a) Laminar boundary layer thickness is 2m ; b) Wall shear stress at the center of the plate is 4.16 x 10⁻⁴ N/m²; c) boundary layer thickness at the trailing edge of the plate 4.16 x 10⁻⁵ m ; d) Wall shear stress at trailing edge of the plate is 1.04 x 10⁻³ N/m².
a) Laminar boundary layer thickness is given by the formula: δ = 5ν / U∞ . x Where, δ = Laminar boundary layer thickness, ν = Kinematic viscosity of water U∞ = Velocity of water at infinity, x = Distance from leading edge of the plate to the point of interest
Here, x = L/2
= 4/2
= 2 m
Now, we have to calculate the kinematic viscosity of water. The kinematic viscosity of water is about 10⁻⁶ m²/s.
Therefore, δ = 5 x 10⁻⁶ / 0.3 x 2
= 8.33 x 10⁻⁶ m
(b) We can calculate the wall shear stress using the following formula: τw = μ . dU / dy Where,τw = Wall shear stressμ = Dynamic viscosity of water, U = Velocity of water at a distance y from the plate surface. The velocity profile for laminar flow over a flat plate is given by: U(y) = (U∞ / ν ) y [ 2 δ - y ]
Therefore, dU / dy = (U∞ / ν ) [ 2 δ - 2y ]
Here, y = 0 (At the plate surface)τw = μ . dU / dy
= μ . U∞ / ν x 2 δτw
= (10⁻³ x 0.3 / 10⁻⁶ ) x 2 x 8.33 x 10⁻⁶
τw = 50 x 8.33 x 10⁻⁶
τw = 4.16 x 10⁻⁴ N/m²
(c) Boundary layer thickness at the trailing edge of the plate
At the trailing edge of the plate, x = L
= 4 m
Now, δ = 5ν / U∞ . x
Therefore,δ = 5 x 10⁻⁶ / 0.3 x 4
= 4.16 x 10⁻⁵ m
(d) Wall shear stress at the trailing edge of the plate
At the trailing edge of the plate, y = δτw
= μ . dU / dy
= μ . U∞ / ν x 2 δ
τw = (10⁻³ x 0.3 / 10⁻⁶ ) x 2 x 4.16 x 10⁻⁵
τw = 25 x 4.16 x 10⁻⁵
τw = 1.04 x 10⁻³ N/m²
Therefore, the wall shear stress at the center of the plate is 4.16 x 10⁻⁴ N/m² and at the trailing edge of the plate is 1.04 x 10⁻³ N/m².
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Two particles are fixed to an x axis: particle 1 of charge q
1
=2.73×10
−8
C at x=24.0 cm and particle 2 of charge q
2
=−4.00q
1
at x=78.0 cm. At what coordinate on the x axis is the electric field produced by the particles equal to zero? Number Units
The electric field produced by the particles is equal to zero at the point x = 0.788 m or 78.8 cm (correct to two decimal places).
The electric field produced by the two particles are in opposite directions. The electric field at point P due to particle 1 is E1 and that due to particle 2 is E2. Therefore, we can write: E=P + E2where P is the position where the electric field is zero. Then, P = - E2/E1
Let's calculate E1 and E2, firstly. Electric field E1 at point P due to particle 1 at x = 24.0 cmE1=k * q1 / r1²where k is Coulomb's constant, q1 is the charge of the first particle, and r1 is the distance of the first particle from point P. k=9.0×10^9 N⋅m²/C² is Coulomb's constant.q1 = 2.73 × 10^-8 C is the charge of the first particle and r1= x - 24 cm = x - 0.24m is the distance of the first particle from point P.
Then, E1 = k * q1 / r1² = 9.0×10^9 * 2.73 × 10^-8 / (x - 0.24)²N/C The electric field E2 at point P due to particle 2 at x = 78.0 cm is calculated as follows: E2=k * q2 / r2²where q2 = - 4.00 q1 = -4.00 × 2.73 × 10^-8 = - 1.092 × 10^-7 C and r2= x - 78 cm = x - 0.78 m is the distance of the second particle from point P. Then, E2=k * q2 / r2² = 9.0×10^9 * (-1.092 × 10^-7) / (x - 0.78)² N/C Now, we will substitute these values in the formula for P: P = - E2 / E1 = - 9.0×10^9 * (-1.092 × 10^-7) / [2.73 × 10^-8 (x - 0.24)]²P = 78.8 cm (correct to two decimal places).
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visible light passes through a diffraction grating that has 900 slits/cm and the interference pattern is observed on a screen that is 2.20 m from the grating. you may wa
The difference between the wavelengths of diffraction grating that has 900 slits/cm and screen distance from the grating is 2.20 m, and the separation between maxima is 3.20 mm (3.20 × 10⁻³ m) is 4.58 × 10⁻⁷ m.
To calculate the difference between these wavelengths, the first-order spectrum is given:
dsinθ = mλ
Where:
d = distance between slits = 1/900 cm = 1/90000 mλ = wavelength of lightm = orderθ = angle between the incident beam and the diffracted beamFor m = 1, d = 1/90000 m, sinθ = 1 and λ = d/1 = d = 1/90000 m
For the first-order spectrum, the difference between the wavelengths of the two diffracted beams separated by 3.20 mm on the screen is given by:
Δλ = λ₂ - λ₁ = y(Δθ)λ = yλ / d
Here, Δθ = θ₂ - θ₁ = sin⁻¹(y/D) - sin⁻¹(0/D) = sin⁻¹(y/D)
D = distance between grating and screen = 2.20 m
On substitution,
Δλ = y(Δθ)λ / d
= (3.20 × 10⁻³ m) (sin⁻¹(3.20 × 10⁻³ m/2.20 m))(1/90000 m)
= 4.58 × 10⁻⁷ m
Therefore, the difference between the wavelengths of the two diffracted beams separated by 3.20 mm on the screen is 4.58 × 10⁻⁷ m.
Your question is incomplete, but most probably your full question was
Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed on a screen that is 2.20m from the grating. In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.20mm. What is the difference between these wavelengths?
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Force acting between two argons are well approximated by the LennardJones potential given by U(r)=
r
12
a
−
r
6
b
. Find the equilibrium separation distance between the argons.
The Lennard-Jones potential for the force acting between two argons is given by:U(r)= (a/r)^12 - (b/r)^6where, r is the distance between the two argon atoms and a and b are constants.The equilibrium separation distance between the argons is given by the minimum value of U(r). Thus, we differentiate U(r) with respect to r and equate it to zero to find the minimum value.U'(r) = -12a^12/r^13 + 6b^6/r^7At the minimum value, U'(r) = 0⇒ -12a^12/r^13 + 6b^6/r^7 = 0⇒ 2(a/r)^12 = (b/r)^6⇒ (a/r)^6 = b^3/r^6⇒ r = (b/a)^(1/6)Thus, the equilibrium separation distance between the argons is given by r = (b/a)^(1/6).Answer: The equilibrium separation distance between the argons is given by r = (b/a)^(1/6).
The equilibrium separation distance between the argon is given by r = (b/a)^(1/6).
The Lennard-Jones potential for the force acting between two argon is given by: U(r)= (a/r)^12 - (b/r)^6, where r is the distance between the two argon atoms and a and b are constants.
The equilibrium separation distance between the argon is given by the minimum value of U(r).
Thus, we differentiate U(r) with respect to r and equate it to zero to find the minimum value: U'(r) = -12a^12/r^13 + 6b^6/r^7
At the minimum value, U'(r) = 0⇒ -12a^12/r^13 + 6b^6/r^7 = 0⇒ 2(a/r)^12 = (b/r)^6⇒ (a/r)^6 = b^3/r^6⇒ r = (b/a)^(1/6)
Thus, the equilibrium separation distance between the argon is given by r = (b/a)^(1/6).
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the NO 5. Identify the crystallographic plane which if formed by the three atoms 111, % % %, and 100 in body- centered cubic lattice. of this level with
The crystallographic plane that is formed by the three atoms 111, % % %, and 100 in body-centered cubic lattice is the (111) plane. When the atoms are situated in a periodic pattern, these planes are formed in a crystal.Let's find out the answer to your question,The formula for a body-centered cubic lattice is a = 4r/sqrt(3).Here, a is the lattice constant and r is the atomic radius.The plane can be identified as (hkl), where h, k, and l are Miller indices. The three points can be expressed as (1, 1, 1), (0, 0, 0), and (1, 0, 0) in Miller indices.
The formula to calculate the distance between two planes is as follows:
For (hkl) planes, the distance is given by d(hkl) = a / sqrt(h² + k² + l²).The distance between the (111) plane can be calculated as follows:d(111) = a / sqrt(h² + k² + l²)= a / sqrt(1² + 1² + 1²)= a / sqrt(3)Therefore, the distance between the (111) plane can be given by d(111) = a / sqrt(3).About Crystallographic planeCrystallographic plane are a series of planes in a crystal that are characterized by their orientation and atomic spacing. The term is used in crystallography to describe the direction and orientation of a crystal plane.
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Charge q1 = 1.50 nC is at
x1 = 0 and charge q2 = 5.00
nC is at x2 = 2.50 m. At what point between the
two charges is the electric field equal to zero? (Enter the
x coordinate in m.)
HINT
m
The x coordinate at which the electric field is zero is 1.25 m.
From the question above, charge q1 = 1.50 nC is at x1 = 0 and charge q2 = 5.00 nC is at x2 = 2.50 m and we have to find out the point between two charges where the electric field is equal to zero.
The electric field due to a point charge q at a distance r from it is given by;E = (kq)/r²
Where, k is a constant and its value is 9 × 10^9 Nm²/C²
The electric field at any point on the axial line joining two point charges is given by;
E = (kq)/(r₁)² - (kq)/(r₂)²
Where, r₁ and r₂ are the distances of the point from the two charges respectively.On equating the above equation to zero, we get;
(kq)/(r₁)² = (kq)/(r₂)²(r₁)² = (r₂)²r₁ = r₂
Using the distance formula, the distance between the two charges can be calculated as follows;d = √(x₂ - x₁)²= √(2.50 - 0)²= √6.25= 2.5 m
Now, the distance between two charges can be divided into two equal parts such that they make a right angle at the point of division.
Since the electric field is proportional to 1/r², we know that the midpoint of the line connecting two point charges is the point at which the electric field is zero.
So, the x-coordinate of the point midway between the charges is;x = x₁ + d/2= 0 + 2.5/2= 1.25 m
Therefore, the x coordinate at which the electric field is zero is 1.25 m.
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Draw the circuit symbol for an npn BJT. Label the terminals and the currents. Choose reference directions that agree with the true direction of the current for operation in the active region.
The three main regions of the NPN transistor are emitter, collector, and base. The emitter is the lead on the left, and the collector is the lead on the right.
The center lead is the base. There are two PN junctions between the emitter and the base and the collector and the base, respectively.A small arrow, known as the emitter arrow, points from the emitter to the base. The arrow indicates the direction of the standard current flow or conventional current.
It corresponds to the direction of the electrons flowing out of the emitter in the active area. The base current flows from the base to the emitter, while the collector current flows from the collector to the emitter.
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Find the charge on the capacitor in an LRC-series circuit at t = 0.03s when L = 0.05 h, R = 3, C = 0.008 f, E(t) = 0 V, q(0) = 8 C, and i(0) = 0 A.
The charge on the capacitor in an LRC-series circuit at t = 0.03s when
L = 0.05 h,
R = 3,
C = 0.008 f,
E(t) = 0 V,
q(0) = 8 C, and
i(0) = 0 A is approximately 4.41 C.
In the given LRC-series circuit, we are required to find the charge on the capacitor at t = 0.03s, when
L = 0.05 H,
R = 3,
C = 0.008 F,
E(t) = 0 V,
q(0) = 8 C, and
i(0) = 0 A. The circuit is shown below: where
R = 3Ω,
C = 0.008F,
L = 0.05H,
q(0) = 8C, and
i(0) = 0A. The differential equation governing the circuit is given by:
[tex]$$L \frac{di}{dt} + Ri + \frac{q}{C} = E(t)$$At t[/tex]
= 0.03s, we know that
E(t) = 0V,
q(0) = 8C and
i(0) = 0A.
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13) Aquarium of Fishy Death (TIR) An aquarium contains no living fish, because it is filled with deadly carbon disulfide (CS 2), having a refractive index of 1.63. The aquarium is made of some unknown type of glass. A scientist with time on her hands measures the critical angle for total internal reflection for light directed out of the aquarium and finds that angle to be 65.2 ∘. Calculate the refractive index of the unknown glass walls of the Aquarium of Fishy Death.
The refractive index of the unknown glass wall of the Aquarium of Fishy Death is 1.4.
The critical angle is the angle at which the light travels from a denser medium to a rarer medium and refracts at 90°. At the critical angle, the refracted angle of light becomes 90°. The critical angle can be calculated by using the following formula;
Critical angle = sin-1 (n2/n1) where, n1 is the refractive index of the medium through which light enters, and n2 is the refractive index of the medium in which light travels. The refractive index of a medium is defined as the ratio of the speed of light in vacuum to the speed of light in the medium. In this case, the refractive index of the medium through which light enters is air, which is approximately equal to 1.
The critical angle is given as 65.2°.
We have to find the refractive index of the unknown glass wall of the Aquarium of Fishy Death.
Therefore, using the above formula, we get;
1.63 = sin (65.2°) / sin (θ)θ = 43.46°
Therefore, the refractive index of the unknown glass wall of the Aquarium of Fishy Death is 1.4.
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The high resistivity of dry skin, about 2 x 105 m, combined with the 1.5 mm thickness of the skin on your palm can limit the flow of current deeper into tissues of the body. Suppose a worker accidentally places his palm against an electrified panel. The palm of an adult is approximately a 9 cm x 9 cm square. Part A What is the approximate resistance of the worker's palm? Express your answer with the appropriate units. ī μA ? -3 R= 2.10 Ω Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining Provide Feedback
The high resistivity of dry skin, about 2 x 105 m, combined with the 1.5 mm thickness of the skin on your palm can
limit
the flow of current
deeper
into tissues of the body. Suppose a worker accidentally places his palm against an electrified panel. The palm of an adult is approximately a 9 cm x 9 cm square.
The approximate resistance of the worker's palm can be calculated as follows:Resistivity of dry skin = ρ = 2 x 105 m
Thickness
of skin on palm = t = 1.5 mm = 0.0015 mArea of palm = A = (9 cm)2 = (0.09 m)2Resistance is given by the formula, R = ρ * L / A
Where, L is the length of the conductorThe length of the conductor is equal to the thickness of the skin on the palm, L = t.R = (2 × 105 × 0.0015) / (0.09)2R = 3.33 × 105 ΩThis is the approximate
resistance
of the worker's palm.Answer: R = 3.33 × 105 Ω
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Please read the question carefully . Use MATLAB show
step by step solution .
Investigation of a unit negative feedback system with an open-loop
transfer
function of G(s) :
a. With the value K limit
In the question, we are given the open-loop transfer function of the negative feedback system. The transfer function of a system is the ratio of its output to its input under steady-state conditions. In this case, the output is the system's response to an input signal.
The transfer function of a negative feedback system is of the form:
[tex]G(s) = H(s)/(1 + G(s)H(s))[/tex]
Where G(s) is the open-loop transfer function and H(s) is the feedback function. The transfer function is used to analyze the behavior of the system. It can be used to determine the stability, transient response, and steady-state response of the system. Now, let's move on to the solution of the problem:Given, the open-loop transfer function of the negative feedback system is G(s).a. With the value of K limit To investigate the system, we need to plot the Bode plot of the open-loop transfer function.
The Bode plot is a graph of the magnitude and phase of the transfer function as a function of frequency. MATLAB can be used to plot the Bode plot of the open-loop transfer function.The magnitude of the transfer function is represented in decibels (dB) and the phase is represented in degrees. We can read off the gain margin and phase margin from the Bode plot. The gain margin is the amount of gain that can be added to the system before it becomes unstable. The phase margin is the amount of phase shift that can be added to the system before it becomes unstable.
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With increasing temperature, the intrinsic density of electrons and holes increases. Select one: True False
Each diode has its own maximum supported current depending on its physical characteristic.
The given statement "With increasing temperature, the intrinsic density of electrons and holes increases." is true. Intrinsic density refers to the density of electrons and holes in the intrinsic semiconductor material.
With the increase in temperature, more electrons and holes are created by thermal energy which leads to an increase in their intrinsic density. The intrinsic density of carriers increases with an increase in temperature since the thermal energy breaks down some of the covalent bonds which generate more free carriers. Hence, the statement "With increasing temperature, the intrinsic density of electrons and holes increases" is true.
Each diode has its maximum supported current which is based on its physical characteristics such as its construction, size, and thermal properties. It is one of the most significant parameters to consider when designing electronic devices that depend on diodes. The maximum current rating for a diode is provided by the manufacturer and should not be exceeded to avoid damage.
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Question 9 of 10 -/1 III View Policies Current Attempt in Progress Late one night on a highway, a car speeds by you and fades into the distance. Under these conditions the pupils of your eyes have diameters of about 7.4 mm. The taillights of this car are separated by a distance of 1.2 m and emit red light (wavelength = 657 nmin vacuum). How far away from you is this car when its taillights appear to merge into a single spot of light because of the effects of diffraction? Number i Units e Textbook and Media Save for Later Attempts: 0 of 5 used Submit Answer
The concept of diffraction is important in understanding how light behaves. Diffraction is a phenomenon that occurs when a wave, such as light, bends around an object or passes through a small aperture, causing the wave to spread out or diffract.
The concept of diffraction is important in understanding how light behaves. Diffraction is a phenomenon that occurs when a wave, such as light, bends around an object or passes through a small aperture, causing the wave to spread out or diffract. As a result, it can be observed that the light emitted by the taillights of a car spread out and merge into a single spot when seen from a distance. This phenomenon is used to calculate the distance between the observer and the car. In order to calculate this distance, we need to determine the angle at which the light from the taillights is diffracted by the pupils of the observer's eyes.
The formula for the diffraction angle is given by θ = 1.22λ/D, where λ is the wavelength of the light, D is the diameter of the pupil, and θ is the angle of diffraction. Here, λ = 657 nm, D = 7.4 mm = 0.0074 m.
Hence, θ = 1.22(657 x 10^-9)/0.0074 = 0.109 radians.
Using trigonometry, the distance between the observer and the car can be calculated as D = d/tan(θ), where d is the distance between the taillights of the car, and θ is the angle of diffraction. Plugging in the values, we get D = 1.2 m/tan(0.109) = 6.7 m. Therefore, the car is 6.7 meters away when the taillights appear to merge into a single spot of light due to the effects of diffraction.
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1. if we have a box of a dozen resistors and want to connect them together in such a way that they offer the highest possible total resistance, how should we connect them? if we had a box of a dozen resistors and wanted to connect them together in such a way that they would offer the highest possible resistance, we would use a series connection. 2. if we now
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Question: 1. If We Have A Box Of A Dozen Resistors And Want To Connect Them Together In Such A Way That They Offer The Highest Possible Total Resistance, How Should We Connect Them? If We Had A Box Of A Dozen Resistors And Wanted To Connect Them Together In Such A Way That They Would Offer The Highest Possible Resistance, We Would Use A Series Connection. 2. If We Now

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1. If we have a box of a dozen resistors and want to connect them together in such a way that they offer the highest possible total resistance, how should we connect them? If we had a box of a dozen resistors and wanted to connect them together in such a way that they would offer the highest possible resistance, we would use a series connection. 2. If we now want to connect those same resistors together such that they have the lowest possible resistance, how should we connect them?
1. This means that by increasing the number of resistors in the series, the total resistance also increases.
2. This means that by increasing the number of resistors in parallel, the total resistance decreases.
1. If we have a box of a dozen resistors and want to connect them together in such a way that they offer the highest possible total resistance, we should connect them in a series connection. By connecting the resistors in a series, the total resistance is equal to the sum of the individual resistances.
2. If we want to connect those same resistors together such that they have the lowest possible resistance, we should connect them in a parallel connection. By connecting the resistors in a parallel connection, the total resistance is given by the reciprocal of the sum of the reciprocals of the individual resistances.
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Part II – Measuring distant objects [24 points] Parallax as
explained in the pre-lab activity, is an interesting way of
measuring the distance of an object by how much it appears to move
when viewed
wZAnswer:d
Explanation:
efwdx
Parallax is a valuable technique used in astronomy to measure the distances of nearby celestial objects accurately. It relies on the apparent shift in an object's position when viewed from different locations on Earth's orbit and utilizes trigonometry to calculate the distance to the object.
Parallax is the apparent shift or change in the position of an object when viewed from different perspectives. This effect occurs when an observer changes their viewing angle. In astronomy, parallax is used to measure the distances of stars, planets, and other celestial objects.
The principle behind parallax is simple: Observers on Earth have slightly different views of a nearby object compared to a distant one, due to the difference in the observer's location on the planet. By measuring the apparent shift in the position of an object when viewed from two different points (such as two different locations on Earth), astronomers can calculate the object's distance.
The baseline used for measuring the parallax is the distance between the two observing points. In the case of celestial objects, the baseline is the distance between two points on the Earth's orbit, which are six months apart. This is because the Earth's position is significantly different after half a year due to its revolution around the Sun.
To measure parallax accurately, astronomers use specialized instruments like telescopes and cameras to observe the position of stars or other celestial objects at different times of the year. By comparing the apparent shifts in the object's position, they can determine the parallax angle. Using trigonometry, they can then calculate the distance to the object.
The formula used to calculate the distance to the object is:
Distance (in parsecs) = 1 / Parallax (in arcseconds)
That 1 parsec is approximately equal to 3.26 light-years.
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Simple BJT OP Amp 1. DC Analysis 1. Find current values of \( I_{A 1}, I_{A C 2}, I_{A C 2}, I_{A 2}, I_{A 3}, I_{R 4}, I_{A S}, I_{R G} \) and \( I_{R 7} \). 2. Find voltage values at \( v_{\text {ou
BJT stands for Bipolar Junction Transistor, and the OP-Amp is the abbreviation of the Operational Amplifier. An OP-Amp circuit consists of various resistors, capacitors, transistors, and voltage sources. The OP-Amp symbol indicates that the input and output signals are AC-coupled.
DC Analysis
The DC analysis of the circuit is very simple and straightforward. We will consider that the capacitors are short circuits because they do not allow DC signals to pass through them. As a result, the voltage values at the terminals of the capacitors are 0V in a DC analysis. Moreover, the current value is the same throughout the series of resistors.
Current Values:
The current flowing through the resistors in the circuit can be calculated using Ohm's law, which is V = IR, where V is the voltage, I is the current, and R is the resistance. In the given circuit, the currents can be calculated as follows:
The current through resistor R1 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R2 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R3 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R4 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R5 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R6 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R7 = (9-0.7) / 1000 = 8.3 mA
The current through resistor RE = (0.7-0.7) / 220 = 0 mA
The current through resistor RG = (5-0) / 1000000 = 5 uA
The current through transistor Q1 = (3.53 - 0) = 3.53 mA
The current through transistor Q2 = (3.53 - 0) = 3.53 mA
Voltage Values:
The voltage values of the circuit can be determined by using Kirchhoff's Voltage Law (KVL), which states that the sum of the voltages around any closed loop is zero. Therefore, we can calculate the voltage values as follows:
The voltage across resistor R4 is V(R4) = 3.53 * 2.2k = 7.766V
The voltage across resistor R5 is V(R5) = 3.53 * 2.2k = 7.766V
The voltage across resistor R6 is V(R6) = 3.53 * 2.2k = 7.766V
The voltage across transistor Q1 is V(Q1) = 0.7V
The voltage across transistor Q2 is V(Q2) = 0.7V
The voltage at the output terminal is V(OUT) = V(R5) - V(R6) = 0V
Therefore, the current values are:
\(I_{A 1}, I_{A C 2}, I_{A C 2}, I_{A 2}, I_{A 3}, I_{R 4}, I_{A S}, I_{R G}\) and \(I_{R 7}\) 3.53mA, 3.53mA, 3.53mA, 3.53mA, 3.53mA, 8.3mA, 0mA, 5μA, 8.3mA respectively.
The voltage values are:
V(R4) = 7.766V, V(R5) = 7.766V, V(R6) = 7.766V, V(Q1) = 0.7V, V(Q2) = 0.7V, V(OUT) = 0V.
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QUESTION 6 A person walks 20.0" north of east for 4.10 km. How far would she have to walk duo north and due east to arrive at the same location? O 3.82 km north and 1.49 km east O 140 km north and 3.85 km east O 3.85 km north and 1.40 km east 1.49 km north and 3.82 km east
The correct answer is option C) 3.85 km north and 1.40 km east.
When a person walks 20.0° north of east for 4.10 km, the horizontal and vertical distances can be calculated as: Horizontal distance = distance * cos θ = 4.10 km * cos 20.0° = 3.85 km
Vertical distance = distance * sin θ = 4.10 km * sin 20.0° = 1.40 km
Therefore, to arrive at the same location, the person would have to walk 3.85 km north and 1.40 km east.
So, the correct answer is option C) 3.85 km north and 1.40 km east.
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The energies of a two-level system are ±E. Consider an ensemble of such non-interacting systems at a temperature T. At low temperatures, the leading term in the specific heat depends on T as दवि-स्तरीय तंत्र के लिए ऊर्जायें ±E है। तापमान T पर ऐसे अन्योन्यक्रियाहीन तंत्रों के समुदाय पर विधार करें। निम्न तापमान पर, विशिष्ट उष्मा का अयग पद T पर निम्नवत् निर्भर है Options:- .
T
2
1
e
−E/k
B
T
Option ID :- 19
T
2
1
e
−2E/k
B
T
Option ID :- 198, - T
2
e
−E/k
B
T
Option ID :- 199, T
2
e
−2E/k
B
T
At low temperatures, the leading term in the specific heat of a two-level system depends on T as [tex]T^2e^{-2E/k_B}[/tex]. Therefore, option (D) is correct.
In a two-level system with energies ±E, when considering an ensemble of non-interacting systems at temperature T, the specific heat behavior can be described by the leading term. At low temperatures, this term depends on T as[tex]T^2e^{-2E/k_B}[/tex].
The specific heat of a system measures its ability to absorb or release heat. In the case of a two-level system, it refers to the amount of energy required to increase its temperature. At low temperatures, the dominant contribution to the specific heat arises from the thermal excitation of the higher energy level.
The expression [tex]T^2e^{-2E/k_B}[/tex] captures the temperature dependence of this specific heat term. As the temperature increases, the exponential term decreases, leading to a decrease in the specific heat. This behavior is characteristic of a two-level system, where the energy separation between levels influences the thermal properties and contributes to the overall specific heat response at low temperatures.
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convex mirrors can produce both real and virtual images.T/F
The statement : convex mirrors can produce both real and virtual images is False. Convex mirrors can only produce virtual images.
A virtual image is formed when the light rays appear to be coming from a location behind the mirror, regardless of the actual position of the object. In the case of convex mirrors, the reflected rays diverge, and the image formed is always virtual, diminished, and upright.
The virtual image in a convex mirror is formed by the apparent intersection of the diverging rays when traced backward. Convex mirrors are commonly used in applications where a wide field of view is necessary, such as in car side mirrors and surveillance systems.
They allow for a greater area to be observed, although the resulting image is smaller and appears closer than the actual object.
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An inclined plane has an inclination angle of 30º with the horizontal plane. The height difference between the lowest
and the highest point on the inclined plane is h. The inclined plane has the length l.
- A small block with lots of sts can slide down the inclined plane without starting speed at the top
inclined and without friction. Find an expression for the block's acceleration as it slides down
the inclined plane.
- Find an expression for the time (in h and g) that the block needs to slide down the entire inclined plane.
The block is replaced with a solid, homogeneous cylinder with mass m and radius R. The cylinder rolls
down the entire inclined plane without slipping. The starting speed is zero. Ignore friction.
- Find an expression for the time (in h and g) that the cylinder needs to roll down the whole
the inclined plane.
-cylinder = 1/2 * m ^ 2
Angle of inclination, α = 30ºThe difference in heights, hLength of the plane, lSmall block with lots of sts can slide down the inclined plane without starting speed at the top inclined and without friction. Find an expression for the block's acceleration as it slides down the inclined plane.
The acceleration of the block as it slides down the plane without friction can be calculated as follows:Acceleration, a = g * sin α [Where g is the acceleration due to gravity and α is the angle of inclination]a = 9.8 * sin 30ºa = 4.9 m/s²The acceleration of the block is 4.9 m/s².Find an expression for the time (in h and g) that the block needs to slide down the entire inclined plane.
Time, t = √(2h/g * sin α)
The block's speed at the bottom is given by,
v = u + at
[where u is the initial speed, a is the acceleration and t is the time].
As the initial speed is 0, v = at [where v is the final velocity]v = gt * sin αSubstituting the value of t, we get
v = √(2gh * sin α)
Find an expression for the time (in h and g) that the cylinder needs to roll down the whole the inclined plane.The moment of inertia of the cylinder about its center of mass,
I = ½ * m * R²
Rolling without slipping implies that the force of friction opposes the rotation of the cylinder. As friction is zero, it means that there will be no rotational force acting on the cylinder.
The acceleration of the cylinder can be calculated as follows:Acceleration,
a = g * sin α / (1 + I / mR²)
Substituting the value of I, we get,
a = g * sin α / (1 + ½)
[Substitute
I = ½ * m * R²]a = 2/3 * g * sin αThe time required to travel down the plane can be calculated as follows:Time, t = l / vSubstituting the value of v, we get:t = l / (R * w) [where w is the angular velocity]As the cylinder rolls down the plane without slipping, the velocity can be calculated as follows:
v = R * w = a * R * t
[where v is the velocity of the cylinder].
Substituting the value of a, we get,
v = 2/3 * g * sin α * R * t
The time taken for the cylinder to roll down the inclined plane is,
t = l / (2/3 * g * sin α * R)
The time taken for the cylinder to roll down the inclined plane is l / (2/3 * g * sin α * R).Therefore, the expressions are as follows:Acceleration of the block as it slides down the inclined plane, a = g * sin α = 4.9 m/s²Time required for the block to slide down the entire inclined plane,
t = √(2h/g * sin α)
and the block's speed at the bottom,
v = √(2gh * sin α)
Acceleration of the cylinder as it rolls down the inclined plane, a = 2/3 * g * sin αTime required for the cylinder to roll down the inclined plane, t = l / (2/3 * g * sin α * R).
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2) How amplitude of Wien Bridge Oscillator can be stabilized against temperature variation? References:
To stabilize the amplitude of a Wien Bridge Oscillator against temperature variation, techniques such as thermistors, temperature compensation networks, and thermal design are employed.
The amplitude of a Wien Bridge Oscillator can be stabilized against temperature variation by employing temperature compensation techniques. One common method is the use of a temperature-sensitive resistor (thermistor) in the feedback network of the oscillator. The thermistor's resistance changes with temperature, and by appropriately selecting its characteristics, it can counteract the temperature-induced variations in the gain of the amplifier.Additionally, a temperature compensation network can be incorporated into the oscillator circuit. This network typically includes components such as resistors, capacitors, or diodes that exhibit temperature-dependent characteristics. By carefully selecting and arranging these components, the effects of temperature changes on the oscillator's gain and frequency response can be minimized.Furthermore, proper thermal design and component selection are crucial to reduce the impact of temperature variations. This includes using components with low-temperature coefficients, providing proper heat sinking, and ensuring the thermal stability of critical components.In conclusion, stabilizing the amplitude of a Wien Bridge Oscillator against temperature variation can be achieved through techniques such as using temperature-sensitive resistors, employing temperature compensation networks, and implementing effective thermal design practices.References:1. A. Sedra and K. Smith, "Microelectronic Circuits," 7th edition, Oxford University Press, 2014.2. J. G. Webster, "Encyclopedia of Medical Devices and Instrumentation," John Wiley & Sons, 2006.For more questions on temperature
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Describe the difference between the motions of stars in the disk of the Milky Way and stars in the halo or bulge of the Milky Way.
The motions of stars in different regions of the Milky Way, such as the disk, halo, and bulge, exhibit distinct characteristics due to the different dynamics and gravitational influences in these regions. Here's a description of the differences in the motions of stars in each region:
1. Disk: The disk of the Milky Way is a flattened, rotating structure primarily composed of young and intermediate-aged stars, gas, and dust. The motion of stars in the disk follows a predominantly circular path around the galactic center. This rotation can be visualized as stars orbiting the center of the Milky Way in a similar way that planets orbit the Sun. Stars closer to the galactic center have shorter orbital periods and higher velocities, while stars farther from the center have longer orbital periods and lower velocities. The motion of stars in the disk is influenced by the gravitational pull of the central bulge and the combined gravitational effects of all the matter within the disk. Additionally, stars in the disk may also exhibit some vertical motion, with oscillations above and below the disk plane, known as vertical oscillation or "breathing" motion.
2. Halo: The halo of the Milky Way refers to the spherical region surrounding the disk. It contains older stars, globular clusters, and dark matter. The motion of stars in the halo is predominantly characterized by random, or more accurately, "elliptical" orbits rather than the orderly rotation observed in the disk. Stars in the halo have more complex trajectories, with their paths appearing more elongated and less confined to a specific plane. This motion is a result of the halo stars being influenced by the overall gravitational potential of the Milky Way, including the combined effects of the disk, bulge, and dark matter. The halo stars have higher velocities compared to the stars in the disk, and their motions are more isotropic (i.e., they move in all directions rather than just in the plane of the disk).
3. Bulge: The bulge of the Milky Way is a central, roughly spherical component located at the center of the galaxy. It contains a dense concentration of stars, gas, and dust. The motion of stars in the bulge is influenced primarily by the gravitational potential of the central supermassive black hole and the overall gravitational field of the galaxy. Similar to the halo, the motion of stars in the bulge is not predominantly rotational but rather follows elliptical or more chaotic orbits. The motions can be a mix of radial (towards or away from the center) and tangential (circular or elliptical) components, depending on the specific location within the bulge. The velocities of stars in the bulge can vary widely, with some stars exhibiting very high velocities due to their proximity to the central black hole.
In summary, stars in the disk of the Milky Way exhibit orderly, predominantly circular motion in a well-defined plane, whereas stars in the halo and bulge display more random, elliptical, and isotropic motions. The dynamics of each region are influenced by the distribution of mass, gravitational forces, and the overall structure of the Milky Way.
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Calculate the values of g at Earth's surface for the following changes in Earth's properties. Note: use g = 9.8 m/s. You can do all calculations without actually knowing Earth's mass or radius try to do the problem without looking them up. Express all answers rounded to one decimal place. a. its mass is tripled and its radius is quartered 2 g 470.4 m/s Correct! b. its mass density is doubled and its radius is unchanged m/s 919.6 Correct! c. its mass density is doubled and its mass is unchanged. * m/s 919.6 X Incorrect.
a. The value of g at Earth's surface is 29.4 m/s².
b. The value of g at Earth's surface is 19.6 m/s².
c. The value of g at Earth's surface remains unchanged at 9.8 m/s².
In order to calculate the values of g at Earth's surface for the given changes in Earth's properties, we need to consider the gravitational acceleration formula:
g = G * (M / R²),
where G is the universal gravitational constant, M is the mass of the Earth, and R is the radius of the Earth.
When the mass of the Earth is tripled and its radius is quartered, we can see that the term M/R² increases by a factor of 9 (3²). Therefore, the value of g becomes 9.8 m/s² * 9 = 88.2 m/s². Rounded to one decimal place, it is approximately 29.4 m/s².When the mass density of the Earth is doubled and its radius remains unchanged, the term M/R² remains the same, as only the mass density is affected. Therefore, the value of g remains unchanged at 9.8 m/s².When the mass density of the Earth is doubled and its mass remains unchanged, we can observe that the term M/R² remains the same, as both the mass and the radius are unaffected. Therefore, the value of g also remains unchanged at 9.8 m/s².Learn more about Gravitational acceleration
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A person places olive oil in a bottle. The person then inserts a cork with a 2.42 cm diameter into the bottle, placing it in direct contact with the olive oil. If the bottom of the bottle has a 12.57 cm diameter, and the person applies a force of 56 N to the cork, what is the force (in N) exerted on the bottom of the bottle?
A person places olive oil in a bottle. The person then inserts a cork with a 2.42 cm diameter into the bottle, placing it in direct contact with the olive oil. If the bottom of the bottle has a 12.57 cm diameter, and the person applies a force of 56 N to the cork, The force (in N) exerted on the bottom of the bottle is 56 N.
The area of the cork is given by the formula below:
A = πr²
where r is the radius of the cork and it is half of the diameter.
Thus,
The radius of the cork r = 2.42/2 = 1.21 cm.
Area of the cork = π(1.21)²=4.59 cm²
The force (in N) exerted on the cork can be calculated using the formula:
F = PA
Where P is the pressure and A is the area.
The pressure is equal to the force divided by the area.
So, F/A = P
Thus, F = PA
The area of the bottom of the bottle is also given by the formula: A = πr²
where r is the radius of the bottom of the bottle and it is half of the diameter. Thus, the radius of the bottle r = 12.57/2 = 6.285 cm.
Area of the bottom of the bottle = π(6.285)²=124.61 cm²
The force exerted on the bottom of the bottle (F₂) can be calculated by multiplying the pressure (P) by the area (A) of the bottom of the bottle. Thus:
F₂ = P.A₂
where P is the pressure and A₂ is the area of the bottom of the bottle.
The pressure is equal to the force (F) divided by the area (A) of the cork. So, P = F/A.
The force exerted on the cork (F) is given as 56 N and the area of the cork is given as 4.59 cm².
Thus the pressure exerted on the cork is given as:
P = F/A= 56/4.59= 12.18 Pa
Therefore, F₂ = P.A₂= 12.18 × 124.61= 1513.34 N ≈ 1513 N
Therefore, the force (in N) exerted on the bottom of the bottle is 1513 N.
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An insulator has 3 units. The capacitance between each insulator pin and earth is 15% of self capacitance of each unit. Find: a. Voltage across each insulator unit in percentage. b. String efficiency
The given conditions are:An insulator has 3 units. The capacitance between each insulator pin and earth is 15% of self capacitance of each unit. We are required to find:a. Voltage across each insulator unit in percentage.b. String efficiencya. Voltage across each insulator unit in percentage:The voltage across each unit is given by the voltage division rule. The total voltage is divided among the three units as per their voltage sharing capacitance. Let the total voltage be V.
The total capacitance of the unit, C1 = C2 = C3 = C (say).Let V1, V2, V3 be the voltages across unit 1, unit 2, unit 3 respectively.The voltage division rule gives:V1 = V x C2C1+C2C3 (i)Similarly,V2 = V x C1C1+C2+C3 (ii)and V3 = V x C3C2C1+C2C3 (iii)Total capacitance of the unit, C1 = C2 = C3 = C (say)The capacitance between each insulator pin and earth is 15% of self capacitance of each unit. Therefore, the capacitance to earth, C1e = 0.15C, C2e = 0.15C, C3e = 0.15C.Then the effective capacitance between unit 1 and unit 2,C12 = C1 + C2 + C1e + C2e = C + C + 0.15C + 0.15C = 2.3C.Using this value in equation (i),V1 = V x 2C.3C/2C.3C+C.3C+C.3C= V x 2/7.So, voltage across each insulator unit in percentage is given by:V1% = (V1/V) x 100= (V x 2/7V) x 100= 28.6%.
Therefore, voltage across each insulator unit is 28.6%.b. String efficiency:For the 3-unit string, the total capacitance is:Cs = C1 + C2 + C3 = 3CAnd, Capacitance to earth, Ce = C1e = C2e = C3e = 0.15C The voltage across the string, V = V1 + V2 + V3= V x 2/7 + V x 2/7 + V x 2/7= (6V/7)Voltage across the string with respect to earth = V - 0.45V= 0.55V Therefore, string efficiency is given by:String efficiency = (Voltage across the string with respect to earth / Voltage across the string) x 100= (0.55V/V) x 100= 55%.Therefore, string efficiency is 55%.
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Question 2 of 5 < 0.05 / 1 III : View Policies Show Attempt History Current Attempt in Progress Your answer is partially correct. a In the red shift of radiation from a distant galaxy, a certain radiation, known to have a wavelength of 409 nm when observed in the laboratory, has a wavelength of 429 nm. (a) What is the radial speed of the galaxy relative to Earth? (b) Is the galaxy approaching or receding from Earth? (a) Number i Units
The correct answer is: b) Receding from Earth.
According to the question, the wavelength of radiation from a distant galaxy is 429 nm, and it was 409 nm in the lab. Therefore, the redshift is z = 429/409 - 1 = 0.0489a)
To determine the radial speed of the galaxy relative to the earth, we'll use the formula:v = zc where v is the radial velocity, z is the redshift, and c is the speed of light.
Substitute the values: v = (0.0489)(3 x 10^5 km/s) ≈ 14,670 km/s
Therefore, the radial velocity of the galaxy relative to the Earth is approximately 14,670 km/s.
b) The galaxy is receding from Earth because the value of z is positive.
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a slowly moving ship has a large momentum because of its
A slowly moving ship has a large momentum because of its mass.
Momentum is a property of moving objects and is defined as the product of an object's mass and its velocity. In the case of a slowly moving ship, it can still have a large momentum because of its mass.
The momentum of an object is directly proportional to its mass and velocity. This means that if the mass of an object is large, its momentum will also be large, even if its velocity is relatively low.
A ship is a massive object, and even if it is moving slowly, its mass contributes to a significant momentum. The mass of a ship is much larger compared to smaller objects like cars or bicycles, which means that even at low speeds, the ship can have a substantial momentum.
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1- Find the change in the BACK E.M.F when the applied voltage on
D.C shunt motor = 250 volts and armature resistance = 2 ohms and
armature current on full load =40 ampers. and on no load = 10
ampers.
Answer: -60v
Explanation:
As the given parameters are:
Applied voltage on DC shunt motor (V) = 250V
Armature resistance (R) = 2Ω
Armature current on full load (I1) = 40A
Armature current on no load (I2) = 10A
The back EMF (E) of a DC shunt motor can be calculated using the formula:
E = V - I * R
where V is the applied voltage, I is the armature current and R is the armature resistance.
When the motor is on full load, the armature current is I1 = 40A, so the back EMF can be calculated as:
E1 = V - I1 * R
E1 = 250V - 40A * 2Ω
E1 = 250V - 80V
E1 = 170V
When the motor is on no load, the armature current is I2 = 10A, so the back EMF can be calculated as:
E2 = V - I2 * R
E2 = 250V - 10A * 2Ω
E2 = 250V - 20V
E2 = 230V
Therefore, the change in the back EMF when the motor goes from full load to no load is:
ΔE = E1 - E2
ΔE = 170V - 230V
ΔE = -60V
Hence, the change in the back EMF when the applied voltage on the DC shunt motor is 250 volts, armature resistance is 2 ohms, armature current on full load is 40 ampers, and on no load 10 ampers are -60V.
A 14.7cm thick copper (k = 380W/mK) disk having an diameter of
27.4cm has a temperature of 128.2C on one side and 16.3C on the
other. Calculate the heat flow per minute through the disk
Substitute the values given;Q/ t = [(380 W/mK x 3.14 x (0.274m/2)²) / 0.147m] (128.2 - 16.3)Q/ t = 9476.43 W/min = 9476.43 J/s Therefore, the heat flow per minute through the disk is 9476.43 W/min.
The rate of heat flow through the disk is the heat transferred in a unit time. The formula for the rate of heat transfer is given by;Q/ t
= (KA / x) (ΔT)Where;Q/ t
= the rate of heat flow through the disk A
= surface area of the diskΔT
= temperature difference between the two faces of the disk K
= thermal conductivity of the material x
= thickness of the disk. Substitute the values given;Q/ t
= [(380 W/mK x 3.14 x (0.274m/2)²) / 0.147m] (128.2 - 16.3)Q/ t
= 9476.43 W/min
= 9476.43 J/s Therefore, the heat flow per minute through the disk is 9476.43 W/min.
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A baseball (m = 154 g) approaches a bat horizontally at a speed of 43.6 m/s (97.6 mi/h) and is hit straight back at a speed of 54.4 m/s (122 mi/h). If the ball is in contact with the bat for a time of 1.83 ms, what is the average force exerted on the ball by the bat? Neglect the weight of the bat, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction. Number i 8247 Units N Vf
We can use the principle of impulse and momentum to solve the given problem. In order to do that, we need to find the initial momentum (p1) and final momentum (p2) of the baseball.
Then, we can find the change in momentum (Δp = p2 - p1) and use it to calculate the average force (F = Δp / Δt) exerted on the ball by the bat. Let's start by finding the initial and final momenta. Initial momentum: The baseball is approaching the bat horizontally with a speed of 43.6 m/s.
Therefore, its initial momentum is given by:p1 = m × v1where m is the mass of the baseball and v1 is its initial velocity.p1 [tex]= 154 g × (43.6 m/s) = 6718.4 g·m/s = 6.7184 kg·m/s[/tex]Final momentum: The baseball is hit straight back by the bat at a speed of 54.4 m/s. Therefore, its final momentum is given by:
p2 = m × v2where v2 is its final velocity.p2 = 154 g × (54.4 m/s) = 8369.6 g·m/s = 8.3696 kg·m/sChange in momentum: The change in momentum of the baseball is given by:[tex]Δp = p2 - p1Δp = 8.3696 kg·m/s - 6.7184 kg·m/s = 1.6512 kg·m/s[/tex]
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4. . .smog only forms in the presence of sunlight.
5. When sunlight strikes an object and the light is seen in all directions, the light is said to be . .
6. Cloud seeding has been used in attempts to. . INCREASE. . the diameter of the eyewall and thereby weaken hurricanes.
7. The bending of light through an object is called. .
4. Smog only forms in the presence of sunlight. This is because sunlight activates the nitrogen oxides and volatile organic compounds in the atmosphere to create smog. Therefore, smog is more prevalent in areas with higher amounts of sunlight.
5. When sunlight strikes an object and the light is seen in all directions, the light is said to be diffused. This is because the rays of light have been scattered and are seen from many different angles. Diffused light is often softer and less harsh than direct light.
6. Cloud seeding has been used in attempts to increase the diameter of the eyewall and thereby weaken hurricanes. Cloud seeding involves introducing substances into the atmosphere, such as silver iodide or dry ice, to encourage the formation of rain or snow.
7. The bending of light through an object is called refraction. Refraction occurs when light passes through a medium, such as air, water, or glass, and its speed changes. This causes the light to bend or change direction. Refraction is responsible for many optical illusions, such as mirages and rainbows, and is also used in the design of lenses for glasses and cameras.
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