6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.
What is a neutralization reaction?A neutralization reaction is defined as the reaction between an strong acid and strong base to produce a salt and water.
The process of the reacting given volume of acids or bases for the determination of the concentration or volume of the acid or base which is required for neutralization is known as titration in volumetric analysis.
The formula used to determine the volume of the acid is given below:
(Ca × Va) /(Cb × Vb) = Na/Nb
where,
where Ca is the concentration of lead nitrate
Cb is the concentration of sodium phosphate
Va is the volume of lead nitrate
Vb is the volume of sodium phosphate
Na is the moles of lead nitrate
Nb is the moles of sodium phosphate
Concentration of lead nitrate = m/V
= 6.931/(0.1 × 331.2)
= 0.0281 M
Ca = 0.222M
Cb = 0.0281M
Na = Nb = 1
Va = ( 0.0281 × 50) /0.222
= 6.32 mL.
Thus, 6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.
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A solution has a [h3o ] of 1 × 10−5 m. what is the [oh−] of the solution? 9 m 14 m 1 × 10−9 m 1 × 10−14 m
option (c) 1 × 10-9 m is the right answer.
The [oh−] of the solution having a [h3o ] of 1 × 10−5 m is 1 × 10-9 m.
What is [OH−] of the solution?The only component of water is H2O, and when the pH of the solution is 7, all of the ions have the same concentration, whereas during dissociation the water splits into H+ and OH- ions.
The concentration of OH- ions will be,
OH- = Kw {H3O+}
{H3O+} = 1 × 10−5 M.
Kw = 14
On substituting the value in the equation,
OH = 14 { 1 × 10−5 M.}
OH = 1 × 10−9 M
Consequently, the [H3O+] of the solution is 1 × 10-5 M.
Option (C) is the right choice because the [OH-] of the solution will be 1 × 10-9 M.
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A substance decays so that the amount a of the substance left at time t is given by: a = a0 ∙ (0.8)t where a0 is the original amount of the substance. what is the half-life (the amount of time that it takes to decay to half the original amount) of this substance rounded to the nearest tenth of a year?
The half-life of the substance is 3.106 years.
What is the formula for exponential decay?The exponential decline, which is a rapid reduction over time, can be calculated with the use of the exponential decay formula. The exponential decay formula is used to determine population decay, half-life, radioactivity decay, and other phenomena. The general form is F(x) = a.Here,
a = the initial amount of substance
1-r is the decay rate
x = time span
The equation is given in its correct form as follows:
a = [tex]a_{0}[/tex]×[tex](0.8)^{t}[/tex]
As this is an exponential decay of a first order reaction, t is an exponent of 0.8.
Now let's figure out the half life. Since the amount left is half of the initial amount at time t, that is when:
a = 0.5 a0
Substituting this into the equation:0.5[tex]a_{0}[/tex] = [tex]a_{0}[/tex]×[tex](0.8)^{t}[/tex]
0.5 = [tex](0.8)^{t}[/tex]
taking log on both sides
t log 0.8 = log 0.5
t = log 0.5/log 0.8
t = 3.106 years
The half-life of the substance is 3.106 years.
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What would the potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions? [h ]=0. 84 mh2=2. 2 atm=298 k
The potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions is - 0.029 V
Calculation ,
Formula used :
[tex]E_{cell}[/tex] = [tex]E_{cell}[/tex] ° - 0.059/n ㏒[tex]H_{2}[/tex]/ [tex][H^{+}]^{2}[/tex]
As we know that ,
[[tex]H^{+}[/tex]] = 0. 84 M
[tex]P_{H_{2}[/tex] = 2. 2 atm
Temperature ( T ) = 298 K
From reaction at electrode number of electrons involve ( n ) = 1
Standard electrode potential of standard hydrogen electrode [tex]E_{cell}[/tex] ° = 0
Putting the value of all data in equation ( i ) , we get
[tex]E_{cell}[/tex] = 0 - 0.059/1 ㏒2. 2 / [tex](0. 84)^{2}[/tex] = - 0.059 ㏒3.14 = - 0.059×0.497
[tex]E_{cell}[/tex] = - 0.029 V
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In an sn2 reaction between bromomethane and hydroxide ion, the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles the rate of reaction?
The rate of reaction in SN2 reaction becomes four times when the the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles.
In SN2 reaction, the rate of reaction is depend on the concentration of both reactant.
For SN2 reaction,
r = k[bromoethane] [hydroxide ion]
r = k [CH3CH2Br] [OH]
When the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles then,
r = k 2×[CH3CH2Br] × 2[OH]
r = 4k[CH3CH2Br] [OH]
Thus, we concluded that the rate of reaction in SN2 reaction becomes four times.
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In the laboratory, a student dilutes 18. 9 ml of a 10. 0 m perchloric acid solution to a total volume of 250. 0 ml. what is the concentration of the diluted solution? concentration = m submit answer
The concentration of diluted solution is 0.756M.
From the question given above, the following data were obtained:
Volume of stock solution (V1) = 18.9 mL
Molarity of stock solution (M1) = 10 M
Volume of diluted solution (V2) = 250 mL
Molarity of diluted solution (M2) =?
We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:
M1V1 = M2V2
10 × 18.9 = M2 ×250
189 = M2 × 250
Divide both side by 100
M2 = 189 / 250
M2 = 0.756 M
Therefore, the molarity of the diluted solution is 0.756 M.
Thus the concluded that concentration of the dilute acid is 0.756 M.
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Electric vehicles have less range they can drive compared to plug-in hybrid electric vehicles. true false
Answer is plug-in hybrid cars also offer advantages and disadvantages. The primary benefit is range. Plug-in hybrid vehicles include a gasoline engine in addition to an electric motor, whereas an electric car can only go as far as its batteries will allow. Plug-in drivers benefit from having the best of both worlds as a consequence.
what is a electric vehicle?
An electric car is fully electric. Instead of a petrol tank, it has a battery, and an electric motor rather than an internal combustion one. If your batteries run out, there isn't a backup motor like in a hybrid electric vehicle. Many versions, nevertheless, offer space for an extra battery. The Nissan Leaf, Tesla Model S, and Ford Focus Electric are a few examples.
what is a plug in hybrid electric vehicle?
A plug-in hybrid electric car combines (or, if you prefer, is a hybrid of) an electric and gasoline-powered vehicle. They have a gas tank, an internal combustion engine, an electric motor, and a battery. You could say they have everything. Gasoline and electricity are both used as fuel in plug-in hybrid electric vehicles. The Chevrolet Volt, Toyota Prius Plug-in, and Cadillac ELR are a few examples.
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Calculate the pressure (in atm) exerted by 1.82 moles of a gas in a steel vessel of volume 5.43 l at 69.50 c.
The pressure in atm is 6.8.
Calculation,
According to ideal gas law,
PV = nRT ..(i)
P is pressure = ?V is volume = 5.43 Ln is number of moles = 1.82 moles T is temperature = 69.50°C = 69.50°C + 278 K = 247.50 KR is universal gas constant = 0.082 atm L/K molPutting the value of all given data in equation (i) we get,
P×5.43 L = 1.82 moles ×247.50 K × 0.082 atm L/K mol
P = 1.82 moles ×247.50 K × 0.082 atm L/K mol /5.43 L = 6.8 atm
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Draw the lewis structure of scl₂ and then determine the hybridization of the central atom
The hybridization of the central atom in SCl₂ is sp³.
What is Lewis Structure ?Lewis structure is also known as Lewis dot structure which simply represent the valence electron of an atom.
What is Hybridization ?Hybridization is defined as the mixing of two atomic orbitals belongs to same atom but having entirely different shapes , energies which produces a new hybridized orbitals.
Now first write the electronic configuration of central atom.
The central atom in SCl₂ is S (Sulphur).
Electronic configuration of S: [Ne] 3s² 3p⁴
One 3s and three 3p undergo hybridization to form sp³ orbitals. Here each atom forms bond with one sp³ hybrid orbital.
Thus from the above conclusion we can say that The hybridization of the central atom in SCl₂ is sp³.
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In the following 2 questions, determine what is being oxidized and what is being reduced in each reaction. Identify the oxidizing and reducing agents in each :
a. 2Mg(s) + O2(g) → 2MgO(s)
b. Pb(NO3)2(aq) + Zn(s) → Zn(NO3)2(aq) +Pb(s)
a) Mg is oxidized and O2 is reduced
b) Zn is oxidized while Pb(NO3)2 is reduced.
Oxidation and reductionOxidation is defined as:
loss of electronsremoval of hydrogenaddition of oxygenincrease in oxidation numberremoval of electropositive elementsReduction is defined as:
gains of electronsaddition of hydrogenremoval of oxygendecrease in oxidation numberaddition of electropositive elementsLooking at the first reaction, the Mg atom gains oxygen to become MgO. This means that Mg is oxidized. The oxidizing agent is O2. At the same time, O2 is being reduced and the reducing agent is Mg.
For the second reaction, the oxidation number of Pb is reduced from +2 to 0. Thus, Pb has been reduced by Zn while Zn itself has been oxidized. The reducing agent here is Zn while the oxidizing agent is Pb(NO3)2.
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If 0. 5371 g of zn was plated onto an electrode, how much charge (in coulombs) was used to reduce the zn2+ to zn(s)?
The amount of charge required to reduce Zn²⁺ to Zn is 1585.26 coulomb.
What is electrolysis?The process that has been equipped with the use of electric current to break the chemical compound and deposited at the constituent electrodes is termed as electrolysis.
The reaction of reduction of Zn can be given as:
Zn²⁺ + 2e⁻ → Zn (s)
Molar mass of Zn = 65.39 g
The equivalent of Zn²⁺ has been:
Equivalent = atomic mass/equivalent weight
Equivalent Zn²⁺ = 65.39/32.69
Equivalent Zn²⁺ = 2 mol
1 equivalent = 1 F charge used
2 mol equivalent = 2 F charge used
Charge in coulomb can be given as:
1 Faraday = 96500 coulomb
2 F = 96500 * 2 coulomb
2 F = 1,93,000 coulomb
The moles of Zn to be deposited is:
Moles = weight /molar weight
Moles = 0.5371 g/ 65.39 g/mol
Moles = 0.00821 mol
Therefore, the charge used for the deposition of 0.00821 mol is:
Charge = 0.00821 * 1,93,000 coulomb
Charge = 1585.26 coulomb
1585.26 coulomb charge was used to reduce the Zn²⁺ to Zn.
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can someone help me really quick this is for science
The rules scientists will have to follow to give an element a symbol is by verifying it and naming it with a one-, or two-letter symbol which is usually derived from the name of the element.
What is an Element?This is referred to as substance which can't be broken down into simpler units by any form of chemical means.
When an element is discovered by an individual, it is best for it to be verified before it is named by the discoverer. The possible name for the element Jofrofrinium is Jo which is a two letter symbol or it could be J which is referred to as a one letter symbol.
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Consider your results for the 0. 1-m znso4 solution. is the solution acidic or basic?
0. 1-m zinc sulfate - znso4 solution. is the solution acidic solution
Zinc sulfate is the inorganic compound with the formula ZnSO4 and historically known as "white vitriol". Zinc Sulfate is a prescription drug used to treat zinc deficiency. The body's healthy tissues grow and develop more quickly thanks to zinc sulfate.
Zinc sulfate inhalation can harm the respiratory system, bring on nausea, vomiting, stomach pain, disorientation, depression, and even death. Skin injury from exposure through skin contact can result in blisters, ulcers, and scars. In cases of mild to moderate acne, topical 5% zinc sulfate proved beneficial. In cases of moderate to severe acne, oral zinc gluconate and sulfate were helpful.
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Two cars A and B are moving in opposite directions with the velocity of 20m/s and 6m/s respectively Calculate the relative of car A with respect to car B If they move in the same velocity what will be the relative velocity of CarA with respect to Car B
The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.
How to find out the Relative Velocity of car A and car B ?a) Velocity of car A (Va) = 20m/s
Velocity of car B (Vb) = -6m/s
To find the Relative Velocity, we should apply the formula as,
Relative Velocity of car A and car B = Vab
Vab = Va - Vb
Vab = 20 - (-6)
Vab = 20+6
Vab = 26m/s
b). if Velocity of car A = Velocity of car B
Va = Vb
In this case,
Relative Velocity = Vab
Vab = Va - Vb
(since Va = Vb)
Vab = 0m/s
Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.
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A bumblebee carries pollen from the male portion of a plant to the female portion of the similar plant. Fertilization occurs. Which statement is true about this type of reproduction?
Answer:
It’s sexual, and the offspring are genetically different from the parents
Explanation:
Since it is the same flower the bee is pollinating, the progeny will be genetically distinct if the bee were to transfer the pollen to the female part of the flower from the male part.
3. 2.71x1022 molecules of CO2 to atoms I NEED HELP
2.71 x 10²² molecules of CO2 is equivalent to 2.71 x 10²² atoms.
What is number of molecules?The number of molecules in an element is the combination of atoms in that element.
The number of molecules of an element can be calculated by multiplying the number of moles of that element by Avogadro's number, which is 6.02 × 10²³.
However, the number of molecules in a substance is equivalent to the number of atoms in that substance.
Therefore, 2.71 x 10²² molecules of CO2 is equivalent to 2.71 x 10²² atoms.
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What can be said about this reaction when the concentration of 2-phosphoglycerate is 0.490 mm and the concentration of 3-phosphoglycerate is 2.90 mm at 25°c?
The reaction is at equilibrium. Option C
What is the equilibrium constant?The term equilibrium constant refers to a value that shows the extent to which reactants are converted into products in the reaction.
We know that;
∆G =∆G'° + RT In Keq
∆G'° = −4.40 kJ/mol
R = 8.314 J/K/mol
T = 25 + 273 = 298 K
Thus;
∆G = −4.40 * 10^3 + (8.314 * 298 * ln[2.90 * 10^-3/0.490 * 10^-3]
∆G = −4.40 * 10^3 + 4.40 * 10^3
∆G = 0
Hence, the reaction is at equilibrium.
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1) Consider the following metabolic reaction:
2-Phosphoglycerate ® 3-Phosphoglycerate DG°' = −4.40 kJ/mol
What can be said about this reaction when the concentration of 2-phosphoglycerate is 0.490 mM and the concentration of 3-phosphoglycerate is 2.90 mM at 25°C?
I. This reaction is endergonic under these conditions.
II. This reaction is exergonic under these conditions.
III. This reaction is at equilibrium under these conditions.
IV. This reaction is not favorable under standard conditions.
A) I, IV
B) II only
C) III only
D) IV only
E) None of the above
2) Consider the following metabolic reaction:
What non-metal has less than 4 valence electrons (Outmost cells electrons)?
Correct Answer: Boron family
Which is an acidic functional group that can dissociate and release h into a solution?
The acidic functional group that can dissociate and release h into a solution is -COOH.
Characteristics of a carboxyl group -COOHCarbon atom is bonded to a high electronegative oxygen and a hydroxyl group in the Carboxyl groupExample: Acetic acid CH3COOHThe acidic functional group ( -COOH ) dissociate and releases H atom from the hydroxyl group into a solution as a proton or as a H+ ionHence the Oxygen atom gets a negative chargeThis negative charge moves between both the oxygen atom.From the characteristics of -COOH group we can conclude it as the acidic functional group that can dissociate and release H into a solution.
Disclaimer: The question was incomplete
Which is an acidic functional group that can dissociate and release h into a solution?
A. -OH
B. -COOH
C. -NH2
D. -SH
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HELP PLS PLS PLS ILL MARK U BRAINLIEST!
Answer:
2 NaI ---> 2 Na + I₂
Explanation:
The only way the reactant NaI can decompose is by separating into 2 atoms, Na and I. However, you must take into account that iodine (I) exists as a diatomic molecule.
An equation is balanced when there is an equal amount of each element on both sides of the reaction. These amounts can be modified by adding coefficients in from of the molecules/atoms.
The unbalanced equation:
NaI -----> Na + I₂
Reactants: 1 sodium, 1 iodine
Products: 1 sodium, 2 iodine
The balanced equation:
2 NaI ---> 2 Na + I₂
Reactants: 2 sodium, 2 iodine
Products: 2 sodium, 2 iodine
I have a mixture of sand salt and water from the sea. Describe in detail how I separate these three substances and explain why each method works
Answer:
You can separate a mixture of sand, salt and water by decantation and evaporation. Decantation will separate sand from salt and water. Sand remains in the original vessel, whereas salt and water is transfered to new vessel. Evaporation will separate salt from water.
What process involves the addition of a hydrogen molecule to compounds containing multiple bonds?
The process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.
Unsaturated hydrocarbons are transformed into saturated hydrocarbons by the addition process when they interact with hydrogen gas and nickel. The term "hydrogenation reaction" is also employed to describe this process.
In the production of fats and oils, hydrogenation seems to be crucial for two reasons. It increases the oil's oxidative stability and turns liquid oils become semisolid or plastic fats for use in shortenings as well as margarine, among other things.
Therefore, the process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.
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To prevent the system refrigerant from quickly dropping in temperature and pressure, refrigerant recovery should?
To prevent the system refrigerant from quickly dropping in temperature and pressure, refrigerant recovery should Begin with a liquid
In the refrigeration cycle of air conditioners and heat pumps, refrigerants are working fluids that typically go through numerous phase changes from a liquid to a gas and back again.
In the refrigeration cycle, which cools a place, a refrigerant is a material, frequently a fluid. Refrigerants use the thermodynamic phenomenon of phase transitions, in which a fluid transforms into a gas or vice versa, to absorb heat and then release it to another area.
At room temperature, it is often a gas. Ammonia, sulfur dioxide, and non-halogenated hydrocarbons like propane are further typical refrigerants that are employed in a variety of applications.
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A solution of naf is added dropwise to a solution that is 0.0122 m in ba2 . when the concentration of f- exceeds ________ m, will precipitate. neglect volume changes. for , ksp = 1.7 x 10-6. 4. calculate the ph of a solution prepared by dissolving 0.270 mol of weak acid ha (ka = 1.77 x 10-4) and 0.260 mol of its conjugate base in water sufficient to yield 1.00 l of solution.
A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 m, BaF₂ will precipitate.
Let's consider the solution of BaF₂.
BaF₂(s) ⇄ Ba²⁺(aq) + 2 F⁻(aq)
We can use the solubility product constant (Ksp) to find the equilibrium concentration of F⁻ when [Ba²⁺] is 0.0144 M.
When [F⁻] exceeds 0.011 M, BaF₂ will precipitate.
A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 M, BaF₂ will precipitate.
What is BaF₂.?
BaF2 crystallizes in the cubic Fm3m space group and has a fluorite structural makeup. Eight comparable F1 atoms and Ba2+ are joined in a cubic shape with the body in the middle. The average Ba-F bond length is 2.72. Four comparable Ba2+ atoms are joined with F1 to create a mixture of corner- and edge-sharing FBa4 tetrahedra.Learn more about BaF2 crystallizes
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The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.
What is the acid dissociation constant?The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.
The ICE table is attached to the image below.
The acid dissociation constant (Ka) for the reaction is,
Ka = [H⁺][ClO⁻] ÷ [HClO]
= a² ÷ (0.015 - a)
= 3.0 x 10⁻⁸
Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0
So, a = 2.210 × 10⁻⁵
Solving further,
[H+] = a = 2.210 × 10⁻⁵ M
The percent ionization is calculated as,
[H+] ÷ [HClO] × 100
= 2.210 × 10⁻⁵ M ÷ 0.015 × 100
= 0.14 %
Therefore, 0.14 % is the percentage of hypochlorous ionization.
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Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?
Finding mole ratios from chemical formulae
This is the chemical formula for nickel tetracarbonyl (a powerfully poisonous liquid used in nickel refining):
Ni(CO)4
A chemical engineer has determined by measurements that there are 93. moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen are in
the sample?
Round your answer to 2 significant digits.
7 moles of oxygen are in the sample.
According to the chemical formula, each mole of nickel tetracarbonyl contains 4 moles of C atoms. Simply convert it into a fraction by putting the original solution in the denominator and the diluted solution in the numerator if you need to determine the concentration ratio between two solutions. The V/n ratio for each gas must be the same if the two gases are at the same temperature and pressure. The volume ratio of two gases at the same temperature and pressure is equal to their molar ratio. The mole ratio of C to O is 1 : 1
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What is the ph of a 2. 3 m solution of the weak acid h2s, with a ka of 1. 19×10−7? the equilibrium expression is: h2s(aq) h2o(l)⇋h3o (aq) hs−(aq)
The equilibrium expression is:
H2S (aq) + H2O (l) ⇋ H3O (aq) + HS (aq)
In order to calculate the pH of equation having aqueous solution of weak acid H2S, let’s assume that molar concentration of the products H3O and HS total released is ‘a’. Now as per given information concentration of weak acid H2S is 2.3 M. Thereby,
Ka = [H3O+] [HS] / [H2S]
1.19 x 10-7 = [a] * [a] / [2.3]
a2 = 1.19 x 10-7 x 2.3
a = 5.24 x 10-4
As per the calculation, the total concentration of the products released (HS) and (H3O) will be 5.24 x 10-4, on that basis, the pH of the weak acid (H2S) can be calculated as follows:
-log (0.000522494) = 3.28
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This family (ethane, propane, butane, etc) of materials is likely to have what set of properties?
This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.
The alkanes are non- polar solvents.The alkanes are immiscible in water but freely miscible in other non-polar solvent .The alkanes are consisting of weak dipole dipole bonds can not breaks the strong hydrogen bond.The alkanes having only carbon (C) and hydrogen (H) atom which is bonded by a single bonds only.The alkanes posses weak force of attraction that is weak van der waals force of attraction.The ethane, propane, butane, belong to alkanes family.The alkanes are also considers as saturated hudrocarbons. Ethane is found in gaseous stae Ethane is the second alkane followed by propane followed by butane.
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Simon measured the density of a piece of metal
to be 11.70 g/cm³. However, the manufacturer
claims it has a density of 12.00 g/cm³. What is
the percent error of Simon's measurement?
From the question we know that 12 - 11.70 = 0.3 so 0.3 / 12 = 0.025 therefore Simon's percent error is 2.5%.
Percent error compares an estimate to an accurate value and expresses the difference among them as a percent. This statistic lets analysts recognize the scale of the mistake relative to the true cost. it's also referred to as percentage error as well as % mistakes.
Percentage errors Calculation Steps :
Subtract one cost from another.Divide the mistake by the exact or ideal price (not your experimental or measured value).Convert the decimal variety into a percentage by multiplying it by using 100.Add a percent or % symbol to record your percentage mistakes value.Percentage error tells you the way huge your mistakes are when you degree something in an experiment. Smaller values suggest that you are close to the accepted or actual value. for instance, a 1% blunder means that you obtain very near the accepted value, whilst 45% means that you were pretty a long way off from the real value.
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Write an equation to represent the following reaction:
Borax is heated with CoO
The equation of the reaction is; B2O3 + CoO -----> Co(BO2)2.
What is a reaction?The term chemical reaction has to do with the interaction between reactants in order to yield products. We know that when a chemical reaction occurs, the reactants are rearranged to form the products.
Now the first step in this reaction is that the Borax is heated to form boric anhydride (B2O3). Thus compound now reacts with cobalt II oxide as follows; B2O3 + CoO -----> Co(BO2)2.
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If the decomposition of a sample of k c l o 3 kclox3 produces 3. 29 g of o 2 ox2 , what was the mass (g) of the original sample?
The mass (g) of the original sample after decomposition is 8.3983 g.
A decomposition reaction can be described as a chemical reaction wherein one reactant breaks down into or extra merchandise.
explanation:
Reaction 2KClO₃ ⇒ 2KCl + 3O₂
moles 2 2 3
molar mass 122.55 74.55 32
Given, Mass of O₂ = 3.29g ⇒ moles of O₂
= (3.29/32) = 0.1028
3 moles of O₂ produced by 2 moles of KClO₃
Therefore, 0.1028 moles of O₂ produced by (2*0.1028/3) = 0.06853 moles of Kclo₃
Mass of KClo₃ in original sample is = moles * molar mass
= 0.06853 * 122.55
= 8.3983 g
A decomposition response occurs whilst one reactant breaks down into or extra merchandise. this may be represented through the general equation: XY → X+ Y. Examples of decomposition reactions consist of the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.
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