Answer:
A
Explanation:
We know that impulse(J) is the force times the change in time OR mass times the change in velocity. Because we're given mass and a final and initial velocity, we'll use the second option written as:
mΔv=J
Since Δ means change in, and Δv= vf-vi, we subtract 10 m/s from 15 m/s to get 5 m/s for Δv.
Now plugging in Δv and m(1,200 kg)
1,200 kg * 5 m/s =J
6000 kg* m/s = J
A. A
B. C
C. D
D. B
HELLLP GUYS!!!
Answer:
B
Explanation:
What process forms the Mid-Atlantic Ridge?
A. Radioactive decay
B. Seafloor spreading
C. Radiometric dating
D. Sediment formation
Answer:
B. seafloor spreading
Explanation:
divergent motion between the Eurasian and North American, and African and South American Plates. ... In this way, as the plates move further apart new ocean lithosphere is formed at the ridge and the ocean basin gets wider
geological society
what is gama rays an it's uses
Answer:
GAMMA RAYS:
A photon emitted spontaneously by a radioactive substance also : a photon of higher energy than that of an X-ray.
USES OF GAMMA RAYS:
Gamma rays are used in medicine (radiotherapy), industry (sterilization and disinfection), and the nuclear industry. Shielding against gamma rays is essential because they can cause diseases to skin or blood, eye disorders, and cancers.
Students were having a catapult contest, launching a tennis ball with their home built devices. The winner launched a ball at 30 degrees from the ground at 6.0 m/s. How high does the ball go?
Answer:
The height reached by the ball=0.459 m
Explanation:
We are given that
[tex]\theta=30^{\circ}[/tex]
Initial speed, u=6 m/s
We have to find the maximum height reached by ball.
Maximum height reached by ball
[tex]h=\frac{u^2sin^2\theta}{2g}[/tex]
Where [tex]g=9.8m/s^2[/tex]
Substitute the values
[tex]h=\frac{6^2sin^230^{\circ}}{2\times 9.8}[/tex]
[tex]h=\frac{36\times \frac{1}{4}}{2\times 9.8}[/tex]
[tex]h=0.459 m[/tex]
Hence, the height reached by the ball=0.459 m
A marble is rolling across a smooth 1.2 m tall table at a velocity of 3 m/s. How far from the edge of the table does it land? (SHOW ALL OF YOUR WORK)
Answer:
S = 1/2 g t^2 where t is the time to fall 1.2 m
t = (2 S / g)^1/2 = (2 * 1.2 / 9.8) = .495 s
Sy = Vy T = 3 m/sec * .495 sec = 1.48 m distance from edge of table
(Rotational speed has no effect since table is smooth)
Beginning at the synapse of a neuron, place the events in neuronal signaling in the correct sequence.1. Ion channels bind the ligand and open.2. Na+ is pumped out of the cell, and the membrane potential is restored.3. Acetylcholinesterase breaks down acetylcholine.4. Na+ enters the postsynaptic cell, and the membrane potential changes.5. Acetylcholine is released into the synapse.6. Na+ ion channels close.A. 3, 4, 6, 1, 5, 2B. 5, 1, 4, 3, 6, 2C. 4, 5, 1, 2, 6, 3D. 1, 2, 3, 4, 5, 6E. 6, 4, 3, 1, 2, 5
Answer:
B. 5, 1, 4, 3, 6, 2
Explanation:
Acetylcholine (ACh) is a molecule that functions as a neurotransmitter and plays diverse roles in brain and muscle function. Ach is released by the presynaptic neurons into the synaptic cleft. The nicotinic acetylcholine receptors are ACh ligand-gated ion channels located at the postsynaptic membrane which admit both sodium (Na+) and potassium (K+) ions. These receptors bind ACh, increasing the permeability of the postsynaptic membrane to Na+ and K+ ions. In consequence, ion channels open and sodium (Na+) ions enter the postsynaptic cell, causing the postsynaptic membrane to depolarize. An enzyme known as acetylcholinesterase breaks down acetylcholine into acetate and choline. If depolarization passes a threshold potential, an action potential is generated in the postsynaptic membrane. The generation of a postsynaptic potential at the excitatory synapse is known as excitatory postsynaptic potential. Once depolarization is complete, Na+ channels close and membrane permeability to Na+ ions declines to the resting levels.
Which of the following best distinguishes the relationship between applied research and basic research?
A Applied research commercializes the discoveries of basic research and brings them to the general public.
B Basic research takes place in academia, and complex research takes place in industry.
C Basic research provides fundamental knowledge that can be used to conduct applied research.
D Applied research is not published for peer review, but basic research must be.
Answer:
C. Basic research provides fundamental knowledge that can be used to conduct applied research.
Explanation:
Applied research is used to solve practical and specific problems. Basic research is used to advance theories and scientific knowledge; it might not result in an invention or a solution, but can be used to gain knowledge about a specific subject.
Using atomic weight crystal structure and atomic radius data tabulated inside the front cover compute the theoritical densities of alminuim ,nikel......
Question
Using atomic weight, crystal structure, and atomic radius data tabulated inside the front cover of thebook, compute the theoretical densities of aluminum (Al), nickel (Ni), magnesium (Mg), and tungsten (W), and thencompare these values with the measured densities listed in this same table. The c/a ratio for magnesium is 1.624.
Explanation:
a trampoline launches a 50kg person 2m into the air. if the springs push with 1960N of force, how much displacement was there in the trampoline
Answer: 0.5 m
Explanation:
Given
Mass of the person is [tex]m=50\ kg[/tex]
Trampoline launches the person into the air up to height of [tex]h=2\ m[/tex]
Force experience by springs is [tex]F=1960\ N[/tex]
Here, the work done on displacing the springs is equivalent to the Potential energy acquired by the person i.e.
[tex]\Rightarrow F\cdot x=mgh\quad [\text{x=displacement of the trampoline}]\\\\\text{Insert the values}\\\\\Rightarrow x=\dfrac{50\times 9.8\times 2}{1960}\\\\\Rightarrow x=\dfrac{980}{1960}\\\\\Rightarrow x=0.5\ m[/tex]
Answer:
0.5
Explanation:
[tex]explain \: \\ \\ how \: rainbow \: form \: {?}[/tex]
asset question.....only answers otherwise u will be reported
Answer:
C. 24 hrs
Explanation:
it takes the earth 24 hrs to make one full revolution.
How does work affect energy between objects so it can cause a change in the form of energy?
A. Work transfers energy.
B. Work changes energy.
C. Work increases energy.
D. Work decreases energy.
An instrument rated pilot is planning a flight under IFR on July 10, this year. Before conducting the flight, the pilot must have
Answer: See explanation
Explanation:
From the information given, we are informed that an instrument rated pilot is planning a flight under IFR on July 10, this year.
It should be noted that before conducting the flight, the pilot must have performed and logged the prescribed tasks and repetitions that are required for instrument currency no earlier than January, 10 for the year.
A car moving along a racetrack has a centripetal acceleration of 11.3 m/ s2. If the speed of the car is 30.0 m/s, what is the distance between the car and the center of the track?
Answer:
Explanation:
The formula for centripetal acceleration is
[tex]a_c=\frac{v^2}{r}[/tex] and filling in:
[tex]11.3=\frac{(30.0)^2}{r}[/tex] and solving for r:
[tex]r=\frac{(30.0)^2}{11.3}[/tex] gives us that
r = 79.6 m
What does the temperature of the gas between galaxies in galaxy clusters tell us about the mass of the cluster
Answer:
HEY THERE!
Explanation:
The temperature tells us the average speeds of the gas particles, which are held in the cluster by gravity, so we can use these speeds to determine the cluster mass
HAVE A GOOD DAY!
Determine the amount of potential energy of a 4.2 kg book that is placed on a shelf with a height of 0.9 meters. Round your answer to one decimal place
Answer:
that is a correct answer maybe .
What is the net force on a remote controlled airplane if a force of 57.6N is applied West and a force of 95.7N is applied South?
Answer:
112 N at 239°
Explanation:
Applying,
Pythagoras theorem,
a² = b²+c².................. Equation 1
Where a = net force
From the question,
Given: b = 57.6 N, c = 95.7 N
Substitute into equation 1
a² = 57.6²+95.7²
a² = 3317.76+9158.49
a² = 12476.25
a = √12476.25
a = 111.7 N
a ≈ 112 N
Then the direction is given as
∅ = tan⁻¹(c/b)........... Equation 2
∅ = tan⁻¹(95.7/57.6)
∅ = tan⁻¹(1.66)
∅ = 58.9°
∅ ≈ 59°
Since the angle is in the third quadrant,
∅' = 59+180
∅ = 239°
Hence the right answer is
112 N at 239°
what is chemical change ??
Answer:
the combination,decomposition or replacement that occurs in the molecules of matter during chemical change called chemical reaction
Answer:
A chemical change happens when one chemical substance is transformed into one or more different substances, such as when iron becomes rust. ... A chemical change is different from a physical change, which doesn't rearrange atoms or molecules and produce a completely new substance.
help help help please please
Answer:
below
Explanation:
that is the procedure above
Please help it's for a test.
A car of mass 1000kg is traveling 30m/s
a) What is the kinetic energy?
b) How high will it have to travel up a hill to have the same potential as kinetic energy as this speed? Remember Ep-Ek
Answer:
Explanation:
[tex]KE=\frac{1}{2}mv^2[/tex] so filling in:
[tex]KE=\frac{1}{2}(1000)(30)^2[/tex] so to 2 sig figs (which is actually not accurate, but oh well...)
KE = 450000 J
If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:
450000 = (1000)(9.8)h so
[tex]h=\frac{450000}{(1000)(9.8)}=45.9m[/tex]
1. Un cable está tendido sobre dos postes colocados con una separación de 10,0 m. A la
mitad del cable esta colgado un letrero que provoca que el cable baje 50,0 cm. Si la tensión
de cada segmento del cable es de 2 000 N ¿Cuál es el peso del letrero?
1.Realice el esquema o dibujo de la situación del problema
2. Realice el Diagrama de Cuerpo Libre sobre el letrero, recuerde colocar el valor del ángulo de cada tensión.
plis s
Explanation:
Hydraulic Pressure-Control, On-Off Deluge Valve
FP-400Y-5DC
The BERMAD model 400Y-5DC is an elastomeric, hydraulic line pressure operated deluge valve, designed specifically for advanced fire protection systems and the latest industry standards. The 400Y-5DC is activated by a hydraulically operated relay valve, through which opening and closing of the valve can be controlled either with a remote hydraulic command or with a wet pilot line with closed fusible plugs. An integral pressure reducing pilot valve ensures a precise, stable, pre-set downstream water pressure. The optional valve position indicator can include a limit switch suitable for Fire & Gas monitoring systems. The 400Y-5DC is ideal for systems that combine a remote wet pilot line with a high pressure water supply.
action and reaction are equal in magnitudeand opposite in direction then why do they not balance each other ?
Because they act on different objects.
Find the sum. Express the answer in scientific notation. (1.54 x 10^6)+(6.15 x 10^6)
Answer:
[tex] { \tt{(1.54 \times {10}^{6}) + (6.15 \times {10}^{6}) }} \\ = { \tt{(1.54 + 6.15) \times {10}^{6} }} \\ = { \tt{7.69 \times {10}^{6} }}[/tex]
how much does a car weighr if each tyre cover of 4cm^2 and exert a pressure of 100000Nm^-2 on the ground it is physics questions
Answer:
Weight = 160 N
Explanation:
The weight of an object is a measure of the gravitational force on the object. So that weight is synonymous to the force applied by the object.
i.e Weight = mass x gravitational force
Also, the pressure of an object is the ratio of its force to area covered by the object. So that;
P = [tex]\frac{F}{A}[/tex]
Given that: area = 4 [tex]cm^{2}[/tex] (0.0004 [tex]m^{2}[/tex]), and pressure = 100 000 N[tex]m^{-2}[/tex].
Then;
F = PA
= 100 000 N[tex]m^{-2}[/tex] x 0.0004 [tex]m^{2}[/tex]
F = 40 N
The force applied on the ground by each of the four tyres of the car is 40 N.
Thus, the weight of the car = 4 x 40 N
= 160 N
A 5.0 kg block of ice is at rest at the top of a smooth inclined plane. The block is released and slides 2.0 m down the plane. Assuming there is no friction between the block and the surface, calculate
a) the gravitational potential energy at the top of the plane
b) the component of the weight parallel to the plane
c) the acceleration of the block
d) the velocity of the block at the bottom of the plane
e) the kinetic energy at the bottom of the plane.
Answer:
a) 98.1 Joules
b) 49.05 N × sin(θ)
c) 9.81 × sin(θ)
d) The velocity of the block at the bottom of the plane, v is approximately 6.264 m/s
e) 98.1 Joules
Explanation:
The given parameters of the block are;
The mass of the block, m = 5.0 kg
The distance down the plane the block slides, h = 2.0 m
The friction between the block and the surface = 0
Let θ represent the angle of inclination oof the plane
a) The gravitational potential energy, P.E. = m·g·h
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
∴ P.E. ≈ 5.0 kg × 9.81 m/s² × 2.0 m = 98.1 Joules
The gravitational potential energy, P.E. ≈ 98.1 Joules
b) The component of the weight of the block parallel to the plane, [tex]w_{\parallel}[/tex], is given as follows;
[tex]w_{\parallel}[/tex] = w × sin(θ) = m·g·sin(θ)
∴ [tex]w_{\parallel}[/tex] ≈ 5.0 kg × 9.81 m/s² × sin(θ) = 49.05 × sin(θ) N
The component of the weight of the block parallel to the plane, [tex]w_{\parallel}[/tex] ≈ 49.05 N × sin(θ)
c) The component of the weight along the inclined plane = The force with which the block moves along the inclined plane, therefore;
[tex]w_{\parallel}[/tex] = m·g·sin(θ) = m·a
Where a represents the acceleration of the block along the plane
Therefore, by comparison, we have;
g·sin(θ) = a
∴ a ≈ 9.81 × sin(θ)
d) Given that the motion of the block is 2.0 m downwards, we have;
The velocity of the block at the bottom of the plane, v² = 2·g·h
Therefore, v² ≈ 2 × 9.81 m/s²× 2.0 m = 39.24 m²/s²
v = √(39.24 m²/s²) ≈ 6.264 m/s
e) The kinetic energy at the bottom of the plane, K.E. = (1/2)·m·v²
∴ K.E. = (1/2) × 5.0 kg × 39.24 m²/s² = 98.1 J
your initial speed is zero. if you increased your speed by 4 m/s after only 2 seconds and continue to accelerate at the same rate, what will your speed be after 10 seconds?
Answer:
20 m/ s
Explanation:
change in velocity = 4m/ s
[tex]acceleration = \frac{rate \: of \: change \: of \: velocity}{time} [/tex]
[tex]acc = \frac{4}{2} \\ = 2[/tex]
initial velocity = 0m/ s
let velocity after 10s be v[tex]2 = \frac{v - 0}{10} [/tex]
cross multiplying
[tex]20 = v[/tex]
so the velocity after 10s will be 20m/s
A car moving east at a velocity of 16.0 m/s collides with a stationary truck with exactly twice the mass. If the two vehicles lock together, calculate the velocity of their combined mass immediately after collision
Answer:
5.33ms-¹
Explanation:
that is the procedure above
An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5 m/s2
over a time of 20 s. What is its new velocity?
Answer:
39 m/s²
Explanation:
initial Velocity (u) = 9m/s
acceleration (a) = 1.5m/s²
time(t) = 20s
V=u + at
V=9 + 1.5(20)
V=9 + 30
V=39m/s
Answer all these questions
What type of waves can only travel through a medium?
What is pitch?
What is the relationship between amplitude and volume?
How does the type of medium affect a sound wave?
Describe the relationship between frequency and wavelength.
Answer:
mechanical waves,
.
the quality of a sound governed by the rate of vibrations producing it; the degree of highness or lowness of a tone.
.
If the amplitude increases the volume increases and vice versa.
.
The type of medium affects a sound wave as sound travels with the help of the vibration in particles.
.
The higher the frequency, the shorter the wavelength.
Explanation:
Answer:
1 . Soundwave
2. pitch are sounds that are high or low corresponding and according to a certain frequency measured in Hertz
3. volume is the increase in sound or decrease in sound how loud or soft something is while amplitude is strength of sound
4. frequency is measured in Hertz one wave per second and wavelength is distance between corresponding points of two recurring and consecutive sound waves
One type of atomic particle that is found in the nucleus does not contribute to
an element's atomic number. What are two characteristics of this type of
atomic particle?
Answer:
1) They are electrically neutral
2) They have slightly more weight than protons
Explanation:
The given atomic particle found in the nucleus has the following characteristics;
The location of the particle = The nucleus
The (numbers of the) particle does not contribute to (change) the atomic number of the element
The particles found within the nucleus of an atom are; Neutrons and protons
The particle within the nucleus that determines the atomic number = The number of protons
Therefore, the particle referenced in the question is the neutrons
The two characteristics of the neutron are;
1) The neutrons are neutral, electrically
2) Neutrons have slightly more weight than protons
3) Neutrons are magnetic
4) Neutrons are very small
5) Neutrons consist of three quarks; One 'Up', and two 'Down' quarks
Therefore, two characteristics of the particle are;
1) They are electrically neutral and 2) They are slightly heavier than protons.
