Explanation:
A simple machine has efficiency 90℅, it means that 90% of the applied force is used in doing useful work and 10% is wasted due to overcoming friction.
I tried zooming it in more, please help-
Answer:
Explanation:
a) 6 mm or 0.6 cm or 0.06 dm or 0.006 m or 0.000006 km
b) 12 mm or 1.2 cm or 0.12 dm or 0.012 m or 0.000012 km
c) 22 mm or 2.2 cm or 0.22 dm or 0.022 m or 0.000022 km
d) 37 mm or 3.7 cm or 0.37 dm or 0.037 m or 0.000037 km
e) 56 mm or 5.6 cm or 0.56 dm or 0.056 m or 0.000056 km
f) 67 mm or 6.7 cm or 0.67 dm or 0.067 m or 0.000067 km
g) 75 mm or 7.5 cm or 0.75 dm or 0.075 m or 0.000075 km
Two boats start together and race across a 44 km wide lake and back. Boat A goes across at 44 km/h and returns at 44 km/h. Boat B goes across at 22 km/h, and its crew, realizing how far behind it is getting, returns at 66 km/h. Turnaround times are negligible, and the boat that completes the round-trip first wins.
Which boat wins and by how much? (Or is it a tie?)
(a) By how much? (Enter NONE if it was a tie.)
km
(b) What is the average velocity of the winning boat? (Enter NONE if it was a tie.)
km/h .... I put 44 for this answer and it was.
Answer:
a. 44 km
b. 0 km/h
Explanation:
For part a, the faster boat finishes when the second turns around to come back.
For part b, the average velocity is zero because he travels forward (+) and then back (-). 44km/h - 44 km/h = 0 km/h
3. Write "T" for true statements and "F" for false statements:
a. Protozoa are multi cellular animals.
b. Vacuoles are larger in plant cell.
c. Body of mammals is covered with feathers.
d. There is a pair of antenna on the head of a cockroach.
e. Birds have hollow and air filled bones.
Answer:
F
T
F
T
T
Explanation:
Thanks for this oppurtunity
The speed of sound through air is approximately 343 m/s. What is the speed in miles per hour
Answer:
At 20 °C (68 °F), the speed of sound in air is about 343 metres per second (1,235 km/h; 1,125 ft/s; 767 mph; 667 kn), or a kilometre in 2.9 s or a mile in 4.7 s.
PLEASE MARK ME BRAINLIEST.7) Somewhere you place a 7.5 kg pumpkin on a spring scale. If the scale reads 78.4 N,
what is the acceleration due to gravity at that location?
Answer:
10.45m/s^2
Explanation:
Cause acceleration is the force divided by the mass
Tina drove 3 miles north and 4 miles west to get to her grandmother’s house. Find the distance and displacement.
Answer:
distance = 3 + 4 = 7 mi
displacement is √(3² + 4²) = 5 mi
Explanation:
how physical science can be truth?
Determine the order of magnitude of the following small number by entering the appropriate exponent n below:
6,370 ≈ 10^n km
The complete question is;
Determine the order of magnitude of the following small number by entering the appropriate exponent n below: 6,370km≈10^n km .
Order of magnitude is 3.
Now, when dealing with order of magnitude, we first write the number in scientific notation. We will have; 6.37 × 10³ kmThe second thing we now do is to approximate the numerical part to either 1 or 10 as the case may be.In this case, we have 6.37 and it is closer to 10 than 1.
Thus, rewriting our number, we now have; 10 × 10³ kmThe order of magnitude is the exponent attached to the 10 on the right.
Thus, order of magnitude is 3.
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The order of magnitude of the given number will be "3.804".
According to the question, the number is:
→ [tex]6370 \ km = 10^n \ km[/tex]
By taking "[tex]log_{10}[/tex]" both sides, we get
→ [tex]log_{10}(6370) = log_{10} \ 10^n[/tex]
By putting the values accordingly, we get
→ [tex]log_{10} (6370) = n[/tex]
→ [tex]n = 3.804[/tex]
Thus the above answer is correct.
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A force of 5000 N is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 mm and a Young's modulus of 125 x 108 N/m^2. The elongation of the rod is:
a. 0.55 mm
b. 1.42 mm
c. 0.0040 mm
d. 0.11 mm
e. 0.022 mm
Answer:
0.55 mm
Explanation:
E = σ/ε
E = (F/A) / (ΔL/L₀)
ΔL/L₀ = F/EA
ΔL = FL₀/EA
ΔL = 5000(5.0) / (125e8(π(0.034²)))
ΔL = 0.00055070914... m
With that Young's modulus our shaft may be made of strong wood such as oak or douglas fir, or possibly lead.
A car traveling at 7.5 m/s accelerates 3.8
m/s2 to reach a speed of 14.0 m/s.
How long does it take for this acceleration
to occur?
Answer:
1.71s
Explanation:
Acceleration = the change in velocity / the change in time
Or I can write it as
a = V2 - v1
- - - -----
t
V1 (initial velocity) = 7.5m/s
V2 ( final velocity) = 14.0m/s
a =3.8m/s^-2
Therefore
a= V2 - V1
- - - - - - - -
t
t = V2 - v1
- - - - - - -
a
t = 14 - 7.5
- - - - - -
3.8
t = 1.71s
At the end of a race, a runner decelerates from a velocity of 9.00 m/s at a rate of 2.00 m/s2 .
(a) How far does she travel in the next 5.00 s?
(b) What is her final velocity?
(c) Evaluate the result. Does it make sense?
Answer:
20m; -1m/s; doesn't make sense.
Explanation:
(a) v=u-at
v=9-2×5
v=-1 m/s
Now, v²=u²-2as
(-1)²=(9)²-2×2×s
4s=81-1=80
s=80/4=20m
(b) v=u-at
v=9-2×5
v=-1 m/s
(c) A runner starts the race at a velocity of 9 m/s and then decelerates at a rate of 2m/s² and her final velocity is -1m/s. This doesn't make sense because that negative final velocity means the runner is running backwards.
what does mercaptan smell like?
Answer:
its been said that is smells like rotten eggs or rotten cabbage.
Explanation:
Depending on the makeup of your olfactory senses, Ethyl Mercaptan most often is reported to smell like rotten eggs or sometimes rotten cabbage. Some also say it has a strong garlic, or skunk-like, smell
Answer: Depending on the makeup of your olfactory senses, Ethyl Mercaptan most often is reported to smell like rotten eggs or sometimes rotten cabbage. Some also say it has a strong garlic, or skunk-like, smell.
d. Hydrogen gas is filled in two
identical bottles, A and B, at the
same temperature. The mass of
hydrogen in the two bottles is 12
gm and 48 gm respectively. In
which bottle will sound travel
faster? How may times as fast as
the other?
(Ans: In A; Twice)
Explanation:
B I think it is because it has 48 gm than A
A bicyclist steadily speeds up from rest to 6.00m/s in 7.30s.
How far did she travel during this time?
Answer:
21.899 m
Explanation:
The explanation here is a little differe because we are starting from rest. So, everyone does physics a little differently, but what I would start with is trying to find the accelaration. I've given the formula, now you are able to plug this into the displacement formula where you Velocity Initial = 0m/s (Since you are starting from rest) and V final = 6.00 m/s...
You just plug numbers into the formula after solving for accelaration and do some simple algebra! I hope this helps! I am attaching a new pdf for visuals! If you can't open it let me know! Also there is a star by accelaration because I didn't know if I spelled it right, sorry!
List two pieces of evidence
related to this picture
Answer:
there was a crash you can tell cause of the 2 cars the dog is curious on what happened, you can tell because the dog is looking at the cash
I NEED THE ANSWER TO THIS SO I CAN GET MY PHONE BACK
An object accelerates uniformly from rest to a speed of
50 meters per second in 5.0 seconds. The average speed of
the object during the 5.0-second interval is
A 5.0 m/s
B 10 m/s
C 25 m/s
D 50 m/s
Answer:
25
Explanation:
v=u+at.
50=a(5)
a=10m/s^2.
distance= ut+ 1/2 at^2
=125
average speed = total distance/total time
=125/5
=25
The average speed of the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.
Hence, Option C) 25 m/s is the correct answer.
Given the data in the question;
Since the object was initially at rest,
Initial velocity; [tex]u = 0[/tex]Final velocity; [tex]v = 50m/s[/tex]Time; [tex]t = 5.0s[/tex]
First we determine the acceleration "a", using the First equation of motion:
[tex]v = u + at[/tex]
Where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
We substitute our values into the equation
[tex]50m/s = 0 + ( a \ * \ 5.0s)\\\\a = \frac{50m/s}{5.0s} \\\\a = 10m/s^2[/tex]
Next we Calculate the distance travelled by the object
From the Second Equation of Motion:
[tex]s = ut \ + \ \frac{1}{2}at^2[/tex]
Where, u is the initial velocity, a is the acceleration and t is the time and s is the distance travelled.
Wes substitute our values into the equation
[tex]s = (0\ * 5.0s) + ( \frac{1}{2} \ *\ 10m/s^2 \ * (5.0s)^2)\\\\s = \frac{1}{2} \ *\ 10m/s^2 \ * 25s^2\\\\s = 125m[/tex]
Now, we can get the Average speed of the object.
We know that, Speed is the distance travelled per unit time.
[tex]Speed = \frac{Distance}{Time}[/tex]
We substitute our values into the equation
[tex]Speed = \frac{125m}{5.0s}\\\\Speed = 25m/s[/tex]
The average speed of the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.
Hence, Option C) 25 m/s is the correct answer.
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john doe operates a crane that can pick up 3.0 tons of excavated earth in an hour. John's wages are $35 per hour. What, then, is the cost of picking up 85kg of excavated earth?
Answer:
1
Explanation:
2. Determine the units of the quantity described by each of the following
combinations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s)
c. (kg/s) (m/s)
d. (kg/s) (m/s)
We have that the unit of the quantities are described
a.kg (m/s) (1/s)=Newton
b. (kg/s) (m/s^2)=Newton
c. (kg/s) (m/s)^2=Newton
d. (kg/s) (m/s)=Newton
From the question we are give the units
a.kg (m/s) (1/s)
b. (kg/s) (m/s^2)
c. (kg/s) (m/s)^2
d. (kg/s) (m/s)
a)
Generally
kg (m/s) (1/s) is Represented as Newton
Where Newton is the unit Force and Weight
b)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
c)
kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
d)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
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An electron and a proton, initially at rest, are pushed by the same force. Which of the two will have greater velocity?
A) proton
B) electron
C) they will have different acceleration but the same velocity
D) the velocity of both the electron and the proton will be same.
Answer:
B electron
Explanation:
electron will have greater velocity
What would make oppositely charged objects attract each other more?
o increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object
O decreasing the positive charge of the positively charged object and decreasing the negative charge of the negatively charged object
O increasing the distance between the positively charged object and the negatively charged object
O maintaining the distance between the positively charged object and the negatively charged object
Answer:
a: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object
Explanation:
The oppositely charged objects attract each other more is option a. It increased the positive charge and the negative charge.
The Attraction of the oppositely charged:At the time when the oppositely charged objects are attracted to each other more so here the positive charge should be increased with respect to the positive charge object and the negative charge is increased with respect to the negative charge object
Hence, the first option is correct.
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An object which starts at the origin is traveling in the positive direction with a constant velocity V. After traveling a distance D with this constant velocity, the object begins to slow down at a constant rate until it stops after traveling an addition distance of 2D. In terms of D and V, determine the average velocity of the entire trip.
Answer:
Explanation:
time to travel first leg
D = Vt₁
t₁ = D/V
time to travel second leg.
at constant deceleration, the average velocity will be half of the original.
2D = (V/2)t₂
t₂ = 4D/V
t = t₁ + t₂ = 5D/V
Vavg = d/t = (D + 2D)/(5D/V) = (3D/5D)V = 0.6V
With the concept of kinematics we find the average speed is 0.6V
given parameters
* initial velocity V
* the distances in each part of the movements x₁ = D and x₂ = 2D
to find
The average speed of the entire trajectory
In kinematics we analyze the motion of bodies, the average velocity is defined by
[tex]V_{avg} = \frac{\Delta x}{\Delta t}[/tex] 1
where [tex]V_{avg}[/tex] is the average velocity, Δx and Δt are the variation of displacement and time in the interval
For this exercise we have two types of movement in the first part a uniform movement and in the second part an accelerated movement let's solve each onaccelerated movement,e separately
1 Part. uniform motion
we look for the time
V = [tex]\frac{x_1}{t_1}[/tex]
t₁ = x₁ / V
t₁ = [tex]\frac{D}{V}[/tex]
2 Part. Accelerated movement, let's start by looking for acceleration, they tell us that the body stops at the end of the interval so its velocity is zero v_f=0, the initial velocity is v₀ = V
[tex]v_f^2 = v_o^2 - 2 \ a \ x_2[/tex]
0 = v₀² - 2 a x₂
a = [tex]\frac{v_o^2}{2x_2}[/tex]
we substitute
a = [tex]\frac{V^2}{D}[/tex]
now we look for the time it takes to stop
v = v₀ - a t₂
0 = v₀ - a t₂
t₂ = [tex]\frac{v_o}{a}[/tex]
we substitute
t₂ = [tex]\frac{V}{\frac{V^2}{4D} }[/tex]
t₂ = [tex]\frac{4D}{V}[/tex]4D / V
for the entire movement, the total displacement is
Δx = x₁ + x₂
Δx = D + 2D
Δx = 3D
the total time is
Δt = t₁ + t₂
Δt = [tex]\frac{D}{V} + \frac{4D}{V}[/tex]
Δt = [tex]\frac{5D}{V}[/tex]
we substitute in equation 1 of average velocity
[tex]V_{avg} = \frac{3D}{\frac{5D}{V} }[/tex]
[tex]V_{avg} = \frac{3}{5} \ V[/tex]
[tex]V_{avg } = 0.6 V[/tex]
With the use of the kinematics equations with constant acceleration we can find the average velocity of the body throughout the journey is 0.6V
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How do
thermal energy and
temperature differ ?
Answer:
Thermal energy adds up kinetic energy of all the molecules in it while temperature is the average kinetic energy of molecules
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other.
What is most likely the phase of the substance?
gas
liquid
solid and gas
liquid and solid
Liquid substance has the most likely phase.
What is solid, liquid and gas and how they relate to the phase?Solid:
In the solids, the particles are arranged orderly and closely packed.The attractive forces between particles are very strong.Particles also gets vibrate about a fixed point.The spaces between the particles are extremely small.Liquid:
In the liquids, the particles arranged randomly but closer than gas and they are also closely packed but further apart than solids.The attractive forces between particles are strong but less than solids.Particles slide or roll over one on the another randomly.There will have some spaces but lesser than gas.Gas:
The particles in the gases are random, far apart from one another.The attractive forces are very weak.There will be no regular movement.The movement will also be freely done.Hence, the correct answer is Option B, liquid.
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If vector A has components Az = -3.00 and Ay = -4.00, then the magnitude of A is
Answer:
√((-3.00)² + (-4.00)²) = 5.00
Explanation:
The formula to determine the magnitude of a vector (in two dimensional space) v = (x, y) is: |v| =√(x2 + y2). This formula is derived from the Pythagorean theorem.
|v| =√(x2 + y2).
V = √((-3.00)² + (-4.00)²)
= 5.00
What is vector ?"A quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. "Although a vector has magnitude and direction, it does not have position.
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A fertilized human egg cannot grow into a crocodile duck or fish because
Answer:
A fertilized human egg cannot grow into a crocodile, duck or fish specifically because of: genetic code. is a stage in reproduction whereby an egg and a sperm fuse to create a single cell.
Explanation:
Because of ; Genetic Code
A car moves with uniform velocity of 40m/s for 5 s. It comes to rest in the next 10 s with uniform deceleration
Answer:
-8 m/s²
Explanation:
Initial velocity = 40 m/s
Final velocity = 0 m/s
Time (T1) = 5 s
Time (T2) = 10 s
Acceleration = v - u/t2 - t1
Acceleration = 0 - 40/10 - 5
Acceleration = -40/5
Acceleration = -8 m/s²
A shot putter puts the shot at a velocity of 14 m/s (assume this represents a constant horizontal
velocity). The shot is in the air for 1.4 seconds. How far did the shot travel?
S = (v-u)t/2
s = (14)1.4/2
s = 9.8m
The range of the shot will be "19.6 m". A complete solution is provided below.
The given values in the question are:
Horizontal velocity,
v = 14 m/s
Time,
t = 1.4 sec
Now,
The Range will be:
= [tex]Velocity\times Time[/tex]
By putting the given values, we get
= [tex]14\times 1.4[/tex]
= [tex]19.6 \ m[/tex]
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i though a=9.8 is in free fall?
show that Newton's first law is the special case of Newton's second law of motion
Please find attached photograph for your answer. Please do comment whether it is useful or not.
