The speed of the object if a string is wrapped tightly around a fixed reel that has a rotational inertia of 0.0352 kg · m² and a radius of 12.5 cm after it has fallen 1.25 m is 1.97 m /s
∑ Fy = m ay
mg - T = ma
m = 423 g = 0.423 kg
g = 9.8 m / s²
( 0.423 * 9.8 ) - T = 0.423 a
4.15 - T = 0.423 a → ( 1 )
τ = F * ⊥d
τ = I α
α = a / r
τ = Torque
F = Force
⊥d = Perpendicular distance
I = Moment of inertia
α = Angular acceleration
a = Tangential acceleration
r = Radius
I = 0.0352 kg m²
r = 12.5 cm = 0.125 m
F * ⊥d = I α
T * r = I a / r
T = I a / r²
T = 0.0352 a / 0.125²
T = 2.26 a → ( 2 )
( 1 ) becomes,
4.15 - 2.26 a = 0.423 a
2.683 a = 4.15
a = 1.55 m / s²
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
s = Distance
u = 0
s = 1.25 m
v² = 0 + ( 2 * 1.55 * 1.25 )
v² = 3.875
v = 1.97 m / s
Therefore, the speed of the object after it has fallen 1.25 m is 1.97 m / s
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consider a 20 kg sphere with a 10 cm radius. what weight would a scale read if the sphere was totally submerged in water?
The weight the scale would read if the sphere of mass 20 kg with a 10 cm radius was totally submerged in water is 155.1 N
Fg = m g
Fb = ρ V g
Fg = Force of gravity
Fb = Buoyant force
m = Mass
g = Acceleration due to gravity
ρ = Density of medium
V = Volume of object
m = 20 kg
g = 9.8 m / s²
ρ = 1000 kg / m³
r = 10 cm = 0.1 m
Fg = 20 * 9.81
Fg = 196.2 N
Fb = ρ ( 4 / 3 π r³ ) g
Fb = 1000 * 4 / 3 * 3.14 * 0.1³ * 9.8
Fb = 41.1 N
N = Fg - Fb
N = Scale reading
N = 196.2 - 41.1
N = 155.1 N
Therefore, the scale reading if the sphere was totally submerged in water is 155.1 N
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a charged particle, passing through a certain region of space, has a velocity whose magnitude and direction remain constant. if it is known that the external electric field is zero everywhere, then can you conclude that the external magnetic field is also zero? ignore gravity.
YES, if it is known that now the external electric field equals zero everywhere, then you can infer that external magnetic field also is zero.
In plain terms, how is a magnetic field?The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.
What are the workings of the magnetic field?The vicinity of a magnet that exhibits magnetic force is known as the magnetic field. South and north poles are found on every magnet. The opposite poles are drawn to one another, whereas the same poles are drawn away from one another. The atoms in iron have north-seeking poles that line up in the exact direction when it is rubbed against a magnet.
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a spaceship moves at speed 0.5c relative to the earth with its headlight on. what value does an observer on the earth get by measuring the speed of light emitted by spaceship
1.0c. Light will always propagate through a vacuum at the speed of light “c”.
What is the velocity of a light?One universal physical constant that is significant in many branches of physics is the speed of light in a vacuum, typically abbreviated as c.The exact value of the speed of light, c, is 299,792,458 meters per second (approximately 300,000 kilometres per second; 186,000 miles per second; 671 million miles per hour).The speed at which common matter or energy (and consequently any signal conveying information) can move through space is c, according to the special theory of relativity.Visible light is an example of electromagnetic radiation that moves at the speed of light.Light and other electromagnetic waves appear to propagate instantly for many practical purposes, but their finite speed has noticeable effects for long distances and very sensitive measurements.To learn more about Special theory of relativity. refer,
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a 0.13- kg block on a wooden table is given a sharp blow with a hammer. the block then slides across the table to a stop. the coefficient of friction between the block and table is 0.33. the hammer's force on the block as a function of time is well approximated by an isosceles triangle with it's base on the horizontal time axis. the length of the base is 0.0067 s and the maximum force is 37.6 n. how far does the block go? use a graphical technique
The length of the base is 0.0067 s and the maximum force is 37.6 n.1.45 ×10^-1 m far does the block go.
When we use graphical method then we can feel that, here the area of the isosceles triangle will give us the change in the momentum, also as here the initial velocity is zero,
so that let the final velocity is V then,
we have
m*V= area of the triangle
or
0.13* V = area of the triangle = 1/2 * base * height =0.5*0.0067*37.6= 0.1258 kg m/s
so V = 0.968 m/s
the frictional force is = mg(0.33)
let the distance required is X then using conservation of energy here we have
KINETIC ENERGY = FRICTIONAL ENERGY.
1/2mV2 = mg(0.33) *X
X= V^2 / ( 2g*0.33) = 0.1450 m = 1.45 ×10^-1 m
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2 balls ball 1 and ball 2 are each thrown horizontally from the same height above the ground. ball 2 has a greater initial velocity after leaving the thrower's hand than ball 1. if air resistance is negligible how do the accelerations of each ball and the time it takes each of them to hit the ground compare?
acceleration on both the balls is same
Time to hit the ground is also equal for both the balls.
Here the acceleration is only acceleration due to gravity in vertically downward direction.
No acceleration in horizontal direction as air resistance is neglected.
Both the balls are projected from same height and downward acceleration is same and there is no initial downward velocity ,hence both the balls take same time to hit the the ground.
Time to hit the ground is also equal for both the balls.
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the bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity at g. the bucket is pinned at e (figure 1).
Answer:
1200
Explanation:
What is the total momentum before the collision?
Answer:
When two objects collide the total momentum before the collision is equal to the total momentum after the collision (in the absence of external forces). This is the law of conservation of momentum. It is true for all collisions.
Explanation:
...
Answer:
When two objects collide the complete momentum before the collision is similar to the complete momentum afterwards the collision (in the absence of outside forces) . This is the law of conservation of momentum . it's accurate for all collisions .
a race car traveling at a constant speed of 50 m/s drives around a circular track that is 500 m in diameter. what is the magnitude of the acceleration of the car
The magnitude of the acceleration of the car was 10m/s^2
what is magnitude?
Magnitude is defined in physics as an object's maximal size and direction. Magnitude is utilised in vector and scalar variables as a common factor. Scalar quantities, by definition, are those with only magnitude. Whereas vector quantities have both magnitude and direction.
Magnitude can be used in a variety of contexts. Some of them include
The magnitude of the earthquake
Charge magnitude on an electron
Force magnitude
The magnitude of the displacement
Gravitational force magnitude
acceleration (a)= v^2/r
v=speed
r=radius
d=diameter=500
r=d/2=500/2=250
a= 50^2/250
=10 m/s^2
Therefore the acceleration was found to be 10m/s^2
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How fast must a 2.0 kg basketball be thrown upward to achieve 160 J of potential energy?
Answer:
i think its 12.6 NATO per second
a mass m is attached to an ideal massless spring. when this system is set in motion with amplitude a, it has a period t. how does the period of the motion change if the amplitude of the motion is increased to 2a? explain.
System is set in motion with an amplitude of a and a period of T. If the amplitude of the motion is increased to 2a, the period of the motion changes.
A straightforward harmonic oscillator's period is independent of its amplitude. with the graphs of acceleration and velocity produced by the time derivatives. These oscillators also show how kinetic and potential energy can be transferred.
The acceleration of the mass increases proportionally with the increase in force, causing the mass to travel farther in the same amount of time. Therefore, increasing the amplitude has no overall impact on the oscillation's period.
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an electron and a photon each have a wavelength of 0.200 nm. a. find the momentum and energy of the photon. b. find the momentum and kinetic energy of the electron. ignore relativistic effects for the electron. c. how fast is each one moving?
a. Momentum is 3.315x [tex]10^{-24}[/tex] kg m/s and energy is 6.21KeV.
b. momentum is 3.315x [tex]10^{-24}[/tex] kg m/s and kinetic energy 0.038 KeV.
c. 3.64x [tex]10^{6} m/s[/tex] fast is each one moving.
a. for photon λp = 0.200 nm
Now, λp = [tex]\frac{h}{p_{p} }[/tex]= [tex]p_{p} = \frac{h}{h_{p} }[/tex] = [tex]\frac{6.63\times 10^{-34} }{0.200\times 10^{-9} }[/tex] kgm/s
= 3.315x [tex]10^{-24}[/tex] kg m/s
[tex]E_{P}[/tex] = [tex]P_{p} C[/tex] = 3.315x [tex]10^{-24}[/tex]x 3x [tex]10^{8}[/tex]/ 1.6x [tex]10^{-19}[/tex] eV
= 6.21KeV.
b. λe = 0.200
[tex]P_{e} =[/tex]λ/λe
= 3.315x [tex]10^{-24}[/tex] kg m/s
E = [tex]\frac{P^{2} _{e} }{2m} }[/tex] = [tex]\frac{( 3.315)^{2} }{2\times 9.1\times 10^{-31\times 1.6\times10^{-19} } }[/tex]
= 0.038 KeV
C. [tex]P_{e} = m V_{e}[/tex]
[tex]V_{e} = \frac{P_{e} }{m\\}[/tex]
= [tex]\frac{ 3.315\times 10^{-24} kg m/s}{9.1\times 10^{-31} }[/tex]
= 3.64x [tex]10^{6} m/s[/tex]
What is momentum?Momentum is a quantity used to describe the state of motion of an object with non-zero mass. Thus, an impulse can be applied to any moving object. Since velocity is considered a vector, momentum is also considered a vector. This means that the impulse has a significant magnitude and direction—an impulse indicated by a vector or arrow. For example, if a ball of a certain mass moves with a certain speed, it has momentum. When the ball hits the wall, it stops and thus carries its momentum over the wall. Therefore momentum is always conserved.
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A basketball hoop is 3.05 m above the playing surface. A basket is made. The ball reached a maximum height that was 2.00 m above the height of the basket hoop. The basketball was launched from a height of 1.95 m. If the ball traveled a horizontal distance of 5.20 m in 2.00 seconds, what was the initial velocity of the basketball?
Answer:
In this question, we have given a basketball hoop that is 3.05 m above the playing surface and the basket is made. The basketball was launched from a height of 1.95 And if the ball travels the original distance of 5.2 m in two seconds, then we have to find the initial velocity of the basketball. So we can find given data is we have given the horizontal distance traveled, that is d is equals to 5.2 m Per meter. And we have given the time taken to cover this distance, that is T equals to two seconds. So we can find the original velocity. So we can see that horizontal velocity that is three X is equal to, this is 5.2 upon two, and this will come out to be 2.6 meter per second. Now we can see that as we have given That the basketball hoop is 3.05 m above the playing surface. So we can say that the height covered, that is delta edges 3.5 minus 1.95. And this will comes out to be 1.10 m. So, using the equation of motion, we can find the vertical velocity Y. So we can say that that is is, we can apply in and wind direction. So we can say that delta edge is equals to this is initial velocity in y direction into time, T plus half into exhalation in y direction into T square. So we can say this is equals to 1.10, that is we're not y and to time is two seconds blood half into disease. Here, exploration is the gravitational acceleration and it is acting downwards. So this is equal to -3, which is -9.8 into two square. So from here we can find the value of velocity in the Y direction. That is 10.35 m/s. So we have the velocity in X direction and velocity in the Y direction. So we can see that the initial velocity that is we note is equal to this under root of we're not in extraction plus we're not wise square. So we can say this is equal to under root of 2.60 sq Plus 10.35 ft sq. And this will comes out to be 10.67 m/s. But this is the answer of arguing cushion. Thank you.
what measure do seismologists use to calculate the distance from a seismic receiving station to the epicenter of an earthquake? group of answer choices the time interval between the first p wave and the last surface wave the magnitude of the ground acceleration of surface wave passing a receiving station the time elapsed between the first p wave arrivals from the first and last aftershocks the time interval between the arrivals of the first p and s waves the amplitude of the strongest s wave
Option A - the time interval between the first P-wave and first S-wave arrivals is correct.
Determine the difference between the first P-wave and the first S-arrival wave's periods, and then use that information to calculate the distance of the epicenter from the seismic recording station.
The study of elastic wave motion through the ground is known as seismology. Seismology of earthquakes is the finest method for investigating the earth's core. A portion of the energy released after an explosion or earthquake is transported through the earth as elastic waves. Stresses increase in the crust as the lithospheric plates of the Earth continue their sluggish motion, particularly close to the plate borders. Compression, tension, and shear stresses increase in the crust until they exceed the resistance of the rock or the friction along an existing fault. Then, an abrupt rock slide along a fault happens. The rocks lurch to their new location in a matter of seconds, and the ground trembles as the stress energy is released. Similar to growing ripples from a pebble thrown in still water, seismic waves propagate outward from the area of the fault that ruptured.
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AP physics 1: Extra points!!
The weight of box 2 and box 3 is 33.72N and 15.32N
According to Lami's Theorem, if three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two forces. The magnitudes of concurrent, coplanar, and non-collinear forces that keep an object in static equilibrium are all related to Lami's Theorem. This theorem also aids in the analysis of most mechanical and structural systems. For all three forces used in Lami's Theorem, the proportionality constant is the same.
Given box1 weighs 31N
Given two angles 63 and 24
So the third angle will be
180 – 87
= 93
By using Lamis theorem
T_2/(SIN 93)=T_3/(SIN (90+63))=T_1/(SIN (90+24))
Here T1 = 31N
Weight of box 2 = w2 = 31/cos24 x sin 93
= 33.72
Weight of box 3 = w3 = 31/cos24 x cos 63
= 15.32
Therefore the weight of box 2 and box 3 is 33.72N and 15.32N
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a lawn roller is rolled across a lawn by a force of 115 n along the direction of the handle, which is 22 above the horizontal. if george develops 64.6 w of power for 90.0 s, what distance is the roller pushed?
The distance roller pushed is 54.7 meter when a lawn roller is rolled across a lawn by a force of 115 N along the direction of the handle.
What is distance and force and what distance is the roller pushed ?Distance is the quantity representing the product of speed and time of the motion under given time period.Force is a newtonian quantity representing the product of mass and acceleration .Here the lawn roller is rolled across a lawn by force 115 N , the force along the horizontal would be F = 115 cos 22 = 106.60.Power = force x speed, P = 115 x speed, 64.6 = 115 x speed , speed = 64.6/115 = 0.56 m/s.Distance = speed x time = 0.56 x 90 = 54.7 meters, hence the distance roller pushed is 54.7 meters.Therefore when a lawn roller across a lawn by force of 115 N the distance roller pushed will be 54.7 meter.To know more about distance visit:
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which has a greater luminosity, a star with absolute magnitude -2 or a star with absolute magnitude 13 ?
The total amount of energy that a star emits each second is measured by its luminosity.
What is Luminosity and magnitude?Some stars are noticeably brighter than others as one looks up at the night sky above the Earth. A star's brilliance, however, is influenced by its makeup and distance from the planet.A star's apparent magnitude, or how bright it appears to be from Earth, and absolute magnitude, or how bright it looks at a standard distance of 32.6 light-years, or 10 parsecs, are words used by astronomers to describe star brightness. (Light travels approximately 6 trillion miles (10 trillion kilometers) in a year, or one light-year.) A star's brightness, or how much energy (light) it radiates from its surface, is another quantity that astronomers measure.Although the concept of measuring star brightness is not new, astronomers now use more sophisticated tools to make the calculation.
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a group of ten friends, each of mass 50kg, want to test the strength of a trampoline. at their highest jump, each friend is 2m above the trampoline. they all land on the trampoline at the same time and decelerate at a constant rate to a point of zero velocity over a period of 0.5s. the trampoline has a threshold of 5000n, above which it breaks. do the friends succeed in breaking their trampoline? neglect air resistance and the distance the trampoline sags as a result of the friends landing.
Calculate the striking trampoline.
What is zero velocity?
The zero-velocity surface is a notion connected to the N-body gravity problem. It represents a surface that a body with the specified energy cannot traverse because it would have zero velocity there. George William Hill made the initial proclamation about it.
What is resistance?
A circuit's opposition to current flow is measured by its resistance. The Greek letter omega () stands for ohms, which are used to measure resistance. Georg Simon Ohm (1784–1854), a German physicist who examined the connection between voltage, current, and resistance, is the subject of the name "Ohm."
mass of each friends= 50kg
number of friends =10
total mass= 50×10=500kg
now initial velocity before, falling =0
let final velocity be V
v²-μ²= 2as
⇒v²+2as=2as(μ=0)
∴V=[tex]\sqrt{2as}[/tex]=[tex]\sqrt{2*9.8*2}[/tex] ( acceleration due to gravity =9.8m/s²) ( s=2m given)
=6.26ms⁻¹
∴The velocity of the friends, just before striking the trampoline= 6.26ms⁻¹
Now after striking the trampoline, the velocity of the people decelerate to 0, in a time interval 0.5s.
∴deceleration= 6.26/ 0.5= 12.52ms⁻²
∴Force required to decelerate=mass× deacceleration
=500×12.52
=6260.99
=6261N
but that trampoline has a threshold of 500N, which is less than force required to stop, the people.
hence the friends succeed in striking the trampoline.
Therefore, the friends succeed in striking the trampoline.
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what has more kinetic energy an object of mass 2m moving with speed 3v or an object of mass m moving with speed 4v
Kinetic energy The height of an object of mass m moving at speed 4v will be greater than that of an object of mass 2m moving at speed 3v. Kinetic energy = 0.5 m v2
A mass of 2 m moving at a speed of 3 v has kinetic energy of 9 m, while a mass of m moving at a speed of 4 v has kinetic energy of 8 m. The ability of an object to move another object is known as its kinetic energy. It is effective for a force to move an object. Furthermore, we are aware that an object in motion can cause a stationary object to move if it collides with it. It can therefore perform a function. The ability of an object to perform work as a result of its motion is how we define kinetic energy.
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The kinetic energy of a baseball that with a mass of 0.140kg is 7 J. What is the baseballs velocity?
Answer:
10 m/s
Explanation:
Kinetic energy= [tex]\frac{1}{2}[/tex]mv² where m is mass and v is velocity.
We have to make v the subject so we should rearrange the equation
K=[tex]\frac{1}{2}[/tex]mv²
v²= [tex]\frac{K}{0.5*m}[/tex] (use algebra)
v²= 7/0.5×0.140
v²=100
v=√100
v=10 m/s
We can confirm this by using the kinetic energy formula.
K=[tex]\frac{1}{2}[/tex]×0.140×10²
K= 7 J
Hence it is proved that velocity is 10 m/s
an art student is designing a large mobile with the dimensions shown below. object c has a mass of 1 kg, and objects b and c are in balance. what does the mass of object a need to be to balance objects b and c?
The mass of object a need to be to balance objects b and c is 12kg
Find man of b
1=[tex]\frac{m_{c}}{m_{b}+m_{c}}[/tex]×4
1=[tex]\frac{1}{1+m_{b} }[/tex]×4
[tex]m_{b}[/tex]=3kg
1=[tex]\frac{(m_{b}+m_{c} )}{m_{a} +(m_{b} +m_{c} )}[/tex] ×4
1=4×4/[tex]m_{a}[/tex]+4
[tex]m_{a}[/tex]=12kg
As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilogram is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one-kilogram times one square meter per second. The kilogram is determined by precise measurements of Planck's constant, while the second and metre are previously defined in terms of other physical constants.
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How many g are in a pack containing 10 tablets of 500 mg each? *
5g
50g
100g
500g
Answer:
5 g
Explanation:
500 mg x 10 = 5000 mg
5000 x 10^-3 g = 5 g
Hello..!
To solve the problem and calculate the number of pills in the package, we will use the conversion factor.
The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.
Find out that 1 gram has a total of 1000 mg.
Problem:
How many g are in a carton containing 10 tablets of 500 mg each?
According to the previous text we can say that the conversion factor would be:
[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]
Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:
[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]
We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:
[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]
We conclude that one box contains 5 grams of tablet, option 1.
[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]
when the moon is directly opposite the sun in the sky, its phase is: when the moon is directly opposite the sun in the sky, its phase is: new. full. waxing or waning gibbous. first or third quarter. waxing or waning crescent.
A full moon is currently visible in the sky across from our sun.
What is a new full moon?
Half of the moon is visible to us, and the other half is not lit by sunlight until around a week after the new moon. We observe the moon in this phase, sometimes referred to as the first quarter moon, around a week following the new moon.
What is waxing gibbous?
The waxing crescent and illuminated first-quarter moon are visible to the west. Since "gibbous" means "swollen" or "humpbacked," the moon phase that follows the first quarter moon is known as the "waxing gibbous moon." And indeed, it does appear as though the moon is slightly swollen or developing a small hump. You should be aware that the word "waxing" is a synonym for "increasing," which will aid you in remembering that during the waxing phase, we see more and more of the moon every night.
Therefore, the moon currently visible in the sky is a full moon.
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what is the relation between the current through the resistor and the voltage drop across the resistor
By way of Ohm's Law, the voltage drop is proportional to the cutting-edge flowing thru a resistor. (So in numerous collection resistors with the same resistance, the drop across each one is identical, because the present day throughout each one is equal).
The connection between the current, voltage, and resistance is expressed through Ohm's regulation. This states that the modern-day flowing in a circuit is at once proportional to the implemented voltage and inversely proportional to the resistance of the circuit, provided the temperature stays steady.
Resistors in the collection deliver identical cutting-edge, however, the voltage drop throughout them isn't the same as their man or woman resistance values will create one-of-a-kind voltage drops across every resistor as decided by way of Ohm's regulation ( V = I*R ).
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If you know the acceleration and time, how can you calculate the average velocity?.
The average velocity in terms of acceleration and time is 1/2at².
Average velocity:
Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
Assume the acceleration a is uniform then:
v(t) = u + at
u = initial velocity
By average velocity v we mean average over time than strictly speaking:
v = 1/t [tex]\int\limits^t_0 {v(t)} \, dt[/tex]
= 1/t [tex]\int\limits^t_0 {(u + at)} \, dt[/tex]
= 1/t ( ut + 1/2 at²)
v = u + 1/2at²
If u =0, then we have
v = 1/2 at²
Therefore the average velocity is 1/2at².
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Highlight (1) calculator
Species
0 0
Harbor seals live off the coast of New England and feed on various fish, squid, shrimp, and other marine life. A sea
approaches a school of fish consisting of mackerel, herring, and harbor pollock. The population of each species is
shown in the table.
mackerel
herring
harbor pollock
What is the probability the seal catches a mackerel?
You may use the calculator.
25%
20%
15%
33%
Elag for Review Normal Color Scheme
Population
15
23
37
There is 20% probability that the seal catches a mackerel.
What is probability?How likely something is to occur is known as its probability.
To determine probability, divide the total number of possible outcomes by the number of possible ways an event could occur. There are differences between probability and odds. Odds are calculated by dividing a situation's likelihood of occurring by its likelihood of not occurring.
Given,
mackerel 15
herring 23
harbor pollock 37
probability = possible event/ no. of event
probability = 15/ 15+23+37
probability = 15/ 75
probability = 0.2
∴ probability is 20%
For numbers less than 1 out of 1,000 (such as 0.20 out of 1,000), it is clearer to recast them as “200 out of 10,000” (“2 out of 10,000,” for instance).
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he earth's atmosphere is transparent tomost waves in thequestion options:visible part of the spectrum.infrared part of the spectrum.ultraviolet part of the spectrum.entire electromagnetic spectrum.
The earth's atmosphere is transparent to most waves is visible part of the spectrum.
What is the visible part of the spectrum?The region of the electromagnetic spectrum that the human eye can see is known as the visible light spectrum. This group of wavelengths is more commonly referred to as visible light.The range of wavelengths that the human eye can typically see is from 380 to 700 nanometers.The region of the electromagnetic spectrum that is visible to the human eye is known as the visible spectrum. This wavelength range of electromagnetic energy is referred to as visible light or just light. The ordinary human eye can see wavelengths between 380 and 750 nanometers.
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If the man pulls the sled with a 10 N
force, what is the horizontal component
of force? Refer to chapter 4, mechanics if
you do not remember how to resolve a
force into its components.
Answer:
Explanation:
The horizontal component of force is Fcosθ if the man pulls the sled with a 10 N force. Force has both a magnitude and a direction since it is a vector quantity.
What is force?A force is an external cause that, when applied, alters or has the potential to alter a body's condition. The body comes to rest while it is moving, and it moves when it is at rest.
The body's orientation, form, size, etc. may also alter as a result. An illustration would be to push or forcefully shove a door. Force has both a magnitude and a direction since it is a vector quantity. If the man pulls the sled with a 10 N force then the horizontal component of force is Fcosθ. Your training at this level should place a major emphasis on the idea that a push or even a pull was referred to as an force.
Therefore, the horizontal component of force is Fcosθ if If the man pulls the sled with a 10 N force.
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a car has a maximum acceleration of 5.8 m/s2 . what will the maximum acceleration be if the car is towing another car of the same mass? neglect the additional friction force. express your answer using two significant figures.
The maximum acceleration if the car is towing another car of the same mass is 2.8 m/s².
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Case 1:-
acceleration = force/mass
5.8 = F/m
Let each mass of the car is m
mass of two car = 2m
a = F/2m
So new acceleration will become = 5.8/2
= 2.8 m/s²
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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Compare the use of an electric bicycle with a normal bicycle used
to cycle a 5 km uphill route. The cyclist does not pedal when using
the electric bike to cycle uphill.
Information about the two bikes is given in Table 1.
Table 1
Information
power of the motor
force used to drive the
bicycle forward
weight of bicycle
battery life
time to travel 5 km
Electric bicycle
350 W
50 N
190 N
25 minutes
12 minutes
Ordinary bicycle
no motor
47 N
120 N
no battery
13 minutes
Your answer should contain descriptions of work done, energy
transfers, and power.
The work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.
W = F d cos θ
P = W / t
W = Work done
F = Force
d = Distance
P = Power
t = Time
θ = 0
d = 5 km = 5000 m
For Electric bicycle
F = 50 N
t = 12 min = 720 s
W = 50 * 5000 * cos 0
W = 250000 J
W = 250 KJ
P = 250 / 720
P = 0.35 KW
For ordinary bicycle,
F = 47 N
t = 13 min = 780 s
W = 47 * 5000 * cos 0
W = 235000 J
W = 235 KJ
P = 235 / 780
P = 0.3 KW
Therefore, the work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.
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a string is under a tension of 760.0 n. a 1.7 m length of the string has a mass of 4.8 grams. what is the speed of a transverse wave of wavelength 0.50 m in this string? what is the frequency of the wave?
The number of waves that pass by each second is the frequency of a wave, which is expressed in Hertz (Hz). For instance, a sound wave may have a frequency of 450 Hz.
Explain about the frequency of wave?
The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second. When two waves of equal amplitude and frequency are compared, the higher frequency wave has greater energy.
Divide the wave's velocity by its wavelength to determine its frequency. The unit for frequency is Hertz (Hz), so use that while writing your response. The frequency will be the inverse of the time, or 1 divided by T, if you need to determine it from the amount of time it takes for a wave cycle to complete, or T.
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