a single conservative force Fx= (2x+7) N acts on a particle of mass 6 kg as the particle moves along the X-axis from X1 = 1 m to X 2 = 5m. calculate the work done by this force​

Answers

Answer 1

Answer:

To calculate the work done by a force, we can use the formula:

Work = ∫F dx

In this case, the force is given by Fx = (2x + 7) N, and the particle moves along the X-axis from X1 = 1 m to X2 = 5 m. Let's calculate the work done.

Work = ∫(2x + 7) dx

Integrating the function (2x + 7) with respect to x, we get:

Work = (x^2 + 7x) evaluated from X1 to X2

Plugging in the values X2 = 5 and X1 = 1 into the expression, we have:

Work = (5^2 + 7 * 5) - (1^2 + 7 * 1)

= (25 + 35) - (1 + 7)

= 60 - 8

= 52

Therefore, the work done by the force is 52 Joules (J).

Explanation:


Related Questions

which action would a chemist most likely take to determine how substances in a fuel affect the types

Answers

A chemist would most likely conduct a controlled combustion experiment to determine how substances in a fuel affect the types of combustion products produced.

A 50-kg ice skater turns a bend at 7 m/sec. If the radius of the curve is 5 m, what is the centripetal force in Newtons provided by the friction between the blade of the skate and the ice?

Answers

The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N

How do i determine the centripetal force?

The following data were obtained from the question:

Mass of ice skater (m) = 50 KgVelocity (v) = 7 m/sRadius (r) = 5 metersCentripetal force (F) =?

The centripetal force can be obtained as illustrated below:

F = mv²/r

= (50 × 7²) / 5

= (50 × 49) / 5

= 2450 / 5

= 490 N

Thus, we can concluded that the centripetal force is 490 N

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(a) Seismographs measure the arrival times of earthquakes with a precision of 0.100 s. To get the distance to the epicenter of the quake, they compare the arrival times of S- and P-waves, which travel at different speeds. Figure 16.44) If S- and P-waves travel at 4.00 and 7.20 km/s, respectively, in the region considered, how precisely can the distance to the source of the earthquake be determined? (b) Seismic waves from underground detonations of nuclear bombs can be used to locate the test site and detect violations of test bans. Discuss whether your answer to (a) implies a serious limit to such detection. (Note also that the uncertainty is greater if there is an uncertainty in the propagation speeds of the S- and P-waves.)

Answers

The distance to the source of the earthquake can be determined with a precision of approximately 1.3 km.

a)The speed of the P-wave is 7.20 km/s and the speed of the S-wave is 4.00 km/s. We want to calculate the precision with which the distance to the source of the earthquake can be determined. The time taken by the P-wave and the S-wave to reach the seismograph station will differ by the time required by the P-wave to travel from the source to the station minus the time taken by the S-wave to do so.Using this equation, we can get the time difference between the P and S waves:

∆t = tP - tS = d/vP - d/vS,

where d is the distance to the epicenter, vP is the speed of the P-wave, and vS is the speed of the S-wave. Rearranging the equation: d = vS ∆t / (vP - vS)We want to know how precisely we can determine the distance, given that seismographs measure the arrival times of earthquakes with a precision of 0.100 s. We will therefore use the propagation velocities provided in the question to calculate the precision with which the distance can be measured.Using the velocities given:

vP = 7.20 km/s and vS = 4.00 km/s,

we can calculate the distance to the epicenter as follows: Substitute the values in the equation we get:

d = (4.00 km/s) (0.100 s) / (7.20 km/s - 4.00 km/s) = 1.3 km Therefore, the distance to the source of the earthquake can be determined with a precision of approximately 1.3 km.

b)Seismic waves from underground detonations of nuclear bombs can be used to detect violations of test bans and locate the test site. Seismic waves from underground explosions are used to detect nuclear explosions by detecting seismic waves that are produced by the explosion and transmitted through the Earth. These waves travel in a manner similar to those produced by an earthquake, and their arrival times can be used to determine the epicenter of the explosion. There is a significant limit to such detection as a result of

the uncertainty in the propagation velocities of the S- and P-waves. If there is an uncertainty in the propagation speeds of the S- and P-waves, then the precision with which the distance to the source of the earthquake can be determined will be even greater. If there is an uncertainty in the propagation speeds of the S- and P-waves, it is critical to take it into account when attempting to detect underground nuclear explosions.

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The thermal conductivity of copper at 300 K is 470.4 Wm ¹K¹. Calculate the electrical conductivity of copper at 300 K (L-2.45 X10 WOK -2)

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The electrical conductivity of copper at 300 K is 0.566 x 10⁸ Sm⁻¹.

Thermal conductivity and electrical conductivity are two different physical quantities used to describe the ability of a material to conduct heat and electricity respectively. Copper is a metal known to be an excellent conductor of both heat and electricity.

The relationship between thermal conductivity and electrical conductivity in copper is given by the Wiedemann-Franz Law, which states that the ratio of the electrical conductivity to thermal conductivity of a metal is proportional to its temperature.

To calculate the electrical conductivity of copper at 300 K, we will make use of the Wiedemann-Franz Law. The law states that:σ / κ = L T Where σ is the electrical conductivity, κ is the thermal conductivity, L is the Lorenz number, and T is the temperature of the material.

Substituting the values given in the problem, we get:σ / 470.4 = (2.45 x 10⁻⁸) x 300σ = (2.45 x 10⁻⁸) x 300 x 470.4σ = 0.566 x 10⁸ Sm⁻¹Therefore, the electrical conductivity of copper at 300 K is 0.566 x 10⁸ Sm⁻¹.

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What is audience going to be in the nine grade physic MCAS 

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The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

How to explain the information

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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What is the period of a mass-spring system with the following characteristics?

Answers

the period of a mass-spring system with the  characteristics can be calculated using the formula T = 2π√(m/k), where m is the mass of the object and k is the spring constant. the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

A mass-spring system has the following characteristics: A spring that is initially stretched or compressed has an oscillatory motion around its equilibrium position. This is referred to as a mass-spring system.The period of the mass-spring system is the time it takes for one complete cycle, including compression and extension. The period is given by the equation

`T = 2π * √(m/k)`,

where T is the period, m is the mass attached to the spring, and k is the spring constant. Let's consider an example to better understand this formula: Suppose a mass of 5 kg is attached to a spring with a spring constant of 20 N/m. What is the period of the system?

T = 2π * √(m/k) = 2π * √(5/20) = 2π * √(1/4) = 2π * (1/2) = π ≈ 3.14s

Therefore, the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

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Angle R in the picture below is the angle of...

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The angle I can rightly be called the angle of reflection.

What is the law of angle of reflection?

The incident ray, the reflected ray, and the normal all reside on the same plane, according to the angles of reflection. This suggests that reflection may occur when two angles are in the same plane as the normal.

The angle I and depicted can appropriately be referred to as the angle of reflection in light of the aforementioned information.

Lastly, it is obvious from the image that angle I is the angle of reflection.

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A flat plate with surface area of 1.8 m2m2 is sliding on a horizontal table with 3.7 mmmm thick oil layer on top. Force applied on the plate in the direction of movement is 2.2 NN. Dynamic viscosity of the oil is 0.89 x10-³ Ns/m².​

Answers

The velocity gradient across the 3.7 mm thick oil layer on the flat plate sliding on the horizontal table is 0.594 m/s/m.

Given:

Surface area of the plate (A) = 1.8 m^2

Thickness of the oil layer (h) = 3.7 mm = 0.0037 m

Force applied on the plate (F) = 2.2 N

Dynamic viscosity of the oil (η) = 0.89 x 10^-3 Ns/m^2

To calculate the velocity gradient across the oil layer, we can use the equation:

τ = η * du/dy

where τ is the shear stress, η is the dynamic viscosity, and du/dy is the velocity gradient.

Since the force (F) applied on the plate is responsible for the shear stress, we can write:

τ = F / A

Substituting the given values, we have:

F / A = η * du/dy

Solving for du/dy, we get:

du/dy = (F / A) / η

Substituting the values, we have:

du/dy = (2.2 N) / (1.8 m^2 * 0.89 x 10^-3 Ns/m^2)

du/dy = 0.594 m/s/m

Therefore, the velocity gradient across the oil layer is 0.594 m/s/m.

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what are the factors affecting center of mass in an object

Answers

- The position of mass from the axis.
- The axis of the system.
- The distribution of mass.
- The mass of the rigid body.

Which correctly describes latent heat?

A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid

Answers

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?

Answers

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

Given the following information, what is the magnitude of the sum of the three
vectors?
Vector A: [13, 8, 0]
Vector B: [13, 0, 8]
Vector C: [0, 1, 8]

Answers

To find the magnitude of the sum of the three vectors, you first need to add the vectors together and then calculate the magnitude of the resulting vector. Let's add the vectors A, B, and C:

Vector A: [13, 8, 0]
Vector B: [13, 0, 8]
Vector C: [0, 1, 8]

Sum of vectors A, B, and C: [13 + 13 + 0, 8 + 0 + 1, 0 + 8 + 8] = [26, 9, 16]

Now, we can calculate the magnitude of the resulting vector:

Magnitude = sqrt((26)^2 + (9)^2 + (16)^2)
Magnitude ≈ sqrt(676 + 81 + 256)
Magnitude ≈ sqrt(1013)
Magnitude ≈ 31.83

Therefore, the magnitude of the sum of vectors A, B, and C is approximately 31.83.

Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. What is the gauge pressure p_gauge at point 2?

Answers

The gauge pressure at point 2 is 98100 Pa or 9.81 x[tex]10^4[/tex] Pa, which is equivalent to 6.97 x[tex]10^4[/tex] Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 [tex]m^2[/tex]

- Cross-sectional area at point 3 (A3) = 0.0160 [tex]m^2[/tex]

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ[tex]v1^2[/tex] + ρgh1 = P2 + (1/2)ρ[tex]v2^2[/tex] + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ[tex]v2^2[/tex] can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

[tex]P_g_a_u_g_e[/tex] = P2 - Patm

Now let's substitute the given values into the equation:

[tex]P_g_a_u_g_e[/tex] = (Patm + ρgh1) - Patm

[tex]P_g_a_u_g_e[/tex] = ρgh1

Plugging in the values:

[tex]P_g_a_u_g_e[/tex] = (1000 kg/m^3) * (9.81 [tex]m/s^2[/tex]) * (10.0 m)

[tex]P_g_a_u_g_e[/tex] = 98100 Pa

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Which sentence best describes Earth's rotation? (2 points)

a
Earth rotates on its axis once every two days.

b
Earth rotates on its axis once every year.

c
Earth rotates on its axis once every 24 hours.

d
Earth rotates on its axis twice every 24 hours.

Answers

The sentence that best describes Earth's rotation is : Earth rotates on its axis once every 24 hours.

The correct answer is option C.

Earth's rotation refers to the spinning of the Earth on its axis, an imaginary line that runs from the North Pole to the South Pole. This rotation is responsible for the cycle of day and night. As the Earth rotates, different parts of the planet are exposed to the Sun's light, resulting in the alternation between daylight and darkness.

The rotation period of the Earth is commonly referred to as a day. One complete rotation corresponds to 360 degrees of rotation, and it takes approximately 24 hours for the Earth to complete one full rotation. This 24-hour period is the basis for our standard measurement of time, with each day consisting of 24 hours.

Option a, stating that Earth rotates on its axis once every two days, is incorrect because it underestimates the duration of Earth's rotation. Option b, stating that Earth rotates on its axis once every year, is incorrect as it confuses Earth's rotation with its revolution around the Sun, which takes approximately 365.25 days. Option d, stating that Earth rotates on its axis twice every 24 hours, is incorrect as it implies a faster rotation rate than the actual 24-hour period.

In conclusion, Earth's rotation takes approximately 24 hours, causing the cycle of day and night. This rotation is a fundamental aspect of Earth's dynamics and has significant implications for various natural processes and phenomena on our planet.

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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Imagine you are riding on a yacht in the ocean and traveling at 20 mph. You then hit a golf ball at 100 mph from the deck of the yacht. You see the ball move away from you at 100mph, while a person standing on a nearby beach would observe your golf ball traveling at 120 mph (20 mph + 100 mph).

Now imagine you are aboard the Hermes spacecraft traveling at 0.1c (1/10 the speed of light) past Mars and shine a laser from the front of the ship. You would see the light traveling at c (the speed of light) away from your ship.

Answers

An observer on the spacecraft would see the light beam moving away from the ship at the speed of light, while an observer on Mars would also see the light beam moving away from the ship at the speed of light. This is because the speed of light is always constant, regardless of the motion of the observer or the light source.

When the ball is hit from the deck of the yacht at 100 mph, it is moving at a speed relative to the yacht.

Since the yacht is moving at 20 mph, the ball would appear to be moving away from the yacht at 100 mph.

This is because the speed of the ball relative to the yacht is 100 mph, while the speed of the yacht relative to the ground is 20 mph.

Therefore, the total speed of the ball relative to the ground would be the sum of the speed of the yacht and the speed of the ball relative to the yacht, which is 120 mph (20 mph + 100 mph).

Now let's consider the Hermes spacecraft traveling at 0.1c past Mars and shining a laser from the front of the ship.

According to the theory of relativity, the speed of light is always the same for all observers, regardless of their motion or the motion of the light source.

So, regardless of the speed of the spacecraft, the light beam would travel away from the ship at the speed of light, c.

An observer on the spacecraft would see the light beam moving away from the ship at the speed of light, while an observer on Mars would also see the light beam moving away from the ship at the speed of light.

This is because the speed of light is always constant, regardless of the motion of the observer or the light source.

In summary, the theory of relativity tells us that the speed of light is always the same for all observers, regardless of their motion or the motion of the light source.

This means that the speed of light is a fundamental constant of the universe, and it plays a crucial role in our understanding of the laws of physics.

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A team of engineers is doing a cost-benefit analysis to determine whether they should develop new technology. What are two risks to human health they should include in their analysis?
A. Increase in human diseases
B. Loss of habitat
C.damage to an ecosystem
D. Reduced workplace safety
E. Using up natural resources

Answers

A team of engineers is doing a cost-benefit analysis to determine whether they should develop new technology. Two risks to human health they should include in their analysis are: . Increase in human diseases and Reduced workplace safety.

The correct answer is option A and D.

When conducting a cost-benefit analysis for the development of new technology, it is essential to consider potential risks to human health. Here are two risks that should be included in the analysis:

1. Increase in human diseases:

New technology can bring about various health risks, including an increase in human diseases. Technological advancements often involve the introduction of novel materials, chemicals, or processes that may have adverse effects on human health. For example, the use of certain chemicals in manufacturing processes or the emissions from new machinery can lead to respiratory problems, allergic reactions, or long-term health issues. These risks should be thoroughly assessed, taking into account the potential exposure levels, the toxicity of the substances involved, and the susceptibility of the population.

2. Reduced workplace safety:

Introducing new technology may also impact workplace safety. While advancements can enhance productivity and efficiency, they can also introduce new hazards or change the nature of existing risks. For instance, automated systems or robotics might increase the risk of injuries or accidents if not properly designed, operated, or maintained. The analysis should consider the potential for occupational hazards, such as physical injuries, exposure to harmful substances, ergonomic issues, or psychological stressors. Proper training, safety protocols, and risk mitigation measures should be implemented to minimize these risks.

It is important to note that while risks to human health are significant considerations, a comprehensive cost-benefit analysis should also examine other factors such as economic impacts, environmental sustainability, social implications, and ethical considerations. The analysis should aim to strike a balance between the potential benefits of the new technology and the risks it poses to human health and overall well-being. Inclusion of these risks allows for a more comprehensive evaluation of the feasibility and desirability of developing the new technology.

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The picture shows two solutions of salt water. Which solution is more concentrated (has a higher concentration)?




Question 15 options:

The first solution is more concentrated


The second solution is more concentrated


The solutions have the same concentration.

Answers

In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated

When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.

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What order does energy flow: sun prodecer consumer?

Answers

Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.

Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.

At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.

The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.

Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.

At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.

It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.

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Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?

Question 12 options:

Put it in the fridge where it is cold


Cover it with a blanket so it's dark


Warm it up on the stove


There is nothing you can do to change the speed of the reaction

Answers

I think there is no way you can change it
Sorry if I’m wrong :(

Answer:

To make a reaction go faster, there are several methods that can be employed depending on the type of reaction and the reactants involved. One common method is to increase the temperature of the reaction mixture, as this typically increases the rate of reaction by providing more energy to the reacting molecules. Another method is to increase the concentration of one or more reactants, as this increases the likelihood of collisions between them. Adding a catalyst can also speed up a reaction by providing an alternative pathway with lower activation energy.

In the case of Samir's slow reaction, warming it up on the stove may be the best option to make it go faster. However, it is important to note that not all reactions can be sped up by simply increasing temperature or concentration, and some reactions may require specific catalysts or conditions to proceed at a reasonable rate. Additionally, it is important to consider safety precautions when attempting to speed up a reaction, as some reactions may become more dangerous at higher temperatures or concentrations.

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Part C Now, grab Tracker’s protractor tool (the green angle in the video frame) and measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below. Hints: To advance the video a frame at a time, use the step buttons on the right. Position the vertex of the protractor exactly at the origin of the coordinate axis. Move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.

Answers

In order to measure the angle of incidence and the angle of refraction using Tracker's protractor tool (the green angle in the video frame), the following steps should be followed:

Step 1: Open the video in Tracker software.

Step 2: Click on the "Measure" button on the toolbar at the top of the software.

Step 3: From the dropdown menu, select "Angle".

Step 4: Click on the "protractor tool" icon (the green angle in the video frame).

Step 5: Position the vertex of the protractor exactly at the origin of the coordinate axis and move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.

Step 6: Measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below by using the step buttons on the right to advance the video a frame at a time.

Step 7: Record the measured angles in the table below. Note that the angle of incidence should be measured on the incident ray (the ray that is coming from the left), and the angle of refraction should be measured on the refracted ray (the ray that is coming from the right).In conclusion, by following these steps, one can measure the angle of incidence and the angle of refraction using Tracker's protractor tool.

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Usually, we do a
when a population is hard to study, for some reason.

Answers

Usually, we use sampling when a population is hard to study, for some reason.

Sampling is a technique commonly employed in research and statistics when it is impractical or impossible to study an entire population directly. It involves selecting a subset, or sample, from the population and using the information gathered from the sample to make inferences about the entire population. This is done with the assumption that the sample is representative of the population and that the findings from the sample can be generalized to the larger population.

There are several reasons why a population might be difficult to study comprehensively. One reason is the size of the population. For example, if the population of interest is the entire world or a country, it would be practically impossible to study each individual in the population due to logistical constraints and limited resources. In such cases, sampling allows researchers to gather information from a smaller, manageable subset of the population.

Another reason for using sampling is when the population is dispersed or geographically scattered. If the population is spread out across a wide area, it can be challenging and costly to reach and collect data from every individual. Sampling allows researchers to select representative individuals or clusters from different regions, making data collection more feasible.

Additionally, there are cases where the population is inaccessible or hard to reach due to privacy concerns or ethical considerations. For example, if the population consists of individuals with certain medical conditions or sensitive personal information, it may be challenging to obtain consent or access to the entire population. In such cases, researchers can use sampling methods to obtain data from a subset of individuals who are willing to participate and meet the necessary criteria.

In summary, sampling is a valuable tool when studying populations that are hard to access, too large, or dispersed. It allows researchers to gather relevant data from a representative subset of the population and make valid inferences about the larger population, despite the challenges posed by studying the population as a whole.

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Usually, we use                  when a population is hard to study, for some reason.

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