =0.81 \end{gathered}[/tex]Answer: 0.81
Triangle DEF is similar to triangle GHI. Find the measure of side GH. Round your answer to the nearest tenth. I E 19 14 H 58 D
Answers
let GH by x. So we get that
[tex]\frac{58}{19}=\frac{x}{14}\rightarrow x=14\cdot\frac{58}{19}\approx42.7[/tex]so the length of GH is 42.7
once a week you babysit your neighbor's toddler after school, usually going to a local playground. You notice that each swing on the swing set takes about the same amount of time, about 2.2 seconds. Use the pendulum formula below to find out how long the swing is. Round your answer to the tenths place.
Answers
We know that T = 2.2, so let's replace it in the equation and solve for L.
[tex]\begin{gathered} T=2\pi\sqrt[]{\frac{L}{32}} \\ \frac{2.2}{2\pi}=\sqrt[]{\frac{L}{32}} \\ \frac{2.2}{2\cdot3.14}=\sqrt[]{\frac{L}{32}} \\ \frac{2.2}{6.28}=\sqrt[]{\frac{L}{32}} \\ \sqrt[]{\frac{L}{32}}=0.35 \\ \frac{L}{32}=(0.35)^2 \\ L=32\cdot0.1225 \\ L\approx3.9 \end{gathered}[/tex]Hence, the length is 3.9 feet. A is the answer.Solve the system of equations below by graphing. x-y=1.57x+y=3.48
Answers
Answer : (0.96, 2.53)
Given the below system of equations
x - y = -1.57 ------------- equation 1
x + y = 3.48------------- equation 2
To find the y intercept of the first equation, make x = 0
x - y = -1.57
when x = 0
0 - y = -1.57
-y = -1.57
y = 1.57
To find x, let y = 0
x - y = -1.57
x - 0 = -1.57
x = -1.57
Therefore, we have (-1.57, 1.57)
Second equation
x + y = 3.48
To find y, make x = 0
0 + y = 3.48
y = 3.48
To find x let y = 0
x + y = 3.48
x +0 = 3.48
x = 3.48
Therefore, we have (3.48, 3.48)
We will now graph the above points
Therefore, the solution of the system of the equation is
x = 0.96 and y = 2.53
(0.96, 2.53)
Find the probability that a randomly selected person from this group moderate, given they have only a high school education
Answers
Let:
A = The person is moderate
B = The person has a high school education
so:
[tex]P(A|B)=\frac{35}{11+35+21}=\frac{35}{67}[/tex]Answer:
35/67
Express the interval in set-builder notation and graph the interval on a number line.
Answers
we need to find the interval of number that belong to both interval, so:
So the answer is: [-3,-2)
7/8 sticks of butter for 1 1/4 flour. rate of flour to sticks of butter
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Therefore,
[tex]\begin{gathered} \frac{7}{8}\text{ sticks of butter = 1}\frac{1}{4}\text{ flour} \\ 1\text{ stick of butter = ?} \\ \text{rate}=\frac{1\frac{1}{4}}{\frac{7}{8}} \\ \text{rate}=\frac{\frac{5}{4}}{\frac{7}{8}} \\ \text{rate}=\frac{5}{4}\times\frac{8}{7}=\frac{40}{28}=\frac{10}{7} \\ \text{rate}=\frac{10}{7}\text{ flour per stick of butter} \end{gathered}[/tex]A rectangular prism has a base with a length of 21 meters and a width of 18 meters. The height of the prism measures half of its width. What is true about the rectangular prisonEnter the correct answers in the boxescubic metersmeters, so its volume isThe height of the prism measures meters,so it’s volume is cubic meters
Answers
The volume of a rectangular prism is given by length times width times height.
V = l * w * h
l = 21
w=18
h = 18/2 = 9
V = 21*18*9
=3402 cubic meters
Write an expression for the perimeter of the triangle shown below 23x + 14 30 2x + 15 0 25x + 29
Answers
The formula for finding the perimeter of a triangle is as stated below;
Perimeter of a triangle = Sum of the three sides of the triangle
Let's assume that the three sides of the triangle are 23x + 14, 2x + 15, and 25x + 29, the expression for the perimeter of the triangle can be given as;
[tex]\begin{gathered} \text{Perimeter of the triangle }=(23x+14)+(2x+15)+(25x+29) \\ =50x+58 \end{gathered}[/tex]Therefore, the expression for the perimeter of the triangle with sides 23x + 14, 2x + 15, and 25x + 29 is;
Perimeter = 50x + 58
The graph of Fx), shown below, has the same shape as the graph of G(x) = x - x2, but it is shifted to the left 1 unit. What is its equation? F(x) = O A. FX) = x2.2.1 x O B. F(x) = (x-1) 6-12 1 O c. Ax) = x. x2 +1 C. X OD. F(x) = (x + 1) - (x + 12
Answers
Find the direction angle of v for the following vector.
Answers
To solve this problem, we will use the following formula for the direction angle of a vector x=ai+bj:
[tex]\tan \theta=(\frac{b}{a}).[/tex]In the given problem:
[tex]\begin{gathered} a=-8\sqrt[]{3}, \\ b=8. \end{gathered}[/tex]Therefore:
[tex]tan\theta=(\frac{8}{-8\sqrt[]{3}})\text{.}[/tex]Simplifying the above result, we get:
[tex]\tan \theta=(-\frac{1}{\sqrt[]{3}}).[/tex]Therefore, since the vector is in the second quadrant, we get:
[tex]\theta=150^{\circ}.[/tex]Answer:
[tex]150^{\circ}.[/tex]Geometry- Question #8a) none of the the optionsb) Triangle DEG is not congruent to triangle FGEFGEc) Triangle DEG is congruent to triangle FGE ; all corresponding sides and angles are congruent.
Answers
Option C:
Triangle DEG is congruent to triangle FGE ; all corresponding sides and angles are congruent.
Explanation:The rectangle DEFG is divided into two triangles. That is △DEG and △FGE
From the diagram shown:
DE ≅ GF
DG ≅ EF
Note that the two sides EF and GF with an included < F in △FGE are equal to DE and DG with an included △DEG.
The SAS rule states that two triangles are congruent if two sides and an included angle of one is equal to the corresponding two sides and an included angle of the other
Therefore, the two triangles △DEG and △FGE are congruent by the Side-Angle-Side rule of congruence (SAS rule)
-1/ -8 positive or negative
Answers
Answer:
Step-by-step explanation:
I believe that the answer is 0.125
Negative and negative = positive
1/8=0.125
An equation is a (blank) sentence with an equal sign = between the two expressions. A coefficient is the (blank) factor that appears (blank) a varible: y=kx.Equations of the form y=kx represents (blank) relationships, where k is called the . Notice that in the form, nothing is added or subtracted in the equation. y=3xx y0 (blank) 1 (blank) 2 (blank) (blank) 9y/x=6/2= (blank)
Answers
An equation is a mathematical sentence with an equal sign = between the two expressions.
A coefficient is the numerical factor that appears before a varible: y=kx.
Equations of the form y=kx represents linear relationships, where k is called the .
Given y=3x. Substitute the value of x to find the value of y.
[tex]\begin{gathered} \text{When x=0, y=3}\ast0=0 \\ \text{When x=1, y=3}\ast1=3 \\ \text{When x=2, y=3}\ast2=6 \\ \end{gathered}[/tex][tex]\frac{y}{x}=\frac{6}{2}=3[/tex]A mail truck traveled 102 miles in 3 1/2 hrs. The distance is the product of the rate and the time. To the nearest tenth, what was the average speed of the mail truck?
Answers
Total distance tarvelled= 102 miles
Total time taken =3.5 hrs
Speed is given by,
[tex]\begin{gathered} \text{Speed}=\frac{Dis\tan ce}{\text{Time}} \\ \text{ =}\frac{102}{3.5}=29.14\text{ miles/hour} \end{gathered}[/tex]To the nearest tenth the speed is 30 miles/hour.
